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<title><![CDATA[285G, Lecture 19: The structure of Ricci flow at the singular time, surgery, and the Poincaré conjecture]]></title>
<link>http://terrytao.wordpress.com/2008/06/06/285g-lecture-19-the-structure-of-ricci-flow-at-the-singular-time-surgery-and-the-poincare-conjecture/</link>
<pubDate>Fri, 06 Jun 2008 17:10:18 +0000</pubDate>
<dc:creator>Terence Tao</dc:creator>
<guid>http://terrytao.wordpress.com/2008/06/06/285g-lecture-19-the-structure-of-ricci-flow-at-the-singular-time-surgery-and-the-poincare-conjecture/</guid>
<description><![CDATA[In the previous lecture, we studied high curvature regions of Ricci flows on some time interval , an]]></description>
<content:encoded><![CDATA[<p>In the previous lecture, we studied high curvature regions of Ricci flows <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> on some time interval <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5B0%2CT%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[0,T)' title='{}[0,T)' class='latex' />, and concluded that (as long as a mild topological condition was obeyed) they all had canonical neighbourhoods.  This is enough control to now study the limits of such flows as one approaches the singularity time T.  It turns out that one can subdivide the manifold M into a <em>continuing region</em> C in which the geometry remains well behaved (for instance, the curvature does not blow up, and in fact converges smoothly to an (incomplete) limit), and a <em>disappearing region</em> D, whose topology is well controlled.  (For instance, the interface <img src='http://s0.wp.com/latex.php?latex=%5CSigma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Sigma' title='&#92;Sigma' class='latex' /> between C and D will be a finite union of disjoint surfaces homeomorphic to <img src='http://s0.wp.com/latex.php?latex=S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2' title='S^2' class='latex' />.)  This allows one (at the topological level, at least) to perform surgery on the interface <img src='http://s0.wp.com/latex.php?latex=%5CSigma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Sigma' title='&#92;Sigma' class='latex' />, removing the disappearing region D and replacing them with a finite number of &#8220;caps&#8221; homeomorphic to the 3-ball <img src='http://s0.wp.com/latex.php?latex=B%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B^3' title='B^3' class='latex' />.  The relationship between the topology of the post-surgery manifold and pre-surgery manifold is as is described way back in <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/01/285g-lecture-2-the-ricci-flow-approach-to-the-poincare-conjecture/">Lecture 2</a>.</p>
<p>However, once surgery is completed, one needs to restart the Ricci flow process, at which point further singularities can occur.  In order to apply surgery to these further singularities, we need to check that all the properties we have been exploiting about Ricci flows &#8211; notably the Hamilton-Ivey pinching property, the <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsing property, and the existence of canonical neighbourhoods for every point of high curvature &#8211; persist even in the presence of a large number of surgeries (indeed, with the way the constants are structured, all quantitative bounds on a fixed time interval [0,T] have to be uniform in the number of surgery times, although we will of course need the set of such times to be discrete).  To ensure that surgeries do not disrupt any of these properties, it turns out that one has to perform these surgeries deep in certain <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-horns of the Ricci flow at the singular time, in which the geometry is extremely close to being cylindrical (in particular, it should be a <img src='http://s0.wp.com/latex.php?latex=%5Cdelta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta' title='&#92;delta' class='latex' />-neck and not just a <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-neck, where the surgery control parameter <img src='http://s0.wp.com/latex.php?latex=%5Cdelta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta' title='&#92;delta' class='latex' /> is much smaller than <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />; selection of this parameter can get a little tricky if one wants to evolve Ricci flow with surgery indefinitely, although for the purposes of the Poincaré conjecture the situation is simpler as there is a fixed upper bound on the time for which one needs to evolve the flow).  Furthermore, the geometry of the manifolds one glues in to replace the disappearing regions has to be carefully chosen (in particular, it has to not disrupt the pinching condition, and the geometry of these glued in regions has to resemble a <img src='http://s0.wp.com/latex.php?latex=%28C%2C%5Cvarepsilon%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(C,&#92;varepsilon)' title='(C,&#92;varepsilon)' class='latex' />-cap for a significant amount of (rescaled) time).  The construction of the &#8220;standard solution&#8221; needed to achieve all these properties is somewhat delicate, although we will not discuss this issue much here.</p>
<p>In this, the final lecture, we shall present these issues from a high-level perspective; due to lack of time and space we will not cover the finer details of the surgery procedure.  More detailed versions of the material here can be found in <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0303109">Perelman&#8217;s second paper</a>, the <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0605667">notes of Kleiner-Lott</a>, the <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2334563">book of Morgan-Tian</a>, and the paper of <a class="snap_noshots" href="http://arxiv.org/abs/math/0612069">Cao-Zhu</a>.  (See also a forthcoming paper of Bessières, Besson, Boileau, Maillot, and Porti.)</p>
<p><!--more--></p>
<p style="text-align:center;">&#8211; Ricci flow at the singular time &#8211;</p>
<p>Suppose we have a compact 3-dimensional Ricci flow <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> on the time interval <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5B0%2CT%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[0,T)' title='{}[0,T)' class='latex' /> without any embedded <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^2' title='&#92;Bbb{RP}^2' class='latex' /> with trivial normal bundle; for simplicity we can take M to be connected (otherwise we simply treat each of the finite number of connected components of M separately).  We are interested in the extent to which we can define a limiting geometry g(T) on M (or on some subset of M) at the final time T, and to work out the topological structure of the portions of M for which such a limit cannot be defined.</p>
<p>From Theorem 1 of Lecture 18, we know that any point <img src='http://s0.wp.com/latex.php?latex=%28t%2Cx%29+%5Cin+%5B0%2CT%29+%5Ctimes+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t,x) &#92;in [0,T) &#92;times M' title='(t,x) &#92;in [0,T) &#92;times M' class='latex' /> for which the curvature R(t,x) exceeds a certain threshold K, will lie in a canonical neighbourhood.  (For sake of discussion we shall suppress the constants C and <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />, as they will not play a major role in what follows.)  One consequence of this is that one has the pointwise bounds</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cnabla+R+%3D+O%28+R%5E%7B3%2F2%7D+%29%3B+%5Cquad+R_t+%3D+O%28R%5E2%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla R = O( R^{3/2} ); &#92;quad R_t = O(R^2)' title='&#92;nabla R = O( R^{3/2} ); &#92;quad R_t = O(R^2)' class='latex' /> (1)</p>
<p>whenever <img src='http://s0.wp.com/latex.php?latex=R+%5Cgeq+K&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R &#92;geq K' title='R &#92;geq K' class='latex' />.  Also recall from the maximum principle that we have <img src='http://s0.wp.com/latex.php?latex=R+%5Cgeq+-O%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R &#92;geq -O(1)' title='R &#92;geq -O(1)' class='latex' /> throughout.</p>
<p>These simple regularity properties of the scalar curvature R are already enough to classify the limiting behaviour of <img src='http://s0.wp.com/latex.php?latex=R%28t%2Cx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(t,x)' title='R(t,x)' class='latex' /> as <img src='http://s0.wp.com/latex.php?latex=t+%5Cto+T&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;to T' title='t &#92;to T' class='latex' /> for each fixed x:</p>
<p><strong>Exercise 1.</strong> Using (1), show that for every <img src='http://s0.wp.com/latex.php?latex=x+%5Cin+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x &#92;in M' title='x &#92;in M' class='latex' /> there are either two possibilities: either <img src='http://s0.wp.com/latex.php?latex=R%28t%2Cx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(t,x)' title='R(t,x)' class='latex' /> remains bounded as <img src='http://s0.wp.com/latex.php?latex=t+%5Cto+T&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;to T' title='t &#92;to T' class='latex' /> (with a bound that can depend on x), or that <img src='http://s0.wp.com/latex.php?latex=R%28t%2Cx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(t,x)' title='R(t,x)' class='latex' /> goes to infinity as <img src='http://s0.wp.com/latex.php?latex=t+%5Cto+T&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;to T' title='t &#92;to T' class='latex' />, and in the latter case we even have the stronger statement <img src='http://s0.wp.com/latex.php?latex=%5Clim_%7Bt+%5Cto+T%7D+%28T-t%29+R%28t%2Cx%29+%26%2362%3B+c&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;lim_{t &#92;to T} (T-t) R(t,x) &gt; c' title='&#92;lim_{t &#92;to T} (T-t) R(t,x) &gt; c' class='latex' /> for some c depending only on the implied constant in (1).   If we let <img src='http://s0.wp.com/latex.php?latex=%5COmega+%5Csubset+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Omega &#92;subset M' title='&#92;Omega &#92;subset M' class='latex' /> be the  set of x for which <img src='http://s0.wp.com/latex.php?latex=R%28t%2Cx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(t,x)' title='R(t,x)' class='latex' /> remains bounded, show that <img src='http://s0.wp.com/latex.php?latex=%5COmega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Omega' title='&#92;Omega' class='latex' /> is open, and <img src='http://s0.wp.com/latex.php?latex=R%28t%2C%5Ccdot%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(t,&#92;cdot)' title='R(t,&#92;cdot)' class='latex' /> converges uniformly on compact subsets of <img src='http://s0.wp.com/latex.php?latex=%5COmega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Omega' title='&#92;Omega' class='latex' /> to some limit <img src='http://s0.wp.com/latex.php?latex=R%28T%2C%5Ccdot%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(T,&#92;cdot)' title='R(T,&#92;cdot)' class='latex' /> as <img src='http://s0.wp.com/latex.php?latex=t+%5Cto+T&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;to T' title='t &#92;to T' class='latex' />. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>The pinching property also lets us establish bounds of the form <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRiem%7D+%3D+O%281+%2B+%26%23124%3BR%26%23124%3B%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Riem} = O(1 + &#124;R&#124;)' title='&#92;hbox{Riem} = O(1 + &#124;R&#124;)' class='latex' />.  Using this and Shi&#8217;s regularity estimates (and the non-collapsing property), one can show that <img src='http://s0.wp.com/latex.php?latex=%28%5COmega%2C+g%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;Omega, g(t))' title='(&#92;Omega, g(t))' class='latex' /> converges in <img src='http://s0.wp.com/latex.php?latex=C%5E%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C^&#92;infty' title='C^&#92;infty' class='latex' /> on compact subsets of <img src='http://s0.wp.com/latex.php?latex=%5COmega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Omega' title='&#92;Omega' class='latex' /> to an incomplete limit <img src='http://s0.wp.com/latex.php?latex=%28%5COmega%2C+g%28T%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;Omega, g(T))' title='(&#92;Omega, g(T))' class='latex' />.</p>
<p>Our main tasks here are to understand the geometry of the limit <img src='http://s0.wp.com/latex.php?latex=%28%5COmega%2C+g%28T%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;Omega, g(T))' title='(&#92;Omega, g(T))' class='latex' />, and the topology of the remaining region <img src='http://s0.wp.com/latex.php?latex=M+%5Cbackslash+%5COmega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M &#92;backslash &#92;Omega' title='M &#92;backslash &#92;Omega' class='latex' /> (and how the two regions connect to each other).</p>
<p>If <img src='http://s0.wp.com/latex.php?latex=%5COmega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Omega' title='&#92;Omega' class='latex' /> is all of M, then the Ricci flow continues smoothly to time T, and we can continue onwards beyond T by the local existence theory for that flow.  Now let us instead consider the other extreme case in which <img src='http://s0.wp.com/latex.php?latex=%5COmega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Omega' title='&#92;Omega' class='latex' /> is empty.  In this case, from Exercise 1 we see that we have <img src='http://s0.wp.com/latex.php?latex=R%28t%2Cx%29+%5Cgeq+K&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(t,x) &#92;geq K' title='R(t,x) &#92;geq K' class='latex' /> for all <img src='http://s0.wp.com/latex.php?latex=x+%5Cin+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x &#92;in M' title='x &#92;in M' class='latex' />, if t is sufficiently close to T.  In particular, this means that <em>every</em> point in M lies in a canonical neighbourhood: an <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-round component (topologically <img src='http://s0.wp.com/latex.php?latex=S%5E3%2F%5CGamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^3/&#92;Gamma' title='S^3/&#92;Gamma' class='latex' />), a C-component (topologically <img src='http://s0.wp.com/latex.php?latex=S%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^3' title='S^3' class='latex' /> or <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^3' title='&#92;Bbb{RP}^3' class='latex' />), a <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-neck (topologically <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5B-1%2C1%5D+%5Ctimes+S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[-1,1] &#92;times S^2' title='{}[-1,1] &#92;times S^2' class='latex' />), or a <img src='http://s0.wp.com/latex.php?latex=%28C%2C%5Cvarepsilon%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(C,&#92;varepsilon)' title='(C,&#92;varepsilon)' class='latex' />-cap (topologically a 3-ball or punctured <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^3' title='&#92;Bbb{RP}^3' class='latex' />).  If any point lies in the first type of canonical neighbourhoods, then M is topologically a spherical space form <img src='http://s0.wp.com/latex.php?latex=S%5E3%2F%5CGamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^3/&#92;Gamma' title='S^3/&#92;Gamma' class='latex' />.  Similarly, if any point lies in the second type, M is either an <img src='http://s0.wp.com/latex.php?latex=S%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^3' title='S^3' class='latex' /> or <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^3' title='&#92;Bbb{RP}^3' class='latex' /> this way.  So the only remaining case left is when every point lies in a neck or a cap.  Since each cap contains at least one neck in it, we have at least one neck; following this neck in both directions, we either must end up with a doubly capped tube, or the tube must eventually connect back to itself.  In the former case we obtain an <img src='http://s0.wp.com/latex.php?latex=S%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^3' title='S^3' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^3' title='&#92;Bbb{RP}^3' class='latex' />, or <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E3+%5C%23+%5CBbb%7BRP%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^3 &#92;# &#92;Bbb{RP}^3' title='&#92;Bbb{RP}^3 &#92;# &#92;Bbb{RP}^3' class='latex' /> (depending on whether zero, one, or two of the caps are punctured <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^3' title='&#92;Bbb{RP}^3' class='latex' />&#8216;s rather than 3-balls); in the latter case, we get an <img src='http://s0.wp.com/latex.php?latex=S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2' title='S^2' class='latex' /> bundle over <img src='http://s0.wp.com/latex.php?latex=S%5E1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^1' title='S^1' class='latex' />, which as discussed back in <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/01/285g-lecture-2-the-ricci-flow-approach-to-the-poincare-conjecture/">Lecture 2</a> comes in only two topological types, oriented and unoriented.</p>
<p>To summarise, if <img src='http://s0.wp.com/latex.php?latex=%5COmega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Omega' title='&#92;Omega' class='latex' /> is empty, then M is either a spherical space form,<br />
<img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E3+%5C%23+%5CBbb%7BRP%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^3 &#92;# &#92;Bbb{RP}^3' title='&#92;Bbb{RP}^3 &#92;# &#92;Bbb{RP}^3' class='latex' />, or an <img src='http://s0.wp.com/latex.php?latex=S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2' title='S^2' class='latex' /> bundle over <img src='http://s0.wp.com/latex.php?latex=S%5E1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^1' title='S^1' class='latex' />.  In this case, the surgery procedure is simply to delete the entire manifold; this respects the topological compatibility condition required for Theorem 2 of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/01/285g-lecture-2-the-ricci-flow-approach-to-the-poincare-conjecture/">Lecture 2</a>.  (The geometric compatibility condition is moot in this case.)  In this case, the disappearing region is the whole manifold M, and the continuing region is empty.</p>
<p>Similar considerations occur if <img src='http://s0.wp.com/latex.php?latex=%5COmega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Omega' title='&#92;Omega' class='latex' /> is non-empty, but that <img src='http://s0.wp.com/latex.php?latex=R%28T%2Cx%29+%5Cgeq+2K&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(T,x) &#92;geq 2K' title='R(T,x) &#92;geq 2K' class='latex' /> (say) for all <img src='http://s0.wp.com/latex.php?latex=x+%5Cin+%5COmega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x &#92;in &#92;Omega' title='x &#92;in &#92;Omega' class='latex' />.  So we may assume that there is at least one x for which <img src='http://s0.wp.com/latex.php?latex=R%28T%2Cx%29+%26%2360%3B+2K&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(T,x) &lt; 2K' title='R(T,x) &lt; 2K' class='latex' />, and thus <img src='http://s0.wp.com/latex.php?latex=R%28t%2Cx%29+%26%2360%3B+2K&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(t,x) &lt; 2K' title='R(t,x) &lt; 2K' class='latex' /> for all t sufficiently close to T.  Thus we are guaranteed at least one point of bounded curvature in M, even at times close to the singular time.  We can also assume that no canonical neighbourhood in M is an <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-round or C-component, since again in this case we could delete the entire manifold by surgery.  Thus every point of curvature greater than K lies in a neck or a cap.</p>
<p>Because of this, it is not hard to show that every boundary point of <img src='http://s0.wp.com/latex.php?latex=%5COmega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Omega' title='&#92;Omega' class='latex' />  (where <img src='http://s0.wp.com/latex.php?latex=R%28T%2Cx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(T,x)' title='R(T,x)' class='latex' /> becomes infinite) lies at the end of an <em><img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-horn</em>:a tube of <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-necks of curvature at least 4K (say) throughout, with the curvature becoming infinite at one or both ends (thus the width of the necks go to zero as one approaches the boundary of <img src='http://s0.wp.com/latex.php?latex=%5COmega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Omega' title='&#92;Omega' class='latex' />).  (Note that if the tube is ever capped off by a <img src='http://s0.wp.com/latex.php?latex=%28C%2C%5Cvarepsilon%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(C,&#92;varepsilon)' title='(C,&#92;varepsilon)' class='latex' />-cap, then the curvature does not go to infinity in this tube.) If the curvature goes to infinity at both ends, we have a <em>double <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-horn</em>; otherwise, we have a <em>single <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-horn</em> will have one infinite curvature end and one end with bounded curvature.</p>
<p>The single <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-horns are all disjoint from each other, and their volume is bounded from below, and so they are finite in number.  So the geometric picture of <img src='http://s0.wp.com/latex.php?latex=%28%5COmega%2Cg%28T%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;Omega,g(T))' title='(&#92;Omega,g(T))' class='latex' /> is that of a (possibly infinite) number of double <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-horns, together with a finite number of additional connected incomplete manifolds, with boundary consisting of a finite number of disjoint spheres <img src='http://s0.wp.com/latex.php?latex=S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2' title='S^2' class='latex' />, with a single <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-horn glued on to each one of these spheres.</p>
<p>Suppose one performs a topological surgery on each single <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-horn, by taking a sphere <img src='http://s0.wp.com/latex.php?latex=S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2' title='S^2' class='latex' /> somewhere in the middle of each horn, removing the portion between that <img src='http://s0.wp.com/latex.php?latex=S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2' title='S^2' class='latex' /> and the boundary, and replacing it by a 3-ball.    We also remove all the double <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-horns; all the removed regions form the disappearing region of M, and the remainder is the continuing region.  This creates a new compact (but possibly disconnected) manifold <img src='http://s0.wp.com/latex.php?latex=M%28T%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M(T)' title='M(T)' class='latex' />, formed by gluing finitely many 3-balls to the continuing region.  To see the topological relationship between this new manifold and the previous manifold M, we move backwards in time a slight amount to an earlier time t, so that the horn is no longer singular at its boundary and instead connects to the remainder <img src='http://s0.wp.com/latex.php?latex=M%5Cbackslash+%5COmega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M&#92;backslash &#92;Omega' title='M&#92;backslash &#92;Omega' class='latex' /> of the manifold.  If t is close enough to T, then (by (1)), the portion of the horn between the <img src='http://s0.wp.com/latex.php?latex=S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2' title='S^2' class='latex' /> and the boundary of the horn will still have curvature at least K, and thus every point here will lie in a neck or cap.  Also, all the points in <img src='http://s0.wp.com/latex.php?latex=M+%5Cbackslash+%5COmega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M &#92;backslash &#92;Omega' title='M &#92;backslash &#92;Omega' class='latex' />, and in particular the portion of the manifold beyond the boundary of the horn, will also have curvature at least K and thus lie in a neck or cap if t is close enough to T.  If we then follow this desingularised horn from the surgery sphere <img src='http://s0.wp.com/latex.php?latex=S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2' title='S^2' class='latex' /> towards its boundary and beyond (possibly passing through any number of double <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-horns in the process), we will either discover a capped tube (which is thus topologically either a 3-ball or a punctured <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^3' title='&#92;Bbb{RP}^3' class='latex' />), or else the tube will eventually connect to another surgery sphere, which may or may not lie in the same connected component of M(T).  Topologically, the first case corresponds to taking a <a href="http://en.wikipedia.org/wiki/Connected_sum">connected sum</a> of (one component of) M(T) with either a sphere <img src='http://s0.wp.com/latex.php?latex=S%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^3' title='S^3' class='latex' /> or a projective space <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^3' title='&#92;Bbb{RP}^3' class='latex' />; the second case corresponds to taking a connected sum of one component of M(T) with either another component of M(T), or with an <img src='http://s0.wp.com/latex.php?latex=S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2' title='S^2' class='latex' />-bundle over <img src='http://s0.wp.com/latex.php?latex=S%5E1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^1' title='S^1' class='latex' />.  Putting all this together we see that M is the connected sum of the components of M(T), together with finitely many <img src='http://s0.wp.com/latex.php?latex=S%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^3' title='S^3' class='latex' />&#8216;s, <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^3' title='&#92;Bbb{RP}^3' class='latex' />&#8216;s, and <img src='http://s0.wp.com/latex.php?latex=S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2' title='S^2' class='latex' />-bundles over <img src='http://s0.wp.com/latex.php?latex=S%5E1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^1' title='S^1' class='latex' />, which again gives the topological compatibility condition required for Theorem 2 of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/01/285g-lecture-2-the-ricci-flow-approach-to-the-poincare-conjecture/">Lecture 2</a>.</p>
<p>We have thus successfully performed a single (topological) surgery.  However, in doing so we have lost a lot of <em>quantitative</em> properties of the geometry, such as Hamilton-Ivey pinching, <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsing, and the canonical neighbourhood property, which means that we cannot yet ensure that we can perform any further surgeries.  To resolve this problem, we need to be more precise about the surgery process, in particular using our freedom to choose the surgery sphere as deep inside the <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-horn as we please, and to prescribe the metric on the cap that we attach to that sphere.</p>
<p style="text-align:center;">&#8211; Surgery &#8211;</p>
<p>To do surgery, a key observation of Perelman is that the geometry of the horn becomes increasingly cylindrical as one goes deeper into the horn:</p>
<blockquote><p><strong>Lemma 1.</strong> Let H be a single <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-horn which has width scale comparable to r at the finite curvature end, and let <img src='http://s0.wp.com/latex.php?latex=%5Cdelta+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta &gt; 0' title='&#92;delta &gt; 0' class='latex' />.  Then there exists a <img src='http://s0.wp.com/latex.php?latex=%5Cdelta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta' title='&#92;delta' class='latex' />-neck of width scale comparable to h inside the horn H, where <img src='http://s0.wp.com/latex.php?latex=h+%3D+h%28r%2C%5Cdelta%29+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='h = h(r,&#92;delta) &gt; 0' title='h = h(r,&#92;delta) &gt; 0' class='latex' /> is a small quantity depending only on r and <img src='http://s0.wp.com/latex.php?latex=%5Cdelta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta' title='&#92;delta' class='latex' />.</p></blockquote>
<p><strong>Proof.</strong> (Sketch) Suppose this was not the case; then one could find a sequence of horns <img src='http://s0.wp.com/latex.php?latex=H_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='H_n' title='H_n' class='latex' /> of this type, and a sequence of points <img src='http://s0.wp.com/latex.php?latex=x_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_n' title='x_n' class='latex' /> inside these horns inside <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-necks of width scale comparable to <img src='http://s0.wp.com/latex.php?latex=h_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='h_n' title='h_n' class='latex' /> which are not inside <img src='http://s0.wp.com/latex.php?latex=%5Cdelta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta' title='&#92;delta' class='latex' />-necks of this scale, where <img src='http://s0.wp.com/latex.php?latex=h_n+%5Cto+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='h_n &#92;to 0' title='h_n &#92;to 0' class='latex' />.  We can find a minimising geodesic from the finite curvature end to the infinite curvature end that goes through the neck near <img src='http://s0.wp.com/latex.php?latex=x_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_n' title='x_n' class='latex' />.  We then rescale <img src='http://s0.wp.com/latex.php?latex=%28H_n%2C+x_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(H_n, x_n)' title='(H_n, x_n)' class='latex' /> to have width 1 at <img src='http://s0.wp.com/latex.php?latex=x_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_n' title='x_n' class='latex' />, and then apply the machinery from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/06/04/285g-lecture-18-the-structure-of-high-curvature-regions-of-ricci-flow/">Lecture 18</a> to obtain a limit <img src='http://s0.wp.com/latex.php?latex=%28H_%5Cinfty%2Cx_%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(H_&#92;infty,x_&#92;infty)' title='(H_&#92;infty,x_&#92;infty)' class='latex' />; the bounded curvature at bounded distance property (Proposition 3 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/06/04/285g-lecture-18-the-structure-of-high-curvature-regions-of-ricci-flow/">Lecture 18</a>) shows that both the bounded curvature end and the infinite curvature end of the horn must recede to be infinitely far away from <img src='http://s0.wp.com/latex.php?latex=x_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_n' title='x_n' class='latex' /> in the limit, and so <img src='http://s0.wp.com/latex.php?latex=H_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='H_&#92;infty' title='H_&#92;infty' class='latex' /> becomes complete; it also has non-negative curvature, by pinching.   The minimising geodesic becomes a minimising line in <img src='http://s0.wp.com/latex.php?latex=H_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='H_&#92;infty' title='H_&#92;infty' class='latex' />, and so by the Cheeger-Gromoll theorem it splits <img src='http://s0.wp.com/latex.php?latex=H_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='H_&#92;infty' title='H_&#92;infty' class='latex' /> into the product of a line and a two-dimensional manifold (which is <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-close to a sphere).  It turns out that we can continue all these manifolds backwards in time and repeat these arguments (much as in <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/06/04/285g-lecture-18-the-structure-of-high-curvature-regions-of-ricci-flow/">Lecture 18</a>) to eventually give <img src='http://s0.wp.com/latex.php?latex=H_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='H_&#92;infty' title='H_&#92;infty' class='latex' /> the structure of a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution; but then the vanishing curvature forces it to be a round cylinder, by Proposition 2 of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/06/02/285g-lecture-17-the-structure-of-%ce%ba-solutions/">Lecture 17</a>.  This implies that the rescaled <img src='http://s0.wp.com/latex.php?latex=H_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='H_n' title='H_n' class='latex' /> are eventually <img src='http://s0.wp.com/latex.php?latex=%5Cdelta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta' title='&#92;delta' class='latex' />-necks, a contradiction. <img src='http://s0.wp.com/latex.php?latex=%5CBox&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Box' title='&#92;Box' class='latex' /></p>
<p>In order to successfully perform Ricci flow with surgery up to some specified time T (starting from controlled initial conditions, and as always assuming that no embedded <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^2' title='&#92;Bbb{RP}^2' class='latex' /> with trivial normal bundle is present), we shall pick <img src='http://s0.wp.com/latex.php?latex=%5Cdelta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta' title='&#92;delta' class='latex' /> to be a very small number depending on T and the initial condition parameters, and perform our surgery on the <img src='http://s0.wp.com/latex.php?latex=%5Cdelta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta' title='&#92;delta' class='latex' />-necks the scale h provided by Lemma 1, where <img src='http://s0.wp.com/latex.php?latex=r%5E%7B-2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r^{-2}' title='r^{-2}' class='latex' /> is (essentially) the curvature threshold beyond which the canonical neighbourhood condition holds.  (In order to avoid a circular dependence of constants, one needs to check that even after surgery, that the curvature threshold for the canonical neighbourhood condition remains bounded even after arbitrarily many surgeries, as long as <img src='http://s0.wp.com/latex.php?latex=%5Cdelta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta' title='&#92;delta' class='latex' /> is chosen sufficiently small depending on this scale, on T, and on the initial conditions.)</p>
<p><strong>Remark 1. </strong>Thanks to finite time extinction in the simply connected case, being able to perform Ricci flow with surgery up to a preassigned finite time T is sufficient for proving the Poincaré conjecture (cf. Remark 1.4 of <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0307245">Perelman&#8217;s third paper</a>).  For the full geometrisation conjecture, however, one needs to perform Ricci flow with surgery for an infinite amount of time.  For this, one cannot pick a single <img src='http://s0.wp.com/latex.php?latex=%5Cdelta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta' title='&#92;delta' class='latex' />; instead, one has to divide the time interval into bounded intervals (e.g. dyadic intervals), and pick a different <img src='http://s0.wp.com/latex.php?latex=%5Cdelta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta' title='&#92;delta' class='latex' /> for each one (which depends on a number of parameters, including the curvature threshold for the canonical neighbourhbood property on the previous dyadic interval).  This selection of constants becomes a little subtle; see e.g. the <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0605667">notes of Kleiner-Lott</a> for further discussion. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>Having located a <img src='http://s0.wp.com/latex.php?latex=%5Cdelta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta' title='&#92;delta' class='latex' />-neck inside each single <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-horn, we remove the half of the neck from the centre sphere to the infinite curvature region, and smoothly interpolate in its place a copy of an (appropriately rescaled) <em>standard solution</em>.   There is some choice as to how to set up this solution (much as there is some freedom when selecting a cutoff function), but roughly speaking this solution should resemble the manifold formed by attaching a hemispherical cap to a round unit cylinder, except that one needs to smooth out the transition between the two portions of this solution; also, one needs to ensure that one has positive curvature throughout the standard solution in order not to disrupt the Hamilton-Ivey pinching property.  It is also technically convenient to demand that this solution is spherically symmetric (at which point Ricci flow collapses to a system of two scalar equations in one spatial dimension).  One can show that such standard solutions exist for unit time (just as the round unit cylinder does), and asymptotically matches the round shrinking solution at spatial infinity.  As one consequence of this, one can check that all points in spacetime on the standard solution have canonical neighbourhoods; and, with some effort, one can also show that the same will be true in the spacetime vicinity of the region in which a standard solution has been inserted via surgery into a Ricci flow, as long as <img src='http://s0.wp.com/latex.php?latex=%5Cdelta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta' title='&#92;delta' class='latex' /> is sufficiently small.  This is an essential tool to ensure that the canonical neighbourhood solution persists after multiple surgeries.</p>
<p><strong>Remark 2.</strong> Suppose that M is irreducible with respect to connected sum (one can easily reduce to this case for the purposes of the Poincaré conjecture, thanks to Kneser&#8217;s theorem on the existence of the <a href="http://en.wikipedia.org/wiki/Prime_decomposition_%283-manifold%29">prime decomposition</a>). Then all surgeries must be topologically trivial, which means that every <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-horn, when viewed just before the singular time, only connects to a tube capped off with a ball.  Then one can show that the surgery procedure is <em>almost distance decreasing</em> in the sense that for any <img src='http://s0.wp.com/latex.php?latex=%5Ceta+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;eta &gt; 0' title='&#92;eta &gt; 0' class='latex' />, there exists a <img src='http://s0.wp.com/latex.php?latex=1+%2B%5Ceta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='1 +&#92;eta' title='1 +&#92;eta' class='latex' />-Lipschitz diffeomorphism from the pre-surgery manifold to the post-surgery manifold.  This property is useful for ensuring that various arguments for establishing finite time extinction for Ricci flows, also work for Ricci flows with surgery, as discussed for in <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/15/285g-lecture-5-finite-time-extinction-of-the-third-homotopy-group-i/">Lecture 5</a> and <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/18/285g-lecture-6-finite-time-extinction-of-the-third-homotopy-group-ii/">Lecture 6</a>.  Even if the manifold is not irreducible, one can show that there are only finitely many surgeries that change the topology of the manifold; this can be established either using the prime decomposition, or by constructing a topological invariant (namely, the maximal number of homotopically non-trivial and homotopiclly distinct embedded 2-spheres in M) which is finite, non-negative, decreases by at least one with non-trivial surgery; see Section 18.2 of <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2334563">Morgan-Tian</a> for details. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p><strong>Remark 3.</strong> The various properties listed above of the standard solution and its insertion into surgery regions are the &#8220;geometric compatibility conditions&#8221; alluded to in <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/01/285g-lecture-2-the-ricci-flow-approach-to-the-poincare-conjecture/">Theorem 2</a> of Lecture 2. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:center;">&#8211; Controlling the geometry after multiple surgeries &#8211;</p>
<p>Suppose that we have already performed a large (but finite) number of surgeries.  In order to be able to continue Ricci flow with surgery, it is necessary that we maintain quantitative control on the geometry of the manifold which is uniform in the number of surgeries.  Specifically, we need to extend the following existing controls on Ricci flow, to Ricci flow with surgery:</p>
<ol>
<li>Lower bounds on <img src='http://s0.wp.com/latex.php?latex=R_%7B%5Chbox%7Bmin%7D%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R_{&#92;hbox{min}}' title='R_{&#92;hbox{min}}' class='latex' />.</li>
<li>Hamilton-Ivey pinching type bounds that lower bound <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRiem%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Riem}' title='&#92;hbox{Riem}' class='latex' /> in terms of R.</li>
<li><img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsing of the manifold.</li>
<li>Canonical neighbourhoods for all high curvature points in the flow.</li>
</ol>
<p>The first two controls are quite easy to establish, because they are propagated by Ricci flow (thanks to the maximum principle), and are easily preserved by surgery (basically because 1. and 2. are primarily concerned with negative curvature, and surgery is only performed in regions of high positive curvature by construction).  It is significantly trickier however to preserve 3., because the proof of <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsing is more global, requiring the use of <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-geodesics through spacetime.  The key new difficulty is that thanks to the presence of surgery, the manifold can become &#8220;parabolically disconnected&#8221;; not every point in the initial manifold <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%280%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g(0))' title='(M,g(0))' class='latex' /> can be reached from a future point in a later manifold <img src='http://s0.wp.com/latex.php?latex=%28M%28t%29%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M(t),g(t))' title='(M(t),g(t))' class='latex' /> by an <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-geodesic, because an intervening surgery could have removed the region of spacetime that the geodesic ought to have passed through.  This forces one to introduce the notion of an <em>admissible curve</em> &#8211; curves that avoid the surgery regions completely &#8211; and <em>barely admissible curves</em>, which are admissible curves which touch the boundary of the surgery regions.  Roughly speaking, the monotonicity of reduced volume now controls the <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsing at future times in terms of the non-collapsing of the portion of the initial manifold <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%280%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g(0))' title='(M,g(0))' class='latex' /> which can be reached by admissible curves; this region is bordered by points which can be reached by barely admissible curves.</p>
<p>Now suppose we knew that all barely admissible curves had large reduced length.  Then the maximum principle argument that located points of small reduced length for Ricci flows (cf. equation (18) from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/14/285g-lecture-11-%ce%ba-noncollapsing-via-perelman-reduced-volume/">Lecture 11</a>), would continue to work for Ricci flows with surgery, with the points located being inside the admissible region.  It turns out that the arguments of Lecture 11 could then be adapted to this setting without much difficulty to establish the desired <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsing.</p>
<p>It is not too difficult to show that if a path did pass through a <img src='http://s0.wp.com/latex.php?latex=%5Cdelta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta' title='&#92;delta' class='latex' />-neck inside an <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-horn in which surgery was taking place, then the portion of the path near to that surgery region would have a large contribution to the reduced length (unless the starting point of the path was very close to the surgery region, but then one could verify the non-collapsing property directly, essentially due to the non-collapsed nature of the standard solution).  This almost settles the problem immediately, except for the technical issue that there might be regions of negative curvature elsewhere in spacetime which could drag the reduced length back down again (note that the reduced length is not guaranteed to be non-negative!).  There is a technical fix for this, defining a modified reduced length in which the curvature term R is replaced by <img src='http://s0.wp.com/latex.php?latex=%5Cmax%28R%2C0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;max(R,0)' title='&#92;max(R,0)' class='latex' /> (and using the lower bounds on <img src='http://s0.wp.com/latex.php?latex=R_%7B%5Cmin%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R_{&#92;min}' title='R_{&#92;min}' class='latex' /> to measure the discrepancy between the two notions), but we will not discuss the details here; see Lemma 5.2 of <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0303109">Perelman&#8217;s second paper</a> (and Chapter 16 of <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2334563">Morgan-Tian</a> for a very detailed treatment).</p>
<p><strong>Remark 4.</strong> A recent <a class="snap_noshots" href="http://arxiv.org/abs/0712.1329">paper of Zhang</a> uses Perelman&#8217;s entropy (as in <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/24/285a-lecture-8-ricci-flow-as-a-gradient-flow-log-sobolev-inequalities-and-perelman-entropy/">Lecture 8</a>) to establish <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsing for Ricci flow with surgery, using the distance-decreasing property to keep control of the entropy functional after each (topologically trivial) surgery.   This should provide a way to simplify this part of the argument, at least in the case of irreducible manifolds M. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>Finally, one has to check that all high-curvature points of Ricci flows with surgery lie in canonical neighbourhoods, where the threshold for &#8220;high curvature&#8221; is uniform in the number of surgeries performed.  Very roughly speaking, there are two cases, depending on whether there was a surgery performed near (in the spacetime sense) such a region or not.  If there was no nearby surgery, then the arguments in Lecture 18 (which are local in nature) essentially go through, exploiting heavily the <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsing and pinching properties that we have just established.  If instead there was a nearby surgery in the recent past, then one needs to approximate the geometry here by the geometry of the standard solution, for which all points have canonical neighbourhoods.  See for instance Section 17.1 of <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2334563">Morgan-Tian</a> for details.</p>
<p style="text-align:center;">&#8211; Surgery times do not accumulate &#8211;</p>
<p>The very last thing one needs to do to establish the Poincaré conjecture is to establish Theorem 3 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/01/285g-lecture-2-the-ricci-flow-approach-to-the-poincare-conjecture/">Lecture 2</a>, which asserts that the set of surgery times is discrete.  It turns out that this is in fact rather easy to establish.  One first observes that each surgery removes at least some constant amount of <img src='http://s0.wp.com/latex.php?latex=c%28h%29+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='c(h) &gt; 0' title='c(h) &gt; 0' class='latex' /> of<br />
volume from the manifold (as can be seen by looking at what happens to a single <img src='http://s0.wp.com/latex.php?latex=%5Cdelta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta' title='&#92;delta' class='latex' />-neck of width roughly h under surgery; all other removals under surgery of course only decrease the volume further).  On the other hand, using the volume variation formula (equation (33) from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/03/28/285g-lecture-1-ricci-flow/">Lecture 1</a>) we have an upper bound on the growth of volume during non-surgery times:</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bd%7D%7Bdt%7D+%5Chbox%7BVol%7D%28M%28t%29%29+%5Cleq+-R_%7B%5Cmin%7D%28t%29+%5Chbox%7BVol%7D%28M%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{d}{dt} &#92;hbox{Vol}(M(t)) &#92;leq -R_{&#92;min}(t) &#92;hbox{Vol}(M(t))' title='&#92;frac{d}{dt} &#92;hbox{Vol}(M(t)) &#92;leq -R_{&#92;min}(t) &#92;hbox{Vol}(M(t))' class='latex' />. (2)</p>
<p>Since we have a uniform lower bound on <img src='http://s0.wp.com/latex.php?latex=R_%7B%5Cmin%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R_{&#92;min}' title='R_{&#92;min}' class='latex' />, this implies that volume can grow at most exponentially, and in particular can only grow by a bounded amount on any fixed time interval.  Hence there can be at most finitely many surgeries on each such time interval, and we are done.</p>
<p><strong>Remark 5. </strong>The number of surgeries performed in a given time interval, while finite, could be incredibly large; it depends on the length scale h of the surgery, which in turn depends on the parameter <img src='http://s0.wp.com/latex.php?latex=%5Cdelta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta' title='&#92;delta' class='latex' />, which needs to be very small in order not to disrupt the <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsing or canonical neighbourhood properties of the flow.  This is why it is essential that our control of such properties is uniform with respect to the number of surgeries. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p><strong>Remark 6. </strong>Note also that there is no lower bound as to how close two surgery times could be to each other; indeed, there is nothing preventing two completely unrelated surgeries from being instantaneous.  However, if there are an infinite number of singularities occurring at (or very close to) a single time, what tends to happen is that the earliest surgeries will not only remove the immediate singularities being formed, but will also pre-emptively eradicate a large number of potential future singularities (in particular, due to the removal of all the double <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-horns, which were not immediately singular but were threatening to become singular very shortly), thus keeping the surgery times discrete. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>This concludes the lecture notes on the Poincaré conjecture.  Have a good summer!</p>
]]></content:encoded>
</item>
<item>
<title><![CDATA[285G, Lecture 18: The structure of high-curvature regions of Ricci flow]]></title>
<link>http://terrytao.wordpress.com/2008/06/04/285g-lecture-18-the-structure-of-high-curvature-regions-of-ricci-flow/</link>
<pubDate>Wed, 04 Jun 2008 16:37:48 +0000</pubDate>
<dc:creator>Terence Tao</dc:creator>
<guid>http://terrytao.wordpress.com/2008/06/04/285g-lecture-18-the-structure-of-high-curvature-regions-of-ricci-flow/</guid>
<description><![CDATA[Having characterised the structure of -solutions, we now use them to describe the structure of high]]></description>
<content:encoded><![CDATA[<p>Having characterised the structure of <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions, we now use them to describe the structure of high curvature regions of Ricci flow, as promised back in <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/16/285g-lecture-12-high-curvature-regions-of-ricci-flow-and-%ce%ba-solutions/">Lecture 12</a>, in particular controlling their geometry and topology to the extent that surgery will be applied, which we will discuss in the next (and final) lecture of this class.</p>
<p>The material here is drawn largely from <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2334563">Morgan-Tian’s book</a> and Perelman&#8217;s <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0211159">first</a> and <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0303109">second</a> papers; see also <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0605667">Kleiner-Lott&#8217;s notes</a> and <a class="snap_noshots" href="http://arxiv.org/abs/math/0612069">Cao-Zhu&#8217;s paper</a> for closely related material.  Due to lack of time, some details here may be a little sketchy.</p>
<p><!--more--></p>
<p style="text-align:center;">&#8211; Canonical neighbourhoods &#8211;</p>
<p>Let us formally define the notions of a canonical neighbourhood that were introduced in Lecture 12.  They are associated with the various local geometries that are possible for three-dimensional <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions.  The first type of neighbourhood is related to the round spherical space forms <img src='http://s0.wp.com/latex.php?latex=S%5E3%2F%5CGamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^3/&#92;Gamma' title='S^3/&#92;Gamma' class='latex' />.</p>
<blockquote><p><strong>Definition 1.</strong> (<img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-round)  Let <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon &gt; 0' title='&#92;varepsilon &gt; 0' class='latex' />.  A compact connected 3-manifold <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g)' title='(M,g)' class='latex' /> is <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-round if one can identify M with a spherical space form <img src='http://s0.wp.com/latex.php?latex=S%5E3%2F%5CGamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^3/&#92;Gamma' title='S^3/&#92;Gamma' class='latex' /> with the constant curvature metric h such that some multiple of g lies within <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' /> of h in the <img src='http://s0.wp.com/latex.php?latex=C%5E%7B%5Clfloor+1%2F%5Cvarepsilon+%5Crfloor%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C^{&#92;lfloor 1/&#92;varepsilon &#92;rfloor}' title='C^{&#92;lfloor 1/&#92;varepsilon &#92;rfloor}' class='latex' /> topology.</p></blockquote>
<p>Note that if a sequence of manifolds <img src='http://s0.wp.com/latex.php?latex=%28M_n%2Cg_n%2Cp_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M_n,g_n,p_n)' title='(M_n,g_n,p_n)' class='latex' />, after rescaling, is converging geometrically to a spherical space form, then for any <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon &gt; 0' title='&#92;varepsilon &gt; 0' class='latex' /> such manifolds will be <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-round for sufficiently large n.</p>
<p>The next type of canonical neighbourhood is associated to the small compact manifolds from Proposition 9 of the <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/06/02/285g-lecture-17-the-structure-of-%ce%ba-solutions/">previous lecture</a>.</p>
<blockquote><p><strong>Definition 2.</strong> (C-component)  Let <img src='http://s0.wp.com/latex.php?latex=C+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C &gt; 0' title='C &gt; 0' class='latex' />.  A C-component is a connected 3-manifold <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g)' title='(M,g)' class='latex' /> homeomorphic to <img src='http://s0.wp.com/latex.php?latex=S%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^3' title='S^3' class='latex' /> or <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^3' title='&#92;Bbb{RP}^3' class='latex' />, such that after rescaling the metric by a constant, the sectional curvatures, diameter, and volume are bounded between 1/C and C, and first and second derivatives of the curvature are also bounded by C.</p></blockquote>
<p>[We have deviated slightly here from the definition in <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2334563">Morgan-Tian</a> by adding control of first and second derivatives for minor technical reasons.]</p>
<p>Thus, for instance, every compact <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution which is small but not round in the sense of Proposition 9 will be a C-component for some C.  Also observe that if a sequence of manifolds converge geometrically to a C-component, then these manifolds will be (say) 2C-components once one is sufficiently far along the sequence.</p>
<p>The remaining canonical neighbourhoods are incomplete, corresponding to portions of non-compact (or compact but large) <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions.  One of them is the <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-neck defined in Definition 1 of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/06/02/285g-lecture-17-the-structure-of-%ce%ba-solutions/">Lecture 17</a>.  The other is that of a cap.</p>
<blockquote><p><strong>Definition 3.</strong> (<img src='http://s0.wp.com/latex.php?latex=%28C%2C%5Cvarepsilon%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(C,&#92;varepsilon)' title='(C,&#92;varepsilon)' class='latex' />-cap)  Let <img src='http://s0.wp.com/latex.php?latex=C%2C+%5Cvarepsilon+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C, &#92;varepsilon &gt; 0' title='C, &#92;varepsilon &gt; 0' class='latex' />.  A <img src='http://s0.wp.com/latex.php?latex=%28C%2C%5Cvarepsilon%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(C,&#92;varepsilon)' title='(C,&#92;varepsilon)' class='latex' />-cap <img src='http://s0.wp.com/latex.php?latex=%28N+%5Ccup+Y%2C+g%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(N &#92;cup Y, g)' title='(N &#92;cup Y, g)' class='latex' /> is an incomplete 3-manifold that is the union of an <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-neck N with an incomplete core <img src='http://s0.wp.com/latex.php?latex=Y&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='Y' title='Y' class='latex' /> along one of the boundaries <img src='http://s0.wp.com/latex.php?latex=S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2' title='S^2' class='latex' /> of the neck N.  The core is homeomorphic to <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+R%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb R}^3' title='{&#92;Bbb R}^3' class='latex' /> or a punctured <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+RP%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb RP}^3' title='{&#92;Bbb RP}^3' class='latex' />, and has boundary <img src='http://s0.wp.com/latex.php?latex=S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2' title='S^2' class='latex' /> equal to the above boundary of N.  Furthermore, after rescaling g by a constant, the sectional curvatures, diameter, volume in the core are bounded between 1/C and C, and the zeroth, first and second derivatives of curvature in the cap are bounded above by C.</p></blockquote>
<blockquote><p><strong>Definition 4.</strong> (Canonical neighbourhood)  Let <img src='http://s0.wp.com/latex.php?latex=C%2C+%5Cvarepsilon+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C, &#92;varepsilon &gt; 0' title='C, &#92;varepsilon &gt; 0' class='latex' />. We say that a point x in a 3-manifold (M,g) (possibly disconnected) has a <em><img src='http://s0.wp.com/latex.php?latex=%28C%2C%5Cvarepsilon%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(C,&#92;varepsilon)' title='(C,&#92;varepsilon)' class='latex' />-canonical neighbourhood</em> if one of the following is true:</p>
<ol>
<li>x lies in an <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-round component of M.</li>
<li>x lies in a C-component of M.</li>
<li>x is the centre of an <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-neck in M.</li>
<li>x lies in the core of a <img src='http://s0.wp.com/latex.php?latex=%28C%2C%5Cvarepsilon%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(C,&#92;varepsilon)' title='(C,&#92;varepsilon)' class='latex' />-cap in M.</li>
</ol>
</blockquote>
<p>We remark that if a sequence of pointed manifolds <img src='http://s0.wp.com/latex.php?latex=%28M_n%2Cg_n%2Cx_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M_n,g_n,x_n)' title='(M_n,g_n,x_n)' class='latex' /> converges to a limit <img src='http://s0.wp.com/latex.php?latex=%28M_%5Cinfty%2Cg_%5Cinfty%2Cx_%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M_&#92;infty,g_&#92;infty,x_&#92;infty)' title='(M_&#92;infty,g_&#92;infty,x_&#92;infty)' class='latex' />, and <img src='http://s0.wp.com/latex.php?latex=x_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_&#92;infty' title='x_&#92;infty' class='latex' /> has a <img src='http://s0.wp.com/latex.php?latex=%28C%2C%5Cvarepsilon%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(C,&#92;varepsilon)' title='(C,&#92;varepsilon)' class='latex' />-neighbourhood of <img src='http://s0.wp.com/latex.php?latex=M_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M_&#92;infty' title='M_&#92;infty' class='latex' />, then for sufficiently large n, <img src='http://s0.wp.com/latex.php?latex=x_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_n' title='x_n' class='latex' /> has a <img src='http://s0.wp.com/latex.php?latex=%282C%2C2%5Cvarepsilon%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(2C,2&#92;varepsilon)' title='(2C,2&#92;varepsilon)' class='latex' />-neighbourhood (say) of <img src='http://s0.wp.com/latex.php?latex=M_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M_n' title='M_n' class='latex' />.  Also observe from construction that the property of having a canonical neighbourhood is scale-invariant.</p>
<p><strong>Exercise 1.</strong> (First derivatives of curvature) Show that if <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' /> is sufficiently small, and x has a <img src='http://s0.wp.com/latex.php?latex=%28C%2C%5Cvarepsilon%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(C,&#92;varepsilon)' title='(C,&#92;varepsilon)' class='latex' />-canonical neighbourhood, then R(x) is positive, <img src='http://s0.wp.com/latex.php?latex=%5Cnabla+R%28x%29+%3D+O_C%28+R%28x%29%5E%7B3%2F2%7D+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla R(x) = O_C( R(x)^{3/2} )' title='&#92;nabla R(x) = O_C( R(x)^{3/2} )' class='latex' />, and <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+R%28x%29+%3D+O_C%28+R%28x%29%5E2+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t R(x) = O_C( R(x)^2 )' title='&#92;partial_t R(x) = O_C( R(x)^2 )' class='latex' />. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>From the theory of the previous lecture we have</p>
<blockquote><p><strong>Proposition 1. </strong>For every <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon &gt; 0' title='&#92;varepsilon &gt; 0' class='latex' /> there exists <img src='http://s0.wp.com/latex.php?latex=C%26%2362%3B0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C&gt;0' title='C&gt;0' class='latex' /> such that every point in a 3-dimensional <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution at any given time will have a <img src='http://s0.wp.com/latex.php?latex=%28C%2C%5Cvarepsilon%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(C,&#92;varepsilon)' title='(C,&#92;varepsilon)' class='latex' />-canonical neighbourhood, unless it is a round shrinking <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+R%7D+%5Ctimes+%5CBbb%7BRP%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb R} &#92;times &#92;Bbb{RP}^2' title='{&#92;Bbb R} &#92;times &#92;Bbb{RP}^2' class='latex' />.</p></blockquote>
<p>Note that C and <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' /> are independent of <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />; this is thanks to the universality property (Proposition 5 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/06/02/285g-lecture-17-the-structure-of-%ce%ba-solutions/">Lecture 17</a>).</p>
<p><strong>Remark 1.</strong> For technical reasons, one actually needs a slightly stronger version of this proposition, in which any canonical neighbourhood which is an <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-neck is extended backwards to some extent in time in a manner that preserves the neck structure (leading to the notion of a <em>strong <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-neck</em> and <em>strong canonical neighbourhood</em>); see Chapter 9.8 of <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2334563">Morgan-Tian</a> for details. Technically, the results below need to be stated for strong canonical neighbourhoods <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>The objective of this lecture is to establish the analogous claim for high-curvature regions of arbitrary Ricci flows:</p>
<blockquote><p><strong>Theorem 1.</strong> (Structure of high-curvature regions) For every <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon &gt; 0' title='&#92;varepsilon &gt; 0' class='latex' /> there exists <img src='http://s0.wp.com/latex.php?latex=C+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C &gt; 0' title='C &gt; 0' class='latex' /> such that the following holds.  Let <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g)' title='t &#92;mapsto (M,g)' class='latex' /> be a three-dimensional compact Ricci flow on some time interval [0,T) with no embedded <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+RP%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb RP}^2' title='{&#92;Bbb RP}^2' class='latex' /> with trivial normal bundle.  Then there exists <img src='http://s0.wp.com/latex.php?latex=K+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='K &gt; 0' title='K &gt; 0' class='latex' /> such for every time <img src='http://s0.wp.com/latex.php?latex=t+%5Cin+%5B0%2CT%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;in [0,T)' title='t &#92;in [0,T)' class='latex' />, every <img src='http://s0.wp.com/latex.php?latex=x+%5Cin+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x &#92;in (M,g(t))' title='x &#92;in (M,g(t))' class='latex' /> with <img src='http://s0.wp.com/latex.php?latex=R%28x%29+%5Cgeq+K&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(x) &#92;geq K' title='R(x) &#92;geq K' class='latex' /> has a <img src='http://s0.wp.com/latex.php?latex=%28C%2C%5Cvarepsilon%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(C,&#92;varepsilon)' title='(C,&#92;varepsilon)' class='latex' />-canonical neighbourhood.</p></blockquote>
<p style="text-align:left;">This theorem will then allow us to perform surgery on Ricci flows, as we will discuss in the final lecture.</p>
<p style="text-align:left;">Morally speaking, Theorem 1 follows from Proposition 1 by rescaling and compactness arguments, but there is a rather delicate issue involved, namely to gain enough control on curvature at points in spacetime both near (and far) from the chosen point (t,x) that the Hamilton compactness theorem can be applied.</p>
<p style="text-align:center;">-- Overview of proof --</p>
<p>We begin with some reductions.  We can of course take M to be connected.  Fix <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />, and take C sufficiently large depending on <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' /> (but not depending on any other parameters).  We first observe that it suffices to prove the theorem for closed intervals [0,T] rather than half-open ones, as long as the bounds on K depend only on an upper bound <img src='http://s0.wp.com/latex.php?latex=T_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='T_0' title='T_0' class='latex' /> on T and the initial metric g(0) and not on T itself (in particular, one cannot just use the trivial fact that R will be bounded on any compact subset of spacetime such as <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5B0%2CT%5D+%5Ctimes+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[0,T] &#92;times M' title='{}[0,T] &#92;times M' class='latex' />.)  Once one does this, one sees that Theorem 1 is now true for some enormous K that depends on T; the task is to get a uniform K that depends only on the initial metric g(0) and on an upper bound <img src='http://s0.wp.com/latex.php?latex=T_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='T_0' title='T_0' class='latex' /> for T.</p>
<p>Perelman&#8217;s argument proceeds by a downward induction on K; assume that K is large (depending on g(0) and <img src='http://s0.wp.com/latex.php?latex=T_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='T_0' title='T_0' class='latex' />), and that Theorem 1 has already been established for 4K (say); and then establish the claim for K.  By the previous discussion, this conditional result will in fact imply the full theorem.</p>
<p>By rescaling we may assume that g(0) has normalised initial conditions (curvature bounded in magnitude by 1, volume of unit balls bounded below by some positive constant <img src='http://s0.wp.com/latex.php?latex=%5Comega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;omega' title='&#92;omega' class='latex' />).  We will now show that the conditional version of Theorem 1 holds for K sufficiently large depending only on <img src='http://s0.wp.com/latex.php?latex=%5Comega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;omega' title='&#92;omega' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=T_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='T_0' title='T_0' class='latex' />.</p>
<p>Suppose this were not the case.  Then there would be a <img src='http://s0.wp.com/latex.php?latex=%5Comega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;omega' title='&#92;omega' class='latex' /> and a <img src='http://s0.wp.com/latex.php?latex=T_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='T_0' title='T_0' class='latex' />, and a sequence <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M_n%2C+g_n%28t%29%2C+x_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M_n, g_n(t), x_n)' title='t &#92;mapsto (M_n, g_n(t), x_n)' class='latex' /> of pointed Ricci flows on <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5B0%2CT_n%5D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[0,T_n]' title='{}[0,T_n]' class='latex' /> (not containing any embedded <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^2' title='&#92;Bbb{RP}^2' class='latex' /> with trivial normal bundle) for some <img src='http://s0.wp.com/latex.php?latex=0+%5Cleq+T_n+%5Cleq+T_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &#92;leq T_n &#92;leq T_0' title='0 &#92;leq T_n &#92;leq T_0' class='latex' /> with normalised initial conditions with constant <img src='http://s0.wp.com/latex.php?latex=%5Comega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;omega' title='&#92;omega' class='latex' />, times <img src='http://s0.wp.com/latex.php?latex=t_n+%5Cin+%5B0%2CT_n%5D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_n &#92;in [0,T_n]' title='t_n &#92;in [0,T_n]' class='latex' />, and scalars <img src='http://s0.wp.com/latex.php?latex=K_n+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='K_n &#92;to &#92;infty' title='K_n &#92;to &#92;infty' class='latex' /> such that every point in <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5B0%2CT_n%5D+%5Ctimes+M_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[0,T_n] &#92;times M_n' title='{}[0,T_n] &#92;times M_n' class='latex' /> of scalar curvature at least 4K_n has a <img src='http://s0.wp.com/latex.php?latex=%28C%2C%5Cvarepsilon%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(C,&#92;varepsilon)' title='(C,&#92;varepsilon)' class='latex' />-canonical neighbourhood, but that <img src='http://s0.wp.com/latex.php?latex=R_n%28t_n%2Cx_n%29+%5Cgeq+K_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R_n(t_n,x_n) &#92;geq K_n' title='R_n(t_n,x_n) &#92;geq K_n' class='latex' /> but does not have a <img src='http://s0.wp.com/latex.php?latex=%28C%2C%5Cvarepsilon%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(C,&#92;varepsilon)' title='(C,&#92;varepsilon)' class='latex' />-canonical neighbourhood (in particular, <img src='http://s0.wp.com/latex.php?latex=R_n%28t_n%2Cx_n%29+%26%2360%3B+4+K_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R_n(t_n,x_n) &lt; 4 K_n' title='R_n(t_n,x_n) &lt; 4 K_n' class='latex' />).  We want to extract a contradiction from this.</p>
<p>From the local theory (Lemma 1 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/14/285g-lecture-11-%ce%ba-noncollapsing-via-perelman-reduced-volume/">Lecture 11</a>) we know that the curvature is bounded for short times (t less than a universal constant depending only on <img src='http://s0.wp.com/latex.php?latex=%5Comega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;omega' title='&#92;omega' class='latex' />), so <img src='http://s0.wp.com/latex.php?latex=t_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_n' title='t_n' class='latex' /> must be bounded uniformly from below.</p>
<p>As usual, we define the rescaled pointed flows <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28%5Ctilde+M_n%2C+%5Ctilde+g_n%28t%29%2C+%5Ctilde+x_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (&#92;tilde M_n, &#92;tilde g_n(t), &#92;tilde x_n)' title='t &#92;mapsto (&#92;tilde M_n, &#92;tilde g_n(t), &#92;tilde x_n)' class='latex' /> by <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+M_n+%3A%3D+M_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde M_n := M_n' title='&#92;tilde M_n := M_n' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+x_n+%3A%3D+x_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde x_n := x_n' title='&#92;tilde x_n := x_n' class='latex' />, and <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+g_n%28t%29+%3A%3D+K_n%5E2+g_n%28+t_n+%2B+K_n%5E%7B-2%7D+t+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde g_n(t) := K_n^2 g_n( t_n + K_n^{-2} t )' title='&#92;tilde g_n(t) := K_n^2 g_n( t_n + K_n^{-2} t )' class='latex' />.  Thus these flows are increasingly ancient and have scalar curvature between 1 and 4 at the origin <img src='http://s0.wp.com/latex.php?latex=%280%2C%5Ctilde+x_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(0,&#92;tilde x_n)' title='(0,&#92;tilde x_n)' class='latex' />.  Also, any point in these flows of curvature at least 4 is contained in a canonical neighbourhood.</p>
<p style="text-align:left;">By Perelman&#8217;s non-collapsing theorem (<a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/20/285g-lecture-7-rescaling-of-ricci-flows-and-kappa-noncollapsing/">Theorem 2</a> from Lecture 7), we know that the flows <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M_n%2C+g_n%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M_n, g_n(t))' title='t &#92;mapsto (M_n, g_n(t))' class='latex' /> flow is <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsed at all scales less than 1 (say) for some <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' /> depending only on <img src='http://s0.wp.com/latex.php?latex=%5Comega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;omega' title='&#92;omega' class='latex' />; by rescaling, the rescaled flows <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28%5Ctilde+M_n%2C+%5Ctilde+g_n%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (&#92;tilde M_n, &#92;tilde g_n(t))' title='t &#92;mapsto (&#92;tilde M_n, &#92;tilde g_n(t))' class='latex' /> are then <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsed at all scales less than 1/o(1).</p>
<p>Meanwhile, from the Hamilton-Ivey pinching theorem (Theorem 1 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/04/285g-lecture-3-the-maximum-principle-and-the-pinching-phenomenon/">Lecture 3</a>) we have <img src='http://s0.wp.com/latex.php?latex=R_n+%5Cgeq+-O%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R_n &#92;geq -O(1)' title='R_n &#92;geq -O(1)' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRiem%7D_n+%5Cgeq+-o%28+R_n+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Riem}_n &#92;geq -o( R_n )' title='&#92;hbox{Riem}_n &#92;geq -o( R_n )' class='latex' /> whenever <img src='http://s0.wp.com/latex.php?latex=R_n+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R_n &#92;to &#92;infty' title='R_n &#92;to &#92;infty' class='latex' />.  Rescaling this, we obtain <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+R_n+%5Cgeq+-o%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde R_n &#92;geq -o(1)' title='&#92;tilde R_n &#92;geq -o(1)' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Cwidetilde%7B%5Chbox%7BRiem%7D%7D_n+%5Cgeq+-o%28+1+%2B+%26%23124%3B%5Ctilde+R_n%26%23124%3B+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;widetilde{&#92;hbox{Riem}}_n &#92;geq -o( 1 + &#124;&#92;tilde R_n&#124; )' title='&#92;widetilde{&#92;hbox{Riem}}_n &#92;geq -o( 1 + &#124;&#92;tilde R_n&#124; )' class='latex' />.</p>
<p>Suppose we were able to prove the following statement.</p>
<blockquote><p><strong>Proposition 2. </strong>(Asymptotically globally bounded normalised curvature) For any <img src='http://s0.wp.com/latex.php?latex=A%2C%5Ctau+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='A,&#92;tau &gt; 0' title='A,&#92;tau &gt; 0' class='latex' /> we have a bound <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+R_n%28+t%2C+x+%29+%3D+O_%7BC%2C%5Cvarepsilon%7D%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde R_n( t, x ) = O_{C,&#92;varepsilon}(1)' title='&#92;tilde R_n( t, x ) = O_{C,&#92;varepsilon}(1)' class='latex' /> for all <img src='http://s0.wp.com/latex.php?latex=x+%5Cin+B_%7B%5Ctilde+g_n%280%29%7D%28%5Ctilde+x_n%2C+A%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x &#92;in B_{&#92;tilde g_n(0)}(&#92;tilde x_n, A)' title='x &#92;in B_{&#92;tilde g_n(0)}(&#92;tilde x_n, A)' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=t+%5Cin+%5B-%5Ctau%2C0%5D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;in [-&#92;tau,0]' title='t &#92;in [-&#92;tau,0]' class='latex' />, if n is sufficiently large depending on <img src='http://s0.wp.com/latex.php?latex=A%2C%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='A,&#92;tau' title='A,&#92;tau' class='latex' />.</p></blockquote>
<p>From this and the <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsing, we see that the Hamilton compactness theorem (Theorem 2 from Lecture 15) applies, and after passing to a subsequence we see that the pointed flows <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28%5Ctilde+M_n%2C+%5Ctilde+g_n%28t%29%2C+%5Ctilde+x_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (&#92;tilde M_n, &#92;tilde g_n(t), &#92;tilde x_n)' title='t &#92;mapsto (&#92;tilde M_n, &#92;tilde g_n(t), &#92;tilde x_n)' class='latex' /> converges geometrically to a Ricci flow <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M_%5Cinfty%2C+g_%5Cinfty%2C+x_%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M_&#92;infty, g_&#92;infty, x_&#92;infty)' title='t &#92;mapsto (M_&#92;infty, g_&#92;infty, x_&#92;infty)' class='latex' /> which has bounded scalar curvature on <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5B-%5Ctau%2C0%5D+%5Ctimes+M_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[-&#92;tau,0] &#92;times M_&#92;infty' title='{}[-&#92;tau,0] &#92;times M_&#92;infty' class='latex' /> for each <img src='http://s0.wp.com/latex.php?latex=%5Ctau+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau &gt; 0' title='&#92;tau &gt; 0' class='latex' />, and is automatically connected, complete, and ancient, and without an embedded <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^2' title='&#92;Bbb{RP}^2' class='latex' /> with trivial normal bundle.    From pinching we also see that we have non-negative sectional curvature; from the <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsing of the flows <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28%5Ctilde+M_n%2C+%5Ctilde+g_n%28t%29%2C+%5Ctilde+x_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (&#92;tilde M_n, &#92;tilde g_n(t), &#92;tilde x_n)' title='t &#92;mapsto (&#92;tilde M_n, &#92;tilde g_n(t), &#92;tilde x_n)' class='latex' /> we have <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsing of the limiting flow <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M_%5Cinfty%2C+g_%5Cinfty%2C+x_%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M_&#92;infty, g_&#92;infty, x_&#92;infty)' title='t &#92;mapsto (M_&#92;infty, g_&#92;infty, x_&#92;infty)' class='latex' />.  From Hamilton&#8217;s Harnack inequality (cf. <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/19/285g-lecture-13-li-yau-hamilton-harnack-inequalities-and-%ce%ba-solutions/">Lecture 13</a>) we can show <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+R+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t R &#92;geq 0' title='&#92;partial_t R &#92;geq 0' class='latex' />, and so we in fact have globally bounded curvature. Finally, since <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+R_n%280%2C+%5Ctilde+x_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde R_n(0, &#92;tilde x_n)' title='&#92;tilde R_n(0, &#92;tilde x_n)' class='latex' /> is bounded between 1 and 4, so is <img src='http://s0.wp.com/latex.php?latex=R_%5Cinfty%280%2Cx_%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R_&#92;infty(0,x_&#92;infty)' title='R_&#92;infty(0,x_&#92;infty)' class='latex' />; thus the flow is not flat.  Putting all this together, we conclude that <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M_%5Cinfty%2C+g_%5Cinfty%2C+x_%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M_&#92;infty, g_&#92;infty, x_&#92;infty)' title='t &#92;mapsto (M_&#92;infty, g_&#92;infty, x_&#92;infty)' class='latex' /> is a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution (see Definition 1 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/16/285g-lecture-12-high-curvature-regions-of-ricci-flow-and-%ce%ba-solutions/">Lecture 12</a>).  From Proposition 1, <img src='http://s0.wp.com/latex.php?latex=%280%2Cx_%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(0,x_&#92;infty)' title='(0,x_&#92;infty)' class='latex' /> has a <img src='http://s0.wp.com/latex.php?latex=%28C%2F2%2C%5Cvarepsilon%2F2%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(C/2,&#92;varepsilon/2)' title='(C/2,&#92;varepsilon/2)' class='latex' />-canonical neighbourhood in <img src='http://s0.wp.com/latex.php?latex=M_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M_&#92;infty' title='M_&#92;infty' class='latex' /> (if C is chosen large enough depending on <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />); thus <img src='http://s0.wp.com/latex.php?latex=%280%2C%5Ctilde+x_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(0,&#92;tilde x_n)' title='(0,&#92;tilde x_n)' class='latex' /> will have a <img src='http://s0.wp.com/latex.php?latex=%28C%2C%5Cvarepsilon%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(C,&#92;varepsilon)' title='(C,&#92;varepsilon)' class='latex' />-canonical neighbourhood in <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+M_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde M_n' title='&#92;tilde M_n' class='latex' /> for large enough n, and so by rescaling <img src='http://s0.wp.com/latex.php?latex=%280%2Cx_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(0,x_n)' title='(0,x_n)' class='latex' /> has a <img src='http://s0.wp.com/latex.php?latex=%28C%2C%5Cvarepsilon%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(C,&#92;varepsilon)' title='(C,&#92;varepsilon)' class='latex' />-canonical neighbourhood in <img src='http://s0.wp.com/latex.php?latex=M_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M_n' title='M_n' class='latex' />, contradicting the hypothesis, and we are done.</p>
<p>So it remains to prove Proposition 2.  If we had the luxury of picking <img src='http://s0.wp.com/latex.php?latex=%28t_n%2Cx_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_n,x_n)' title='(t_n,x_n)' class='latex' /> to be a point which had maximal curvature amongst all other points in <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5B0%2Ct_n%5D+%5Ctimes+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[0,t_n] &#92;times M' title='{}[0,t_n] &#92;times M' class='latex' />, then this proposition would be automatic.  However, we do not have this luxury (roughly speaking, this would only let us get canonical neighbourhoods for the &#8220;highest curvature region&#8221; of the Ricci flow, leaving aside the &#8220;second highest curvature region&#8221;, &#8220;third highest curvature region&#8221;, etc., unprepared for surgery).  So one has to work significantly harder to achieve this aim.</p>
<p style="text-align:center;">&#8211; Bounded curvature at bounded distance &#8211;</p>
<p>A key step in the execution of Proposition 2 is the following partial result, in which the bound on curvature is allowed to depend on A, and for which one cannot go backwards in time.</p>
<blockquote><p><strong>Proposition 3. </strong> (Bounded curvature at bounded distance)  For any A &#62; 0 we have a bound <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+R_n%28+0%2C+x+%29+%3D+O_%7BC%2C%5Cvarepsilon%2CA%7D%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde R_n( 0, x ) = O_{C,&#92;varepsilon,A}(1)' title='&#92;tilde R_n( 0, x ) = O_{C,&#92;varepsilon,A}(1)' class='latex' /> for all <img src='http://s0.wp.com/latex.php?latex=x+%5Cin+B_%7B%5Ctilde+g_n%280%29%7D%28%5Ctilde+x_n%2C+A%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x &#92;in B_{&#92;tilde g_n(0)}(&#92;tilde x_n, A)' title='x &#92;in B_{&#92;tilde g_n(0)}(&#92;tilde x_n, A)' class='latex' />, if n is large enough depending on A.</p></blockquote>
<p>This partial result is already rather tricky; we sketch the proof as follows (full details can be found in Chapter 10 of <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2334563">Morgan-Tian</a>, Section 51 of <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0605667">Kleiner-Lott</a>, or Section 7.1 of <a class="snap_noshots" href="http://arxiv.org/abs/math/0612069">Cao-Zhu</a>).  If this result failed, then we have a sequence <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+y_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde y_n' title='&#92;tilde y_n' class='latex' /> with <img src='http://s0.wp.com/latex.php?latex=d_%7B%5Ctilde+g_n%280%29%7D%28x_n%2Cy_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d_{&#92;tilde g_n(0)}(x_n,y_n)' title='d_{&#92;tilde g_n(0)}(x_n,y_n)' class='latex' /> bounded and <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+R_n%280%2C%5Ctilde+y_n%29+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde R_n(0,&#92;tilde y_n) &#92;to &#92;infty' title='&#92;tilde R_n(0,&#92;tilde y_n) &#92;to &#92;infty' class='latex' />, thus one can move a bounded distance along a minimising geodesic from <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+x_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde x_n' title='&#92;tilde x_n' class='latex' /> (which has curvature between 1 and 4) to <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+y_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde y_n' title='&#92;tilde y_n' class='latex' /> and reach a point of arbitrarily high curvature.   On the other hand, we know that every point of curvature at least 4 has a canonical neighbourhood.  Thus there is a bounded length minimising geodesic in <img src='http://s0.wp.com/latex.php?latex=%28%5Ctilde+M_n%2C+%5Ctilde+g_n%280%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;tilde M_n, &#92;tilde g_n(0))' title='(&#92;tilde M_n, &#92;tilde g_n(0))' class='latex' /> that goes entirely through canonical neighbourhoods, starts with scalar curvature 4, and ends up with arbitrarily high curvature, with curvature staying 4 or greater throughout this process.  This cannot happen if the canonical neighbourhoods are <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-round or C-components (since these neighhourhoods are already complete and curvatures are comparable to each other on the entire neighbourhood), so this geodesic can only go through <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-necks and <img src='http://s0.wp.com/latex.php?latex=%28C%2C%5Cvarepsilon%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(C,&#92;varepsilon)' title='(C,&#92;varepsilon)' class='latex' />-caps.  One can also rule out the latter possibility (a long geodesic path that goes through the core of a <img src='http://s0.wp.com/latex.php?latex=%28C%2C%5Cvarepsilon%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(C,&#92;varepsilon)' title='(C,&#92;varepsilon)' class='latex' />-cap can easily be shown to not be minimising); thus the geodesic is simply going through a tube of <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-necks, with the width of these necks starting off being comparable to 1 and ending up being arbitrarily small.  It turns out that by using a version of Hamilton&#8217;s compactness theorem for incomplete Ricci flows, one can take a limit, which at time zero is a tube (topologically <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5B0%2C1%5D+%5Ctimes+S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[0,1] &#92;times S^2' title='{}[0,1] &#92;times S^2' class='latex' />) of non-negative curvature in which the curvature has become infinite at one end.  Also, thanks to time derivative control on the curvature (see Exercise 1), the tube can be extended a little bit backwards in time  as an incomplete Ricci flow (though the amount to which one can do this shrinks to zero as one approaches the infinite curvature end of the tube).</p>
<p>One can show that as one approaches the infinite curvature end of the cylinder and rescales, the cylinder increasingly resembles a cone.  (For instance, one can use the bound <img src='http://s0.wp.com/latex.php?latex=%5Cint_%5Cgamma+%5Chbox%7BRic%7D%28X%2CX%29+%3D+O%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_&#92;gamma &#92;hbox{Ric}(X,X) = O(1)' title='&#92;int_&#92;gamma &#92;hbox{Ric}(X,X) = O(1)' class='latex' /> from Lemma 1 of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/27/285g-lecture-15-geometric-limits-of-ricci-flows-and-asymptotic-gradient-shrinking-solitons/">Lecture 15</a>, where <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' /> are geodesics emanating from the infinite curvature end, to establish this sort of thing.) By taking another limit one can then get an incomplete Ricci flow which at time zero is a cone.  Because curvature is bounded away from zero, this cone is not flat.  At this point, a version of Hamilton&#8217;s splitting theorem (Proposition 1 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/19/285g-lecture-13-li-yau-hamilton-harnack-inequalities-and-%ce%ba-solutions/">Lecture 13</a>) for incomplete flows asserts that the manifold locally splits as the product of a line and a two-dimensional manifold.  But non-flat cones cannot split like this, a contradiction.  This establishes Proposition 3.</p>
<p><strong>Remark 2. </strong>More generally, this argument can be used to show that if <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+R_n%28t%2Cx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde R_n(t,x)' title='&#92;tilde R_n(t,x)' class='latex' /> is bounded by some <img src='http://s0.wp.com/latex.php?latex=L+%5Cgeq+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='L &#92;geq 1' title='L &#92;geq 1' class='latex' />, then <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+R_n%28t%2Cy%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde R_n(t,y)' title='&#92;tilde R_n(t,y)' class='latex' /> is bounded by <img src='http://s0.wp.com/latex.php?latex=O_%7BA%2CC%2C%5Cvarepsilon%7D%28L%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='O_{A,C,&#92;varepsilon}(L)' title='O_{A,C,&#92;varepsilon}(L)' class='latex' /> for all <img src='http://s0.wp.com/latex.php?latex=y+%5Cin+B_%7B%5Ctilde+g_n%28t%29%7D%28x%2CA+L%5E%7B-1%2F2%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y &#92;in B_{&#92;tilde g_n(t)}(x,A L^{-1/2})' title='y &#92;in B_{&#92;tilde g_n(t)}(x,A L^{-1/2})' class='latex' />. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:center;">&#8211; Bounded curvature at all distances &#8211;</p>
<p>Now we extend Proposition 3 by making the bound global in A:</p>
<blockquote><p><strong>Proposition 4. </strong> (Bounded curvature at all distances)  For any A &#62; 0 we have a bound <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+R_n%28+0%2C+x+%29+%3D+O_%7BC%2C%5Cvarepsilon%7D%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde R_n( 0, x ) = O_{C,&#92;varepsilon}(1)' title='&#92;tilde R_n( 0, x ) = O_{C,&#92;varepsilon}(1)' class='latex' /> for all <img src='http://s0.wp.com/latex.php?latex=x+%5Cin+B_%7B%5Ctilde+g_n%280%29%7D%28%5Ctilde+x_n%2C+A%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x &#92;in B_{&#92;tilde g_n(0)}(&#92;tilde x_n, A)' title='x &#92;in B_{&#92;tilde g_n(0)}(&#92;tilde x_n, A)' class='latex' />, if n is large enough depending on A.</p></blockquote>
<p>We sketch a proof as follows.  From Proposition 3 and compactness (taking advantage of non-collapsing, of course) we already know (passing to a subsequence if necessary) that <img src='http://s0.wp.com/latex.php?latex=%28%5Ctilde+M_n%2C+%5Ctilde+g_n%280%29%2C+x_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;tilde M_n, &#92;tilde g_n(0), x_n)' title='(&#92;tilde M_n, &#92;tilde g_n(0), x_n)' class='latex' /> converges to some  limit<br />
<img src='http://s0.wp.com/latex.php?latex=%28%5Ctilde+M_%5Cinfty%2C+%5Ctilde+g_%5Cinfty%280%29%2C+x_%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;tilde M_&#92;infty, &#92;tilde g_&#92;infty(0), x_&#92;infty)' title='(&#92;tilde M_&#92;infty, &#92;tilde g_&#92;infty(0), x_&#92;infty)' class='latex' /> which has non-negative curvature; it can also be extended a little bit backwards in time as an incomplete Ricci flow.  Also, every point in this limit of curvature greater than 4 has a canonical neighbourhood.  Our task is to basically to show that <img src='http://s0.wp.com/latex.php?latex=%28%5Ctilde+M_%5Cinfty%2C+%5Ctilde+g_%5Cinfty%280%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;tilde M_&#92;infty, &#92;tilde g_&#92;infty(0))' title='(&#92;tilde M_&#92;infty, &#92;tilde g_&#92;infty(0))' class='latex' /> has bounded curvature.  If this is not the case, then there are points of arbitrarily high curvature, which must be contained in either <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-necks or <img src='http://s0.wp.com/latex.php?latex=%28C%2C%5Cvarepsilon%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(C,&#92;varepsilon)' title='(C,&#92;varepsilon)' class='latex' />-caps.  We conclude that there exist arbitrarily narrow <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-necks.  One can then show that the manifold had strictly positive curvature, since otherwise by Hamilton&#8217;s splitting theorem the manifold would split locally into a product of a two-dimensional manifold and a line, which can be shown to be incompatible with having arbitrarily narrow necks.</p>
<p>At this point one uses a general result that complete manifolds of strictly positive curvature cannot have arbitrarily narrow necks. We sketch the proof as follows.  Clearly we may assume the manifold is compact, and hence by the <a href="http://en.wikipedia.org/wiki/Soul_theorem">soul theorem</a> is diffeomorphic to <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+R%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb R}^3' title='{&#92;Bbb R}^3' class='latex' />.  This implies that every neck in fact separates the manifold into a compact part and a non-compact part.  In fact, one can show that if p is a soul for the manifold, then there is a minimising geodesic <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%3A+%5B0%2C%2B%5Cinfty%29+%5Cto+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma: [0,+&#92;infty) &#92;to M' title='&#92;gamma: [0,+&#92;infty) &#92;to M' class='latex' /> from p to infinity that passes through all the necks.  But if one then considers the Busemann function <img src='http://s0.wp.com/latex.php?latex=B%28y%29+%3A%3D+%5Clim_%7Bs+%5Cto+%5Cinfty%7D+d%28y%2C%5Cgamma%28s%29%29+-+s&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B(y) := &#92;lim_{s &#92;to &#92;infty} d(y,&#92;gamma(s)) - s' title='B(y) := &#92;lim_{s &#92;to &#92;infty} d(y,&#92;gamma(s)) - s' class='latex' />, one can show that the gradient field <img src='http://s0.wp.com/latex.php?latex=%5Cnabla+B&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla B' title='&#92;nabla B' class='latex' /> is a unit vector which is within <img src='http://s0.wp.com/latex.php?latex=O%28%5Cvarepsilon%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='O(&#92;varepsilon)' title='O(&#92;varepsilon)' class='latex' /> to parallel to the necks.  This, combined with Stokes theorem, tells us that the area of the level sets of B inside a neck (which, up to errors of <img src='http://s0.wp.com/latex.php?latex=O%28%5Cvarepsilon%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='O(&#92;varepsilon)' title='O(&#92;varepsilon)' class='latex' />, are basically slices of that neck) does not fluctuate by more than <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />, even as one compares very distant necks together.   But this contradicts the assumption that there are arbitrarily small necks.  (For full details see Proposition 2.19 of <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2334563">Morgan-Tian</a>.  )</p>
<p style="text-align:center;">&#8211; Bounded curvature at all times &#8211;</p>
<p>Now we need to extend Proposition 4 backwards in time.  The time derivative bound on curvature (Exercise 1) lets us extend backwards by some fixed amount of time, but at the cost of potentially increasing the curvature, and we cannot simply iterate this (much as one cannot iterate a local existence result for a PDE to obtain a global one without some sort of <em>a priori</em> bound on whatever is controlling the time of existence).  But what Exercise 1 does let us do, is reduce matters to establishing an <em>a priori</em> bound:</p>
<blockquote><p><strong>Proposition 5. </strong> (A priori bound)  Let <img src='http://s0.wp.com/latex.php?latex=%5Ctau+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau &gt; 0' title='&#92;tau &gt; 0' class='latex' />, and suppose <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+R_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde R_n' title='&#92;tilde R_n' class='latex' /> is uniformly bounded on <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5B-%5Ctau%2C0%5D+%5Ctimes+%5Ctilde+M_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[-&#92;tau,0] &#92;times &#92;tilde M_n' title='{}[-&#92;tau,0] &#92;times &#92;tilde M_n' class='latex' /> for all sufficiently large n.  Then in fact we can bound <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+R_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde R_n' title='&#92;tilde R_n' class='latex' /> on these slabs by a universal bound <img src='http://s0.wp.com/latex.php?latex=O_%7BC%2C%5Cvarepsilon%2C%5Ctau%7D%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='O_{C,&#92;varepsilon,&#92;tau}(1)' title='O_{C,&#92;varepsilon,&#92;tau}(1)' class='latex' /> (not depending on the previous universal bound).</p></blockquote>
<p>Indeed, Exercise 1 then lets us extend the uniform bounds a little bit to the past of <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' />, and one can continue this procedure indefinitely to establish Proposition 2.</p>
<p>We sketch the proof as follows.  We allow all implied constants to depend on <img src='http://s0.wp.com/latex.php?latex=C%2C+%5Cvarepsilon%2C+%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C, &#92;varepsilon, &#92;tau' title='C, &#92;varepsilon, &#92;tau' class='latex' /> for brevity.  The bounds are already enough to give a non-ancient limiting flow <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M_%5Cinfty%2C+g_%5Cinfty%28t%29%2C+x_%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M_&#92;infty, g_&#92;infty(t), x_&#92;infty)' title='t &#92;mapsto (M_&#92;infty, g_&#92;infty(t), x_&#92;infty)' class='latex' /> on <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5B-%5Ctau%2C0%5D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[-&#92;tau,0]' title='{}[-&#92;tau,0]' class='latex' /> which is complete, connected, and non-negative curvature which is bounded at all times (but with an unspecified bound), and bounded at time zero by <img src='http://s0.wp.com/latex.php?latex=O%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='O(1)' title='O(1)' class='latex' />.  Also, every point with curvature greater than 4 is known to have a canonical neighbourhood.  The challenge is now to propagate the quantitative curvature bounds backwards in time, to replace the qualitative bound.</p>
<p>In the case of an ancient flow of non-negative curvature, Hamilton&#8217;s Harnack inequality (equation (29) from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/19/285g-lecture-13-li-yau-hamilton-harnack-inequalities-and-%ce%ba-solutions/">Lecture 13</a>) gives <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+R+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t R &#92;geq 0' title='&#92;partial_t R &#92;geq 0' class='latex' />, which automatically does this propagation for us.  We are however non-ancient here, and the Harnack inequality in this setting only gives a bound of the form <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+R+%5Cgeq+R+%2F+%28t%2B%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t R &#92;geq R / (t+&#92;tau)' title='&#92;partial_t R &#92;geq R / (t+&#92;tau)' class='latex' />.  This can be integrated to give <img src='http://s0.wp.com/latex.php?latex=R%28t%2Cx%29+%3D+O%28+1+%2F+%28t%2B%5Ctau%29+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(t,x) = O( 1 / (t+&#92;tau) )' title='R(t,x) = O( 1 / (t+&#92;tau) )' class='latex' />, thus our bounds blow up as we approach <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' />.  However, this is at least enough to get good control on distances; in particular, using Corollary 1 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/27/285g-lecture-15-geometric-limits-of-ricci-flows-and-asymptotic-gradient-shrinking-solitons/">Lecture 15</a> we see that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=-+O%28+%5Cfrac%7B1%7D%7B%5Csqrt%7Bt%2B%5Ctau%7D%7D+%29+%5Cleq+%5Cfrac%7Bd%7D%7Bdt%7D+d_%7Bg%28t%29%7D%28x%2Cy%29+%5Cleq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='- O( &#92;frac{1}{&#92;sqrt{t+&#92;tau}} ) &#92;leq &#92;frac{d}{dt} d_{g(t)}(x,y) &#92;leq 0' title='- O( &#92;frac{1}{&#92;sqrt{t+&#92;tau}} ) &#92;leq &#92;frac{d}{dt} d_{g(t)}(x,y) &#92;leq 0' class='latex' /> (1)</p>
<p>for all <img src='http://s0.wp.com/latex.php?latex=x%2Cy+%5Cin+M_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x,y &#92;in M_&#92;infty' title='x,y &#92;in M_&#92;infty' class='latex' />. Fortunately, the left-hand side here is absolutely integrable, and so we obtain a useful global distance comparison estimate:</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=d_%7Bg%280%29%7D%28x%2Cy%29+-+O%281%29+%5Cleq+d_%7Bg%28t%29%7D%28x%2Cy%29+%5Cleq+d_%7Bg%280%29%7D%28x%2Cy%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d_{g(0)}(x,y) - O(1) &#92;leq d_{g(t)}(x,y) &#92;leq d_{g(0)}(x,y)' title='d_{g(0)}(x,y) - O(1) &#92;leq d_{g(t)}(x,y) &#92;leq d_{g(0)}(x,y)' class='latex' />. (2)</p>
<p style="text-align:left;">To use this, pick a large curvature <img src='http://s0.wp.com/latex.php?latex=L+%5Cge+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='L &#92;ge 1' title='L &#92;ge 1' class='latex' />, then a much larger radius r, then an extremely large curvature L&#8217;.  Now suppose for contradiction that we have a point (t,x) in <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5B%5Ctau%2C0%5D+%5Ctimes+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[&#92;tau,0] &#92;times M' title='{}[&#92;tau,0] &#92;times M' class='latex' /> of curvature larger than L&#8217;.  This point is then contained in a canonical neighbourhood.  This neighbourhood cannot be compact (i.e. an <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-round or C-component), since that would mean that the<br />
minimal scalar curvature <img src='http://s0.wp.com/latex.php?latex=R_%7B%5Cmin%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R_{&#92;min}' title='R_{&#92;min}' class='latex' /> was comparable to L&#8217; at time t, which by monotonicity of <img src='http://s0.wp.com/latex.php?latex=R_%7B%5Cmin%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R_{&#92;min}' title='R_{&#92;min}' class='latex' /> (Proposition 2 of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/04/285g-lecture-3-the-maximum-principle-and-the-pinching-phenomenon/">Lecture 3</a>) would mean that the scalar curvature is comparable to L&#8217; at time 0, contradicting the boundedness of curvature there.  This argument in fact shows that all large curvature regions are contained in either <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-necks or <img src='http://s0.wp.com/latex.php?latex=%28C%2C%5Cvarepsilon%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(C,&#92;varepsilon)' title='(C,&#92;varepsilon)' class='latex' />-caps.
</p>
<p style="text-align:left;">Consider the ball <img src='http://s0.wp.com/latex.php?latex=B_%7Bg%28t%29%7D%28x%2Cr%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_{g(t)}(x,r)' title='B_{g(t)}(x,r)' class='latex' />.  From Remark 2 we see (if L&#8217; is large enough) that the curvature is larger than L on this ball, and so this ball consists entirely of necks and caps of width at most <img src='http://s0.wp.com/latex.php?latex=O%28L%5E%7B-1%2F2%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='O(L^{-1/2})' title='O(L^{-1/2})' class='latex' />.  From this it is not hard to see that the volume of this ball at time t is <img src='http://s0.wp.com/latex.php?latex=O%28+L%5E%7B-1%2F2%7D+r+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='O( L^{-1/2} r )' title='O( L^{-1/2} r )' class='latex' />.  On the other hand, there must be at least one point y on the boundary of this ball, since otherwise <img src='http://s0.wp.com/latex.php?latex=R_%7B%5Cmin%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R_{&#92;min}' title='R_{&#92;min}' class='latex' /> would be at least L, which as noted before is not possible.</p>
<p style="text-align:left;">Applying (2) (and noting that Ricci flow reduces volume when there is non-negative curvature, see equation (33) of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/01/285g-lecture-2-the-ricci-flow-approach-to-the-poincare-conjecture/">Lecture 2</a>) we conclude that <img src='http://s0.wp.com/latex.php?latex=B_%7Bg%28t%29%7D%28x%2Cr-O%281%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_{g(t)}(x,r-O(1))' title='B_{g(t)}(x,r-O(1))' class='latex' /> also has volume O(L^{-1/2} r).  On the other hand, we know that there is a point y at distance r from x at time t, thus y at distance r-O(1) from x at time 0.  Thus (by the triangle inequality, and dividing the geodesic from x to y at time zero into unit length segments) <img src='http://s0.wp.com/latex.php?latex=B_%7Bg%280%29%7D%28x%2Cr%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_{g(0)}(x,r)' title='B_{g(0)}(x,r)' class='latex' /> contains <img src='http://s0.wp.com/latex.php?latex=%5Csim+r&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;sim r' title='&#92;sim r' class='latex' /> disjoint balls of radius 1/2 (say).  By the non-collapsing and curvature bounds at time zero, this forces <img src='http://s0.wp.com/latex.php?latex=B_%7Bg%280%29%7D%28x%2Cr%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_{g(0)}(x,r)' title='B_{g(0)}(x,r)' class='latex' /> to have volume at least comparable to r, a contradiction.  This proves Proposition 5 and thus Theorem 1.</p>
<p style="text-align:left;"><strong>Remark 3. </strong>Perelman (and the authors who follow him) uses a slight variant of this argument, using the <a href="http://en.wikipedia.org/wiki/Soul_theorem">soul theorem</a> to fashion a small <img src='http://s0.wp.com/latex.php?latex=S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2' title='S^2' class='latex' /> in a narrow neck that separates two widely distant points at time t, which then evolves to a small <img src='http://s0.wp.com/latex.php?latex=S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2' title='S^2' class='latex' /> separating two widely distant points at time zero (here we use (2)).  But this is not possible due to the bounded curvature at that time. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
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<title><![CDATA[285G, Lecture 17: The structure of κ-solutions]]></title>
<link>http://terrytao.wordpress.com/2008/06/02/285g-lecture-17-the-structure-of-%ce%ba-solutions/</link>
<pubDate>Mon, 02 Jun 2008 21:14:33 +0000</pubDate>
<dc:creator>Terence Tao</dc:creator>
<guid>http://terrytao.wordpress.com/2008/06/02/285g-lecture-17-the-structure-of-%ce%ba-solutions/</guid>
<description><![CDATA[Having classified all asymptotic gradient shrinking solitons in three and fewer dimensions in the pr]]></description>
<content:encoded><![CDATA[<p>Having classified all asymptotic gradient shrinking solitons in three and fewer dimensions in the <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/30/285g-lecture-16-classification-of-asymptotic-gradient-shrinking-solitons/">previous lecture</a>, we now use this classification, combined with extensive use of compactness and contradiction arguments, as well as the comparison geometry of complete Riemannian manifolds of non-negative curvature, to understand the structure of <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions in these dimensions, with the aim being to state and prove precise versions of Theorem 1 and Corollary 1 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/16/285g-lecture-12-high-curvature-regions-of-ricci-flow-and-%ce%ba-solutions/">Lecture 12</a>.</p>
<p>The arguments are particularly simple when the asymptotic gradient shrinking soliton is compact; in this case, the rounding theorems of Hamilton show that the <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution is a (time-shifted) round shrinking spherical space form.  This already classifies <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions completely in two dimensions; the only remaining case is the three-dimensional case when the asymptotic gradient soliton is a round shrinking cylinder (or a quotient thereof by an involution).  To proceed further, one has to show that the <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution exhibits significant amounts of curvature, and in particular that one does not have bounded normalised curvature at infinity.  This curvature (combined with comparison geometry tools such as the Bishop-Gromov inequality) will cause asymptotic volume collapse of the <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution at infinity.  These facts lead to the fundamental <em>Perelman compactness theorem</em> for <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions, which then provides enough geometric control on such solutions that one can establish the structural theorems mentioned earlier.</p>
<p>The treatment here is a (slightly simplified) version of the arguments in <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2334563">Morgan-Tian&#8217;s book</a>, which is based in turn on <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0211159">Perelman&#8217;s paper</a> and the notes of <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0605667">Kleiner-Lott</a> (see also the paper of <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2233789">Cao-Zhu</a> for a slightly different treatment of this theory).</p>
<p><!--more--></p>
<p style="text-align:center;">&#8211; The compact soliton case &#8211;</p>
<p>As we saw in <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/27/285g-lecture-15-geometric-limits-of-ricci-flows-and-asymptotic-gradient-shrinking-solitons/">Lecture 15</a>, every <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> has at least one asymptotic gradient shrinking soliton <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M_%5Cinfty%2Cg_%5Cinfty%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M_&#92;infty,g_&#92;infty(t))' title='t &#92;mapsto (M_&#92;infty,g_&#92;infty(t))' class='latex' /> associated to it.  Suppose we are in the case in which at least one of these asymptotic gradient shrinking solitons is compact; by  Theorem 1 of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/30/285g-lecture-16-classification-of-asymptotic-gradient-shrinking-solitons/">Lecture 16</a>, this means that this soliton is a round shrinking spherical space form.  Since this soliton is the geometric limit of a rescaled sequence of M, this implies that M is homeomorphic to <img src='http://s0.wp.com/latex.php?latex=M_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M_&#92;infty' title='M_&#92;infty' class='latex' /> and, along a sequence of times <img src='http://s0.wp.com/latex.php?latex=t_n+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_n &#92;to &#92;infty' title='t_n &#92;to &#92;infty' class='latex' />, converges geometrically after rescaling to a round spherical space form. Thus M is asymptotically round as <img src='http://s0.wp.com/latex.php?latex=t+%5Cto+-%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;to -&#92;infty' title='t &#92;to -&#92;infty' class='latex' />.</p>
<p>One can now apply Hamilton&#8217;s rounding theorems in <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=954419">two</a> and <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=664497">three</a> dimensions to conclude that M is in fact perfectly round.  In the case of two dimensions this can be done by a variety of methods; let me sketch one way, using Perelman entropy; this is not the most elementary way to proceed but allows us to quickly utilise a lot of the theory we have built up.  First we can lift M up to be <img src='http://s0.wp.com/latex.php?latex=S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2' title='S^2' class='latex' /> instead of the quotient <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^2' title='&#92;Bbb{RP}^2' class='latex' />.  Then we observe from the Gauss-Bonnet theorem (Proposition 1 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/11/285g-lecture-4-finite-time-extinction-of-the-second-homotopy-group/">Lecture 4</a>) that <img src='http://s0.wp.com/latex.php?latex=%5Cint_M+R%5C+d%5Cmu+%3D+4%5Cpi&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_M R&#92; d&#92;mu = 4&#92;pi' title='&#92;int_M R&#92; d&#92;mu = 4&#92;pi' class='latex' />, and hence by the volume variation formula (equation (33) from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/03/28/285g-lecture-1-ricci-flow/">Lecture 1</a>) the volume <img src='http://s0.wp.com/latex.php?latex=%5Cint_M%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_M&#92; d&#92;mu' title='&#92;int_M&#92; d&#92;mu' class='latex' /> is decreasing in time at a constant rate <img src='http://s0.wp.com/latex.php?latex=-4%5Cpi&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='-4&#92;pi' title='-4&#92;pi' class='latex' />.  Let us shift time so that the volume is in fact equal to <img src='http://s0.wp.com/latex.php?latex=4+%5Cpi+%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='4 &#92;pi &#92;tau' title='4 &#92;pi &#92;tau' class='latex' />, and consider the Perelman entropy <img src='http://s0.wp.com/latex.php?latex=%5Cmu%28+M%2C+g%28t%29%2C+%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;mu( M, g(t), &#92;tau)' title='&#92;mu( M, g(t), &#92;tau)' class='latex' /> defined in <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/24/285a-lecture-8-ricci-flow-as-a-gradient-flow-log-sobolev-inequalities-and-perelman-entropy/">Lecture 8</a>.  Testing this entropy with <img src='http://s0.wp.com/latex.php?latex=f+%3A%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='f := 0' title='f := 0' class='latex' />) we obtain an upper bound <img src='http://s0.wp.com/latex.php?latex=%5Cmu%28+M%2C+g%28t%29%2C+%5Ctau%29+%5Cleq+-4%5Cpi&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;mu( M, g(t), &#92;tau) &#92;leq -4&#92;pi' title='&#92;mu( M, g(t), &#92;tau) &#92;leq -4&#92;pi' class='latex' />.  On the other hand, on the sequence of times <img src='http://s0.wp.com/latex.php?latex=t_n+%5Cto+-%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_n &#92;to -&#92;infty' title='t_n &#92;to -&#92;infty' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g(t))' title='(M,g(t))' class='latex' /> is smoothly approaching a round sphere, on which the entropy can be shown to be <em>exactly</em> <img src='http://s0.wp.com/latex.php?latex=-4%5Cpi&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='-4&#92;pi' title='-4&#92;pi' class='latex' /> by the log-Sobolev inequality for the sphere (which can be proven in a similar way to the log-Sobolev inequality for Euclidean space in <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/24/285a-lecture-8-ricci-flow-as-a-gradient-flow-log-sobolev-inequalities-and-perelman-entropy/">Lecture 8</a>).  Thus one can soon show that <img src='http://s0.wp.com/latex.php?latex=%5Cmu%28+M%2C+g%28t_n%29%2C+%5Ctau_n%29+%5Cto+-4%5Cpi&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;mu( M, g(t_n), &#92;tau_n) &#92;to -4&#92;pi' title='&#92;mu( M, g(t_n), &#92;tau_n) &#92;to -4&#92;pi' class='latex' />.  On the other hand, this entropy is non-increasing in <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' />; thus <img src='http://s0.wp.com/latex.php?latex=%5Cmu%28M%2Cg%28t%29%2C%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;mu(M,g(t),&#92;tau)' title='&#92;mu(M,g(t),&#92;tau)' class='latex' /> is constant.  Applying the results from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/21/285g-lecture-14-stationary-points-of-perelman-entropy-or-reduced-volume-are-gradient-shrinking-solitons/">Lecture 14</a> we conclude that this time-shifted manifold M is itself a gradient shrinking soliton, and thus is round by the results of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/27/285g-lecture-15-geometric-limits-of-ricci-flows-and-asymptotic-gradient-shrinking-solitons/">Lecture 15</a>.</p>
<p><strong>Exercise 1.</strong> In this exercise we give an alternate way to establish the roundness of M in two dimensions, using a slightly different notion of &#8220;entropy&#8221;.  Firstly, observe that under conformal change of metric <img src='http://s0.wp.com/latex.php?latex=g+%3D+ah&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='g = ah' title='g = ah' class='latex' /> on a surface, one has <img src='http://s0.wp.com/latex.php?latex=d%5Cmu_g+%3D+a+d%5Cmu_h&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d&#92;mu_g = a d&#92;mu_h' title='d&#92;mu_g = a d&#92;mu_h' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=%5CDelta_g+%3D+%5Cfrac%7B1%7D%7Ba%7D+%5CDelta_h&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Delta_g = &#92;frac{1}{a} &#92;Delta_h' title='&#92;Delta_g = &#92;frac{1}{a} &#92;Delta_h' class='latex' />, and <img src='http://s0.wp.com/latex.php?latex=R_g+%3D+%5Cfrac%7B1%7D%7Ba%7D+%28+R_h+-+%5CDelta_h+%5Clog+a+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R_g = &#92;frac{1}{a} ( R_h - &#92;Delta_h &#92;log a )' title='R_g = &#92;frac{1}{a} ( R_h - &#92;Delta_h &#92;log a )' class='latex' />.  If we then express <img src='http://s0.wp.com/latex.php?latex=g+%3D+ah&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='g = ah' title='g = ah' class='latex' /> where h is the metric on <img src='http://s0.wp.com/latex.php?latex=S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2' title='S^2' class='latex' /> of constant curvature +1, show that the Ricci flow equation becomes <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+a+%3D+%5CDelta+%5Clog+a+-+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t a = &#92;Delta &#92;log a - 1' title='&#92;partial_t a = &#92;Delta &#92;log a - 1' class='latex' />, and in particular that the volume <img src='http://s0.wp.com/latex.php?latex=%5Cint_M+a%5C+d%5Cmu_h&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_M a&#92; d&#92;mu_h' title='&#92;int_M a&#92; d&#92;mu_h' class='latex' /> is decreasing at constant rate <img src='http://s0.wp.com/latex.php?latex=4%5Cpi&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='4&#92;pi' title='4&#92;pi' class='latex' />.  If we time shift so that <img src='http://s0.wp.com/latex.php?latex=%5Cint_M+a%5C+d%5Cmu_h+%3D+4%5Cpi+%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_M a&#92; d&#92;mu_h = 4&#92;pi &#92;tau' title='&#92;int_M a&#92; d&#92;mu_h = 4&#92;pi &#92;tau' class='latex' />, show that the <a href="http://en.wikipedia.org/wiki/Relative_entropy">relative entropy</a><em> </em><img src='http://s0.wp.com/latex.php?latex=%5Cint_M+%5Cfrac%7Ba%7D%7B%5Ctau%7D+%5Clog+%5Cfrac%7Ba%7D%7B%5Ctau%7D%5C+d%5Cmu_h&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_M &#92;frac{a}{&#92;tau} &#92;log &#92;frac{a}{&#92;tau}&#92; d&#92;mu_h' title='&#92;int_M &#92;frac{a}{&#92;tau} &#92;log &#92;frac{a}{&#92;tau}&#92; d&#92;mu_h' class='latex' /> is non-decreasing in <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' />, and converges to 0 along <img src='http://s0.wp.com/latex.php?latex=%5Ctau_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau_n' title='&#92;tau_n' class='latex' /> (here one needs a stability result for the uniformisation theorem).  From this and the converse to <a href="http://en.wikipedia.org/wiki/Jensen%27s_inequality">Jensen&#8217;s inequality</a>, conclude that a is constant at every time, which gives the rounding. (For more proofs of the rounding theorem, for instance using the <em>Hamilton entropy</em> <img src='http://s0.wp.com/latex.php?latex=%5Cint_M+R+%5Clog+R%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_M R &#92;log R&#92; d&#92;mu' title='&#92;int_M R &#92;log R&#92; d&#92;mu' class='latex' />, see the <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2061425">book of Chow and Knopf</a>.) <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>In two dimensions, we saw in the <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/30/285g-lecture-16-classification-of-asymptotic-gradient-shrinking-solitons/">previous lecture</a> that the only gradient shrinking soliton was the round shrinking sphere.  We have thus shown the following classification of <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions in two dimensions:</p>
<blockquote><p><strong>Proposition 1. </strong>The only two-dimensional <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions are time translates of the round shrinking <img src='http://s0.wp.com/latex.php?latex=S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2' title='S^2' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^2' title='&#92;Bbb{RP}^2' class='latex' />.</p></blockquote>
<p>For three dimensions, we can argue as in Case 4 of the <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/30/285g-lecture-16-classification-of-asymptotic-gradient-shrinking-solitons/">previous lecture</a>.  Write <img src='http://s0.wp.com/latex.php?latex=%5Clambda+%5Cgeq+%5Cmu+%5Cgeq+%5Cnu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;lambda &#92;geq &#92;mu &#92;geq &#92;nu' title='&#92;lambda &#92;geq &#92;mu &#92;geq &#92;nu' class='latex' /> for the eigenvalues of the curvature tensor.  At the times <img src='http://s0.wp.com/latex.php?latex=t_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_n' title='t_n' class='latex' />, we have <img src='http://s0.wp.com/latex.php?latex=%28%5Cmu+%2B+%5Cnu%29%2F%5Clambda+%5Cgeq+2-%5Cdelta_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;mu + &#92;nu)/&#92;lambda &#92;geq 2-&#92;delta_n' title='(&#92;mu + &#92;nu)/&#92;lambda &#92;geq 2-&#92;delta_n' class='latex' /> for some <img src='http://s0.wp.com/latex.php?latex=%5Cdelta_n+%5Cto+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta_n &#92;to 0' title='&#92;delta_n &#92;to 0' class='latex' />.  Applying the tensor maximum principle (Proposition 1 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/04/285g-lecture-3-the-maximum-principle-and-the-pinching-phenomenon/">Lecture 3</a>) and the analysis from Case 4 of the <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/30/285g-lecture-16-classification-of-asymptotic-gradient-shrinking-solitons/">previous lecture</a>, we thus see that <img src='http://s0.wp.com/latex.php?latex=%28%5Cmu+%2B+%5Cnu%29%2F%5Clambda+%5Cgeq+2-%5Cdelta_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;mu + &#92;nu)/&#92;lambda &#92;geq 2-&#92;delta_n' title='(&#92;mu + &#92;nu)/&#92;lambda &#92;geq 2-&#92;delta_n' class='latex' /> for all times <img src='http://s0.wp.com/latex.php?latex=t+%5Cgeq+t_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;geq t_n' title='t &#92;geq t_n' class='latex' />; sending n to infinity we conclude that <img src='http://s0.wp.com/latex.php?latex=%28%5Cmu+%2B+%5Cnu%29%2F%5Clambda+%5Cgeq+2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;mu + &#92;nu)/&#92;lambda &#92;geq 2' title='(&#92;mu + &#92;nu)/&#92;lambda &#92;geq 2' class='latex' /> for all times, and so curvature is conformal.  Using the <a href="http://en.wikipedia.org/wiki/Bianchi_identity#Bianchi_identities">Bianchi identity</a> as in Case 4 of the <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/30/285g-lecture-16-classification-of-asymptotic-gradient-shrinking-solitons/">previous lecture</a>, we conclude that the manifold is round.</p>
<p style="text-align:center;">&#8211; The case of a vanishing curvature &#8211;</p>
<p>Now we deal with the case in which there is a vanishing curvature:</p>
<blockquote><p><strong>Proposition 2. </strong>Let <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> be a 3-dimensional <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution for which the Ricci curvature has a null eigenvector at some point in spacetime.  Then M is a time-shifted round shrinking cylinder, or the oriented or unoriented quotient of that cylinder by an involution.</p></blockquote>
<p><strong>Proof.</strong> If the Ricci curvature vanishes at any point, then by Hamilton&#8217;s splitting theorem (Proposition 1 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/19/285g-lecture-13-li-yau-hamilton-harnack-inequalities-and-%ce%ba-solutions/">Lecture 13</a>) the flow splits (locally, at least) as a line and a two-dimensional flow.  Passing to a double cover if necessary, we see that the flow is the product of a two-dimensional Ricci flow and either a line or a circle.  The two-dimensional flow is itself a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution and is thus a round shrinking <img src='http://s0.wp.com/latex.php?latex=S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2' title='S^2' class='latex' /> or <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+RP%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb RP}^2' title='{&#92;Bbb RP}^2' class='latex' />.  Checking all the cases and eliminating those which are not <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsed we obtain the claim. <img src='http://s0.wp.com/latex.php?latex=%5CBox&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Box' title='&#92;Box' class='latex' /></p>
<p style="text-align:center;">&#8211; Asymptotic volume collapse &#8211;</p>
<p>Our next structural result on <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions is</p>
<blockquote><p><strong>Proposition 3. </strong>(Asymptotic collapse of Bishop-Gromov reduced volume) Let <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g(t))' title='(M,g(t))' class='latex' /> be a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution of dimension 3.  Then for any time t and <img src='http://s0.wp.com/latex.php?latex=r+%5Cin+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r &#92;in M' title='r &#92;in M' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=%5Clim_%7Br+%5Cto+%5Cinfty%7D+%5Chbox%7BVol%7D%28B_%7Bg%28t%29%7D%28p%2Cr%29%29%2Fr%5E3+%5Cto+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;lim_{r &#92;to &#92;infty} &#92;hbox{Vol}(B_{g(t)}(p,r))/r^3 &#92;to 0' title='&#92;lim_{r &#92;to &#92;infty} &#92;hbox{Vol}(B_{g(t)}(p,r))/r^3 &#92;to 0' class='latex' />.</p></blockquote>
<p><strong>Proof.</strong> We first observe, by inspecting all the possibilities from Theorem 1 of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/30/285g-lecture-16-classification-of-asymptotic-gradient-shrinking-solitons/">Lecture 16</a>, that the claim is already true of all 3-dimensional asymptotic gradient shrinking solitons.  We apply this to a gradient shrinking soliton for M and conclude that for any <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon &gt; 0' title='&#92;varepsilon &gt; 0' class='latex' /> there exists arbitrarily negative times <img src='http://s0.wp.com/latex.php?latex=t_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_n' title='t_n' class='latex' />, points <img src='http://s0.wp.com/latex.php?latex=x_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_n' title='x_n' class='latex' /> and radii <img src='http://s0.wp.com/latex.php?latex=r_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_n' title='r_n' class='latex' /> such that <img src='http://s0.wp.com/latex.php?latex=B_%7Bg%28t_n%29%7D%28x_n%2Cr_n%29%2Fr_n%5E3+%5Cleq+%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_{g(t_n)}(x_n,r_n)/r_n^3 &#92;leq &#92;varepsilon' title='B_{g(t_n)}(x_n,r_n)/r_n^3 &#92;leq &#92;varepsilon' class='latex' />.  Applying the <a href="http://en.wikipedia.org/wiki/Bishop%E2%80%93Gromov_inequality">Bishop-Gromov comparison inequality</a> (Lemma 1 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/27/285g-lecture-9-comparison-geometry-the-high-dimensional-limit-and-perelman-reduced-volume/">Lecture 9</a>) we conclude that <img src='http://s0.wp.com/latex.php?latex=%5Clim_%7Br+%5Cto+%5Cinfty%7D+B_%7Bg%28t_n%29%7D%28x_n%2Cr%29%2Fr%5E3+%5Cleq+%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;lim_{r &#92;to &#92;infty} B_{g(t_n)}(x_n,r)/r^3 &#92;leq &#92;varepsilon' title='&#92;lim_{r &#92;to &#92;infty} B_{g(t_n)}(x_n,r)/r^3 &#92;leq &#92;varepsilon' class='latex' />.  By the triangle inequality this implies that <img src='http://s0.wp.com/latex.php?latex=%5Clim_%7Br+%5Cto+%5Cinfty%7D+B_%7Bg%28t_n%29%7D%28p%2Cr%29%2Fr%5E3+%5Cleq+%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;lim_{r &#92;to &#92;infty} B_{g(t_n)}(p,r)/r^3 &#92;leq &#92;varepsilon' title='&#92;lim_{r &#92;to &#92;infty} B_{g(t_n)}(p,r)/r^3 &#92;leq &#92;varepsilon' class='latex' />.</p>
<p>Now we need to move from time <img src='http://s0.wp.com/latex.php?latex=t_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_n' title='t_n' class='latex' /> to time t; since <img src='http://s0.wp.com/latex.php?latex=t_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_n' title='t_n' class='latex' /> is arbitrarily negative we can assume <img src='http://s0.wp.com/latex.php?latex=t+%5Cgeq+t_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;geq t_n' title='t &#92;geq t_n' class='latex' />.  Recall from Lemma 1 of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/27/285g-lecture-15-geometric-limits-of-ricci-flows-and-asymptotic-gradient-shrinking-solitons/">Lecture 15</a> and the bounded curvature hypothesis that <img src='http://s0.wp.com/latex.php?latex=%5Cint_%5Cgamma+%5Chbox%7BRic%7D%28X%2CX%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_&#92;gamma &#92;hbox{Ric}(X,X)' title='&#92;int_&#92;gamma &#92;hbox{Ric}(X,X)' class='latex' /> is bounded for all times and all geodesics <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' />.  Plugging this into the Ricci flow equation, we see that <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bd%7D%7Bdt%7D+d_%7Bg%28t%29%7D%28x%2Cy%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{d}{dt} d_{g(t)}(x,y)' title='&#92;frac{d}{dt} d_{g(t)}(x,y)' class='latex' /> is also bounded (in the sense of forward difference quotients) for all times and all geodesics.  In particular we have the additive distance fluctuation estimate <img src='http://s0.wp.com/latex.php?latex=d_%7Bg%28t%29%7D%28p%2Cx%29+%3D+d_%7Bg%28t_n%29%7D%28p%2Cx%29+%2B+O%28+%26%23124%3Bt_n-t%26%23124%3B+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d_{g(t)}(p,x) = d_{g(t_n)}(p,x) + O( &#124;t_n-t&#124; )' title='d_{g(t)}(p,x) = d_{g(t_n)}(p,x) + O( &#124;t_n-t&#124; )' class='latex' />, where the error is bounded even as <img src='http://s0.wp.com/latex.php?latex=d_%7Bg%28t_n%29%7D%28p%2Cx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d_{g(t_n)}(p,x)' title='d_{g(t_n)}(p,x)' class='latex' /> or <img src='http://s0.wp.com/latex.php?latex=d_%7Bg%28t%29%7D%28p%2Cx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d_{g(t)}(p,x)' title='d_{g(t)}(p,x)' class='latex' /> goes to infinity.  Also, from equation (33) from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/03/28/285g-lecture-1-ricci-flow">Lecture 1</a> we know that the volume measure <img src='http://s0.wp.com/latex.php?latex=d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d&#92;mu' title='d&#92;mu' class='latex' /> is decreasing over time. From this we conclude that <img src='http://s0.wp.com/latex.php?latex=%5Clim_%7Br+%5Cto+%5Cinfty%7D+B_%7Bg%28t%29%7D%28p%2Cr%29%2Fr%5E3+%5Cleq+%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;lim_{r &#92;to &#92;infty} B_{g(t)}(p,r)/r^3 &#92;leq &#92;varepsilon' title='&#92;lim_{r &#92;to &#92;infty} B_{g(t)}(p,r)/r^3 &#92;leq &#92;varepsilon' class='latex' />.  Since <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' /> is arbitrary, the claim follows. <img src='http://s0.wp.com/latex.php?latex=%5CBox&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Box' title='&#92;Box' class='latex' /></p>
<p>We have a corollary:</p>
<blockquote><p><strong>Corollary 1. </strong>Let <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g(t))' title='(M,g(t))' class='latex' /> be a non-compact <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution of dimension 3.  Then for any time t and point <img src='http://s0.wp.com/latex.php?latex=p+%5Cin+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='p &#92;in M' title='p &#92;in M' class='latex' /> we have <img src='http://s0.wp.com/latex.php?latex=%5Climsup_%7Bx+%5Cto+%5Cinfty%7D+R%28x%29+d%28p%2Cx%29%5E2+%3D+%2B%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;limsup_{x &#92;to &#92;infty} R(x) d(p,x)^2 = +&#92;infty' title='&#92;limsup_{x &#92;to &#92;infty} R(x) d(p,x)^2 = +&#92;infty' class='latex' />.  (Of course, the claim is vacuous for compact solutions.)</p></blockquote>
<p><strong>Proof. </strong> By time shifting we may take t=0.  Suppose for contradiction that <img src='http://s0.wp.com/latex.php?latex=%5Climsup_%7Bx+%5Cto+%5Cinfty%7D+R%28x%29+d%28p%2Cx%29%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;limsup_{x &#92;to &#92;infty} R(x) d(p,x)^2' title='&#92;limsup_{x &#92;to &#92;infty} R(x) d(p,x)^2' class='latex' /> is finite, thus <img src='http://s0.wp.com/latex.php?latex=R%28x%29+%3D+O%28+1+%2F+d%28p%2Cx%29%5E2+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(x) = O( 1 / d(p,x)^2 )' title='R(x) = O( 1 / d(p,x)^2 )' class='latex' /> at time t=0, and thus at all previous times since <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+R+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t R &#92;geq 0' title='&#92;partial_t R &#92;geq 0' class='latex' /> (equation (29) of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/19/285g-lecture-13-li-yau-hamilton-harnack-inequalities-and-%ce%ba-solutions/">Lecture 13</a>).  From the non-negativity of the curvature we obtain the similar upper bounds on the Riemann curvature.  From the <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsed nature of M we may thus conclude that <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BVol%7D+B%28+x%2C+c+d%28p%2Cx%29+%29+%2F+d%28p%2Cx%29%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Vol} B( x, c d(p,x) ) / d(p,x)^3' title='&#92;hbox{Vol} B( x, c d(p,x) ) / d(p,x)^3' class='latex' /> is bounded away from zero for some small c &#62; 0.  But this contradicts Proposition 3. <img src='http://s0.wp.com/latex.php?latex=%5CBox&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Box' title='&#92;Box' class='latex' /></p>
<p><strong>Remark 1.</strong> In other treatments of this argument (e.g. in <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2334563">Morgan-Tian</a>), Corollary 1 is established first (using the Topogonov theory from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/30/285g-lecture-16-classification-of-asymptotic-gradient-shrinking-solitons/">Lecture 16</a>) and then used to derive Proposition 3.  The two approaches are essentially just permutations of each other, but the arguments above seem to be slightly simpler (in particular, the theory of the Tits cone is avoided). <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>By combining Proposition 3 with another compactness argument, we obtain an important relationship:</p>
<blockquote><p><strong>Corollary 2. </strong>(Volume noncollapsing implies curvature bound) Let <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> be a 3-dimensional <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution, and let <img src='http://s0.wp.com/latex.php?latex=B%28x_0%2Cr%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B(x_0,r)' title='B(x_0,r)' class='latex' /> be a ball at time zero with volume at least <img src='http://s0.wp.com/latex.php?latex=%5Cnu+r%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nu r^3' title='&#92;nu r^3' class='latex' />.  Then for every <img src='http://s0.wp.com/latex.php?latex=A+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='A &gt; 0' title='A &gt; 0' class='latex' /> we have a bound <img src='http://s0.wp.com/latex.php?latex=R%28x%29+%3D+O_%7B%5Ckappa%2C%5Cnu%2CA%7D%28r%5E%7B-2%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(x) = O_{&#92;kappa,&#92;nu,A}(r^{-2})' title='R(x) = O_{&#92;kappa,&#92;nu,A}(r^{-2})' class='latex' /> for all x in <img src='http://s0.wp.com/latex.php?latex=B%28x_0%2CAr%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B(x_0,Ar)' title='B(x_0,Ar)' class='latex' />.</p></blockquote>
<p>This result can be viewed as a converse to the <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsing property (bounded curvature implies volume noncollapsing).  A key point here is that the bound depends only on <img src='http://s0.wp.com/latex.php?latex=%5Ckappa%2C%5Cnu%2CA&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa,&#92;nu,A' title='&#92;kappa,&#92;nu,A' class='latex' /> and not on the <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution itself; this uniformity will be a crucial ingredient in the Perelman compactness theorem below.</p>
<p><strong>Proof. </strong>Since <img src='http://s0.wp.com/latex.php?latex=B%28x_0%2Cr%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B(x_0,r)' title='B(x_0,r)' class='latex' /> is contained in <img src='http://s0.wp.com/latex.php?latex=B%28x%2C%28A%2B1%29r%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B(x,(A+1)r)' title='B(x,(A+1)r)' class='latex' />, it suffices to establish the claim when <img src='http://s0.wp.com/latex.php?latex=x%3Dx_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x=x_0' title='x=x_0' class='latex' />.  By replacing r with Ar if necessary we may normalise A=1; we may also rescale <img src='http://s0.wp.com/latex.php?latex=R%28x_0%29%3D1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(x_0)=1' title='R(x_0)=1' class='latex' />.   Suppose the claim failed, then there exists a sequence of pointed <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M_n%2Cg_n%28t%29%2Cx_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M_n,g_n(t),x_n)' title='t &#92;mapsto (M_n,g_n(t),x_n)' class='latex' /> with <img src='http://s0.wp.com/latex.php?latex=R_n%280%2Cx_n%29+%3D+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R_n(0,x_n) = 1' title='R_n(0,x_n) = 1' class='latex' /> and balls <img src='http://s0.wp.com/latex.php?latex=B_%7Bg_n%280%29%7D%28x_n%2Cr_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_{g_n(0)}(x_n,r_n)' title='B_{g_n(0)}(x_n,r_n)' class='latex' /> with <img src='http://s0.wp.com/latex.php?latex=r_n+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_n &#92;to &#92;infty' title='r_n &#92;to &#92;infty' class='latex' /> whose volume is bounded below by <img src='http://s0.wp.com/latex.php?latex=%5Cnu+r_n%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nu r_n^3' title='&#92;nu r_n^3' class='latex' /> for some <img src='http://s0.wp.com/latex.php?latex=%5Cnu+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nu &gt; 0' title='&#92;nu &gt; 0' class='latex' />. Using the point picking argument (Exercise 1 from Lecture 16) we can also ensure that for each r, we have <img src='http://s0.wp.com/latex.php?latex=R_n%280%2Cx%29+%5Cleq+4&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R_n(0,x) &#92;leq 4' title='R_n(0,x) &#92;leq 4' class='latex' /> on <img src='http://s0.wp.com/latex.php?latex=B_%7Bg_n%280%29%7D%280%2Cr%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_{g_n(0)}(0,r)' title='B_{g_n(0)}(0,r)' class='latex' /> if n is sufficiently large depending on r.  Using the monotonicity <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+R+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t R &#92;geq 0' title='&#92;partial_t R &#92;geq 0' class='latex' /> and Hamilton&#8217;s compactness theorem (Theorem 2 from <a class="snap_noshots" href="../2008/05/27/285g-lecture-15-geometric-limits-of-ricci-flows-and-asymptotic-gradient-shrinking-solitons/">Lecture 15</a>) we may may thus pass to a subsequence and assume that the flows <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M_n%2C+g_n%28t%29%2C+x_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M_n, g_n(t), x_n)' title='t &#92;mapsto (M_n, g_n(t), x_n)' class='latex' /> converge geometrically to a limit <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M_%5Cinfty%2C+g_%5Cinfty%28t%29%2C+x_%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M_&#92;infty, g_&#92;infty(t), x_&#92;infty)' title='t &#92;mapsto (M_&#92;infty, g_&#92;infty(t), x_&#92;infty)' class='latex' />, which one easily verifies to be a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution whose asymptotic volume at time zero is bounded below by <img src='http://s0.wp.com/latex.php?latex=%5Cnu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nu' title='&#92;nu' class='latex' />.  But this contradicts Proposition 3. <img src='http://s0.wp.com/latex.php?latex=%5CBox&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Box' title='&#92;Box' class='latex' /></p>
<p style="text-align:center;">&#8211; The Perelman compactness theorem &#8211;</p>
<p>Corollary 2 leads to another important bound:</p>
<blockquote><p><strong>Proposition 4</strong> (Bounded curvature at bounded distance).  Let <img src='http://s0.wp.com/latex.php?latex=%5Ckappa+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa &gt; 0' title='&#92;kappa &gt; 0' class='latex' />, and let <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2C+g%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M, g(t))' title='t &#92;mapsto (M, g(t))' class='latex' /> be a three-dimensional <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution.  Then at time zero, for every <img src='http://s0.wp.com/latex.php?latex=x_0+%5Cin+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0 &#92;in M' title='x_0 &#92;in M' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=A+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='A &gt; 0' title='A &gt; 0' class='latex' /> we have <img src='http://s0.wp.com/latex.php?latex=R%28x%29+%3D+O_%7B%5Ckappa%2C+A%7D%28+R%28x_0%29+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(x) = O_{&#92;kappa, A}( R(x_0) )' title='R(x) = O_{&#92;kappa, A}( R(x_0) )' class='latex' /> on <img src='http://s0.wp.com/latex.php?latex=B%28x_0%2C+A+R%28x_0%29%5E%7B-1%2F2%7D+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B(x_0, A R(x_0)^{-1/2} )' title='B(x_0, A R(x_0)^{-1/2} )' class='latex' />.</p></blockquote>
<p style="text-align:left;"><strong>Proof.</strong> If the claim failed, then there will be an <img src='http://s0.wp.com/latex.php?latex=A+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='A &gt; 0' title='A &gt; 0' class='latex' /> sequence <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M_n%2Cg_n%28t%29%2Cx_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M_n,g_n(t),x_n)' title='t &#92;mapsto (M_n,g_n(t),x_n)' class='latex' /> of pointed <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions and <img src='http://s0.wp.com/latex.php?latex=y_n+%5Cin+B_%7Bg_n%280%29%7D%28x_n%2C+R_n%28x_n%29%5E%7B-1%2F2%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y_n &#92;in B_{g_n(0)}(x_n, R_n(x_n)^{-1/2})' title='y_n &#92;in B_{g_n(0)}(x_n, R_n(x_n)^{-1/2})' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=R_n%28y_n%29%2FR_n%28x_n%29+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R_n(y_n)/R_n(x_n) &#92;to &#92;infty' title='R_n(y_n)/R_n(x_n) &#92;to &#92;infty' class='latex' />.  Applying Corollary 2 in the contrapositive we conclude that <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BVol%7D_%7Bg_n%280%29%7D%28+B_%7Bg_n%280%29%7D%28+x_n%2C+R_n%28x_n%29%5E%7B-1%2F2%7D+%29+%2F+R_n%28x_n%29%5E%7B-3%2F2%7D+%3D+o%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Vol}_{g_n(0)}( B_{g_n(0)}( x_n, R_n(x_n)^{-1/2} ) / R_n(x_n)^{-3/2} = o(1)' title='&#92;hbox{Vol}_{g_n(0)}( B_{g_n(0)}( x_n, R_n(x_n)^{-1/2} ) / R_n(x_n)^{-3/2} = o(1)' class='latex' />.  By the Bishop-Gromov inequality, we can thus find a radius <img src='http://s0.wp.com/latex.php?latex=r_n+%3D+o%28+R_n%28x_n%29%5E%7B-1%2F2%7D+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_n = o( R_n(x_n)^{-1/2} )' title='r_n = o( R_n(x_n)^{-1/2} )' class='latex' /> such that <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BVol%7D_%7Bg_n%280%29%7D%28+B_%7Bg_n%280%29%7D%28+x_n%2C+r_n+%29%2Fr_n%5E3+%3D+%5Comega_3%2F2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Vol}_{g_n(0)}( B_{g_n(0)}( x_n, r_n )/r_n^3 = &#92;omega_3/2' title='&#92;hbox{Vol}_{g_n(0)}( B_{g_n(0)}( x_n, r_n )/r_n^3 = &#92;omega_3/2' class='latex' /> (say), where <img src='http://s0.wp.com/latex.php?latex=%5Comega_3+%3A%3D+%5Cfrac%7B4%7D%7B3%7D+%5Cpi&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;omega_3 := &#92;frac{4}{3} &#92;pi' title='&#92;omega_3 := &#92;frac{4}{3} &#92;pi' class='latex' /> is the volume of the Euclidean 3-ball.   By rescaling we may normalise <img src='http://s0.wp.com/latex.php?latex=r_n%3D1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_n=1' title='r_n=1' class='latex' />, thus <img src='http://s0.wp.com/latex.php?latex=R_n%28x_n%29%3Do%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R_n(x_n)=o(1)' title='R_n(x_n)=o(1)' class='latex' />.  By Corollary 2 we now have <img src='http://s0.wp.com/latex.php?latex=R_n%28x%29+%3D+O_%7B%5Ckappa%2CA%7D%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R_n(x) = O_{&#92;kappa,A}(1)' title='R_n(x) = O_{&#92;kappa,A}(1)' class='latex' /> on <img src='http://s0.wp.com/latex.php?latex=B_%7Bg_n%280%29%7D%28x_n%2CA%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_{g_n(0)}(x_n,A)' title='B_{g_n(0)}(x_n,A)' class='latex' /> for every <img src='http://s0.wp.com/latex.php?latex=A+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='A &gt; 0' title='A &gt; 0' class='latex' />.  We may thus use monotonicity <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+R_n+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t R_n &#92;geq 0' title='&#92;partial_t R_n &#92;geq 0' class='latex' /> and Hamilton compactness as before to extract a limiting solution <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M_%5Cinfty%2C+g_%5Cinfty%28t%29%2C+x_%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M_&#92;infty, g_&#92;infty(t), x_&#92;infty)' title='t &#92;mapsto (M_&#92;infty, g_&#92;infty(t), x_&#92;infty)' class='latex' /> with <img src='http://s0.wp.com/latex.php?latex=R_%5Cinfty%280%2Cx_%5Cinfty%29%3D0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R_&#92;infty(0,x_&#92;infty)=0' title='R_&#92;infty(0,x_&#92;infty)=0' class='latex' /> and with <img src='http://s0.wp.com/latex.php?latex=B_%7Bg_%5Cinfty%280%29%7D%28x_%5Cinfty%2C1%29+%3D+%5Comega_3%2F2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_{g_&#92;infty(0)}(x_&#92;infty,1) = &#92;omega_3/2' title='B_{g_&#92;infty(0)}(x_&#92;infty,1) = &#92;omega_3/2' class='latex' />.  But then by the strong maximum principle (see Exercise 7 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/19/285g-lecture-13-li-yau-hamilton-harnack-inequalities-and-%ce%ba-solutions/">Lecture 13</a>), <img src='http://s0.wp.com/latex.php?latex=M_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M_&#92;infty' title='M_&#92;infty' class='latex' /> must be flat; since it is <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-non-collapsed, it must be <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+R%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb R}^3' title='{&#92;Bbb R}^3' class='latex' />.  But then we have <img src='http://s0.wp.com/latex.php?latex=B_%7Bg_%5Cinfty%280%29%7D%28x_%5Cinfty%2C1%29+%3D+%5Comega_3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_{g_&#92;infty(0)}(x_&#92;infty,1) = &#92;omega_3' title='B_{g_&#92;infty(0)}(x_&#92;infty,1) = &#92;omega_3' class='latex' />, a contradiction.  <img src='http://s0.wp.com/latex.php?latex=%5CBox&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Box' title='&#92;Box' class='latex' /></p>
<p><strong>Exercise 2.</strong> Use Proposition 4 to improve the lim sup in Corollary 1 to a lim inf. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>This in turn gives a fundamental compactness theorem.</p>
<blockquote><p><strong>Theorem 1</strong> (Perelman compactness theorem).  Let <img src='http://s0.wp.com/latex.php?latex=%5Ckappa+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa &gt; 0' title='&#92;kappa &gt; 0' class='latex' />, and let <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M_n%2C+g_n%28t%29%2C+p_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M_n, g_n(t), p_n)' title='t &#92;mapsto (M_n, g_n(t), p_n)' class='latex' /> be a sequence of three-dimensional <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions, normalised so that <img src='http://s0.wp.com/latex.php?latex=R_n%280%2Cp_n%29%3D1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R_n(0,p_n)=1' title='R_n(0,p_n)=1' class='latex' />.  Then after passing to a subsequence, these solutions converge geometrically to another <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M_%5Cinfty%2C+g_%5Cinfty%28t%29%2C+p_%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M_&#92;infty, g_&#92;infty(t), p_&#92;infty)' title='t &#92;mapsto (M_&#92;infty, g_&#92;infty(t), p_&#92;infty)' class='latex' />.</p></blockquote>
<p><strong>Proof. </strong>By Proposition 4, we have <img src='http://s0.wp.com/latex.php?latex=R_n%280%2Cx%29+%3D+O_A%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R_n(0,x) = O_A(1)' title='R_n(0,x) = O_A(1)' class='latex' /> on <img src='http://s0.wp.com/latex.php?latex=B_%7Bg_n%280%29%7D%28p_n%2CA%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_{g_n(0)}(p_n,A)' title='B_{g_n(0)}(p_n,A)' class='latex' /> for every <img src='http://s0.wp.com/latex.php?latex=A+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='A &gt; 0' title='A &gt; 0' class='latex' />.  Using monotonicity <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+R_n+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t R_n &#92;geq 0' title='&#92;partial_t R_n &#92;geq 0' class='latex' /> and Hamilton compactness as before, the claim follows. <img src='http://s0.wp.com/latex.php?latex=%5CBox&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Box' title='&#92;Box' class='latex' /></p>
<p style="text-align:center;">&#8211; Universal noncollapsing &#8211;</p>
<p style="text-align:left;">The Perelman compactness theorem requires <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' /> to be fixed.  However, the theorem can be largely extended to allow for variable <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' /> by the following proposition.</p>
<blockquote><p><strong>Proposition 5. </strong>(Universal <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />) There exists a universal <img src='http://s0.wp.com/latex.php?latex=%5Ckappa_0+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa_0 &gt; 0' title='&#92;kappa_0 &gt; 0' class='latex' /> such that every 3-dimensional <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution which is not round, is in fact a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa_0' title='&#92;kappa_0' class='latex' />-solution (no matter how small <img src='http://s0.wp.com/latex.php?latex=%5Ckappa+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa &gt; 0' title='&#92;kappa &gt; 0' class='latex' /> is).</p></blockquote>
<p>The reason one needs to exclude the round case is that sphere quotients <img src='http://s0.wp.com/latex.php?latex=S%5E3%2F%5CGamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^3/&#92;Gamma' title='S^3/&#92;Gamma' class='latex' /> can be arbitrarily collapsed if one takes <img src='http://s0.wp.com/latex.php?latex=%5CGamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Gamma' title='&#92;Gamma' class='latex' /> to be large (e.g. consider the action of the <img src='http://s0.wp.com/latex.php?latex=n%5E%7Bth%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='n^{th}' title='n^{th}' class='latex' /> roots of unity on the unit ball of <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+C%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb C}^2' title='{&#92;Bbb C}^2' class='latex' /> (which is of course identifiable with <img src='http://s0.wp.com/latex.php?latex=S%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^3' title='S^3' class='latex' />) for n large).</p>
<p><strong>Proof.</strong> By time shifting it suffices to show <img src='http://s0.wp.com/latex.php?latex=%5Ckappa_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa_0' title='&#92;kappa_0' class='latex' />-noncollapsing at time zero at at some spatial origin <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' />, which we now fix.</p>
<p>Let <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> be a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution. By Proposition 1, M is non-compact, which means that any asymptotic gradient shrinking soliton must also be non-compact. By Theorem 1 from the <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/30/285g-lecture-16-classification-of-asymptotic-gradient-shrinking-solitons/">previous lecture</a>, all asymptotic gradient shrinking solitons are thus round shrinking cylinders, or the oriented or unoriented quotient of such a cylinder.</p>
<p>Let <img src='http://s0.wp.com/latex.php?latex=l+%3D+l_%7B%280%2Cx_0%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l = l_{(0,x_0)}' title='l = l_{(0,x_0)}' class='latex' /> be the reduced length function from <img src='http://s0.wp.com/latex.php?latex=%280%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(0,x_0)' title='(0,x_0)' class='latex' />. Recall from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/27/285g-lecture-15-geometric-limits-of-ricci-flows-and-asymptotic-gradient-shrinking-solitons/">Lecture 15</a> that one can find a sequence of points <img src='http://s0.wp.com/latex.php?latex=%28t_n%2Cx_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_n,x_n)' title='(t_n,x_n)' class='latex' /> with <img src='http://s0.wp.com/latex.php?latex=t_n+%5Cto+-%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_n &#92;to -&#92;infty' title='t_n &#92;to -&#92;infty' class='latex' /> with <img src='http://s0.wp.com/latex.php?latex=l+%3D+O_A%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l = O_A(1)' title='l = O_A(1)' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=R+%3D+O_A%28t_n%5E%7B-1%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R = O_A(t_n^{-1})' title='R = O_A(t_n^{-1})' class='latex' /> on any cylinder <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5BAt_n%2C+t_n%2FA%5D+%5Ctimes+B_%7Bg%28t_n%29%7D%28x_n%2C+A+t_n%5E%7B1%2F2%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[At_n, t_n/A] &#92;times B_{g(t_n)}(x_n, A t_n^{1/2})' title='{}[At_n, t_n/A] &#92;times B_{g(t_n)}(x_n, A t_n^{1/2})' class='latex' />, whose rescalings by <img src='http://s0.wp.com/latex.php?latex=t_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_n' title='t_n' class='latex' /> converge geometrically to an asymptotic gradient shrinking soliton (and thus to a round cylinder or quotient thereof), and the bound <img src='http://s0.wp.com/latex.php?latex=O_A%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='O_A(1)' title='O_A(1)' class='latex' /> does not depend on <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />. A computation shows that these round cylinders or quotients are <img src='http://s0.wp.com/latex.php?latex=%5Ckappa%27_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa&#039;_0' title='&#92;kappa&#039;_0' class='latex' />-noncollapsed for some universal <img src='http://s0.wp.com/latex.php?latex=%5Ckappa%27_0+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa&#039;_0 &gt; 0' title='&#92;kappa&#039;_0 &gt; 0' class='latex' />, and so the cylinders <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5BAt_n%2C+t_n%2FA%5D+%5Ctimes+B_%7Bg%28t_n%29%7D%28x_n%2C+A+t_n%5E%7B1%2F2%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[At_n, t_n/A] &#92;times B_{g(t_n)}(x_n, A t_n^{1/2})' title='{}[At_n, t_n/A] &#92;times B_{g(t_n)}(x_n, A t_n^{1/2})' class='latex' /> are similarly <img src='http://s0.wp.com/latex.php?latex=%5Ckappa%27%27_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa&#039;&#039;_0' title='&#92;kappa&#039;&#039;_0' class='latex' />-noncollapsed (for some slightly smaller but universal <img src='http://s0.wp.com/latex.php?latex=%5Ckappa%27%27_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa&#039;&#039;_0' title='&#92;kappa&#039;&#039;_0' class='latex' />). From the bounds on l and R, this implies that reduced volume at time <img src='http://s0.wp.com/latex.php?latex=t_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_n' title='t_n' class='latex' /> is bounded from below by a constant independent of <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />. Using monotonicity of reduced volume, we thus have this lower bound for all times. The arguments in <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/14/285g-lecture-11-%ce%ba-noncollapsing-via-perelman-reduced-volume/">Lecture 11</a> then give <img src='http://s0.wp.com/latex.php?latex=%5Ckappa_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa_0' title='&#92;kappa_0' class='latex' />-noncollapsing for some other universal <img src='http://s0.wp.com/latex.php?latex=%5Ckappa_0+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa_0 &gt; 0' title='&#92;kappa_0 &gt; 0' class='latex' />. <img src='http://s0.wp.com/latex.php?latex=%5CBox&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Box' title='&#92;Box' class='latex' /></p>
<p>Here is one useful corollary of Perelman compactness and universality:</p>
<blockquote><p><strong>Corollary 3.</strong> (Universal derivative bounds)  Let <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> be a three-dimensional <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution.  Then we have the pointwise bounds <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Cpartial_t%5Ek+%5Cnabla%5Em+%5Chbox%7BRiem%7D%26%23124%3B+%3D+O_%7Bk%2Cm%7D%28+R%5E%7B1+%2B+m%2F2+%2B+k%7D+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;partial_t^k &#92;nabla^m &#92;hbox{Riem}&#124; = O_{k,m}( R^{1 + m/2 + k} )' title='&#124;&#92;partial_t^k &#92;nabla^m &#92;hbox{Riem}&#124; = O_{k,m}( R^{1 + m/2 + k} )' class='latex' /> for all <img src='http://s0.wp.com/latex.php?latex=m%2Ck+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='m,k &#92;geq 0' title='m,k &#92;geq 0' class='latex' />.  In particular we have <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Cpartial_t%5Ek+%5Cnabla%5Em+R%26%23124%3B+%3D+O_%7Bk%2Cm%7D%28+R%5E%7B1+%2B+m%2F2+%2B+k%7D+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;partial_t^k &#92;nabla^m R&#124; = O_{k,m}( R^{1 + m/2 + k} )' title='&#124;&#92;partial_t^k &#92;nabla^m R&#124; = O_{k,m}( R^{1 + m/2 + k} )' class='latex' />.</p></blockquote>
<p><strong>Proof. </strong>The claim is clear for the round shrinking solitons (which we can lift up to live on the sphere <img src='http://s0.wp.com/latex.php?latex=S%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^3' title='S^3' class='latex' />), so we may assume that the <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution is not round.  By Proposition 5, we may then replace <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' /> by a universal <img src='http://s0.wp.com/latex.php?latex=%5Ckappa_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa_0' title='&#92;kappa_0' class='latex' />.  We may then time shift so that t=0 and rescale so that R(0,x)=1.  If the claim failed, then we could find a sequence <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M_n%2C+g_n%28t%29%2C+x_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M_n, g_n(t), x_n)' title='t &#92;mapsto (M_n, g_n(t), x_n)' class='latex' /> of pointed <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions with <img src='http://s0.wp.com/latex.php?latex=R_n%280%2Cx_n%29%3D1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R_n(0,x_n)=1' title='R_n(0,x_n)=1' class='latex' />, but such that some derivative of the curvature goes to infinity at this point.  But this contradicts Theorem 1. <img src='http://s0.wp.com/latex.php?latex=%5CBox&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Box' title='&#92;Box' class='latex' /></p>
<p>Here is another useful consequence:</p>
<p><strong>Exercise 3.</strong> Let <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M_n%2C+g_n%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M_n, g_n(t))' title='t &#92;mapsto (M_n, g_n(t))' class='latex' /> be a sequence of three-dimensional <img src='http://s0.wp.com/latex.php?latex=%5Ckappa_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa_n' title='&#92;kappa_n' class='latex' />-solutions, and let <img src='http://s0.wp.com/latex.php?latex=x_n%2C+y_n+%5Cin+M_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_n, y_n &#92;in M_n' title='x_n, y_n &#92;in M_n' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=t_n+%5Cleq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_n &#92;leq 0' title='t_n &#92;leq 0' class='latex' />.  If <img src='http://s0.wp.com/latex.php?latex=R_n%28t_n%2Cx_n%29+d_%7Bg%28t_n%29%7D%28x_n%2Cy_n%29%5E2+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R_n(t_n,x_n) d_{g(t_n)}(x_n,y_n)^2 &#92;to &#92;infty' title='R_n(t_n,x_n) d_{g(t_n)}(x_n,y_n)^2 &#92;to &#92;infty' class='latex' />, show that <img src='http://s0.wp.com/latex.php?latex=R_n%28t_n%2Cy_n%29+d_%7Bg%28t_n%29%7D%28x_n%2Cy_n%29%5E2+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R_n(t_n,y_n) d_{g(t_n)}(x_n,y_n)^2 &#92;to &#92;infty' title='R_n(t_n,y_n) d_{g(t_n)}(x_n,y_n)^2 &#92;to &#92;infty' class='latex' />.  (Note that this generalises Corollary 1 or Exercise 2.  Hint: the claim is trivial in the round case, so assume non-roundness; then apply universality and compactness.) <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:center;">&#8211; Global structure of <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions &#8211;</p>
<p>Roughly speaking, the above theory tells us that the geometry around any point <img src='http://s0.wp.com/latex.php?latex=%28t%2Cx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t,x)' title='(t,x)' class='latex' /> in a 3-dimensional <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions has only bounded complexity if we only move <img src='http://s0.wp.com/latex.php?latex=O%28+R%28t%2Cx%29%5E%7B-1%2F2%7D+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='O( R(t,x)^{-1/2} )' title='O( R(t,x)^{-1/2} )' class='latex' /> in space and <img src='http://s0.wp.com/latex.php?latex=O%28+R%28t%2Cx%29%5E%7B-1%7D+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='O( R(t,x)^{-1} )' title='O( R(t,x)^{-1} )' class='latex' /> in time. This is about as good a control on the local geometry of such solutions as we can hope for; we now turn to the global geometry.  [<em>Aside</em>: It is unlikely that the space of 3-dimensional <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions is finite dimensional, as it is in the 2-dimensional case; see for instance Example 1.4 of <a href="http://arxiv.org/abs/math.DG/0303109">Perelman's second paper</a> for what is probably an infinite-dimensional family of <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions.]</p>
<p>Let us begin with non-compact 3-dimensional <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions.   A key point is that if such solutions are not already round cylinders (or quotients thereof), they must mostly resemble such cylinders.</p>
<blockquote><p><strong>Definition 1.</strong> (Necks)  Let <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon &gt; 0' title='&#92;varepsilon &gt; 0' class='latex' />.  An <em><img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-neck </em>in a Riemannian 3-manifold <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g)' title='(M,g)' class='latex' /> centred at a point <img src='http://s0.wp.com/latex.php?latex=x+%5Cin+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x &#92;in M' title='x &#92;in M' class='latex' /> is a diffeomorphism <img src='http://s0.wp.com/latex.php?latex=%5Cphi%3A+S%5E2+%5Ctimes+%28-%5Cfrac%7B1%7D%7B%5Cvarepsilon%7D%2C+%5Cfrac%7B1%7D%7B%5Cvarepsilon%7D+%29+%5Cto+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;phi: S^2 &#92;times (-&#92;frac{1}{&#92;varepsilon}, &#92;frac{1}{&#92;varepsilon} ) &#92;to M' title='&#92;phi: S^2 &#92;times (-&#92;frac{1}{&#92;varepsilon}, &#92;frac{1}{&#92;varepsilon} ) &#92;to M' class='latex' /> from a long cylinder to M, such that the normalised pullback metric <img src='http://s0.wp.com/latex.php?latex=R%28x%29+%5Cphi%5E%2A+g&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(x) &#92;phi^* g' title='R(x) &#92;phi^* g' class='latex' /> lies within <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' /> of the standard round metric on the cylinder in the <img src='http://s0.wp.com/latex.php?latex=C%5E%7B%5Clfloor+1%2F%5Cvarepsilon+%5Crfloor%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C^{&#92;lfloor 1/&#92;varepsilon &#92;rfloor}' title='C^{&#92;lfloor 1/&#92;varepsilon &#92;rfloor}' class='latex' /> topology, where we require of course that R(x) &#62; 0.  The number <img src='http://s0.wp.com/latex.php?latex=R%28x%29%5E%7B-1%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(x)^{-1/2}' title='R(x)^{-1/2}' class='latex' /> is called the <em>width scale</em> of the neck, and <img src='http://s0.wp.com/latex.php?latex=R%28x%29%5E%7B-1%2F2%7D%2F%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(x)^{-1/2}/&#92;varepsilon' title='R(x)^{-1/2}/&#92;varepsilon' class='latex' /> is the <em>length scale</em>.</p></blockquote>
<p>Clearly, the notion of a <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-neck is a scale-invariant concept.  Note that if a sequence of pointed manifolds <img src='http://s0.wp.com/latex.php?latex=%28M_n%2Cg_n%2Cx_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M_n,g_n,x_n)' title='(M_n,g_n,x_n)' class='latex' /> is converging geometrically (after rescaling) to a round cylinder <img src='http://s0.wp.com/latex.php?latex=S%5E2+%5Ctimes+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2 &#92;times {&#92;Bbb R}' title='S^2 &#92;times {&#92;Bbb R}' class='latex' />, then for any <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon &gt; 0' title='&#92;varepsilon &gt; 0' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=x_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_n' title='x_n' class='latex' /> will be in the centre of an <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-neck for sufficiently large n.  Since round cylinders appear prominently as geometric limits, it is then not surprising that <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions, particularly non-compact ones, tend to be awash in <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-necks.  For instance, we have</p>
<blockquote><p><strong>Proposition 6. </strong>For every <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon &gt; 0' title='&#92;varepsilon &gt; 0' class='latex' /> there exists an <img src='http://s0.wp.com/latex.php?latex=A+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='A &gt; 0' title='A &gt; 0' class='latex' /> such that whenever <img src='http://s0.wp.com/latex.php?latex=%28t%2Cx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t,x)' title='(t,x)' class='latex' /> is a point in a 3-dimensional non-compact <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution of strictly positive curvature and <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%3A+%5B0%2C%2B%5Cinfty%29+%5Cto+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma: [0,+&#92;infty) &#92;to M' title='&#92;gamma: [0,+&#92;infty) &#92;to M' class='latex' /> is a unit speed minimising geodesic from x to infinity (such things can easily be shown to exist by compactness arguments) at time t, then every point in <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%28%5BA+R%28x%29%5E%7B-1%2F2%7D%2C%2B%5Cinfty%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma([A R(x)^{-1/2},+&#92;infty))' title='&#92;gamma([A R(x)^{-1/2},+&#92;infty))' class='latex' /> lies in the centre of an <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-neck at time t.</p></blockquote>
<p><strong>Proof. </strong> By time shifting we can take t=0.  Suppose the claim is not the case, then we have a sequence <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M_n%2C+g_n%28t%29%2C+x_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M_n, g_n(t), x_n)' title='t &#92;mapsto (M_n, g_n(t), x_n)' class='latex' /> of pointed 3-dimensional non-compact <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions of strictly positive curvature and <img src='http://s0.wp.com/latex.php?latex=y_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y_n' title='y_n' class='latex' /> on a minimising geodesic from <img src='http://s0.wp.com/latex.php?latex=x_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_n' title='x_n' class='latex' /> to infinity such that <img src='http://s0.wp.com/latex.php?latex=d_n%28x_n%2Cy_n%29%5E2+R_n%28x_n%29+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d_n(x_n,y_n)^2 R_n(x_n) &#92;to &#92;infty' title='d_n(x_n,y_n)^2 R_n(x_n) &#92;to &#92;infty' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=y_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y_n' title='y_n' class='latex' /> is not the centre of a <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-neck at time zero.  By Exercise 3 we thus have <img src='http://s0.wp.com/latex.php?latex=d_n%28x_n%2Cy_n%29%5E2+R_n%28y_n%29+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d_n(x_n,y_n)^2 R_n(y_n) &#92;to &#92;infty' title='d_n(x_n,y_n)^2 R_n(y_n) &#92;to &#92;infty' class='latex' />.  Let us now rescale so that <img src='http://s0.wp.com/latex.php?latex=R%28y_n%29+%3D+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(y_n) = 1' title='R(y_n) = 1' class='latex' />.  Since the <img src='http://s0.wp.com/latex.php?latex=M_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M_n' title='M_n' class='latex' /> are non-compact, they are non-round and so by Proposition 5 we can take <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' /> to be universal, at which point by Perelman compactness (Theorem 1) we can pass to a subsequence and assume that <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M_n%2Cg_n%28t%29%2Cy_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M_n,g_n(t),y_n)' title='t &#92;mapsto (M_n,g_n(t),y_n)' class='latex' /> is converging to a limit <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M_%5Cinfty%2Cg_%5Cinfty%28t%29%2Cy_%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M_&#92;infty,g_&#92;infty(t),y_&#92;infty)' title='t &#92;mapsto (M_&#92;infty,g_&#92;infty(t),y_&#92;infty)' class='latex' />, which is also a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution.  Since <img src='http://s0.wp.com/latex.php?latex=d_n%28x_n%2Cy_n%29+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d_n(x_n,y_n) &#92;to &#92;infty' title='d_n(x_n,y_n) &#92;to &#92;infty' class='latex' />, we see that the limit manifold contains a minimising geodesic line through <img src='http://s0.wp.com/latex.php?latex=y_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y_&#92;infty' title='y_&#92;infty' class='latex' />, and hence by the Cheeger-Gromoll splitting theorem (Theorem 2 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/30/285g-lecture-16-classification-of-asymptotic-gradient-shrinking-solitons/">Lecture 16</a>) <img src='http://s0.wp.com/latex.php?latex=M_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M_&#92;infty' title='M_&#92;infty' class='latex' /> must split into the product of a line and a positively curved manifold.   By Proposition 2, we conclude that <img src='http://s0.wp.com/latex.php?latex=M_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M_&#92;infty' title='M_&#92;infty' class='latex' /> is either a cylinder <img src='http://s0.wp.com/latex.php?latex=S%5E2+%5Ctimes+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2 &#92;times {&#92;Bbb R}' title='S^2 &#92;times {&#92;Bbb R}' class='latex' /> or a projective cylinder <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E2+%5Ctimes+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^2 &#92;times {&#92;Bbb R}' title='&#92;Bbb{RP}^2 &#92;times {&#92;Bbb R}' class='latex' />.</p>
<p>The latter can be ruled out by topological considerations; a positively curved complete non-compact 3-manifold <img src='http://s0.wp.com/latex.php?latex=M_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M_n' title='M_n' class='latex' /> is homoemorphic to <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+R%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb R}^3' title='{&#92;Bbb R}^3' class='latex' /> by the <a href="http://en.wikipedia.org/wiki/Soul_theorem">soul theorem</a>, and so does not contain any embedded <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^2' title='&#92;Bbb{RP}^2' class='latex' /> with trivial normal bundle.  (In any event, for applications to the Poincaré conjecture one can always assume that no such embedded projective plane exists in any manifold being studied.)  So <img src='http://s0.wp.com/latex.php?latex=M_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M_&#92;infty' title='M_&#92;infty' class='latex' /> is a round cylinder, and thus <img src='http://s0.wp.com/latex.php?latex=y_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y_n' title='y_n' class='latex' /> is the centre of an <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-neck, a contradiction, and the claim follows. <img src='http://s0.wp.com/latex.php?latex=%5CBox&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Box' title='&#92;Box' class='latex' /></p>
<p>There is a variant of Proposition 6 that works in the compact case also:</p>
<blockquote><p><strong>Proposition 7. </strong>For every <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon &gt; 0' title='&#92;varepsilon &gt; 0' class='latex' /> there exists an <img src='http://s0.wp.com/latex.php?latex=A+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='A &gt; 0' title='A &gt; 0' class='latex' /> such that whenever <img src='http://s0.wp.com/latex.php?latex=%28t%2Cx%29%2C+%28t%2Cy%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t,x), (t,y)' title='(t,x), (t,y)' class='latex' /> are points in a 3-dimensional <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution (either compact or noncompact) then at time t, any point on the minimising geodesic between x and y at a distance at least <img src='http://s0.wp.com/latex.php?latex=A+R%28x%29%5E%7B-1%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='A R(x)^{-1/2}' title='A R(x)^{-1/2}' class='latex' /> from x and <img src='http://s0.wp.com/latex.php?latex=A+R%28y%29%5E%7B-1%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='A R(y)^{-1/2}' title='A R(y)^{-1/2}' class='latex' /> from y, lies in the centre of an <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-neck at time t.</p></blockquote>
<p><strong>Proof.</strong> We can repeat the proof of Proposition 6. The one non-trivial task is the topological one, namely to show that M does not contain an embedded <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^2' title='&#92;Bbb{RP}^2' class='latex' /> with trivial normal bundle in the compact case (the non-compact case already being covered in Proposition 6). But M is compact and has strictly positive curvature (thanks to Proposition 2) and so by Hamilton&#8217;s <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=664497">rounding theorem</a>, is diffeomorphic to a spherical space form <img src='http://s0.wp.com/latex.php?latex=S%5E3%2F%5CGamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^3/&#92;Gamma' title='S^3/&#92;Gamma' class='latex' /> for some finite <img src='http://s0.wp.com/latex.php?latex=%5CGamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Gamma' title='&#92;Gamma' class='latex' />; in particular the <a href="http://en.wikipedia.org/wiki/Fundamental_group">fundamental group</a> <img src='http://s0.wp.com/latex.php?latex=%5Cpi_1%28M%29+%5Cequiv+%5CGamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;pi_1(M) &#92;equiv &#92;Gamma' title='&#92;pi_1(M) &#92;equiv &#92;Gamma' class='latex' /> is finite. On the other hand, an embedded <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^2' title='&#92;Bbb{RP}^2' class='latex' /> with trivial normal bundle cannot separate M (as its <a href="http://en.wikipedia.org/wiki/Euler_characteristic">Euler characteristic</a> is 1) and so a closed loop in M can have a non-trivial intersection number with such a projective plane (using the normal bundle to give a sign to each intersection), leading to a non-trivial homomorphism from <img src='http://s0.wp.com/latex.php?latex=%5Cpi_1%28M%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;pi_1(M)' title='&#92;pi_1(M)' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+Z%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb Z}' title='{&#92;Bbb Z}' class='latex' />, contradicting the finiteness of the fundamental group. [An alternate argument would be to use Perelman compactness to extract a non-compact (but positively curved) limiting <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution from a sequence of increasingly long compact <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions. Proposition 6 prohibits the limiting solutions from asymptotically looking like <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E2+%5Ctimes+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^2 &#92;times {&#92;Bbb R}' title='&#92;Bbb{RP}^2 &#92;times {&#92;Bbb R}' class='latex' />, and so the long compact solutions cannot have such projective necks either.] <img src='http://s0.wp.com/latex.php?latex=%5CBox&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Box' title='&#92;Box' class='latex' /></p>
<p>Informally, the above proposition shows that any two sufficiently far apart points in a compact <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution will be separated almost entirely by <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-necks. Since the only way that necks can be glued together is by forming a tube, one can then show the following two corollaries:</p>
<blockquote><p><strong>Corollary 4. </strong>(Description of non-compact positively curved <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions)  For every <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon &gt; 0' title='&#92;varepsilon &gt; 0' class='latex' /> there exists <img src='http://s0.wp.com/latex.php?latex=A+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='A &gt; 0' title='A &gt; 0' class='latex' /> such that for every non-compact 3-dimensional positively curved <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution  <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> and time t there exists a point <img src='http://s0.wp.com/latex.php?latex=p+%5Cin+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='p &#92;in M' title='p &#92;in M' class='latex' /> such that at time t</p>
<ol>
<li>Every point outside of <img src='http://s0.wp.com/latex.php?latex=B%28+p%2C+A+R%28p%29%5E%7B-1%2F2%7D+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B( p, A R(p)^{-1/2} )' title='B( p, A R(p)^{-1/2} )' class='latex' /> lies in an <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-neck (and in particular, the exterior of this ball is topologically a half-infinite cylinder <img src='http://s0.wp.com/latex.php?latex=S%5E2+%5Ctimes+%5B0%2C%2B%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2 &#92;times [0,+&#92;infty)' title='S^2 &#92;times [0,+&#92;infty)' class='latex' />); and</li>
<li>Inside the ball <img src='http://s0.wp.com/latex.php?latex=B%28+p%2C+A+R%28p%29%5E%7B-1%2F2%7D+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B( p, A R(p)^{-1/2} )' title='B( p, A R(p)^{-1/2} )' class='latex' /> (which is topologically a standard 3-ball by the soul theorem) all sectional curvatures are comparable to R(p) modulo constants C depending only on <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />, and the volume of the ball is comparable to <img src='http://s0.wp.com/latex.php?latex=R%28p%29%5E%7B-3%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(p)^{-3/2}' title='R(p)^{-3/2}' class='latex' /> modulo similar constants C.</li>
</ol>
</blockquote>
<p>(The control inside the ball is coming from results such as Corollary 3, as well as the non-collapsed nature of M.)</p>
<p>In the language of <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2334563">Morgan-Tian</a>, we have described non-compact positively curved 3-dimensional <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions as <em>C-capped <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-tubes</em>.  [Actually, Morgan-Tian prove a little more: they control the time evolution of the necks and not just individual time slices, leading to the notion of a <em>strong <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-neck</em>.  See Section 9.8 of that book for details, as well as a precise definition of the C-capped <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-tubes.]  Combined with Proposition 2, we now have a satisfactory description of non-compact <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions: they are either round cylinders (and thus doubly infinite <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-tubes), oriented quotients of round cylinders (and thus a half-infinite <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-tube capped off by a punctured <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^3' title='&#92;Bbb{RP}^3' class='latex' />), oriented quotients of round cylinders (and thus containing an <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^2' title='&#92;Bbb{RP}^2' class='latex' /> with trivial normal bundle), or a half-infinite <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-tube capped off by a 3-ball.</p>
<p>For compact <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions, we have something similar:</p>
<blockquote><p><strong>Proposition 8.</strong> (Characterisation of large compact <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions) For every <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon &gt; 0' title='&#92;varepsilon &gt; 0' class='latex' /> there exists <img src='http://s0.wp.com/latex.php?latex=A%2C+A%27+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='A, A&#039; &gt; 0' title='A, A&#039; &gt; 0' class='latex' /> such that if <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g)' title='t &#92;mapsto (M,g)' class='latex' /> is a compact 3-dimensional <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution with <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7Bdiam%7D%28M%29+%5Cgeq+A%27+%28%5Csup+R%29%5E%7B-1%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{diam}(M) &#92;geq A&#039; (&#92;sup R)^{-1/2}' title='&#92;hbox{diam}(M) &#92;geq A&#039; (&#92;sup R)^{-1/2}' class='latex' /> at some time t, then <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g(t))' title='(M,g(t))' class='latex' /> can be partitioned into an <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-tube (roughly speaking, a region in which every point lies in the middle of an <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-neck, and bordered on both ends by an <img src='http://s0.wp.com/latex.php?latex=S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2' title='S^2' class='latex' />) and two <img src='http://s0.wp.com/latex.php?latex=%28C%2C%5Cvarepsilon%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(C,&#92;varepsilon)' title='(C,&#92;varepsilon)' class='latex' />-caps (roughly speaking, two regions diffeomorphic to either a 3-ball or punctured <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^3' title='&#92;Bbb{RP}^3' class='latex' />, bounded by an <img src='http://s0.wp.com/latex.php?latex=S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2' title='S^2' class='latex' />, in which the sectional curvatures are comparable to a scalar R, the diameter is comparable to <img src='http://s0.wp.com/latex.php?latex=R%5E%7B-1%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R^{-1/2}' title='R^{-1/2}' class='latex' />, and volume comparable to <img src='http://s0.wp.com/latex.php?latex=R%5E%7B-3%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R^{-3/2}' title='R^{-3/2}' class='latex' />).  See Section 9.8 of <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2334563">Morgan-Tian</a> for precise definitions.</p></blockquote>
<p>The topological characterisation of the caps (that they are either 3-balls or punctured <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^3' title='&#92;Bbb{RP}^3' class='latex' />s) follows from the corresponding characterisations of the caps in the non-compact case, followed by a compactness argument.    Note that the round compact manifolds have diameter <img src='http://s0.wp.com/latex.php?latex=O%28R%5E%7B-1%2F2%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='O(R^{-1/2})' title='O(R^{-1/2})' class='latex' />, where R is the constant curvature, and thus are not covered by the above Proposition.</p>
<p>By considering the various topologies for the caps, we see from basic topology then tells us that the manifolds in this case are homeomorphic to either <img src='http://s0.wp.com/latex.php?latex=S%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^3' title='S^3' class='latex' /> or <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+RP%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb RP}^3' title='{&#92;Bbb RP}^3' class='latex' />, or <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+RP%7D%5E3+%5C%23+%7B%5CBbb+RP%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb RP}^3 &#92;# {&#92;Bbb RP}^3' title='{&#92;Bbb RP}^3 &#92;# {&#92;Bbb RP}^3' class='latex' />.  The latter has infinite fundamental group, though, and thus not homeomorphic to a spherical space form; thus it cannot actually arise since Hamilton&#8217;s rounding theorem asserts that all compact manifolds of positive curvature are homeomorphic to spherical space forms.</p>
<p>Finally, we turn to small compact non-round <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions.</p>
<blockquote><p><strong>Proposition 9.</strong> (Characterisation of small compact <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions) Let <img src='http://s0.wp.com/latex.php?latex=C+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C &gt; 0' title='C &gt; 0' class='latex' />, and let <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g)' title='t &#92;mapsto (M,g)' class='latex' /> be a compact 3-dimensional <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution with <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7Bdiam%7D%28M%29+%5Cleq+C+%28%5Csup+R%29%5E%7B-1%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{diam}(M) &#92;leq C (&#92;sup R)^{-1/2}' title='&#92;hbox{diam}(M) &#92;leq C (&#92;sup R)^{-1/2}' class='latex' /> at some time t which is not round, then all sectional curvatures are comparable up to constants depending on C, the diameter is comparable to <img src='http://s0.wp.com/latex.php?latex=%28%5Csup+R%29%5E%7B-1%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;sup R)^{-1/2}' title='(&#92;sup R)^{-1/2}' class='latex' /> up to similar constants, the volume is comparable to <img src='http://s0.wp.com/latex.php?latex=%28%5Csup+R%29%5E%7B-3%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;sup R)^{-3/2}' title='(&#92;sup R)^{-3/2}' class='latex' />, and the manifold is topologically either <img src='http://s0.wp.com/latex.php?latex=S%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^3' title='S^3' class='latex' /> or <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+RP%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb RP}^3' title='{&#92;Bbb RP}^3' class='latex' />.</p></blockquote>
<p><strong>Proof.</strong> The diameter, curvature, and volume bounds follow from the compactness theory.  To get the topological type, observe from the treatment of the compact soliton case that as M is not round, the asymptotic gradient shrinking soliton is non-compact, and thus must be a cylinder or one of its quotients.  In particular this implies that as one goes back in time, the manifold M must eventually become large in the sense of Proposition 8.  Since the manifolds in that proposition were topologically either <img src='http://s0.wp.com/latex.php?latex=S%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^3' title='S^3' class='latex' /> or <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+RP%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb RP}^3' title='{&#92;Bbb RP}^3' class='latex' />, the same is true here. <img src='http://s0.wp.com/latex.php?latex=%5CBox&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Box' title='&#92;Box' class='latex' /></p>
<p>Putting all of the above results together, we obtain Proposition 1 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/16/285g-lecture-12-high-curvature-regions-of-ricci-flow-and-%ce%ba-solutions/">Lecture 12</a> (modulo some imprecision in the definitions which I have decided not to detail here).</p>
<p>[<em>Updated</em>, June 3: Proposition 9 added.]</p>
]]></content:encoded>
</item>
<item>
<title><![CDATA[285G, Lecture 16: Classification of asymptotic gradient shrinking solitons]]></title>
<link>http://terrytao.wordpress.com/2008/05/30/285g-lecture-16-classification-of-asymptotic-gradient-shrinking-solitons/</link>
<pubDate>Sat, 31 May 2008 06:14:33 +0000</pubDate>
<dc:creator>Terence Tao</dc:creator>
<guid>http://terrytao.wordpress.com/2008/05/30/285g-lecture-16-classification-of-asymptotic-gradient-shrinking-solitons/</guid>
<description><![CDATA[In the previous lecture, we showed that every -solution generated at least one asymptotic gradient s]]></description>
<content:encoded><![CDATA[<p>In the <a href="http://terrytao.wordpress.com/2008/05/27/285g-lecture-15-geometric-limits-of-ricci-flows-and-asymptotic-gradient-shrinking-solitons/">previous lecture</a>, we showed that every <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution generated at least one asymptotic gradient shrinking soliton <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' />. This soliton is known to have the following properties:</p>
<ol>
<li>It is ancient: t ranges over <img src='http://s0.wp.com/latex.php?latex=%28-%5Cinfty%2C0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(-&#92;infty,0)' title='(-&#92;infty,0)' class='latex' />.</li>
<li>It is a Ricci flow.</li>
<li>M is complete and connected.</li>
<li>The Riemann curvature is non-negative (though it could theoretically be unbounded).</li>
<li><img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7BdR%7D%7Bdt%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{dR}{dt}' title='&#92;frac{dR}{dt}' class='latex' /> is non-negative.</li>
<li>M is <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsed.</li>
<li>M is not flat.</li>
<li>It obeys the gradient shrinking soliton equation</li>
</ol>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRic%7D+%2B+%5Chbox%7BHess%7D%28f%29+%3D+%5Cfrac%7B1%7D%7B2%5Ctau%7D+g&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Ric} + &#92;hbox{Hess}(f) = &#92;frac{1}{2&#92;tau} g' title='&#92;hbox{Ric} + &#92;hbox{Hess}(f) = &#92;frac{1}{2&#92;tau} g' class='latex' /> (1)</p>
<p style="padding-left:60px;">for some smooth f.</p>
<p>The main result of this lecture is to classify all such solutions in low dimension:</p>
<blockquote><p><strong>Theorem 1.</strong> (Classification of asymptotic gradient shrinking solitons) Let <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> be as above, and suppose that the dimension d is at most 3. Then one of the following is true (up to isometry and rescaling):</p>
<ol>
<li>d=2,3 and M is a round shrinking spherical space form (i.e. a round shrinking <img src='http://s0.wp.com/latex.php?latex=S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2' title='S^2' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=S%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^3' title='S^3' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^2' title='&#92;Bbb{RP}^2' class='latex' />, or <img src='http://s0.wp.com/latex.php?latex=S%5E3%2F%5CGamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^3/&#92;Gamma' title='S^3/&#92;Gamma' class='latex' /> for some finite group <img src='http://s0.wp.com/latex.php?latex=%5CGamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Gamma' title='&#92;Gamma' class='latex' /> acting freely on <img src='http://s0.wp.com/latex.php?latex=S%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^3' title='S^3' class='latex' />).</li>
<li>d=3 and M is the round shrinking cylinder <img src='http://s0.wp.com/latex.php?latex=S%5E2+%5Ctimes+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2 &#92;times {&#92;Bbb R}' title='S^2 &#92;times {&#92;Bbb R}' class='latex' /> or the oriented or unoriented quotient of this cylinder by an involution.</li>
</ol>
</blockquote>
<p>The case d=2 of this theorem is due to Hamilton; the compact d=3 case is due to  Ivey; and the full d=3 case was sketched out by Perelman.  In higher dimension, partial results towards the full classification (and also relaxing many of the hypotheses 1-8) have been established <a class="snap_noshots" href="http://www.math.ucla.edu/%7Ewylie/preprints/ConformalFlat.pdf">by Petersen-Wylie,</a> <a class="snap_noshots" href="http://arxiv.org/abs/0710.3194">by Ni-Wallach</a>, and <a class="snap_noshots" href="http://arxiv.org/abs/0710.5579">by Naber</a>; these papers also give alternate proofs of Perelman&#8217;s classification.</p>
<p>To prove this theorem, we induct on dimension.  In 1 dimension, all manifolds are flat and so the claim is trivial.  We will thus take d=2 or d=3, and assume that the result has already been established for dimension d-1.  We will then split into several cases:</p>
<ol>
<li>Case 1: Ricci curvature has a zero eigenvector at some point.  In this case we can use Hamilton&#8217;s splitting theorem to reduce the dimension by one, at which point we can use the induction hypothesis.</li>
<li>Case 2: Manifold noncompact, and Ricci curvature is positive and unbounded.  In this case we can take a further geometric limit (using some Toponogov theory on the asymptotics of rays in a positively curved manifold) which is a round cylinder (or quotient thereof), and also a gradient steady soliton.  One can easily rule out such an object by studying the potential function of that soliton on a closed loop.</li>
<li>Case 3: Manifold noncompact, and Ricci curvature is positive and bounded.  Here we shall follow the gradient curves of f using some identities arising from the gradient shrinking soliton equation to get a contradiction.</li>
<li>Case 4: Manifold compact, and curvature positive.  Here we shall use Hamilton&#8217;s rounding theorem to show that one is a round shrinking sphere or spherical space form.</li>
</ol>
<p>We will follow <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2334563">Morgan-Tian</a>&#8216;s treatment of <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0211159">Perelman&#8217;s argument</a>; see also the <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0605667">notes of Kleiner-Lott</a>, the paper of <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2233789">Cao-Zhu</a>, and the <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2274812">book of Chow-Lu-Ni</a> for other treatments of this argument.</p>
<p><!--more--></p>
<p style="text-align:center;">&#8211; Case 1: Ricci curvature degenerates at some point &#8211;</p>
<p>This case cannot happen in two dimensions.  Indeed, since the Ricci curvature is conformal in this case, the only way that the Ricci curvature can degenerate is if the scalar curvature vanishes also.  But then the strong maximum principle (Exercise 7 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/19/285g-lecture-13-li-yau-hamilton-harnack-inequalities-and-%ce%ba-solutions/">Lecture 13</a>) forces the gradient shrinking soliton to be flat at all sufficiently early times (and hence at all times), a contradiction.  (It turns out that this application of strong maximum principle can be extended to cover the case in which one does not have bounded curvature.)</p>
<p>So now suppose that we are in three dimensions with bounded Ricci curvature, and a point where the Ricci curvature vanishes.  Then by Hamilton&#8217;s splitting theorem (Proposition 1 from <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2274812">Lecture 13</a>) the gradient shrinking soliton locally splits into the product of a two-dimensional flow and a line (for sufficiently early times, at least), with the Ricci curvature being degenerate along these lines that foliate the flow.  (Again, one has to extend the strong maximum principle argument to cover the case of unbounded curvature, but this can be done.) In particular, from (1) we see that <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BHess%7D%28f%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Hess}(f)' title='&#92;hbox{Hess}(f)' class='latex' /> is constant and strictly positive along these lines; in other words, f is strictly convex (and quadratic) along these lines.  As a consequence, the lines cannot loop back upon themselves.</p>
<p>By lifting to a double cover if necessary, we can find a global unit vector field X along these lines, thus <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRic%7D%28X%2C%5Ccdot%29+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Ric}(X,&#92;cdot) = 0' title='&#92;hbox{Ric}(X,&#92;cdot) = 0' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Cnabla+X+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla X = 0' title='&#92;nabla X = 0' class='latex' />.  If we set <img src='http://s0.wp.com/latex.php?latex=F+%3A%3D+%5Cnabla_X+f&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='F := &#92;nabla_X f' title='F := &#92;nabla_X f' class='latex' />, we conclude from (1) that <img src='http://s0.wp.com/latex.php?latex=%5Cnabla+F+%3D+X+%2F+2%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla F = X / 2&#92;tau' title='&#92;nabla F = X / 2&#92;tau' class='latex' />, thus the level sets of F have X as a unit normal.  Thus, at any fixed time, we use F to <em>globally</em> split the manifold M (or a double cover thereof) as the product of a line and a two-dimensional manifold (given by the level sets of F).  Applying the induction hypothesis, we conclude that M (or a double cover) is a product of a line and a round shrinking <img src='http://s0.wp.com/latex.php?latex=S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2' title='S^2' class='latex' /> or <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^2' title='&#92;Bbb{RP}^2' class='latex' /> (as these are the only two-dimensional spherical space forms), at which point we end up in alternative 2 of Theorem 1.  (We initially establish this fact only for sufficiently early times, but then by uniqueness of Ricci flow one obtains it for late times also.)</p>
<p><strong>Remark 1.</strong> We can also proceed here using the global splitting theorem from Lemma 9.1 of <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=862046">Hamilton&#8217;s paper</a>.  <img src='http://s0.wp.com/latex.php?latex=%5CBox&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Box' title='&#92;Box' class='latex' /></p>
<p style="text-align:center;">&#8211; Case 2: Manifold non-compact, curvature positive and unbounded &#8211;</p>
<p>Now we handle the case in which M is non-compact (and in particular has a meaningful notion of convergence to spatial infinity) with Ricci curvature strictly positive and unbounded.  In particular one has a sequence of points <img src='http://s0.wp.com/latex.php?latex=x_n+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_n &#92;to &#92;infty' title='x_n &#92;to &#92;infty' class='latex' /> in M such that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=R%28x_n%29+d%28x_0%2Cx_n%29%5E2+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(x_n) d(x_0,x_n)^2 &#92;to &#92;infty' title='R(x_n) d(x_0,x_n)^2 &#92;to &#92;infty' class='latex' /> (2)</p>
<p>at some time (which we can normalise to t=-1), where we arbitrarily pick an origin <img src='http://s0.wp.com/latex.php?latex=x_0+%5Cin+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0 &#92;in M' title='x_0 &#92;in M' class='latex' />.  Thus the curvature is not decaying as fast as <img src='http://s0.wp.com/latex.php?latex=1%2Fd%28x_0%2C%5Ccdot%29%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='1/d(x_0,&#92;cdot)^2' title='1/d(x_0,&#92;cdot)^2' class='latex' /> at infinity, and may even be unbounded.  Henceforth we normalise t as t=-1 and write g for g(-1).</p>
<p>The basic idea here is to look at the rescaled pointed manifolds <img src='http://s0.wp.com/latex.php?latex=%28M_n%2C+g_n%2C+p_n%29+%3A%3D+%28M%2C+R%28x_n%29%5E%7B1%2F2%7D+g%2C+x_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M_n, g_n, p_n) := (M, R(x_n)^{1/2} g, x_n)' title='(M_n, g_n, p_n) := (M, R(x_n)^{1/2} g, x_n)' class='latex' /> and extract a limit in which the original base point <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' /> has now been sent off to infinity (thanks to (2)).  There is a technical obstacle to doing this, though, which is that the rescaled manifolds have bounded curvature at <img src='http://s0.wp.com/latex.php?latex=x_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_n' title='x_n' class='latex' /> (indeed, it has been normalised to equal 1) but might have unbounded curvature at nearby points <img src='http://s0.wp.com/latex.php?latex=y_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y_n' title='y_n' class='latex' /> with respect to the rescaled metric (i.e. points <img src='http://s0.wp.com/latex.php?latex=y_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y_n' title='y_n' class='latex' /> within distance <img src='http://s0.wp.com/latex.php?latex=O%28+R%28x_n%29%5E%7B-1%2F2%7D+%29+%3D+o%28+d%28x_n%2Cx_0%29+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='O( R(x_n)^{-1/2} ) = o( d(x_n,x_0) )' title='O( R(x_n)^{-1/2} ) = o( d(x_n,x_0) )' class='latex' /> in the original metric) because such points may have significantly higher curvature than <img src='http://s0.wp.com/latex.php?latex=x_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_n' title='x_n' class='latex' /> (e.g. <img src='http://s0.wp.com/latex.php?latex=R%28y_n%29+%5Cgeq+4+R%28x_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(y_n) &#92;geq 4 R(x_n)' title='R(y_n) &#92;geq 4 R(x_n)' class='latex' />).  But it is easy to resolve this: simply pick <img src='http://s0.wp.com/latex.php?latex=y_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y_n' title='y_n' class='latex' /> instead of <img src='http://s0.wp.com/latex.php?latex=x_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_n' title='x_n' class='latex' />.  Now <img src='http://s0.wp.com/latex.php?latex=y_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y_n' title='y_n' class='latex' /> may itself be close to another point of even higher curvature, but we can then move that point instead.  We can continue in this manner, moving in a geometrically decreasing sequence of distances, until we stop (which we must, since the manifold is smooth and so curvature is locally bounded).  The precise result of this &#8220;point-picking argument&#8221;, originally due to Hamilton, that we will need is as follows:</p>
<p><strong>Exercise 1. </strong>(Point picking lemma) Assuming that (2) holds for some sequence <img src='http://s0.wp.com/latex.php?latex=x_n+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_n &#92;to &#92;infty' title='x_n &#92;to &#92;infty' class='latex' />, show that there exists another sequence <img src='http://s0.wp.com/latex.php?latex=y_n+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y_n &#92;to &#92;infty' title='y_n &#92;to &#92;infty' class='latex' /> also obeying (2), and such that for any <img src='http://s0.wp.com/latex.php?latex=A+%26%2362%3B+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='A &gt; 1' title='A &gt; 1' class='latex' />, and for all n sufficiently large depending on A, we have <img src='http://s0.wp.com/latex.php?latex=R%28z_n%29+%5Cleq+4+R%28y_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(z_n) &#92;leq 4 R(y_n)' title='R(z_n) &#92;leq 4 R(y_n)' class='latex' /> for all <img src='http://s0.wp.com/latex.php?latex=z_n+%5Cin+B%28+y_n%2C+A+R%28y_n%29%5E%7B-1%2F2%7D+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='z_n &#92;in B( y_n, A R(y_n)^{-1/2} )' title='z_n &#92;in B( y_n, A R(y_n)^{-1/2} )' class='latex' />. If the original manifold had unbounded curvature, show that we can also ensure that <img src='http://s0.wp.com/latex.php?latex=R%28y_n%29+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(y_n) &#92;to &#92;infty' title='R(y_n) &#92;to &#92;infty' class='latex' />.  <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>We now let <img src='http://s0.wp.com/latex.php?latex=y_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y_n' title='y_n' class='latex' /> be as above, and consider the rescaled manifolds <img src='http://s0.wp.com/latex.php?latex=%28M_n%2C+g_n%2C+p_n%29+%3A%3D+%28M%2C+R%28y_n%29%5E%7B1%2F2%7D+g%2C+y_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M_n, g_n, p_n) := (M, R(y_n)^{1/2} g, y_n)' title='(M_n, g_n, p_n) := (M, R(y_n)^{1/2} g, y_n)' class='latex' />.  Using Hamilton&#8217;s compactness theorem (Theorem 2 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/27/285g-lecture-15-geometric-limits-of-ricci-flows-and-asymptotic-gradient-shrinking-solitons/">Lecture 15</a>) we may assume that these manifolds converge geometrically to a limit <img src='http://s0.wp.com/latex.php?latex=%28M_%5Cinfty%2C+g_%5Cinfty%2C+p_%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M_&#92;infty, g_&#92;infty, p_&#92;infty)' title='(M_&#92;infty, g_&#92;infty, p_&#92;infty)' class='latex' /> of nonnegative Riemann curvature whose scalar curvature is at most 4 (and is equal to 1 at <img src='http://s0.wp.com/latex.php?latex=p_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='p_&#92;infty' title='p_&#92;infty' class='latex' />); in particular the limit has bounded curvature.  From the analogue of (2) for <img src='http://s0.wp.com/latex.php?latex=y_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y_n' title='y_n' class='latex' /> we have <img src='http://s0.wp.com/latex.php?latex=d_%7Bg_n%7D%28+x_0%2C+p_n+%29+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d_{g_n}( x_0, p_n ) &#92;to &#92;infty' title='d_{g_n}( x_0, p_n ) &#92;to &#92;infty' class='latex' />, and so <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' /> has &#8220;escaped to infinity&#8221; in the limit <img src='http://s0.wp.com/latex.php?latex=M_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M_&#92;infty' title='M_&#92;infty' class='latex' /> (this shows in particular that <img src='http://s0.wp.com/latex.php?latex=M_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M_&#92;infty' title='M_&#92;infty' class='latex' /> is non-compact).</p>
<p>Let <img src='http://s0.wp.com/latex.php?latex=r_n+%3A%3D+d%28x_0%2Cy_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_n := d(x_0,y_n)' title='r_n := d(x_0,y_n)' class='latex' />, thus <img src='http://s0.wp.com/latex.php?latex=r_n+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_n &#92;to &#92;infty' title='r_n &#92;to &#92;infty' class='latex' />.  By refining this sequence we may assume that we have rapid growth in the sense that <img src='http://s0.wp.com/latex.php?latex=r_n+%3D+o%28r_%7Bn%2B1%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_n = o(r_{n+1})' title='r_n = o(r_{n+1})' class='latex' />.  Let <img src='http://s0.wp.com/latex.php?latex=x_0y_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0y_n' title='x_0y_n' class='latex' /> be a minimising geodesic from <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=y_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y_n' title='y_n' class='latex' />; by compactness we may assume that the direction of <img src='http://s0.wp.com/latex.php?latex=x_0y_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0y_n' title='x_0y_n' class='latex' /> at <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' /> is convergent.  In particular, the angle subtended between <img src='http://s0.wp.com/latex.php?latex=x_0y_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0y_n' title='x_0y_n' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=x_0y_%7Bn%2B1%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0y_{n+1}' title='x_0y_{n+1}' class='latex' /> is <img src='http://s0.wp.com/latex.php?latex=o%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='o(1)' title='o(1)' class='latex' />.  If we let <img src='http://s0.wp.com/latex.php?latex=y_ny_%7Bn%2B1%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y_ny_{n+1}' title='y_ny_{n+1}' class='latex' /> be a minimising geodesic from <img src='http://s0.wp.com/latex.php?latex=y_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y_n' title='y_n' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=y_%7Bn%2B1%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y_{n+1}' title='y_{n+1}' class='latex' />, we thus see from the triangle inequality and the cosine rule (Lemma 2) that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=d%28y_n%2Cy_%7Bn%2B1%7D%29+%3D+r_%7Bn%2B1%7D+-+r_n+%2B+o%28r_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d(y_n,y_{n+1}) = r_{n+1} - r_n + o(r_n)' title='d(y_n,y_{n+1}) = r_{n+1} - r_n + o(r_n)' class='latex' />. (3)</p>
<p>Using the cosine rule again, we see that the angle subtended between <img src='http://s0.wp.com/latex.php?latex=x_0y_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0y_n' title='x_0y_n' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=y_n+y_%7Bn%2B1%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y_n y_{n+1}' title='y_n y_{n+1}' class='latex' /> is <img src='http://s0.wp.com/latex.php?latex=%5Cpi-o%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;pi-o(1)' title='&#92;pi-o(1)' class='latex' />.  Using relative Toponogov comparison (Exercise 3) we see that the rays <img src='http://s0.wp.com/latex.php?latex=x_0y_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0y_n' title='x_0y_n' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=y_n+y_%7Bn%2B1%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y_n y_{n+1}' title='y_n y_{n+1}' class='latex' /> asymptotically form a minimising geodesic, in the sense that <img src='http://s0.wp.com/latex.php?latex=d%28z%2Cy_n%29+%2B+d%28y_n%2Cw%29+%3D+d%28z%2Cw%29+%2B+o%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d(z,y_n) + d(y_n,w) = d(z,w) + o(1)' title='d(z,y_n) + d(y_n,w) = d(z,w) + o(1)' class='latex' /> for any z, w at a bounded distance away from <img src='http://s0.wp.com/latex.php?latex=y_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y_n' title='y_n' class='latex' /> on <img src='http://s0.wp.com/latex.php?latex=x_0+y_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0 y_n' title='x_0 y_n' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=y_n+y_%7Bn%2B1%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y_n y_{n+1}' title='y_n y_{n+1}' class='latex' /> respectively.  From this, we see in the limit <img src='http://s0.wp.com/latex.php?latex=%28M_%5Cinfty%2C+g_%5Cinfty%2C+p_%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M_&#92;infty, g_&#92;infty, p_&#92;infty)' title='(M_&#92;infty, g_&#92;infty, p_&#92;infty)' class='latex' /> that there exists a minimising geodesic line through <img src='http://s0.wp.com/latex.php?latex=p_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='p_&#92;infty' title='p_&#92;infty' class='latex' />.  But by the Cheeger-Gromoll splitting theorem (Theorem 2) we see that <img src='http://s0.wp.com/latex.php?latex=M_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M_&#92;infty' title='M_&#92;infty' class='latex' /> splits into the product of a line and a manifold <img src='http://s0.wp.com/latex.php?latex=%5CSigma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Sigma' title='&#92;Sigma' class='latex' /> of one dimension less.  This cannot happen in the two-dimensional case d=2, since <img src='http://s0.wp.com/latex.php?latex=%5CSigma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Sigma' title='&#92;Sigma' class='latex' /> becomes one-dimensional and thus flat, and <img src='http://s0.wp.com/latex.php?latex=M_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M_&#92;infty' title='M_&#92;infty' class='latex' /> has non-zero curvature at <img src='http://s0.wp.com/latex.php?latex=p_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='p_&#92;infty' title='p_&#92;infty' class='latex' /> (indeed, its scalar curvature is equal to 1).  So we can now assume d=3.</p>
<p>We have only taken limits at time t=-1.  But we can use Hamilton&#8217;s compactness theorem (Theorem 2 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/27/285g-lecture-15-geometric-limits-of-ricci-flows-and-asymptotic-gradient-shrinking-solitons/">Lecture 15</a>) again (using the property <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+R+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t R &#92;geq 0' title='&#92;partial_t R &#92;geq 0' class='latex' />) and extend <img src='http://s0.wp.com/latex.php?latex=M_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M_&#92;infty' title='M_&#92;infty' class='latex' /> to a Ricci flow backwards in time from t=-1; this is a limit of rescaled versions of <img src='http://s0.wp.com/latex.php?latex=%28M%2C+g%2C+y_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M, g, y_n)' title='(M, g, y_n)' class='latex' /> by <img src='http://s0.wp.com/latex.php?latex=R%28y_n%29%5E%7B1%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(y_n)^{1/2}' title='R(y_n)^{1/2}' class='latex' />.  Since M was originally a gradient shrinking soliton, and <img src='http://s0.wp.com/latex.php?latex=R%28y_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(y_n)' title='R(y_n)' class='latex' /> is going to infinity, the limit <img src='http://s0.wp.com/latex.php?latex=%28M_%5Cinfty%2Cg_%5Cinfty%2Cp_%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M_&#92;infty,g_&#92;infty,p_&#92;infty)' title='(M_&#92;infty,g_&#92;infty,p_&#92;infty)' class='latex' /> can be shown to be a gradient steady soliton: <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRic%7D_%5Cinfty+%2B+%5Chbox%7BHess%7D%28f_%5Cinfty%29+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Ric}_&#92;infty + &#92;hbox{Hess}(f_&#92;infty) = 0' title='&#92;hbox{Ric}_&#92;infty + &#92;hbox{Hess}(f_&#92;infty) = 0' class='latex' /> for some <img src='http://s0.wp.com/latex.php?latex=f_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='f_&#92;infty' title='f_&#92;infty' class='latex' />.</p>
<p>Since <img src='http://s0.wp.com/latex.php?latex=M_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M_&#92;infty' title='M_&#92;infty' class='latex' /> had bounded curvature at time t=-1, it had bounded curvature for all previous times also.  Since the Ricci curvature is vanishing along one direction, we can now apply the Case 1 argument and show that <img src='http://s0.wp.com/latex.php?latex=M_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M_&#92;infty' title='M_&#92;infty' class='latex' /> is the product of a line and a round shrinking <img src='http://s0.wp.com/latex.php?latex=S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2' title='S^2' class='latex' /> or <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^2' title='&#92;Bbb{RP}^2' class='latex' />.  In particular, <img src='http://s0.wp.com/latex.php?latex=M_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M_&#92;infty' title='M_&#92;infty' class='latex' /> contains closed geodesic loops <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' /> on which the Ricci curvature <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRic%7D%28X%2CX%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Ric}(X,X)' title='&#92;hbox{Ric}(X,X)' class='latex' /> is strictly positive.  From the gradient steady equation, this means that <img src='http://s0.wp.com/latex.php?latex=f_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='f_&#92;infty' title='f_&#92;infty' class='latex' /> is strictly concave on this loop, which is absurd.  Thus this situation does not occur.</p>
<p><strong>Remark 2.</strong> In <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2334563">Morgan-Tian</a>, the contradiction was obtained using the <a href="http://en.wikipedia.org/wiki/Soul_theorem">soul theorem</a>, and a rather non-trivial result asserting that complete manifolds of non-negative sectional curvature cannot contain arbitrarily small necks, but the above argument seems to be somewhat shorter.  An even simpler argument (avoiding the use of the splitting theorem altogether) was given <a href="http://arxiv.org/abs/0710.5579">by Naber</a>, based on the observation (from (1)) that the normalised gradient vector field <img src='http://s0.wp.com/latex.php?latex=%5Cnabla+f+%2F+%26%23124%3B%5Cnabla+f%26%23124%3B&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla f / &#124;&#92;nabla f&#124;' title='&#92;nabla f / &#124;&#92;nabla f&#124;' class='latex' /> of the potential function becomes increasingly parallel to the connection if <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Cnabla+f%26%23124%3B&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;nabla f&#124;' title='&#124;&#92;nabla f&#124;' class='latex' /> goes to infinity.  We thank Peter Petersen for pointing out Naber&#8217;s argument to us. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:center;">&#8211; Case 3: M noncompact, curvature positive and bounded &#8211;</p>
<p>Now we assume that M is compact, with Ricci curvature strictly positive but also bounded.  By Lemma 1 of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/27/285g-lecture-15-geometric-limits-of-ricci-flows-and-asymptotic-gradient-shrinking-solitons/">Lecture 15</a>, we conclude in particular that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cint_%5Cgamma+%5Chbox%7BRic%7D%28X%2CX%29%5C+ds+%5Cleq+C&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_&#92;gamma &#92;hbox{Ric}(X,X)&#92; ds &#92;leq C' title='&#92;int_&#92;gamma &#92;hbox{Ric}(X,X)&#92; ds &#92;leq C' class='latex' /> (4)</p>
<p>for some C and all minimising geodesics (thus the Ricci curvature must decay along long geodesics).  On the other hand, along such a geodesic, we see from (1) that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%5E2%7D%7Bds%5E2%7D+f%28%5Cgamma%28s%29%29+%3D+%5Cfrac%7B1%7D%7B2%7D+-+%5Chbox%7BRic%7D%28X%2CX%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d^2}{ds^2} f(&#92;gamma(s)) = &#92;frac{1}{2} - &#92;hbox{Ric}(X,X)' title='&#92;displaystyle &#92;frac{d^2}{ds^2} f(&#92;gamma(s)) = &#92;frac{1}{2} - &#92;hbox{Ric}(X,X)' class='latex' />. (5)</p>
<p>From (4) and (5) we see that <img src='http://s0.wp.com/latex.php?latex=%5Cnabla_X+f%28%5Cgamma%28s%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_X f(&#92;gamma(s))' title='&#92;nabla_X f(&#92;gamma(s))' class='latex' /> increases like <img src='http://s0.wp.com/latex.php?latex=s%2F2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='s/2' title='s/2' class='latex' /> as <img src='http://s0.wp.com/latex.php?latex=s+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='s &#92;to &#92;infty' title='s &#92;to &#92;infty' class='latex' />.  Similarly, if E is any vector field orthogonal to X and transported by parallel transport along <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' />, an application of Cauchy-Schwarz, (4), and the bounded curvature hypothesis gives</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Cint_%5Cgamma+%5Chbox%7BRic%7D%28X%2CE%29%26%23124%3B%5C+ds+%5Cleq+C%27+%26%23124%3B%5Cgamma%26%23124%3B%5E%7B1%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;int_&#92;gamma &#92;hbox{Ric}(X,E)&#124;&#92; ds &#92;leq C&#039; &#124;&#92;gamma&#124;^{1/2}' title='&#124;&#92;int_&#92;gamma &#92;hbox{Ric}(X,E)&#124;&#92; ds &#92;leq C&#039; &#124;&#92;gamma&#124;^{1/2}' class='latex' /> (6)</p>
<p>while (1) gives</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bds%7D+%5Cnabla_E+f%28%5Cgamma+s%29%29+%3D+-+%5Chbox%7BRic%7D%28X%2CE%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{ds} &#92;nabla_E f(&#92;gamma s)) = - &#92;hbox{Ric}(X,E)' title='&#92;displaystyle &#92;frac{d}{ds} &#92;nabla_E f(&#92;gamma s)) = - &#92;hbox{Ric}(X,E)' class='latex' /> (7)</p>
<p>and so <img src='http://s0.wp.com/latex.php?latex=%5Cnabla_E+f%28%5Cgamma%28s%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_E f(&#92;gamma(s))' title='&#92;nabla_E f(&#92;gamma(s))' class='latex' /> grows like at most <img src='http://s0.wp.com/latex.php?latex=O%28s%5E%7B1%2F2%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='O(s^{1/2})' title='O(s^{1/2})' class='latex' /> as <img src='http://s0.wp.com/latex.php?latex=s+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='s &#92;to &#92;infty' title='s &#92;to &#92;infty' class='latex' />.  These bounds ensure that f goes to <img src='http://s0.wp.com/latex.php?latex=%2B%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='+&#92;infty' title='+&#92;infty' class='latex' /> at infinity (in particular, it is <a href="http://en.wikipedia.org/wiki/Proper_function">proper</a>), and that there exist curves following the gradient <img src='http://s0.wp.com/latex.php?latex=%5Cnabla+f&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla f' title='&#92;nabla f' class='latex' /> of f which go to infinity.</p>
<p>On the other hand, using the identity</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cnabla_%5Calpha+R+%3D+2+%5Chbox%7BRic%7D_%7B%5Calpha+%5Cbeta%7D+%5Cnabla%5E%5Cbeta+f&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_&#92;alpha R = 2 &#92;hbox{Ric}_{&#92;alpha &#92;beta} &#92;nabla^&#92;beta f' title='&#92;nabla_&#92;alpha R = 2 &#92;hbox{Ric}_{&#92;alpha &#92;beta} &#92;nabla^&#92;beta f' class='latex' /> (8)</p>
<p>(see (27) from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/19/285g-lecture-13-li-yau-hamilton-harnack-inequalities-and-%ce%ba-solutions/">Lecture 13</a>) we see that <img src='http://s0.wp.com/latex.php?latex=%5Cnabla_%7B%5Cnabla+f%7D+R+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_{&#92;nabla f} R &gt; 0' title='&#92;nabla_{&#92;nabla f} R &gt; 0' class='latex' />, thus R is increasing along gradient flow curves.  In particular, <img src='http://s0.wp.com/latex.php?latex=R%28%5Cinfty%29+%3A%3D+%5Climsup_%7Bx+%5Cto+%5Cinfty%7D+R%28x%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(&#92;infty) := &#92;limsup_{x &#92;to &#92;infty} R(x)' title='R(&#92;infty) := &#92;limsup_{x &#92;to &#92;infty} R(x)' class='latex' />  is strictly positive (and finite, since curvature is bounded).</p>
<p>As a consequence, we can repeat the point-picking arguments from Case 2 and extract a sequence of points <img src='http://s0.wp.com/latex.php?latex=y_n+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y_n &#92;to &#92;infty' title='y_n &#92;to &#92;infty' class='latex' /> for which <img src='http://s0.wp.com/latex.php?latex=%28M%2C+g%2C+x_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M, g, x_n)' title='(M, g, x_n)' class='latex' /> converges geometrically to a limit <img src='http://s0.wp.com/latex.php?latex=%28M_%5Cinfty%2Cg_%5Cinfty%2Cp_%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M_&#92;infty,g_&#92;infty,p_&#92;infty)' title='(M_&#92;infty,g_&#92;infty,p_&#92;infty)' class='latex' />, which has scalar curvature <img src='http://s0.wp.com/latex.php?latex=R%28%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(&#92;infty)' title='R(&#92;infty)' class='latex' /> at <img src='http://s0.wp.com/latex.php?latex=p_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='p_&#92;infty' title='p_&#92;infty' class='latex' />.  Since M is a gradient shrinking soliton on <img src='http://s0.wp.com/latex.php?latex=%28-%5Cinfty%2C0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(-&#92;infty,0)' title='(-&#92;infty,0)' class='latex' />, one can show that <img src='http://s0.wp.com/latex.php?latex=M_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M_&#92;infty' title='M_&#92;infty' class='latex' /> is also.  By repeating the Case 2 analysis one can show that <img src='http://s0.wp.com/latex.php?latex=M_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M_&#92;infty' title='M_&#92;infty' class='latex' /> is also a round shrinking <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+R%7D+%5Ctimes+S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb R} &#92;times S^2' title='{&#92;Bbb R} &#92;times S^2' class='latex' /> or <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+R%7D+%5Ctimes+%5CBbb%7BRP%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb R} &#92;times &#92;Bbb{RP}^2' title='{&#92;Bbb R} &#92;times &#92;Bbb{RP}^2' class='latex' />.  Since these solitons have scalar curvature 1 at time -1, we thus have <img src='http://s0.wp.com/latex.php?latex=R%28%5Cinfty%29%3D1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(&#92;infty)=1' title='R(&#92;infty)=1' class='latex' />.</p>
<p>For sake of argument let us take M to be the round shrinking cylinder <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+R%7D+%5Ctimes+S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb R} &#92;times S^2' title='{&#92;Bbb R} &#92;times S^2' class='latex' />; the other case is similar but with all areas divided by a factor of two.  (One can also eliminate this case by appealing to the <a href="http://en.wikipedia.org/wiki/Soul_theorem">soul theorem</a>, or by adding an additional hypothesis throughout the argument that the manifolds being studied do not contain embedded <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^2' title='&#92;Bbb{RP}^2' class='latex' />&#8216;s with trivial normal bundle.)</p>
<p>Now we return to the original gradient shrinking soliton M.  Since R is strictly increasing along gradient flow curves, we conclude that <img src='http://s0.wp.com/latex.php?latex=R+%26%2360%3B+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R &lt; 1' title='R &lt; 1' class='latex' /> near infinity. Since M has non-negative Riemann curvature, this implies <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRic%7D+%26%2360%3B+%5Cfrac%7B1%7D%7B2%7D+g&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Ric} &lt; &#92;frac{1}{2} g' title='&#92;hbox{Ric} &lt; &#92;frac{1}{2} g' class='latex' /> near infinity.  From (1) this implies that f is strictly convex (i.e. <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BHess%7D%28f%29+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Hess}(f) &gt; 0' title='&#92;hbox{Hess}(f) &gt; 0' class='latex' />) near infinity.  Thus the level sets of f have increasing area.  On the other hand, on any region of M that approaches <img src='http://s0.wp.com/latex.php?latex=M_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M_&#92;infty' title='M_&#92;infty' class='latex' /> (e.g. in the neighbourhoods of <img src='http://s0.wp.com/latex.php?latex=y_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y_n' title='y_n' class='latex' />) one easily sees (e.g. from (1), or from the analysis from Case 2) that the level sets of f converge to the sections <img src='http://s0.wp.com/latex.php?latex=S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2' title='S^2' class='latex' /> of the cylinder, which have area <img src='http://s0.wp.com/latex.php?latex=8%5Cpi&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='8&#92;pi' title='8&#92;pi' class='latex' /> (note we are normalising the scalar curvature here to be 1, rather than the sectional curvature, which is 1/2).    Thus the level sets <img src='http://s0.wp.com/latex.php?latex=%5CSigma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Sigma' title='&#92;Sigma' class='latex' /> of f have area strictly less than <img src='http://s0.wp.com/latex.php?latex=8%5Cpi&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='8&#92;pi' title='8&#92;pi' class='latex' />.</p>
<p>On the other hand, from the Gauss-Codazzi formula (equation (4) from Lecture 4), the Gaussian curvature K of <img src='http://s0.wp.com/latex.php?latex=%5CSigma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Sigma' title='&#92;Sigma' class='latex' /> is given by the formula</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=K+%3D+K_M+%2B+%5Cdet%28%5CPi%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='K = K_M + &#92;det(&#92;Pi)' title='K = K_M + &#92;det(&#92;Pi)' class='latex' /> (9)</p>
<p>where <img src='http://s0.wp.com/latex.php?latex=K_M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='K_M' title='K_M' class='latex' /> is the sectional curvature of <img src='http://s0.wp.com/latex.php?latex=%5CSigma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Sigma' title='&#92;Sigma' class='latex' />, and <img src='http://s0.wp.com/latex.php?latex=%5CPi+%3D+%5Cfrac%7B%5Chbox%7BHess%7D%28f%29%26%23124%3B_%5CSigma+%7D%7B%26%23124%3B%5Cnabla+f%26%23124%3B%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Pi = &#92;frac{&#92;hbox{Hess}(f)&#124;_&#92;Sigma }{&#124;&#92;nabla f&#124;}' title='&#92;Pi = &#92;frac{&#92;hbox{Hess}(f)&#124;_&#92;Sigma }{&#124;&#92;nabla f&#124;}' class='latex' /> is the second fundamental form.  Applying (1) we eventually compute</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+2K+%5Cleq+R+-+2%5Chbox%7BRic%7D%28n%2Cn%29+-+%5Cfrac%7B%281-R%2B%5Chbox%7BRic%7D%28n%2Cn%29%29%5E2%7D%7B2%26%23124%3B%5Cnabla+f%26%23124%3B%5E2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle 2K &#92;leq R - 2&#92;hbox{Ric}(n,n) - &#92;frac{(1-R+&#92;hbox{Ric}(n,n))^2}{2&#124;&#92;nabla f&#124;^2}' title='&#92;displaystyle 2K &#92;leq R - 2&#92;hbox{Ric}(n,n) - &#92;frac{(1-R+&#92;hbox{Ric}(n,n))^2}{2&#124;&#92;nabla f&#124;^2}' class='latex' />. (10)</p>
<p>Following the gradient flow lines of f, we see from previous analysis that <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Cnabla+f%26%23124%3B&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;nabla f&#124;' title='&#124;&#92;nabla f&#124;' class='latex' /> goes to infinity (while curvature stays bounded and strictly positive), and so it is not hard to see that the right-hand side must be strictly less than 1 near infinity.  But this means that <img src='http://s0.wp.com/latex.php?latex=%5Cint_%5CSigma+K+%26%2360%3B+4%5Cpi&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_&#92;Sigma K &lt; 4&#92;pi' title='&#92;int_&#92;Sigma K &lt; 4&#92;pi' class='latex' />, contradicting the <a href="http://en.wikipedia.org/wiki/Gauss%E2%80%93Bonnet_theorem">Gauss-Bonnet formula</a> (Proposition 1 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/11/285g-lecture-4-finite-time-extinction-of-the-second-homotopy-group/">Lecture 4</a>).  Thus Case 3 cannot in fact occur.</p>
<p style="text-align:center;">&#8211; Case 4: M compact, strictly positive curvature &#8211;</p>
<p>Let us first deal with the two-dimensional case.  Here one could use <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=954419">Hamilton&#8217;s results on Ricci flow for surfaces</a> to show that this gradient shrinking soliton must be a round shrinking <img src='http://s0.wp.com/latex.php?latex=S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2' title='S^2' class='latex' /> or <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^2' title='&#92;Bbb{RP}^2' class='latex' />, but we give here an argument adapted from the book of <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2061425">Chow and Knopf</a>.  It relies on the following identity, that provides an additional global constraint on the curvature R beyond that provided by the <a href="http://en.wikipedia.org/wiki/Gauss%E2%80%93Bonnet_theorem">Gauss-Bonnet theorem</a>:</p>
<blockquote><p><strong>Lemma 1</strong> (<a href="http://www.ams.org/mathscinet-getitem?mr=343205">Kazhdan-Warner</a> type identity)  Let (M,g) be a compact surface, and let X be a conformal <a href="http://en.wikipedia.org/wiki/Killing_vector_field">Killing vector field</a> (thus <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D_X+g&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}_X g' title='{&#92;mathcal L}_X g' class='latex' /> is a scalar multiple of g).  Then <img src='http://s0.wp.com/latex.php?latex=%5Cint_M+R+%5Chbox%7Bdiv%7D+X%5C+d%5Cmu+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_M R &#92;hbox{div} X&#92; d&#92;mu = 0' title='&#92;int_M R &#92;hbox{div} X&#92; d&#92;mu = 0' class='latex' />.</p></blockquote>
<p><strong>Proof.</strong> When M has constant curvature, the claim is clear by integration by parts.  On the other hand, by the <a href="http://en.wikipedia.org/wiki/Uniformization_theorem">uniformization theorem</a>, any metric g can be conformally deformed to a constant curvature metric.  Note also from definition that a conformal Killing vector field remains conformal after any conformal change of metric.  Thus it suffices to show that <img src='http://s0.wp.com/latex.php?latex=%5Cint_M+R+%5Chbox%7Bdiv%7D+X%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_M R &#92;hbox{div} X&#92; d&#92;mu' title='&#92;int_M R &#92;hbox{div} X&#92; d&#92;mu' class='latex' /> is constant under any conformal change <img src='http://s0.wp.com/latex.php?latex=%5Cdot+g+%3D+u+g&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;dot g = u g' title='&#92;dot g = u g' class='latex' /> of g, keeping X static.</p>
<p>From the variation formulae from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/03/28/285g-lecture-1-ricci-flow/">Lecture 1</a>, we have <img src='http://s0.wp.com/latex.php?latex=%5Cdot+R+%3D+-Ru-%5CDelta+u&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;dot R = -Ru-&#92;Delta u' title='&#92;dot R = -Ru-&#92;Delta u' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Cdot%7Bd%5Cmu%7D+%3D+u%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;dot{d&#92;mu} = u&#92; d&#92;mu' title='&#92;dot{d&#92;mu} = u&#92; d&#92;mu' class='latex' />.  Inserting these formulae and integrating by parts to isolate u, we see that it suffices to show that <img src='http://s0.wp.com/latex.php?latex=%5Cnabla_%5Calpha%28X%5E%5Calpha+R%29+%2B+%5CDelta%28%5Cnabla_%5Calpha+X%5E%5Calpha%29+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_&#92;alpha(X^&#92;alpha R) + &#92;Delta(&#92;nabla_&#92;alpha X^&#92;alpha) = 0' title='&#92;nabla_&#92;alpha(X^&#92;alpha R) + &#92;Delta(&#92;nabla_&#92;alpha X^&#92;alpha) = 0' class='latex' />.  On the other hand, since <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D_X++g_%7B%5Calpha%5Cbeta%7D%3D+%5Cnabla_%5Calpha+X_%5Cbeta+%2B+%5Cnabla_%5Cbeta+X_%5Calpha&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}_X  g_{&#92;alpha&#92;beta}= &#92;nabla_&#92;alpha X_&#92;beta + &#92;nabla_&#92;beta X_&#92;alpha' title='{&#92;mathcal L}_X  g_{&#92;alpha&#92;beta}= &#92;nabla_&#92;alpha X_&#92;beta + &#92;nabla_&#92;beta X_&#92;alpha' class='latex' /> is conformal, we have the identity <img src='http://s0.wp.com/latex.php?latex=%5Cnabla_%5Calpha+X_%5Cbeta+%2B+%5Cnabla_%5Cbeta+X_%5Calpha+%3D+%28%5Cnabla%5E%5Cgamma+X_%5Cgamma%29+g_%7B%5Calpha+%5Cbeta%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_&#92;alpha X_&#92;beta + &#92;nabla_&#92;beta X_&#92;alpha = (&#92;nabla^&#92;gamma X_&#92;gamma) g_{&#92;alpha &#92;beta}' title='&#92;nabla_&#92;alpha X_&#92;beta + &#92;nabla_&#92;beta X_&#92;alpha = (&#92;nabla^&#92;gamma X_&#92;gamma) g_{&#92;alpha &#92;beta}' class='latex' />.  Taking divergences of this identity twice and rearranging derivatives repeatedly, we eventually obtain this claim. <img src='http://s0.wp.com/latex.php?latex=%5CBox&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Box' title='&#92;Box' class='latex' /></p>
<p>[<em>Aside</em>: I do not know of any proof of the Kazhdan-Warner identity that does not require the uniformisation theorem; the result seems to have an irreducibly "global" nature to it.]</p>
<p>Now we apply this lemma to the vector field <img src='http://s0.wp.com/latex.php?latex=%5Cnabla+f&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla f' title='&#92;nabla f' class='latex' />, which is conformal thanks to (1).  We conclude that <img src='http://s0.wp.com/latex.php?latex=%5Cint_M+R+%5CDelta+f%5C+d%5Cmu+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_M R &#92;Delta f&#92; d&#92;mu = 0' title='&#92;int_M R &#92;Delta f&#92; d&#92;mu = 0' class='latex' />.  On the other hand, from the trace of (1) we have <img src='http://s0.wp.com/latex.php?latex=R+-+1%2F%5Ctau+%3D+%5CDelta+f&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R - 1/&#92;tau = &#92;Delta f' title='R - 1/&#92;tau = &#92;Delta f' class='latex' />.  Integrating this against <img src='http://s0.wp.com/latex.php?latex=%5CDelta+f&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Delta f' title='&#92;Delta f' class='latex' /> we conclude that <img src='http://s0.wp.com/latex.php?latex=%5Cint_M+%26%23124%3B%5CDelta+f%26%23124%3B%5E2%5C+d%5Cmu+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_M &#124;&#92;Delta f&#124;^2&#92; d&#92;mu = 0' title='&#92;int_M &#124;&#92;Delta f&#124;^2&#92; d&#92;mu = 0' class='latex' />, thus f is harmonic; and so <img src='http://s0.wp.com/latex.php?latex=R+%3D+1%2F%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R = 1/&#92;tau' title='R = 1/&#92;tau' class='latex' />.  M is now constant curvature and is therefore either a round shrinking <img src='http://s0.wp.com/latex.php?latex=S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2' title='S^2' class='latex' /> or <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^2' title='&#92;Bbb{RP}^2' class='latex' /> as required.</p>
<p>Now we turn to three dimensions. The result in this case follows immediately from <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=664497">Hamilton&#8217;s rounding theorem</a>, but we will take advantage of the gradient shrinking soliton structure to extract just the key components of that theorem here.  Let <img src='http://s0.wp.com/latex.php?latex=%5Clambda+%5Cgeq+%5Cmu+%5Cgeq+%5Cnu+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;lambda &#92;geq &#92;mu &#92;geq &#92;nu &#92;geq 0' title='&#92;lambda &#92;geq &#92;mu &#92;geq &#92;nu &#92;geq 0' class='latex' /> denote the eigenvalues of the Riemann curvature.  Note that as the Ricci curvature is positive, <img src='http://s0.wp.com/latex.php?latex=%5Cmu%2B%5Cnu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;mu+&#92;nu' title='&#92;mu+&#92;nu' class='latex' /> is strictly greater than zero.</p>
<p>The quantity <img src='http://s0.wp.com/latex.php?latex=%28%5Cmu%2B%5Cnu%29%2F%5Clambda&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;mu+&#92;nu)/&#92;lambda' title='(&#92;mu+&#92;nu)/&#92;lambda' class='latex' /> ranges between 0 and 2 and reaches a minimum value <img src='http://s0.wp.com/latex.php?latex=%5Cdelta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta' title='&#92;delta' class='latex' /> at some point x.   If we rewrite things in terms of the tensor <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+T%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal T}' title='{&#92;mathcal T}' class='latex' /> from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/04/285g-lecture-3-the-maximum-principle-and-the-pinching-phenomenon/">Lecture 3</a>, the gradient shrinking soliton structure means that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B1%7D%7B%5Ctau%7D+%7B%5Cmathcal+T%7D+%3D+%5CDelta+%7B%5Cmathcal+T%7D+%2B+%7B%5Cmathcal+L%7D_%7B%5Cnabla+f%7D+%7B%5Cmathcal+T%7D+%2B+%7B%5Cmathcal+T%7D%5E2+%2B+%7B%5Cmathcal+T%7D%5E%5C%23&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{1}{&#92;tau} {&#92;mathcal T} = &#92;Delta {&#92;mathcal T} + {&#92;mathcal L}_{&#92;nabla f} {&#92;mathcal T} + {&#92;mathcal T}^2 + {&#92;mathcal T}^&#92;#' title='&#92;frac{1}{&#92;tau} {&#92;mathcal T} = &#92;Delta {&#92;mathcal T} + {&#92;mathcal L}_{&#92;nabla f} {&#92;mathcal T} + {&#92;mathcal T}^2 + {&#92;mathcal T}^&#92;#' class='latex' /> (11)</p>
<p>But the region <img src='http://s0.wp.com/latex.php?latex=%5C%7B+%7B%5Cmathcal+T%7D%3A+%5Cnu+%5Cgeq+0%3B+%5Cmu+%2B+%5Cnu+%5Cgeq+%5Cdelta+%5Clambda+%5C%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;{ {&#92;mathcal T}: &#92;nu &#92;geq 0; &#92;mu + &#92;nu &#92;geq &#92;delta &#92;lambda &#92;}' title='&#92;{ {&#92;mathcal T}: &#92;nu &#92;geq 0; &#92;mu + &#92;nu &#92;geq &#92;delta &#92;lambda &#92;}' class='latex' /> is fibrewise convex and parallel, and at x, <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B1%7D%7B%5Ctau%7D+%7B%5Cmathcal+T%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{1}{&#92;tau} {&#92;mathcal T}' title='&#92;frac{1}{&#92;tau} {&#92;mathcal T}' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D_%7B%5Cnabla+f%7D+%7B%5Cmathcal+T%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}_{&#92;nabla f} {&#92;mathcal T}' title='{&#92;mathcal L}_{&#92;nabla f} {&#92;mathcal T}' class='latex' /> are tangential to this region and <img src='http://s0.wp.com/latex.php?latex=%5CDelta+%7B%5Cmathcal+T%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Delta {&#92;mathcal T}' title='&#92;Delta {&#92;mathcal T}' class='latex' /> is tangential or inward.  On the other hand, a computation shows that <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+T%7D%5E2+%2B+%7B%5Cmathcal+T%7D%5E%5C%23&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal T}^2 + {&#92;mathcal T}^&#92;#' title='{&#92;mathcal T}^2 + {&#92;mathcal T}^&#92;#' class='latex' /> is strictly inward unless <img src='http://s0.wp.com/latex.php?latex=%5Cdelta%3D2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta=2' title='&#92;delta=2' class='latex' />, in which case it is tangential.  So we must have <img src='http://s0.wp.com/latex.php?latex=%5Cdelta%3D2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta=2' title='&#92;delta=2' class='latex' />, which implies that <img src='http://s0.wp.com/latex.php?latex=%5Clambda%3D%5Cmu%3D%5Cnu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;lambda=&#92;mu=&#92;nu' title='&#92;lambda=&#92;mu=&#92;nu' class='latex' />.  In other words, the Ricci tensor is conformal: <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRic%7D+%3D+%5Cfrac%7B1%7D%7B3%7D+R+g&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Ric} = &#92;frac{1}{3} R g' title='&#92;hbox{Ric} = &#92;frac{1}{3} R g' class='latex' />.  Comparing this with the <a href="http://en.wikipedia.org/wiki/Bianchi_identity#Bianchi_identities">Bianchi identity</a> <img src='http://s0.wp.com/latex.php?latex=%5Cnabla_%5Calpha+R+%3D++2+%5Cnabla%5E%5Cbeta+%5Chbox%7BRic%7D_%7B%5Calpha+%5Cbeta%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_&#92;alpha R =  2 &#92;nabla^&#92;beta &#92;hbox{Ric}_{&#92;alpha &#92;beta}' title='&#92;nabla_&#92;alpha R =  2 &#92;nabla^&#92;beta &#92;hbox{Ric}_{&#92;alpha &#92;beta}' class='latex' /> (equation (28) from <a href="http://terrytao.wordpress.com/2008/03/26/285g-lecture-0-riemannian-manifolds-and-curvature/">Lecture 0</a>) we conclude that <img src='http://s0.wp.com/latex.php?latex=%5Cnabla+R+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla R = 0' title='&#92;nabla R = 0' class='latex' />, and thus <img src='http://s0.wp.com/latex.php?latex=%5Cnabla+%5Chbox%7BRic%7D%3D0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla &#92;hbox{Ric}=0' title='&#92;nabla &#92;hbox{Ric}=0' class='latex' />.  Thus M has constant sectional curvature and is therefore a round shrinking spherical space form, as required.</p>
<p style="text-align:center;">&#8211; Appendix: Toponogov theory &#8211;</p>
<p>Roughly speaking, <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=103510">Toponogov</a> comparison theory is to triangle geometry as Bishop-Gromov theory is to volumes of balls: in both cases, lower bounds on curvature are used to bound the geometry of Riemannian manifolds by model geometries such as Euclidean space.  This theory links modern Riemannian geometry with the more classical approach to curved space (or non-Euclidean geometries) which often proceeded via analysing the angles formed by a triangle.  The material here is loosely drawn from <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=1480173">Petersen&#8217;s book</a>.</p>
<blockquote><p><strong>Lemma 2. </strong>(Toponogov cosine rule) Let <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g)' title='(M,g)' class='latex' /> be a complete Riemannian manifold of non-negative sectional curvature, and let <img src='http://s0.wp.com/latex.php?latex=x_0%2C+x_1%2C+x_2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0, x_1, x_2' title='x_0, x_1, x_2' class='latex' /> be three distinct points in M.  Let <img src='http://s0.wp.com/latex.php?latex=%5Ctheta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;theta' title='&#92;theta' class='latex' /> be the angle formed at <img src='http://s0.wp.com/latex.php?latex=x_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_1' title='x_1' class='latex' /> by the minimising geodesics from <img src='http://s0.wp.com/latex.php?latex=x_0%2C+x_2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0, x_2' title='x_0, x_2' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=x_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_1' title='x_1' class='latex' />.  Then</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=d%28x_2%2C+x_0%29%5E2+%5Cleq+d%28x_1%2Cx_0%29%5E2+%2B+d%28x_2%2Cx_1%29%5E2+-+2+d%28x_1%2Cx_0%29+d%28x_2%2Cx_1%29+%5Ccos+%5Ctheta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d(x_2, x_0)^2 &#92;leq d(x_1,x_0)^2 + d(x_2,x_1)^2 - 2 d(x_1,x_0) d(x_2,x_1) &#92;cos &#92;theta' title='d(x_2, x_0)^2 &#92;leq d(x_1,x_0)^2 + d(x_2,x_1)^2 - 2 d(x_1,x_0) d(x_2,x_1) &#92;cos &#92;theta' class='latex' /> (12).</p>
</blockquote>
<p>Of course, when M is flat we have equality in (12), by the classical <a href="http://en.wikipedia.org/wiki/Law_of_cosines">cosine rule</a>.</p>
<p><strong>Proof.</strong> Let f be the function <img src='http://s0.wp.com/latex.php?latex=f%28x%29+%3A%3D+%5Cfrac%7B1%7D%7B2%7D+d%28x%2Cx_0%29%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='f(x) := &#92;frac{1}{2} d(x,x_0)^2' title='f(x) := &#92;frac{1}{2} d(x,x_0)^2' class='latex' />, and let <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%3A+%5B0%2C+d%28x_2%2Cx_1%29%5D+%5Cto+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma: [0, d(x_2,x_1)] &#92;to M' title='&#92;gamma: [0, d(x_2,x_1)] &#92;to M' class='latex' /> be the unit speed geodesic from <img src='http://s0.wp.com/latex.php?latex=x_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_1' title='x_1' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=x_2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_2' title='x_2' class='latex' />.  Our task is to show that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=f%28%5Cgamma%28t%29%29+%5Cleq+f%28%5Cgamma%280%29%29+%2B+%5Cfrac%7B1%7D%7B2%7D+t%5E2+-+t+d%28x_1%2Cx_0%29+%5Ccos+%5Ctheta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='f(&#92;gamma(t)) &#92;leq f(&#92;gamma(0)) + &#92;frac{1}{2} t^2 - t d(x_1,x_0) &#92;cos &#92;theta' title='f(&#92;gamma(t)) &#92;leq f(&#92;gamma(0)) + &#92;frac{1}{2} t^2 - t d(x_1,x_0) &#92;cos &#92;theta' class='latex' /> (13)</p>
<p>for t = d(x_2,x_1).  From the Gauss lemma we know that <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bd%7D%7Bdt%7D+f%28%5Cgamma%28t%29%29%26%23124%3B_%7Bt%3D0%7D+%5Cleq+-+d%28x_1%2Cx_0%29+%5Ccos+%5Ctheta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{d}{dt} f(&#92;gamma(t))&#124;_{t=0} &#92;leq - d(x_1,x_0) &#92;cos &#92;theta' title='&#92;frac{d}{dt} f(&#92;gamma(t))&#124;_{t=0} &#92;leq - d(x_1,x_0) &#92;cos &#92;theta' class='latex' />.  On the other hand, from the second variation formula for distance (or more precisely, equation (21) of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/09/285g-lecture-10-variation-of-l-geodesics-and-monotonicity-of-perelman-reduced-volume/">Lecture 10</a>) and the non-negative sectional curvature assumption we have <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bd%5E2%7D%7Bdt%5E2%7D+f%28%5Cgamma%28t%29%29+%5Cleq+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{d^2}{dt^2} f(&#92;gamma(t)) &#92;leq 1' title='&#92;frac{d^2}{dt^2} f(&#92;gamma(t)) &#92;leq 1' class='latex' />.  (Actually one has to justify this in a suitable barrier sense when one is in the cut locus, but let us ignore this issue here for simplicity.)  The claim follows. <img src='http://s0.wp.com/latex.php?latex=%5CBox&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Box' title='&#92;Box' class='latex' /></p>
<p>There is an appealing reformulation of this lemma.  Define a <em>triangle</em> to be three points A, B, C connected by three minimising geodesics AB, BC, CA.</p>
<p><strong>Exercise 2. </strong> (Positive curvature increases angles) Let ABC be a triangle in a Riemannian manifold of non-negative sectional curvature, and let A&#8217;B'C&#8217; be a triangle in Euclidean space with the same side lengths as ABC.  Show that the angle subtended at A is larger than or equal to that subtended at A&#8217; (and similarly of course for B and B&#8217;, and C and C&#8217;).  In particular, the sum of the angles of ABC is at least <img src='http://s0.wp.com/latex.php?latex=%5Cpi&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;pi' title='&#92;pi' class='latex' />. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>There is also a relative version of this result:</p>
<p><strong>Exercise 3. </strong> (Relative Toponogov comparison) Let the notation and assumptions be as in the previous exercise.  Let X, Y be points on AB, AC respectively, and let X&#8217;, Y&#8217; be the corresponding points on A&#8217;B&#8217; and A&#8217;C&#8217;.  Show that the length of XY is greater than or equal to the length of X&#8217;Y&#8217;. (Hint: it suffices to do this in the case X=B (or Y=C), since the general case follows by two applications of this special case.  Now repeat the argument used to prove Lemma 2.) <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p><strong>Remark 3.</strong> Similar statements hold when one assumes that the sectional curvatures are bounded below by some number K other than zero.  In this case, one replaces Euclidean space with the model geometry of constant curvature K, much as in the discussion of the Bishop-Gromov inequality in <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/27/285g-lecture-9-comparison-geometry-the-high-dimensional-limit-and-perelman-reduced-volume/">Lecture 9</a>.  See <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=1480173">Petersen&#8217;s book</a> for details. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:center;">&#8211; The Cheeger-Gromoll splitting theorem &#8211;</p>
<p>When a manifold has positive curvature, it is difficult for long geodesics to be minimising; see for example <a href="http://en.wikipedia.org/wiki/Myers_theorem">Myers&#8217; theorem</a> for one instance of this phenomenon.<br />
Another important example of this is the <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=303460">Cheeger-Gromoll splitting theorem</a>.</p>
<blockquote><p><strong>Theorem 2</strong> (splitting theorem).  Let <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g)' title='(M,g)' class='latex' /> be a complete Riemannian manifold of nonnegative Ricci curvature that contains a minimising geodesic line <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%3A+%7B%5CBbb+R%7D+%5Cto+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma: {&#92;Bbb R} &#92;to M' title='&#92;gamma: {&#92;Bbb R} &#92;to M' class='latex' />.  Then M splits as the product of <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb R}' title='{&#92;Bbb R}' class='latex' /> with a manifold of one lower dimension.</p></blockquote>
<p><strong>Remark 4.</strong> If one strengthens the non-negative Ricci curvature assumption to non-negative sectional curvature, this is a result <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=185551">of Toponogov</a>; if one strengthens further to have a uniform positive lower bound on sectional curvature, then this follows from <a href="http://en.wikipedia.org/wiki/Myers_theorem">Myers&#8217; theorem</a>. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p><strong>Proof. </strong> We can parameterise <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' /> to be unit speed.  Consider the <em>Busemann functions</em> <img src='http://s0.wp.com/latex.php?latex=B_%2B%2C+B_-%3A+M+%5Cto+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_+, B_-: M &#92;to {&#92;Bbb R}' title='B_+, B_-: M &#92;to {&#92;Bbb R}' class='latex' /> defined by</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=B_%5Cpm%28x%29+%3A%3D+%5Clim_%7Bt+%5Cto+%5Cpm+%5Cinfty%7D+d%28+%5Cgamma%28t%29%2C+x+%29+-+t.&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_&#92;pm(x) := &#92;lim_{t &#92;to &#92;pm &#92;infty} d( &#92;gamma(t), x ) - t.' title='B_&#92;pm(x) := &#92;lim_{t &#92;to &#92;pm &#92;infty} d( &#92;gamma(t), x ) - t.' class='latex' /> (13)</p>
<p>One can show that the limits exist (because, by the triangle inequality, the expressions in the limits are bounded and monotone), and that <img src='http://s0.wp.com/latex.php?latex=B_%2B%2C+B_-&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_+, B_-' title='B_+, B_-' class='latex' /> are both Lipschitz.  From the non-negative curvature we have the upper bound <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BHess%7D%28r%29%28v%2Cv%29+%5Cleq+1%2Fr&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Hess}(r)(v,v) &#92;leq 1/r' title='&#92;hbox{Hess}(r)(v,v) &#92;leq 1/r' class='latex' /> for any distance function <img src='http://s0.wp.com/latex.php?latex=r+%3D+d%28x%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r = d(x,x_0)' title='r = d(x,x_0)' class='latex' /> (see e.g. equation (21) from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/09/285g-lecture-10-variation-of-l-geodesics-and-monotonicity-of-perelman-reduced-volume/">Lecture 10</a>); applying this with <img src='http://s0.wp.com/latex.php?latex=x_0+%3D+%5Cgamma%28t%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0 = &#92;gamma(t)' title='x_0 = &#92;gamma(t)' class='latex' /> and letting <img src='http://s0.wp.com/latex.php?latex=t+%5Cto+%5Cpm+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;to &#92;pm &#92;infty' title='t &#92;to &#92;pm &#92;infty' class='latex' /> we obtain the concavity <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BHess%7D%28B_%5Cpm%29+%5Cleq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Hess}(B_&#92;pm) &#92;leq 0' title='&#92;hbox{Hess}(B_&#92;pm) &#92;leq 0' class='latex' />.  In particular, <img src='http://s0.wp.com/latex.php?latex=B_%2B+%2B+B_-&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_+ + B_-' title='B_+ + B_-' class='latex' /> is concave.  On the other hand, from the triangle inequality we see that <img src='http://s0.wp.com/latex.php?latex=B_%2B+%2B+B_-&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_+ + B_-' title='B_+ + B_-' class='latex' /> is non-negative and vanishes on <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' />.  Applying the (elliptic) strong maximum principle (which can be viewed as the static case of the parabolic strong maximum principle, Exercise 5 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/19/285g-lecture-13-li-yau-hamilton-harnack-inequalities-and-%ce%ba-solutions/">Lecture 13</a>, though in the static case the bounded curvature hypothesis is not needed) we conclude that <img src='http://s0.wp.com/latex.php?latex=B_%2B+%2B+B_-&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_+ + B_-' title='B_+ + B_-' class='latex' /> vanishes identically.  Since <img src='http://s0.wp.com/latex.php?latex=B_%2B&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_+' title='B_+' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=B_-&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_-' title='B_-' class='latex' /> were both concave, they now must flat in the sense that <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BHess%7D%28B_%2B%29+%3D+%5Chbox%7BHess%7D%28B_-%29+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Hess}(B_+) = &#92;hbox{Hess}(B_-) = 0' title='&#92;hbox{Hess}(B_+) = &#92;hbox{Hess}(B_-) = 0' class='latex' />.  In particular they are smooth, and the gradient vector field <img src='http://s0.wp.com/latex.php?latex=X+%3A%3D+%5Cnabla+B_%2B&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='X := &#92;nabla B_+' title='X := &#92;nabla B_+' class='latex' /> is parallel to the Levi-Civita connection.  On the other hand, by applying the <a href="http://en.wikipedia.org/wiki/Gauss%27s_lemma_%28Riemannian_geometry%29">Gauss lemma</a> carefully we see that X is a unit vector field.  Thus X splits M into a line and the level sets of <img src='http://s0.wp.com/latex.php?latex=B_%2B&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_+' title='B_+' class='latex' /> (cf. Proposition 1 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/19/285g-lecture-13-li-yau-hamilton-harnack-inequalities-and-%ce%ba-solutions/">Lecture 13</a>) as desired. <img src='http://s0.wp.com/latex.php?latex=%5CBox&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Box' title='&#92;Box' class='latex' /></p>
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</item>
<item>
<title><![CDATA[285G, Lecture 15: Geometric limits of Ricci flows, and asymptotic gradient shrinking solitons]]></title>
<link>http://terrytao.wordpress.com/2008/05/27/285g-lecture-15-geometric-limits-of-ricci-flows-and-asymptotic-gradient-shrinking-solitons/</link>
<pubDate>Wed, 28 May 2008 01:58:32 +0000</pubDate>
<dc:creator>Terence Tao</dc:creator>
<guid>http://terrytao.wordpress.com/2008/05/27/285g-lecture-15-geometric-limits-of-ricci-flows-and-asymptotic-gradient-shrinking-solitons/</guid>
<description><![CDATA[We now begin using the theory established in the last two lectures to rigorously extract an asymptot]]></description>
<content:encoded><![CDATA[<p>We now begin using the theory established in the last two lectures to rigorously extract an asymptotic gradient shrinking soliton from the scaling limit of any given <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution. This will require a number of new tools, including the notion of a <em>geometric limit</em> of pointed Ricci flows <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2C+g%28t%29%2C+p%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M, g(t), p)' title='t &#92;mapsto (M, g(t), p)' class='latex' />, which can be viewed as the analogue of the <a href="http://en.wikipedia.org/wiki/Gromov-Hausdorff_convergence">Gromov-Hausdorff limit</a> in the category of smooth Riemannian flows. A key result here is <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=1333936"><em>Hamilton&#8217;s compactness theorem</em></a>: a sequence of complete pointed non-collapsed Ricci flows with uniform bounds on curvature will have a subsequence which converges geometrically to another Ricci flow. This result, which one can view as an analogue of the <a href="http://en.wikipedia.org/wiki/Arzel%C3%A0-Ascoli_theorem">Arzelá-Ascoli theorem</a> for Ricci flows, relies on some parabolic regularity estimates for Ricci flow due <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=1010165">to Shi</a>.</p>
<p>Next, we use the estimates on reduced length from the Harnack inequality analysis in <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/19/285g-lecture-13-li-yau-hamilton-harnack-inequalities-and-%ce%ba-solutions/">Lecture 13</a> to locate some good regions of spacetime of a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution in which to do the asymptotic analysis. Rescaling these regions and applying Hamilton&#8217;s compactness theorem (relying heavily here on the <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsed nature of such solutions) we extract a limit. Formally, the reduced volume is now constant and so <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/21/285g-lecture-14-stationary-points-of-perelman-entropy-or-reduced-volume-are-gradient-shrinking-solitons/">Lecture 14</a> suggests that this limit is a gradient soliton; however, some care is required to make this argument rigorous. In the next section we shall study such solitons, which will then reveal important information about the original <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution.</p>
<p>Our treatment here is primarily based on <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2334563">Morgan-Tian&#8217;s book</a> and the <a class="snap_noshots" href="http://www.math.ucsb.edu/%7Eyer/ricciflow.html">notes of Ye</a>. Other treatments can be found in <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0211159">Perelman&#8217;s original paper</a>, the <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0605667">notes of Kleiner-Lott</a>, and the <a class="snap_noshots" href="http://arxiv.org/abs/math/0612069">paper of Cao-Zhu</a>. See also the foundational papers of <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=1010165">Shi</a> and <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=1333936">Hamilton</a>, as well as the <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2274812">book of Chow, Lu, and Ni.</a></p>
<p><!--more--></p>
<p style="text-align:center;">&#8211; Geometric limits &#8211;</p>
<p>To develop the theory of geometric limits for pointed Ricci flows <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%2Cp%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t),p)' title='t &#92;mapsto (M,g(t),p)' class='latex' />, we begin by studying such limits in the simpler context of pointed Riemannian manifolds <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%2Cp%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g,p)' title='(M,g,p)' class='latex' />, i.e. a Riemannian manifold <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g)' title='(M,g)' class='latex' /> together with a point <img src='http://s0.wp.com/latex.php?latex=p+%5Cin+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='p &#92;in M' title='p &#92;in M' class='latex' />, which we shall call the <em>origin</em> or distinguished point of the manifold. To simplify the discussion, let us restrict attention to complete Riemannian manifolds (though for later analysis we will eventually have to deal with incomplete manifolds).</p>
<blockquote><p><strong>Definition 1.</strong> (Geometric limits) A sequence <img src='http://s0.wp.com/latex.php?latex=%28M_n%2Cg_n%2Cp_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M_n,g_n,p_n)' title='(M_n,g_n,p_n)' class='latex' /> of pointed d-dimensional connected complete Riemannian manifolds is said to converge geometrically to another pointed d-dimensional connected complete Riemannian manifold <img src='http://s0.wp.com/latex.php?latex=%28M_%5Cinfty%2Cg_%5Cinfty%2Cp_%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M_&#92;infty,g_&#92;infty,p_&#92;infty)' title='(M_&#92;infty,g_&#92;infty,p_&#92;infty)' class='latex' /> if there exists a sequence <img src='http://s0.wp.com/latex.php?latex=V_1+%5Csubset+V_2+%5Csubset+%5Cldots&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='V_1 &#92;subset V_2 &#92;subset &#92;ldots' title='V_1 &#92;subset V_2 &#92;subset &#92;ldots' class='latex' /> of connected neighbourhoods of <img src='http://s0.wp.com/latex.php?latex=p_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='p_&#92;infty' title='p_&#92;infty' class='latex' /> increasing to <img src='http://s0.wp.com/latex.php?latex=M_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M_&#92;infty' title='M_&#92;infty' class='latex' /> (i.e. <img src='http://s0.wp.com/latex.php?latex=%5Cbigcup_n+V_n+%3D+M_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;bigcup_n V_n = M_&#92;infty' title='&#92;bigcup_n V_n = M_&#92;infty' class='latex' />) and a sequence of smooth embeddings <img src='http://s0.wp.com/latex.php?latex=%5Cphi_n%3A+V_n+%5Cto+M_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;phi_n: V_n &#92;to M_n' title='&#92;phi_n: V_n &#92;to M_n' class='latex' /> mapping <img src='http://s0.wp.com/latex.php?latex=p_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='p_&#92;infty' title='p_&#92;infty' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=p_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='p_n' title='p_n' class='latex' /> such that</p>
<ol>
<li>The closure of each <img src='http://s0.wp.com/latex.php?latex=V_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='V_n' title='V_n' class='latex' /> is compact and contained in <img src='http://s0.wp.com/latex.php?latex=V_%7Bn%2B1%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='V_{n+1}' title='V_{n+1}' class='latex' /> (note that this implies that every compact subset of <img src='http://s0.wp.com/latex.php?latex=M_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M_&#92;infty' title='M_&#92;infty' class='latex' /> will be contained in <img src='http://s0.wp.com/latex.php?latex=V_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='V_n' title='V_n' class='latex' /> for sufficiently large n);</li>
<li>The pullback metric <img src='http://s0.wp.com/latex.php?latex=%5Cphi_n%5E%2A+g_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;phi_n^* g_n' title='&#92;phi_n^* g_n' class='latex' /> converges in the <img src='http://s0.wp.com/latex.php?latex=C%5E%5Cinfty_%7Bloc%7D%28M_%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C^&#92;infty_{loc}(M_&#92;infty)' title='C^&#92;infty_{loc}(M_&#92;infty)' class='latex' /> topology to <img src='http://s0.wp.com/latex.php?latex=g_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='g_&#92;infty' title='g_&#92;infty' class='latex' /> (i.e. all derivatives of the metric converge uniformly on compact sets).</li>
</ol>
</blockquote>
<p><strong>Example 1.</strong> The pointed round d-sphere of radius R converges geometrically to the pointed Euclidean space <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+R%7D%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb R}^d' title='{&#92;Bbb R}^d' class='latex' /> as <img src='http://s0.wp.com/latex.php?latex=R+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R &#92;to &#92;infty' title='R &#92;to &#92;infty' class='latex' />. Note how this example shows that the geometric limit of compact manifolds can be non-compact. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p><strong>Example 2.</strong> If (M,g) is Hamilton&#8217;s cigar (Example 3 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/24/285a-lecture-8-ricci-flow-as-a-gradient-flow-log-sobolev-inequalities-and-perelman-entropy/">Lecture 8</a>), and <img src='http://s0.wp.com/latex.php?latex=p_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='p_n' title='p_n' class='latex' /> is a sequence on M tending to infinity, then <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%2Cp_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g,p_n)' title='(M,g,p_n)' class='latex' /> converges geometrically to the pointed round 2-cylinder. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;"><strong>Example 3.</strong> The d-torus of length 1/n does not converge to a geometric limit as <img src='http://s0.wp.com/latex.php?latex=n+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='n &#92;to &#92;infty' title='n &#92;to &#92;infty' class='latex' />, despite being flat. More generally, the sequence needs to be locally uniformly non-collapsed in order to have a geometric limit. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;"><strong>Exercise 1.</strong> Show that the geometric limit <img src='http://s0.wp.com/latex.php?latex=%28M_%5Cinfty%2Cg_%5Cinfty%2Cp_%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M_&#92;infty,g_&#92;infty,p_&#92;infty)' title='(M_&#92;infty,g_&#92;infty,p_&#92;infty)' class='latex' /> of a sequence <img src='http://s0.wp.com/latex.php?latex=%28M_n%2Cg_n%2Cp_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M_n,g_n,p_n)' title='(M_n,g_n,p_n)' class='latex' />, if it exists, is unique up to (pointed) isometry. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;">Geometric limits, as their name suggests, tend to preserve all (local) &#8220;geometric&#8221; or &#8220;intrinsic&#8221; information about the manifold, although <em>global</em> information of this type can be lost. Here is a typical example:</p>
<p style="text-align:left;"><strong>Exercise 2.</strong> Suppose that <img src='http://s0.wp.com/latex.php?latex=%28M_n%2Cg_n%2Cp_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M_n,g_n,p_n)' title='(M_n,g_n,p_n)' class='latex' /> converges geometrically to <img src='http://s0.wp.com/latex.php?latex=%28M_%5Cinfty%2Cg_%5Cinfty%2Cp_%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M_&#92;infty,g_&#92;infty,p_&#92;infty)' title='(M_&#92;infty,g_&#92;infty,p_&#92;infty)' class='latex' />. Show that <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BVol%7D_%7Bg_%5Cinfty%7D%28B_%7Bg_%5Cinfty%7D%28p_%5Cinfty%2Cr%29%29+%3D+%5Clim_%7Bn+%5Cto+%5Cinfty%7D+%5Chbox%7BVol%7D_%7Bg_n%7D%28B_%7Bg_n%7D%28p_n%2Cr%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Vol}_{g_&#92;infty}(B_{g_&#92;infty}(p_&#92;infty,r)) = &#92;lim_{n &#92;to &#92;infty} &#92;hbox{Vol}_{g_n}(B_{g_n}(p_n,r))' title='&#92;hbox{Vol}_{g_&#92;infty}(B_{g_&#92;infty}(p_&#92;infty,r)) = &#92;lim_{n &#92;to &#92;infty} &#92;hbox{Vol}_{g_n}(B_{g_n}(p_n,r))' class='latex' /> for every <img src='http://s0.wp.com/latex.php?latex=0+%26%2360%3B+r+%26%2360%3B+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &lt; r &lt; &#92;infty' title='0 &lt; r &lt; &#92;infty' class='latex' />, and that we have the <a href="http://en.wikipedia.org/wiki/Fatou's_lemma">Fatou</a>-type inequality <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BVol%7D_%7Bg_%5Cinfty%7D%28M_%5Cinfty%29+%5Cleq+%5Clim%5Cinf_%7Bn+%5Cto+%5Cinfty%7D+%5Chbox%7BVol%7D_%7Bg_n%7D%28M_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Vol}_{g_&#92;infty}(M_&#92;infty) &#92;leq &#92;lim&#92;inf_{n &#92;to &#92;infty} &#92;hbox{Vol}_{g_n}(M_n)' title='&#92;hbox{Vol}_{g_&#92;infty}(M_&#92;infty) &#92;leq &#92;lim&#92;inf_{n &#92;to &#92;infty} &#92;hbox{Vol}_{g_n}(M_n)' class='latex' />. Give an example to show that the latter inequality can be strict. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;">Here is the basic compactness theorem for such limits.</p>
<blockquote>
<p style="text-align:left;"><strong>Theorem 1. </strong> (Compactness theorem) Let <img src='http://s0.wp.com/latex.php?latex=%28M_n%2Cg_n%2Cp_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M_n,g_n,p_n)' title='(M_n,g_n,p_n)' class='latex' /> be a sequence of connected complete Riemannian d-dimensional manifolds. Assume that</p>
<ol>
<li>(Uniform bounds on curvature and derivatives) For all <img src='http://s0.wp.com/latex.php?latex=k%2C+r_0+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='k, r_0 &#92;geq 0' title='k, r_0 &#92;geq 0' class='latex' />, one has the pointwise bound <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Cnabla%5Ek+%5Chbox%7BRiem%7D_n%26%23124%3B_%7Bg_n%7D+%5Cleq+C_%7Bk%2Cr_0%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;nabla^k &#92;hbox{Riem}_n&#124;_{g_n} &#92;leq C_{k,r_0}' title='&#124;&#92;nabla^k &#92;hbox{Riem}_n&#124;_{g_n} &#92;leq C_{k,r_0}' class='latex' /> on the ball <img src='http://s0.wp.com/latex.php?latex=B_n%28p_n%2Cr_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_n(p_n,r_0)' title='B_n(p_n,r_0)' class='latex' /> for all sufficiently large n and some constant <img src='http://s0.wp.com/latex.php?latex=C_%7Bk%2Cr_0%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C_{k,r_0}' title='C_{k,r_0}' class='latex' />.</li>
<li>(Uniform non-collapsing) For every <img src='http://s0.wp.com/latex.php?latex=r_0+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_0 &gt; 0' title='r_0 &gt; 0' class='latex' /> there exists <img src='http://s0.wp.com/latex.php?latex=%5Cdelta%2C+%5Ckappa+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta, &#92;kappa &gt; 0' title='&#92;delta, &#92;kappa &gt; 0' class='latex' /> such that <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BVol%7D_n%28x%2Cr%29+%5Cgeq+%5Ckappa+r%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Vol}_n(x,r) &#92;geq &#92;kappa r^d' title='&#92;hbox{Vol}_n(x,r) &#92;geq &#92;kappa r^d' class='latex' /> for all <img src='http://s0.wp.com/latex.php?latex=x+%5Cin+B_n%28p_n%2Cr_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x &#92;in B_n(p_n,r_0)' title='x &#92;in B_n(p_n,r_0)' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=0+%26%2360%3B+r+%5Cleq+%5Cdelta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &lt; r &#92;leq &#92;delta' title='0 &lt; r &#92;leq &#92;delta' class='latex' />, and all sufficiently large n.</li>
</ol>
<p style="text-align:left;">Then, after passing to a subsequence if necessary, the sequence <img src='http://s0.wp.com/latex.php?latex=%28M_n%2Cg_n%2Cp_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M_n,g_n,p_n)' title='(M_n,g_n,p_n)' class='latex' /> has a geometric limit.</p>
</blockquote>
<p style="text-align:left;"><strong>Proof.</strong> (Sketch) Let <img src='http://s0.wp.com/latex.php?latex=r_0+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_0 &gt; 0' title='r_0 &gt; 0' class='latex' /> be an arbitrary radius. From Cheeger&#8217;s lemma (Theorem 1 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/24/285a-lecture-8-ricci-flow-as-a-gradient-flow-log-sobolev-inequalities-and-perelman-entropy/">Lecture 7</a>) and hypothesis 2, we know that the injectivity radius on <img src='http://s0.wp.com/latex.php?latex=B_n%28p_n%2C2r_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_n(p_n,2r_0)' title='B_n(p_n,2r_0)' class='latex' /> is bounded from below by some small <img src='http://s0.wp.com/latex.php?latex=%5Cdelta+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta &gt; 0' title='&#92;delta &gt; 0' class='latex' /> for sufficiently large n. Also, from the curvature bounds and Bishop-Gromov comparison geometry (Lemma 1 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/27/285g-lecture-9-comparison-geometry-the-high-dimensional-limit-and-perelman-reduced-volume/">Lecture 9</a>) we know that the volume of <img src='http://s0.wp.com/latex.php?latex=B_n%28p_n%2C2r_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_n(p_n,2r_0)' title='B_n(p_n,2r_0)' class='latex' /> is uniformly bounded from above for sufficiently large n.</p>
<p style="text-align:left;">Now find a maximal <img src='http://s0.wp.com/latex.php?latex=%5Cdelta%2F4&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta/4' title='&#92;delta/4' class='latex' />-net <img src='http://s0.wp.com/latex.php?latex=x_%7Bn%2C1%7D%2C%5Cldots%2Cx_%7Bn%2Ck%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_{n,1},&#92;ldots,x_{n,k}' title='x_{n,1},&#92;ldots,x_{n,k}' class='latex' /> of <img src='http://s0.wp.com/latex.php?latex=B_n%28p_n%2Cr_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_n(p_n,r_0)' title='B_n(p_n,r_0)' class='latex' />, thus the balls <img src='http://s0.wp.com/latex.php?latex=B_n%28x_%7Bn%2C1%7D%2C%5Cdelta%2F8%29%2C+%5Cldots%2C+B_n%28x_%7Bn%2Ck%7D%2C%5Cdelta%2F8%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_n(x_{n,1},&#92;delta/8), &#92;ldots, B_n(x_{n,k},&#92;delta/8)' title='B_n(x_{n,1},&#92;delta/8), &#92;ldots, B_n(x_{n,k},&#92;delta/8)' class='latex' /> are disjoint and the balls <img src='http://s0.wp.com/latex.php?latex=B_n%28x_%7Bn%2C1%7D%2C%5Cdelta%2F4%29%2C+%5Cldots%2C+B_n%28x_%7Bn%2Ck%7D%2C%5Cdelta%2F4%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_n(x_{n,1},&#92;delta/4), &#92;ldots, B_n(x_{n,k},&#92;delta/4)' title='B_n(x_{n,1},&#92;delta/4), &#92;ldots, B_n(x_{n,k},&#92;delta/4)' class='latex' /> cover <img src='http://s0.wp.com/latex.php?latex=B_n%28p_n%2Cr_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_n(p_n,r_0)' title='B_n(p_n,r_0)' class='latex' />. Volume counting shows that k is bounded for all sufficiently large n; by passing to a subsequence we may assume that it is constant. Similarly we may assume that all the distances <img src='http://s0.wp.com/latex.php?latex=d_n%28x_%7Bn%2Ci%7D%2Cx_%7Bn%2Cj%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d_n(x_{n,i},x_{n,j})' title='d_n(x_{n,i},x_{n,j})' class='latex' /> converge to a limit. Using the exponential map and some arbitrary identification of tangent spaces with <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+R%7D%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb R}^d' title='{&#92;Bbb R}^d' class='latex' />, we can identify each ball <img src='http://s0.wp.com/latex.php?latex=B_n%28x_%7Bn%2Ci%7D%2C%5Cdelta%2F2%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_n(x_{n,i},&#92;delta/2)' title='B_n(x_{n,i},&#92;delta/2)' class='latex' /> with the standard Euclidean ball of radius <img src='http://s0.wp.com/latex.php?latex=%5Cdelta%2F2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta/2' title='&#92;delta/2' class='latex' />. Any pair <img src='http://s0.wp.com/latex.php?latex=x_%7Bn%2Ci%7D%2C+x_%7Bn%2Cj%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_{n,i}, x_{n,j}' title='x_{n,i}, x_{n,j}' class='latex' /> of separation less than <img src='http://s0.wp.com/latex.php?latex=%5Cdelta%2F2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta/2' title='&#92;delta/2' class='latex' /> induces a smooth transition map from the Euclidean ball of radius <img src='http://s0.wp.com/latex.php?latex=%5Cdelta%2F2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta/2' title='&#92;delta/2' class='latex' /> into some subset of <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+R%7D%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb R}^d' title='{&#92;Bbb R}^d' class='latex' />, which can be shown by comparison geometry to be uniformly bounded in <img src='http://s0.wp.com/latex.php?latex=C%5E%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C^&#92;infty' title='C^&#92;infty' class='latex' /> norms; applying the (<img src='http://s0.wp.com/latex.php?latex=C%5E%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C^&#92;infty' title='C^&#92;infty' class='latex' /> version of the) <a class="snap_noshots" href="http://en.wikipedia.org/wiki/Arzel%C3%A0-Ascoli_theorem">Arzelá-Ascoli theorem</a> we may thus pass to a subsequence and assume that all these transition maps converge in <img src='http://s0.wp.com/latex.php?latex=C%5E%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C^&#92;infty' title='C^&#92;infty' class='latex' /> to a limit. It is then a routine matter to glue together all the limit transition maps to fashion an incomplete manifold to which the balls <img src='http://s0.wp.com/latex.php?latex=B_n%28p_0%2Cr_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_n(p_0,r_0)' title='B_n(p_0,r_0)' class='latex' /> converge geometrically (up to errors of <img src='http://s0.wp.com/latex.php?latex=O%28%5Cdelta%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='O(&#92;delta)' title='O(&#92;delta)' class='latex' /> at the boundary). Furthermore, as one increases <img src='http://s0.wp.com/latex.php?latex=r_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_0' title='r_0' class='latex' />, one can show (by a modification of Exercise 1) that these limits are compatible. Now letting <img src='http://s0.wp.com/latex.php?latex=r_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_0' title='r_0' class='latex' /> go to infinity (and using the usual diagonalisation trick on all the subsequences obtained), and then gluing together all the incomplete limits obtained, one can create the full geometric limit. <img src='http://s0.wp.com/latex.php?latex=%5CBox&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Box' title='&#92;Box' class='latex' /></p>
<p style="text-align:left;"><strong>Remark 1.</strong> One could use <a class="snap_noshots" href="http://terrytao.wordpress.com/2007/06/25/ultrafilters-nonstandard-analysis-and-epsilon-management/">ultrafilters</a> here in place of subsequences, but this does not significantly affect any of the arguments. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>Now we turn to geometric limits of pointed Ricci flows (Ricci flows <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> with a specified origin <img src='http://s0.wp.com/latex.php?latex=p+%5Cin+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='p &#92;in M' title='p &#92;in M' class='latex' />).</p>
<blockquote><p><strong>Definition 2.</strong> Let <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M_n%2Cg_n%28t%29%2Cp_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M_n,g_n(t),p_n)' title='t &#92;mapsto (M_n,g_n(t),p_n)' class='latex' /> be a sequence of pointed d-dimensional complete connected Ricci flows, each on its own time interval <img src='http://s0.wp.com/latex.php?latex=I_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='I_n' title='I_n' class='latex' />. We say that a pointed d-dimensional complete connected Ricci flow <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M_%5Cinfty%2Cg_%5Cinfty%28t%29%2Cp_%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M_&#92;infty,g_&#92;infty(t),p_&#92;infty)' title='t &#92;mapsto (M_&#92;infty,g_&#92;infty(t),p_&#92;infty)' class='latex' /> on a time interval I is a geometric limit of this sequence if</p>
<ol>
<li>Every compact subinterval of I is contained in <img src='http://s0.wp.com/latex.php?latex=I_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='I_n' title='I_n' class='latex' /> for all sufficiently large n.</li>
<li>There exists neighbourhoods <img src='http://s0.wp.com/latex.php?latex=V_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='V_n' title='V_n' class='latex' /> of <img src='http://s0.wp.com/latex.php?latex=p_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='p_&#92;infty' title='p_&#92;infty' class='latex' /> as in Definition 1, compact time intervals <img src='http://s0.wp.com/latex.php?latex=J_n+%5Csubset+I&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='J_n &#92;subset I' title='J_n &#92;subset I' class='latex' /> increasing to I, and smooth embeddings <img src='http://s0.wp.com/latex.php?latex=%5Cphi_n%3A+V_n+%5Cto+M_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;phi_n: V_n &#92;to M_n' title='&#92;phi_n: V_n &#92;to M_n' class='latex' /> preserving the origin such that the pullback of the flow <img src='http://s0.wp.com/latex.php?latex=g_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='g_n' title='g_n' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=J_n+%5Ctimes+V_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='J_n &#92;times V_n' title='J_n &#92;times V_n' class='latex' /> converges in spacetime <img src='http://s0.wp.com/latex.php?latex=C%5E%5Cinfty_%7Bloc%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C^&#92;infty_{loc}' title='C^&#92;infty_{loc}' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=g_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='g_&#92;infty' title='g_&#92;infty' class='latex' />.</li>
</ol>
</blockquote>
<p><strong>Exercise 3.</strong> Show that if a sequence of <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsed Ricci flows (with a uniform value of <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />) converges geometrically to another Ricci flow, then the limit flow is also <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsed. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>Now we present <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=1333936">Hamilton&#8217;s compactness theorem</a> for Ricci flows, which requires less regularity hypotheses than Theorem 1 due to the parabolic smoothing effects of Ricci flow (as captured by Shi&#8217;s estimates, see Theorem 3).</p>
<blockquote><p><strong>Theorem 2.</strong> (Hamilton compactness theorem) Let <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M_n%2Cg_n%28t%29%2Cp_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M_n,g_n(t),p_n)' title='t &#92;mapsto (M_n,g_n(t),p_n)' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=I_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='I_n' title='I_n' class='latex' /> be as in Definition 2, and let I be an open interval obeying hypothesis 1 of that definition. Let <img src='http://s0.wp.com/latex.php?latex=t_0+%5Cin+I&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_0 &#92;in I' title='t_0 &#92;in I' class='latex' /> be a time. Suppose that</p>
<ol>
<li>For every compact subinterval J of I containing <img src='http://s0.wp.com/latex.php?latex=t_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_0' title='t_0' class='latex' /> and every <img src='http://s0.wp.com/latex.php?latex=r+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r &gt; 0' title='r &gt; 0' class='latex' />, one has the curvature bound <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Chbox%7BRiem%7D_n%26%23124%3B_%7Bg_n%7D+%5Cleq+K&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;hbox{Riem}_n&#124;_{g_n} &#92;leq K' title='&#124;&#92;hbox{Riem}_n&#124;_{g_n} &#92;leq K' class='latex' /> on the cylinder <img src='http://s0.wp.com/latex.php?latex=J+%5Ctimes+B_%7Bg_n%28t_0%29%7D%28p_n%2Cr%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='J &#92;times B_{g_n(t_0)}(p_n,r)' title='J &#92;times B_{g_n(t_0)}(p_n,r)' class='latex' /> for some <img src='http://s0.wp.com/latex.php?latex=K+%3D+K%28J%2Cr%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='K = K(J,r)' title='K = K(J,r)' class='latex' /> and all sufficiently large n; and</li>
<li>One has the non-collapsing bound <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BVol%7D_%7Bg_n%28t_0%29%7D%28B_%7Bg_n%28t_0%29%7D%28p_n%2Cr%29%29+%5Cgeq+%5Ckappa+r%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Vol}_{g_n(t_0)}(B_{g_n(t_0)}(p_n,r)) &#92;geq &#92;kappa r^d' title='&#92;hbox{Vol}_{g_n(t_0)}(B_{g_n(t_0)}(p_n,r)) &#92;geq &#92;kappa r^d' class='latex' /> for some <img src='http://s0.wp.com/latex.php?latex=r+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r &gt; 0' title='r &gt; 0' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Ckappa+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa &gt; 0' title='&#92;kappa &gt; 0' class='latex' />, and all sufficiently large n.</li>
<li>(Uniform lower bound on curvature)  For any compact J, there is a K such that for any <img src='http://s0.wp.com/latex.php?latex=r%26%2362%3B0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r&gt;0' title='r&gt;0' class='latex' />, one has the curvature lower bound <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRic%7D_n%28g_n%29+%5Cgeq+-K&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Ric}_n(g_n) &#92;geq -K' title='&#92;hbox{Ric}_n(g_n) &#92;geq -K' class='latex' /> on <img src='http://s0.wp.com/latex.php?latex=J+%5Ctimes+B_%7Bg_n%28t_0%29%7D%28p_n%2Cr%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='J &#92;times B_{g_n(t_0)}(p_n,r)' title='J &#92;times B_{g_n(t_0)}(p_n,r)' class='latex' /> for all sufficiently large n.  (This is not quite implied by 1. because the curvature bound K there is allowed to depend on r, whereas here we require that K is independent of r.)</li>
</ol>
<p>Then some subsequence of <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M_n%2Cg_n%28t%29%2Cp_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M_n,g_n(t),p_n)' title='t &#92;mapsto (M_n,g_n(t),p_n)' class='latex' /> converges geometrically to a limit <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M_%5Cinfty%2Cg_%5Cinfty%28t%29%2Cp_%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M_&#92;infty,g_&#92;infty(t),p_&#92;infty)' title='t &#92;mapsto (M_&#92;infty,g_&#92;infty(t),p_&#92;infty)' class='latex' /> on I.</p></blockquote>
<p>Condition 3 is technical (and was erroneously omitted in some of the literature), but it was recently observed <a href="http://arxiv.org/abs/1110.3714">by Topping</a> that the claim fails without some hypothesis of this form.  Fortunately, in the applications to the Poincare conjecture one always has a uniform lower bound on Ricci curvature, and so Condition 3 is not difficult to verify in practice.</p>
<p><strong>Proof. </strong> By Shi&#8217;s estimates (Theorem 3) we can upgrade the bound on curvature in hypothesis 1 to bounds on derivatives of curvature. Indeed, these estimates imply that for any J, r as in that hypothesis, and any <img src='http://s0.wp.com/latex.php?latex=k+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='k &#92;geq 0' title='k &#92;geq 0' class='latex' />, we have <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Cnabla%5Ek+%5Chbox%7BRiem%7D_n%26%23124%3B_%7Bg_n%7D+%5Cleq+K&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;nabla^k &#92;hbox{Riem}_n&#124;_{g_n} &#92;leq K' title='&#124;&#92;nabla^k &#92;hbox{Riem}_n&#124;_{g_n} &#92;leq K' class='latex' /> for some <img src='http://s0.wp.com/latex.php?latex=K+%3D+K%28J%2Cr%2Ck%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='K = K(J,r,k)' title='K = K(J,r,k)' class='latex' /> and sufficiently large n.</p>
<p>Now we restrict to the time slice <img src='http://s0.wp.com/latex.php?latex=t%3Dt_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t=t_0' title='t=t_0' class='latex' /> and apply Theorem 1. Passing to a subsequence, we can assume that <img src='http://s0.wp.com/latex.php?latex=%28M_n%2Cg_n%28t_0%29%2Cp_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M_n,g_n(t_0),p_n)' title='(M_n,g_n(t_0),p_n)' class='latex' /> converges geometrically to a limit <img src='http://s0.wp.com/latex.php?latex=%28M_%5Cinfty%2Cg_%5Cinfty%28t_0%29%2Cp_%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M_&#92;infty,g_&#92;infty(t_0),p_&#92;infty)' title='(M_&#92;infty,g_&#92;infty(t_0),p_&#92;infty)' class='latex' />.</p>
<p>For any radius r and any compact J in I containing <img src='http://s0.wp.com/latex.php?latex=t_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_0' title='t_0' class='latex' />, we can pull back the flow <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M_n%2Cg_n%28t%29%2Cp_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M_n,g_n(t),p_n)' title='t &#92;mapsto (M_n,g_n(t),p_n)' class='latex' /> to a (spatially incomplete) flow <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28B_%7Bg_%5Cinfty%28t_0%29%7D%28p_%5Cinfty%2Cr%29%2C+%5Ctilde+g_n%28t%29%2C+p_%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (B_{g_&#92;infty(t_0)}(p_&#92;infty,r), &#92;tilde g_n(t), p_&#92;infty)' title='t &#92;mapsto (B_{g_&#92;infty(t_0)}(p_&#92;infty,r), &#92;tilde g_n(t), p_&#92;infty)' class='latex' /> on the cylinder <img src='http://s0.wp.com/latex.php?latex=J+%5Ctimes+B_%7Bg_%5Cinfty%28t_0%29%7D%28p_%5Cinfty%2Cr%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='J &#92;times B_{g_&#92;infty(t_0)}(p_&#92;infty,r)' title='J &#92;times B_{g_&#92;infty(t_0)}(p_&#92;infty,r)' class='latex' /> for sufficiently large n. By construction, <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+g_n%28t_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde g_n(t_0)' title='&#92;tilde g_n(t_0)' class='latex' /> converges in <img src='http://s0.wp.com/latex.php?latex=C%5E%5Cinfty_%7Bloc%7D%28B_%7Bg_%5Cinfty%28t_0%29%7D%28p_%5Cinfty%2Cr%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C^&#92;infty_{loc}(B_{g_&#92;infty(t_0)}(p_&#92;infty,r))' title='C^&#92;infty_{loc}(B_{g_&#92;infty(t_0)}(p_&#92;infty,r))' class='latex' /> norm to <img src='http://s0.wp.com/latex.php?latex=g_%5Cinfty%28t_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='g_&#92;infty(t_0)' title='g_&#92;infty(t_0)' class='latex' />; in particular, it is uniformly bounded in each of the seminorms of this space. Also, each <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%5Ctilde+g_n%28t%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto &#92;tilde g_n(t)' title='t &#92;mapsto &#92;tilde g_n(t)' class='latex' /> is a Ricci flow with uniform bounds on any derivative of curvature for sufficiently large n.</p>
<p><strong>Exercise 4.</strong> Using these facts, show that the sequence of flows <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%5Ctilde+g_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto &#92;tilde g_n' title='t &#92;mapsto &#92;tilde g_n' class='latex' /> is uniformly bounded in each of the seminorms of <img src='http://s0.wp.com/latex.php?latex=C%5E%5Cinfty_%7Bloc%7D%28J+%5Ctimes+B_%7Bg_%5Cinfty%28t_0%29%7D%28p_%5Cinfty%2Cr%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C^&#92;infty_{loc}(J &#92;times B_{g_&#92;infty(t_0)}(p_&#92;infty,r))' title='C^&#92;infty_{loc}(J &#92;times B_{g_&#92;infty(t_0)}(p_&#92;infty,r))' class='latex' /> for each fixed J, r, and for n sufficiently large. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>By using the <a href="http://en.wikipedia.org/wiki/Arzel%C3%A0-Ascoli_theorem">Arzelá-Ascoli theorem</a> as before, we may thus pass to a further subsequence and assume that <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%5Ctilde+g_n%28t%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto &#92;tilde g_n(t)' title='t &#92;mapsto &#92;tilde g_n(t)' class='latex' /> converges in <img src='http://s0.wp.com/latex.php?latex=C%5E%5Cinfty_%7Bloc%7D%28J+%5Ctimes+B_%7Bg_%5Cinfty%28t_0%29%7D%28p_%5Cinfty%2Cr%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C^&#92;infty_{loc}(J &#92;times B_{g_&#92;infty(t_0)}(p_&#92;infty,r))' title='C^&#92;infty_{loc}(J &#92;times B_{g_&#92;infty(t_0)}(p_&#92;infty,r))' class='latex' /> to a limiting flow <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+g_%5Cinfty%28t%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto g_&#92;infty(t)' title='t &#92;mapsto g_&#92;infty(t)' class='latex' />. Clearly this limit is a Ricci flow. Letting <img src='http://s0.wp.com/latex.php?latex=r+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r &#92;to &#92;infty' title='r &#92;to &#92;infty' class='latex' /> and pasting together the resulting limits one obtains the desired geometric limit. (One has to verify that every geodesic in <img src='http://s0.wp.com/latex.php?latex=%28M_%5Cinfty%2Cg_%5Cinfty%28t%29%2Cp_%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M_&#92;infty,g_&#92;infty(t),p_&#92;infty)' title='(M_&#92;infty,g_&#92;infty(t),p_&#92;infty)' class='latex' /> starting from <img src='http://s0.wp.com/latex.php?latex=p_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='p_&#92;infty' title='p_&#92;infty' class='latex' /> can be extended to any desired length, thus establishing completeness by the <a href="http://en.wikipedia.org/wiki/Hopf-Rinow_theorem">Hopf-Rinow theorem</a>, but this is easy to establish given all the uniform bounds on the metric and curvature, and their derivatives. It is here that hypothesis 3 is used to prevent the metric from shrinking too rapidly as one goes backwards in time. ) <img src='http://s0.wp.com/latex.php?latex=%5CBox&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Box' title='&#92;Box' class='latex' /></p>
<p style="text-align:center;">&#8211; Locating an asymptotic gradient shrinking soliton &#8211;</p>
<p>We now return to the study of <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' />. We pick an arbitrary point <img src='http://s0.wp.com/latex.php?latex=x_0+%5Cin+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0 &#92;in M' title='x_0 &#92;in M' class='latex' /> and consider the reduced length function <img src='http://s0.wp.com/latex.php?latex=l+%3D+l_%7B%280%2Cx_0%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l = l_{(0,x_0)}' title='l = l_{(0,x_0)}' class='latex' />. Recall (see equation (18) from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/14/285g-lecture-11-%ce%ba-noncollapsing-via-perelman-reduced-volume/">Lecture 11</a>) that we had</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cinf_%7Bx+%5Cin+M%7D+l%28t%2Cx%29+%26%2360%3B+d%2F2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;inf_{x &#92;in M} l(t,x) &lt; d/2' title='&#92;inf_{x &#92;in M} l(t,x) &lt; d/2' class='latex' /> (1)</p>
<p>for every <img src='http://s0.wp.com/latex.php?latex=t+%26%2360%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &lt; 0' title='t &lt; 0' class='latex' />. (This bound was obtained from the parabolic inequality <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_%5Ctau+l+%5Cgeq+%5CDelta+l+%2B+%5Cfrac%7Bl-%28d%2F2%29%7D%7B%5Ctau%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_&#92;tau l &#92;geq &#92;Delta l + &#92;frac{l-(d/2)}{&#92;tau}' title='&#92;partial_&#92;tau l &#92;geq &#92;Delta l + &#92;frac{l-(d/2)}{&#92;tau}' class='latex' /> and the maximum principle.) Thus we can find a sequence <img src='http://s0.wp.com/latex.php?latex=%28-%5Ctau_n%2C+x_n%29+%5Cin+%28-%5Cinfty%2C0%5D+%5Ctimes+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(-&#92;tau_n, x_n) &#92;in (-&#92;infty,0] &#92;times M' title='(-&#92;tau_n, x_n) &#92;in (-&#92;infty,0] &#92;times M' class='latex' /> with <img src='http://s0.wp.com/latex.php?latex=%5Ctau_n+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau_n &#92;to &#92;infty' title='&#92;tau_n &#92;to &#92;infty' class='latex' /> such that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=l%28-%5Ctau_n%2Cx_n%29+%3D+O%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l(-&#92;tau_n,x_n) = O(1)' title='l(-&#92;tau_n,x_n) = O(1)' class='latex' />. (2)</p>
<p>Now recall that as a consequence of Hamilton&#8217;s Harnack inequality, we have the pointwise estimates</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+0+%5Cleq+%26%23124%3B%5Cnabla+l%26%23124%3B%5E2+%2B+R+%5Cleq+%5Cfrac%7B3l%7D%7B%5Ctau%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle 0 &#92;leq &#124;&#92;nabla l&#124;^2 + R &#92;leq &#92;frac{3l}{&#92;tau}' title='&#92;displaystyle 0 &#92;leq &#124;&#92;nabla l&#124;^2 + R &#92;leq &#92;frac{3l}{&#92;tau}' class='latex' /> (3)</p>
<p>and</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+-%5Cfrac%7B2l%7D%7B%5Ctau%7D+%5Cleq+%5Cpartial_t+l+%5Cleq+%5Cfrac%7Bl%7D%7B%5Ctau%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle -&#92;frac{2l}{&#92;tau} &#92;leq &#92;partial_t l &#92;leq &#92;frac{l}{&#92;tau}' title='&#92;displaystyle -&#92;frac{2l}{&#92;tau} &#92;leq &#92;partial_t l &#92;leq &#92;frac{l}{&#92;tau}' class='latex' /> (4)</p>
<p>(see equations (37), (38) from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/19/285g-lecture-13-li-yau-hamilton-harnack-inequalities-and-%ce%ba-solutions/">Lecture 13</a>). From these bounds and Gronwall&#8217;s inequality, one easily sees that we can extend (2) to say that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=l%28-%5Ctau%2Cx%29+%3D+O_r%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l(-&#92;tau,x) = O_r(1)' title='l(-&#92;tau,x) = O_r(1)' class='latex' /> (5)</p>
<p>for any <img src='http://s0.wp.com/latex.php?latex=%28-%5Ctau%2Cx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(-&#92;tau,x)' title='(-&#92;tau,x)' class='latex' /> in the cylinder <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5B-%5Ctau_n%2Fr%2C+-r%5Ctau_n%5D+%5Ctimes+B_%7Bg%28-%5Ctau%27%29%7D%28x_n%2Cr%5Csqrt%7B%5Ctau_n%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[-&#92;tau_n/r, -r&#92;tau_n] &#92;times B_{g(-&#92;tau&#039;)}(x_n,r&#92;sqrt{&#92;tau_n})' title='{}[-&#92;tau_n/r, -r&#92;tau_n] &#92;times B_{g(-&#92;tau&#039;)}(x_n,r&#92;sqrt{&#92;tau_n})' class='latex' /> and any <img src='http://s0.wp.com/latex.php?latex=r+%5Cgeq+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r &#92;geq 1' title='r &#92;geq 1' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Ctau_n%2Fr+%5Cleq+%5Ctau%27+%5Cleq+r%5Ctau_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau_n/r &#92;leq &#92;tau&#039; &#92;leq r&#92;tau_n' title='&#92;tau_n/r &#92;leq &#92;tau&#039; &#92;leq r&#92;tau_n' class='latex' />. Applying (3) once more, together with the hypothesis of non-negative curvature more, we also obtain bounded normalised curvature on this cylinder:</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Chbox%7BRiem%7D%28-%5Ctau%2Cx%29%26%23124%3B_g+%3D+O_r%28+%5Ctau%5E%7B-1%7D+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;hbox{Riem}(-&#92;tau,x)&#124;_g = O_r( &#92;tau^{-1} )' title='&#124;&#92;hbox{Riem}(-&#92;tau,x)&#124;_g = O_r( &#92;tau^{-1} )' class='latex' /> (6).</p>
<p>If we thus introduce the rescaled flow <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M_n%2C+g_n%28t%29%2C+p_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M_n, g_n(t), p_n)' title='t &#92;mapsto (M_n, g_n(t), p_n)' class='latex' /> by setting <img src='http://s0.wp.com/latex.php?latex=M_n+%3A%3D+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M_n := M' title='M_n := M' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=p_n+%3A%3D+x_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='p_n := x_n' title='p_n := x_n' class='latex' />, and <img src='http://s0.wp.com/latex.php?latex=g_n%28t%29+%3A%3D+t_n+g%28t+t_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='g_n(t) := t_n g(t t_n)' title='g_n(t) := t_n g(t t_n)' class='latex' />, we see that these flows obey hypothesis 1 of Theorem 2. Also, since the original <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions are <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsed, so are their rescalings, which (in conjunction with hypothesis 1) gives us hypothesis 2. We can thus invoke Theorem 2 and assume (after passing to a subsequence) that the rescaled flows converge geometrically to an ancient Ricci flow <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M_%5Cinfty%2C+g_%5Cinfty%28t%29%2C+p_%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M_&#92;infty, g_&#92;infty(t), p_&#92;infty)' title='t &#92;mapsto (M_&#92;infty, g_&#92;infty(t), p_&#92;infty)' class='latex' /> on the time interval <img src='http://s0.wp.com/latex.php?latex=t+%5Cin+%28-%5Cinfty%2C0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;in (-&#92;infty,0)' title='t &#92;in (-&#92;infty,0)' class='latex' />. From Exercise 3 we see that this limit is also <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsed. Since the rescaled flows have non-negative curvature, the limit flow has non-negative curvature also. (Note however that we do not expect in general that <img src='http://s0.wp.com/latex.php?latex=%28M_%5Cinfty%2Cg_%5Cinfty%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M_&#92;infty,g_&#92;infty(t))' title='(M_&#92;infty,g_&#92;infty(t))' class='latex' /> has bounded curvature (for instance, if the original <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution was a round shrinking sphere terminating at the unit radius sphere, the limit object would be a round shrinking sphere terminating at a point). In particular we do not expect <img src='http://s0.wp.com/latex.php?latex=%28M_%5Cinfty%2Cg_%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M_&#92;infty,g_&#92;infty)' title='(M_&#92;infty,g_&#92;infty)' class='latex' /> to be a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution.)</p>
<p>Let <img src='http://s0.wp.com/latex.php?latex=l_n%3A+%28-%5Cinfty%2C0%29+%5Ctimes+M_n+%5Cto+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_n: (-&#92;infty,0) &#92;times M_n &#92;to {&#92;Bbb R}' title='l_n: (-&#92;infty,0) &#92;times M_n &#92;to {&#92;Bbb R}' class='latex' /> be the rescaled length function, thus <img src='http://s0.wp.com/latex.php?latex=l_n%28t%2Cx%29+%3A%3D+l%28t+t_n%2C+x%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_n(t,x) := l(t t_n, x)' title='l_n(t,x) := l(t t_n, x)' class='latex' />. From (5) we see that <img src='http://s0.wp.com/latex.php?latex=l_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_n' title='l_n' class='latex' /> is uniformly bounded on compact subsets of <img src='http://s0.wp.com/latex.php?latex=%28-%5Cinfty%2C0%29+%5Ctimes+M_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(-&#92;infty,0) &#92;times M_&#92;infty' title='(-&#92;infty,0) &#92;times M_&#92;infty' class='latex' /> for n sufficiently large (where we identify compact subsets of <img src='http://s0.wp.com/latex.php?latex=M_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M_&#92;infty' title='M_&#92;infty' class='latex' /> with subsets of <img src='http://s0.wp.com/latex.php?latex=M_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M_n' title='M_n' class='latex' /> for n large enough). By the rescaled versions of (4) and (5) we also see that <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Cnabla+l_n%26%23124%3B_%7Bg_%5Cinfty%7D%2C+%26%23124%3B%5Cpartial_t+l_n%26%23124%3B&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;nabla l_n&#124;_{g_&#92;infty}, &#124;&#92;partial_t l_n&#124;' title='&#124;&#92;nabla l_n&#124;_{g_&#92;infty}, &#124;&#92;partial_t l_n&#124;' class='latex' /> is also uniformly bounded on such compact sets for sufficiently large n; thus the <img src='http://s0.wp.com/latex.php?latex=l_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_n' title='l_n' class='latex' /> are uniformly Lipschitz on each compact set. Applying the <a href="http://en.wikipedia.org/wiki/Arzel%C3%A0-Ascoli_theorem">Arzelá-Ascoli theorem</a> and passing to a subsequence, we may thus assume that the <img src='http://s0.wp.com/latex.php?latex=l_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_n' title='l_n' class='latex' /> converge uniformly on compact sets to some limit <img src='http://s0.wp.com/latex.php?latex=l_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_&#92;infty' title='l_&#92;infty' class='latex' />, which is then locally Lipschitz.</p>
<p><strong>Remark 2.</strong> We do not attempt to interpret <img src='http://s0.wp.com/latex.php?latex=l_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_&#92;infty' title='l_&#92;infty' class='latex' /> as a reduced length function arising from some point at time t=0; indeed we expect the limiting flow to develop a singularity at this time. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>We know that the reduced volume <img src='http://s0.wp.com/latex.php?latex=%5Cint_M+%5Ctau%5E%7B-d%2F2%7D+e%5E%7B-l%7D%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_M &#92;tau^{-d/2} e^{-l}&#92; d&#92;mu' title='&#92;int_M &#92;tau^{-d/2} e^{-l}&#92; d&#92;mu' class='latex' /> is non-increasing in <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' /> and ranges between 0 and <img src='http://s0.wp.com/latex.php?latex=%284%5Cpi%29%5E%7Bd%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(4&#92;pi)^{d/2}' title='(4&#92;pi)^{d/2}' class='latex' />, and so converges to a limit <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+V%28-%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde V(-&#92;infty)' title='&#92;tilde V(-&#92;infty)' class='latex' /> between 0 and <img src='http://s0.wp.com/latex.php?latex=%284%5Cpi%29%5E%7Bd%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(4&#92;pi)^{d/2}' title='(4&#92;pi)^{d/2}' class='latex' />. This limit cannot equal <img src='http://s0.wp.com/latex.php?latex=%284%5Cpi%29%5E%7Bd%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(4&#92;pi)^{d/2}' title='(4&#92;pi)^{d/2}' class='latex' /> since this would mean that the <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution is flat (by Theorem 1 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/21/285g-lecture-14-stationary-points-of-perelman-entropy-or-reduced-volume-are-gradient-shrinking-solitons/">Lecture 14</a>), which is absurd. The limit cannot be zero either, since the bounds (5) and the non-collapsing ensure a uniform lower bound on the reduced volume. By rescaling, we conclude that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cint_%7BM_n%7D+%5Ctau%5E%7B-d%2F2%7D+e%5E%7B-l_n%7D%5C+d%5Cmu_n+%5Cto+%5Ctilde+V%28-%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_{M_n} &#92;tau^{-d/2} e^{-l_n}&#92; d&#92;mu_n &#92;to &#92;tilde V(-&#92;infty)' title='&#92;int_{M_n} &#92;tau^{-d/2} e^{-l_n}&#92; d&#92;mu_n &#92;to &#92;tilde V(-&#92;infty)' class='latex' /> (7)</p>
<p>for each fixed <img src='http://s0.wp.com/latex.php?latex=%5Ctau+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau &gt; 0' title='&#92;tau &gt; 0' class='latex' />.</p>
<p>Let us now argue informally, and then return to make the argument rigorous later. Formally taking limits in (7), we conclude that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cint_%7BM_%5Cinfty%7D+%5Ctau%5E%7B-d%2F2%7D+e%5E%7B-l_%5Cinfty%7D%5C+d%5Cmu_%5Cinfty+%3D+%5Ctilde+V%28-%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_{M_&#92;infty} &#92;tau^{-d/2} e^{-l_&#92;infty}&#92; d&#92;mu_&#92;infty = &#92;tilde V(-&#92;infty)' title='&#92;int_{M_&#92;infty} &#92;tau^{-d/2} e^{-l_&#92;infty}&#92; d&#92;mu_&#92;infty = &#92;tilde V(-&#92;infty)' class='latex' />. (8)</p>
<p>On the other hand, from the proof of the monotonicity of reduced volume from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/09/285g-lecture-10-variation-of-l-geodesics-and-monotonicity-of-perelman-reduced-volume/">Lecture 10</a> we have (formally, at least)</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cpartial_%7B%5Ctau%7D+l+-+%5CDelta+l+%2B+%26%23124%3B%5Cnabla+l%26%23124%3B_g%5E2+-+R+%2B+%5Cfrac%7Bd%7D%7B2%5Ctau%7D+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;partial_{&#92;tau} l - &#92;Delta l + &#124;&#92;nabla l&#124;_g^2 - R + &#92;frac{d}{2&#92;tau} &#92;geq 0' title='&#92;displaystyle &#92;partial_{&#92;tau} l - &#92;Delta l + &#124;&#92;nabla l&#124;_g^2 - R + &#92;frac{d}{2&#92;tau} &#92;geq 0' class='latex' /> (9)</p>
<p>and hence by rescaling</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cpartial_%7B%5Ctau%7D+l_n+-+%5CDelta+l_n+%2B+%26%23124%3B%5Cnabla+l_n%26%23124%3B_%7Bg_n%7D%5E2+-+R+%2B+%5Cfrac%7Bd%7D%7B2%5Ctau%7D+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;partial_{&#92;tau} l_n - &#92;Delta l_n + &#124;&#92;nabla l_n&#124;_{g_n}^2 - R + &#92;frac{d}{2&#92;tau} &#92;geq 0' title='&#92;displaystyle &#92;partial_{&#92;tau} l_n - &#92;Delta l_n + &#124;&#92;nabla l_n&#124;_{g_n}^2 - R + &#92;frac{d}{2&#92;tau} &#92;geq 0' class='latex' />. (10)</p>
<p>Formally taking limits, we obtain</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cpartial_%7B%5Ctau%7D+l_%5Cinfty+-+%5CDelta+l_%5Cinfty+%2B+%26%23124%3B%5Cnabla+l_%5Cinfty%26%23124%3B_%7Bg_%5Cinfty%7D%5E2+-+R_%5Cinfty+%2B+%5Cfrac%7Bd%7D%7B2%5Ctau%7D+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;partial_{&#92;tau} l_&#92;infty - &#92;Delta l_&#92;infty + &#124;&#92;nabla l_&#92;infty&#124;_{g_&#92;infty}^2 - R_&#92;infty + &#92;frac{d}{2&#92;tau} &#92;geq 0' title='&#92;displaystyle &#92;partial_{&#92;tau} l_&#92;infty - &#92;Delta l_&#92;infty + &#124;&#92;nabla l_&#92;infty&#124;_{g_&#92;infty}^2 - R_&#92;infty + &#92;frac{d}{2&#92;tau} &#92;geq 0' class='latex' />. (11)</p>
<p>We can rewrite this as the assertion that <img src='http://s0.wp.com/latex.php?latex=%5Ctau%5E%7B-d%2F2%7D+e%5E%7B-l_%5Cinfty%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau^{-d/2} e^{-l_&#92;infty}' title='&#92;tau^{-d/2} e^{-l_&#92;infty}' class='latex' /> is a subsolution of the backwards heat equation:</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%28%5Cpartial_%5Ctau+-+%5CDelta_%7Bg_%5Cinfty%7D+-+R_%5Cinfty%29+%28+%5Ctau%5E%7B-d%2F2%7D+e%5E%7B-l_%5Cinfty%7D+%29+%5Cleq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;partial_&#92;tau - &#92;Delta_{g_&#92;infty} - R_&#92;infty) ( &#92;tau^{-d/2} e^{-l_&#92;infty} ) &#92;leq 0' title='(&#92;partial_&#92;tau - &#92;Delta_{g_&#92;infty} - R_&#92;infty) ( &#92;tau^{-d/2} e^{-l_&#92;infty} ) &#92;leq 0' class='latex' />. (12)</p>
<p>This (formally) implies that the left-hand side of (8) is non-increasing in <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' />. On the other hand, this quantity is constant in <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' />; and so (12) must be obeyed with equality, and thus</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cpartial_%7B%5Ctau%7D+l_%5Cinfty+-+%5CDelta+l_%5Cinfty+%2B+%26%23124%3B%5Cnabla+l_%5Cinfty%26%23124%3B%5E2+-+R_%5Cinfty+%2B+%5Cfrac%7Bd%7D%7B2%5Ctau%7D+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;partial_{&#92;tau} l_&#92;infty - &#92;Delta l_&#92;infty + &#124;&#92;nabla l_&#92;infty&#124;^2 - R_&#92;infty + &#92;frac{d}{2&#92;tau} = 0' title='&#92;displaystyle &#92;partial_{&#92;tau} l_&#92;infty - &#92;Delta l_&#92;infty + &#124;&#92;nabla l_&#92;infty&#124;^2 - R_&#92;infty + &#92;frac{d}{2&#92;tau} = 0' class='latex' />. (13)</p>
<p>Also, recall from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/09/285g-lecture-10-variation-of-l-geodesics-and-monotonicity-of-perelman-reduced-volume/">Lecture 10</a> that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cpartial_%5Ctau+l+%3D+%5Cfrac%7B1%7D%7B2%7D+R+-+%5Cfrac%7B1%7D%7B2%7D+%26%23124%3B%5Cnabla+l%26%23124%3B_g%5E2+-+%5Cfrac%7B1%7D%7B2%5Ctau%7D+l&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;partial_&#92;tau l = &#92;frac{1}{2} R - &#92;frac{1}{2} &#124;&#92;nabla l&#124;_g^2 - &#92;frac{1}{2&#92;tau} l' title='&#92;displaystyle &#92;partial_&#92;tau l = &#92;frac{1}{2} R - &#92;frac{1}{2} &#124;&#92;nabla l&#124;_g^2 - &#92;frac{1}{2&#92;tau} l' class='latex' />. (14)</p>
<p>Rescaling and taking limits, we formally conclude that the same is true for <img src='http://s0.wp.com/latex.php?latex=l_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_&#92;infty' title='l_&#92;infty' class='latex' />;</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cpartial_%5Ctau+l_%5Cinfty+%3D+%5Cfrac%7B1%7D%7B2%7D+R_%5Cinfty+-+%5Cfrac%7B1%7D%7B2%7D+%26%23124%3B%5Cnabla+l_%5Cinfty%26%23124%3B_%7Bg_%5Cinfty%7D%5E2+-+%5Cfrac%7B1%7D%7B2%5Ctau%7D+l_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;partial_&#92;tau l_&#92;infty = &#92;frac{1}{2} R_&#92;infty - &#92;frac{1}{2} &#124;&#92;nabla l_&#92;infty&#124;_{g_&#92;infty}^2 - &#92;frac{1}{2&#92;tau} l_&#92;infty' title='&#92;displaystyle &#92;partial_&#92;tau l_&#92;infty = &#92;frac{1}{2} R_&#92;infty - &#92;frac{1}{2} &#124;&#92;nabla l_&#92;infty&#124;_{g_&#92;infty}^2 - &#92;frac{1}{2&#92;tau} l_&#92;infty' class='latex' />. (15)</p>
<p>From (14) and (15) we obtain that the Perelman <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+W%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal W}' title='{&#92;mathcal W}' class='latex' />-functional</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%7B%5Cmathcal+W%7D%28M_%5Cinfty%2Cg_%5Cinfty%28t%29%2Cl_%5Cinfty%2C%5Ctau%29+%3D+&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle {&#92;mathcal W}(M_&#92;infty,g_&#92;infty(t),l_&#92;infty,&#92;tau) = ' title='&#92;displaystyle {&#92;mathcal W}(M_&#92;infty,g_&#92;infty(t),l_&#92;infty,&#92;tau) = ' class='latex' /></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cint_%7BM+_%5Cinfty%7D%28%5Ctau%28%26%23124%3B%5Cnabla+l_%5Cinfty%26%23124%3B%5E2+%2B+R_%5Cinfty%29+%2B+l_%5Cinfty+-+d%29+%284%5Cpi%5Ctau%29%5E%7B-d%2F2%7D+e%5E%7B-l_%5Cinfty%7D%5C+d%5Cmu_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;int_{M _&#92;infty}(&#92;tau(&#124;&#92;nabla l_&#92;infty&#124;^2 + R_&#92;infty) + l_&#92;infty - d) (4&#92;pi&#92;tau)^{-d/2} e^{-l_&#92;infty}&#92; d&#92;mu_&#92;infty' title='&#92;displaystyle &#92;int_{M _&#92;infty}(&#92;tau(&#124;&#92;nabla l_&#92;infty&#124;^2 + R_&#92;infty) + l_&#92;infty - d) (4&#92;pi&#92;tau)^{-d/2} e^{-l_&#92;infty}&#92; d&#92;mu_&#92;infty' class='latex' /> (16)</p>
<p>vanishes (cf. the last section of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/14/285g-lecture-11-%ce%ba-noncollapsing-via-perelman-reduced-volume/">Lecture 11</a>). In particular, it is constant. On the other hand, by (13) and the monotonicity formula for this functional (see Exercise 9 of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/24/285a-lecture-8-ricci-flow-as-a-gradient-flow-log-sobolev-inequalities-and-perelman-entropy/">Lecture 8</a>) we have</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7B%5Cpartial%7D%7B%5Cpartial+%5Ctau%7D+%7B%5Cmathcal+W%7D%28M_%5Cinfty%2Cg_%5Cinfty%28t%29%2Cl_%5Cinfty%2C%5Ctau%29+%3D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{&#92;partial}{&#92;partial &#92;tau} {&#92;mathcal W}(M_&#92;infty,g_&#92;infty(t),l_&#92;infty,&#92;tau) =' title='&#92;displaystyle &#92;frac{&#92;partial}{&#92;partial &#92;tau} {&#92;mathcal W}(M_&#92;infty,g_&#92;infty(t),l_&#92;infty,&#92;tau) =' class='latex' /></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+-+%5Cint_M+2%5Ctau+%26%23124%3B%5Chbox%7BRic%7D_%5Cinfty+%2B+%5Chbox%7BHess%7D%28l_%5Cinfty%29-+%5Cfrac%7B1%7D%7B2%5Ctau%7D+g_%5Cinfty%26%23124%3B_%7Bg_%5Cinfty%7D%5E2+%284%5Cpi+%5Ctau%29%5E%7B-d%2F2%7D+e%5E%7B-l_%5Cinfty%7D%5C+d%5Cmu_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle - &#92;int_M 2&#92;tau &#124;&#92;hbox{Ric}_&#92;infty + &#92;hbox{Hess}(l_&#92;infty)- &#92;frac{1}{2&#92;tau} g_&#92;infty&#124;_{g_&#92;infty}^2 (4&#92;pi &#92;tau)^{-d/2} e^{-l_&#92;infty}&#92; d&#92;mu_&#92;infty' title='&#92;displaystyle - &#92;int_M 2&#92;tau &#124;&#92;hbox{Ric}_&#92;infty + &#92;hbox{Hess}(l_&#92;infty)- &#92;frac{1}{2&#92;tau} g_&#92;infty&#124;_{g_&#92;infty}^2 (4&#92;pi &#92;tau)^{-d/2} e^{-l_&#92;infty}&#92; d&#92;mu_&#92;infty' class='latex' />. (17)</p>
<p>Combining this with the vanishing of (16) we thus conclude that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRic%7D_%5Cinfty+%2B+%5Chbox%7BHess%7D%28l_%5Cinfty%29-+%5Cfrac%7B1%7D%7B2%5Ctau%7D+g_%5Cinfty+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Ric}_&#92;infty + &#92;hbox{Hess}(l_&#92;infty)- &#92;frac{1}{2&#92;tau} g_&#92;infty = 0' title='&#92;hbox{Ric}_&#92;infty + &#92;hbox{Hess}(l_&#92;infty)- &#92;frac{1}{2&#92;tau} g_&#92;infty = 0' class='latex' /> (18)</p>
<p>and thus <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M_%5Cinfty%2Cg_%5Cinfty%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M_&#92;infty,g_&#92;infty(t))' title='t &#92;mapsto (M_&#92;infty,g_&#92;infty(t))' class='latex' /> is a gradient shrinking soliton as desired.</p>
<p style="text-align:center;">&#8211; Making the argument rigorous I. Spatial localisation &#8211;</p>
<p>Now we turn to the (surprisingly delicate) task of justifying the steps from (7) to (18).</p>
<p>The first task is to deduce (8) from (7). From the dominated convergence theorem it is not difficult to show that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cint_%7BB_n%28p_n%2Cr%29%7D+%5Ctau%5E%7B-d%2F2%7D+e%5E%7B-l_n%7D%5C+d%5Cmu_n+%5Cto+%5Cint_%7BB_%5Cinfty%28p_%5Cinfty%2Cr%29%7D+%5Ctau%5E%7B-d%2F2%7D+e%5E%7B-l_%5Cinfty%7D%5C+d%5Cmu_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_{B_n(p_n,r)} &#92;tau^{-d/2} e^{-l_n}&#92; d&#92;mu_n &#92;to &#92;int_{B_&#92;infty(p_&#92;infty,r)} &#92;tau^{-d/2} e^{-l_&#92;infty}&#92; d&#92;mu_&#92;infty' title='&#92;int_{B_n(p_n,r)} &#92;tau^{-d/2} e^{-l_n}&#92; d&#92;mu_n &#92;to &#92;int_{B_&#92;infty(p_&#92;infty,r)} &#92;tau^{-d/2} e^{-l_&#92;infty}&#92; d&#92;mu_&#92;infty' class='latex' /> (19)</p>
<p>for any fixed <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' /> and r; the difficulty is to prevent the escape of mass of <img src='http://s0.wp.com/latex.php?latex=e%5E%7B-l_n%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='e^{-l_n}' title='e^{-l_n}' class='latex' /> to spatial infinity. (<a href="http://en.wikipedia.org/wiki/Fatou%27s_lemma">Fatou&#8217;s lemma</a> will tell us that the left-hand side of (8) is less than or equal to the right, but this is not enough for our application.)</p>
<p>In order to prevent such an escape, one needs a lower bound on <img src='http://s0.wp.com/latex.php?latex=l_n%28-%5Ctau%2Cx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_n(-&#92;tau,x)' title='l_n(-&#92;tau,x)' class='latex' /> when <img src='http://s0.wp.com/latex.php?latex=d_%7Bg_n%28-%5Ctau%29%7D%28x_n%2Cx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d_{g_n(-&#92;tau)}(x_n,x)' title='d_{g_n(-&#92;tau)}(x_n,x)' class='latex' /> is large. (Note that estimates such as (3), (4) only provide upper bounds on <img src='http://s0.wp.com/latex.php?latex=l_n%28-%5Ctau%2Cx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_n(-&#92;tau,x)' title='l_n(-&#92;tau,x)' class='latex' />.) The problem is equivalent to that of upper bounding <img src='http://s0.wp.com/latex.php?latex=d_%7Bg_n%28-%5Ctau%29%7D%28x_n%2Cx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d_{g_n(-&#92;tau)}(x_n,x)' title='d_{g_n(-&#92;tau)}(x_n,x)' class='latex' /> in terms of <img src='http://s0.wp.com/latex.php?latex=l_n%28-%5Ctau%2Cx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_n(-&#92;tau,x)' title='l_n(-&#92;tau,x)' class='latex' />. To do this we need some control on quantities related to the distance function at extremely large distances. Remarkably, such bounds are possible. We begin with a lemma <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0211159">of Perelman</a> (related to an earlier argument <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=1375255">of Hamilton</a>).</p>
<blockquote><p><strong>Lemma 1.</strong> Let <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g)' title='(M,g)' class='latex' /> be a d-dimensional Riemannian manifold, let <img src='http://s0.wp.com/latex.php?latex=x%2C+y+%5Cin+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x, y &#92;in M' title='x, y &#92;in M' class='latex' />, and let <img src='http://s0.wp.com/latex.php?latex=r+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r &gt; 0' title='r &gt; 0' class='latex' />. Suppose that <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRic%7D+%5Cleq+K&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Ric} &#92;leq K' title='&#92;hbox{Ric} &#92;leq K' class='latex' /> on the balls <img src='http://s0.wp.com/latex.php?latex=B%28x%2Cr%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B(x,r)' title='B(x,r)' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=B%28y%2Cr%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B(y,r)' title='B(y,r)' class='latex' />. Then for any minimising geodesic <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' /> connecting x and y, we have <img src='http://s0.wp.com/latex.php?latex=%5Cint_%5Cgamma+%5Chbox%7BRic%7D%28X%2CX%29+%5Cleq+O_d%28+K+r+%2B+r%5E%7B-1%7D+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_&#92;gamma &#92;hbox{Ric}(X,X) &#92;leq O_d( K r + r^{-1} )' title='&#92;int_&#92;gamma &#92;hbox{Ric}(X,X) &#92;leq O_d( K r + r^{-1} )' class='latex' />, where <img src='http://s0.wp.com/latex.php?latex=X+%3A%3D+%5Cgamma%27&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='X := &#92;gamma&#039;' title='X := &#92;gamma&#039;' class='latex' /> is the velocity field.</p></blockquote>
<p><strong>Proof. </strong>We may assume that <img src='http://s0.wp.com/latex.php?latex=d%28x%2Cy%29+%5Cgeq+2r&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d(x,y) &#92;geq 2r' title='d(x,y) &#92;geq 2r' class='latex' />, since the claim is trivial otherwise. We recall the second variation formula</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bd%5E2%7D%7Bds%5E2%7D+E%28%5Cgamma%29+%3D+%5Cint_%5Cgamma+%26%23124%3B%5Cnabla_X+Y%26%23124%3B%5E2+-+g%28%5Chbox%7BRiem%7D%28X%2CY%29+X%2C+Y%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{d^2}{ds^2} E(&#92;gamma) = &#92;int_&#92;gamma &#124;&#92;nabla_X Y&#124;^2 - g(&#92;hbox{Riem}(X,Y) X, Y)' title='&#92;frac{d^2}{ds^2} E(&#92;gamma) = &#92;int_&#92;gamma &#124;&#92;nabla_X Y&#124;^2 - g(&#92;hbox{Riem}(X,Y) X, Y)' class='latex' /> (20)</p>
<p>whenever one deforms a geodesic <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' /> along a vector field Y (see equation (17) of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/09/285g-lecture-10-variation-of-l-geodesics-and-monotonicity-of-perelman-reduced-volume/">Lecture 10</a>). Since <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' /> is minimising, the left-hand side of (20) is non-negative when Y vanishes at the endpoints of <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' />. Now let v be any unit vector at x, transported by parallel transport along <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' />. Setting Y(t) to equal tv/r when <img src='http://s0.wp.com/latex.php?latex=0+%5Cleq+t+%5Cleq+r&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &#92;leq t &#92;leq r' title='0 &#92;leq t &#92;leq r' class='latex' />, equal to v when <img src='http://s0.wp.com/latex.php?latex=r+%5Cleq+t+%5Cleq+d%28x%2Cy%29-r&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r &#92;leq t &#92;leq d(x,y)-r' title='r &#92;leq t &#92;leq d(x,y)-r' class='latex' />, and equal to (d(x,y)-t)v/r when <img src='http://s0.wp.com/latex.php?latex=d%28x%2Cy%29-r+%5Cleq+t+%5Cleq+d%28x%2Cy%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d(x,y)-r &#92;leq t &#92;leq d(x,y)' title='d(x,y)-r &#92;leq t &#92;leq d(x,y)' class='latex' />, we conclude that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cint_%5Cgamma+g%28%5Chbox%7BRiem%7D%28X%2CY%29+X%2C+Y%29+%5Cleq+O%28+r%5E%7B-1%7D+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_&#92;gamma g(&#92;hbox{Riem}(X,Y) X, Y) &#92;leq O( r^{-1} )' title='&#92;int_&#92;gamma g(&#92;hbox{Riem}(X,Y) X, Y) &#92;leq O( r^{-1} )' class='latex' />. (21)</p>
<p>Letting v vary over an orthonormal frame and summing, we soon obtain the claim. <img src='http://s0.wp.com/latex.php?latex=%5CBox&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Box' title='&#92;Box' class='latex' /></p>
<p>The above lemma, combined with the Ricci flow equation, gives an upper bound as to how rapidly the distance function can grow as one goes backwards in time.</p>
<blockquote><p><strong>Corollary 1.</strong> Let <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> be a d-dimensional Ricci flow, let <img src='http://s0.wp.com/latex.php?latex=x%2Cy+%5Cin+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x,y &#92;in M' title='x,y &#92;in M' class='latex' />, let t be a time, and let <img src='http://s0.wp.com/latex.php?latex=r+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r &gt; 0' title='r &gt; 0' class='latex' />. Suppose that <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRic%7D+%5Cleq+K&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Ric} &#92;leq K' title='&#92;hbox{Ric} &#92;leq K' class='latex' /> on <img src='http://s0.wp.com/latex.php?latex=B_%7Bg%28t%29%7D%28x%2Cr%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_{g(t)}(x,r)' title='B_{g(t)}(x,r)' class='latex' /> and on <img src='http://s0.wp.com/latex.php?latex=B_%7Bg%28t%29%7D%28y%2Cr%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_{g(t)}(y,r)' title='B_{g(t)}(y,r)' class='latex' />. Then <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bd%7D%7Bd%5Ctau%7D+d_%7Bg%28t%29%7D%28x%2Cy%29+%5Cleq+O_d%28+K+r+%2B+r%5E%7B-1%7D+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{d}{d&#92;tau} d_{g(t)}(x,y) &#92;leq O_d( K r + r^{-1} )' title='&#92;frac{d}{d&#92;tau} d_{g(t)}(x,y) &#92;leq O_d( K r + r^{-1} )' class='latex' /> (in the sense of forward difference quotients).</p></blockquote>
<p>Using this estimate, we can now obtain a bound on distance in terms of reduced length.</p>
<blockquote><p><strong>Proposition 1.</strong> Let <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> be a d-dimensional <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution, let <img src='http://s0.wp.com/latex.php?latex=x_0%2C+p%2C+p%27+%5Cin+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0, p, p&#039; &#92;in M' title='x_0, p, p&#039; &#92;in M' class='latex' />, and <img src='http://s0.wp.com/latex.php?latex=%5Ctau_1+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau_1 &gt; 0' title='&#92;tau_1 &gt; 0' class='latex' />. Then</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd_%7Bg%28-%5Ctau_1%29%7D%28p%2Cp%27%29%5E2%7D%7B%5Ctau_1%7D+%5Cleq+O_d%28+1+%2B+l_%7B%280%2Cx_0%29%7D%28-%5Ctau_1%2Cp%29+%2Bl_%7B%280%2Cx_0%29%7D%28-%5Ctau_1%2Cp%27%29+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d_{g(-&#92;tau_1)}(p,p&#039;)^2}{&#92;tau_1} &#92;leq O_d( 1 + l_{(0,x_0)}(-&#92;tau_1,p) +l_{(0,x_0)}(-&#92;tau_1,p&#039;) )' title='&#92;displaystyle &#92;frac{d_{g(-&#92;tau_1)}(p,p&#039;)^2}{&#92;tau_1} &#92;leq O_d( 1 + l_{(0,x_0)}(-&#92;tau_1,p) +l_{(0,x_0)}(-&#92;tau_1,p&#039;) )' class='latex' />. (22)</p>
</blockquote>
<p><strong>Proof.</strong> We use an argument of Ye. Write A for the expression inside the <img src='http://s0.wp.com/latex.php?latex=O_d%28%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='O_d()' title='O_d()' class='latex' /> on the right-hand side, and let <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%2C+%5Cgamma%27%3A+%5B0%2C%5Ctau_1%5D+%5Cto+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma, &#92;gamma&#039;: [0,&#92;tau_1] &#92;to M' title='&#92;gamma, &#92;gamma&#039;: [0,&#92;tau_1] &#92;to M' class='latex' /> be minimising <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-geodesics from <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' /> to p, p&#8217; respectively. By the fundamental theorem of calculus, we have</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=d_%7Bg%28-%5Ctau_1%29%7D%28p%2Cp%27%29+%3D+%5Cint_0%5E%7B%5Ctau_1%7D+%5Cfrac%7Bd%7D%7Bd%5Ctau%7D+d_%7Bg%28-%5Ctau%29%7D%28+%5Cgamma%28-%5Ctau%29%2C+%5Cgamma%27%28-%5Ctau%29+%29%5C+d%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d_{g(-&#92;tau_1)}(p,p&#039;) = &#92;int_0^{&#92;tau_1} &#92;frac{d}{d&#92;tau} d_{g(-&#92;tau)}( &#92;gamma(-&#92;tau), &#92;gamma&#039;(-&#92;tau) )&#92; d&#92;tau' title='d_{g(-&#92;tau_1)}(p,p&#039;) = &#92;int_0^{&#92;tau_1} &#92;frac{d}{d&#92;tau} d_{g(-&#92;tau)}( &#92;gamma(-&#92;tau), &#92;gamma&#039;(-&#92;tau) )&#92; d&#92;tau' class='latex' />. (24)</p>
<p>Using (3) and the <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-Gauss lemma <img src='http://s0.wp.com/latex.php?latex=%5Cnabla+l+%3D+X&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla l = X' title='&#92;nabla l = X' class='latex' /> we see that <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%2C+%5Cgamma%27&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma, &#92;gamma&#039;' title='&#92;gamma, &#92;gamma&#039;' class='latex' /> move at speed <img src='http://s0.wp.com/latex.php?latex=O%28A%5E%7B1%2F2%7D%2F%5Ctau%5E%7B1%2F2%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='O(A^{1/2}/&#92;tau^{1/2})' title='O(A^{1/2}/&#92;tau^{1/2})' class='latex' />, and that all curvature tensors are <img src='http://s0.wp.com/latex.php?latex=O%28+A+%2F+%5Ctau+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='O( A / &#92;tau )' title='O( A / &#92;tau )' class='latex' /> in a <img src='http://s0.wp.com/latex.php?latex=O%28+%5Ctau%5E%7B1%2F2%7D%2FA%5E%7B1%2F2%7D+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='O( &#92;tau^{1/2}/A^{1/2} )' title='O( &#92;tau^{1/2}/A^{1/2} )' class='latex' />-neighbourhood of either curve. Applying Corollary 1, the chain rule, and the Gauss lemma we conclude that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bd%7D%7Bd%5Ctau%7D+d_%7Bg%28-%5Ctau%29%7D%28+%5Cgamma%28-%5Ctau%29%2C+%5Cgamma%27%28-%5Ctau%29+%29+%5Cleq+O_d%28A%5E%7B1%2F2%7D%2F%5Ctau%5E%7B1%2F2%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{d}{d&#92;tau} d_{g(-&#92;tau)}( &#92;gamma(-&#92;tau), &#92;gamma&#039;(-&#92;tau) ) &#92;leq O_d(A^{1/2}/&#92;tau^{1/2})' title='&#92;frac{d}{d&#92;tau} d_{g(-&#92;tau)}( &#92;gamma(-&#92;tau), &#92;gamma&#039;(-&#92;tau) ) &#92;leq O_d(A^{1/2}/&#92;tau^{1/2})' class='latex' />; (25)</p>
<p>inserting this into (24) we obtain the claim. <img src='http://s0.wp.com/latex.php?latex=%5CBox&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Box' title='&#92;Box' class='latex' /></p>
<p>Combining this with (5) and rescaling we see that we have a bound of the form</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=l_n%28+-%5Ctau%2C+x+%29+%5Cgeq+c+d_%7Bg_n%28-%5Ctau%29%7D%28p_n%2Cx%29%5E2+%2F+%5Ctau+-+O_d%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_n( -&#92;tau, x ) &#92;geq c d_{g_n(-&#92;tau)}(p_n,x)^2 / &#92;tau - O_d(1)' title='l_n( -&#92;tau, x ) &#92;geq c d_{g_n(-&#92;tau)}(p_n,x)^2 / &#92;tau - O_d(1)' class='latex' /> (26)</p>
<p>for all x and some <img src='http://s0.wp.com/latex.php?latex=c+%3D+c_d+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='c = c_d &gt; 0' title='c = c_d &gt; 0' class='latex' />; taking limits we also obtain</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=l_%5Cinfty%28+-%5Ctau%2C+x+%29+%5Cgeq+c+d_%7Bg_%5Cinfty%28-%5Ctau%29%7D%28p_%5Cinfty%2Cx%29%5E2%2F%5Ctau+-+O_d%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_&#92;infty( -&#92;tau, x ) &#92;geq c d_{g_&#92;infty(-&#92;tau)}(p_&#92;infty,x)^2/&#92;tau - O_d(1)' title='l_&#92;infty( -&#92;tau, x ) &#92;geq c d_{g_&#92;infty(-&#92;tau)}(p_&#92;infty,x)^2/&#92;tau - O_d(1)' class='latex' />. (27)</p>
<p>On the other hand, from the Bishop-Gromov inequality we know that balls of radius r in either <img src='http://s0.wp.com/latex.php?latex=%28M_n%2C+g_n%28-%5Ctau%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M_n, g_n(-&#92;tau))' title='(M_n, g_n(-&#92;tau))' class='latex' /> or <img src='http://s0.wp.com/latex.php?latex=%28M_%5Cinfty%2C+g_%5Cinfty%28-%5Ctau%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M_&#92;infty, g_&#92;infty(-&#92;tau))' title='(M_&#92;infty, g_&#92;infty(-&#92;tau))' class='latex' /> have volume <img src='http://s0.wp.com/latex.php?latex=O_d%28r%5Ed%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='O_d(r^d)' title='O_d(r^d)' class='latex' />. These facts are enough to establish that the portion of (7) or (8) outside of the ball of radius r decays exponentially fast in r, uniformly in n, and this allows us to take limits in (19) as <img src='http://s0.wp.com/latex.php?latex=r+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r &#92;to &#92;infty' title='r &#92;to &#92;infty' class='latex' /> to deduce (8) from (7).</p>
<p style="text-align:center;">&#8211; Making the argument rigorous II. Parabolic inequality for <img src='http://s0.wp.com/latex.php?latex=l_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_&#92;infty' title='l_&#92;infty' class='latex' /> &#8211;</p>
<p>The next major task in making the previous arguments rigorous is to justify the passage from (10) to (11). First of all, because of the <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-cut locus, (10) is only valid in the sense of distributions. We would like to take limits and conclude that (11) holds in the sense of distributions as well. There is no difficulty taking limits with the linear terms <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_%5Ctau+l_n+-+%5CDelta+l_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_&#92;tau l_n - &#92;Delta l_n' title='&#92;partial_&#92;tau l_n - &#92;Delta l_n' class='latex' /> in (10), or in the zeroth order terms <img src='http://s0.wp.com/latex.php?latex=-R_n+%2B+%5Cfrac%7Bd%7D%7B%5Ctau%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='-R_n + &#92;frac{d}{&#92;tau}' title='-R_n + &#92;frac{d}{&#92;tau}' class='latex' />; the only problem is in justifying the limit from <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Cnabla+l_n%26%23124%3B_%7Bg_n%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;nabla l_n&#124;_{g_n}^2' title='&#124;&#92;nabla l_n&#124;_{g_n}^2' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Cnabla+l_%5Cinfty%26%23124%3B_%7Bg_n%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;nabla l_&#92;infty&#124;_{g_n}^2' title='&#124;&#92;nabla l_&#92;infty&#124;_{g_n}^2' class='latex' />. We know that the <img src='http://s0.wp.com/latex.php?latex=l_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_n' title='l_n' class='latex' /> are uniformly locally Lipschitz, and converge locally uniformly to <img src='http://s0.wp.com/latex.php?latex=l_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_&#92;infty' title='l_&#92;infty' class='latex' />; but this is unfortunately not enough to ensure that <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Cnabla+l_n%26%23124%3B_%7Bg_n%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;nabla l_n&#124;_{g_n}^2' title='&#124;&#92;nabla l_n&#124;_{g_n}^2' class='latex' /> converges in the sense of distributions to <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Cnabla+l_%5Cinfty%26%23124%3B_%7Bg_n%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;nabla l_&#92;infty&#124;_{g_n}^2' title='&#124;&#92;nabla l_&#92;infty&#124;_{g_n}^2' class='latex' />, due to possible high frequency oscillations in <img src='http://s0.wp.com/latex.php?latex=l_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_n' title='l_n' class='latex' />. To give a toy counterexample, the one-dimensional functions <img src='http://s0.wp.com/latex.php?latex=l_n%28x%29+%3A%3D+%5Cfrac%7B1%7D%7Bn%7D+%5Csin%28nx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_n(x) := &#92;frac{1}{n} &#92;sin(nx)' title='l_n(x) := &#92;frac{1}{n} &#92;sin(nx)' class='latex' /> are uniformly Lipschitz and converge uniformly to zero, but <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Cfrac%7Bd%7D%7Bdx%7D+l_n%26%23124%3B%5E2+%3D+%5Ccos%5E2%28nx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;frac{d}{dx} l_n&#124;^2 = &#92;cos^2(nx)' title='&#124;&#92;frac{d}{dx} l_n&#124;^2 = &#92;cos^2(nx)' class='latex' /> converges in the distributional sense to <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B1%7D%7B2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{1}{2}' title='&#92;frac{1}{2}' class='latex' /> rather than zero.</p>
<p>Since <img src='http://s0.wp.com/latex.php?latex=%5Cnabla+l_n+-+%5Cnabla+l_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla l_n - &#92;nabla l_&#92;infty' title='&#92;nabla l_n - &#92;nabla l_&#92;infty' class='latex' /> is bounded and converges distributionally to zero, it will be locally asymptotically orthogonal <img src='http://s0.wp.com/latex.php?latex=l_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_&#92;infty' title='l_&#92;infty' class='latex' />. From this and Pythagoras&#8217; theorem we obtain</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Clim_%7Bn+%5Cto+%5Cinfty%7D+%26%23124%3B%5Cnabla+l_n%26%23124%3B_%7Bg_n%7D%5E2+%3D+%26%23124%3B%5Cnabla+l_%5Cinfty%26%23124%3B_g%5E2+%2B+%5Clim_%7Bn+%5Cto+%5Cinfty%7D+%26%23124%3B%5Cnabla+l_%5Cinfty+-+%5Cnabla+l_n%26%23124%3B_%7Bg_n%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;lim_{n &#92;to &#92;infty} &#124;&#92;nabla l_n&#124;_{g_n}^2 = &#124;&#92;nabla l_&#92;infty&#124;_g^2 + &#92;lim_{n &#92;to &#92;infty} &#124;&#92;nabla l_&#92;infty - &#92;nabla l_n&#124;_{g_n}^2' title='&#92;lim_{n &#92;to &#92;infty} &#124;&#92;nabla l_n&#124;_{g_n}^2 = &#124;&#92;nabla l_&#92;infty&#124;_g^2 + &#92;lim_{n &#92;to &#92;infty} &#124;&#92;nabla l_&#92;infty - &#92;nabla l_n&#124;_{g_n}^2' class='latex' /> (28)</p>
<p>in the sense of distributions, where we pass to a subsequence in order to make the limits on both sides exist. (Note that <img src='http://s0.wp.com/latex.php?latex=g_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='g_n' title='g_n' class='latex' /> converges locally uniformly to g and so there is no difficulty passing back and forth between those metrics.) The task is now to show that there is not enough oscillation to cause the second term on the right-hand side to be non-vanishing.</p>
<p>To do this, we observe that (10) provides an upper bound on <img src='http://s0.wp.com/latex.php?latex=%5CDelta_%7Bg_n%7D+l_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Delta_{g_n} l_n' title='&#92;Delta_{g_n} l_n' class='latex' />; indeed on any fixed compact set in <img src='http://s0.wp.com/latex.php?latex=%28-%5Cinfty%2C0%29+%5Ctimes+M_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(-&#92;infty,0) &#92;times M_&#92;infty' title='(-&#92;infty,0) &#92;times M_&#92;infty' class='latex' />, we have <img src='http://s0.wp.com/latex.php?latex=%5CDelta_%7Bg_n%7D+l_n+%5Cleq+O%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Delta_{g_n} l_n &#92;leq O(1)' title='&#92;Delta_{g_n} l_n &#92;leq O(1)' class='latex' />. This one-sided bound on the Laplacian is enough to rule out the oscillation problem. Indeed, as <img src='http://s0.wp.com/latex.php?latex=l_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_n' title='l_n' class='latex' /> converges locally uniformly to <img src='http://s0.wp.com/latex.php?latex=l_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_&#92;infty' title='l_&#92;infty' class='latex' />, we see that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Climsup_%7Bn+%5Cto+%5Cinfty%7D+%5Cint_%7BM_%5Cinfty%7D+%5Cphi+%28l_%5Cinfty+-+l_n+%2B+%5Cvarepsilon_n%29+%5CDelta_%7Bg_n%7D+l_n%5C+d%5Cmu_n+%5Cleq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;limsup_{n &#92;to &#92;infty} &#92;int_{M_&#92;infty} &#92;phi (l_&#92;infty - l_n + &#92;varepsilon_n) &#92;Delta_{g_n} l_n&#92; d&#92;mu_n &#92;leq 0' title='&#92;displaystyle &#92;limsup_{n &#92;to &#92;infty} &#92;int_{M_&#92;infty} &#92;phi (l_&#92;infty - l_n + &#92;varepsilon_n) &#92;Delta_{g_n} l_n&#92; d&#92;mu_n &#92;leq 0' class='latex' /> (29)</p>
<p>for any non-negative bump function <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon_n+%5Cto+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon_n &#92;to 0' title='&#92;varepsilon_n &#92;to 0' class='latex' /> chosen so that <img src='http://s0.wp.com/latex.php?latex=l_%5Cinfty+-+l_n+%2B+%5Cvarepsilon_n+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_&#92;infty - l_n + &#92;varepsilon_n &#92;geq 0' title='l_&#92;infty - l_n + &#92;varepsilon_n &#92;geq 0' class='latex' /> on the support of <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' />. Integrating by parts and disposing of a lower order term, we conclude that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Climsup_%7Bn+%5Cto+%5Cinfty%7D+%5Cint_%7BM_%5Cinfty%7D+%5Cphi+%5Clangle+%5Cnabla+%28l_n-l_%5Cinfty%29%2C+%5Cnabla+l_n+%5Crangle_%7Bg_n%7D%5C+d%5Cmu_n+%5Cleq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;limsup_{n &#92;to &#92;infty} &#92;int_{M_&#92;infty} &#92;phi &#92;langle &#92;nabla (l_n-l_&#92;infty), &#92;nabla l_n &#92;rangle_{g_n}&#92; d&#92;mu_n &#92;leq 0' title='&#92;displaystyle &#92;limsup_{n &#92;to &#92;infty} &#92;int_{M_&#92;infty} &#92;phi &#92;langle &#92;nabla (l_n-l_&#92;infty), &#92;nabla l_n &#92;rangle_{g_n}&#92; d&#92;mu_n &#92;leq 0' class='latex' />. (30)</p>
<p>On the other hand, since <img src='http://s0.wp.com/latex.php?latex=%5Cnabla+%28l_n+-+l_%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla (l_n - l_&#92;infty)' title='&#92;nabla (l_n - l_&#92;infty)' class='latex' /> is bounded converges weakly to zero, one has</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Climsup_%7Bn+%5Cto+%5Cinfty%7D+%5Cint_M+%5Cphi+%5Clangle+%5Cnabla+%28l_n-l_%5Cinfty%29%2C+%5Cnabla+l_%5Cinfty+%5Crangle_%7Bg_%5Cinfty%7D%5C+d%5Cmu_%5Cinfty+%5Cto+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;limsup_{n &#92;to &#92;infty} &#92;int_M &#92;phi &#92;langle &#92;nabla (l_n-l_&#92;infty), &#92;nabla l_&#92;infty &#92;rangle_{g_&#92;infty}&#92; d&#92;mu_&#92;infty &#92;to 0' title='&#92;displaystyle &#92;limsup_{n &#92;to &#92;infty} &#92;int_M &#92;phi &#92;langle &#92;nabla (l_n-l_&#92;infty), &#92;nabla l_&#92;infty &#92;rangle_{g_&#92;infty}&#92; d&#92;mu_&#92;infty &#92;to 0' class='latex' />. (31)</p>
<p style="text-align:left;">One can easily replace <img src='http://s0.wp.com/latex.php?latex=g_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='g_&#92;infty' title='g_&#92;infty' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Cmu_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;mu_&#92;infty' title='&#92;mu_&#92;infty' class='latex' /> here by <img src='http://s0.wp.com/latex.php?latex=g_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='g_n' title='g_n' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Cmu_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;mu_n' title='&#92;mu_n' class='latex' />. Combining (30) and (31) we conclude that the second term on the RHS of (28) is non-positive in the sense of distributions. But it is clearly also non-negative, and so it vanishes as required.</p>
<p>This gives (11); as a by-product of the argument we have also established the useful fact</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Clim_%7Bn+%5Cto+%5Cinfty%7D+%26%23124%3B%5Cnabla+l_n%26%23124%3B_%7Bg_n%7D%5E2+%3D+%26%23124%3B%5Cnabla+l_%5Cinfty%26%23124%3B_g%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;lim_{n &#92;to &#92;infty} &#124;&#92;nabla l_n&#124;_{g_n}^2 = &#124;&#92;nabla l_&#92;infty&#124;_g^2' title='&#92;lim_{n &#92;to &#92;infty} &#124;&#92;nabla l_n&#124;_{g_n}^2 = &#124;&#92;nabla l_&#92;infty&#124;_g^2' class='latex' /> (32)</p>
<p>in the sense of distributions. Combining this with the growth bounds (26), (27) on <img src='http://s0.wp.com/latex.php?latex=l_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_n' title='l_n' class='latex' /> and $l_\infty$ from the previous section (which give exponential decay bounds on <img src='http://s0.wp.com/latex.php?latex=e%5E%7B-l_n%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='e^{-l_n}' title='e^{-l_n}' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=e%5E%7B-l_%5Cinfty%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='e^{-l_&#92;infty}' title='e^{-l_&#92;infty}' class='latex' /> and their first derivatives), it is not too difficult to then justify the remaining steps (12)-(18) of the argument rigorously; see Section 9.2 of <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2334563">Morgan-Tian</a> for full details. (Note that once one reaches (13), one has a nonlinear heat equation for <img src='http://s0.wp.com/latex.php?latex=l_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_&#92;infty' title='l_&#92;infty' class='latex' />, and it is not difficult to use the smoothing effects of the heat kernel to then show that the locally Lipschitz function <img src='http://s0.wp.com/latex.php?latex=l_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_&#92;infty' title='l_&#92;infty' class='latex' /> is in fact smooth.)</p>
<p style="text-align:center;">&#8211; The asymptotic gradient shrinking soliton is not flat &#8211;</p>
<p>Finally, we show that the asymptotic gradient shrinking soliton <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M_%5Cinfty%2C+g_%5Cinfty%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M_&#92;infty, g_&#92;infty(t))' title='t &#92;mapsto (M_&#92;infty, g_&#92;infty(t))' class='latex' /> is non-trivial in the sense that its curvature is not identically zero at some time. For if the curvature did vanish everywhere at time t, then the equation (18) simplifies to <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BHess%7D%28l_%5Cinfty%29+%3D+%5Cfrac%7B1%7D%7B2%5Ctau%7D+g_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Hess}(l_&#92;infty) = &#92;frac{1}{2&#92;tau} g_&#92;infty' title='&#92;hbox{Hess}(l_&#92;infty) = &#92;frac{1}{2&#92;tau} g_&#92;infty' class='latex' />. On the other hand, being flat, <img src='http://s0.wp.com/latex.php?latex=%28M_%5Cinfty%2Cg_%5Cinfty%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M_&#92;infty,g_&#92;infty(t))' title='(M_&#92;infty,g_&#92;infty(t))' class='latex' /> is the quotient of Euclidean space <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+R%7D%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb R}^d' title='{&#92;Bbb R}^d' class='latex' /> by some discrete subgroup. Lifting <img src='http://s0.wp.com/latex.php?latex=l_%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_&#92;infty' title='l_&#92;infty' class='latex' /> up to this space, we thus see that f is quadratic, and more precisely is equal to <img src='http://s0.wp.com/latex.php?latex=%26%23124%3Bx%26%23124%3B%5E2%2F4%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;x&#124;^2/4&#92;tau' title='&#124;x&#124;^2/4&#92;tau' class='latex' /> plus an affine-linear function. Thus f has no periodicity whatsoever and so the above-mentioned discrete subgroup is trivial. If we now apply (8) we see that <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+V%28-%5Ctau%29+%3D+%284%5Cpi%29%5E%7Bd%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde V(-&#92;tau) = (4&#92;pi)^{d/2}' title='&#92;tilde V(-&#92;tau) = (4&#92;pi)^{d/2}' class='latex' />. But on the other hand, as the original <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution was not flat, its reduced volume was strictly less than <img src='http://s0.wp.com/latex.php?latex=%284%5Cpi%29%5E%7Bd%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(4&#92;pi)^{d/2}' title='(4&#92;pi)^{d/2}' class='latex' /> by Theorem 1 from <a href="http://terrytao.wordpress.com/2008/05/21/285g-lecture-14-stationary-points-of-perelman-entropy-or-reduced-volume-are-gradient-shrinking-solitons/">Lecture 14</a>, a contradiction. Thus the asymptotic gradient soliton is not flat.</p>
<p style="text-align:center;">&#8211; Appendix: Shi&#8217;s derivative estimates &#8211;</p>
<p>The purpose of this appendix is to prove the following estimate of Shi.</p>
<blockquote><p><strong>Theorem 3. </strong>Suppose that <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> is a complete d-dimensional Ricci flow on the time interval <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5B0%2CT%5D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[0,T]' title='{}[0,T]' class='latex' />, and that on the cylinder <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5B0%2CT%5D+%5Ctimes+B_%7Bg%280%29%7D%28x_0%2Cr_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[0,T] &#92;times B_{g(0)}(x_0,r_0)' title='{}[0,T] &#92;times B_{g(0)}(x_0,r_0)' class='latex' /> one has the pointwise curvature bound <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Chbox%7BRiem%7D%26%23124%3B_g+%5Cleq+K&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;hbox{Riem}&#124;_g &#92;leq K' title='&#124;&#92;hbox{Riem}&#124;_g &#92;leq K' class='latex' />. Then on any slightly smaller cylinder <img src='http://s0.wp.com/latex.php?latex=%7B%7D%280%2CT%5D+%5Ctimes+B_%7Bg%280%29%7D%28x_0%2C%281-%5Cvarepsilon%29r_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}(0,T] &#92;times B_{g(0)}(x_0,(1-&#92;varepsilon)r_0)' title='{}(0,T] &#92;times B_{g(0)}(x_0,(1-&#92;varepsilon)r_0)' class='latex' /> one has the curvature bounds <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Cnabla%5Ek+%5Chbox%7BRiem%7D%26%23124%3B_g+%3D+O%28+t%5E%7B-k%2F2%7D+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;nabla^k &#92;hbox{Riem}&#124;_g = O( t^{-k/2} )' title='&#124;&#92;nabla^k &#92;hbox{Riem}&#124;_g = O( t^{-k/2} )' class='latex' /> for any <img src='http://s0.wp.com/latex.php?latex=k+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='k &#92;geq 0' title='k &#92;geq 0' class='latex' />, where the implied constant depend on <img src='http://s0.wp.com/latex.php?latex=d%2C+T%2C+r_0%2C+K%2C+%5Cvarepsilon%2C+k&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d, T, r_0, K, &#92;varepsilon, k' title='d, T, r_0, K, &#92;varepsilon, k' class='latex' />.</p></blockquote>
<p><strong>Proof.</strong> (Sketch) We induct on k. The case <img src='http://s0.wp.com/latex.php?latex=k+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='k = 0' title='k = 0' class='latex' /> is trivial, so suppose that <img src='http://s0.wp.com/latex.php?latex=k+%5Cgeq+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='k &#92;geq 1' title='k &#92;geq 1' class='latex' /> and that the claim has already been proven for all smaller values of k. We allow all implied constants in the O() notation to depend on <img src='http://s0.wp.com/latex.php?latex=d%2C+T%2C+r_0%2C+K%2C+%5Cvarepsilon%2C+k&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d, T, r_0, K, &#92;varepsilon, k' title='d, T, r_0, K, &#92;varepsilon, k' class='latex' />. We refer to <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5B0%2CT%5D+%5Ctimes+B_%7Bg%280%29%7D%28x_0%2Cr_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[0,T] &#92;times B_{g(0)}(x_0,r_0)' title='{}[0,T] &#92;times B_{g(0)}(x_0,r_0)' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%7B%7D%280%2CT%5D+%5Ctimes+B_%7Bg%280%29%7D%28x_0%2C%281-%5Cvarepsilon%29r_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}(0,T] &#92;times B_{g(0)}(x_0,(1-&#92;varepsilon)r_0)' title='{}(0,T] &#92;times B_{g(0)}(x_0,(1-&#92;varepsilon)r_0)' class='latex' /> as the &#8220;large cylinder&#8221; and &#8220;small cylinder&#8221; respectively.</p>
<p>We make some reductions. It is easy to see that we can take <img src='http://s0.wp.com/latex.php?latex=r_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_0' title='r_0' class='latex' /> and T to be small.</p>
<p>Since <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Cdot+g%26%23124%3B_g+%3D+2+%26%23124%3B%5Chbox%7BRic%7D%26%23124%3B+%3D+O%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;dot g&#124;_g = 2 &#124;&#92;hbox{Ric}&#124; = O(1)' title='&#124;&#92;dot g&#124;_g = 2 &#124;&#92;hbox{Ric}&#124; = O(1)' class='latex' /> on the cylinder, we see that the metric at later times of the large cylinder is comparable to the initial metric up to multiplicative constants. The curvature bound tells us that if <img src='http://s0.wp.com/latex.php?latex=r_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_0' title='r_0' class='latex' /> is small, then we are inside the conjugacy radius; pulling back under the exponential map, we may thus assume that the exponential map from <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' /> is injective on the large cylinder. Let <img src='http://s0.wp.com/latex.php?latex=r+%3D+d_%7Bg%28t%29%7D%28x_0%2Cx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r = d_{g(t)}(x_0,x)' title='r = d_{g(t)}(x_0,x)' class='latex' /> be the <em>time-varying</em> radial coordinate; observe that the annulus <img src='http://s0.wp.com/latex.php?latex=%5C%7B+%281-2%5Cvarepsilon%2F3%29r_0+%5Cleq+r+%5Cleq+%281-%5Cvarepsilon%2F3%29r_0+%5C%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;{ (1-2&#92;varepsilon/3)r_0 &#92;leq r &#92;leq (1-&#92;varepsilon/3)r_0 &#92;}' title='&#92;{ (1-2&#92;varepsilon/3)r_0 &#92;leq r &#92;leq (1-&#92;varepsilon/3)r_0 &#92;}' class='latex' /> will be contained between the large cylinder and small cylinder for T small enough.</p>
<p><strong>Exercise 5. </strong>Show that if <img src='http://s0.wp.com/latex.php?latex=r_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_0' title='r_0' class='latex' /> and T are small enough, then <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Chbox%7BHess%7D%28r%29%26%23124%3B_g+%3D+O%281%2Fr%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;hbox{Hess}(r)&#124;_g = O(1/r)' title='&#124;&#92;hbox{Hess}(r)&#124;_g = O(1/r)' class='latex' /> on the large cylinder. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>Let <img src='http://s0.wp.com/latex.php?latex=%5Ceta+%3D+%5Ceta%28r%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;eta = &#92;eta(r)' title='&#92;eta = &#92;eta(r)' class='latex' /> be a smooth non-negative radial cutoff to the large cylinder that equals 1 on the small cylinder. From the above exercise, the Gauss lemma, and the chain rule, we see that <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Cnabla+%5Ceta%26%23124%3B_g%2C+%26%23124%3B%5Cpartial_t+%5Ceta%26%23124%3B%2C+%26%23124%3B%5Chbox%7BHess%7D+%5Ceta%26%23124%3B_g%2C+%5CDelta+%5Ceta+%3D+O%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;nabla &#92;eta&#124;_g, &#124;&#92;partial_t &#92;eta&#124;, &#124;&#92;hbox{Hess} &#92;eta&#124;_g, &#92;Delta &#92;eta = O(1)' title='&#124;&#92;nabla &#92;eta&#124;_g, &#124;&#92;partial_t &#92;eta&#124;, &#124;&#92;hbox{Hess} &#92;eta&#124;_g, &#92;Delta &#92;eta = O(1)' class='latex' />.</p>
<p>Now we study the heat equation obeyed by the &#8220;energy densities&#8221; <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Cnabla%5Em+%5Chbox%7BRiem%7D%26%23124%3B_g%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;nabla^m &#92;hbox{Riem}&#124;_g^2' title='&#124;&#92;nabla^m &#92;hbox{Riem}&#124;_g^2' class='latex' /> for various m.</p>
<p><strong>Exercise 6. </strong>(<a href="http://en.wikipedia.org/wiki/Weitzenb%C3%B6ck_identity">Bochner-Weitzenböck</a> type estimate) For any <img src='http://s0.wp.com/latex.php?latex=m+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='m &#92;geq 0' title='m &#92;geq 0' class='latex' />, show that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%28%5Cpartial_t+-+%5CDelta%29+%26%23124%3B%5Cnabla%5Em+%5Chbox%7BRiem%7D%26%23124%3B_g%5E2+%5Cleq+O%28%5Csum_%7Bj%3D0%7D%5Em+%26%23124%3B%5Cnabla%5Ej+%5Chbox%7BRiem%7D%26%23124%3B_g+%26%23124%3B%5Cnabla%5E%7Bm-j%7D+%5Chbox%7BRiem%7D%26%23124%3B_g+%26%23124%3B%5Cnabla%5Em+%5Chbox%7BRiem%7D%26%23124%3B_g%29+&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;partial_t - &#92;Delta) &#124;&#92;nabla^m &#92;hbox{Riem}&#124;_g^2 &#92;leq O(&#92;sum_{j=0}^m &#124;&#92;nabla^j &#92;hbox{Riem}&#124;_g &#124;&#92;nabla^{m-j} &#92;hbox{Riem}&#124;_g &#124;&#92;nabla^m &#92;hbox{Riem}&#124;_g) ' title='(&#92;partial_t - &#92;Delta) &#124;&#92;nabla^m &#92;hbox{Riem}&#124;_g^2 &#92;leq O(&#92;sum_{j=0}^m &#124;&#92;nabla^j &#92;hbox{Riem}&#124;_g &#124;&#92;nabla^{m-j} &#92;hbox{Riem}&#124;_g &#124;&#92;nabla^m &#92;hbox{Riem}&#124;_g) ' class='latex' /></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=-+2+%26%23124%3B%5Cnabla%5E%7Bm%2B1%7D+%5Chbox%7BRiem%7D%26%23124%3B_g%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='- 2 &#124;&#92;nabla^{m+1} &#92;hbox{Riem}&#124;_g^2' title='- 2 &#124;&#92;nabla^{m+1} &#92;hbox{Riem}&#124;_g^2' class='latex' />. (33)</p>
<p>(Hint: start with the equation <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+%5Chbox%7BRiem%7D+%3D+%5CDelta+%5Chbox%7BRiem%7D+%2B+%7B%5Cmathcal+O%7D%28+g%5E%7B-1%7D+%5Chbox%7BRiem%7D%5E2+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t &#92;hbox{Riem} = &#92;Delta &#92;hbox{Riem} + {&#92;mathcal O}( g^{-1} &#92;hbox{Riem}^2 )' title='&#92;partial_t &#92;hbox{Riem} = &#92;Delta &#92;hbox{Riem} + {&#92;mathcal O}( g^{-1} &#92;hbox{Riem}^2 )' class='latex' /> and use the product rule and the definition of curvature repeatedly.) <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>From this exercise and the induction hypothesis we see that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%28%5Cpartial_t+-+%5CDelta%29+%5B%5Ceta%5E%7B2m%2B2%7D+t%5Em+%26%23124%3B%5Cnabla%5Em+%5Chbox%7BRiem%7D%26%23124%3B_g%5E2%5D+%5Cleq+O%281%29+%2B+O%28%5Ceta%5E%7B2m%7D+t%5E%7Bm-1%7D+%26%23124%3B%5Cnabla%5Em+%5Chbox%7BRiem%7D%26%23124%3B_g%5E2%29+&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;partial_t - &#92;Delta) [&#92;eta^{2m+2} t^m &#124;&#92;nabla^m &#92;hbox{Riem}&#124;_g^2] &#92;leq O(1) + O(&#92;eta^{2m} t^{m-1} &#124;&#92;nabla^m &#92;hbox{Riem}&#124;_g^2) ' title='(&#92;partial_t - &#92;Delta) [&#92;eta^{2m+2} t^m &#124;&#92;nabla^m &#92;hbox{Riem}&#124;_g^2] &#92;leq O(1) + O(&#92;eta^{2m} t^{m-1} &#124;&#92;nabla^m &#92;hbox{Riem}&#124;_g^2) ' class='latex' /></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=-+2+%5Ceta%5E%7B2m%2B2%7D+t%5Em+%26%23124%3B%5Cnabla%5E%7Bm%2B1%7D+%5Chbox%7BRiem%7D%26%23124%3B_g%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='- 2 &#92;eta^{2m+2} t^m &#124;&#92;nabla^{m+1} &#92;hbox{Riem}&#124;_g^2' title='- 2 &#92;eta^{2m+2} t^m &#124;&#92;nabla^{m+1} &#92;hbox{Riem}&#124;_g^2' class='latex' /> (34)</p>
<p>for all <img src='http://s0.wp.com/latex.php?latex=0+%5Cleq+m+%5Cleq+k&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &#92;leq m &#92;leq k' title='0 &#92;leq m &#92;leq k' class='latex' />, with the understanding that the second term on the right-hand side is absent when m=0. Telescoping this, we can thus find an expression</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=E+%3A%3D+%5Csum_%7Bm%3D0%7D%5Ek+C%5E%7B-m%7D+%5Ceta%5E%7B2m%2B2%7D+t%5Em+%26%23124%3B%5Cnabla%5Em+%5Chbox%7BRiem%7D%26%23124%3B_g%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='E := &#92;sum_{m=0}^k C^{-m} &#92;eta^{2m+2} t^m &#124;&#92;nabla^m &#92;hbox{Riem}&#124;_g^2' title='E := &#92;sum_{m=0}^k C^{-m} &#92;eta^{2m+2} t^m &#124;&#92;nabla^m &#92;hbox{Riem}&#124;_g^2' class='latex' /> (35)</p>
<p>for some sufficiently large positive constant <img src='http://s0.wp.com/latex.php?latex=C&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C' title='C' class='latex' />, which obeys the heat equation <img src='http://s0.wp.com/latex.php?latex=%28%5Cpartial_t+-+%5CDelta%29+E+%5Cleq+O%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;partial_t - &#92;Delta) E &#92;leq O(1)' title='(&#92;partial_t - &#92;Delta) E &#92;leq O(1)' class='latex' />. Also, by hypothesis we have E=O(1) at time zero. Applying the maximum principle, we obtain the claim. <img src='http://s0.wp.com/latex.php?latex=%5CBox&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Box' title='&#92;Box' class='latex' /></p>
<p><strong>Exercise 6.</strong> Suppose that in the hypotheses of Shi&#8217;s theorem that we also have <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Cnabla%5Ej+%5Chbox%7BRiem%7D%26%23124%3B%3DO%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;nabla^j &#92;hbox{Riem}&#124;=O(1)' title='&#124;&#92;nabla^j &#92;hbox{Riem}&#124;=O(1)' class='latex' /> for <img src='http://s0.wp.com/latex.php?latex=0+%5Cleq+j+%5Cleq+m&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &#92;leq j &#92;leq m' title='0 &#92;leq j &#92;leq m' class='latex' /> on the large cylinder at time zero. Conclude that we have <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Cnabla%5Ej+%5Chbox%7BRiem%7D%26%23124%3B%3DO%28+1+%2B+t%5E%7B-%28j-m%29%2F2%7D+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;nabla^j &#92;hbox{Riem}&#124;=O( 1 + t^{-(j-m)/2} )' title='&#124;&#92;nabla^j &#92;hbox{Riem}&#124;=O( 1 + t^{-(j-m)/2} )' class='latex' /> on the small cylinder for all j. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p><strong>Exercise 7.</strong> Let <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g)' title='(M,g)' class='latex' /> be a smooth compact manifold, and let <img src='http://s0.wp.com/latex.php?latex=u%3A+%5B0%2CT%5D+%5Ctimes+M+%5Cto+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u: [0,T] &#92;times M &#92;to {&#92;Bbb R}' title='u: [0,T] &#92;times M &#92;to {&#92;Bbb R}' class='latex' /> be a bounded solution to the heat equation <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+u+%3D+%5CDelta+u&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t u = &#92;Delta u' title='&#92;partial_t u = &#92;Delta u' class='latex' /> which obeys a pointwise bound <img src='http://s0.wp.com/latex.php?latex=%26%23124%3Bu%280%29%26%23124%3B+%5Cleq+K&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;u(0)&#124; &#92;leq K' title='&#124;u(0)&#124; &#92;leq K' class='latex' /> at time zero. Establish the bounds <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Cnabla%5Ek+u%26%23124%3B_g+%3D+O%28+t%5E%7B-k%2F2%7D+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;nabla^k u&#124;_g = O( t^{-k/2} )' title='&#124;&#92;nabla^k u&#124;_g = O( t^{-k/2} )' class='latex' /> on the spacetime <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5B0%2CT%5D+%5Ctimes+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[0,T] &#92;times M' title='{}[0,T] &#92;times M' class='latex' /> and all <img src='http://s0.wp.com/latex.php?latex=k+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='k &#92;geq 0' title='k &#92;geq 0' class='latex' />, where the implied constant depends on (M,g), K, T, and k. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>(<em>Update</em>, June 2: some corrections.)</p>
<p>(<em>Update</em>, Oct 18 2011: A recently discovered issue with the Hamilton compactness theorem in the case where the curvature bound is not uniform in r has been addressed.)</p>
]]></content:encoded>
</item>
<item>
<title><![CDATA[285G, Lecture 14: Stationary points of Perelman entropy or reduced volume are gradient shrinking solitons]]></title>
<link>http://terrytao.wordpress.com/2008/05/21/285g-lecture-14-stationary-points-of-perelman-entropy-or-reduced-volume-are-gradient-shrinking-solitons/</link>
<pubDate>Wed, 21 May 2008 21:01:46 +0000</pubDate>
<dc:creator>Terence Tao</dc:creator>
<guid>http://terrytao.wordpress.com/2008/05/21/285g-lecture-14-stationary-points-of-perelman-entropy-or-reduced-volume-are-gradient-shrinking-solitons/</guid>
<description><![CDATA[We continue our study of -solutions. In the previous lecture we primarily exploited the non-negative]]></description>
<content:encoded><![CDATA[<p>We continue our study of <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions.  In the <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/19/285g-lecture-13-li-yau-hamilton-harnack-inequalities-and-%ce%ba-solutions/">previous lecture</a> we primarily exploited the non-negative curvature of such solutions; in this lecture and the next, we primarily exploit the ancient nature of these solutions, together with the finer analysis of the two scale-invariant monotone quantities we possess (Perelman entropy and Perelman reduced volume) to obtain a important scaling limit of <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions, the <em>asymptotic gradient shrinking soliton</em> of such a solution.</p>
<p>The main idea here is to exploit what I have called the <em>infinite convergence principle</em> in a  <a class="snap_noshots" href="http://terrytao.wordpress.com/2007/05/23/soft-analysis-hard-analysis-and-the-finite-convergence-principle/">previous post</a>: that every bounded monotone sequence converges.  In the context of <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions, we can apply this principle to either of our monotone quantities: the <em>Perelman entropy</em></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cmu%28g%28t%29%2C%5Ctau%29+%3A%3D+%5Cinf+%5C%7B+%7B%5Cmathcal+W%7D%28M%2Cg%28t%29%2Cf%2C%5Ctau%29%3A+%5Cint_M+%284%5Cpi%5Ctau%29%5E%7B-d%2F2%7D+e%5E%7B-f%7D%5C+d%5Cmu+%3D+1+%5C%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;mu(g(t),&#92;tau) := &#92;inf &#92;{ {&#92;mathcal W}(M,g(t),f,&#92;tau): &#92;int_M (4&#92;pi&#92;tau)^{-d/2} e^{-f}&#92; d&#92;mu = 1 &#92;}' title='&#92;displaystyle &#92;mu(g(t),&#92;tau) := &#92;inf &#92;{ {&#92;mathcal W}(M,g(t),f,&#92;tau): &#92;int_M (4&#92;pi&#92;tau)^{-d/2} e^{-f}&#92; d&#92;mu = 1 &#92;}' class='latex' /> (1)</p>
<p style="text-align:left;">where <img src='http://s0.wp.com/latex.php?latex=%5Ctau+%3A%3D+-t&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau := -t' title='&#92;tau := -t' class='latex' /> is the backwards time variable and</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%7B%5Cmathcal+W%7D%28M%2Cg%28t%29%2Cf%2C%5Ctau%29+%3A%3D+%5Cint_M+%28%5Ctau%28%26%23124%3B%5Cnabla+f%26%23124%3B%5E2+%2B+R%29+%2B+f+-+d%29+%284%5Cpi%5Ctau%29%5E%7B-d%2F2%7D+e%5E%7B-f%7D%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle {&#92;mathcal W}(M,g(t),f,&#92;tau) := &#92;int_M (&#92;tau(&#124;&#92;nabla f&#124;^2 + R) + f - d) (4&#92;pi&#92;tau)^{-d/2} e^{-f}&#92; d&#92;mu' title='&#92;displaystyle {&#92;mathcal W}(M,g(t),f,&#92;tau) := &#92;int_M (&#92;tau(&#124;&#92;nabla f&#124;^2 + R) + f - d) (4&#92;pi&#92;tau)^{-d/2} e^{-f}&#92; d&#92;mu' class='latex' />,   (2)</p>
<p style="text-align:left;">or the<em> Perelman reduced volume</em></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Ctilde+V_%7B%280%2Cx_0%29%7D%28-%5Ctau%29+%3A%3D+%5Ctau%5E%7B-d%2F2%7D+%5Cint_M+e%5E%7B-l_%7B%280%2Cx_0%29%7D%28-%5Ctau%2Cx%29%7D%5C+d%5Cmu%28x%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;tilde V_{(0,x_0)}(-&#92;tau) := &#92;tau^{-d/2} &#92;int_M e^{-l_{(0,x_0)}(-&#92;tau,x)}&#92; d&#92;mu(x)' title='&#92;displaystyle &#92;tilde V_{(0,x_0)}(-&#92;tau) := &#92;tau^{-d/2} &#92;int_M e^{-l_{(0,x_0)}(-&#92;tau,x)}&#92; d&#92;mu(x)' class='latex' /> (3)</p>
<p style="text-align:left;">where <img src='http://s0.wp.com/latex.php?latex=x_0+%5Cin+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0 &#92;in M' title='x_0 &#92;in M' class='latex' /> is a fixed base point.  As pointed out in Lecture 11, these quantities are related, and both are non-increasing in <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' />.</p>
<p style="text-align:left;">The reduced volume starts off at <img src='http://s0.wp.com/latex.php?latex=%284%5Cpi%29%5E%7Bd%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(4&#92;pi)^{d/2}' title='(4&#92;pi)^{d/2}' class='latex' /> when <img src='http://s0.wp.com/latex.php?latex=%5Ctau%3D0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau=0' title='&#92;tau=0' class='latex' />, and so by the infinite convergence principle it approaches some asymptotic limit <img src='http://s0.wp.com/latex.php?latex=0+%5Cleq+%5Ctilde+V_%7B%280%2Cx_0%29%7D%28-%5Cinfty%29+%5Cleq+%284%5Cpi%29%5E%7Bd%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &#92;leq &#92;tilde V_{(0,x_0)}(-&#92;infty) &#92;leq (4&#92;pi)^{d/2}' title='0 &#92;leq &#92;tilde V_{(0,x_0)}(-&#92;infty) &#92;leq (4&#92;pi)^{d/2}' class='latex' /> as <img src='http://s0.wp.com/latex.php?latex=%5Ctau+%5Cto+-%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau &#92;to -&#92;infty' title='&#92;tau &#92;to -&#92;infty' class='latex' />.  (We will later see that this limit is strictly between 0 and <img src='http://s0.wp.com/latex.php?latex=%284%5Cpi%29%5E%7Bd%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(4&#92;pi)^{d/2}' title='(4&#92;pi)^{d/2}' class='latex' />.)  On the other hand, the reduced volume is invariant under the scaling</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=g%5E%7B%28%5Clambda%29%7D%28t%29+%3A%3D+%5Cfrac%7B1%7D%7B%5Clambda%5E2%7D+g%28+%5Clambda%5E2+t+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='g^{(&#92;lambda)}(t) := &#92;frac{1}{&#92;lambda^2} g( &#92;lambda^2 t )' title='g^{(&#92;lambda)}(t) := &#92;frac{1}{&#92;lambda^2} g( &#92;lambda^2 t )' class='latex' />, (4)</p>
<p style="text-align:left;">in the sense that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Ctilde+V_%7B%280%2Cx_0%29%7D%5E%7B%28%5Clambda%29%7D%28-%5Ctau%29+%3D+%5Ctilde+V_%7B%280%2Cx_0%29%7D%28-%5Clambda%5E2+%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde V_{(0,x_0)}^{(&#92;lambda)}(-&#92;tau) = &#92;tilde V_{(0,x_0)}(-&#92;lambda^2 &#92;tau)' title='&#92;tilde V_{(0,x_0)}^{(&#92;lambda)}(-&#92;tau) = &#92;tilde V_{(0,x_0)}(-&#92;lambda^2 &#92;tau)' class='latex' />. (5)</p>
<p style="text-align:left;">Thus, as we send <img src='http://s0.wp.com/latex.php?latex=%5Clambda+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;lambda &#92;to &#92;infty' title='&#92;lambda &#92;to &#92;infty' class='latex' />, the reduced volumes of the rescaled flows <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2C+g%5E%7B%28%5Clambda%29%7D%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M, g^{(&#92;lambda)}(t))' title='t &#92;mapsto (M, g^{(&#92;lambda)}(t))' class='latex' /> (which are also <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions) converge pointwise to a constant <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+V_%7B%280%2Cx_0%29%7D%28-%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde V_{(0,x_0)}(-&#92;infty)' title='&#92;tilde V_{(0,x_0)}(-&#92;infty)' class='latex' />.</p>
<p style="text-align:left;">Suppose that we could somehow &#8220;take a limit&#8221; of the flows <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2C+g%5E%7B%28%5Clambda%29%7D%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M, g^{(&#92;lambda)}(t))' title='t &#92;mapsto (M, g^{(&#92;lambda)}(t))' class='latex' /> (or perhaps a subsequence of such flows) and obtain some limiting flow <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%5E%7B%28%5Cinfty%29%7D%2C+g%5E%7B%28%5Cinfty%29%7D%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M^{(&#92;infty)}, g^{(&#92;infty)}(t))' title='t &#92;mapsto (M^{(&#92;infty)}, g^{(&#92;infty)}(t))' class='latex' />.  <em>Formally</em>, such a flow would then have a constant reduced volume of <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+V_%7B%280%2Cx_0%29%7D%28-%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde V_{(0,x_0)}(-&#92;infty)' title='&#92;tilde V_{(0,x_0)}(-&#92;infty)' class='latex' />. On the other hand, the reduced volume is monotone.  If we could have a criterion as to when the reduced volume became stationary, we could thus classify all possible limiting flows <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%5E%7B%28%5Cinfty%29%7D%2C+g%5E%7B%28%5Cinfty%29%7D%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M^{(&#92;infty)}, g^{(&#92;infty)}(t))' title='t &#92;mapsto (M^{(&#92;infty)}, g^{(&#92;infty)}(t))' class='latex' />, and thus obtain information about the asymptotic behaviour of <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions (at least along a subsequence of scales going to infinity).</p>
<p style="text-align:left;">We will carry out this program more formally in the next lecture, in which we define the concept of an <em>asymptotic gradient-shrinking soliton</em> of a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution.<br />
In this lecture, we content ourselves with a key step in this program, namely to characterise when the Perelman entropy or Perelman reduced volume becomes stationary; this requires us to revisit the theory we have built up in the last few lectures.  It turns out that, roughly speaking, this only happens when the solution is a gradient shrinking soliton, thus at any given time <img src='http://s0.wp.com/latex.php?latex=-%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='-&#92;tau' title='-&#92;tau' class='latex' /> one has an equation of the form <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRic%7D+%2B+%5Chbox%7BHess%7D%28f%29+%3D+%5Clambda+g&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Ric} + &#92;hbox{Hess}(f) = &#92;lambda g' title='&#92;hbox{Ric} + &#92;hbox{Hess}(f) = &#92;lambda g' class='latex' /> for some <img src='http://s0.wp.com/latex.php?latex=f%3A+M+%5Cto+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='f: M &#92;to {&#92;Bbb R}' title='f: M &#92;to {&#92;Bbb R}' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Clambda+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;lambda &gt; 0' title='&#92;lambda &gt; 0' class='latex' />.  Our computations here will be somewhat formal in nature; we will make them more rigorous in the next lecture.</p>
<p style="text-align:left;">The material here is largely based on <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2334563">Morgan-Tian&#8217;s book</a> and the <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0211159">first paper of Perelman</a>.  Closely related treatments also appear in the <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0605667">notes of Kleiner-Lott</a> and the <a class="snap_noshots" href="http://arxiv.org/abs/math/0612069">paper of Cao-Zhu</a>.</p>
<p style="text-align:left;"><!--more--></p>
<p style="text-align:center;">&#8211; Stationarity of the Perelman entropy &#8211;</p>
<p style="text-align:left;">We begin with a discussion of the Perelman entropy, which is simpler than the Perelman reduced volume but which will serve as a model for the latter.  To simplify the exposition we shall argue at a formal level, assuming all integrals converge, that all functions are smooth, all infima are actually attained, etc.</p>
<p style="text-align:left;">In Exercise 9, we already saw that if <img src='http://s0.wp.com/latex.php?latex=f%3A+%28-%5Cinfty%2C0%5D+%5Ctimes+M+%5Cto+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='f: (-&#92;infty,0] &#92;times M &#92;to {&#92;Bbb R}' title='f: (-&#92;infty,0] &#92;times M &#92;to {&#92;Bbb R}' class='latex' /> solves the nonlinear backwards heat equation</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle++f_%5Ctau+%3D+%5CDelta+f+-+%26%23124%3B%5Cnabla+f%26%23124%3B_g%5E2+%2B+R+-+%5Cfrac%7Bd%7D%7B2%5Ctau%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle  f_&#92;tau = &#92;Delta f - &#124;&#92;nabla f&#124;_g^2 + R - &#92;frac{d}{2&#92;tau}' title='&#92;displaystyle  f_&#92;tau = &#92;Delta f - &#124;&#92;nabla f&#124;_g^2 + R - &#92;frac{d}{2&#92;tau}' class='latex' /> (6)</p>
<p style="text-align:left;">then the quantity <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+W%7D%28M%2Cg%28t%29%2Cf%2C%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal W}(M,g(t),f,&#92;tau)' title='{&#92;mathcal W}(M,g(t),f,&#92;tau)' class='latex' /> obeyed the monotonicity formula</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bd%5Ctau%7D+%7B%5Cmathcal+W%7D%28M%2Cg%28t%29%2Cf%2C%5Ctau%29+%3D+-%5Cint_M+H%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{d&#92;tau} {&#92;mathcal W}(M,g(t),f,&#92;tau) = -&#92;int_M H&#92; d&#92;mu' title='&#92;displaystyle &#92;frac{d}{d&#92;tau} {&#92;mathcal W}(M,g(t),f,&#92;tau) = -&#92;int_M H&#92; d&#92;mu' class='latex' /> (7)</p>
<p style="text-align:left;">where H is the non-negative quantity</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+H+%3A%3D+2%5Ctau+%26%23124%3B%5Chbox%7BRic%7D+%2B+%5Chbox%7BHess%7D%28f%29-+%5Cfrac%7B1%7D%7B2%5Ctau%7D+g%26%23124%3B%5E2+%284%5Cpi+%5Ctau%29%5E%7B-d%2F2%7D+e%5E%7B-f%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle H := 2&#92;tau &#124;&#92;hbox{Ric} + &#92;hbox{Hess}(f)- &#92;frac{1}{2&#92;tau} g&#124;^2 (4&#92;pi &#92;tau)^{-d/2} e^{-f}' title='&#92;displaystyle H := 2&#92;tau &#124;&#92;hbox{Ric} + &#92;hbox{Hess}(f)- &#92;frac{1}{2&#92;tau} g&#124;^2 (4&#92;pi &#92;tau)^{-d/2} e^{-f}' class='latex' />. (8)</p>
<p style="text-align:left;">In terms of the function <img src='http://s0.wp.com/latex.php?latex=u+%3A%3D+%284%5Cpi+%5Ctau%29%5E%7B-d%2F2%7D+e%5E%7B-f%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u := (4&#92;pi &#92;tau)^{-d/2} e^{-f}' title='u := (4&#92;pi &#92;tau)^{-d/2} e^{-f}' class='latex' />, we also recall that (6) can be rewritten as the adjoint heat equation <img src='http://s0.wp.com/latex.php?latex=u_%5Ctau+%3D+%5CDelta+u+%2B+Ru&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u_&#92;tau = &#92;Delta u + Ru' title='u_&#92;tau = &#92;Delta u + Ru' class='latex' />. In particular, we see that if <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+W%7D%28M%2Cg%28t%29%2Cf%2C%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal W}(M,g(t),f,&#92;tau)' title='{&#92;mathcal W}(M,g(t),f,&#92;tau)' class='latex' /> is ever stationary at some time <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' />, then the solution must obey the gradient shrinking soliton equation</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRic%7D+%2B+%5Chbox%7BHess%7D%28f%29+%3D+%5Cfrac%7B1%7D%7B2%5Ctau%7D+g&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Ric} + &#92;hbox{Hess}(f) = &#92;frac{1}{2&#92;tau} g' title='&#92;hbox{Ric} + &#92;hbox{Hess}(f) = &#92;frac{1}{2&#92;tau} g' class='latex' /> (9)</p>
<p style="text-align:left;">at that time <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' />.  Using the uniqueness properties of Ricci flow (and of the backwards heat equation), one can then show that (9) persists for all subsequent times.  Formally at least, this argument also shows that the Perelman reduced entropy <img src='http://s0.wp.com/latex.php?latex=%5Cmu%28M%2Cg%2C%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;mu(M,g,&#92;tau)' title='&#92;mu(M,g,&#92;tau)' class='latex' /> can only be stationary on gradient shrinking solitons.</p>
<p style="text-align:left;">Let us analyse the monotonicity formula (7) further.  If we write</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=v+%3A%3D+%28%5Ctau%28%26%23124%3B%5Cnabla+f%26%23124%3B%5E2+%2B+R%29+%2B+f+-+d%29+%284%5Cpi%5Ctau%29%5E%7B-d%2F2%7D+e%5E%7B-f%7D+%3D+%28%5Ctau%28%26%23124%3B%5Cnabla+f%26%23124%3B%5E2+%2B+R%29+%2B+f+-+d%29+u&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='v := (&#92;tau(&#124;&#92;nabla f&#124;^2 + R) + f - d) (4&#92;pi&#92;tau)^{-d/2} e^{-f} = (&#92;tau(&#124;&#92;nabla f&#124;^2 + R) + f - d) u' title='v := (&#92;tau(&#124;&#92;nabla f&#124;^2 + R) + f - d) (4&#92;pi&#92;tau)^{-d/2} e^{-f} = (&#92;tau(&#124;&#92;nabla f&#124;^2 + R) + f - d) u' class='latex' /> (10)</p>
<p style="text-align:left;">then (7) asserts that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bd%5Ctau%7D+%5Cint_M+v%5C+d%5Cmu+%3D+-%5Cint_M+H%5C+d%5Cmu.&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{d&#92;tau} &#92;int_M v&#92; d&#92;mu = -&#92;int_M H&#92; d&#92;mu.' title='&#92;displaystyle &#92;frac{d}{d&#92;tau} &#92;int_M v&#92; d&#92;mu = -&#92;int_M H&#92; d&#92;mu.' class='latex' /> (11)</p>
<p style="text-align:left;">Since <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bd%7D%7Bd%5Ctau%7D+d%5Cmu+%3D+R%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{d}{d&#92;tau} d&#92;mu = R&#92; d&#92;mu' title='&#92;frac{d}{d&#92;tau} d&#92;mu = R&#92; d&#92;mu' class='latex' />, we thus see that <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_%5Ctau+v&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_&#92;tau v' title='&#92;partial_&#92;tau v' class='latex' /> must equal <img src='http://s0.wp.com/latex.php?latex=-H-Rv&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='-H-Rv' title='-H-Rv' class='latex' /> plus a quantity which integrates to zero (i.e. a divergence).  Given this, and given the fact that u (which is a close relative to v) obeys the adjoint heat equation), the following fact is then not so surprising:</p>
<p style="text-align:left;"><strong>Exercise 1.</strong> With the above assumptions, show that v obeys the forced adjoint heat equation</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=v_%5Ctau+%3D+%5CDelta+v+-+Rv+-+H&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='v_&#92;tau = &#92;Delta v - Rv - H' title='v_&#92;tau = &#92;Delta v - Rv - H' class='latex' />. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /> (12)</p>
<p style="text-align:center;">&#8211; Stationarity in the Bishop-Gromov reduced volume &#8211;</p>
<p style="text-align:left;">Before we turn to the monotonicity of the Perelman reduced volume, we first consider the simpler model case of the Bishop-Gromov reduced volume (Corollary 1 of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/27/285g-lecture-9-comparison-geometry-the-high-dimensional-limit-and-perelman-reduced-volume/">Lecture 9</a>).  An inspection of the proof of that result reveals that the key point was to establish the pointwise inequality</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5CDelta+r+%5Cleq+%5Cfrac%7Bd-1%7D%7Br%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Delta r &#92;leq &#92;frac{d-1}{r}' title='&#92;Delta r &#92;leq &#92;frac{d-1}{r}' class='latex' /> (13)</p>
<p style="text-align:left;">on a manifold <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g)' title='(M,g)' class='latex' /> of non-negative Ricci curvature <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRic%7D+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Ric} &#92;geq 0' title='&#92;hbox{Ric} &#92;geq 0' class='latex' />, where <img src='http://s0.wp.com/latex.php?latex=r+%3A%3D+d%28x%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r := d(x,x_0)' title='r := d(x,x_0)' class='latex' /> for some fixed origin <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' />. To simplify the exposition let us assume we are inside the injectivity radius, and away from the origin, to avoid any issues with lack of smoothness.</p>
<p style="text-align:left;">We gave a proof of (13) in <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/09/285g-lecture-10-variation-of-l-geodesics-and-monotonicity-of-perelman-reduced-volume/">Lecture 10</a> using the second variation formula</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%5E2%7D%7Bds%5E2%7D+E%28%5Cgamma%29%26%23124%3B_%7Bs%3D0%7D+%3D+%5Cint_0%5E1+%26%23124%3B%5Cnabla_X+Y%26%23124%3B_g%5E2+-+g%28%5Chbox%7BRiem%7D%28X%2C+Y%29+Y%2C+X%29%5C+dt&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d^2}{ds^2} E(&#92;gamma)&#124;_{s=0} = &#92;int_0^1 &#124;&#92;nabla_X Y&#124;_g^2 - g(&#92;hbox{Riem}(X, Y) Y, X)&#92; dt' title='&#92;displaystyle &#92;frac{d^2}{ds^2} E(&#92;gamma)&#124;_{s=0} = &#92;int_0^1 &#124;&#92;nabla_X Y&#124;_g^2 - g(&#92;hbox{Riem}(X, Y) Y, X)&#92; dt' class='latex' /> (14)</p>
<p style="text-align:left;">whenever <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%3A+%28-%5Cvarepsilon%2C%5Cvarepsilon%29+%5Ctimes+%5B0%2C1%5D+%5Cto+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma: (-&#92;varepsilon,&#92;varepsilon) &#92;times [0,1] &#92;to M' title='&#92;gamma: (-&#92;varepsilon,&#92;varepsilon) &#92;times [0,1] &#92;to M' class='latex' /> is a geodesic at <img src='http://s0.wp.com/latex.php?latex=s%3D0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='s=0' title='s=0' class='latex' />, with <img src='http://s0.wp.com/latex.php?latex=X+%3D+%5Cpartial_t+%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='X = &#92;partial_t &#92;gamma' title='X = &#92;partial_t &#92;gamma' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=Y+%3A%3D+%5Cpartial_s+%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='Y := &#92;partial_s &#92;gamma' title='Y := &#92;partial_s &#92;gamma' class='latex' />; (see equation (17) of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/09/285g-lecture-10-variation-of-l-geodesics-and-monotonicity-of-perelman-reduced-volume/">Lecture 10</a>).  From this (and the first variation formula) we obtain the inequality</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BHess%7D%28r%29%28v%2Cv%29+%5Cleq+%5Cint_0%5E1+%26%23124%3B%5Cnabla_X+Y%26%23124%3B_g%5E2+-+g%28%5Chbox%7BRiem%7D%28X%2C+Y%29+Y%2C+X%29%5C+dt&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Hess}(r)(v,v) &#92;leq &#92;int_0^1 &#124;&#92;nabla_X Y&#124;_g^2 - g(&#92;hbox{Riem}(X, Y) Y, X)&#92; dt' title='&#92;hbox{Hess}(r)(v,v) &#92;leq &#92;int_0^1 &#124;&#92;nabla_X Y&#124;_g^2 - g(&#92;hbox{Riem}(X, Y) Y, X)&#92; dt' class='latex' /> (15)</p>
<p style="text-align:left;">for any vector field Y along the minimising geodesic from <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' /> to x that equals 0 at <img src='http://s0.wp.com/latex.php?latex=t%3D0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t=0' title='t=0' class='latex' /> and equals v at <img src='http://s0.wp.com/latex.php?latex=t%3D1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t=1' title='t=1' class='latex' />.</p>
<p style="text-align:left;">Of course, the only way that (15) can be an equality is if Y minimises the right-hand side subject to the constraints just mentioned.  A standard calculus of variations computation lets one extract the <a href="http://en.wikipedia.org/wiki/Euler-Lagrange_equation">Euler-Lagrange equation</a> for this variational problem:</p>
<p style="text-align:left;"><strong>Exercise 2.</strong> Show that if (15) is obeyed with equality, then Y must obey the <a href="http://en.wikipedia.org/wiki/Jacobi_equation">Jacobi equation</a></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cnabla_X+%5Cnabla_X+Y+%2B+%5Chbox%7BRiem%7D%28Y%2CX%29+X+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_X &#92;nabla_X Y + &#92;hbox{Riem}(Y,X) X = 0' title='&#92;nabla_X &#92;nabla_X Y + &#92;hbox{Riem}(Y,X) X = 0' class='latex' />. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /> (16)</p>
<p style="text-align:left;">Vector fields obeying (16) are known as <em>Jacobi fields</em>.</p>
<p style="text-align:left;">Recall from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/09/285g-lecture-10-variation-of-l-geodesics-and-monotonicity-of-perelman-reduced-volume/">Lecture 10</a> that the inequality (13) was derived by applying (15) for v in an arbitrary orthonormal frame, and with <img src='http://s0.wp.com/latex.php?latex=Y%28t%29+%3A%3D+tv&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='Y(t) := tv' title='Y(t) := tv' class='latex' />, where v was extended by parallel transport along <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' /> (thus <img src='http://s0.wp.com/latex.php?latex=%5Cnabla_X+v+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_X v = 0' title='&#92;nabla_X v = 0' class='latex' />).  Thus, in order for (13) to be obeyed with equality, the fields <img src='http://s0.wp.com/latex.php?latex=Y%28t%29%3Dtv&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='Y(t)=tv' title='Y(t)=tv' class='latex' /> must be a Jacobi field for each v.  Applying (16), and noting that <img src='http://s0.wp.com/latex.php?latex=X+%3D+%5Cpartial_r&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='X = &#92;partial_r' title='X = &#92;partial_r' class='latex' />, we conclude that we must have</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRiem%7D%28+%5Ccdot%2C+%5Cpartial_r+%29+%5Cpartial_r+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Riem}( &#92;cdot, &#92;partial_r ) &#92;partial_r = 0' title='&#92;hbox{Riem}( &#92;cdot, &#92;partial_r ) &#92;partial_r = 0' class='latex' /> (17)</p>
<p style="text-align:left;">along <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' /> in order for (13) to be obeyed with equality.  The converse is also true:</p>
<p style="text-align:left;"><strong>Exercise 3. </strong> Establish the identity</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cnabla_%7B%5Cpartial+r%7D+%5Chbox%7BHess%7D%28r%29_%7B%5Calpha+%5Cbeta%7D+%2B+%5Chbox%7BHess%7D%28r%29_%7B%5Calpha+%5Cgamma%7D+%5Chbox%7BHess%7D%28r%29%5E%5Cgamma_%5Cbeta+%3D+-+%5Chbox%7BRiem%7D_%7B%5Calpha+%5Cgamma+%5Cdelta+%5Cbeta%7D+%28%5Cpartial_r%29%5E%7B%5Cgamma%7D+%28%5Cpartial_r%29%5E%7B%5Cdelta%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_{&#92;partial r} &#92;hbox{Hess}(r)_{&#92;alpha &#92;beta} + &#92;hbox{Hess}(r)_{&#92;alpha &#92;gamma} &#92;hbox{Hess}(r)^&#92;gamma_&#92;beta = - &#92;hbox{Riem}_{&#92;alpha &#92;gamma &#92;delta &#92;beta} (&#92;partial_r)^{&#92;gamma} (&#92;partial_r)^{&#92;delta}' title='&#92;nabla_{&#92;partial r} &#92;hbox{Hess}(r)_{&#92;alpha &#92;beta} + &#92;hbox{Hess}(r)_{&#92;alpha &#92;gamma} &#92;hbox{Hess}(r)^&#92;gamma_&#92;beta = - &#92;hbox{Riem}_{&#92;alpha &#92;gamma &#92;delta &#92;beta} (&#92;partial_r)^{&#92;gamma} (&#92;partial_r)^{&#92;delta}' class='latex' /> (18)</p>
<p style="text-align:left;">in the injectivity region, and conclude (13) is true with equality whenever (17) holds along the minimising geodesic <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' />. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>As a consequence of the above analysis, we see that the Bishop-Gromov reduced volume can only be stationary on a sphere when (17) holds on the ball within that sphere.</p>
<p>We can also use the theory of Jacobi fields to get a more precise formula for <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BHess%7D%28r%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Hess}(r)' title='&#92;hbox{Hess}(r)' class='latex' /> (and hence <img src='http://s0.wp.com/latex.php?latex=%5CDelta+r&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Delta r' title='&#92;Delta r' class='latex' />).  The key observation is that the Jacobi equation (16) can be written as the linearisation</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cnabla_Y%28+%5Cnabla_X+X+%29+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_Y( &#92;nabla_X X ) = 0' title='&#92;nabla_Y( &#92;nabla_X X ) = 0' class='latex' /> (19)</p>
<p>of the geodesic equation <img src='http://s0.wp.com/latex.php?latex=%5Cnabla_X+X+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_X X = 0' title='&#92;nabla_X X = 0' class='latex' />.  This is ultimately unsurprising, since the geodesic equation and the Jacobi equation come from the Euler-Lagrange equations for the energy functional and a quantity related to a variation of the energy functional.  But it allows us (at least inside the injectivity region, which also turns out (again, unsurprisingly) to be the region where the boundary value problem for the Jacobi equation always has unique solutions), to view Jacobi fields as the infinitesimal deformation field of geodesics.</p>
<p>Now let <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%3A+%28-%5Cvarepsilon%2C%5Cvarepsilon%29+%5Ctimes+%5B0%2C1%5D+%5Cto+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma: (-&#92;varepsilon,&#92;varepsilon) &#92;times [0,1] &#92;to M' title='&#92;gamma: (-&#92;varepsilon,&#92;varepsilon) &#92;times [0,1] &#92;to M' class='latex' /> be a family of geodesics <img src='http://s0.wp.com/latex.php?latex=%5Cgamma_s%3A+%5B0%2C1%5D+%5Cto+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma_s: [0,1] &#92;to M' title='&#92;gamma_s: [0,1] &#92;to M' class='latex' /> from <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=x%28s%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x(s)' title='x(s)' class='latex' />, so that <img src='http://s0.wp.com/latex.php?latex=%5Cnabla_X+X+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_X X = 0' title='&#92;nabla_X X = 0' class='latex' /> and so (by (19)) Y is a Jacobi field for each s with Y(s,0)=0 and <img src='http://s0.wp.com/latex.php?latex=Y%28s%2C1%29+%3D+v%28s%29+%3A%3D+x%27%28s%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='Y(s,1) = v(s) := x&#039;(s)' title='Y(s,1) = v(s) := x&#039;(s)' class='latex' />.  (In general one no longer expects to have Y be geodesic in the s direction, i.e. <img src='http://s0.wp.com/latex.php?latex=%5Cnabla_Y+Y&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_Y Y' title='&#92;nabla_Y Y' class='latex' /> need not be zero, but this will not concern us.)  The first variation formula (i.e. the <a href="http://en.wikipedia.org/wiki/Gauss%27s_lemma_%28Riemannian_geometry%29">Gauss lemma</a> <img src='http://s0.wp.com/latex.php?latex=%5Cnabla+r+%3D+X%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla r = X(1)' title='&#92;nabla r = X(1)' class='latex' />) then gives</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cnabla_%7Bv%7D+r+%3D+g%28++X%28%5Ccdot%2C1%29%2C++v+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_{v} r = g(  X(&#92;cdot,1),  v )' title='&#92;nabla_{v} r = g(  X(&#92;cdot,1),  v )' class='latex' /> (20)</p>
<p>and differentiating this again gives</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cnabla_%7Bv%7D++%5Cnabla_%7Bv%7D+r+%3D+g%28++%5Cnabla_v+X%28%5Ccdot%2C1%29%2C++v+%29+%2B+g%28+X%28%5Ccdot%2C1%29%2C+%5Cnabla_v+v+%29.&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_{v}  &#92;nabla_{v} r = g(  &#92;nabla_v X(&#92;cdot,1),  v ) + g( X(&#92;cdot,1), &#92;nabla_v v ).' title='&#92;nabla_{v}  &#92;nabla_{v} r = g(  &#92;nabla_v X(&#92;cdot,1),  v ) + g( X(&#92;cdot,1), &#92;nabla_v v ).' class='latex' /> (21)</p>
<p>Expanding out the left-hand side by the product rule and using (20) and the torsion-free identity <img src='http://s0.wp.com/latex.php?latex=%5Cnabla_Y+X+%3D+%5Cnabla_X+Y&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_Y X = &#92;nabla_X Y' title='&#92;nabla_Y X = &#92;nabla_X Y' class='latex' /> we conclude the second variation formula</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BHess%7D%28r%29%28v%2Cv%29+%3D+g%28+%5Cnabla_X+Y%281%29%2C+v+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Hess}(r)(v,v) = g( &#92;nabla_X Y(1), v )' title='&#92;hbox{Hess}(r)(v,v) = g( &#92;nabla_X Y(1), v )' class='latex' /> (22)</p>
<p>whenever <img src='http://s0.wp.com/latex.php?latex=Y&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='Y' title='Y' class='latex' /> is a Jacobi field along the minimal geodesic <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' /> from <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=x&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x' title='x' class='latex' /> with Y(0)=0 and Y(1)=v, and whenever one is inside the injectivity region.</p>
<p><strong>Exercise 4.</strong> Let Y be a Jacobi field with Y(0)=0 and Y(1)=v, and suppose one is inside the injectivity region.  Use (22) and (16) to show that (15) in fact holds with equality, thus providing a converse to Exercise 2.  (Hint: apply the fundamental theorem of calculus to the right-hand side of (22).)  <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:center;">&#8211; Constancy of the Perelman reduced volume &#8211;</p>
<p style="text-align:left;">We can obtain parabolic analogues of the above elliptic arguments to conclude when the Perelman reduced volume is stationary.  Again, let us argue formally and assume that we are working inside the injectivity domain from a point <img src='http://s0.wp.com/latex.php?latex=%280%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(0,x_0)' title='(0,x_0)' class='latex' />.</p>
<p style="text-align:left;">Write <img src='http://s0.wp.com/latex.php?latex=l+%3D+l_%7B%280%2Cx_0%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l = l_{(0,x_0)}' title='l = l_{(0,x_0)}' class='latex' />.  Recall from <a href="http://terrytao.wordpress.com/2008/05/09/285g-lecture-10-variation-of-l-geodesics-and-monotonicity-of-perelman-reduced-volume/">Lecture 10</a> that the proof of monotonicity of reduced volume relied on the inequality</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cpartial_%7B%5Ctau%7D+l+-+%5CDelta+l+%2B+%26%23124%3B%5Cnabla+l%26%23124%3B%5E2+-+R+%2B+%5Cfrac%7Bd%7D%7B2%5Ctau%7D+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;partial_{&#92;tau} l - &#92;Delta l + &#124;&#92;nabla l&#124;^2 - R + &#92;frac{d}{2&#92;tau} &#92;geq 0' title='&#92;displaystyle &#92;partial_{&#92;tau} l - &#92;Delta l + &#124;&#92;nabla l&#124;^2 - R + &#92;frac{d}{2&#92;tau} &#92;geq 0' class='latex' /> (23)</p>
<p style="text-align:left;">which in turn followed from the three equalities and estimates</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cnabla+l+%3D+X&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;nabla l = X' title='&#92;displaystyle &#92;nabla l = X' class='latex' /> (24)</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cpartial_%5Ctau+l+%3D+%5Cfrac%7B1%7D%7B2%7D+R+-+%5Cfrac%7B1%7D%7B2%7D+%26%23124%3BX%26%23124%3B_g%5E2+-+%5Cfrac%7B1%7D%7B2%5Ctau%7D+l&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;partial_&#92;tau l = &#92;frac{1}{2} R - &#92;frac{1}{2} &#124;X&#124;_g^2 - &#92;frac{1}{2&#92;tau} l' title='&#92;displaystyle &#92;partial_&#92;tau l = &#92;frac{1}{2} R - &#92;frac{1}{2} &#124;X&#124;_g^2 - &#92;frac{1}{2&#92;tau} l' class='latex' /> (25)</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5CDelta+l+%5Cleq+%5Cfrac%7Bd%7D%7B2%5Ctau%7D+%2B+%5Cfrac%7B1%7D%7B2%7D+%26%23124%3BX%26%23124%3B_g%5E2+-+%5Cfrac%7B1%7D%7B2%7D+R+-+%5Cfrac%7B1%7D%7B2%5Ctau%7D+l&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;Delta l &#92;leq &#92;frac{d}{2&#92;tau} + &#92;frac{1}{2} &#124;X&#124;_g^2 - &#92;frac{1}{2} R - &#92;frac{1}{2&#92;tau} l' title='&#92;displaystyle &#92;Delta l &#92;leq &#92;frac{d}{2&#92;tau} + &#92;frac{1}{2} &#124;X&#124;_g^2 - &#92;frac{1}{2} R - &#92;frac{1}{2&#92;tau} l' class='latex' />. (26)</p>
<p style="text-align:left;">Thus, in order for the reduced volume to be stationary at some time <img src='http://s0.wp.com/latex.php?latex=t+%3D+-%5Ctau_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t = -&#92;tau_1' title='t = -&#92;tau_1' class='latex' />, one must have (23) (or equivalently, (26)) holding with equality throughout M at this time.</p>
<p style="text-align:left;">It is convenient to normalise <img src='http://s0.wp.com/latex.php?latex=%5Ctau_1%3D1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau_1=1' title='&#92;tau_1=1' class='latex' />.  Recall from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/09/285g-lecture-10-variation-of-l-geodesics-and-monotonicity-of-perelman-reduced-volume/">Lecture 10</a> that the proof of (26) proceeded via the second variation formula</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%5E2%7D%7Bds%5E2%7D+%7B%5Cmathcal+L%7D%28%5Cgamma%29+%3D+%5Cint_0%5E%7B1%7D+%5Csqrt%7B%5Ctau%7D+%28+%5Chbox%7BHess%7D%28R%29%28Y%2CY%29+&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d^2}{ds^2} {&#92;mathcal L}(&#92;gamma) = &#92;int_0^{1} &#92;sqrt{&#92;tau} ( &#92;hbox{Hess}(R)(Y,Y) ' title='&#92;displaystyle &#92;frac{d^2}{ds^2} {&#92;mathcal L}(&#92;gamma) = &#92;int_0^{1} &#92;sqrt{&#92;tau} ( &#92;hbox{Hess}(R)(Y,Y) ' class='latex' /></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%2B+2+%26%23124%3B%5Cnabla_X+Y%26%23124%3B%5E2+-+2+g%28%5Chbox%7BRiem%7D%28X%2CY%29+Y%2C+X%29%29%5C+d%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle + 2 &#124;&#92;nabla_X Y&#124;^2 - 2 g(&#92;hbox{Riem}(X,Y) Y, X))&#92; d&#92;tau' title='&#92;displaystyle + 2 &#124;&#92;nabla_X Y&#124;^2 - 2 g(&#92;hbox{Riem}(X,Y) Y, X))&#92; d&#92;tau' class='latex' /> (27)</p>
<p style="text-align:left;">applied to the vector field <img src='http://s0.wp.com/latex.php?latex=Y+%3A%3D+%5Csqrt%7B%5Ctau%7D+v&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='Y := &#92;sqrt{&#92;tau} v' title='Y := &#92;sqrt{&#92;tau} v' class='latex' />, where v obeys the ODE</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cnabla_X+v+%3D+-+%5Chbox%7BRic%7D%28v%2C%5Ccdot%29%5E%2A%3B+v%28s%2C1%29+%3D+x%27%28s%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_X v = - &#92;hbox{Ric}(v,&#92;cdot)^*; v(s,1) = x&#039;(s)' title='&#92;nabla_X v = - &#92;hbox{Ric}(v,&#92;cdot)^*; v(s,1) = x&#039;(s)' class='latex' />. (28)</p>
<p style="text-align:left;">As in the elliptic case, equality in (26) can only hold if Y obeys the Euler-Lagrange equation for the right-hand side of (23), which can be computed to be</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cnabla_X+%5Cnabla_X+Y+%2B+%5Chbox%7BRiem%7D%28Y%2CX%29+X+-+%5Cfrac%7B1%7D%7B2%7D+%5Cnabla_Y%28+%5Cnabla+R+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;nabla_X &#92;nabla_X Y + &#92;hbox{Riem}(Y,X) X - &#92;frac{1}{2} &#92;nabla_Y( &#92;nabla R )' title='&#92;displaystyle &#92;nabla_X &#92;nabla_X Y + &#92;hbox{Riem}(Y,X) X - &#92;frac{1}{2} &#92;nabla_Y( &#92;nabla R )' class='latex' /></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%2B+%5Cfrac%7B1%7D%7B2%5Ctau%7D+%5Cnabla_X+Y+%2B+2+%28%5Cnabla_Y+%5Chbox%7BRic%7D%29%28X%2C%5Ccdot%29%5E%2A+%2B+2%5Chbox%7BRic%7D%28%5Cnabla_X+Y%2C+%5Ccdot%29%5E%2A+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle + &#92;frac{1}{2&#92;tau} &#92;nabla_X Y + 2 (&#92;nabla_Y &#92;hbox{Ric})(X,&#92;cdot)^* + 2&#92;hbox{Ric}(&#92;nabla_X Y, &#92;cdot)^* = 0' title='&#92;displaystyle + &#92;frac{1}{2&#92;tau} &#92;nabla_X Y + 2 (&#92;nabla_Y &#92;hbox{Ric})(X,&#92;cdot)^* + 2&#92;hbox{Ric}(&#92;nabla_X Y, &#92;cdot)^* = 0' class='latex' />. (29)</p>
<p style="text-align:left;">Solutions of (29) are known as <em><img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-Jacobi fields</em>.  As in the elliptic case, this equation can be rewritten as the linearisation</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cnabla_Y+G%28X%29+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_Y G(X) = 0' title='&#92;nabla_Y G(X) = 0' class='latex' /> (30)</p>
<p style="text-align:left;">of the <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-geodesic equation <img src='http://s0.wp.com/latex.php?latex=G%28X%29%3D0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='G(X)=0' title='G(X)=0' class='latex' />, where</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+G%28X%29+%3A%3D+%5Cnabla_X+X+-+%5Cfrac%7B1%7D%7B2%7D+%5Cnabla+R+%2B+%5Cfrac%7B1%7D%7B2%5Ctau%7D+X+%2B+2+%5Chbox%7BRic%7D%28X%2C%5Ccdot%29%5E%2A&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle G(X) := &#92;nabla_X X - &#92;frac{1}{2} &#92;nabla R + &#92;frac{1}{2&#92;tau} X + 2 &#92;hbox{Ric}(X,&#92;cdot)^*' title='&#92;displaystyle G(X) := &#92;nabla_X X - &#92;frac{1}{2} &#92;nabla R + &#92;frac{1}{2&#92;tau} X + 2 &#92;hbox{Ric}(X,&#92;cdot)^*' class='latex' /> (31)</p>
<p style="text-align:left;">was introduced in <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/09/285g-lecture-10-variation-of-l-geodesics-and-monotonicity-of-perelman-reduced-volume/">Lecture 10</a>.</p>
<p style="text-align:left;"><strong>Exercise 5. </strong> Verify (29) and (30). <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;">If <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%3A+%28-%5Cvarepsilon%2C%5Cvarepsilon%29+%5Ctimes+%5B0%2C%5Ctau_1%5D+%5Cto+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma: (-&#92;varepsilon,&#92;varepsilon) &#92;times [0,&#92;tau_1] &#92;to M' title='&#92;gamma: (-&#92;varepsilon,&#92;varepsilon) &#92;times [0,&#92;tau_1] &#92;to M' class='latex' /> is now a smooth family of minimising <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-geodesics from <img src='http://s0.wp.com/latex.php?latex=%280%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(0,x_0)' title='(0,x_0)' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=%28-%5Ctau_1%2C+x_1%28s%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(-&#92;tau_1, x_1(s))' title='(-&#92;tau_1, x_1(s))' class='latex' />, then the variation field <img src='http://s0.wp.com/latex.php?latex=Y+%3D+%5Cpartial_s+X&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='Y = &#92;partial_s X' title='Y = &#92;partial_s X' class='latex' /> is an <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-Jacobi field by (30) (and conversely, inside the region of injectivity, any Jacobi field on a minimising geodesic can be extended locally to such a smooth family.  The first variation formula (24) gives</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cnabla_v+l+%3D+g%28+X%2C+v+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_v l = g( X, v )' title='&#92;nabla_v l = g( X, v )' class='latex' /> (32)</p>
<p style="text-align:left;">where <img src='http://s0.wp.com/latex.php?latex=v%28s%29+%3A%3D+x%27_1%28s%29+%3D+Y%28s%2C1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='v(s) := x&#039;_1(s) = Y(s,1)' title='v(s) := x&#039;_1(s) = Y(s,1)' class='latex' />, and so on differentiating again and arguing as in the elliptic case we obtain</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BHess%7D%28l%29%28v%2Cv%29+%3D+g%28+%5Cnabla_X+Y%281%29%2C+v+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Hess}(l)(v,v) = g( &#92;nabla_X Y(1), v )' title='&#92;hbox{Hess}(l)(v,v) = g( &#92;nabla_X Y(1), v )' class='latex' /> (33)</p>
<p style="text-align:left;">whenever Y is an <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-Jacobi field with Y(0)=0 and Y(1)=v.</p>
<p style="text-align:left;"><strong>Exercise 6. </strong> Show (using (31) and the fundamental theorem of calculus, as in Exercise 4) that (33) is equal to (27). <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;">Now we return to our analysis of when the reduced volume is stationary at <img src='http://s0.wp.com/latex.php?latex=%5Ctau%3D1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau=1' title='&#92;tau=1' class='latex' />.  We had found in that case that the vector field <img src='http://s0.wp.com/latex.php?latex=Y+%3A%3D+%5Csqrt%7B%5Ctau%7D+v&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='Y := &#92;sqrt{&#92;tau} v' title='Y := &#92;sqrt{&#92;tau} v' class='latex' />, where v solved (28), must be a Jacobi field.  Combining this with (33) we conclude that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Chbox%7BHess%7D%28l%29%28v%2Cv%29+%3D+%5Cfrac%7B1%7D%7B2%7D+%26%23124%3Bv%26%23124%3B%5E2+-+%5Chbox%7BRic%7D%28v%2Cv%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;hbox{Hess}(l)(v,v) = &#92;frac{1}{2} &#124;v&#124;^2 - &#92;hbox{Ric}(v,v)' title='&#92;displaystyle &#92;hbox{Hess}(l)(v,v) = &#92;frac{1}{2} &#124;v&#124;^2 - &#92;hbox{Ric}(v,v)' class='latex' /> (34)</p>
<p style="text-align:left;">for any v, or in other words that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Chbox%7BRic%7D+%2B+%5Chbox%7BHess%7D%28l%29+%3D+%5Cfrac%7B1%7D%7B2%7D+g&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;hbox{Ric} + &#92;hbox{Hess}(l) = &#92;frac{1}{2} g' title='&#92;displaystyle &#92;hbox{Ric} + &#92;hbox{Hess}(l) = &#92;frac{1}{2} g' class='latex' />. (35)</p>
<p style="text-align:left;">This is for time <img src='http://s0.wp.com/latex.php?latex=%5Ctau%3D1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau=1' title='&#92;tau=1' class='latex' />; rescaling the above analysis gives more generally that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Chbox%7BRic%7D+%2B+%5Chbox%7BHess%7D%28l%29+%3D+%5Cfrac%7B1%7D%7B2%5Ctau%7D+g&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;hbox{Ric} + &#92;hbox{Hess}(l) = &#92;frac{1}{2&#92;tau} g' title='&#92;displaystyle &#92;hbox{Ric} + &#92;hbox{Hess}(l) = &#92;frac{1}{2&#92;tau} g' class='latex' />. (36)</p>
<p style="text-align:left;">We thus conclude (formally, at least) that whenever the reduced volume is stationary, then the manifold is a gradient shrinking soliton (at that instant in time, at least) with potential function given by the reduced length.  (The computation is only formal at present, because we have not addressed the issue of what to do on the <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-cut locus.)</p>
<p style="text-align:left;"><strong>Exercise 7.</strong> If (26) is obeyed with equality, show that the function <img src='http://s0.wp.com/latex.php?latex=f+%3A%3D+l&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='f := l' title='f := l' class='latex' /> obeys (6) and that <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+W%7D%28M%2Cg%28t%29%2Cf%2C%5Ctau%29+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal W}(M,g(t),f,&#92;tau) = 0' title='{&#92;mathcal W}(M,g(t),f,&#92;tau) = 0' class='latex' /> (cf. the computations at the end of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/14/285g-lecture-11-%ce%ba-noncollapsing-via-perelman-reduced-volume/">Lecture 11</a>).  From this and (7), deduce another (formal) proof of (36) whenever the reduced volume is stationary on an open time interval. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;"><strong>Remark 1.</strong> We have just seen that in the case of stationary reduced volume, the function f that appears in the entropy functional can be taken to be equal to the reduced length l.  In general, one can take f to be a function bounded from above by the reduced length; see  Corollary 9.5 of <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0211159">Perelman&#8217;s paper</a>.  <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:center;">&#8211; Ricci flows of maximal reduced volume &#8211;</p>
<p style="text-align:left;">Recall that the reduced volume <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+V_%7B%280%2Cx_0%29%7D%28-%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde V_{(0,x_0)}(-&#92;tau)' title='&#92;tilde V_{(0,x_0)}(-&#92;tau)' class='latex' /> is equal to <img src='http://s0.wp.com/latex.php?latex=%284%5Cpi%29%5E%7Bd%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(4&#92;pi)^{d/2}' title='(4&#92;pi)^{d/2}' class='latex' /> in the case of Euclidean space, and converges to this value in the limit <img src='http://s0.wp.com/latex.php?latex=%5Ctau+%5Cto+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau &#92;to 0' title='&#92;tau &#92;to 0' class='latex' /> in the case of complete Ricci flows of bounded curvature<br />
(this can be shown by an analysis of the <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-exponential map for small values of <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' />, as discussed in <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/14/285g-lecture-11-%ce%ba-noncollapsing-via-perelman-reduced-volume/">Lecture 11</a>).  From this and the monotonicity of reduced volume we conclude that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Ctilde+V_%7B%280%2Cx_0%29%7D%28-%5Ctau%29+%5Cleq+%284%5Cpi%29%5E%7Bd%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde V_{(0,x_0)}(-&#92;tau) &#92;leq (4&#92;pi)^{d/2}' title='&#92;tilde V_{(0,x_0)}(-&#92;tau) &#92;leq (4&#92;pi)^{d/2}' class='latex' /> (37)</p>
<p style="text-align:left;">for all such flows.  We now characterise when equality occurs:</p>
<blockquote>
<p style="text-align:left;"><strong>Theorem 1. </strong>Suppose that <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> is a connected Ricci flow of bounded curvature on <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5B-%5Ctau_1%2C0%5D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[-&#92;tau_1,0]' title='{}[-&#92;tau_1,0]' class='latex' /> for some <img src='http://s0.wp.com/latex.php?latex=%5Ctau_1+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau_1 &gt; 0' title='&#92;tau_1 &gt; 0' class='latex' />, such that (37) is obeyed with equality at the initial time <img src='http://s0.wp.com/latex.php?latex=-%5Ctau_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='-&#92;tau_1' title='-&#92;tau_1' class='latex' /> for some point <img src='http://s0.wp.com/latex.php?latex=x_0+%5Cin+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0 &#92;in M' title='x_0 &#92;in M' class='latex' />.  Then M is Euclidean.</p>
</blockquote>
<p style="text-align:left;"><strong>Proof.</strong> We give a sketch here only; full details can be found in Proposition 7.27 of <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2334563">Morgan-Tian&#8217;s book</a>.</p>
<p style="text-align:left;">An inspection of the proof of monotonicity of reduced volume (especially as viewed through the <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-exponential map, as in <a href="http://terrytao.wordpress.com/2008/05/14/285g-lecture-11-%ce%ba-noncollapsing-via-perelman-reduced-volume/">Lecture 11</a>) reveals that the domain of injectivity <img src='http://s0.wp.com/latex.php?latex=%5COmega+%5Csubset+T_%7Bx_0%7D+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Omega &#92;subset T_{x_0} M' title='&#92;Omega &#92;subset T_{x_0} M' class='latex' /> of the exponential map must have full measure, otherwise there will be a loss of reduced volume.  The previous analysis then reveals that the equation (32) must hold outside of the cut locus; as l is Lipschitz and the manifold is smooth, one can then take limits and conclude that (32) holds globally (and so l is in fact smooth).</p>
<p style="text-align:left;">Combining (32) with the Ricci flow equation we obtain</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bd%7D%7Bdt%7D+g+%3D+%7B%5Cmathcal+L%7D_%7B%5Cnabla+l%7D+g+-+%5Cfrac%7B1%7D%7B%5Ctau%7D+g&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{d}{dt} g = {&#92;mathcal L}_{&#92;nabla l} g - &#92;frac{1}{&#92;tau} g' title='&#92;frac{d}{dt} g = {&#92;mathcal L}_{&#92;nabla l} g - &#92;frac{1}{&#92;tau} g' class='latex' />, (38)</p>
<p style="text-align:left;">thus the metric is shrinking and also deforming by a vector field.  In particular this gives an analogous equation for the magnitude <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Chbox%7BRiem%7D%26%23124%3B_g%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;hbox{Riem}&#124;_g^2' title='&#124;&#92;hbox{Riem}&#124;_g^2' class='latex' /> of curvature (see equations (22), (26)):</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bd%7D%7Bdt%7D++%26%23124%3B%5Chbox%7BRiem%7D%26%23124%3B_g%5E2+%3D+%5Cnabla_%7B%5Cnabla+l%7D+%26%23124%3B%5Chbox%7BRiem%7D%26%23124%3B_g%5E2+%2B+%5Cfrac%7B1%7D%7B%5Ctau%7D+%26%23124%3B%5Chbox%7BRiem%7D%26%23124%3B_g%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{d}{dt}  &#124;&#92;hbox{Riem}&#124;_g^2 = &#92;nabla_{&#92;nabla l} &#124;&#92;hbox{Riem}&#124;_g^2 + &#92;frac{1}{&#92;tau} &#124;&#92;hbox{Riem}&#124;_g^2' title='&#92;frac{d}{dt}  &#124;&#92;hbox{Riem}&#124;_g^2 = &#92;nabla_{&#92;nabla l} &#124;&#92;hbox{Riem}&#124;_g^2 + &#92;frac{1}{&#92;tau} &#124;&#92;hbox{Riem}&#124;_g^2' class='latex' />. (39)</p>
<p style="text-align:left;">A maximum principle argument (which of course works in the absence of the dissipation term) then shows that if <img src='http://s0.wp.com/latex.php?latex=%5Csup_x+%26%23124%3B%5Chbox%7BRiem%7D%26%23124%3B_g%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;sup_x &#124;&#92;hbox{Riem}&#124;_g^2' title='&#92;sup_x &#124;&#92;hbox{Riem}&#124;_g^2' class='latex' /> is strictly positive at one time, then it blows up as <img src='http://s0.wp.com/latex.php?latex=%5Ctau+%5Cto+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau &#92;to 0' title='&#92;tau &#92;to 0' class='latex' /> (like <img src='http://s0.wp.com/latex.php?latex=1%2F%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='1/&#92;tau' title='1/&#92;tau' class='latex' />, in fact), which is absurd; and so this supremum must always be zero.  In other words, the manifold is flat, and is therefore the quotient of <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+R%7D%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb R}^d' title='{&#92;Bbb R}^d' class='latex' /> by some discrete subgroup.  But as the exponential map is almost always in the injectivity domain, this subgroup must be trivial, and the claim follows. <img src='http://s0.wp.com/latex.php?latex=%5CBox&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Box' title='&#92;Box' class='latex' /></p>
<p style="text-align:left;">
<p style="text-align:left;">
]]></content:encoded>
</item>
<item>
<title><![CDATA[285G, Lecture 13: Li-Yau-Hamilton Harnack inequalities and κ-solutions ]]></title>
<link>http://terrytao.wordpress.com/2008/05/19/285g-lecture-13-li-yau-hamilton-harnack-inequalities-and-%ce%ba-solutions/</link>
<pubDate>Mon, 19 May 2008 18:12:39 +0000</pubDate>
<dc:creator>Terence Tao</dc:creator>
<guid>http://terrytao.wordpress.com/2008/05/19/285g-lecture-13-li-yau-hamilton-harnack-inequalities-and-%ce%ba-solutions/</guid>
<description><![CDATA[We now turn to the theory of parabolic Harnack inequalities, which control the variation over space]]></description>
<content:encoded><![CDATA[<p>We now turn to the theory of <em>parabolic Harnack inequalities</em>, which control the variation over space and time of solutions to the scalar heat equation</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=u_t+%3D+%5CDelta+u&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u_t = &#92;Delta u' title='u_t = &#92;Delta u' class='latex' /> (1)</p>
<p>which are bounded and non-negative, and (more pertinently to our applications) of the curvature of Ricci flows</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=g_t+%3D+-2%5Chbox%7BRic%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='g_t = -2&#92;hbox{Ric}' title='g_t = -2&#92;hbox{Ric}' class='latex' /> (2)</p>
<p>whose Riemann curvature <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRiem%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Riem}' title='&#92;hbox{Riem}' class='latex' /> or Ricci curvature <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRic%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Ric}' title='&#92;hbox{Ric}' class='latex' /> is bounded and non-negative.  For instance, the classical <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=159139">parabolic Harnack inequality of Moser</a> asserts, among other things, that one has a bound of the form</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=u%28t_1%2Cx_1%29+%5Cleq+C%28t_1%2Cx_1%2Ct_0%2Cx_0%2CT_-%2CT_%2B%2CM%29+u%28t_0%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u(t_1,x_1) &#92;leq C(t_1,x_1,t_0,x_0,T_-,T_+,M) u(t_0,x_0)' title='u(t_1,x_1) &#92;leq C(t_1,x_1,t_0,x_0,T_-,T_+,M) u(t_0,x_0)' class='latex' /> (3)</p>
<p>whenever <img src='http://s0.wp.com/latex.php?latex=u%3A+%5BT_-%2CT_%2B%5D+%5Ctimes+M+%5Cto+%7B%5CBbb+R%7D%5E%2B&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u: [T_-,T_+] &#92;times M &#92;to {&#92;Bbb R}^+' title='u: [T_-,T_+] &#92;times M &#92;to {&#92;Bbb R}^+' class='latex' /> is a bounded non-negative solution to (1) on a complete static Riemannian manifold M of bounded curvature, <img src='http://s0.wp.com/latex.php?latex=%28t_1%2Cx_1%29%2C+%28t_0%2Cx_0%29+%5Cin+%5BT_-%2CT_%2B%5D+%5Ctimes+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_1,x_1), (t_0,x_0) &#92;in [T_-,T_+] &#92;times M' title='(t_1,x_1), (t_0,x_0) &#92;in [T_-,T_+] &#92;times M' class='latex' /> are spacetime points with <img src='http://s0.wp.com/latex.php?latex=t_1+%26%2360%3B+t_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_1 &lt; t_0' title='t_1 &lt; t_0' class='latex' />, and <img src='http://s0.wp.com/latex.php?latex=C%28t_1%2Cx_1%2Ct_0%2Cx_0%2CT_-%2CT_%2B%2CM%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C(t_1,x_1,t_0,x_0,T_-,T_+,M)' title='C(t_1,x_1,t_0,x_0,T_-,T_+,M)' class='latex' /> is a constant which is uniformly bounded for fixed <img src='http://s0.wp.com/latex.php?latex=t_1%2Ct_0%2CT_-%2CT_%2B%2CM&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_1,t_0,T_-,T_+,M' title='t_1,t_0,T_-,T_+,M' class='latex' /> when <img src='http://s0.wp.com/latex.php?latex=x_1%2Cx_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_1,x_0' title='x_1,x_0' class='latex' /> range over a compact set.  (The even more classical <a href="http://en.wikipedia.org/wiki/Harnack's_inequality">elliptic Harnack inequality</a> gives (1) in the steady state case, i.e. for bounded non-negative harmonic functions.)  In terms of <a href="http://en.wikipedia.org/wiki/Heat_kernel">heat kernels</a>, one can view (1) as an assertion that the heat kernel associated to <img src='http://s0.wp.com/latex.php?latex=%28t_0%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_0,x_0)' title='(t_0,x_0)' class='latex' /> dominates (up to multiplicative constants) the heat kernel at <img src='http://s0.wp.com/latex.php?latex=%28t_1%2Cx_1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_1,x_1)' title='(t_1,x_1)' class='latex' />.</p>
<p>The classical proofs of the parabolic Harnack inequality do not give particularly sharp bounds on the constant <img src='http://s0.wp.com/latex.php?latex=C%28t_1%2Cx_1%2Ct_0%2Cx_0%2CT_-%2CT_%2B%2CM%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C(t_1,x_1,t_0,x_0,T_-,T_+,M)' title='C(t_1,x_1,t_0,x_0,T_-,T_+,M)' class='latex' />.  Such sharp bounds were obtained <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=834612">by Li and Yau</a>, especially in the case of the scalar heat equation (1) in the case of static manifolds of non-negative Ricci curvature, using Bochner-type identities and the scalar maximum principle.  In fact, a stronger differential version of  (3) was obtained which implied (3) by an integration along spacetime curves (closely analogous to the <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-geodesics considered in earlier lectures).    These bounds were particularly strong in the case of ancient solutions (in which one can send <img src='http://s0.wp.com/latex.php?latex=T_-+%5Cto+-%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='T_- &#92;to -&#92;infty' title='T_- &#92;to -&#92;infty' class='latex' />).  Subsequently, <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=1198607">Hamilton applied</a> his tensor-valued maximum principle together with some remarkably delicate tensor algebra manipulations to obtain Harnack inequalities of Li-Yau type for solutions to the Ricci flow (2) with bounded non-negative Riemannian curvature.  In particular, this inequality applies to the <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions introduced in the <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/16/285g-lecture-12-high-curvature-regions-of-ricci-flow-and-%ce%ba-solutions/">previous lecture</a>.</p>
<p>In this current lecture, we shall discuss all of these inequalities (although we will not give the full details for the proof of Hamilton&#8217;s Harnack inequality, as the computations are quite involved), and derive several important consequences of that inequality for <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions.  The material here is based on several sources, including <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=1625845">Evans&#8217; PDE book</a>, <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2251315">Müller&#8217;s book</a>, <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2334563">Morgan-Tian&#8217;s book</a>, the <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2233789">paper of Cao-Zhu</a>, and of course the primary source papers mentioned in this article.</p>
<p><!--more--></p>
<p style="text-align:center;">&#8211; Scalar parabolic Harnack inequalities &#8211;</p>
<p>Before we turn to the inequalities for Ricci flows (which are our main interest), we first consider the simpler case of scalar non-negative bounded solutions <img src='http://s0.wp.com/latex.php?latex=u%3A+%5BT_-%2CT_%2B%5D+%5Ctimes+M+%5Cto+%7B%5CBbb+R%7D%5E%2B&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u: [T_-,T_+] &#92;times M &#92;to {&#92;Bbb R}^+' title='u: [T_-,T_+] &#92;times M &#92;to {&#92;Bbb R}^+' class='latex' /> to the heat equation (1) on a static complete smooth Riemannian manifold <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g)' title='(M,g)' class='latex' />.  This case will not actually be used in our applications but serve as an important motivating example of the method.  Our basic tools will be the scalar maximum principle and the following identity.</p>
<p><strong>Exercise 1.</strong> Let <img src='http://s0.wp.com/latex.php?latex=f%3A+M+%5Cto+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='f: M &#92;to {&#92;Bbb R}' title='f: M &#92;to {&#92;Bbb R}' class='latex' /> be a smooth function.  Establish the <a href="http://en.wikipedia.org/wiki/Bochner%27s_formula">Bochner formula</a></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5CDelta+%26%23124%3B%5Cnabla+f%26%23124%3B_g%5E2+%3D+2+%5Cnabla_%7B%5Cnabla+f%7D+%5CDelta+f+%2B+2+%26%23124%3B%5Chbox%7BHess%7D%28f%29%26%23124%3B_g%5E2+%2B+2+%5Chbox%7BRic%7D%28%5Cnabla+f%2C+%5Cnabla+f%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Delta &#124;&#92;nabla f&#124;_g^2 = 2 &#92;nabla_{&#92;nabla f} &#92;Delta f + 2 &#124;&#92;hbox{Hess}(f)&#124;_g^2 + 2 &#92;hbox{Ric}(&#92;nabla f, &#92;nabla f)' title='&#92;Delta &#124;&#92;nabla f&#124;_g^2 = 2 &#92;nabla_{&#92;nabla f} &#92;Delta f + 2 &#124;&#92;hbox{Hess}(f)&#124;_g^2 + 2 &#92;hbox{Ric}(&#92;nabla f, &#92;nabla f)' class='latex' />.  (4)</p>
<p>(Hint: use abstract index notation, and use the torsion-free nature of the connection, combined with the definitions of Riemann and Ricci curvature.) <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>This leads to the following consequence:</p>
<p><strong>Exercise 2.</strong> Let <img src='http://s0.wp.com/latex.php?latex=u%3A+%5BT_-%2CT_%2B%5D+%5Ctimes+M+%5Cto+%7B%5CBbb+R%7D%5E%2B&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u: [T_-,T_+] &#92;times M &#92;to {&#92;Bbb R}^+' title='u: [T_-,T_+] &#92;times M &#92;to {&#92;Bbb R}^+' class='latex' /> be a strictly positive solution to (1), and let <img src='http://s0.wp.com/latex.php?latex=f+%3A%3D+%5Clog+u&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='f := &#92;log u' title='f := &#92;log u' class='latex' />.  Establish the nonlinear heat equation identities</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=f_t+%3D+%5CDelta+f+%2B+%5Cnabla_%7B%5Cnabla+f%7D+f+%3D+%5CDelta+f+%2B+%26%23124%3B%5Cnabla+f%26%23124%3B_g%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='f_t = &#92;Delta f + &#92;nabla_{&#92;nabla f} f = &#92;Delta f + &#124;&#92;nabla f&#124;_g^2' title='f_t = &#92;Delta f + &#92;nabla_{&#92;nabla f} f = &#92;Delta f + &#124;&#92;nabla f&#124;_g^2' class='latex' /> (5)</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+%28%5CDelta+f%29+%3D+%5CDelta%28%5CDelta+f%29+%2B+%5Cnabla_%7B%5Cnabla+f%7D+%5CDelta+f+%2B+2+%26%23124%3B%5Chbox%7BHess%7D+f%26%23124%3B_g%5E2+%2B+2+%5Chbox%7BRic%7D%28%5Cnabla+f%2C+%5Cnabla+f%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t (&#92;Delta f) = &#92;Delta(&#92;Delta f) + &#92;nabla_{&#92;nabla f} &#92;Delta f + 2 &#124;&#92;hbox{Hess} f&#124;_g^2 + 2 &#92;hbox{Ric}(&#92;nabla f, &#92;nabla f)' title='&#92;partial_t (&#92;Delta f) = &#92;Delta(&#92;Delta f) + &#92;nabla_{&#92;nabla f} &#92;Delta f + 2 &#124;&#92;hbox{Hess} f&#124;_g^2 + 2 &#92;hbox{Ric}(&#92;nabla f, &#92;nabla f)' class='latex' /> (6)</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+%28%26%23124%3B%5Cnabla+f%26%23124%3B%5E2%29+%3D+%5CDelta%28%26%23124%3B%5Cnabla+f%26%23124%3B%5E2%29+%2B+%5Cnabla_%7B%5Cnabla+f%7D%28%26%23124%3B%5Cnabla+f%26%23124%3B%5E2%29+-+2+%26%23124%3B%5Chbox%7BHess%7D+f%26%23124%3B_g%5E2+%2B+2+%5Chbox%7BRic%7D%28%5Cnabla+f%2C+%5Cnabla+f%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t (&#124;&#92;nabla f&#124;^2) = &#92;Delta(&#124;&#92;nabla f&#124;^2) + &#92;nabla_{&#92;nabla f}(&#124;&#92;nabla f&#124;^2) - 2 &#124;&#92;hbox{Hess} f&#124;_g^2 + 2 &#92;hbox{Ric}(&#92;nabla f, &#92;nabla f)' title='&#92;partial_t (&#124;&#92;nabla f&#124;^2) = &#92;Delta(&#124;&#92;nabla f&#124;^2) + &#92;nabla_{&#92;nabla f}(&#124;&#92;nabla f&#124;^2) - 2 &#124;&#92;hbox{Hess} f&#124;_g^2 + 2 &#92;hbox{Ric}(&#92;nabla f, &#92;nabla f)' class='latex' />. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /> (7)</p>
<p>Now we can state the Li-Yau Harnack inequality.</p>
<blockquote><p><strong>Proposition 1.</strong> (Li-Yau Harnack inequality) Let M be a smooth compact d-dimensional Riemannian manifold with non-negative Ricci curvature, and let <img src='http://s0.wp.com/latex.php?latex=u%3A+%5BT_-%2CT_%2B%5D+%5Ctimes+M+%5Cto+%7B%5CBbb+R%7D%5E%2B&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u: [T_-,T_+] &#92;times M &#92;to {&#92;Bbb R}^+' title='u: [T_-,T_+] &#92;times M &#92;to {&#92;Bbb R}^+' class='latex' /> be a strictly positive smooth solution to (1).   Then for every <img src='http://s0.wp.com/latex.php?latex=%28t%2Cx%29+%5Cin+%28T_-%2CT_%2B%5D+%5Ctimes+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t,x) &#92;in (T_-,T_+] &#92;times M' title='(t,x) &#92;in (T_-,T_+] &#92;times M' class='latex' />, we have</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7B%5Cpartial_t+u%7D%7Bu%7D+-+%5Cfrac%7B%26%23124%3B%5Cnabla+u%26%23124%3B%5E2%7D%7Bu%5E2%7D+%2B+%5Cfrac%7Bd%7D%7B2%28t-T_-%29%7D+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{&#92;partial_t u}{u} - &#92;frac{&#124;&#92;nabla u&#124;^2}{u^2} + &#92;frac{d}{2(t-T_-)} &#92;geq 0' title='&#92;displaystyle &#92;frac{&#92;partial_t u}{u} - &#92;frac{&#124;&#92;nabla u&#124;^2}{u^2} + &#92;frac{d}{2(t-T_-)} &#92;geq 0' class='latex' />. (8)</p>
</blockquote>
<p style="text-align:left;"><strong>Proof.</strong> By adding an epsilon to u if necessary (and then sending epsilon back to zero at the end of the argument) we may assume that <img src='http://s0.wp.com/latex.php?latex=u+%5Cgeq+%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u &#92;geq &#92;varepsilon' title='u &#92;geq &#92;varepsilon' class='latex' /> for some <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon &gt; 0' title='&#92;varepsilon &gt; 0' class='latex' />.  (We shall use this trick frequently in the sequel and refer to it as the <em>epsilon-regularisation trick</em>.) Write <img src='http://s0.wp.com/latex.php?latex=f+%3A%3D+%5Clog+u&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='f := &#92;log u' title='f := &#92;log u' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=F+%3A%3D+%5CDelta+f&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='F := &#92;Delta f' title='F := &#92;Delta f' class='latex' />.  From Cauchy-Schwarz we have <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Chbox%7BHess%7D+f%26%23124%3B_g%5E2+%5Cgeq+%5Cfrac%7B1%7D%7Bd%7D+F%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;hbox{Hess} f&#124;_g^2 &#92;geq &#92;frac{1}{d} F^2' title='&#124;&#92;hbox{Hess} f&#124;_g^2 &#92;geq &#92;frac{1}{d} F^2' class='latex' />, and so from (6) we see that F is a supersolution to a nonlinear heat equation:</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+F_t+%5Cgeq+%5CDelta+F+%2B+%5Cnabla_%7B%5Cnabla+f%7D+F+%2B+%5Cfrac%7B2%7D%7Bd%7D+%26%23124%3BF%26%23124%3B%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle F_t &#92;geq &#92;Delta F + &#92;nabla_{&#92;nabla f} F + &#92;frac{2}{d} &#124;F&#124;^2' title='&#92;displaystyle F_t &#92;geq &#92;Delta F + &#92;nabla_{&#92;nabla f} F + &#92;frac{2}{d} &#124;F&#124;^2' class='latex' />. (9)</p>
<p style="text-align:left;">On the other hand, <img src='http://s0.wp.com/latex.php?latex=-%5Cfrac%7Bd%7D%7B2%28t-T_-%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='-&#92;frac{d}{2(t-T_-)}' title='-&#92;frac{d}{2(t-T_-)}' class='latex' /> is a sub-solution to the same equation, and the hypothesis that u is smooth and bounded below by <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' /> (together with the compactness of M) implies that F dominates <img src='http://s0.wp.com/latex.php?latex=-%5Cfrac%7Bd%7D%7B2%28t-T_-%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='-&#92;frac{d}{2(t-T_-)}' title='-&#92;frac{d}{2(t-T_-)}' class='latex' /> at times close to <img src='http://s0.wp.com/latex.php?latex=T_-&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='T_-' title='T_-' class='latex' />.  Applying the scalar maximum principle (Corollary 1 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/04/285g-lecture-3-the-maximum-principle-and-the-pinching-phenomenon/">Lecture 3</a>) we conclude that <img src='http://s0.wp.com/latex.php?latex=F+%5Cgeq+-%5Cfrac%7Bd%7D%7B2%28t-T_-%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='F &#92;geq -&#92;frac{d}{2(t-T_-)}' title='F &#92;geq -&#92;frac{d}{2(t-T_-)}' class='latex' />.  The claim (8) now follows from (5) and the chain rule. <img src='http://s0.wp.com/latex.php?latex=%5CBox&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Box' title='&#92;Box' class='latex' /></p>
<p style="text-align:left;"><strong>Remark 1.</strong> One can extend this inequality to the case when M is not compact, but is instead complete with bounded curvature, as long as one now adds the hypothesis that u is bounded (which was automatic in the compact case).  The basic idea used to modify the proof is to multiply u by a suitable weight that grows at infinity to force the minimum value of F to lie in a compact set so that the maximum principle arguments can still be applied; we omit the standard details. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;"><strong>Remark 2.</strong> Observe that when <img src='http://s0.wp.com/latex.php?latex=M%3D%7B%5CBbb+R%7D%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M={&#92;Bbb R}^d' title='M={&#92;Bbb R}^d' class='latex' /> is Euclidean and u is the fundamental solution <img src='http://s0.wp.com/latex.php?latex=u%28t%2Cx%29+%3D+%5Cfrac%7B1%7D%7B%284%5Cpi+%28t-T_-%29%29%5E%7Bd%2F2%7D%7D+e%5E%7B-%26%23124%3Bx-x_0%26%23124%3B%5E2%2F4%28t-T_-%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u(t,x) = &#92;frac{1}{(4&#92;pi (t-T_-))^{d/2}} e^{-&#124;x-x_0&#124;^2/4(t-T_-)}' title='u(t,x) = &#92;frac{1}{(4&#92;pi (t-T_-))^{d/2}} e^{-&#124;x-x_0&#124;^2/4(t-T_-)}' class='latex' /> for some <img src='http://s0.wp.com/latex.php?latex=x_0+%5Cin+%7B%5CBbb+R%7D%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0 &#92;in {&#92;Bbb R}^d' title='x_0 &#92;in {&#92;Bbb R}^d' class='latex' />, that (8) becomes an equality. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;">For strictly positive ancient solutions <img src='http://s0.wp.com/latex.php?latex=u%3A+%28-%5Cinfty%2C0%5D+%5Ctimes+M+%5Cto+%7B%5CBbb+R%7D%5E%2B&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u: (-&#92;infty,0] &#92;times M &#92;to {&#92;Bbb R}^+' title='u: (-&#92;infty,0] &#92;times M &#92;to {&#92;Bbb R}^+' class='latex' /> to (1) on a compact manifold of non-negative Ricci curvature, one can send <img src='http://s0.wp.com/latex.php?latex=T_-&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='T_-' title='T_-' class='latex' /> to negative infinity, we conclude from (8) that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7B%5Cpartial_t+u%7D%7Bu%7D+%5Cgeq+%5Cfrac%7B%26%23124%3B%5Cnabla+u%26%23124%3B%5E2%7D%7Bu%5E2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{&#92;partial_t u}{u} &#92;geq &#92;frac{&#124;&#92;nabla u&#124;^2}{u^2}' title='&#92;displaystyle &#92;frac{&#92;partial_t u}{u} &#92;geq &#92;frac{&#124;&#92;nabla u&#124;^2}{u^2}' class='latex' />. (10)</p>
<p style="text-align:left;">In particular we see that <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+u+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t u &#92;geq 0' title='&#92;partial_t u &#92;geq 0' class='latex' />; thus non-negative ancient solutions to the linear heat equation on compact manifolds of non-negative Ricci curvature are non-decreasing in time.  [Actually, it turns out that the only such solutions are in fact constant, but we will shortly generalise this assertion to less trivial situations.]</p>
<p style="text-align:left;">One can linearise the inequality (10) in u, obtaining the assertion that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cpartial_t+u+-+%5Cnabla_X+u+%2B+%5Cfrac%7B1%7D%7B4%7D+%26%23124%3BX%26%23124%3B_g%5E2+u+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;partial_t u - &#92;nabla_X u + &#92;frac{1}{4} &#124;X&#124;_g^2 u &#92;geq 0' title='&#92;displaystyle &#92;partial_t u - &#92;nabla_X u + &#92;frac{1}{4} &#124;X&#124;_g^2 u &#92;geq 0' class='latex' /> (10&#8242;)</p>
<p style="text-align:left;">for any vector field X.  Indeed (10) and (10&#8242;) are easily seen to be equivalent by the Cauchy-Schwarz inequality.  One advantage of the formulation (10&#8242;) is that it also holds true when u is merely non-negative, as opposed to strictly positive u, by the epsilon-regularisation trick.  In terms of <img src='http://s0.wp.com/latex.php?latex=f+%3D+%5Clog+u&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='f = &#92;log u' title='f = &#92;log u' class='latex' />, (10&#8242;) can also be expressed as</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cpartial_t+f+-+%5Cnabla_X+f+%2B+%5Cfrac%7B1%7D%7B4%7D+%26%23124%3BX%26%23124%3B_g%5E2+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;partial_t f - &#92;nabla_X f + &#92;frac{1}{4} &#124;X&#124;_g^2 &#92;geq 0' title='&#92;displaystyle &#92;partial_t f - &#92;nabla_X f + &#92;frac{1}{4} &#124;X&#124;_g^2 &#92;geq 0' class='latex' /> (11)</p>
<p style="text-align:left;">although now one needs u to be strictly positive for (11) to make sense.</p>
<p style="text-align:left;">Now let <img src='http://s0.wp.com/latex.php?latex=%28t_0%2Cx_0%29%2C+%28t_1%2Cx_1%29+%5Cin+%28-%5Cinfty%2C0%5D+%5Ctimes+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_0,x_0), (t_1,x_1) &#92;in (-&#92;infty,0] &#92;times M' title='(t_0,x_0), (t_1,x_1) &#92;in (-&#92;infty,0] &#92;times M' class='latex' /> be points in spacetime with <img src='http://s0.wp.com/latex.php?latex=t_1+%26%2360%3B+t_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_1 &lt; t_0' title='t_1 &lt; t_0' class='latex' />, let <img src='http://s0.wp.com/latex.php?latex=%5Ctau_1+%3A%3D+t_0+-+t_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau_1 := t_0 - t_1' title='&#92;tau_1 := t_0 - t_1' class='latex' />, and let <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%3A+%5B0%2C%5Ctau_1%5D+%5Cto+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma: [0,&#92;tau_1] &#92;to M' title='&#92;gamma: [0,&#92;tau_1] &#92;to M' class='latex' /> be a path from <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=x_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_1' title='x_1' class='latex' />.  From the fundamental theorem of calculus and the chain rule we have</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+f%28t_1%2Cx_1%29+-+f%28t_0%2Cx_0%29+%3D+%5Cint_0%5E%7B%5Ctau_1%7D+-%5Cpartial_t+f+%2B+%5Cnabla_X+f%5C+d%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle f(t_1,x_1) - f(t_0,x_0) = &#92;int_0^{&#92;tau_1} -&#92;partial_t f + &#92;nabla_X f&#92; d&#92;tau' title='&#92;displaystyle f(t_1,x_1) - f(t_0,x_0) = &#92;int_0^{&#92;tau_1} -&#92;partial_t f + &#92;nabla_X f&#92; d&#92;tau' class='latex' /> (12)</p>
<p style="text-align:left;">where <img src='http://s0.wp.com/latex.php?latex=X+%3A%3D+%5Cgamma%27%28%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='X := &#92;gamma&#039;(&#92;tau)' title='X := &#92;gamma&#039;(&#92;tau)' class='latex' /> and the integrand is evaluated at <img src='http://s0.wp.com/latex.php?latex=%28t_0-%5Ctau%2C%5Cgamma%28%5Ctau%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_0-&#92;tau,&#92;gamma(&#92;tau))' title='(t_0-&#92;tau,&#92;gamma(&#92;tau))' class='latex' />.  Applying (11) and then exponentiating we obtain the Harnack inequality</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+u%28t_1%2Cx_1%29+%5Cleq+%5Cexp%28+%5Cfrac%7B1%7D%7B4%7D+%5Cint_0%5E%7B%5Ctau_1%7D+%26%23124%3BX%26%23124%3B%5E2%5C+d%5Ctau+%29+u%28t_0%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle u(t_1,x_1) &#92;leq &#92;exp( &#92;frac{1}{4} &#92;int_0^{&#92;tau_1} &#124;X&#124;^2&#92; d&#92;tau ) u(t_0,x_0)' title='&#92;displaystyle u(t_1,x_1) &#92;leq &#92;exp( &#92;frac{1}{4} &#92;int_0^{&#92;tau_1} &#124;X&#124;^2&#92; d&#92;tau ) u(t_0,x_0)' class='latex' /> (13)</p>
<p style="text-align:left;">which can be extended from strictly positive solutions u to non-negative solutions u by the epsilon-regularisation trick.  (Observe the similarity here with the <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-geodesic theory from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/09/285g-lecture-10-variation-of-l-geodesics-and-monotonicity-of-perelman-reduced-volume/">Lecture 10</a>.) By choosing <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' /> to be the constant-speed minimising geodesic from <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=x_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_1' title='x_1' class='latex' />, we thus conclude that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+u%28t_1%2Cx_1%29+%5Cleq+%5Cexp%28+d%28x_0%2Cx_1%29%5E2%2F4%5Ctau_1+%29+u%28t_0%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle u(t_1,x_1) &#92;leq &#92;exp( d(x_0,x_1)^2/4&#92;tau_1 ) u(t_0,x_0)' title='&#92;displaystyle u(t_1,x_1) &#92;leq &#92;exp( d(x_0,x_1)^2/4&#92;tau_1 ) u(t_0,x_0)' class='latex' />. (14)</p>
<p style="text-align:left;"><strong>Remark 3.</strong> Specialising to the case when u is a static harmonic function and sending <img src='http://s0.wp.com/latex.php?latex=%5Ctau_1+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau_1 &#92;to &#92;infty' title='&#92;tau_1 &#92;to &#92;infty' class='latex' /> (and using Remark 1), we recover a variant of <a href="http://en.wikipedia.org/wiki/Liouville%27s_theorem_%28complex_analysis%29">Liouville&#8217;s theorem</a>: a bounded harmonic function on a Riemannian manifold of bounded non-negative curvature is constant. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;"><strong>Exercise 3.</strong> If the non-negative solution u to (1) is not ancient, but is only restricted to a time interval <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5BT_-%2CT_%2B%5D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[T_-,T_+]' title='{}[T_-,T_+]' class='latex' />, show that one still has the variant</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle++u%28t_1%2Cx_1%29+%5Cleq+%28%5Cfrac%7Bt_2-T_-%7D%7Bt_1-T_-%7D%29%5E%7Bd%2F2%7D+%5Cexp%28+d%28x_0%2Cx_1%29%5E2%2F4%5Ctau_1+%29+u%28t_0%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle  u(t_1,x_1) &#92;leq (&#92;frac{t_2-T_-}{t_1-T_-})^{d/2} &#92;exp( d(x_0,x_1)^2/4&#92;tau_1 ) u(t_0,x_0)' title='&#92;displaystyle  u(t_1,x_1) &#92;leq (&#92;frac{t_2-T_-}{t_1-T_-})^{d/2} &#92;exp( d(x_0,x_1)^2/4&#92;tau_1 ) u(t_0,x_0)' class='latex' />. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /> (15)</p>
<p style="text-align:left;"><strong>Exercise 4. </strong>If the non-negative solution u to (1) is restricted to a time interval <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5BT_-%2CT_%2B%5D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[T_-,T_+]' title='{}[T_-,T_+]' class='latex' />, and one no longer assumes that the Ricci curvature is non-negative (but it will still be bounded, since M is compact), establish the Harnack inequality (3) for some <img src='http://s0.wp.com/latex.php?latex=C%28t_1%2Cx_1%2Ct_0%2Cx_0%2CT_-%2CT_%2B%2CM%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C(t_1,x_1,t_0,x_0,T_-,T_+,M)' title='C(t_1,x_1,t_0,x_0,T_-,T_+,M)' class='latex' />.  (Hint: repeat the above arguments but with F replaced by <img src='http://s0.wp.com/latex.php?latex=F_%5Ckappa+%3A%3D+%5CDelta+f+%2B+%5Ckappa+%26%23124%3B%5Cnabla+f%26%23124%3B%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='F_&#92;kappa := &#92;Delta f + &#92;kappa &#124;&#92;nabla f&#124;^2' title='F_&#92;kappa := &#92;Delta f + &#92;kappa &#124;&#92;nabla f&#124;^2' class='latex' /> for some small <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />.  Show (using (6), (7)) that if <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' /> is small enough, then <img src='http://s0.wp.com/latex.php?latex=F_%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='F_&#92;kappa' title='F_&#92;kappa' class='latex' /> obeys an inequality similar to (9) but with an additional factor of <img src='http://s0.wp.com/latex.php?latex=-O_%5Ckappa%28%26%23124%3BF_%5Ckappa%26%23124%3B%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='-O_&#92;kappa(&#124;F_&#92;kappa&#124;)' title='-O_&#92;kappa(&#124;F_&#92;kappa&#124;)' class='latex' /> on the right-hand side. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;"><strong>Exercise 5.</strong> Establish the <em>strong maximum principle</em>: if M is compact and <img src='http://s0.wp.com/latex.php?latex=u%3A+%5BT_-%2CT_%2B%5D+%5Ctimes+M+%5Cto+%7B%5CBbb+R%7D%5E%2B&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u: [T_-,T_+] &#92;times M &#92;to {&#92;Bbb R}^+' title='u: [T_-,T_+] &#92;times M &#92;to {&#92;Bbb R}^+' class='latex' /> is a non-negative solution to (1) which is not identically zero, then it is strictly positive for times <img src='http://s0.wp.com/latex.php?latex=t+%5Cin+%28T_-%2CT_%2B%5D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;in (T_-,T_+]' title='t &#92;in (T_-,T_+]' class='latex' /> (or equivalently, if u vanishes at even one point in <img src='http://s0.wp.com/latex.php?latex=%28T_-%2CT_%2B%5D+%5Ctimes+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(T_-,T_+] &#92;times M' title='(T_-,T_+] &#92;times M' class='latex' />, then it is identically zero).  <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;"><strong>Exercise 6.</strong> Generalise the strong maximum principle to the case when u is a supersolution <img src='http://s0.wp.com/latex.php?latex=u_t+%5Cgeq+%5CDelta+u&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u_t &#92;geq &#92;Delta u' title='u_t &#92;geq &#92;Delta u' class='latex' /> to the heat equation rather than a solution.  Also generalise it to the case when the metric g is not static, but instead varies smoothly in time.  (For an additional challenge, generalise further to the case when M is complete, the metric has uniformly bounded Riemann curvature, u is bounded, and one also has a drift term <img src='http://s0.wp.com/latex.php?latex=%5Cnabla_X+u&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_X u' title='&#92;nabla_X u' class='latex' /> on the right-hand side of the equation for some bounded X.) <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;"><strong>Exercise 7.</strong> Using the final generalisation of Exercise 6, as well as the evolution equation for scalar curvature (equation (31) of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/03/28/285g-lecture-1-ricci-flow/">Lecture 1</a>), show that the scalar curvature of a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' /> solution is strictly positive at every point in spacetime. (We will prove stronger versions of this fact later in this lecture.) <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;">Further variants and applications of these scalar Harnack inequalities can be found in the <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=834612">paper of Li and Yau</a>.</p>
<p style="text-align:center;">&#8211; Parabolic Harnack inequalities for the Ricci flow &#8211;</p>
<p style="text-align:left;">Now we turn from the scalar equation (1) to the Ricci flow equation (2), which one could think of as a kind of tensor-valued quasilinear heat equation (by de Turck&#8217;s trick, see <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/03/28/285g-lecture-1-ricci-flow/">Lecture 1</a>).  To begin with let us first consider the simple two-dimensional case d=2.  In this case the Bianchi identities make the Riemann, Ricci, and scalar curvatures are all essentially equivalent (see <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/03/26/285g-lecture-0-riemannian-manifolds-and-curvature/">Lecture 0</a>); in particular one has the identity</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRic%7D+%3D+%5Cfrac%7B1%7D%7B2%7D+R+g&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Ric} = &#92;frac{1}{2} R g' title='&#92;hbox{Ric} = &#92;frac{1}{2} R g' class='latex' /> (16)</p>
<p style="text-align:left;">in the two-dimensional case. In particular, the heat equation for scalar curvature (equation (31) from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/03/28/285g-lecture-1-ricci-flow/">Lecture 1</a>) simplifies to</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+R+%3D+%5CDelta+R+%2B+R%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t R = &#92;Delta R + R^2' title='&#92;partial_t R = &#92;Delta R + R^2' class='latex' /> (17)</p>
<p style="text-align:left;">in this case; compare this with (1).</p>
<p style="text-align:left;">Suppose that the scalar curvature R is strictly positive.  Setting <img src='http://s0.wp.com/latex.php?latex=f+%3A%3D+%5Clog+R&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='f := &#92;log R' title='f := &#92;log R' class='latex' />, one has an analogue of (5):</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+f+%3D+%5CDelta+f+%2B+%5Cnabla_f+f+%2B+R&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t f = &#92;Delta f + &#92;nabla_f f + R' title='&#92;partial_t f = &#92;Delta f + &#92;nabla_f f + R' class='latex' />. (18)</p>
<p style="text-align:left;"><strong>Exercise 8.</strong> If we set <img src='http://s0.wp.com/latex.php?latex=F+%3A%3D++%5Cpartial_t+f+-+%5Cnabla_f+f+%3D+%5CDelta+f+%2B+R&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='F :=  &#92;partial_t f - &#92;nabla_f f = &#92;Delta f + R' title='F :=  &#92;partial_t f - &#92;nabla_f f = &#92;Delta f + R' class='latex' />, show the following analogue of (9):</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+F+%5Cgeq+%5CDelta+F+%2B+2+%5Cnabla_%7B%5Cnabla+f%7D+F+%2B+F%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t F &#92;geq &#92;Delta F + 2 &#92;nabla_{&#92;nabla f} F + F^2' title='&#92;partial_t F &#92;geq &#92;Delta F + 2 &#92;nabla_{&#92;nabla f} F + F^2' class='latex' />. (19)</p>
<p style="text-align:left;">[Hint: you will need to first derive the identity <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+%5CDelta+v+%3D+%5CDelta+%5Cpartial_t+v+%2B+R+%5CDelta+v&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t &#92;Delta v = &#92;Delta &#92;partial_t v + R &#92;Delta v' title='&#92;partial_t &#92;Delta v = &#92;Delta &#92;partial_t v + R &#92;Delta v' class='latex' /> for arbitrary smooth v.]  Conclude that if M is compact and R is strictly positive on the time interval <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5BT_-%2CT_%2B%5D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[T_-,T_+]' title='{}[T_-,T_+]' class='latex' />, then <img src='http://s0.wp.com/latex.php?latex=F+%5Cgeq+-1%2F%28t-T_-%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='F &#92;geq -1/(t-T_-)' title='F &#92;geq -1/(t-T_-)' class='latex' />, and thus conclude <em>Hamilton&#8217;s Harnack inequality for surfaces</em>:</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cpartial_t+R+-+%5Cfrac%7B%26%23124%3B%5Cnabla+R%26%23124%3B_g%5E2%7D%7BR%7D+%2B+%5Cfrac%7BR%7D%7Bt-T_-%7D+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;partial_t R - &#92;frac{&#124;&#92;nabla R&#124;_g^2}{R} + &#92;frac{R}{t-T_-} &#92;geq 0' title='&#92;displaystyle &#92;partial_t R - &#92;frac{&#124;&#92;nabla R&#124;_g^2}{R} + &#92;frac{R}{t-T_-} &#92;geq 0' class='latex' />.  (20)</p>
<p style="text-align:left;">Extend this inequality to the case when R is merely non-negative rather than strictly positive by setting f equal to <img src='http://s0.wp.com/latex.php?latex=%5Clog%28R%2B%5Cvarepsilon%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;log(R+&#92;varepsilon)' title='&#92;log(R+&#92;varepsilon)' class='latex' /> rather than <img src='http://s0.wp.com/latex.php?latex=%5Clog+R&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;log R' title='&#92;log R' class='latex' /> and then setting <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' /> to zero (this is how should performs the epsilon regularisation trick for Ricci flow, by modifying the logarithm function by an epsilon, rather than the solution).  <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>For ancient two-dimensional solutions with non-negative curvature, we thus conclude from the Harnack inequality (20) that R (and <img src='http://s0.wp.com/latex.php?latex=f+%3D+%5Clog+R&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='f = &#92;log R' title='f = &#92;log R' class='latex' />) obeys the same bounds (10), (10&#8242;), (11) that scalar solutions u did previously.  In particular R is non-decreasing in time, and more generally</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cpartial_t+R+-+%5Cnabla_X+R+%2B+%5Cfrac%7B1%7D%7B4%7D+%26%23124%3BX%26%23124%3B_g%5E2+R+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;partial_t R - &#92;nabla_X R + &#92;frac{1}{4} &#124;X&#124;_g^2 R &#92;geq 0' title='&#92;displaystyle &#92;partial_t R - &#92;nabla_X R + &#92;frac{1}{4} &#124;X&#124;_g^2 R &#92;geq 0' class='latex' /> (21)</p>
<p>for any X.  We can also obtain an analogue of (13).  Also, observe from the assumption of non-negative curvature and (2) that the metric is non-increasing with time, and so we can also deduce an analogue of (14):</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+R%28t_1%2Cx_1%29+%5Cleq+%5Cexp%28+d_%7Bg%28t_1%29%7D%28x_0%2Cx_1%29%5E2%2F4%5Ctau_1+%29+R%28t_0%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle R(t_1,x_1) &#92;leq &#92;exp( d_{g(t_1)}(x_0,x_1)^2/4&#92;tau_1 ) R(t_0,x_0)' title='&#92;displaystyle R(t_1,x_1) &#92;leq &#92;exp( d_{g(t_1)}(x_0,x_1)^2/4&#92;tau_1 ) R(t_0,x_0)' class='latex' />. (22)</p>
<p style="text-align:left;">With a non-trivial amount of effort, one can extend Hamilton&#8217;s Harnack inequality to higher dimensions.  One cannot argue solely using the scalar curvature R, because the equation <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+R+%3D+%5CDelta+R+%2B+2+%26%23124%3B%5Chbox%7BRic%7D%26%23124%3B%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t R = &#92;Delta R + 2 &#124;&#92;hbox{Ric}&#124;^2' title='&#92;partial_t R = &#92;Delta R + 2 &#124;&#92;hbox{Ric}&#124;^2' class='latex' /> for that curvature also involves the Ricci tensor, which thus also needs to be controlled.  What is worse, one cannot argue solely using the Ricci tensor either, because the equation</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+%5Chbox%7BRic%7D_%7B%5Calpha+%5Cbeta%7D+%3D+%5CDelta+%5Chbox%7BRic%7D_%7B%5Calpha+%5Cbeta%7D+%2B+2+%5Chbox%7BRic%7D%5E%5Cgamma_%5Cdelta+%5Chbox%7BRiem%7D%5E%5Cdelta_%7B%5Calpha+%5Cgamma+%5Cbeta%7D+-+2+%5Chbox%7BRic%7D_%7B%5Calpha+%5Cgamma%7D+%5Chbox%7BRic%7D%5E%5Cgamma_%5Cbeta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t &#92;hbox{Ric}_{&#92;alpha &#92;beta} = &#92;Delta &#92;hbox{Ric}_{&#92;alpha &#92;beta} + 2 &#92;hbox{Ric}^&#92;gamma_&#92;delta &#92;hbox{Riem}^&#92;delta_{&#92;alpha &#92;gamma &#92;beta} - 2 &#92;hbox{Ric}_{&#92;alpha &#92;gamma} &#92;hbox{Ric}^&#92;gamma_&#92;beta' title='&#92;partial_t &#92;hbox{Ric}_{&#92;alpha &#92;beta} = &#92;Delta &#92;hbox{Ric}_{&#92;alpha &#92;beta} + 2 &#92;hbox{Ric}^&#92;gamma_&#92;delta &#92;hbox{Riem}^&#92;delta_{&#92;alpha &#92;gamma &#92;beta} - 2 &#92;hbox{Ric}_{&#92;alpha &#92;gamma} &#92;hbox{Ric}^&#92;gamma_&#92;beta' class='latex' /> (23)</p>
<p style="text-align:left;">for the evolution of that curvature involves the Riemann tensor.  To proceed, one in fact has to deal with the equation for the full Riemann tensor,</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+%5Chbox%7BRiem%7D+%3D+%5CDelta+%5Chbox%7BRiem%7D+%2B+%7B%5Cmathcal+O%7D%28g%5E%7B-1%7D+%5Chbox%7BRiem%7D%5E2+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t &#92;hbox{Riem} = &#92;Delta &#92;hbox{Riem} + {&#92;mathcal O}(g^{-1} &#92;hbox{Riem}^2 )' title='&#92;partial_t &#92;hbox{Riem} = &#92;Delta &#92;hbox{Riem} + {&#92;mathcal O}(g^{-1} &#92;hbox{Riem}^2 )' class='latex' /> (24)</p>
<p style="text-align:left;">where <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+O%7D%28g%5E%7B-1%7D+%5Chbox%7BRiem%7D%5E2+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal O}(g^{-1} &#92;hbox{Riem}^2 )' title='{&#92;mathcal O}(g^{-1} &#92;hbox{Riem}^2 )' class='latex' /> is an explicit but rather complicated quadratic expression in the Riemann curvature.  This expression simplifies when using a moving orthonormal frame, as was done in Lecture 3, to the form</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+%7B%5Cmathcal+T%7D+%3D+%5CDelta+%7B%5Cmathcal+T%7D+%2B+%7B%5Cmathcal+T%7D%5E2+%2B+%7B%5Cmathcal+T%7D%5E%5C%23&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t {&#92;mathcal T} = &#92;Delta {&#92;mathcal T} + {&#92;mathcal T}^2 + {&#92;mathcal T}^&#92;#' title='&#92;partial_t {&#92;mathcal T} = &#92;Delta {&#92;mathcal T} + {&#92;mathcal T}^2 + {&#92;mathcal T}^&#92;#' class='latex' />. (25)</p>
<p style="text-align:left;">By using (25) and many tensor calculations, one can (eventually) establish a (rather complicated) analogue of the  (21) for <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+T%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal T}' title='{&#92;mathcal T}' class='latex' />, and hence for <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRiem%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Riem}' title='&#92;hbox{Riem}' class='latex' /> and then (after taking some traces) to R.  In particular, we have</p>
<blockquote>
<p style="text-align:left;"><strong>Theorem 1.</strong> (Hamilton&#8217;s Harnack inequality for ancient Ricci flows) Let <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> be a complete ancient Ricci flow with non-negative bounded Riemann curvature.  (In particular, all <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions are of this form.) Then we have the pointwise inequality</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+R+-+%5Cnabla_X+R+%2B+%5Cfrac%7B1%7D%7B2%7D+%5Chbox%7BRic%7D%28X%2CX%29+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t R - &#92;nabla_X R + &#92;frac{1}{2} &#92;hbox{Ric}(X,X) &#92;geq 0' title='&#92;partial_t R - &#92;nabla_X R + &#92;frac{1}{2} &#92;hbox{Ric}(X,X) &#92;geq 0' class='latex' /> (26)</p>
<p style="text-align:left;">for any vector field X.</p>
</blockquote>
<p>Note that in the two-dimensional case, (26) collapses to (23) thanks to (16).</p>
<p>The proof of (26) is remarkably delicate (in particular, going through the tensor curvature equation (25)), but ultimately follows broadly similar lines to the previous arguments (i.e. Bochner-type identities, Cauchy-Schwarz type inequalities, and tensor maximum principles).  For technical reasons it is also convenient to carry auxiliary tensor fields such as the vector field X appearing in (26) throughout the argument.  We refer the reader to <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=1198607">Hamilton&#8217;s original paper</a> for details. (There are alternate proofs, such as the one by <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=1362964">Chow and Chu</a> using a metric closely related to the high-dimensional metrics considered in <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/27/285g-lecture-9-comparison-geometry-the-high-dimensional-limit-and-perelman-reduced-volume/">Lecture 9</a>, but all of the proofs I know of require a significant amount of calculation.)</p>
<p><strong>Exercise 9.</strong> Suppose that <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g)' title='(M,g)' class='latex' /> solves the gradient steady soliton equation <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRic%7D+%2B+%5Chbox%7BHess%7D%28f%29+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Ric} + &#92;hbox{Hess}(f) = 0' title='&#92;hbox{Ric} + &#92;hbox{Hess}(f) = 0' class='latex' /> for some smooth f.  Using the Bianchi identity <img src='http://s0.wp.com/latex.php?latex=%5Cnabla_%5Calpha+R+%3D+2+%5Cnabla%5E%5Cbeta+%5Chbox%7BRic%7D_%7B%5Calpha%5Cbeta%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_&#92;alpha R = 2 &#92;nabla^&#92;beta &#92;hbox{Ric}_{&#92;alpha&#92;beta}' title='&#92;nabla_&#92;alpha R = 2 &#92;nabla^&#92;beta &#92;hbox{Ric}_{&#92;alpha&#92;beta}' class='latex' />, establish the identity</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cnabla_%5Calpha+R+%3D+2%5Chbox%7BRic%7D_%7B%5Calpha+%5Cbeta%7D+%5Cnabla%5E%5Cbeta+f&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_&#92;alpha R = 2&#92;hbox{Ric}_{&#92;alpha &#92;beta} &#92;nabla^&#92;beta f' title='&#92;nabla_&#92;alpha R = 2&#92;hbox{Ric}_{&#92;alpha &#92;beta} &#92;nabla^&#92;beta f' class='latex' /> (27)</p>
<p>(note this identity also holds for gradient shrinking or expanding solitons) and then by taking divergences and using the Bianchi identity again, establish that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5CDelta+R+%2B+2+%26%23124%3B%5Chbox%7BRic%7D%26%23124%3B%5E2+%3D+%5Cnabla_%5Calpha+R+%5Cnabla%5E%5Calpha+f&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Delta R + 2 &#124;&#92;hbox{Ric}&#124;^2 = &#92;nabla_&#92;alpha R &#92;nabla^&#92;alpha f' title='&#92;Delta R + 2 &#124;&#92;hbox{Ric}&#124;^2 = &#92;nabla_&#92;alpha R &#92;nabla^&#92;alpha f' class='latex' />. (28)</p>
<p>Conclude that (26) is an identity in this case when one sets <img src='http://s0.wp.com/latex.php?latex=X%5E%5Calpha+%3A%3D+2+%5Cnabla%5E%5Calpha+f&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='X^&#92;alpha := 2 &#92;nabla^&#92;alpha f' title='X^&#92;alpha := 2 &#92;nabla^&#92;alpha f' class='latex' />. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:center;">&#8211; Applications of the Harnack inequality &#8211;</p>
<p>Now we develop some applications of the Harnack inequality for <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions.  One easy application follows by setting X equal to 0, giving<br />
the pointwise monotonicity of the scalar curvature in time:</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+R+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t R &#92;geq 0' title='&#92;partial_t R &#92;geq 0' class='latex' />. (29)</p>
<p>Another application is to obtain a slightly weakened version of (22) (with the 4 in the denominator replaced by 2):</p>
<p><strong>Exercise 10.</strong> Show that one has <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRic%7D%28X%2CX%29+%5Cleq+%5Cfrac%7B1%7D%7B2%7D+R+%26%23124%3BX%26%23124%3B%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Ric}(X,X) &#92;leq &#92;frac{1}{2} R &#124;X&#124;^2' title='&#92;hbox{Ric}(X,X) &#92;leq &#92;frac{1}{2} R &#124;X&#124;^2' class='latex' /> whenever one has non-negative Riemann curvature.  Using this and (26), show that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+R%28t_1%2Cx_1%29+%5Cleq+%5Cexp%28+d_%7Bg%28t_1%29%7D%28x_0%2Cx_1%29%5E2%2F2%5Ctau_1+%29+R%28t_0%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle R(t_1,x_1) &#92;leq &#92;exp( d_{g(t_1)}(x_0,x_1)^2/2&#92;tau_1 ) R(t_0,x_0)' title='&#92;displaystyle R(t_1,x_1) &#92;leq &#92;exp( d_{g(t_1)}(x_0,x_1)^2/2&#92;tau_1 ) R(t_0,x_0)' class='latex' />. (30)</p>
<p>for all <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions and all spacetime points <img src='http://s0.wp.com/latex.php?latex=%28t_0%2Cx_0%29%2C+%28t_1%2Cx_1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_0,x_0), (t_1,x_1)' title='(t_0,x_0), (t_1,x_1)' class='latex' /> with <img src='http://s0.wp.com/latex.php?latex=t_1+%26%2360%3B+t_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_1 &lt; t_0' title='t_1 &lt; t_0' class='latex' />. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>Now we use the Harnack inequality to obtain some further control on the reduced length function <img src='http://s0.wp.com/latex.php?latex=l_%7B%28t_0%2Cx_0%29%7D%28t_1%2Cx_1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_{(t_0,x_0)}(t_1,x_1)' title='l_{(t_0,x_0)}(t_1,x_1)' class='latex' />.  Recall that this quantity takes the form</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+l_%7B%28t_0%2Cx_0%29%7D%28t_1%2Cx_1%29+%3D+%5Cfrac%7B1%7D%7B%5Csqrt%7B2%5Ctau_1%7D%7D+%5Cint_0%5E%7B%5Ctau_1%7D+%5Csqrt%7B%5Ctau%7D+%28+%26%23124%3BX%26%23124%3B_g%5E2+%2B+R%29%5C+d%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle l_{(t_0,x_0)}(t_1,x_1) = &#92;frac{1}{&#92;sqrt{2&#92;tau_1}} &#92;int_0^{&#92;tau_1} &#92;sqrt{&#92;tau} ( &#124;X&#124;_g^2 + R)&#92; d&#92;tau' title='&#92;displaystyle l_{(t_0,x_0)}(t_1,x_1) = &#92;frac{1}{&#92;sqrt{2&#92;tau_1}} &#92;int_0^{&#92;tau_1} &#92;sqrt{&#92;tau} ( &#124;X&#124;_g^2 + R)&#92; d&#92;tau' class='latex' /> (31)</p>
<p>where <img src='http://s0.wp.com/latex.php?latex=X+%3A%3D+%5Cgamma%27&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='X := &#92;gamma&#039;' title='X := &#92;gamma&#039;' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%3A+%5B0%2C%5Ctau_1%5D+%5Cto+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma: [0,&#92;tau_1] &#92;to M' title='&#92;gamma: [0,&#92;tau_1] &#92;to M' class='latex' /> is a minimising <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-geodesic, which in particular means that it obeys the <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-geodesic equation</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cnabla_X+X+-+%5Cfrac%7B1%7D%7B2%7D+%5Cnabla_X+R+%2B%5Cfrac%7B1%7D%7B2%5Ctau%7D+X+%2B+2+%5Chbox%7BRic%7D%28X%2C%5Ccdot%29%5E%2A+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;nabla_X X - &#92;frac{1}{2} &#92;nabla_X R +&#92;frac{1}{2&#92;tau} X + 2 &#92;hbox{Ric}(X,&#92;cdot)^* = 0' title='&#92;displaystyle &#92;nabla_X X - &#92;frac{1}{2} &#92;nabla_X R +&#92;frac{1}{2&#92;tau} X + 2 &#92;hbox{Ric}(X,&#92;cdot)^* = 0' class='latex' /> (32)</p>
<p>(see equation (27) from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/09/285g-lecture-10-variation-of-l-geodesics-and-monotonicity-of-perelman-reduced-volume/">Lecture 10</a>).  Using (32) and the chain rule, we can compute the <a href="http://en.wikipedia.org/wiki/Total_derivative">total derivative</a> <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bd%7D%7Bd%5Ctau%7D+%26%23124%3BX%26%23124%3B%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{d}{d&#92;tau} &#124;X&#124;^2' title='&#92;frac{d}{d&#92;tau} &#124;X&#124;^2' class='latex' /> along the path <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' /><br />
as</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bd%7D%7Bd%5Ctau%7D+%26%23124%3BX%26%23124%3B%5E2+%3D+%5Cnabla_X+R+-+%5Cfrac%7B1%7D%7B%5Ctau%7D+%26%23124%3BX%26%23124%3B%5E2+-+2+%5Chbox%7BRic%7D%28X%2CX%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{d}{d&#92;tau} &#124;X&#124;^2 = &#92;nabla_X R - &#92;frac{1}{&#92;tau} &#124;X&#124;^2 - 2 &#92;hbox{Ric}(X,X)' title='&#92;frac{d}{d&#92;tau} &#124;X&#124;^2 = &#92;nabla_X R - &#92;frac{1}{&#92;tau} &#124;X&#124;^2 - 2 &#92;hbox{Ric}(X,X)' class='latex' />. (33)</p>
<p>On the other hand, the Harnack inequality (26) (with X replaced by 2X) lets us bound the total derivative of R:</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bd%7D%7Bd%5Ctau%7D+R+%5Cleq+-+%5Cnabla_X+R+%2B+2+%5Chbox%7BRic%7D%28X%2CX%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{d}{d&#92;tau} R &#92;leq - &#92;nabla_X R + 2 &#92;hbox{Ric}(X,X)' title='&#92;frac{d}{d&#92;tau} R &#92;leq - &#92;nabla_X R + 2 &#92;hbox{Ric}(X,X)' class='latex' />. (34)</p>
<p>We add (33) and (34) and rearrange to obtain</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bd%5Ctau%7D+%5B%5Ctau%5E%7B3%2F2%7D+%28%26%23124%3BX%26%23124%3B%5E2%2BR%29%5D+%5Cleq+%5Cfrac%7B3%7D%7B2%7D+%5Csqrt%7B%5Ctau%7D+%28%26%23124%3BX%26%23124%3B%5E2%2BR%29+-+%5Ctau%5E%7B1%2F2%7D+%26%23124%3BX%26%23124%3B%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{d&#92;tau} [&#92;tau^{3/2} (&#124;X&#124;^2+R)] &#92;leq &#92;frac{3}{2} &#92;sqrt{&#92;tau} (&#124;X&#124;^2+R) - &#92;tau^{1/2} &#124;X&#124;^2' title='&#92;displaystyle &#92;frac{d}{d&#92;tau} [&#92;tau^{3/2} (&#124;X&#124;^2+R)] &#92;leq &#92;frac{3}{2} &#92;sqrt{&#92;tau} (&#124;X&#124;^2+R) - &#92;tau^{1/2} &#124;X&#124;^2' class='latex' />. (35)</p>
<p>We (somewhat crudely) discard the non-negative <img src='http://s0.wp.com/latex.php?latex=%5Ctau%5E%7B1%2F2%7D+%26%23124%3BX%26%23124%3B%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau^{1/2} &#124;X&#124;^2' title='&#92;tau^{1/2} &#124;X&#124;^2' class='latex' /> term and integrate in <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' /> using (31) to obtain</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Ctau_1%5E%7B3%2F2%7D+%28%26%23124%3BX%28%5Ctau_1%29%26%23124%3B%5E2%2BR%29+%5Cleq+%5Cfrac%7B3%7D%7B2%7D+2%5Ctau%5E%7B1%2F2%7D+l%28t_1%2Cx_1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;tau_1^{3/2} (&#124;X(&#92;tau_1)&#124;^2+R) &#92;leq &#92;frac{3}{2} 2&#92;tau^{1/2} l(t_1,x_1)' title='&#92;displaystyle &#92;tau_1^{3/2} (&#124;X(&#92;tau_1)&#124;^2+R) &#92;leq &#92;frac{3}{2} 2&#92;tau^{1/2} l(t_1,x_1)' class='latex' /> (36)</p>
<p>where we abbreviate <img src='http://s0.wp.com/latex.php?latex=l_%7B%28t_0%2Cx_0%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_{(t_0,x_0)}' title='l_{(t_0,x_0)}' class='latex' /> as l. Using the first variation formulae for reduced length (see equations (14), (15) from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/14/285g-lecture-11-%ce%ba-noncollapsing-via-perelman-reduced-volume/">Lecture 11</a>), as well as the nonnegativity of R (and hence of l), we obtain the useful inequalities</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+0+%5Cleq+%26%23124%3B%5Cnabla+l%26%23124%3B%5E2+%2B+R+%5Cleq+%5Cfrac%7B3l%7D%7B%5Ctau%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle 0 &#92;leq &#124;&#92;nabla l&#124;^2 + R &#92;leq &#92;frac{3l}{&#92;tau}' title='&#92;displaystyle 0 &#92;leq &#124;&#92;nabla l&#124;^2 + R &#92;leq &#92;frac{3l}{&#92;tau}' class='latex' /> (37)</p>
<p>and</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+-%5Cfrac%7B2l%7D%7B%5Ctau%7D+%5Cleq+%5Cpartial_%5Ctau+l+%5Cleq+%5Cfrac%7Bl%7D%7B%5Ctau%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle -&#92;frac{2l}{&#92;tau} &#92;leq &#92;partial_&#92;tau l &#92;leq &#92;frac{l}{&#92;tau}' title='&#92;displaystyle -&#92;frac{2l}{&#92;tau} &#92;leq &#92;partial_&#92;tau l &#92;leq &#92;frac{l}{&#92;tau}' class='latex' />. (38)</p>
<p>Informally, this means that at any given point <img src='http://s0.wp.com/latex.php?latex=%28t_1%2Cx_1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_1,x_1)' title='(t_1,x_1)' class='latex' /> to the past of <img src='http://s0.wp.com/latex.php?latex=%28t_0%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_0,x_0)' title='(t_0,x_0)' class='latex' />, l is roughly constant at spatial scales <img src='http://s0.wp.com/latex.php?latex=%5Csqrt%7B%5Ctau%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;sqrt{&#92;tau}' title='&#92;sqrt{&#92;tau}' class='latex' /> and at temporal scales <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' />.  Furthermore, if l is bounded, then one has bounded normalised curvature at such scales.</p>
<p style="text-align:center;">&#8211; A splitting theorem &#8211;</p>
<p>Our final application of these ideas (or more precisely, of the strong maximum principle) will be to establish a dichotomy (due <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=862046">to Hamilton</a>) for 3-dimensional <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions: either their Ricci curvature is strictly positive, or the solution splits locally as the product of a line with a two-dimensional solution.</p>
<blockquote><p><strong>Proposition 1. </strong> Let <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> be a three-dimensional <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution.  Suppose that the Ricci tensor has a zero eigenvalue at some point <img src='http://s0.wp.com/latex.php?latex=%28t_0%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_0,x_0)' title='(t_0,x_0)' class='latex' />.  Then on the slab <img src='http://s0.wp.com/latex.php?latex=%28-%5Cinfty%2Ct_0%29+%5Ctimes+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(-&#92;infty,t_0) &#92;times M' title='(-&#92;infty,t_0) &#92;times M' class='latex' />, the Ricci flow locally splits as the product of a two-dimensional Ricci flow and a line.</p></blockquote>
<p><strong>Proof.</strong> The first stage is to show that the Ricci tensor has a zero eigenvalue on all of<br />
<img src='http://s0.wp.com/latex.php?latex=%28-%5Cinfty%2Ct_0%29+%5Ctimes+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(-&#92;infty,t_0) &#92;times M' title='(-&#92;infty,t_0) &#92;times M' class='latex' />.  Let <img src='http://s0.wp.com/latex.php?latex=0+%5Cleq+%5Cnu+%5Cleq+%5Cmu+%5Cleq+%5Clambda&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &#92;leq &#92;nu &#92;leq &#92;mu &#92;leq &#92;lambda' title='0 &#92;leq &#92;nu &#92;leq &#92;mu &#92;leq &#92;lambda' class='latex' /> denote the three eigenvalues of the Riemann tensor <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+T%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal T}' title='{&#92;mathcal T}' class='latex' /> as viewed in an orthonormal frame (as in <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/04/285g-lecture-3-the-maximum-principle-and-the-pinching-phenomenon/">Lecture 3</a>), thus a zero eigenvalue of the Ricci tensor is equivalent to <img src='http://s0.wp.com/latex.php?latex=%5Cnu%2B%5Cmu%3D0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nu+&#92;mu=0' title='&#92;nu+&#92;mu=0' class='latex' />.   Suppose for contradiction that at some time <img src='http://s0.wp.com/latex.php?latex=t_1+%26%2360%3B+t_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_1 &lt; t_0' title='t_1 &lt; t_0' class='latex' />, this quantity is not identically zero, thus we can find some non-negative scalar function <img src='http://s0.wp.com/latex.php?latex=h%28t_1%2C%5Ccdot%29%3A+M+%5Cto+%7B%5CBbb+R%7D%5E%2B&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='h(t_1,&#92;cdot): M &#92;to {&#92;Bbb R}^+' title='h(t_1,&#92;cdot): M &#92;to {&#92;Bbb R}^+' class='latex' />, not<br />
identically zero, such that <img src='http://s0.wp.com/latex.php?latex=%5Cnu%2B%5Cmu+%5Cgeq+h&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nu+&#92;mu &#92;geq h' title='&#92;nu+&#92;mu &#92;geq h' class='latex' /> at time <img src='http://s0.wp.com/latex.php?latex=t_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_1' title='t_1' class='latex' />.  We then extend h by the heat equation, so by the strong maximum principle h is strictly positive for all times after <img src='http://s0.wp.com/latex.php?latex=t_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_1' title='t_1' class='latex' />.  From the convexity of the functional <img src='http://s0.wp.com/latex.php?latex=%5Cnu%2B%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nu+&#92;mu' title='&#92;nu+&#92;mu' class='latex' /> (which one can view as the minimal trace of <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+T%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal T}' title='{&#92;mathcal T}' class='latex' /> over two-dimensional subspaces), we see that the set <img src='http://s0.wp.com/latex.php?latex=%5C%7B+%28%7B%5Cmathcal+T%7D%2Ch%29%3A+%5Cnu%2B%5Cmu+%5Cgeq+h+%5C%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;{ ({&#92;mathcal T},h): &#92;nu+&#92;mu &#92;geq h &#92;}' title='&#92;{ ({&#92;mathcal T},h): &#92;nu+&#92;mu &#92;geq h &#92;}' class='latex' /> cuts out a fibrewise convex parallel subset of a suitable vector bundle over <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5Bt_1%2Ct_0%5D+%5Ctimes+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[t_1,t_0] &#92;times M' title='{}[t_1,t_0] &#92;times M' class='latex' /> (in the sense of the tensor maximum principle, Proposition 1 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/04/285g-lecture-3-the-maximum-principle-and-the-pinching-phenomenon/">Lecture 3</a>), which one can easily check to be preserved under the ODE associated to the simultaneous evolution of (25) and the scalar heat equation for h.<br />
Applying the tensor maximum principle we conclude that <img src='http://s0.wp.com/latex.php?latex=%5Cnu%2B%5Cmu+%5Cgeq+h&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nu+&#92;mu &#92;geq h' title='&#92;nu+&#92;mu &#92;geq h' class='latex' /> for all times in <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5Bt_1%2Ct_0%5D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[t_1,t_0]' title='{}[t_1,t_0]' class='latex' />, and in particular that <img src='http://s0.wp.com/latex.php?latex=%5Cnu%2B%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nu+&#92;mu' title='&#92;nu+&#92;mu' class='latex' /> is non-zero at <img src='http://s0.wp.com/latex.php?latex=%28t_0%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_0,x_0)' title='(t_0,x_0)' class='latex' />, a contradiction.  Thus the Ricci curvature must have a zero eigenvalue on all of <img src='http://s0.wp.com/latex.php?latex=%28-%5Cinfty%2Ct_0%29+%5Ctimes+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(-&#92;infty,t_0) &#92;times M' title='(-&#92;infty,t_0) &#92;times M' class='latex' />, thus <img src='http://s0.wp.com/latex.php?latex=%5Cnu%3D%5Cmu%3D0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nu=&#92;mu=0' title='&#92;nu=&#92;mu=0' class='latex' /> on this slab.  On the other hand, from Exercise 7 we must have <img src='http://s0.wp.com/latex.php?latex=%5Clambda+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;lambda &gt; 0' title='&#92;lambda &gt; 0' class='latex' /> throughout this slab.</p>
<p>The symmetric rank 2 tensor <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+T%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal T}' title='{&#92;mathcal T}' class='latex' /> thus has rank 1 at every point, and thus locally can be expressed in the form <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+T%7D+%3D+a+v+%5Cotimes+v&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal T} = a v &#92;otimes v' title='{&#92;mathcal T} = a v &#92;otimes v' class='latex' /> for some smooth non-zero scalar a and a unit vector field v.  (If M was orientable, one could extend this vector field to be global).  The equation (25) then becomes</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=a_t+v+%5Cotimes+v+%2B+a+v+%5Cotimes+v_t+%2B+a+v_t+%5Cotimes+v+%3D+%28%5CDelta+a+%2B+a%5E2%29+v+%5Cotimes+v+&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='a_t v &#92;otimes v + a v &#92;otimes v_t + a v_t &#92;otimes v = (&#92;Delta a + a^2) v &#92;otimes v ' title='a_t v &#92;otimes v + a v &#92;otimes v_t + a v_t &#92;otimes v = (&#92;Delta a + a^2) v &#92;otimes v ' class='latex' /></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%2B+%28%5Cnabla%5E%5Calpha+a%29+%28v+%5Cotimes+%5Cnabla_%5Calpha+v+%2B+%5Cnabla_%5Calpha+v+%5Cotimes+v%29+%2B+2a+%5Cnabla_%5Calpha+v+%5Cotimes+%5Cnabla%5E%5Calpha+v&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='+ (&#92;nabla^&#92;alpha a) (v &#92;otimes &#92;nabla_&#92;alpha v + &#92;nabla_&#92;alpha v &#92;otimes v) + 2a &#92;nabla_&#92;alpha v &#92;otimes &#92;nabla^&#92;alpha v' title='+ (&#92;nabla^&#92;alpha a) (v &#92;otimes &#92;nabla_&#92;alpha v + &#92;nabla_&#92;alpha v &#92;otimes v) + 2a &#92;nabla_&#92;alpha v &#92;otimes &#92;nabla^&#92;alpha v' class='latex' />. (39)</p>
<p>Since v is a unit vector field, the vector fields <img src='http://s0.wp.com/latex.php?latex=%5Cnabla_X+v&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_X v' title='&#92;nabla_X v' class='latex' /> are orthogonal to v for every v.  Thus we can restrict to the component of (39) that is completely orthogonal to v, and conclude (since a is nonzero) that <img src='http://s0.wp.com/latex.php?latex=%5Cnabla_%5Calpha+v+%5Cotimes+%5Cnabla%5E%5Calpha+v+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_&#92;alpha v &#92;otimes &#92;nabla^&#92;alpha v = 0' title='&#92;nabla_&#92;alpha v &#92;otimes &#92;nabla^&#92;alpha v = 0' class='latex' />.  If we then inspect the component of (39) which is partially orthogonal to v, we also learn that <img src='http://s0.wp.com/latex.php?latex=v_t+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='v_t = 0' title='v_t = 0' class='latex' />.  Expressing the left-hand side in an orthonormal basis as the sum of rank one positive semi-definite matrices, we easily conclude that <img src='http://s0.wp.com/latex.php?latex=%5Cnabla_%5Calpha+v+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_&#92;alpha v = 0' title='&#92;nabla_&#92;alpha v = 0' class='latex' />, i.e. v is parallel to the connection.  This implies that the dual one-form <img src='http://s0.wp.com/latex.php?latex=v%5E%2A+%5Cin+%5CGamma%28T%5E%2A+M%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='v^* &#92;in &#92;Gamma(T^* M)' title='v^* &#92;in &#92;Gamma(T^* M)' class='latex' /> is closed and hence locally exact; thus v is locally the gradient of some potential function f.  From this we easily see that the flow locally splits as the product of a two-dimensional flow (on a level set of f) and a line (the flow lines of v), and then it is easy to verify that the two-dimensional flow is a Ricci flow, as claimed. <img src='http://s0.wp.com/latex.php?latex=%5CBox&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Box' title='&#92;Box' class='latex' /></p>
<p><strong>Remark 4</strong>.  One cannot always extend this local splitting to a global one, due to topological obstructions; consider for instance the oriented round shrinking cylinder quotient (Example 3 of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/16/285g-lecture-12-high-curvature-regions-of-ricci-flow-and-%ce%ba-solutions/">Lecture 12</a>).   One could also imagine the product of a round shrinking <img src='http://s0.wp.com/latex.php?latex=S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2' title='S^2' class='latex' /> and a static circle <img src='http://s0.wp.com/latex.php?latex=S%5E1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^1' title='S^1' class='latex' />, in which the null eigenvector of the Ricci tensor splits off as a circle rather than a line; but this is not a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution because it becomes collapsed at large scales in the distant past.<br />
<img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p><strong>Remark 5.</strong> The above splitting analysis can be carried out in any dimension; for instance, one can show that the rank of the Riemann tensor is a constant for any ancient solution with bounded non-negative Riemann curvature.  For this and further splitting results in this case, see the paper of <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=862046">Hamilton</a>. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
]]></content:encoded>
</item>
<item>
<title><![CDATA[285G, Lecture 12: High curvature regions of Ricci flow and κ-solutions]]></title>
<link>http://terrytao.wordpress.com/2008/05/16/285g-lecture-12-high-curvature-regions-of-ricci-flow-and-%ce%ba-solutions/</link>
<pubDate>Fri, 16 May 2008 18:37:46 +0000</pubDate>
<dc:creator>Terence Tao</dc:creator>
<guid>http://terrytao.wordpress.com/2008/05/16/285g-lecture-12-high-curvature-regions-of-ricci-flow-and-%ce%ba-solutions/</guid>
<description><![CDATA[In previous lectures, we have established (modulo some technical details) two significant components]]></description>
<content:encoded><![CDATA[<p>In previous lectures, we have established (modulo some technical details) two significant components of the proof of the Poincaré conjecture: finite time extinction of Ricci flow with surgery (Theorem 4 of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/01/285g-lecture-2-the-ricci-flow-approach-to-the-poincare-conjecture/">Lecture 2</a>), and a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsing of Ricci flows with surgery (which, except for the surgery part, is Theorem 2  of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/20/285g-lecture-7-rescaling-of-ricci-flows-and-kappa-noncollapsing/">Lecture 7</a>).  Now we come to the heart of the entire argument: the topological and geometric control of the high curvature regions of a Ricci flow, which is absolutely essential in order for one to define surgery on these regions in order to move the flow past singularities.  This control is intimately tied to the study of a special type of Ricci flow, the <em><img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions</em> to the Ricci flow equation; we will be able to use compactness arguments (as well as the <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsing results already obtained) to deduce control of high curvature regions of arbitrary Ricci flows from similar control of <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions.  A secondary compactness argument lets us obtain that control of <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions from control of an even more special type of solution, the <em>gradient shrinking solitons</em> that we already encountered in <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/24/285a-lecture-8-ricci-flow-as-a-gradient-flow-log-sobolev-inequalities-and-perelman-entropy/">Lecture 8</a>.</p>
<p>[Even once one has this control of high curvature regions, the proof of the Poincaré conjecture is still not finished; there is significant work required to properly define the surgery procedure, and then one has to show that the surgeries do not accumulate in time, and also do not disrupt the various monotonicity formulae that we are using to deduce finite time extinction, <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsing, etc.  But the control of high curvature regions is arguably the largest single task one has to establish in the entire proof.]</p>
<p>The next few lectures will be devoted to the analysis of <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions, culminating in Perelman&#8217;s topological and geometric classification (or near-classification) of such solutions (which in particular leads to the <em>canonical neighbourhood theorem</em> for these solutions, which we will briefly discuss below).  In this lecture we shall formally define the notion of a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution, and indicate informally why  control of such solutions should lead to control of high curvature regions of Ricci flows.  We&#8217;ll also outline the various types of results that we will prove about <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions.</p>
<p>Our treatment here is based primarily on the <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2334563">book of Morgan and Tian</a>.</p>
<p><!--more--></p>
<p style="text-align:center;">&#8211; Definition of a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution &#8211;</p>
<p>We fix a small number <img src='http://s0.wp.com/latex.php?latex=%5Ckappa+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa &gt; 0' title='&#92;kappa &gt; 0' class='latex' /> (basically the parameter that comes out of the non-collapsing theorem).  Here is the formal definition of a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution:</p>
<blockquote><p><strong>Definition 1. </strong> (<img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions) A <em><img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution</em> is a Ricci flow <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> which is</p>
<ol>
<li><em>Ancient</em>, in the sense that t ranges on the interval <img src='http://s0.wp.com/latex.php?latex=%28-%5Cinfty%2C0%5D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(-&#92;infty,0]' title='(-&#92;infty,0]' class='latex' />;</li>
<li><em>Complete and connected</em> (i.e. (M,g(t)) is complete and connected for every t);</li>
<li><em>Non-negative Riemann curvature</em>, i.e. <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRiem%7D%3A+%5Cbigwedge%5E2+TM+%5Cto+%5Cbigwedge%5E2+TM&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Riem}: &#92;bigwedge^2 TM &#92;to &#92;bigwedge^2 TM' title='&#92;hbox{Riem}: &#92;bigwedge^2 TM &#92;to &#92;bigwedge^2 TM' class='latex' /> is positive semidefinite at all points in spacetime;</li>
<li><em>Bounded curvature</em>, thus <img src='http://s0.wp.com/latex.php?latex=%5Csup_%7B%28t%2Cx%29+%5Cin+%28-%5Cinfty%2C0%5D+%5Ctimes+M%7D+%26%23124%3B%5Chbox%7BRiem%7D%26%23124%3B_g+%26%2360%3B+%2B%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;sup_{(t,x) &#92;in (-&#92;infty,0] &#92;times M} &#124;&#92;hbox{Riem}&#124;_g &lt; +&#92;infty' title='&#92;sup_{(t,x) &#92;in (-&#92;infty,0] &#92;times M} &#124;&#92;hbox{Riem}&#124;_g &lt; +&#92;infty' class='latex' />;</li>
<li><em><img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsed</em> (see Definition 1 of <a href="http://terrytao.wordpress.com/2008/04/20/285g-lecture-7-rescaling-of-ricci-flows-and-kappa-noncollapsing/">Lecture 7</a>) at every point <img src='http://s0.wp.com/latex.php?latex=%28t_0%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_0,x_0)' title='(t_0,x_0)' class='latex' /> in spacetime and at every scale <img src='http://s0.wp.com/latex.php?latex=r_0+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_0 &gt; 0' title='r_0 &gt; 0' class='latex' />;</li>
<li><em>Non-flat</em>, i.e. the curvature is non-zero at at least one point in spacetime.</li>
</ol>
</blockquote>
<p>This laundry list of properties arises because they are the properties that we are able to directly establish on limits of rescaled Ricci flows; see below.</p>
<p><strong>Remark 1. </strong> If a d-dimensional Riemann manifold is both flat (thus <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRiem%7D%3D0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Riem}=0' title='&#92;hbox{Riem}=0' class='latex' />) and non-collapsed at every scale, then (by Cheeger&#8217;s lemma, Theorem 1 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/20/285g-lecture-7-rescaling-of-ricci-flows-and-kappa-noncollapsing/">Lecture 7</a>) its injectivity radius is infinite, and by normal coordinates the manifold is isometric to Euclidean space <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+R%7D%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb R}^d' title='{&#92;Bbb R}^d' class='latex' />.  Thus the non-flat condition is only excluding the <em>trivial Ricci flow</em> <img src='http://s0.wp.com/latex.php?latex=M+%3D+%7B%5CBbb+R%7D%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M = {&#92;Bbb R}^d' title='M = {&#92;Bbb R}^d' class='latex' /> with the standard (and static) metric. The non-flat condition tells us that the (scalar, say) curvature is positive in at least one point of spacetime, but we will shortly be able to use the strong maximum principle to conclude in fact that the curvature is positive everywhere. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p><strong>Remark 2.</strong> In three dimensions, the condition of non-negative RIemann curvature is equivalent to that of non-negative sectional curvature; see the discussion in <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/03/26/285g-lecture-0-riemannian-manifolds-and-curvature/">Lecture 0</a>.  In any dimension, the conditions of non-negative bounded Riemann curvature imply that R and <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRic%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Ric}' title='&#92;hbox{Ric}' class='latex' /> are non-negative, and that <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Chbox%7BRiem%7D%26%23124%3B_g%2C+%26%23124%3B%5Chbox%7BRic%7D%26%23124%3B_g+%3D+O%28R%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;hbox{Riem}&#124;_g, &#124;&#92;hbox{Ric}&#124;_g = O(R)' title='&#124;&#92;hbox{Riem}&#124;_g, &#124;&#92;hbox{Ric}&#124;_g = O(R)' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=R+%3D+O_d%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R = O_d(1)' title='R = O_d(1)' class='latex' />.  Thus as far as magnitude is concerned, the Riemann and Ricci curvatures of <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions are controlled by the scalar curvature. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>Now we discuss examples (and non-examples) of <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions.</p>
<p><strong>Example 1.</strong> Every gradient shrinking soliton or gradient steady soliton (M,g) (see <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/24/285a-lecture-8-ricci-flow-as-a-gradient-flow-log-sobolev-inequalities-and-perelman-entropy/">Lecture 8</a>) gives an ancient flow.  This flow will be a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution for sufficiently small <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' /> if the Einstein manifold (M,g) is complete, connected, non-collapsed at every scale, and is not Euclidean space.   For instance, the round sphere <img src='http://s0.wp.com/latex.php?latex=S%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^d' title='S^d' class='latex' /> with the standard metric is a gradient shrinking solution and will generate a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution for any <img src='http://s0.wp.com/latex.php?latex=d+%5Cgeq+2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d &#92;geq 2' title='d &#92;geq 2' class='latex' /> and sufficiently small <img src='http://s0.wp.com/latex.php?latex=%5Ckappa+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa &gt; 0' title='&#92;kappa &gt; 0' class='latex' />, which we will refer to as the <em>shrinking round sphere</em> <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution.   <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p><strong>Exercse 1.</strong> Show that the Cartesian product of two <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions is again a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution  (with a smaller value of <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />), as is the Cartesian product of a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution.  Thus for instance the product <img src='http://s0.wp.com/latex.php?latex=S%5E2+%5Ctimes+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2 &#92;times {&#92;Bbb R}' title='S^2 &#92;times {&#92;Bbb R}' class='latex' /> of the shrinking round 2-sphere and the Euclidean line is a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution, which we refer to as the <em>shrinking round 3-cylinder</em> <img src='http://s0.wp.com/latex.php?latex=S%5E2+%5Ctimes+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2 &#92;times {&#92;Bbb R}' title='S^2 &#92;times {&#92;Bbb R}' class='latex' />. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p><strong>Example 2.</strong> In one dimension, there are no <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions, as every manifold is flat; in particular, the 1-sphere (i.e. a circle) is <em>not</em> a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution (it is flat and also collapsed at large scales).  In two dimensions, the shrinking round 2-sphere <img src='http://s0.wp.com/latex.php?latex=S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2' title='S^2' class='latex' /> is <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution, as discussed above.  We can quotient this by the obvious <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+Z%7D%2F2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb Z}/2' title='{&#92;Bbb Z}/2' class='latex' /> action to also get a shrinking round projective plane <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^2' title='&#92;Bbb{RP}^2' class='latex' /> as a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution.  But we shall show in later lectures that if we restrict attention to oriented manifolds, then the shrinking round 2-sphere is the only 2-dimensional <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions; this result is due to Hamilton, see e.g. Chapter 5 of <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2061425">Chow-Knopf</a>. For instance, the 2-cylinder <img src='http://s0.wp.com/latex.php?latex=S%5E1+%5Ctimes+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^1 &#92;times {&#92;Bbb R}' title='S^1 &#92;times {&#92;Bbb R}' class='latex' /> is not a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution (it is both flat and collapsed at large scales). The cigar soliton (Example 3 from <a href="http://terrytao.wordpress.com/2008/04/24/285a-lecture-8-ricci-flow-as-a-gradient-flow-log-sobolev-inequalities-and-perelman-entropy/">Lecture 8</a>) also fails to be a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution due to it being collapsed at large scales.  <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /><strong><br />
</strong></p>
<p><strong>Example 3.</strong> In three dimensions, we begin to get significantly more variety amongst <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions.  We have the round shrinking 3-sphere <img src='http://s0.wp.com/latex.php?latex=S%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^3' title='S^3' class='latex' />, but also all the quotients <img src='http://s0.wp.com/latex.php?latex=S%5E3%2F%5CGamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^3/&#92;Gamma' title='S^3/&#92;Gamma' class='latex' /> of such round spheres by free finite group actions (including the projective space <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+RP%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb RP}^3' title='{&#92;Bbb RP}^3' class='latex' />, but with many other examples.  We refer to these examples as <em>round shrinking 3-spherical space forms</em>.  We have also seen the shrinking round cylinder <img src='http://s0.wp.com/latex.php?latex=S%5E2+%5Ctimes+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2 &#92;times {&#92;Bbb R}' title='S^2 &#92;times {&#92;Bbb R}' class='latex' />; there are also finite quotients of this example such as shrinking round projective cylinder <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E2+%5Ctimes+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^2 &#92;times {&#92;Bbb R}' title='&#92;Bbb{RP}^2 &#92;times {&#92;Bbb R}' class='latex' />, or the quotient of the cylinder by the orientation-preserving free involution <img src='http://s0.wp.com/latex.php?latex=%28%5Comega%2Cz%29+%5Cmapsto+%28-%5Comega%2C-z%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;omega,z) &#92;mapsto (-&#92;omega,-z)' title='(&#92;omega,z) &#92;mapsto (-&#92;omega,-z)' class='latex' />.  We refer to these examples as the <em>unoriented and oriented quotients of the shrinking round 3-cylinder</em> respectively. The oriented quotient can be viewed as a half-cylinder <img src='http://s0.wp.com/latex.php?latex=S%5E2+%5Ctimes+%5B1%2C%2B%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2 &#92;times [1,+&#92;infty)' title='S^2 &#92;times [1,+&#92;infty)' class='latex' /> capped off with a punctured <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^3' title='&#92;Bbb{RP}^3' class='latex' /> (and the whole manifold is in fact homeomorphic to a punctured <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^3' title='&#92;Bbb{RP}^3' class='latex' />).   <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p><strong>Example 4. </strong>One can also imagine perturbations of the shrinking solutions mentioned above.  For instance, one could imagine non-round versions of the shrinking <img src='http://s0.wp.com/latex.php?latex=S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2' title='S^2' class='latex' /> or shrinking <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+RP%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb RP}^3' title='{&#92;Bbb RP}^3' class='latex' /> example, in which the manifold has sectional curvature which is still positive but not constant.  We shall informally refer to such solutions as <em>C-components</em> (we will define this term formally later, and explain the role of the parameter C).  Similarly one could imagine variants of the oriented quotient of the shrinking round cylinder, which are approximately round half-cylinders <img src='http://s0.wp.com/latex.php?latex=S%5E2+%5Ctimes+%5B1%2C%2B%5Cinfty%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2 &#92;times [1,+&#92;infty)' title='S^2 &#92;times [1,+&#92;infty)' class='latex' /> capped off with what is topologically either a punctured <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^3' title='&#92;Bbb{RP}^3' class='latex' /> or punctured <img src='http://s0.wp.com/latex.php?latex=S%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^3' title='S^3' class='latex' /> (i.e. with something homeomorphic to a ball); a 3-dimensional variant of a cigar soliton would fall into this category (such solitons have been constructed <a class="snap_noshots" href="http://arxiv.org/abs/math/0407453">by Bryant</a> and <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=1417944">by Cao</a>).  We informally refer to such solutions as <img src='http://s0.wp.com/latex.php?latex=C&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C' title='C' class='latex' />-capped strong <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-tubes (we will define this term precisely later).  One can also consider <em>doubly <img src='http://s0.wp.com/latex.php?latex=C&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C' title='C' class='latex' />-capped strong <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-tubes</em>, in which an approximately round finite cylinder <img src='http://s0.wp.com/latex.php?latex=S%5E2+%5Ctimes+%5B-T%2CT%5D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2 &#92;times [-T,T]' title='S^2 &#92;times [-T,T]' class='latex' /> is capped off at both ends by either a punctured <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^3' title='&#92;Bbb{RP}^3' class='latex' /> or punctured <img src='http://s0.wp.com/latex.php?latex=S%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^3' title='S^3' class='latex' />; such manifolds then become homeomorphic to either <img src='http://s0.wp.com/latex.php?latex=S%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^3' title='S^3' class='latex' /> or <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+RP%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb RP}^3' title='{&#92;Bbb RP}^3' class='latex' />.  (Note we need to cap off any ends that show up in order to keep the manifold M complete.)  <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>An important theorem of Perelman shows that these examples of <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions are in fact the only ones:</p>
<blockquote><p><strong>Theorem 1.</strong> (Perelman classification theorem, imprecise version)  Every 3-dimensional <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution takes on one of the following forms at time zero (after isometry and rescaling, if necessary):</p>
<ol>
<li>A shrinking round 3-sphere <img src='http://s0.wp.com/latex.php?latex=S%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^3' title='S^3' class='latex' /> (or shrinking round spherical space form <img src='http://s0.wp.com/latex.php?latex=S%5E3%2F%5CGamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^3/&#92;Gamma' title='S^3/&#92;Gamma' class='latex' />);</li>
<li>A shrinking round 3-cylinder <img src='http://s0.wp.com/latex.php?latex=S%5E2+%5Ctimes+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2 &#92;times {&#92;Bbb R}' title='S^2 &#92;times {&#92;Bbb R}' class='latex' />, the quotient <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E2+%5Ctimes+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^2 &#92;times {&#92;Bbb R}' title='&#92;Bbb{RP}^2 &#92;times {&#92;Bbb R}' class='latex' />, or one of its quotients (either oriented or unoriented);</li>
<li>A C-component;</li>
<li>A C-capped strong <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-tube;</li>
<li>A doubly C-capped strong <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-tube.</li>
</ol>
</blockquote>
<p>We will make this theorem more precise in later lectures (or if you are impatient, you can read Chapter 9 of <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2334563">Morgan-Tian</a>).</p>
<p><strong>Remark 3.</strong> At very large scales, Theorem 1 implies that an ancient solution at time zero either looks 0-dimensional (because the manifold was compact, as in the case of a sphere, spherical space form, C-component, or doubly C-capped strong <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-tube) or 1-dimensional, resembling a line (in the case of the cylinder) or half-line (for C-capped strong <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-tube). Oversimplifying somewhat, this 0- or 1-dimensionality of the three-dimensional <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions is the main reason why surgery is even possible; if Ricci flow singularities could look 2-dimensional (such as <img src='http://s0.wp.com/latex.php?latex=S%5E1+%5Ctimes+%7B%5CBbb+R%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^1 &#92;times {&#92;Bbb R}^2' title='S^1 &#92;times {&#92;Bbb R}^2' class='latex' />, or as the product of the cigar soliton and a line) or 3-dimensional (as in <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+R%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb R}^3' title='{&#92;Bbb R}^3' class='latex' />) then it is not clear at all how to define a surgery procedure to excise the singularity.  The point is that all the potential candidates for singularity that look 2-dimensional or 3-dimensional at large scales (after rescaling) are either flat or collapsed (or do not have bounded nonnegative curvature), and so are not <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions.  The unoriented quotiented cylinder <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E2+%5Ctimes+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^2 &#92;times {&#92;Bbb R}' title='&#92;Bbb{RP}^2 &#92;times {&#92;Bbb R}' class='latex' /> also causes difficulties with surgery (despite being only one-dimensional at large scales), because it is hard to cap off such a cylinder in a manner which is well-behaved with respect to Ricci flow; however if we assume that the original manifold M contains no embedded copy of <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E2+%5Ctimes+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^2 &#92;times {&#92;Bbb R}' title='&#92;Bbb{RP}^2 &#92;times {&#92;Bbb R}' class='latex' /> (which is for instance the case if the manifold is oriented, and in particular if it is simply connected) then this case does not occur. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p><strong>Remark 4.</strong> In four and higher dimensions, things look much worse; consider for instance the product of a shrinking round <img src='http://s0.wp.com/latex.php?latex=S%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2' title='S^2' class='latex' /> with the trivial plane <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+R%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb R}^2' title='{&#92;Bbb R}^2' class='latex' />.  This is a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution but has a two-dimensional large-scale structure, and so there is no obvious way to remove singularities of this shape by surgery.  It may be that in order to have analogues of Perelman&#8217;s theory in higher dimensions one has to make much stronger topological or geometric assumptions on the manifold.  Note however that four-dimensional Ricci flows with surgery were already considered <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=862046">by Hamilton</a> (with a rather different definition of surgery, however).</p>
<p>The classification theorem lets one understand the geometry of neighbourhoods of any given point in a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution.  Let us make the following imprecise definitions (which, again, will be made precise in later lectures):</p>
<blockquote><p><strong>Definition 2. </strong> (Canonical neighbourhoods, informal version) Let (M,g) be a complete connected 3-manifold, let x be a point in M, and let U be an open neighbourhood of x.  We normalise the scalar curvature at x to be 1.</p>
<ol>
<li>We say that U is an <em><img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-neck</em> if it is close (in a smooth topology) to a round cylinder <img src='http://s0.wp.com/latex.php?latex=S%5E2+%5Ctimes+%28-R%2CR%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^2 &#92;times (-R,R)' title='S^2 &#92;times (-R,R)' class='latex' />, with x well in the middle of of this cylinder;</li>
<li>We say that U is a <em>C-component</em> if U is diffeomorphic to <img src='http://s0.wp.com/latex.php?latex=S%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^3' title='S^3' class='latex' /> or <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^3' title='&#92;Bbb{RP}^3' class='latex' /> (in particular, it must be all of M) with sectional curvatures bounded above and below by positive constants, and with diameter comparable to 1.</li>
<li>We say that U is <em><img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-round</em> if it is close (in a smooth topology) to a round sphere <img src='http://s0.wp.com/latex.php?latex=S%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^3' title='S^3' class='latex' /> or spherical space form <img src='http://s0.wp.com/latex.php?latex=S%5E3%2F%5CGamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^3/&#92;Gamma' title='S^3/&#92;Gamma' class='latex' /> (i.e. it is close to a constant curvature manifold).</li>
<li>We say that U is a <em><img src='http://s0.wp.com/latex.php?latex=%28C%2C%5Cvarepsilon%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(C,&#92;varepsilon)' title='(C,&#92;varepsilon)' class='latex' />-cap</em> if it consists of an <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />-neck together with a cap at one end, where the cap is homeomorphic to either an open 3-ball or a punctured <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+RP%7D%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb RP}^3' title='{&#92;Bbb RP}^3' class='latex' /> and obeys similar bounds as a C-component, and that x is contained inside the cap.  (For technical reasons one also needs some derivative bounds on curvature, but we omit them here.)</li>
<li>We say that U is a <em>canonical neighbourhood</em> of x if it is one of the above four types.</li>
</ol>
<p>When the scalar curvature is some other positive number than 1, we can generalise the above definition by rescaling the metric to have curvature 1.</p></blockquote>
<p>Using Theorem 1 (and defining all terms precisely), one can easily show the following important statement:</p>
<blockquote><p><strong>Corollary 1</strong> (Canonical neighbourhood theorem for <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solitons, informal version)  Every point in a 3-dimensional <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution that does not contain an embedded copy of <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^2' title='&#92;Bbb{RP}^2' class='latex' /> with trivial normal bundle is contained in a canonical neighbourhood.</p></blockquote>
<p>The next few lectures will be devoted to establishing precise versions of Theorem 1, Definition 2, and Corollary 1.</p>
<p style="text-align:center;">&#8211; High curvature regions of Ricci flows &#8211;</p>
<p>Corollary 1 is an assertion about <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions only, but it implies an important property about more general Ricci flows:</p>
<blockquote><p><strong>Theorem 2.</strong> (Canonical neighbourhood for Ricci flows, informal version)  Let <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g)' title='t &#92;mapsto (M,g)' class='latex' /> be a Ricci flow of compact 3-manifolds on a time interval <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5B0%2CT%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[0,T)' title='{}[0,T)' class='latex' />, without any embedded copy of <img src='http://s0.wp.com/latex.php?latex=%5CBbb%7BRP%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Bbb{RP}^2' title='&#92;Bbb{RP}^2' class='latex' /> with trivial normal bundle.  Then every point <img src='http://s0.wp.com/latex.php?latex=%28t%2Cx%29+%5Cin+%5B0%2CT%29+%5Ctimes+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t,x) &#92;in [0,T) &#92;times M' title='(t,x) &#92;in [0,T) &#92;times M' class='latex' /> with sufficiently large scalar curvature is contained in a canonical neighbourhood.</p></blockquote>
<p>(Actually, as with many other components of this proof, we actually need a generalisation of this result for Ricci flow with surgery, but we will address this (non-trivial) complication later.)</p>
<p>The importance of this theorem lies in the fact that all the singular regions that need surgery will have large scalar curvature, and Theorem 2 provides the crucial topological and geometric control in order to perform surgery on these regions.  (This is a significant oversimplification, as one has to also study certain &#8220;horns&#8221; that appear at the singular time in order to find a particularly good place to perform surgery, but we will postpone discussion of this major additional issue later in this course.)</p>
<p>Theorem 2 is deduced from Corollary 1 and a significant number of additional arguments.  The strategy is to use a compactness-and-contradiction argument.  As a very crude first approximation, the proof goes as follows:</p>
<ol>
<li>Suppose for contradiction that Theorem 2 failed.  Then one could find a sequence <img src='http://s0.wp.com/latex.php?latex=%28t_n%2Cx_n%29+%5Cin+%5B0%2CT%29+%5Ctimes+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_n,x_n) &#92;in [0,T) &#92;times M' title='(t_n,x_n) &#92;in [0,T) &#92;times M' class='latex' /> of points with <img src='http://s0.wp.com/latex.php?latex=R%28t_n%2Cx_n%29+%5Cto+%2B%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(t_n,x_n) &#92;to +&#92;infty' title='R(t_n,x_n) &#92;to +&#92;infty' class='latex' /> which were not contained in canonical neighbourhoods.</li>
<li>M, being compact, has finitely many components; by restricting attention to a subsequence of points if necessary, we can take M to be connected.</li>
<li>On any compact time interval <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5B0%2Ct%5D+%5Ctimes+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[0,t] &#92;times M' title='{}[0,t] &#92;times M' class='latex' />, the scalar curvature is necessarily bounded, and thus <img src='http://s0.wp.com/latex.php?latex=t_n+%5Cto+T&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_n &#92;to T' title='t_n &#92;to T' class='latex' />.  As a consequence, if we define the rescaled Ricci flows <img src='http://s0.wp.com/latex.php?latex=g%5E%7B%28n%29%7D%28t%29+%3D+%5Cfrac%7B1%7D%7BL_n%5E2%7D+g%28+t_n+%2B+L_n%5E2+t+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='g^{(n)}(t) = &#92;frac{1}{L_n^2} g( t_n + L_n^2 t )' title='g^{(n)}(t) = &#92;frac{1}{L_n^2} g( t_n + L_n^2 t )' class='latex' />, where <img src='http://s0.wp.com/latex.php?latex=L_n+%3A%3D+R%28t_n%2Cx_n%29%5E%7B-1%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='L_n := R(t_n,x_n)^{-1/2}' title='L_n := R(t_n,x_n)^{-1/2}' class='latex' /> is the natural length scale associated to the scalar curvature at <img src='http://s0.wp.com/latex.php?latex=%28t_n%2Cx_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_n,x_n)' title='(t_n,x_n)' class='latex' />, then these flows will become increasingly ancient.   Note that in the limit (which we will not define rigorously yet, but think of a <a href="http://en.wikipedia.org/wiki/Gromov-Hausdorff_limit#Pointed_Gromov.E2.80.93Hausdorff_convergence">pointed Gromov-Hausdorff limit</a> for now), the increasingly large manifolds <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%5E%7B%28n%29%7D%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g^{(n)}(t))' title='(M,g^{(n)}(t))' class='latex' /> may cease to be compact, but will remain complete.</li>
<li>Because of the Hamilton-Ivey pinching phenomenon (Theorem 1 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/04/285g-lecture-3-the-maximum-principle-and-the-pinching-phenomenon/">Lecture 3</a>), we expect the rescaled flows <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2C+g%5E%7B%28n%29%7D%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M, g^{(n)}(t))' title='t &#92;mapsto (M, g^{(n)}(t))' class='latex' /> to have non-negative Ricci curvature in the limit (and hence non-negative Riemann curvature also, as we are in three dimensions).</li>
<li>If we can pick the points <img src='http://s0.wp.com/latex.php?latex=%28t_n%2Cx_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_n,x_n)' title='(t_n,x_n)' class='latex' /> suitably (so that the scalar curvature <img src='http://s0.wp.com/latex.php?latex=R%28t_n%2Cx_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(t_n,x_n)' title='R(t_n,x_n)' class='latex' /> is larger than or comparable to the scalar curvatures at other nearby points), then we should be able to ensure that the rescaled flows <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2C+g%5E%7B%28n%29%7D%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M, g^{(n)}(t))' title='t &#92;mapsto (M, g^{(n)}(t))' class='latex' /> have bounded curvature in the limit.</li>
<li>Since <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsing is invariant under rescaling, the non-collapsing theorem (Theorem 2 of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/20/285g-lecture-7-rescaling-of-ricci-flows-and-kappa-noncollapsing/">Lecture 7</a>) should ensure that the rescaled flows remain <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsed in the limit.</li>
<li>Since the rescaled scalar curvature at the base point <img src='http://s0.wp.com/latex.php?latex=x_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_n' title='x_n' class='latex' /> of <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%5E%7B%28n%29%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g^{(n)})' title='(M,g^{(n)})' class='latex' /> is equal to 1 by construction, any limiting flow will be non-flat.</li>
<li>Various compactness theorems (of Gromov, Hamilton, and Perelman) exploiting the non-collapsed, bounded curvature, and parabolic nature of the rescaled Ricci flows now allows one to extract a limiting flow <img src='http://s0.wp.com/latex.php?latex=%28M%5E%7B%28%5Cinfty%29%7D%2C+g%5E%7B%28%5Cinfty%29%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M^{(&#92;infty)}, g^{(&#92;infty)})' title='(M^{(&#92;infty)}, g^{(&#92;infty)})' class='latex' />. This limit is initially in a fairly weak sense, but one can use parabolic theory to upgrade the convergence to quite a strong (and smooth) convergence.  In particular, the limit of the Ricci flows will remain a Ricci flow.</li>
<li>Applying 2-8, we see that the limiting flow <img src='http://s0.wp.com/latex.php?latex=%28M%5E%7B%28%5Cinfty%29%7D%2C+g%5E%7B%28%5Cinfty%29%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M^{(&#92;infty)}, g^{(&#92;infty)})' title='(M^{(&#92;infty)}, g^{(&#92;infty)})' class='latex' /> is a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution.</li>
<li>Applying Corollary 1, we conclude that every point in the limiting flow lies inside a canonical neighbourhood.  Using the strong nature of the convergence (and the scale-invariant nature of canonical neighbourhoods), we deduce that the points <img src='http://s0.wp.com/latex.php?latex=%28t_n%2Cx_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_n,x_n)' title='(t_n,x_n)' class='latex' /> also lie in canonical neighbourhoods for sufficiently large n, a contradiction.</li>
</ol>
<p>There are some non-trivial technical difficulties in executing the above scheme, especially in Step 5 and Step 8.  Step 8 will require some compactness theorems for <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions which we will deduce in later lectures.  For Step 5, the problem is that the points <img src='http://s0.wp.com/latex.php?latex=%28t_n%2Cx_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_n,x_n)' title='(t_n,x_n)' class='latex' /> that we are trying to place inside canonical neighbourhoods have large curvature, but they may be adjacent to other points of significantly higher curvature, so that the limiting flow <img src='http://s0.wp.com/latex.php?latex=%28M%5E%7B%28%5Cinfty%29%7D%2C+g%5E%7B%28%5Cinfty%29%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M^{(&#92;infty)}, g^{(&#92;infty)})' title='(M^{(&#92;infty)}, g^{(&#92;infty)})' class='latex' /> ends up having unbounded curvature.  To get around this, Perelman established Theorem 2 by a downwards induction argument on the curvature, first establishing the result for extremely high curvature, then for slightly less extreme curvature, and so forth.  The point is that with such an induction hypothesis, any potentially bad adjacent points of really high curvature will be safely tucked away in a canonical neighbourhood of high curvature, which in turn is connected to another canonical neighbourhood of high curvature, and so forth; some basic topological and geometric analysis then eventually lets us conclude that this bad point must in fact be quite far from the base point <img src='http://s0.wp.com/latex.php?latex=%28t_n%2Cx_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_n,x_n)' title='(t_n,x_n)' class='latex' /> (much further away than the natural length scale <img src='http://s0.wp.com/latex.php?latex=L_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='L_n' title='L_n' class='latex' />, in particular), so that it does not show up in the limiting flow <img src='http://s0.wp.com/latex.php?latex=%28M%5E%7B%28%5Cinfty%29%7D%2C+g%5E%7B%28%5Cinfty%29%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M^{(&#92;infty)}, g^{(&#92;infty)})' title='(M^{(&#92;infty)}, g^{(&#92;infty)})' class='latex' />.  We will discuss these issues in more detail in later lectures.</p>
<p style="text-align:center;">&#8211; Benchmarks in controlling <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions &#8211;</p>
<p>As mentioned earlier, the next few lectures will be focused on controlling <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions.  It turns out that the various properties in Definition 1 interact very well with each other, and give remarkably precise control on these solutions.  In this section we state (without proofs) some of the results we will establish concerning such solutions.</p>
<blockquote><p><strong>Proposition 1.</strong> (Consequences of Hamilton&#8217;s Harnack inequality)  Let <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> be a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution.  Then <img src='http://s0.wp.com/latex.php?latex=R%28t%2Cx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R(t,x)' title='R(t,x)' class='latex' /> is a non-decreasing function of time.  Furthermore, for any <img src='http://s0.wp.com/latex.php?latex=%28t_0%2Cx_0%29+%5Cin+%28-%5Cinfty%2C0%5D+%5Ctimes+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_0,x_0) &#92;in (-&#92;infty,0] &#92;times M' title='(t_0,x_0) &#92;in (-&#92;infty,0] &#92;times M' class='latex' />, we have the pointwise inequalities</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%26%23124%3B%5Cnabla+l_%7B%28t_0%2Cx_0%29%7D%26%23124%3B%5E2+%2B+R+%5Cleq+%5Cfrac%7B3+l_%7B%28t_0%2Cx_0%29%7D%7D%7B%5Ctau%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#124;&#92;nabla l_{(t_0,x_0)}&#124;^2 + R &#92;leq &#92;frac{3 l_{(t_0,x_0)}}{&#92;tau}' title='&#92;displaystyle &#124;&#92;nabla l_{(t_0,x_0)}&#124;^2 + R &#92;leq &#92;frac{3 l_{(t_0,x_0)}}{&#92;tau}' class='latex' /> (1)</p>
<p>and</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+-2+%5Cfrac%7Bl_%7B%28t_0%2Cx_0%29%7D%7D%7B%5Ctau%7D+%5Cleq+%5Cfrac%7B%5Cpartial+l_%7B%28t_0%2Cx_0%29%7D%7D%7B%5Cpartial+%5Ctau%7D+%5Cleq+%5Cfrac%7Bl_%7B%28t_0%2Cx_0%29%7D%7D%7B%5Ctau%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle -2 &#92;frac{l_{(t_0,x_0)}}{&#92;tau} &#92;leq &#92;frac{&#92;partial l_{(t_0,x_0)}}{&#92;partial &#92;tau} &#92;leq &#92;frac{l_{(t_0,x_0)}}{&#92;tau}' title='&#92;displaystyle -2 &#92;frac{l_{(t_0,x_0)}}{&#92;tau} &#92;leq &#92;frac{&#92;partial l_{(t_0,x_0)}}{&#92;partial &#92;tau} &#92;leq &#92;frac{l_{(t_0,x_0)}}{&#92;tau}' class='latex' /> (2)</p>
<p>on <img src='http://s0.wp.com/latex.php?latex=%28-%5Cinfty%2Ct_0%29+%5Ctimes+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(-&#92;infty,t_0) &#92;times M' title='(-&#92;infty,t_0) &#92;times M' class='latex' />, where of course <img src='http://s0.wp.com/latex.php?latex=%5Ctau+%3A%3D+t_0+-+t&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau := t_0 - t' title='&#92;tau := t_0 - t' class='latex' /> is the backwards time variable.</p></blockquote>
<p>These inequalities follow from an important <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=1198607">Harnack inequality of Hamilton</a> (also related to earlier <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=834612">work of Li and Yau</a>) that we will discuss in the next lecture.  These results rely primarily on the ancient and non-negatively curved nature of <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions, as well as the Ricci flow equation <img src='http://s0.wp.com/latex.php?latex=%5Cdot+g+%3D+-2+%5Chbox%7BRic%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;dot g = -2 &#92;hbox{Ric}' title='&#92;dot g = -2 &#92;hbox{Ric}' class='latex' /> of course.</p>
<p>Now one can handle the two-dimensional case:</p>
<blockquote><p><strong>Proposition 2. </strong>(Classification of 2-dimensional <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions) The only two-dimensional <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions are the round shrinking 2-spheres.</p></blockquote>
<p>This proposition relies on first studying a certain asymptotic limit of the <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution, known as the asymptotic soliton, to be defined later.   One shows that this asymptotic limit is a round shrinking 2-sphere, which implies that the original <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution is asymptotically a round shrinking 2-sphere.  One can then invoke Hamilton&#8217;s rounding theorem to finish the claim.</p>
<p>Turning now to three dimensions, the first important result that the curvature R decays slower at infinity than what scaling naively predicts.</p>
<blockquote><p><strong>Proposition 3.</strong> (Asymptotic curvature) Let <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> be a 3-dimensional <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' /> solution which is not compact.  Then for any time <img src='http://s0.wp.com/latex.php?latex=t+%5Cin+%28-%5Cinfty%2C0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;in (-&#92;infty,0)' title='t &#92;in (-&#92;infty,0)' class='latex' /> and any base point <img src='http://s0.wp.com/latex.php?latex=p+%5Cin+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='p &#92;in M' title='p &#92;in M' class='latex' />, we have <img src='http://s0.wp.com/latex.php?latex=%5Climsup_%7Bx+%5Cto+%5Cinfty%7D+R%28t%2Cx%29+d_%7Bg%28t%29%7D%28x%2Cp%29%5E2+%3D+%2B%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;limsup_{x &#92;to &#92;infty} R(t,x) d_{g(t)}(x,p)^2 = +&#92;infty' title='&#92;limsup_{x &#92;to &#92;infty} R(t,x) d_{g(t)}(x,p)^2 = +&#92;infty' class='latex' />.</p></blockquote>
<p>The proof of Proposition 3 is based on another compactness-and-contradiction argument which also heavily exploits some splitting theorems in Riemannian geometry, as well as the <a href="http://en.wikipedia.org/wiki/Soul_theorem">soul theorem</a>.</p>
<p>The increasing curvature at infinity can be used to show that the volume does not grow as fast at infinity as scaling predicts:</p>
<blockquote>
<p style="text-align:left;"><strong>Proposition 4.</strong> (Asymptotic volume collapse) Let <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> be a 3-dimensional <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' /> solution which is not compact.  Then for any time <img src='http://s0.wp.com/latex.php?latex=t+%5Cin+%28-%5Cinfty%2C0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;in (-&#92;infty,0)' title='t &#92;in (-&#92;infty,0)' class='latex' /> and any base point <img src='http://s0.wp.com/latex.php?latex=p+%5Cin+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='p &#92;in M' title='p &#92;in M' class='latex' />, we have <img src='http://s0.wp.com/latex.php?latex=%5Climsup_%7Br+%5Cto+%2B%5Cinfty%7D+%5Chbox%7BVol%7D_%7Bg%28t%29%7D%28+B_%7Bg%28t%29%7D%29%28p%2Cr%29+%29+%2F+r%5E3+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;limsup_{r &#92;to +&#92;infty} &#92;hbox{Vol}_{g(t)}( B_{g(t)})(p,r) ) / r^3 = 0' title='&#92;limsup_{r &#92;to +&#92;infty} &#92;hbox{Vol}_{g(t)}( B_{g(t)})(p,r) ) / r^3 = 0' class='latex' />.</p>
</blockquote>
<p>Note that Proposition 4 does not contradict the non-collapsed nature of the flow, since one does not expect bounded normalised curvature at extremely large scales.  Proposition 4 morally follows from Bishop-Gromov comparison geometry theory, but its proof in fact uses yet another compactness-and-contradiction argument combined with splitting theory.</p>
<p>An important variant of Proposition 4 and Proposition 3 (and yet another compactness-and-contradiction argument) states that on any ball <img src='http://s0.wp.com/latex.php?latex=B_%7Bg%280%29%7D%28p%2Cr%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_{g(0)}(p,r)' title='B_{g(0)}(p,r)' class='latex' /> at time zero on which the volume is large (e.g. larger than <img src='http://s0.wp.com/latex.php?latex=%5Cnu+r%5E3&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nu r^3' title='&#92;nu r^3' class='latex' /> for some <img src='http://s0.wp.com/latex.php?latex=%5Cnu+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nu &gt; 0' title='&#92;nu &gt; 0' class='latex' />), one has bounded normalised curvature, thus <img src='http://s0.wp.com/latex.php?latex=R+%3D+O_%5Cnu%28+1+%2F+r%5E2+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R = O_&#92;nu( 1 / r^2 )' title='R = O_&#92;nu( 1 / r^2 )' class='latex' /> on this ball.  This fact helps us deduce</p>
<blockquote><p><strong>Theorem 3.</strong> (Perelman compactness theorem, informal version)  The space of all pointed <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions (allowing <img src='http://s0.wp.com/latex.php?latex=%5Ckappa+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa &gt; 0' title='&#92;kappa &gt; 0' class='latex' /> to range over the positive real numbers) is compact (in a suitable topology) after normalising the scalar curvature at the base point to be 1.</p></blockquote>
<p>One corollary of this compactness is that there is in fact a universal <img src='http://s0.wp.com/latex.php?latex=%5Ckappa_0+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa_0 &gt; 0' title='&#92;kappa_0 &gt; 0' class='latex' /> such that every <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solution is a <img src='http://s0.wp.com/latex.php?latex=%5Ckappa_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa_0' title='&#92;kappa_0' class='latex' />-solution.  (Indeed, the proof of this universality is one of the key steps in the proof of the above theorem.)  This theorem is proven by establishing some uniform curvature bounds on <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-solutions which come from the previous volume analysis.</p>
<p>The proof of Theorem 1 (and thus Corollary 1) follows from this compactness once one can classify the asymptotic solitons mentioned earlier.  This task in turn requires many of the techniques already mentioned, together with some variational analysis of the gradient curves of the potential function f that controls the geometry of the soliton.</p>
]]></content:encoded>
</item>
<item>
<title><![CDATA[285G, Lecture 11: κ-noncollapsing via Perelman reduced volume]]></title>
<link>http://terrytao.wordpress.com/2008/05/14/285g-lecture-11-%ce%ba-noncollapsing-via-perelman-reduced-volume/</link>
<pubDate>Wed, 14 May 2008 15:42:39 +0000</pubDate>
<dc:creator>Terence Tao</dc:creator>
<guid>http://terrytao.wordpress.com/2008/05/14/285g-lecture-11-%ce%ba-noncollapsing-via-perelman-reduced-volume/</guid>
<description><![CDATA[Having established the monotonicity of the Perelman reduced volume in the previous lecture (after fi]]></description>
<content:encoded><![CDATA[<p>Having established the monotonicity of the Perelman reduced volume in the <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/09/285g-lecture-10-variation-of-l-geodesics-and-monotonicity-of-perelman-reduced-volume/">previous lecture</a> (after first heuristically justifying this monotonicity in <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/27/285g-lecture-9-comparison-geometry-the-high-dimensional-limit-and-perelman-reduced-volume/">Lecture 9</a>), we now show how this can be used to establish <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsing of Ricci flows, thus giving a second proof of Theorem 2 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/20/285g-lecture-7-rescaling-of-ricci-flows-and-kappa-noncollapsing/">Lecture 7</a>.  Of course, we already proved (a stronger version) of this theorem already in <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/24/285a-lecture-8-ricci-flow-as-a-gradient-flow-log-sobolev-inequalities-and-perelman-entropy/">Lecture 8</a>, using the Perelman entropy, but this second proof is also important, because the reduced volume is a more localised quantity (due to the weight <img src='http://s0.wp.com/latex.php?latex=e%5E%7B-l_%7B%280%2Cx_0%29%7D%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='e^{-l_{(0,x_0)}}' title='e^{-l_{(0,x_0)}}' class='latex' /> in its definition and so one can in fact establish <em>local </em>versions of the non-collapsing theorem which turn out to be important when we study ancient <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsing solutions later in Perelman&#8217;s proof, because such solutions need not be compact and so cannot be controlled by global quantities (such as the Perelman entropy).</p>
<p>The route to <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsing via reduced volume proceeds by the following scheme:</p>
<blockquote>
<p style="text-align:center;">Non-collapsing at time t=0 (1)</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5CDownarrow&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Downarrow' title='&#92;Downarrow' class='latex' /></p>
<p style="text-align:center;">Large reduced volume at time t=0 (2)</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5CDownarrow&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Downarrow' title='&#92;Downarrow' class='latex' /></p>
<p style="text-align:center;">Large reduced volume at later times t (3)</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5CDownarrow&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Downarrow' title='&#92;Downarrow' class='latex' /></p>
<p style="text-align:center;">Non-collapsing at later times t (4)</p>
</blockquote>
<p style="text-align:left;">The implication <img src='http://s0.wp.com/latex.php?latex=%282%29+%5Cimplies+%283%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(2) &#92;implies (3)' title='(2) &#92;implies (3)' class='latex' /> is the monotonicity of Perelman reduced volume.  In this lecture we discuss the other two implications <img src='http://s0.wp.com/latex.php?latex=%281%29+%5Cimplies+%282%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(1) &#92;implies (2)' title='(1) &#92;implies (2)' class='latex' />, and <img src='http://s0.wp.com/latex.php?latex=%283%29+%5Cimplies+%284%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(3) &#92;implies (4)' title='(3) &#92;implies (4)' class='latex' />).</p>
<p style="text-align:left;">Our arguments here are based on <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0211159">Perelman&#8217;s first paper</a>, <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0605667">Kleiner-Lott&#8217;s notes</a>, and <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2334563">Morgan-Tian&#8217;s book</a>, though the material in the Morgan-Tian book differs in some key respects from the other two texts.  A closely related presentation of these topics also appears in the paper of <a class="snap_noshots" href="http://arxiv.org/abs/math/0612069">Cao-Zhu</a>.</p>
<p style="text-align:left;"><!--more--></p>
<p style="text-align:center;">&#8211; Definitions &#8211;</p>
<p>Let us first recall our definitions.  Previously we defined Perelman reduced length and reduced volume for ancient flows <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> for <img src='http://s0.wp.com/latex.php?latex=t+%5Cin+%28-%5Cinfty%2C0%5D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;in (-&#92;infty,0]' title='t &#92;in (-&#92;infty,0]' class='latex' />, centred at a point <img src='http://s0.wp.com/latex.php?latex=%280%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(0,x_0)' title='(0,x_0)' class='latex' /> on the final time slice <img src='http://s0.wp.com/latex.php?latex=t%3D0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t=0' title='t=0' class='latex' />, but one can also define these quantities for flows on the time interval <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5B0%2CT%5D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[0,T]' title='{}[0,T]' class='latex' /> and for points <img src='http://s0.wp.com/latex.php?latex=%28t_0%2Cx_0%29+%5Cin+%5B0%2CT%5D+%5Ctimes+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_0,x_0) &#92;in [0,T] &#92;times M' title='(t_0,x_0) &#92;in [0,T] &#92;times M' class='latex' /> as follows.  We introduce the backward time variable <img src='http://s0.wp.com/latex.php?latex=%5Ctau+%3A%3D+t_0+-+t&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau := t_0 - t' title='&#92;tau := t_0 - t' class='latex' />.  Given any path <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%3A+%5B0%2C%5Ctau_1%5D+%5Cto+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma: [0,&#92;tau_1] &#92;to M' title='&#92;gamma: [0,&#92;tau_1] &#92;to M' class='latex' />, we define its length</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+L%28%5Cgamma%29+%3A%3D+%5Cint_0%5E%7B%5Ctau_1%7D+%5Csqrt%7B%5Ctau%7D+%28R+%2B+%26%23124%3B%5Cdot+%5Cgamma%28%5Ctau%29%26%23124%3B_g%5E2%29%5C+d%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle L(&#92;gamma) := &#92;int_0^{&#92;tau_1} &#92;sqrt{&#92;tau} (R + &#124;&#92;dot &#92;gamma(&#92;tau)&#124;_g^2)&#92; d&#92;tau' title='&#92;displaystyle L(&#92;gamma) := &#92;int_0^{&#92;tau_1} &#92;sqrt{&#92;tau} (R + &#124;&#92;dot &#92;gamma(&#92;tau)&#124;_g^2)&#92; d&#92;tau' class='latex' />(5)</p>
<p>and for any <img src='http://s0.wp.com/latex.php?latex=%28t_1%2Cx_1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_1,x_1)' title='(t_1,x_1)' class='latex' /> with <img src='http://s0.wp.com/latex.php?latex=0+%5Cleq+t_1+%26%2360%3B+t_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &#92;leq t_1 &lt; t_0' title='0 &#92;leq t_1 &lt; t_0' class='latex' />, with <img src='http://s0.wp.com/latex.php?latex=%5Ctau_1+%3A%3D+t_0+-+t_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau_1 := t_0 - t_1' title='&#92;tau_1 := t_0 - t_1' class='latex' />, we define the reduced length</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=l_%7B%28t_0%2Cx_0%29%7D%28t_1%2Cx_1%29+%3A%3D+%5Cfrac%7B1%7D%7B2%5Csqrt%7B%5Ctau_1%7D%7D+%5Cinf_%5Cgamma+L%28%5Cgamma%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_{(t_0,x_0)}(t_1,x_1) := &#92;frac{1}{2&#92;sqrt{&#92;tau_1}} &#92;inf_&#92;gamma L(&#92;gamma)' title='l_{(t_0,x_0)}(t_1,x_1) := &#92;frac{1}{2&#92;sqrt{&#92;tau_1}} &#92;inf_&#92;gamma L(&#92;gamma)' class='latex' /> (6)</p>
<p>where <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%3A+%5B0%2C%5Ctau_1%5D+%5Cto+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma: [0,&#92;tau_1] &#92;to M' title='&#92;gamma: [0,&#92;tau_1] &#92;to M' class='latex' /> ranges over all <img src='http://s0.wp.com/latex.php?latex=C%5E1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C^1' title='C^1' class='latex' /> paths from <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=x_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_1' title='x_1' class='latex' /> (which can also be viewed as trajectories in the spacetime manifold <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5B0%2CT%5D+%5Ctimes+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[0,T] &#92;times M' title='{}[0,T] &#92;times M' class='latex' /> from <img src='http://s0.wp.com/latex.php?latex=%28t_0%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_0,x_0)' title='(t_0,x_0)' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=%28t_1%2Cx_1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_1,x_1)' title='(t_1,x_1)' class='latex' />.  The reduced volume is then defined as</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Ctilde+V_%7B%28t_0%2Cx_0%29%7D%28%5Ctau_1%29+%3A%3D+%5Cfrac%7B1%7D%7B%5Ctau_1%5E%7Bd%2F2%7D%7D+%5Cint_M+e%5E%7B-l_%7B%28t_0%2Cx_0%29%7D%28t_1%2Cx_1%29%7D%5C+d%5Cmu_%7Bt_1%7D%28x_1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;tilde V_{(t_0,x_0)}(&#92;tau_1) := &#92;frac{1}{&#92;tau_1^{d/2}} &#92;int_M e^{-l_{(t_0,x_0)}(t_1,x_1)}&#92; d&#92;mu_{t_1}(x_1)' title='&#92;displaystyle &#92;tilde V_{(t_0,x_0)}(&#92;tau_1) := &#92;frac{1}{&#92;tau_1^{d/2}} &#92;int_M e^{-l_{(t_0,x_0)}(t_1,x_1)}&#92; d&#92;mu_{t_1}(x_1)' class='latex' />. (7)</p>
<p>[Note: some authors normalise the reduced volume by using <img src='http://s0.wp.com/latex.php?latex=%284%5Cpi+%5Ctau_1%29%5E%7Bd%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(4&#92;pi &#92;tau_1)^{d/2}' title='(4&#92;pi &#92;tau_1)^{d/2}' class='latex' /> instead of <img src='http://s0.wp.com/latex.php?latex=%5Ctau_1%5E%7Bd%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau_1^{d/2}' title='&#92;tau_1^{d/2}' class='latex' />, in order to give Euclidean space a reduced volume of 1, but this makes no essential difference to the analysis.]</p>
<p>The arguments of the <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/09/285g-lecture-10-variation-of-l-geodesics-and-monotonicity-of-perelman-reduced-volume/">previous lecture</a> show that if <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> is a Ricci flow, then the reduced volume is a non-increasing function of <img src='http://s0.wp.com/latex.php?latex=%5Ctau_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau_1' title='&#92;tau_1' class='latex' /> for fixed <img src='http://s0.wp.com/latex.php?latex=%28t_0%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_0,x_0)' title='(t_0,x_0)' class='latex' />.  In particular, the reduced volume at later times <img src='http://s0.wp.com/latex.php?latex=t_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_1' title='t_1' class='latex' /> is bounded from below by the reduced volume at time 0 (which is the implication <img src='http://s0.wp.com/latex.php?latex=%282%29+%5Cimplies+%283%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(2) &#92;implies (3)' title='(2) &#92;implies (3)' class='latex' />).</p>
<p style="text-align:center;">&#8211; Heuristic analysis &#8211;</p>
<p>In the case of the trivial Euclidean flow, the reduced length is given by the formula</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=l_%7B%28t_0%2Cx_0%29%7D%28t_1%2Cx_1%29+%3D+%5Cfrac%7B%26%23124%3Bx_1-x_0%26%23124%3B%5E2%7D%7B4%5Ctau_1%7D+%3D+%5Cfrac%7B%26%23124%3Bx_1-x_0%26%23124%3B%5E2%7D%7B4%28t_1-t_0%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_{(t_0,x_0)}(t_1,x_1) = &#92;frac{&#124;x_1-x_0&#124;^2}{4&#92;tau_1} = &#92;frac{&#124;x_1-x_0&#124;^2}{4(t_1-t_0)}' title='l_{(t_0,x_0)}(t_1,x_1) = &#92;frac{&#124;x_1-x_0&#124;^2}{4&#92;tau_1} = &#92;frac{&#124;x_1-x_0&#124;^2}{4(t_1-t_0)}' class='latex' /> (8)</p>
<p style="text-align:left;">with the minimising geodesic given by the formula</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cgamma%28%5Ctau%29+%3D+x_0+%2B+2v+%5Csqrt%7B%5Ctau%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma(&#92;tau) = x_0 + 2v &#92;sqrt{&#92;tau}' title='&#92;gamma(&#92;tau) = x_0 + 2v &#92;sqrt{&#92;tau}' class='latex' /> with <img src='http://s0.wp.com/latex.php?latex=v+%3A%3D+%5Cfrac%7Bx_1-x_0%7D%7B2%5Csqrt%7B%5Ctau_1%7D%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='v := &#92;frac{x_1-x_0}{2&#92;sqrt{&#92;tau_1}}' title='v := &#92;frac{x_1-x_0}{2&#92;sqrt{&#92;tau_1}}' class='latex' /> (9)</p>
<p>Here, we briefly argue why we expect heuristically to have a similar relationship</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=l_%7B%28t_0%2Cx_0%29%7D%28t_1%2Cx_1%29+%5Capprox+%5Cfrac%7Bd_%7Bg%28t_1%29%7D%28+x_0%2C+x_1+%29%5E2%7D%7B%5Ctau_1%7D+%2B+O%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_{(t_0,x_0)}(t_1,x_1) &#92;approx &#92;frac{d_{g(t_1)}( x_0, x_1 )^2}{&#92;tau_1} + O(1)' title='l_{(t_0,x_0)}(t_1,x_1) &#92;approx &#92;frac{d_{g(t_1)}( x_0, x_1 )^2}{&#92;tau_1} + O(1)' class='latex' /> (10)</p>
<p>for the reduced length on more general Ricci flows, under an assumption of bounded normalised curvature.</p>
<p>Specifically, suppose that we have a normalised curvature bound <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Chbox%7BRiem%7D%26%23124%3B_g+%3D+O%281%2F%5Ctau_1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;hbox{Riem}&#124;_g = O(1/&#92;tau_1)' title='&#124;&#92;hbox{Riem}&#124;_g = O(1/&#92;tau_1)' class='latex' />.  Then we have <img src='http://s0.wp.com/latex.php?latex=%5Cdot+g+%3D+-+2%5Chbox%7BRic%7D+%3D+O%28+g+%2F+%5Ctau_1+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;dot g = - 2&#92;hbox{Ric} = O( g / &#92;tau_1 )' title='&#92;dot g = - 2&#92;hbox{Ric} = O( g / &#92;tau_1 )' class='latex' />, and so over the time scale <img src='http://s0.wp.com/latex.php?latex=%5Ctau_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau_1' title='&#92;tau_1' class='latex' />, we see that the metric only changes by a multiplicative constant.   If we ignore such constants for now, we see that the distance function <img src='http://s0.wp.com/latex.php?latex=d_%7Bg%28t%29%7D%28x%2C+y%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d_{g(t)}(x, y)' title='d_{g(t)}(x, y)' class='latex' /> does not change much over the time interval of interest.</p>
<p>Let <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' /> be a minimising <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-geodesic from <img src='http://s0.wp.com/latex.php?latex=%28t_0%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_0,x_0)' title='(t_0,x_0)' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=%28t_1%2Cx_1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_1,x_1)' title='(t_1,x_1)' class='latex' />.  This path has to traverse a distance roughly <img src='http://s0.wp.com/latex.php?latex=d_%7Bg%28t_1%29%7D%28x_0%2Cx_1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d_{g(t_1)}(x_0,x_1)' title='d_{g(t_1)}(x_0,x_1)' class='latex' /> in time <img src='http://s0.wp.com/latex.php?latex=%5Ctau_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau_1' title='&#92;tau_1' class='latex' />, and so its speed <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Cdot+%5Cgamma%26%23124%3B_g&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;dot &#92;gamma&#124;_g' title='&#124;&#92;dot &#92;gamma&#124;_g' class='latex' /> should be at least <img src='http://s0.wp.com/latex.php?latex=d_%7Bg%28t_1%29%7D%28x_0%2Cx_1%29+%2F+%5Ctau_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d_{g(t_1)}(x_0,x_1) / &#92;tau_1' title='d_{g(t_1)}(x_0,x_1) / &#92;tau_1' class='latex' />.  Also, the scalar curvature R should be <img src='http://s0.wp.com/latex.php?latex=O%281%2F%5Ctau_1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='O(1/&#92;tau_1)' title='O(1/&#92;tau_1)' class='latex' /> by the bounded normalised curvature assumption.  Putting all this into (5) and (6) we heuristically obtain (10).</p>
<p>From (10), we expect the expression <img src='http://s0.wp.com/latex.php?latex=e%5E%7B-l_%7B%28t_0%2Cx_0%29%7D%28t_1%2Cx_1%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='e^{-l_{(t_0,x_0)}(t_1,x_1)}' title='e^{-l_{(t_0,x_0)}(t_1,x_1)}' class='latex' /> to be comparable to 1 when <img src='http://s0.wp.com/latex.php?latex=x_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_1' title='x_1' class='latex' /> is inside the ball <img src='http://s0.wp.com/latex.php?latex=B_%7Bg%28t_1%29%7D%28x_0%2C+O%28+%5Csqrt%7Bt_1%7D+%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_{g(t_1)}(x_0, O( &#92;sqrt{t_1} ))' title='B_{g(t_1)}(x_0, O( &#92;sqrt{t_1} ))' class='latex' />, and to be exponentially small outside of this ball.  Using (7), we thus obtain a heuristic approximation for the Perelman reduced volume:</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Ctilde+V_%7B%28t_0%2Cx_0%29%7D%28%5Ctau_1%29+%5Capprox+%5Chbox%7BVol%7D_%7Bg%28t_1%29%7D%28x_0%2C+%5Csqrt%7B%5Ctau_1%7D+%29+%2F+%5Ctau_1%5E%7Bd%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde V_{(t_0,x_0)}(&#92;tau_1) &#92;approx &#92;hbox{Vol}_{g(t_1)}(x_0, &#92;sqrt{&#92;tau_1} ) / &#92;tau_1^{d/2}' title='&#92;tilde V_{(t_0,x_0)}(&#92;tau_1) &#92;approx &#92;hbox{Vol}_{g(t_1)}(x_0, &#92;sqrt{&#92;tau_1} ) / &#92;tau_1^{d/2}' class='latex' />. (11)</p>
<p>Thus the Perelman reduced volume <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+V_%7B%28t_0%2Cx_0%29%7D%28%5Ctau_1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde V_{(t_0,x_0)}(&#92;tau_1)' title='&#92;tilde V_{(t_0,x_0)}(&#92;tau_1)' class='latex' /> is heuristically equivalent to the Bishop-Gromov reduced volume at <img src='http://s0.wp.com/latex.php?latex=%28x_1%2Ct_1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(x_1,t_1)' title='(x_1,t_1)' class='latex' /> at scale <img src='http://s0.wp.com/latex.php?latex=%5Ctau_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau_1' title='&#92;tau_1' class='latex' />.  Since the latter measures non-collapsing, we heuristically obtain the implications <img src='http://s0.wp.com/latex.php?latex=%281%29+%5Cimplies+%282%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(1) &#92;implies (2)' title='(1) &#92;implies (2)' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%283%29+%5Cimplies+%284%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(3) &#92;implies (4)' title='(3) &#92;implies (4)' class='latex' />.</p>
<p style="text-align:center;">&#8211; From non-collapsing to lower bounds on reduced volume &#8211;</p>
<p>Now we discuss implications of the form <img src='http://s0.wp.com/latex.php?latex=%281%29+%5Cimplies+%282%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(1) &#92;implies (2)' title='(1) &#92;implies (2)' class='latex' /> in more detail.  Specifically, we show</p>
<blockquote><p><strong>Proposition 1. </strong> Let <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> be a d-dimensional Ricci flow on a complete manifold M for <img src='http://s0.wp.com/latex.php?latex=t+%5Cin+%5B0%2CT%5D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;in [0,T]' title='t &#92;in [0,T]' class='latex' /> such that we have the normalised initial conditions <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Chbox%7BRiem%7D%280%2Cx%29%26%23124%3B_g+%5Cleq+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;hbox{Riem}(0,x)&#124;_g &#92;leq 1' title='&#124;&#92;hbox{Riem}(0,x)&#124;_g &#92;leq 1' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BVol%7D_%7Bg%280%29%7D%28B_%7Bg%280%29%7D%28x%2C1%29%29+%5Cgeq+%5Comega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Vol}_{g(0)}(B_{g(0)}(x,1)) &#92;geq &#92;omega' title='&#92;hbox{Vol}_{g(0)}(B_{g(0)}(x,1)) &#92;geq &#92;omega' class='latex' /> at time t=0 for some <img src='http://s0.wp.com/latex.php?latex=%5Comega+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;omega &gt; 0' title='&#92;omega &gt; 0' class='latex' /> and all x (so in particular, the geometry is non-collapsed at scale 1 at all points at time zero).  Then we have <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+V_%7B%28t_0%2Cx_0%29%7D%28t_0%29+%5Cgeq+c&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde V_{(t_0,x_0)}(t_0) &#92;geq c' title='&#92;tilde V_{(t_0,x_0)}(t_0) &#92;geq c' class='latex' /> for some <img src='http://s0.wp.com/latex.php?latex=c+%3D+c%28d%2C%5Comega%2CT%29+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='c = c(d,&#92;omega,T) &gt; 0' title='c = c(d,&#92;omega,T) &gt; 0' class='latex' /> and all <img src='http://s0.wp.com/latex.php?latex=%28t_0%2Cx_0%29+%5Cin+%280%2CT%29+%5Ctimes+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_0,x_0) &#92;in (0,T) &#92;times M' title='(t_0,x_0) &#92;in (0,T) &#92;times M' class='latex' />.</p></blockquote>
<p>The main task in proving implications of the form <img src='http://s0.wp.com/latex.php?latex=%281%29+%5Cimplies+%282%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(1) &#92;implies (2)' title='(1) &#92;implies (2)' class='latex' /> is to show the existence of some large ball at time zero on which <img src='http://s0.wp.com/latex.php?latex=l+%3D+l_%7B%28t_0%2Cx_0%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l = l_{(t_0,x_0)}' title='l = l_{(t_0,x_0)}' class='latex' /> is bounded from above.</p>
<p>Turning to the specific proposition above, we first observe that we can reduce to the large time case <img src='http://s0.wp.com/latex.php?latex=t_0+%5Cgeq+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_0 &#92;geq 1' title='t_0 &#92;geq 1' class='latex' />.  Indeed, if <img src='http://s0.wp.com/latex.php?latex=0+%26%2360%3B+t_0+%26%2360%3B+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &lt; t_0 &lt; 1' title='0 &lt; t_0 &lt; 1' class='latex' />, then we can rescale the Ricci flow until <img src='http://s0.wp.com/latex.php?latex=t_0+%3D+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_0 = 1' title='t_0 = 1' class='latex' /> (this increases T, but we can simply truncate T to compensate for this).  This rescaling reduces the size of the initial Riemann curvature, and the volume of balls of unit radius are still bounded from below thanks to the <a href="http://en.wikipedia.org/wiki/Bishop%E2%80%93Gromov_inequality">Bishop-Gromov inequality</a>.</p>
<p>The next observation we need is that the control on the geometry at time zero persists for a short amount of additional time:</p>
<blockquote><p><strong>Lemma 1.</strong> (Local persistence of controlled geometry) Let the hypotheses be as in Proposition 1.  Then there exists an absolute constant c &#62; 0 (depending only on d) such that <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Chbox%7BRiem%7D%28t%2Cx%29%26%23124%3B_g+%5Cleq+2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;hbox{Riem}(t,x)&#124;_g &#92;leq 2' title='&#124;&#92;hbox{Riem}(t,x)&#124;_g &#92;leq 2' class='latex' /> for all times <img src='http://s0.wp.com/latex.php?latex=0+%5Cleq+t+%5Cleq+c&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &#92;leq t &#92;leq c' title='0 &#92;leq t &#92;leq c' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=x+%5Cin+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x &#92;in M' title='x &#92;in M' class='latex' />.  Also we have <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BVol%7D_%7Bg%28t%29%7D%28B_%7Bg%28t%29%7D%28x%2C1%29%29+%5Cge+%5Comega%27&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Vol}_{g(t)}(B_{g(t)}(x,1)) &#92;ge &#92;omega&#039;' title='&#92;hbox{Vol}_{g(t)}(B_{g(t)}(x,1)) &#92;ge &#92;omega&#039;' class='latex' /> for all <img src='http://s0.wp.com/latex.php?latex=0+%5Cleq+t+%5Cleq+c&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &#92;leq t &#92;leq c' title='0 &#92;leq t &#92;leq c' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=x+%5Cin+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x &#92;in M' title='x &#92;in M' class='latex' />, and some <img src='http://s0.wp.com/latex.php?latex=%5Comega%27+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;omega&#039; &gt; 0' title='&#92;omega&#039; &gt; 0' class='latex' /> depending only on <img src='http://s0.wp.com/latex.php?latex=%5Comega%2C+d&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;omega, d' title='&#92;omega, d' class='latex' />.</p></blockquote>
<p><strong>Proof.</strong> We recall the nonlinear heat equation</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+%5Chbox%7BRiem%7D+%3D+%5CDelta+%5Chbox%7BRiem%7D+%2B+%7B%5Cmathcal+O%7D%28+g%5E%7B-1%7D+%5Chbox%7BRiem%7D%5E2+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t &#92;hbox{Riem} = &#92;Delta &#92;hbox{Riem} + {&#92;mathcal O}( g^{-1} &#92;hbox{Riem}^2 )' title='&#92;partial_t &#92;hbox{Riem} = &#92;Delta &#92;hbox{Riem} + {&#92;mathcal O}( g^{-1} &#92;hbox{Riem}^2 )' class='latex' /> (12)</p>
<p>for the Riemann curvature tensor <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRiem%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Riem}' title='&#92;hbox{Riem}' class='latex' /> under Ricci flow (see equation (31) of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/03/28/285g-lecture-1-ricci-flow/">Lecture 1</a>).  The bound on Riemann curvature can then obtained by an application of Hamilton&#8217;s maximum principle (Proposition 1 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/04/285g-lecture-3-the-maximum-principle-and-the-pinching-phenomenon/">Lecture 3</a>); we leave this as an exercise to the reader.  [Technically, one needs to first generalise the maximum principle from compact manifolds to complete manifolds of bounded curvature.  This can be done using barrier functions, but it is somewhat technically involved: see Chapter 12 of <a href="http://www.ams.org/mathscinet-getitem?mr=2365237">Chow et al.</a> for details.]  As in the heuristic discussion, the bounds on the Riemann curvature (and hence the Ricci curvature) show that the metric g and the distance function <img src='http://s0.wp.com/latex.php?latex=d_%7Bg%28t%29%7D%28x%2Cy%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d_{g(t)}(x,y)' title='d_{g(t)}(x,y)' class='latex' /> only change by at most a multiplicative constant; this also implies that the volume measure only changes by a multiplicative constant as well.  From this we see that the lower bound on the volume of unit balls at time zero implies a lower bound on the volume of balls of radius O(1) at times <img src='http://s0.wp.com/latex.php?latex=0+%5Cleq+t+%5Cleq+c&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &#92;leq t &#92;leq c' title='0 &#92;leq t &#92;leq c' class='latex' />; one can then get back to balls of radius 1 by invoking the Bishop-Gromov inequality. <img src='http://s0.wp.com/latex.php?latex=%5CBox&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Box' title='&#92;Box' class='latex' /></p>
<p>The next task is to find a point <img src='http://s0.wp.com/latex.php?latex=y+%5Cin+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y &#92;in M' title='y &#92;in M' class='latex' /> such that the reduced length from <img src='http://s0.wp.com/latex.php?latex=%28t_0%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_0,x_0)' title='(t_0,x_0)' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=%280%2Cy%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(0,y)' title='(0,y)' class='latex' /> is small, since this should force y (and the points close to y) to give a large contribution to the reduced volume.  In the Euclidean case, one would just take <img src='http://s0.wp.com/latex.php?latex=y+%3D+x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y = x_0' title='y = x_0' class='latex' /> (see (8)), but this does not necessarily work for general Ricci flows: note from (5), (6) that the reduced length from <img src='http://s0.wp.com/latex.php?latex=%28t_0%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_0,x_0)' title='(t_0,x_0)' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=%28t_1%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_1,x_0)' title='(t_1,x_0)' class='latex' /> could in principle be as large as</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7B1%7D%7B2%5Csqrt%7Bt_0-t_1%7D%7D+%5Cint_0%5E%7Bt_0-t_1%7D+%5Csqrt%7B%5Ctau%7D+R%28t_0-%5Ctau%2Cx_0%29%5C+d%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{1}{2&#92;sqrt{t_0-t_1}} &#92;int_0^{t_0-t_1} &#92;sqrt{&#92;tau} R(t_0-&#92;tau,x_0)&#92; d&#92;tau' title='&#92;displaystyle &#92;frac{1}{2&#92;sqrt{t_0-t_1}} &#92;int_0^{t_0-t_1} &#92;sqrt{&#92;tau} R(t_0-&#92;tau,x_0)&#92; d&#92;tau' class='latex' />, (13)</p>
<p>which could be quite large if the scalar curvature becomes large and positive (which is certainly within the realm of possibility, especially if one is approaching a singularity).</p>
<p>Fortunately, we can use the parabolic properties of the reduced length <img src='http://s0.wp.com/latex.php?latex=l+%3D+l_%7B%28t_0%2Cx_0%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l = l_{(t_0,x_0)}' title='l = l_{(t_0,x_0)}' class='latex' />, combined with the maximum principle, to locate a good point y with the required properties.  From the analysis of the <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/09/285g-lecture-10-variation-of-l-geodesics-and-monotonicity-of-perelman-reduced-volume/">previous lecture</a>, and some rescaling and time translation, we obtain the identities and inequalities</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cnabla+l+%3D+X&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;nabla l = X' title='&#92;displaystyle &#92;nabla l = X' class='latex' /> (14)</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cpartial_%5Ctau+l+%3D+%5Cfrac%7B1%7D%7B2%7D+R+-+%5Cfrac%7B1%7D%7B2%7D+%26%23124%3BX%26%23124%3B_g%5E2+-+%5Cfrac%7B1%7D%7B2%5Ctau%7D+l&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;partial_&#92;tau l = &#92;frac{1}{2} R - &#92;frac{1}{2} &#124;X&#124;_g^2 - &#92;frac{1}{2&#92;tau} l' title='&#92;displaystyle &#92;partial_&#92;tau l = &#92;frac{1}{2} R - &#92;frac{1}{2} &#124;X&#124;_g^2 - &#92;frac{1}{2&#92;tau} l' class='latex' /> (15)</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5CDelta+l+%5Cleq+%5Cfrac%7Bd%7D%7B2%5Ctau%7D+%2B+%5Cfrac%7B1%7D%7B2%7D+%26%23124%3BX%26%23124%3B_g%5E2+-+%5Cfrac%7B1%7D%7B2%7D+R+-+%5Cfrac%7B1%7D%7B2%5Ctau%7D+l&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;Delta l &#92;leq &#92;frac{d}{2&#92;tau} + &#92;frac{1}{2} &#124;X&#124;_g^2 - &#92;frac{1}{2} R - &#92;frac{1}{2&#92;tau} l' title='&#92;displaystyle &#92;Delta l &#92;leq &#92;frac{d}{2&#92;tau} + &#92;frac{1}{2} &#124;X&#124;_g^2 - &#92;frac{1}{2} R - &#92;frac{1}{2&#92;tau} l' class='latex' /> (16)</p>
<p>(cf. equations (29), (33), (47) from the <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/09/285g-lecture-10-variation-of-l-geodesics-and-monotonicity-of-perelman-reduced-volume/">previous lecture</a>), where <img src='http://s0.wp.com/latex.php?latex=X+%3D+%5Cgamma%27%28%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='X = &#92;gamma&#039;(&#92;tau)' title='X = &#92;gamma&#039;(&#92;tau)' class='latex' /> is the final velocity vector of the minimising <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-geodesic from <img src='http://s0.wp.com/latex.php?latex=%28t_0%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_0,x_0)' title='(t_0,x_0)' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=%28t_1%2Cx_1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_1,x_1)' title='(t_1,x_1)' class='latex' />.  [We only derived (14)-(16) rigorously inside the domain of injectivity, but as discussed in the <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/09/285g-lecture-10-variation-of-l-geodesics-and-monotonicity-of-perelman-reduced-volume/">previous lecture</a>, one can establish the above inequalities in the sense of distributions on the whole manifold M.]  From (15), (16) we obtain in particular that l is a supersolution of a heat equation:</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cpartial_t+l+%5Cgeq+%5CDelta+l+%2B+%5Cfrac%7Bl-%28d%2F2%29%7D%7B%5Ctau%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;partial_t l &#92;geq &#92;Delta l + &#92;frac{l-(d/2)}{&#92;tau}' title='&#92;displaystyle &#92;partial_t l &#92;geq &#92;Delta l + &#92;frac{l-(d/2)}{&#92;tau}' class='latex' />. (17)</p>
<p>[Note that (17) holds with equality in the Euclidean case (8).] From the maximum principle (Corollary 1 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/04/285g-lecture-3-the-maximum-principle-and-the-pinching-phenomenon/">Lecture 3</a>), we see that if we have the uniform lower bound <img src='http://s0.wp.com/latex.php?latex=l+%5Cgeq+d%2F2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l &#92;geq d/2' title='l &#92;geq d/2' class='latex' /> at some time <img src='http://s0.wp.com/latex.php?latex=0+%5Cleq+t+%26%2360%3B+t_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &#92;leq t &lt; t_0' title='0 &#92;leq t &lt; t_0' class='latex' />, then this bound will persist for all times between t and <img src='http://s0.wp.com/latex.php?latex=t_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_0' title='t_0' class='latex' />.  On the other hand, by using the upper bound (12) for <img src='http://s0.wp.com/latex.php?latex=l%28t_1%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l(t_1,x_0)' title='l(t_1,x_0)' class='latex' /> we see that the bound <img src='http://s0.wp.com/latex.php?latex=l+%5Cgeq+d%2F2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l &#92;geq d/2' title='l &#92;geq d/2' class='latex' /> breaks down for times t sufficiently close to <img src='http://s0.wp.com/latex.php?latex=t_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_0' title='t_0' class='latex' />.  We therefore conclude that <img src='http://s0.wp.com/latex.php?latex=%5Cinf_%7Bx+%5Cin+M%7D+l%28t%2Cx%29+%26%2360%3B+d%2F2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;inf_{x &#92;in M} l(t,x) &lt; d/2' title='&#92;inf_{x &#92;in M} l(t,x) &lt; d/2' class='latex' /> for all <img src='http://s0.wp.com/latex.php?latex=0+%5Cleq+t+%26%2360%3B+t_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &#92;leq t &lt; t_0' title='0 &#92;leq t &lt; t_0' class='latex' />.  In particular we can find a point y such that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=l%28c%2Cy%29+%26%2360%3B+d%2F2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l(c,y) &lt; d/2' title='l(c,y) &lt; d/2' class='latex' />, (18)</p>
<p style="text-align:left;">where c is the small constant in Lemma 1.  Given the bounded geometry control in Lemma 1 (and in particular the fact that g(t) is comparable to g(0) for <img src='http://s0.wp.com/latex.php?latex=0+%5Cleq+t+%5Cleq+c&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &#92;leq t &#92;leq c' title='0 &#92;leq t &#92;leq c' class='latex' />), it is thus not hard to see (by concatenating the minimising path from <img src='http://s0.wp.com/latex.php?latex=%280%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(0,x_0)' title='(0,x_0)' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=%28c%2Cy%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(c,y)' title='(c,y)' class='latex' /> with a geodesic segment (in the g(0) metric) from <img src='http://s0.wp.com/latex.php?latex=%28c%2Cy%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(c,y)' title='(c,y)' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=%280%2Cy%27%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(0,y&#039;)' title='(0,y&#039;)' class='latex' />) that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=l%280%2C+y%27%29+%5Cleq+C+%5Chbox%7B+for+%7D+y%27+%5Cin+B_%7Bg%280%29%7D%28y%2C+c%27%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l(0, y&#039;) &#92;leq C &#92;hbox{ for } y&#039; &#92;in B_{g(0)}(y, c&#039;)' title='l(0, y&#039;) &#92;leq C &#92;hbox{ for } y&#039; &#92;in B_{g(0)}(y, c&#039;)' class='latex' /> (19)</p>
<p style="text-align:left;">for some <img src='http://s0.wp.com/latex.php?latex=C%2C+c%27+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C, c&#039; &gt; 0' title='C, c&#039; &gt; 0' class='latex' /> depending only on d, where.  The hypotheses on the geometry of g(0), combined with the Bishop-Gromov inequality, give a uniform lower bound for the volume of <img src='http://s0.wp.com/latex.php?latex=B_%7Bg%280%29%7D%28y%2Cc%27%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_{g(0)}(y,c&#039;)' title='B_{g(0)}(y,c&#039;)' class='latex' />, and Proposition 1 now follows directly from the definition (7) of reduced volume.</p>
<p style="text-align:center;">&#8211; From lower bounds on reduced volume to non-collapsing &#8211;</p>
<p style="text-align:left;">Now we consider the reverse type of implication <img src='http://s0.wp.com/latex.php?latex=%283%29+%5Cimplies+%284%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(3) &#92;implies (4)' title='(3) &#92;implies (4)' class='latex' /> from those just discussed.  Here, the task is reversed; rather than establishing <em>upper</em> bounds on l on a ball of radius comparable to one, the main challenge is now to establish <em>lower</em> bounds (of the form <img src='http://s0.wp.com/latex.php?latex=l+%5Cgeq+-O%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l &#92;geq -O(1)' title='l &#92;geq -O(1)' class='latex' />) on l on such a ball, as well as some growth bounds on l away from this ball.</p>
<p style="text-align:left;">We begin by formally stating the result of the form <img src='http://s0.wp.com/latex.php?latex=%283%29+%5Cimplies+%284%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(3) &#92;implies (4)' title='(3) &#92;implies (4)' class='latex' /> that we shall establish.</p>
<blockquote>
<p style="text-align:left;"><strong>Proposition 2.</strong> Let <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> be a d-dimensional Ricci flow on a complete manifold M for <img src='http://s0.wp.com/latex.php?latex=t+%5Cin+%5B0%2CT%5D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;in [0,T]' title='t &#92;in [0,T]' class='latex' />, and let <img src='http://s0.wp.com/latex.php?latex=0+%5Cleq+t_0-r_0%5E2+%5Cleq+t_0+%5Cleq+T&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &#92;leq t_0-r_0^2 &#92;leq t_0 &#92;leq T' title='0 &#92;leq t_0-r_0^2 &#92;leq t_0 &#92;leq T' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=x_0+%5Cin+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0 &#92;in M' title='x_0 &#92;in M' class='latex' /> be such that <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Chbox%7BRiem%7D%28t%2Cx%29%26%23124%3B_g+%5Cleq+r_0%5E%7B-2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;hbox{Riem}(t,x)&#124;_g &#92;leq r_0^{-2}' title='&#124;&#92;hbox{Riem}(t,x)&#124;_g &#92;leq r_0^{-2}' class='latex' /> for <img src='http://s0.wp.com/latex.php?latex=x+%5Cin+B_%7Bg%28t_0%29%7D%28x_0%2Cr_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x &#92;in B_{g(t_0)}(x_0,r_0)' title='x &#92;in B_{g(t_0)}(x_0,r_0)' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=t+%5Cin+%5Bt_0-r_0%5E2%2Ct_0%5D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;in [t_0-r_0^2,t_0]' title='t &#92;in [t_0-r_0^2,t_0]' class='latex' />, and such that <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+V_%7B%28t_0%2Cx_0%29%7D%28%5Ctau%29+%5Cgeq+%5Cdelta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde V_{(t_0,x_0)}(&#92;tau) &#92;geq &#92;delta' title='&#92;tilde V_{(t_0,x_0)}(&#92;tau) &#92;geq &#92;delta' class='latex' /> for some <img src='http://s0.wp.com/latex.php?latex=%5Cdelta+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta &gt; 0' title='&#92;delta &gt; 0' class='latex' /> and all <img src='http://s0.wp.com/latex.php?latex=0+%26%2360%3B+%5Ctau+%26%2360%3B+r_0%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &lt; &#92;tau &lt; r_0^2' title='0 &lt; &#92;tau &lt; r_0^2' class='latex' />.  Then one has <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BVol%7D_%7Bg%28t_0%29%7D%28+B_%7Bg%28t_0%29%7D%28x_0%2Cr_0%29+%29+%5Cgeq+c&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Vol}_{g(t_0)}( B_{g(t_0)}(x_0,r_0) ) &#92;geq c' title='&#92;hbox{Vol}_{g(t_0)}( B_{g(t_0)}(x_0,r_0) ) &#92;geq c' class='latex' /> for some c depending only on d and <img src='http://s0.wp.com/latex.php?latex=%5Cdelta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta' title='&#92;delta' class='latex' />.</p>
</blockquote>
<p style="text-align:left;"><strong>Exercise 1.</strong> Use Proposition 1, Proposition 2, and the monotonicity of Perelman reduced volume to deduce Theorem 2 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/20/285g-lecture-7-rescaling-of-ricci-flows-and-kappa-noncollapsing/">Lecture 7</a>. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;">We now prove Proposition 2.  We first observe by time translation (and by removing the portion of the Ricci flow below <img src='http://s0.wp.com/latex.php?latex=t_0-r_0%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_0-r_0^2' title='t_0-r_0^2' class='latex' /> that we may normalise <img src='http://s0.wp.com/latex.php?latex=t_0-r_0%5E2%3D0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_0-r_0^2=0' title='t_0-r_0^2=0' class='latex' />, and then by scaling we may normalise <img src='http://s0.wp.com/latex.php?latex=t_0+%3D+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_0 = 1' title='t_0 = 1' class='latex' />.  Thus we now have a Ricci flow on [0,1] with <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Chbox%7BRiem%7D%28t%2Cx%29%26%23124%3B_g+%5Cleq+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;hbox{Riem}(t,x)&#124;_g &#92;leq 1' title='&#124;&#92;hbox{Riem}(t,x)&#124;_g &#92;leq 1' class='latex' /> on <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5B0%2C1%5D+%5Ctimes+B_%7Bg%281%29%7D%28x_0%2C1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[0,1] &#92;times B_{g(1)}(x_0,1)' title='{}[0,1] &#92;times B_{g(1)}(x_0,1)' class='latex' /> and</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Ctilde+V_%7B%281%2Cx_0%29%7D%28%5Ctau%29+%3D+%5Cint_M+e%5E%7B-l%28%5Ctau%2Cx%29%7D%5C+d%5Cmu_%7Bg%28%5Ctau%29%7D%28x%29+%5Cgeq+%5Cdelta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;tilde V_{(1,x_0)}(&#92;tau) = &#92;int_M e^{-l(&#92;tau,x)}&#92; d&#92;mu_{g(&#92;tau)}(x) &#92;geq &#92;delta' title='&#92;displaystyle &#92;tilde V_{(1,x_0)}(&#92;tau) = &#92;int_M e^{-l(&#92;tau,x)}&#92; d&#92;mu_{g(&#92;tau)}(x) &#92;geq &#92;delta' class='latex' /> (20)</p>
<p style="text-align:left;">for all <img src='http://s0.wp.com/latex.php?latex=0+%26%2360%3B+%5Ctau+%5Cleq+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &lt; &#92;tau &#92;leq 1' title='0 &lt; &#92;tau &#92;leq 1' class='latex' />, where <img src='http://s0.wp.com/latex.php?latex=l+%3D+l_%7B%281%2Cx_0%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l = l_{(1,x_0)}' title='l = l_{(1,x_0)}' class='latex' /> is the reduced length function.  Our task is to show that <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BVol%7D_%7Bg%281%29%7D%28+B_%7Bg%281%29%7D%28x_0%2C1%29+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Vol}_{g(1)}( B_{g(1)}(x_0,1) )' title='&#92;hbox{Vol}_{g(1)}( B_{g(1)}(x_0,1) )' class='latex' /> is bounded away from zero.</p>
<p style="text-align:left;">We first observe (as in Lemma 1) that the metrics g(t) for <img src='http://s0.wp.com/latex.php?latex=0+%5Cleq+t+%5Cleq+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &#92;leq t &#92;leq 1' title='0 &#92;leq t &#92;leq 1' class='latex' /> are all comparable to each other up to multiplicative constants on <img src='http://s0.wp.com/latex.php?latex=B_%7Bg%281%29%7D%28x_0%2C1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_{g(1)}(x_0,1)' title='B_{g(1)}(x_0,1)' class='latex' />, and so the balls in these metrics also differ only up to multiplicative constants.</p>
<p style="text-align:left;">Next, we would like to localise the reduced volume (20) to the ball <img src='http://s0.wp.com/latex.php?latex=B_%7Bg%281%29%7D%28x_0%2C1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_{g(1)}(x_0,1)' title='B_{g(1)}(x_0,1)' class='latex' /> (since this is the only place where we really control the geometry).  To do this it is convenient to work in the parabolic counterpart of normal coordinates around <img src='http://s0.wp.com/latex.php?latex=%281%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(1,x_0)' title='(1,x_0)' class='latex' /> and exploit the pointwise version of the Perelman reduced volume monotonicity.  To motivate this, recall from the pointwise inequality</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D_%7B%5Cpartial+r%7D+d%5Cmu+%5Cleq+%5Cfrac%7Bd-1%7D%7Br%7D%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}_{&#92;partial r} d&#92;mu &#92;leq &#92;frac{d-1}{r}&#92; d&#92;mu' title='{&#92;mathcal L}_{&#92;partial r} d&#92;mu &#92;leq &#92;frac{d-1}{r}&#92; d&#92;mu' class='latex' /> (21)</p>
<p style="text-align:left;">that we had the Bishop-Gromov inequality</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cpartial_r+r%5E%7B-%28d-1%29%7D+%5Cint_%7BS%28x_0%2Cr%29%7D%5C+dS+%5Cleq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;partial_r r^{-(d-1)} &#92;int_{S(x_0,r)}&#92; dS &#92;leq 0' title='&#92;displaystyle &#92;partial_r r^{-(d-1)} &#92;int_{S(x_0,r)}&#92; dS &#92;leq 0' class='latex' /> (21&#8242;)</p>
<p style="text-align:left;">where <img src='http://s0.wp.com/latex.php?latex=S%28x_0%2Cr%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S(x_0,r)' title='S(x_0,r)' class='latex' /> is the sphere of radius r centred at <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' /> with area element dS.  Indeed, we can rewrite the left-hand side of (21&#8242;) as</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cpartial_r+r%5E%7B-%28d-1%29%7D+%5Cint_%7BS%5E%7Bd-1%7D%7D+J_r%28+%5Comega+%29%5C+d%5Comega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;partial_r r^{-(d-1)} &#92;int_{S^{d-1}} J_r( &#92;omega )&#92; d&#92;omega' title='&#92;displaystyle &#92;partial_r r^{-(d-1)} &#92;int_{S^{d-1}} J_r( &#92;omega )&#92; d&#92;omega' class='latex' /> (22)</p>
<p style="text-align:left;">where <img src='http://s0.wp.com/latex.php?latex=S%5E%7Bd-1%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^{d-1}' title='S^{d-1}' class='latex' /> is the standard sphere with the standard area element <img src='http://s0.wp.com/latex.php?latex=d%5Comega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d&#92;omega' title='d&#92;omega' class='latex' />, and <img src='http://s0.wp.com/latex.php?latex=J_r&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='J_r' title='J_r' class='latex' /> is the <a href="http://en.wikipedia.org/wiki/Jacobian">Jacobian</a> of the exponential map <img src='http://s0.wp.com/latex.php?latex=%5Comega+%5Cmapsto+%5Cexp_%7Bx_0%7D%28r+%5Comega%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;omega &#92;mapsto &#92;exp_{x_0}(r &#92;omega)' title='&#92;omega &#92;mapsto &#92;exp_{x_0}(r &#92;omega)' class='latex' />; in the Euclidean case, <img src='http://s0.wp.com/latex.php?latex=J_r%28%5Comega%29+%3D+r%5E%7Bd-1%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='J_r(&#92;omega) = r^{d-1}' title='J_r(&#92;omega) = r^{d-1}' class='latex' />.   [Actually, once the radius r exceeds the injectivity radius, one has to restrict to the portion of <img src='http://s0.wp.com/latex.php?latex=S%5E%7Bd-1%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^{d-1}' title='S^{d-1}' class='latex' /> that has not yet encountered the <a href="http://en.wikipedia.org/wiki/Cut_locus_%28Riemannian_manifold%29">cut locus</a>, but let us ignore this technical issue for now.]  The inequality (21) (when combined with the <a href="http://en.wikipedia.org/wiki/Gauss%27s_lemma_%28Riemannian_geometry%29">Gauss lemma</a>) is equivalent to the pointwise inequality</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cpartial_r+r%5E%7B-%28d-1%29%7D+J_r%28%5Comega%29+%5Cleq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_r r^{-(d-1)} J_r(&#92;omega) &#92;leq 0' title='&#92;partial_r r^{-(d-1)} J_r(&#92;omega) &#92;leq 0' class='latex' /> (23)</p>
<p style="text-align:left;">which certainly implies (22), but also implies the stronger fact that the Bishop-Gromov inequality can be localised to arbitrary sectors in the sense that <img src='http://s0.wp.com/latex.php?latex=r%5E%7B-%28d-1%29%7D+%5Cint_%7B%5COmega%7D+J_r%28%5Comega%29%5C+d%5Comega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r^{-(d-1)} &#92;int_{&#92;Omega} J_r(&#92;omega)&#92; d&#92;omega' title='r^{-(d-1)} &#92;int_{&#92;Omega} J_r(&#92;omega)&#92; d&#92;omega' class='latex' /> (which can be viewed as the Bishop-Gromov reduced volume of the sector <img src='http://s0.wp.com/latex.php?latex=%5C%7B+%5Cexp_%7Bx_0%7D%28r%5Comega%29%3A+%5Comega+%5Cin+%5COmega+%5C%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;{ &#92;exp_{x_0}(r&#92;omega): &#92;omega &#92;in &#92;Omega &#92;}' title='&#92;{ &#92;exp_{x_0}(r&#92;omega): &#92;omega &#92;in &#92;Omega &#92;}' class='latex' />) is non-increasing in <img src='http://s0.wp.com/latex.php?latex=r&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r' title='r' class='latex' />.</p>
<p style="text-align:left;">Now we develop parabolic analogues of the above observations.  Recall from the <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/09/285g-lecture-10-variation-of-l-geodesics-and-monotonicity-of-perelman-reduced-volume/">previous lecture</a> that we have an <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-exponential map <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D%5Cexp_%7B%281%2Cx_0%29%2C%5Ctau_1%7D%3A+T_%7Bx_0%7D+M+%5Cto+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}&#92;exp_{(1,x_0),&#92;tau_1}: T_{x_0} M &#92;to M' title='{&#92;mathcal L}&#92;exp_{(1,x_0),&#92;tau_1}: T_{x_0} M &#92;to M' class='latex' /> for <img src='http://s0.wp.com/latex.php?latex=0+%5Cleq+%5Ctau_1+%5Cleq+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &#92;leq &#92;tau_1 &#92;leq 1' title='0 &#92;leq &#92;tau_1 &#92;leq 1' class='latex' /> that sends a tangent vector v to <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%28%5Ctau_1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma(&#92;tau_1)' title='&#92;gamma(&#92;tau_1)' class='latex' />, where <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%3A+%5B0%2C%5Ctau%5D+%5Cto+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma: [0,&#92;tau] &#92;to M' title='&#92;gamma: [0,&#92;tau] &#92;to M' class='latex' /> is the unique <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-geodesic starting at <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' /> with initial condition <img src='http://s0.wp.com/latex.php?latex=v+%3D+%5Clim_%7B%5Ctau+%5Cto+0%7D+%5Csqrt%7B%5Ctau%7D+X%28%5Ctau%29+%3D+%5Clim_%7B%5Ctau+%5Cto+0%7D+%5Csqrt%7B%5Ctau%7D+%5Cgamma%27%28%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='v = &#92;lim_{&#92;tau &#92;to 0} &#92;sqrt{&#92;tau} X(&#92;tau) = &#92;lim_{&#92;tau &#92;to 0} &#92;sqrt{&#92;tau} &#92;gamma&#039;(&#92;tau)' title='v = &#92;lim_{&#92;tau &#92;to 0} &#92;sqrt{&#92;tau} X(&#92;tau) = &#92;lim_{&#92;tau &#92;to 0} &#92;sqrt{&#92;tau} &#92;gamma&#039;(&#92;tau)' class='latex' />.  In the Euclidean case, this map is given by the formula</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D%5Cexp_%7B%281%2Cx_0%29%2C%5Ctau_1%7D%28v%29%3D+x_0+%2B+2+%28x_1-x_0%29+%5Csqrt%7B%5Ctau_1%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}&#92;exp_{(1,x_0),&#92;tau_1}(v)= x_0 + 2 (x_1-x_0) &#92;sqrt{&#92;tau_1}' title='{&#92;mathcal L}&#92;exp_{(1,x_0),&#92;tau_1}(v)= x_0 + 2 (x_1-x_0) &#92;sqrt{&#92;tau_1}' class='latex' /> (24)</p>
<p style="text-align:left;">as can be seen from (9).  We can then rewrite the reduced volume <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+V_%7B%281%2Cx_0%29%7D%28%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde V_{(1,x_0)}(&#92;tau)' title='&#92;tilde V_{(1,x_0)}(&#92;tau)' class='latex' /> in terms of &#8220;normal coordinates&#8221; as</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Ctilde+V_%7B%281%2Cx_0%29%7D%28%5Ctau%29+%3D+%5Ctau%5E%7B-d%2F2%7D+%5Cint_%7B%7B%5CBbb+R%7D%5Ed%7D+e%5E%7B-l%28%7B%5Cmathcal+L%7D+%5Cexp_%7B%281%2Cx_0%29%2C%5Ctau%7D%28v%29%29%7D+J_%7B%5Ctau%7D%28v%29%5C+dv&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde V_{(1,x_0)}(&#92;tau) = &#92;tau^{-d/2} &#92;int_{{&#92;Bbb R}^d} e^{-l({&#92;mathcal L} &#92;exp_{(1,x_0),&#92;tau}(v))} J_{&#92;tau}(v)&#92; dv' title='&#92;tilde V_{(1,x_0)}(&#92;tau) = &#92;tau^{-d/2} &#92;int_{{&#92;Bbb R}^d} e^{-l({&#92;mathcal L} &#92;exp_{(1,x_0),&#92;tau}(v))} J_{&#92;tau}(v)&#92; dv' class='latex' /> (25)</p>
<p style="text-align:left;">where <img src='http://s0.wp.com/latex.php?latex=J_%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='J_&#92;tau' title='J_&#92;tau' class='latex' /> is the Jacobian of the map <img src='http://s0.wp.com/latex.php?latex=v+%5Cmapsto+%7B%5Cmathcal+L%7D%5Cexp_%7B%281%2Cx_0%29%2C%5Ctau_1%7D%28v%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='v &#92;mapsto {&#92;mathcal L}&#92;exp_{(1,x_0),&#92;tau_1}(v)' title='v &#92;mapsto {&#92;mathcal L}&#92;exp_{(1,x_0),&#92;tau_1}(v)' class='latex' />.  (Again, one has to restrict <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+R%7D%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb R}^d' title='{&#92;Bbb R}^d' class='latex' /> to the portion of the tangent manifold lies inside the injectivity domain, but this domain turns out to be non-increasing in <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' /> (for much the same reason that the region inside the cut locus of a point in a Riemannian manifold is star-shaped) and so this effect works in our favour as far as monotonicity is concerned.)</p>
<p style="text-align:left;">In the <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/05/09/285g-lecture-10-variation-of-l-geodesics-and-monotonicity-of-perelman-reduced-volume/">previous lecture</a> we saw that the monotonicity of Perelman reduced volume followed from the pointwise inequality</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cpartial_%7B%5Ctau%7D+l+-+%5CDelta+l+%2B+%26%23124%3B%5Cnabla+l%26%23124%3B_%7Bg%7D%5E2+-+R+%2B+%5Cfrac%7Bd%7D%7B2%5Ctau%7D+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;partial_{&#92;tau} l - &#92;Delta l + &#124;&#92;nabla l&#124;_{g}^2 - R + &#92;frac{d}{2&#92;tau} &#92;geq 0' title='&#92;displaystyle &#92;partial_{&#92;tau} l - &#92;Delta l + &#124;&#92;nabla l&#124;_{g}^2 - R + &#92;frac{d}{2&#92;tau} &#92;geq 0' class='latex' /> (26)</p>
<p style="text-align:left;">which of course also follows from (14)-(16).</p>
<p style="text-align:left;"><strong>Exercise 2.</strong> Use (14), (26), and the identity</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cpartial_%5Ctau+%7B%5Cmathcal+L%7D%5Cexp_%7B%281%2Cx_0%29%2C%5Ctau%7D%28v%29+%3D+X&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_&#92;tau {&#92;mathcal L}&#92;exp_{(1,x_0),&#92;tau}(v) = X' title='&#92;partial_&#92;tau {&#92;mathcal L}&#92;exp_{(1,x_0),&#92;tau}(v) = X' class='latex' /> (27)</p>
<p style="text-align:left;">(which basically follows from the fact that any segment of a minimising <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-geodesic is again a <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-geodesic) to derive the pointwise inequality</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cpartial_%5Ctau+%5Ctau%5E%7B-d%2F2%7D+e%5E%7B-l%28%7B%5Cmathcal+L%7D+%5Cexp_%7B%281%2Cx_0%29%2C%5Ctau%7D%28v%29%29%7D+J_%7B%5Ctau%7D%28v%29+%5Cleq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;partial_&#92;tau &#92;tau^{-d/2} e^{-l({&#92;mathcal L} &#92;exp_{(1,x_0),&#92;tau}(v))} J_{&#92;tau}(v) &#92;leq 0' title='&#92;displaystyle &#92;partial_&#92;tau &#92;tau^{-d/2} e^{-l({&#92;mathcal L} &#92;exp_{(1,x_0),&#92;tau}(v))} J_{&#92;tau}(v) &#92;leq 0' class='latex' />. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /> (38)</p>
<p style="text-align:left;">Exercise 2 reproves the monotonicity of Perelman reduced volume (25), but also proves a stronger local version of this monotonicity in which the region of integration <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathbb+R%7D%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathbb R}^d' title='{&#92;mathbb R}^d' class='latex' /> is replaced by an arbitrary region <img src='http://s0.wp.com/latex.php?latex=%5COmega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Omega' title='&#92;Omega' class='latex' /> (intersected with the injectivity region, as mentioned earlier).</p>
<p style="text-align:left;">In the Euclidean case, a computation using (8) and (24) shows that <img src='http://s0.wp.com/latex.php?latex=l%28%7B%5Cmathcal+L%7D+%5Cexp_%7B%281%2Cx_0%29%2C%5Ctau%7D%28v%29%29+%3D+%26%23124%3Bv%26%23124%3B%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l({&#92;mathcal L} &#92;exp_{(1,x_0),&#92;tau}(v)) = &#124;v&#124;^2' title='l({&#92;mathcal L} &#92;exp_{(1,x_0),&#92;tau}(v)) = &#124;v&#124;^2' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=J_%5Ctau%28v%29+%3D+2%5En+%5Ctau%5E%7Bd%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='J_&#92;tau(v) = 2^n &#92;tau^{d/2}' title='J_&#92;tau(v) = 2^n &#92;tau^{d/2}' class='latex' />.    Also, one can use some basic analysis arguments to show that in the limit <img src='http://s0.wp.com/latex.php?latex=%5Ctau+%5Cto+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau &#92;to 0' title='&#92;tau &#92;to 0' class='latex' />, the expressions in (25) converge pointwise to their Euclidean counterparts.  As a consequence we obtain the pointwise domination</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Ctau%5E%7B-d%2F2%7D+e%5E%7B-l%28%7B%5Cmathcal+L%7D+%5Cexp_%7B%281%2Cx_0%29%2C%5Ctau%7D%28v%29%29%7D+J_%7B%5Ctau%7D%28v%29+%5Cleq+2%5E%7Bn%2F2%7D+e%5E%7B-%26%23124%3Bv%26%23124%3B%5E2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;tau^{-d/2} e^{-l({&#92;mathcal L} &#92;exp_{(1,x_0),&#92;tau}(v))} J_{&#92;tau}(v) &#92;leq 2^{n/2} e^{-&#124;v&#124;^2}' title='&#92;displaystyle &#92;tau^{-d/2} e^{-l({&#92;mathcal L} &#92;exp_{(1,x_0),&#92;tau}(v))} J_{&#92;tau}(v) &#92;leq 2^{n/2} e^{-&#124;v&#124;^2}' class='latex' /> (39)</p>
<p style="text-align:left;">for any v and any <img src='http://s0.wp.com/latex.php?latex=0+%26%2360%3B+%5Ctau+%26%2360%3B+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &lt; &#92;tau &lt; 1' title='0 &lt; &#92;tau &lt; 1' class='latex' />.  As a consequence, the far part of (25) (corresponding to &#8220;fast&#8221; geodesics) is negligible: we have</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Ctau%5E%7B-d%2F2%7D+%5Cint_%7B%26%23124%3Bv%26%23124%3B+%26%2362%3B+C%7D+e%5E%7B-l%28%7B%5Cmathcal+L%7D+%5Cexp_%7B%281%2Cx_0%29%2C%5Ctau%7D%28v%29%29%7D+J_%7B%5Ctau%7D%28v%29%5C+dv+%5Cleq+%5Cdelta%2F2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;tau^{-d/2} &#92;int_{&#124;v&#124; &gt; C} e^{-l({&#92;mathcal L} &#92;exp_{(1,x_0),&#92;tau}(v))} J_{&#92;tau}(v)&#92; dv &#92;leq &#92;delta/2' title='&#92;displaystyle &#92;tau^{-d/2} &#92;int_{&#124;v&#124; &gt; C} e^{-l({&#92;mathcal L} &#92;exp_{(1,x_0),&#92;tau}(v))} J_{&#92;tau}(v)&#92; dv &#92;leq &#92;delta/2' class='latex' /> (40)</p>
<p style="text-align:left;">for some C depending only on d and <img src='http://s0.wp.com/latex.php?latex=%5Cdelta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta' title='&#92;delta' class='latex' />.  From this and the hypothesis (19) we thus obtain lower bounds on <em>local</em> Perelman reduced volume, or more precisely that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Ctau%5E%7B-d%2F2%7D+%5Cint_%7B%26%23124%3Bv%26%23124%3B+%5Cleq+C%7D+e%5E%7B-l%28%7B%5Cmathcal+L%7D+%5Cexp_%7B%281%2Cx_0%29%2C%5Ctau%7D%28v%29%29%7D+J_%7B%5Ctau%7D%28v%29%5C+dv+%5Cgeq+%5Cdelta%2F2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;tau^{-d/2} &#92;int_{&#124;v&#124; &#92;leq C} e^{-l({&#92;mathcal L} &#92;exp_{(1,x_0),&#92;tau}(v))} J_{&#92;tau}(v)&#92; dv &#92;geq &#92;delta/2' title='&#92;displaystyle &#92;tau^{-d/2} &#92;int_{&#124;v&#124; &#92;leq C} e^{-l({&#92;mathcal L} &#92;exp_{(1,x_0),&#92;tau}(v))} J_{&#92;tau}(v)&#92; dv &#92;geq &#92;delta/2' class='latex' /> (41)</p>
<p style="text-align:left;">for all <img src='http://s0.wp.com/latex.php?latex=0+%26%2360%3B+%5Ctau+%5Cleq+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &lt; &#92;tau &#92;leq 1' title='0 &lt; &#92;tau &#92;leq 1' class='latex' />.</p>
<p style="text-align:left;">Now, we have bounded curvature on the cylinder <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5B0%2C1%5D+%5Ctimes+B_%7Bg%281%29%7D%28x_0%2C1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[0,1] &#92;times B_{g(1)}(x_0,1)' title='{}[0,1] &#92;times B_{g(1)}(x_0,1)' class='latex' />.  Using the heat equation (12) and standard parabolic regularity estimates, we thus conclude that any first derivatives of the curvature are also bounded on the cylinder <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5B1%2F2%2C1%5D+%5Ctimes+B_%7B%28g%281%29%7D%28x_0%2C1%2F2%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[1/2,1] &#92;times B_{(g(1)}(x_0,1/2)' title='{}[1/2,1] &#92;times B_{(g(1)}(x_0,1/2)' class='latex' />.  (In fact, all higher derivatives are controlled as well; see this <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=1001277">paper of Shi</a> for full details.)  In particular we have <img src='http://s0.wp.com/latex.php?latex=%5Cnabla+R+%3D+O%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla R = O(1)' title='&#92;nabla R = O(1)' class='latex' /> in this cylinder.  Thus the equation G=0 for an <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-geodesic (where G was defined in equation (27) of the previous lecture) becomes</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cnabla_%5Ctau+X+%2B+%5Cfrac%7B1%7D%7B2%5Ctau%7D+X+%3D+O%281%29+%2B+O%28+%26%23124%3BX%26%23124%3B+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_&#92;tau X + &#92;frac{1}{2&#92;tau} X = O(1) + O( &#124;X&#124; )' title='&#92;nabla_&#92;tau X + &#92;frac{1}{2&#92;tau} X = O(1) + O( &#124;X&#124; )' class='latex' /> (42)</p>
<p style="text-align:left;">or equivalently that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cnabla_%5Ctau+%28%5Csqrt%7B%5Ctau%7D+X%29+%3D+O%28%5Csqrt%7B%5Ctau%7D%29+%2B+O%28+%5Csqrt%7B%5Ctau%7D+%26%23124%3BX%26%23124%3B+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_&#92;tau (&#92;sqrt{&#92;tau} X) = O(&#92;sqrt{&#92;tau}) + O( &#92;sqrt{&#92;tau} &#124;X&#124; )' title='&#92;nabla_&#92;tau (&#92;sqrt{&#92;tau} X) = O(&#92;sqrt{&#92;tau}) + O( &#92;sqrt{&#92;tau} &#124;X&#124; )' class='latex' /> (43)</p>
<p style="text-align:left;">as long as the geodesic stays inside this smaller cylinder.  From this and Gronwall&#8217;s inequality one easily verifies that for sufficiently small <img src='http://s0.wp.com/latex.php?latex=0+%26%2360%3B+%5Ctau+%26%2360%3B+1%2F2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &lt; &#92;tau &lt; 1/2' title='0 &lt; &#92;tau &lt; 1/2' class='latex' /> (depending on C, d), the exponential map <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D%5Cexp_%7B%281%2Cx_0%29%2C%5Ctau%7D%28v%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}&#92;exp_{(1,x_0),&#92;tau}(v)' title='{&#92;mathcal L}&#92;exp_{(1,x_0),&#92;tau}(v)' class='latex' /> does not exit the cylinder <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5B1%2F2%2C1%5D+%5Ctimes+B_%7Bg%281%29%7D%28x_0%2C1%2F2%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[1/2,1] &#92;times B_{g(1)}(x_0,1/2)' title='{}[1/2,1] &#92;times B_{g(1)}(x_0,1/2)' class='latex' /> for <img src='http://s0.wp.com/latex.php?latex=%26%23124%3Bv+%26%23124%3B%5Cleq+C&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;v &#124;&#92;leq C' title='&#124;v &#124;&#92;leq C' class='latex' />.  On the other hand, at time <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' />, we see from (5), (6) and the bounds on curvature in this cylinder that the reduced length l of the associated <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-geodesic is bounded below by some constant  depending on <img src='http://s0.wp.com/latex.php?latex=%5Ctau%2C+C%2C+d&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau, C, d' title='&#92;tau, C, d' class='latex' />.  We thus see (from the change of variables formula) that the left-hand side of (41) is bounded above by <img src='http://s0.wp.com/latex.php?latex=O_%7B%5Ctau%2CC%2Cd%7D%28+%5Chbox%7BVol%7D_%7Bg%281-%5Ctau%29%7D%28+B_%7Bg%281%29%7D%28x_0%2C1%2F2%29+%29+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='O_{&#92;tau,C,d}( &#92;hbox{Vol}_{g(1-&#92;tau)}( B_{g(1)}(x_0,1/2) ) )' title='O_{&#92;tau,C,d}( &#92;hbox{Vol}_{g(1-&#92;tau)}( B_{g(1)}(x_0,1/2) ) )' class='latex' />.  Choosing <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' /> to be a small number depending on C, d, we thus conclude from (41) that the volume of <img src='http://s0.wp.com/latex.php?latex=B_%7Bg%281%29%7D%28x_0%2C1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_{g(1)}(x_0,1)' title='B_{g(1)}(x_0,1)' class='latex' /> with respect to <img src='http://s0.wp.com/latex.php?latex=g%281-%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='g(1-&#92;tau)' title='g(1-&#92;tau)' class='latex' /> (and hence g(1), by comparability of metrics) is bounded from below by some constant depending on C and d, and thus ultimately on <img src='http://s0.wp.com/latex.php?latex=%5Cdelta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta' title='&#92;delta' class='latex' /> and d, giving Proposition 2 as desired.</p>
<p style="text-align:center;">&#8211; Extensions &#8211;</p>
<p style="text-align:left;">The pointwise nature of the monotonicity of Perelman reduced volume allows one to derive local versions of the non-collapsing result, in which one only needs a portion of the geometry to be non-collapsed at the initial time.   A typical version of such a local noncollapsing result reads as follows.</p>
<blockquote>
<p style="text-align:left;"><strong>Theorem 1</strong> (Perelman&#8217;s non-collapsing theorem, second version) Let <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> be a d-dimensional Ricci flow on the time interval <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5B0%2Cr_0%5E2%5D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[0,r_0^2]' title='{}[0,r_0^2]' class='latex' />, and suppose that one has the bounded normalised curvature condition <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Chbox%7BRiem%7D%26%23124%3B_g+%5Cleq+r_0%5E%7B-2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;hbox{Riem}&#124;_g &#92;leq r_0^{-2}' title='&#124;&#92;hbox{Riem}&#124;_g &#92;leq r_0^{-2}' class='latex' /> on a cylinder <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5B0%2Cr_0%5E2%5D+%5Ctimes+B_%7Bg%280%29%7D%28x_0%2Cr_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[0,r_0^2] &#92;times B_{g(0)}(x_0,r_0)' title='{}[0,r_0^2] &#92;times B_{g(0)}(x_0,r_0)' class='latex' /> for some <img src='http://s0.wp.com/latex.php?latex=x_0+%5Cin+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0 &#92;in M' title='x_0 &#92;in M' class='latex' />.  Suppose also that we have the volume lower bound <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BVol%7D_%7Bg%280%29%7D%28B_%7Bg%280%29%7D%28x_0%2Cr_0%29%29+%5Cgeq+c+r_0%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Vol}_{g(0)}(B_{g(0)}(x_0,r_0)) &#92;geq c r_0^d' title='&#92;hbox{Vol}_{g(0)}(B_{g(0)}(x_0,r_0)) &#92;geq c r_0^d' class='latex' /> for some <img src='http://s0.wp.com/latex.php?latex=c%26%2362%3B0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='c&gt;0' title='c&gt;0' class='latex' />.  Then for any <img src='http://s0.wp.com/latex.php?latex=A+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='A &gt; 0' title='A &gt; 0' class='latex' />, the Ricci flow is <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsed at <img src='http://s0.wp.com/latex.php?latex=%28r_0%5E2%2Cx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(r_0^2,x)' title='(r_0^2,x)' class='latex' /> for any <img src='http://s0.wp.com/latex.php?latex=x+%5Cin+B_%7Bg%28r_0%5E2%29%7D%28x_0%2CAr_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x &#92;in B_{g(r_0^2)}(x_0,Ar_0)' title='x &#92;in B_{g(r_0^2)}(x_0,Ar_0)' class='latex' /> and at any scale <img src='http://s0.wp.com/latex.php?latex=0+%26%2360%3B+r+%26%2360%3B+r_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &lt; r &lt; r_0' title='0 &lt; r &lt; r_0' class='latex' />, for some <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' /> depending only on d, c, A.</p>
</blockquote>
<p style="text-align:left;">The novelty here is that the geometry is controlled in a cylinder, rather than on the initial time slice, but one gets to conclude <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsing at points some distance away from the cylinder.  In view of Lemma 1, we see that this result is more or less a strengthening of the previous <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsing theorem.</p>
<p style="text-align:left;">This theorem (or more precisely, a generalisation of it involving Ricci flow with surgery) is used in the original argument of <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0211159">Perelman</a> (and then in the later treatments by <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0605667">Kleiner-Lott</a> and <a class="snap_noshots" href="http://arxiv.org/abs/math/0612069">Cao-Zhu</a>) in order to deal with the long-time behaviour of Ricci flow with surgery, which is needed for the geometrisation conjecture.  For proving the Poincaré conjecture, though, one has finite time extinction, and it turns out that the above theorem is not needed for the proof of that conjecture (for instance, it does not appear in treatment of <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2334563">Morgan-Tian</a>).   Nevertheless I will sketch how the above theorem is proven below, since there are one or two interesting technical tricks that get used in the argument.</p>
<p style="text-align:left;">The proof of Theorem 1 is, unsurprisingly, a modification of the previous arguments .  The implications <img src='http://s0.wp.com/latex.php?latex=%282%29+%5Cimplies+%283%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(2) &#92;implies (3)' title='(2) &#92;implies (3)' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%283%29+%5Cimplies+%284%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(3) &#92;implies (4)' title='(3) &#92;implies (4)' class='latex' /> are basically unchanged, but one needs to replace Proposition 1 by the following variant.</p>
<blockquote>
<p style="text-align:left;"><strong>Proposition 3. </strong> Let the hypotheses be as in Theorem 1.  Then for any <img src='http://s0.wp.com/latex.php?latex=x+%5Cin+B_%7Bg%28r_0%5E2%29%7D%28x_0%2CAr_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x &#92;in B_{g(r_0^2)}(x_0,Ar_0)' title='x &#92;in B_{g(r_0^2)}(x_0,Ar_0)' class='latex' /> one has <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+V_%7B%28r_0%5E2%2Cx%29%7D%28r_0%5E2%29+%5Cgeq+c%27&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde V_{(r_0^2,x)}(r_0^2) &#92;geq c&#039;' title='&#92;tilde V_{(r_0^2,x)}(r_0^2) &#92;geq c&#039;' class='latex' /> for some <img src='http://s0.wp.com/latex.php?latex=c%27+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='c&#039; &gt; 0' title='c&#039; &gt; 0' class='latex' /> depending on A, c, d.</p>
</blockquote>
<p style="text-align:left;">We sketch the proof of Proposition 3.  It is convenient to rescale so that <img src='http://s0.wp.com/latex.php?latex=r_0%3D1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_0=1' title='r_0=1' class='latex' />.  In view of the non-collapsed nature of the geometry in <img src='http://s0.wp.com/latex.php?latex=B_%7Bg%280%29%7D%28x_0%2C1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_{g(0)}(x_0,1)' title='B_{g(0)}(x_0,1)' class='latex' />, it suffices to establish a lower bound of the form <img src='http://s0.wp.com/latex.php?latex=l_%7B%281%2Cx%29%7D%280%2Cz%29+%5Cgeq+-C&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_{(1,x)}(0,z) &#92;geq -C' title='l_{(1,x)}(0,z) &#92;geq -C' class='latex' /> for all <img src='http://s0.wp.com/latex.php?latex=z+%5Cin+B_%7Bg%280%29%7D%28x_0%2C1%2F2%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='z &#92;in B_{g(0)}(x_0,1/2)' title='z &#92;in B_{g(0)}(x_0,1/2)' class='latex' /> for some <img src='http://s0.wp.com/latex.php?latex=C+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C &gt; 0' title='C &gt; 0' class='latex' /> depending on A,c,d.  Actually, because of the bounded geometry in the cylinder, it suffices to show that <img src='http://s0.wp.com/latex.php?latex=l_%7B%281%2Cx%29%7D%281%2F2%2Cy%29+%5Cgeq+-C%27&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_{(1,x)}(1/2,y) &#92;geq -C&#039;' title='l_{(1,x)}(1/2,y) &#92;geq -C&#039;' class='latex' /> for just one point <img src='http://s0.wp.com/latex.php?latex=z+%5Cin+B_%7Bg%281%2F2%29%7D%28x_0%2C1%2F10%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='z &#92;in B_{g(1/2)}(x_0,1/10)' title='z &#92;in B_{g(1/2)}(x_0,1/10)' class='latex' /> for some <img src='http://s0.wp.com/latex.php?latex=C%27+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C&#039; &gt; 0' title='C&#039; &gt; 0' class='latex' /> depending on A,c,d, since one can join (1/2,y) by a geodesic to (1,z) much as in the proof of Proposition 1.</p>
<p>The task is now analogous to that of finding a point y that obeyed the relation (18), so we expect the heat equation (17) to again play a role.  We do not need the sharp bound of n/2 which occurs in (18); on the other hand, y is now constrained to lie in a ball, which defeats a direct application of the maximum principle.  To fix this one has to multiply the reduced length l by a penalising weight to force the minimum to lie in the desired ball at time 1/2, and then rapidly relax this weight as one moves from time 1/2 to time 1 so that it incorporates the point x at time 1.  It turns out the maximum principle can then be applied with a suitable choice of weights, as long as one knows that the distance function <img src='http://s0.wp.com/latex.php?latex=r%28t%2Cy%29+%3D+d_%7Bg%28t%29%7D%28x_0%2Cy%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r(t,y) = d_{g(t)}(x_0,y)' title='r(t,y) = d_{g(t)}(x_0,y)' class='latex' /> is a supersolution to a heat equation, and more precisely that <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+r+-+%5CDelta+r+%5Cgeq+-C&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t r - &#92;Delta r &#92;geq -C' title='&#92;partial_t r - &#92;Delta r &#92;geq -C' class='latex' /> when r is bounded away from the origin.  But this can be established by the first and second variation formulae for the distance function, and in particular using the non-negativity of the second variation for minimising geodesics.  Details can be found in Section 8 of <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0211159">Perelman&#8217;s paper</a>, Sections 26-27 of <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0605667">Kleiner-Lott</a>, or Section 3.4 of <a class="snap_noshots" href="http://arxiv.org/abs/math/0612069">Cao-Zhu</a>.</p>
<p><strong>Remark 1.</strong> One can also interpret the above analysis in terms of heat kernels, and using (26) instead of (17).  The former inequality is equivalent to the assertion that the function <img src='http://s0.wp.com/latex.php?latex=v+%3A%3D+%284%5Cpi+%5Ctau%29%5E%7B-d%2F2%7D+e%5E%7B-l%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='v := (4&#92;pi &#92;tau)^{-d/2} e^{-l}' title='v := (4&#92;pi &#92;tau)^{-d/2} e^{-l}' class='latex' /> is a subsolution of the adjoint heat equation: <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+v+%2B+%5CDelta+v+-+Rv+%5Cleq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t v + &#92;Delta v - Rv &#92;leq 0' title='&#92;partial_t v + &#92;Delta v - Rv &#92;leq 0' class='latex' />.  As <img src='http://s0.wp.com/latex.php?latex=t+%5Cto+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;to 1' title='t &#92;to 1' class='latex' />, v approaches a Dirac mass at x (indeed, v asymptotically resembles the Euclidean backwards heat kernel from <img src='http://s0.wp.com/latex.php?latex=%281%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(1,x_0)' title='(1,x_0)' class='latex' />) and the task is to obtain upper bounds on v at some point on a ball <img src='http://s0.wp.com/latex.php?latex=B_%7Bg%281%2F2%29%7D%28x_0%2C1%2F10%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_{g(1/2)}(x_0,1/10)' title='B_{g(1/2)}(x_0,1/10)' class='latex' /> at time 1/2.  This is basically equivalent to establishing lower bounds of Gaussian type for the fundamental solution of the adjoint heat equation at some point in <img src='http://s0.wp.com/latex.php?latex=B_%7Bg%281%2F2%29%7D%28x_0%2C1%2F10%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_{g(1/2)}(x_0,1/10)' title='B_{g(1/2)}(x_0,1/10)' class='latex' />.  Similar analysis in the case of a static manifold with potential (and a lower bound on Ricci curvature) was carried out somewhat earlier by <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=834612">Li and Yau</a>. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>As mentioned previously, in order to apply the non-collapsing result beyond the first surgery time, it is necessary to develop analogues of the above theory for Ricci flows with surgery.  This turns out to be remarkably technical, but the main ideas at least are fairly clear.  Firstly, one has to delete all <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-geodesics which pass through surgery regions when defining the Perelman reduced volume; such curves are called &#8220;inadmissible&#8221;.  Note that if <img src='http://s0.wp.com/latex.php?latex=%281%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(1,x_0)' title='(1,x_0)' class='latex' /> is in a surgery region to begin with, then every curve is inadmissible but in this case the geometry can be controlled directly from the surgery theory.  As it turns out, one can similarly deal with the case when <img src='http://s0.wp.com/latex.php?latex=%281%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(1,x_0)' title='(1,x_0)' class='latex' /> has extremely high curvature because one can control the geometry of such regions.  So we can easily eliminate these bad cases.</p>
<p>Because of the pointwise nature of the monotonicity formula for reduced volume, this restriction of admissibility does not affect the &#8220;<img src='http://s0.wp.com/latex.php?latex=%282%29+%5Cimplies+%283%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(2) &#92;implies (3)' title='(2) &#92;implies (3)' class='latex' />&#8221; stage of the argument.  The &#8220;<img src='http://s0.wp.com/latex.php?latex=%283%29+%5Cimplies+%284%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(3) &#92;implies (4)' title='(3) &#92;implies (4)' class='latex' />&#8221; step is also largely unaffected, since removing inadmissible components of the reduced volume only serves to strengthen the hypothesis (3).  But significant new technical difficulties arise in the &#8220;<img src='http://s0.wp.com/latex.php?latex=%281%29+%5Cimplies+%282%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(1) &#92;implies (2)' title='(1) &#92;implies (2)' class='latex' />&#8221; portion of the argument, when one has to argue that not too much of the reduced volume has been deleted by all the various surgeries that take place between time t=0 and time <img src='http://s0.wp.com/latex.php?latex=t%3D1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t=1' title='t=1' class='latex' />.  In particular, we still need to find a point y obeying (18) (or something very much like (18)) which is admissible.  To do this, the basic idea is to establish that inadmissible curves have large reduced length (and so removing them will not impact the search for a solution to (18)).  For technical reasons it is better to restrict attention to <em>barely admissible</em> curves &#8211; curves which just touch the border of the surgery region, but do not actually enter it.  In this case it is possible to use the geometric control of the surgery regions to give some non-trivial lower bounds on the reduced length of such curves, although there are still significant technical issues to resolve beyond this.  I hope to return to this point later in the course, when we have defined surgery properly.</p>
<p style="text-align:center;">&#8211; Epilogue: a connection between Perelman entropy and Perelman reduced volume &#8211;</p>
<p>We have shown two routes towards establishing <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-non-collapsing of Ricci flows, one using the (parameterised) Perelman entropies</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cmu%28g%28t%29%2C%5Ctau%29+%3A%3D+%5Cinf+%5C%7B+%5Cint_M+%28%5Ctau%28%26%23124%3B%5Cnabla+f%26%23124%3B%5E2+%2B+R%29+%2B+f+-+d%29+%284%5Cpi%5Ctau%29%5E%7B-d%2F2%7D+e%5E%7B-f%7D%5C+d%5Cmu%3A+&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;mu(g(t),&#92;tau) := &#92;inf &#92;{ &#92;int_M (&#92;tau(&#124;&#92;nabla f&#124;^2 + R) + f - d) (4&#92;pi&#92;tau)^{-d/2} e^{-f}&#92; d&#92;mu: ' title='&#92;displaystyle &#92;mu(g(t),&#92;tau) := &#92;inf &#92;{ &#92;int_M (&#92;tau(&#124;&#92;nabla f&#124;^2 + R) + f - d) (4&#92;pi&#92;tau)^{-d/2} e^{-f}&#92; d&#92;mu: ' class='latex' /></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cint_M+%284%5Cpi%5Ctau%29%5E%7B-d%2F2%7D+e%5E%7B-f%7D%5C+d%5Cmu+%3D+1+%5C%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;int_M (4&#92;pi&#92;tau)^{-d/2} e^{-f}&#92; d&#92;mu = 1 &#92;}' title='&#92;displaystyle &#92;int_M (4&#92;pi&#92;tau)^{-d/2} e^{-f}&#92; d&#92;mu = 1 &#92;}' class='latex' /> (44)</p>
<p>and one using the reduced volumes <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+V_%7B%280%2Cx_0%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde V_{(0,x_0)}' title='&#92;tilde V_{(0,x_0)}' class='latex' /> mentioned above.  Actually, the two quantities are related to each other (this is hinted at in Section 9 of <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0211159">Perelman&#8217;s paper</a>); very roughly speaking, the potential function f in the theory of Perelman entropy plays the same role that reduced length l does in the theory of Perelman volume.  Indeed, using (44) and shifting f by a constant if necessary, we have the log-Sobolev inequality</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cint_M+%28%5Ctau%28%26%23124%3B%5Cnabla+f%26%23124%3B%5E2+%2B+R%29+%2B+f+-+d%29+%284%5Cpi%5Ctau%29%5E%7B-d%2F2%7D+e%5E%7B-f%7D%5C+d%5Cmu+&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;int_M (&#92;tau(&#124;&#92;nabla f&#124;^2 + R) + f - d) (4&#92;pi&#92;tau)^{-d/2} e^{-f}&#92; d&#92;mu ' title='&#92;displaystyle &#92;int_M (&#92;tau(&#124;&#92;nabla f&#124;^2 + R) + f - d) (4&#92;pi&#92;tau)^{-d/2} e^{-f}&#92; d&#92;mu ' class='latex' /></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cgeq+%5B%5Cmu%28g%28t%29%2C%5Ctau%29+-+%5Clog+%5Cint_M+%284%5Cpi%5Ctau%29%5E%7B-d%2F2%7D+e%5E%7B-f%7D%5C+d%5Cmu%5D+%5Cint_M+%284%5Cpi%5Ctau%29%5E%7B-d%2F2%7D+e%5E%7B-f%7D%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;geq [&#92;mu(g(t),&#92;tau) - &#92;log &#92;int_M (4&#92;pi&#92;tau)^{-d/2} e^{-f}&#92; d&#92;mu] &#92;int_M (4&#92;pi&#92;tau)^{-d/2} e^{-f}&#92; d&#92;mu' title='&#92;displaystyle &#92;geq [&#92;mu(g(t),&#92;tau) - &#92;log &#92;int_M (4&#92;pi&#92;tau)^{-d/2} e^{-f}&#92; d&#92;mu] &#92;int_M (4&#92;pi&#92;tau)^{-d/2} e^{-f}&#92; d&#92;mu' class='latex' />. (45)</p>
<p>An integration by parts reveals that we can replace the <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Cnabla+f%26%23124%3B%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;nabla f&#124;^2' title='&#124;&#92;nabla f&#124;^2' class='latex' /> on the left -hand side by <img src='http://s0.wp.com/latex.php?latex=%5CDelta+f&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Delta f' title='&#92;Delta f' class='latex' />, and hence one can also replace this quantity by <img src='http://s0.wp.com/latex.php?latex=2%5CDelta+f+-+%26%23124%3B%5Cnabla+f%26%23124%3B%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='2&#92;Delta f - &#124;&#92;nabla f&#124;^2' title='2&#92;Delta f - &#124;&#92;nabla f&#124;^2' class='latex' />.</p>
<p>We now apply this inequality with <img src='http://s0.wp.com/latex.php?latex=%5Ctau+%3A%3D+t_0-t&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau := t_0-t' title='&#92;tau := t_0-t' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=f+%3D+l_%7B%28t_0%2Cx_0%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='f = l_{(t_0,x_0)}' title='f = l_{(t_0,x_0)}' class='latex' /> for some spacetime point <img src='http://s0.wp.com/latex.php?latex=%28t_0%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_0,x_0)' title='(t_0,x_0)' class='latex' /> in the Ricci flow.  Using (14), (16) we see that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+2+%5CDelta+f+-+%26%23124%3B%5Cnabla+f%26%23124%3B%5E2+%5Cleq+%5Cfrac%7Bd%7D%7B2%5Ctau%7D+-+R+-+%5Cfrac%7B1%7D%7B%5Ctau%7D+f&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle 2 &#92;Delta f - &#124;&#92;nabla f&#124;^2 &#92;leq &#92;frac{d}{2&#92;tau} - R - &#92;frac{1}{&#92;tau} f' title='&#92;displaystyle 2 &#92;Delta f - &#124;&#92;nabla f&#124;^2 &#92;leq &#92;frac{d}{2&#92;tau} - R - &#92;frac{1}{&#92;tau} f' class='latex' /> (46)</p>
<p>and thus the left-hand side of (45) is non-positive.  Using (7) we thus conclude a simple relationship between entropy and reduced volume:</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cmu%28g%28t_0-%5Ctau%29%2C%5Ctau%29+%5Cleq+%5Clog+%5Cfrac%7B%5Ctilde+V_%7B%28t_0%2Cx_0%29%7D%28%5Ctau%29%7D%7B%284%5Cpi%29%5E%7Bd%2F2%7D%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;mu(g(t_0-&#92;tau),&#92;tau) &#92;leq &#92;log &#92;frac{&#92;tilde V_{(t_0,x_0)}(&#92;tau)}{(4&#92;pi)^{d/2}}' title='&#92;displaystyle &#92;mu(g(t_0-&#92;tau),&#92;tau) &#92;leq &#92;log &#92;frac{&#92;tilde V_{(t_0,x_0)}(&#92;tau)}{(4&#92;pi)^{d/2}}' class='latex' />. (47)</p>
<p>[As usual, we have equality in physical space; this inequality also reinforces the suggestion that one normalise the reduced volume by an additional factor of <img src='http://s0.wp.com/latex.php?latex=1%2F%284%5Cpi%29%5E%7Bd%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='1/(4&#92;pi)^{d/2}' title='1/(4&#92;pi)^{d/2}' class='latex' />.]</p>
<p>Thus the Perelman entropy can be viewed as a global analogue of the Perelman reduced volume, in which we allow the base point <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' /> to vary (thus it measures the global non-collapsing nature of the manifold, as opposed to the local nature; we already saw this in <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/24/285a-lecture-8-ricci-flow-as-a-gradient-flow-log-sobolev-inequalities-and-perelman-entropy/">Lecture 8</a>; compare in particular equation (62) from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/24/285a-lecture-8-ricci-flow-as-a-gradient-flow-log-sobolev-inequalities-and-perelman-entropy/">Lecture 8</a> with the heuristic (11) using (47).)</p>
<p>There are other connections between entropy and reduced volume; compare for instance the flow equation for the potential f (equation (46) from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/24/285a-lecture-8-ricci-flow-as-a-gradient-flow-log-sobolev-inequalities-and-perelman-entropy/">Lecture 8</a>) with equation (26) here.  The adjoint heat equation <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+u+%2B+%5CDelta+u+-+Ru+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t u + &#92;Delta u - Ru = 0' title='&#92;partial_t u + &#92;Delta u - Ru = 0' class='latex' /> also makes essentially the same appearance in both theories.  See Section 9 of <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0211159">Perelman&#8217;s paper</a> for further discussion.</p>
<p><strong>Remark 2.</strong> As remarked above, the flow equation for f can be viewed as a pointwise versions of the entropy monotonicity formula, which in principle leads to localised monotonicity formulae for the Perelman entropy; some analysis in this direction appears in Section 9 of <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0211159">Perelman&#8217;s paper</a>.  But I do not know if these localised entropy formulae can substitute to give a different proof of Theorem 1.  <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;">
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<item>
<title><![CDATA[285G, Lecture 10: Variation of L-geodesics, and monotonicity of Perelman reduced volume]]></title>
<link>http://terrytao.wordpress.com/2008/05/09/285g-lecture-10-variation-of-l-geodesics-and-monotonicity-of-perelman-reduced-volume/</link>
<pubDate>Fri, 09 May 2008 15:40:23 +0000</pubDate>
<dc:creator>Terence Tao</dc:creator>
<guid>http://terrytao.wordpress.com/2008/05/09/285g-lecture-10-variation-of-l-geodesics-and-monotonicity-of-perelman-reduced-volume/</guid>
<description><![CDATA[Having completed a heuristic derivation of the monotonicity of Perelman reduced volume (Conjecture 1]]></description>
<content:encoded><![CDATA[<p style="text-align:left;">Having completed a heuristic derivation of the monotonicity of Perelman reduced volume (Conjecture 1 from the <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/27/285g-lecture-9-comparison-geometry-the-high-dimensional-limit-and-perelman-reduced-volume/">previous lecture</a>), we now turn to a rigorous proof.  Whereas in the <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/27/285g-lecture-9-comparison-geometry-the-high-dimensional-limit-and-perelman-reduced-volume/">previous lecture</a> we derived this monotonicity by converting a parabolic spacetime to a high-dimensional Riemannian manifold, and then formally applying tools such as the <a href="http://en.wikipedia.org/wiki/Bishop%E2%80%93Gromov_inequality">Bishop-Gromov inequality</a> to that setting, our approach here shall take the opposite tack, finding parabolic analogues of the <em>proof</em> of the elliptic Bishop-Gromov inequality, in particular obtaining analogues of the classical first and second variation formulae for geodesics, in which the notion of length is replaced by the notion of <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-length introduced in the <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/27/285g-lecture-9-comparison-geometry-the-high-dimensional-limit-and-perelman-reduced-volume/">previous lecture</a>.</p>
<p style="text-align:left;">The material here is primarily based on <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0211159">Perelman&#8217;s first paper</a> and <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2251315">Müller&#8217;s book</a>, but detailed treatments also appear in the <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2342013">paper of Ye</a>, the <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0605667">notes of Kleiner-Lott</a>, the book of <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2334563">Morgan-Tian</a>, and the <a class="snap_noshots" href="http://arxiv.org/abs/math/0612069">paper of Cao-Zhu</a>.</p>
<p style="text-align:left;"><!--more--></p>
<p style="text-align:center;">&#8211; Reduction to a pointwise inequality &#8211;</p>
<p style="text-align:left;">Recall that the Bishop-Gromov inequality (Corollary 1 from the <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/27/285g-lecture-9-comparison-geometry-the-high-dimensional-limit-and-perelman-reduced-volume/">previous lecture</a>) states (among other things) that if a d-dimensional complete Riemannian manifold (M,g) is Ricci-flat (or more generally, has non-negative Ricci curvature), and <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' /> is any point in M, then the Bishop-Gromov reduced volume <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BVol%7D%28B%28x_0%2Cr%29%29%2Fr%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Vol}(B(x_0,r))/r^d' title='&#92;hbox{Vol}(B(x_0,r))/r^d' class='latex' /> is a non-increasing function of r.  In fact one can obtain the slightly sharper result that <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BArea%7D%28S%28x_0%2Cr%29%29%2Fr%5E%7Bd-1%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Area}(S(x_0,r))/r^{d-1}' title='&#92;hbox{Area}(S(x_0,r))/r^{d-1}' class='latex' /> is a non-increasing function of r, where <img src='http://s0.wp.com/latex.php?latex=S%28x_0%2Cr%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S(x_0,r)' title='S(x_0,r)' class='latex' /> is the sphere of radius r centred at <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' />.</p>
<p style="text-align:left;">From the basic formula <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D_%7B%5Cpartial+r%7D+d%5Cmu+%3D+%28%5CDelta+r%29%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}_{&#92;partial r} d&#92;mu = (&#92;Delta r)&#92; d&#92;mu' title='{&#92;mathcal L}_{&#92;partial r} d&#92;mu = (&#92;Delta r)&#92; d&#92;mu' class='latex' /> (equation (1) from the <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/27/285g-lecture-9-comparison-geometry-the-high-dimensional-limit-and-perelman-reduced-volume/">previous lecture</a>) and the <a href="http://en.wikipedia.org/wiki/Gauss%27s_lemma_%28Riemannian_geometry%29">Gauss lemma</a>, one readily obtains the identity</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bdr%7D+%5Chbox%7BArea%7D%28S%28x_0%2Cr%29%29+%3D+%5Cint_%7BS%28x_0%2Cr%29%7D+%5CDelta+r%5C+dS&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{dr} &#92;hbox{Area}(S(x_0,r)) = &#92;int_{S(x_0,r)} &#92;Delta r&#92; dS' title='&#92;displaystyle &#92;frac{d}{dr} &#92;hbox{Area}(S(x_0,r)) = &#92;int_{S(x_0,r)} &#92;Delta r&#92; dS' class='latex' /> (1)</p>
<p style="text-align:left;">where <img src='http://s0.wp.com/latex.php?latex=dS&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='dS' title='dS' class='latex' /> is the area element.  The monotonicity of <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BArea%7D%28S%28x_0%2Cr%29%29%2Fr%5E%7Bd-1%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Area}(S(x_0,r))/r^{d-1}' title='&#92;hbox{Area}(S(x_0,r))/r^{d-1}' class='latex' /> then follows (formally, at least) from the pointwise inequality</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5CDelta+r+%5Cleq+%5Cfrac%7Bd-1%7D%7Br%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;Delta r &#92;leq &#92;frac{d-1}{r}' title='&#92;displaystyle &#92;Delta r &#92;leq &#92;frac{d-1}{r}' class='latex' /> (2)</p>
<p style="text-align:left;">which we will derive shortly (at least for the portion of the manifold inside the cut locus) as a consequence of the first and second variation formulae for geodesics.  (In the <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/27/285g-lecture-9-comparison-geometry-the-high-dimensional-limit-and-perelman-reduced-volume/">previous lecture</a>, the inequality (2) was derived from a transport inequality for <img src='http://s0.wp.com/latex.php?latex=%5CDelta+r&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Delta r' title='&#92;Delta r' class='latex' />, but we will take a slightly different tack here.)  Observe that (2) is an equality when (M,g) is a Euclidean space <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+R%7D%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb R}^d' title='{&#92;Bbb R}^d' class='latex' />.</p>
<p style="text-align:left;">It turns out that the monotonicity of Perelman reduced volume for Ricci flows can similarly be reduced to a pointwise inequality, in which the Laplacian <img src='http://s0.wp.com/latex.php?latex=%5CDelta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Delta' title='&#92;Delta' class='latex' /> is replaced by a heat operator, and the radial variable r is replaced by the Perelman reduced length.  More precisely, given an ancient Ricci flow <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> for <img src='http://s0.wp.com/latex.php?latex=t+%5Cin+%28-%5Cinfty%2C0%5D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;in (-&#92;infty,0]' title='t &#92;in (-&#92;infty,0]' class='latex' />, a time <img src='http://s0.wp.com/latex.php?latex=-%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='-&#92;tau' title='-&#92;tau' class='latex' />, and two points <img src='http://s0.wp.com/latex.php?latex=x_0%2C+x+%5Cin+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0, x &#92;in M' title='x_0, x &#92;in M' class='latex' />, recall that the reduced length <img src='http://s0.wp.com/latex.php?latex=l_%7B%280%2Cx_0%29%7D%28+-%5Ctau%2Cx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_{(0,x_0)}( -&#92;tau,x)' title='l_{(0,x_0)}( -&#92;tau,x)' class='latex' /> is defined as</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+l_%7B%280%2Cx_0%29%7D%28+-%5Ctau%2Cx%29+%3A%3D+%5Cfrac%7B1%7D%7B2%5Csqrt%7B%5Ctau%7D%7D+%5Cinf_%5Cgamma+%7B%5Cmathcal+L%7D%28%5Cgamma%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle l_{(0,x_0)}( -&#92;tau,x) := &#92;frac{1}{2&#92;sqrt{&#92;tau}} &#92;inf_&#92;gamma {&#92;mathcal L}(&#92;gamma)' title='&#92;displaystyle l_{(0,x_0)}( -&#92;tau,x) := &#92;frac{1}{2&#92;sqrt{&#92;tau}} &#92;inf_&#92;gamma {&#92;mathcal L}(&#92;gamma)' class='latex' /> (3)</p>
<p style="text-align:left;">where the <em><img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-length</em> <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D%28%5Cgamma%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}(&#92;gamma)' title='{&#92;mathcal L}(&#92;gamma)' class='latex' /> of a curve <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%3A+%5B0%2C%5Ctau_1%5D+%5Cto+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma: [0,&#92;tau_1] &#92;to M' title='&#92;gamma: [0,&#92;tau_1] &#92;to M' class='latex' /> from <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=x_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_1' title='x_1' class='latex' /> is defined as</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%7B%5Cmathcal+L%7D%28%5Cgamma%29+%3D+%5Cint_0%5E%7B%5Ctau_1%7D+%5Csqrt%7B%5Ctau%7D+%28R+%2B+%26%23124%3BX%26%23124%3B_%7Bg%28-%5Ctau%29%7D%5E2%29%5C+d%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle {&#92;mathcal L}(&#92;gamma) = &#92;int_0^{&#92;tau_1} &#92;sqrt{&#92;tau} (R + &#124;X&#124;_{g(-&#92;tau)}^2)&#92; d&#92;tau' title='&#92;displaystyle {&#92;mathcal L}(&#92;gamma) = &#92;int_0^{&#92;tau_1} &#92;sqrt{&#92;tau} (R + &#124;X&#124;_{g(-&#92;tau)}^2)&#92; d&#92;tau' class='latex' />, (4)</p>
<p style="text-align:left;">where we adopt the shorthand <img src='http://s0.wp.com/latex.php?latex=X+%3A%3D+%5Cpartial_%7B%5Ctau%7D+%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='X := &#92;partial_{&#92;tau} &#92;gamma' title='X := &#92;partial_{&#92;tau} &#92;gamma' class='latex' />, and that Conjecture 1 from the <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/27/285g-lecture-9-comparison-geometry-the-high-dimensional-limit-and-perelman-reduced-volume/">previous lecture</a> asserts that the Perelman reduced volume</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Ctilde+V_%7B%280%2Cx_0%29%7D%28-%5Ctau%29+%3D+%5Cint_M+%5Ctau%5E%7B-d%2F2%7D+%5Cexp%28+-+l_%7B%280%2Cx_0%29%7D%28-%5Ctau%2Cx%29+%29%5C+d%5Cmu_%7Bg%28-%5Ctau%29%7D%28x%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;tilde V_{(0,x_0)}(-&#92;tau) = &#92;int_M &#92;tau^{-d/2} &#92;exp( - l_{(0,x_0)}(-&#92;tau,x) )&#92; d&#92;mu_{g(-&#92;tau)}(x)' title='&#92;displaystyle &#92;tilde V_{(0,x_0)}(-&#92;tau) = &#92;int_M &#92;tau^{-d/2} &#92;exp( - l_{(0,x_0)}(-&#92;tau,x) )&#92; d&#92;mu_{g(-&#92;tau)}(x)' class='latex' /> (5)</p>
<p style="text-align:left;">is non-increasing in <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' /> for Ricci flows.  If we differentiate (5) in <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' />, using the variation formula <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bd%7D%7Bd%5Ctau%7D+d%5Cmu+%3D+R%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{d}{d&#92;tau} d&#92;mu = R&#92; d&#92;mu' title='&#92;frac{d}{d&#92;tau} d&#92;mu = R&#92; d&#92;mu' class='latex' />, we easily verify that the monotonicity of (5) will follow (assuming <img src='http://s0.wp.com/latex.php?latex=l_%7B%280%2Cx_0%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_{(0,x_0)}' title='l_{(0,x_0)}' class='latex' /> is sufficiently smooth, and that either M is compact, or <img src='http://s0.wp.com/latex.php?latex=l_%7B%280%2Cx_0%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_{(0,x_0)}' title='l_{(0,x_0)}' class='latex' /> grows sufficiently quickly at infinity) from the pointwise inequality</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cpartial_%7B%5Ctau%7D+l_%7B%280%2Cx_0%29%7D+-+%5CDelta_%7Bg%28-%5Ctau%29%7D+l_%7B%280%2Cx_0%29%7D+%2B+%26%23124%3B%5Cnabla+l%26%23124%3B_%7Bg%28-%5Ctau%29%7D%5E2+-+R+%2B+%5Cfrac%7Bd%7D%7B2%5Ctau%7D+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;partial_{&#92;tau} l_{(0,x_0)} - &#92;Delta_{g(-&#92;tau)} l_{(0,x_0)} + &#124;&#92;nabla l&#124;_{g(-&#92;tau)}^2 - R + &#92;frac{d}{2&#92;tau} &#92;geq 0' title='&#92;displaystyle &#92;partial_{&#92;tau} l_{(0,x_0)} - &#92;Delta_{g(-&#92;tau)} l_{(0,x_0)} + &#124;&#92;nabla l&#124;_{g(-&#92;tau)}^2 - R + &#92;frac{d}{2&#92;tau} &#92;geq 0' class='latex' /> (6)</p>
<p style="text-align:left;">which should be viewed as a parabolic analogue to (2).</p>
<p style="text-align:left;"><strong>Exercise 1. </strong>Verify that (6) is an equality in the case of the (trivial) Ricci flow on Euclidean space, using Example 1 from the <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/27/285g-lecture-9-comparison-geometry-the-high-dimensional-limit-and-perelman-reduced-volume/">previous lecture</a>.  (This is of course consistent with Example 2 from that lecture.) <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;"><strong>Exercise 2.</strong> Show that (6) is equivalent to the assertion that the function <img src='http://s0.wp.com/latex.php?latex=v%28-%5Ctau%2Cx%29+%3A%3D+%284%5Cpi+%5Ctau%29%5E%7B-d%2F2%7D+%5Cexp%28-l_%7B%280%2Cx_0%29%7D%28-%5Ctau%2Cx%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='v(-&#92;tau,x) := (4&#92;pi &#92;tau)^{-d/2} &#92;exp(-l_{(0,x_0)}(-&#92;tau,x))' title='v(-&#92;tau,x) := (4&#92;pi &#92;tau)^{-d/2} &#92;exp(-l_{(0,x_0)}(-&#92;tau,x))' class='latex' /> is a subsolution of the adjoint heat equation, or more precisely that <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+v+-+%5CDelta+v+%2B+Rv+%5Cleq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t v - &#92;Delta v + Rv &#92;leq 0' title='&#92;partial_t v - &#92;Delta v + Rv &#92;leq 0' class='latex' />.  Note that this fact implies the monotonicity of Perelman reduced volume (cf. Exercise 2 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/24/285a-lecture-8-ricci-flow-as-a-gradient-flow-log-sobolev-inequalities-and-perelman-entropy/">Lecture 8</a>). [It seems that the elliptic analogue of this fact is the assertion that the <a href="http://en.wikipedia.org/wiki/Newtonian_potential">Newton-type potential</a> <img src='http://s0.wp.com/latex.php?latex=1%2Fr%5E%7Bd-2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='1/r^{d-2}' title='1/r^{d-2}' class='latex' /> is subharmonic away from the origin for Ricci flat manifolds of dimension three or larger , which is a claim which is easily seen to be equivalent to (2) thanks to the Gauss lemma.] <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;">So to prove monotonicity of the Perelman reduced volume, the main task will be to establish the pointwise inequality (6).  (There are some additional technical issues, mainly concerning the parabolic counterpart of the cut locus, which we will also have to address, but we will work formally for now, and deal with these analytical matters later.)</p>
<p style="text-align:left;">We will perform a minor simplification: by using the rescaling symmetry <img src='http://s0.wp.com/latex.php?latex=g%28t%2Cx%29+%5Cmapsto+%5Clambda%5E2+g%28%5Cfrac%7Bt%7D%7B%5Clambda%5E2%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='g(t,x) &#92;mapsto &#92;lambda^2 g(&#92;frac{t}{&#92;lambda^2})' title='g(t,x) &#92;mapsto &#92;lambda^2 g(&#92;frac{t}{&#92;lambda^2})' class='latex' /> (and noting the unsurprising fact that (6) is dimensionally consistent) we can normalise <img src='http://s0.wp.com/latex.php?latex=%5Ctau_1+%3D+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau_1 = 1' title='&#92;tau_1 = 1' class='latex' />.</p>
<p style="text-align:center;">&#8211; First and second variation formulae for <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-geodesics &#8211;</p>
<p style="text-align:left;">To establish (6), we of course need some <em>variation formulae</em> that compute the first and second derivatives of the reduced length function <img src='http://s0.wp.com/latex.php?latex=l_%7B%280%2Cx_0%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_{(0,x_0)}' title='l_{(0,x_0)}' class='latex' />.  To motivate these formulae, let us first recall the more classical variation formulae that give the first and second derivatives of the metric function <img src='http://s0.wp.com/latex.php?latex=d%28x_0%2Cx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d(x_0,x)' title='d(x_0,x)' class='latex' /> on a Riemannian manifold (M,g), which in particular can be used to derive (2) when the Ricci curvature is non-negative.</p>
<p style="text-align:left;">We recall that the distance <img src='http://s0.wp.com/latex.php?latex=d%28x_0%2Cx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d(x_0,x)' title='d(x_0,x)' class='latex' /> can be defined by the energy-minimisation formula</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7B1%7D%7B2%7D+d%28x_0%2Cx%29%5E2+%3D+%5Cinf_%5Cgamma+E%28%5Cgamma%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{1}{2} d(x_0,x)^2 = &#92;inf_&#92;gamma E(&#92;gamma)' title='&#92;displaystyle &#92;frac{1}{2} d(x_0,x)^2 = &#92;inf_&#92;gamma E(&#92;gamma)' class='latex' /> (7)</p>
<p style="text-align:left;">where <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%3A+%5B0%2C1%5D+%5Cto+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma: [0,1] &#92;to M' title='&#92;gamma: [0,1] &#92;to M' class='latex' /> ranges over all <img src='http://s0.wp.com/latex.php?latex=C%5E1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C^1' title='C^1' class='latex' /> curves from <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' /> to x, where the <a href="http://en.wikipedia.org/wiki/Dirichlet_energy">Dirichlet energy</a> <img src='http://s0.wp.com/latex.php?latex=E%28%5Cgamma%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='E(&#92;gamma)' title='E(&#92;gamma)' class='latex' /> of the curve is given by the formula</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+E%28%5Cgamma%29+%3D+%5Cfrac%7B1%7D%7B2%7D+%5Cint_0%5E1+%26%23124%3BX%26%23124%3B_g%5E2%5C+dt&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle E(&#92;gamma) = &#92;frac{1}{2} &#92;int_0^1 &#124;X&#124;_g^2&#92; dt' title='&#92;displaystyle E(&#92;gamma) = &#92;frac{1}{2} &#92;int_0^1 &#124;X&#124;_g^2&#92; dt' class='latex' /> (8)</p>
<p style="text-align:left;">where we write <img src='http://s0.wp.com/latex.php?latex=X+%3A%3D+%5Cpartial_t+%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='X := &#92;partial_t &#92;gamma' title='X := &#92;partial_t &#92;gamma' class='latex' />.  It is known that this infimum is always attained by some geodesic <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' />; we shall assume this implicitly in the computations which follow.</p>
<p style="text-align:left;">Now suppose that we deform such a curve <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' /> with respect to a real parameter <img src='http://s0.wp.com/latex.php?latex=s+%5Cin+%28-%5Cvarepsilon%2C%5Cvarepsilon%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='s &#92;in (-&#92;varepsilon,&#92;varepsilon)' title='s &#92;in (-&#92;varepsilon,&#92;varepsilon)' class='latex' />, thus <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%3A+%28s%2Ct%29+%5Cmapsto+%5Cgamma%28s%2Ct%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma: (s,t) &#92;mapsto &#92;gamma(s,t)' title='&#92;gamma: (s,t) &#92;mapsto &#92;gamma(s,t)' class='latex' /> is now a function on the two-dimensional parameter space <img src='http://s0.wp.com/latex.php?latex=%28%5Cvarepsilon%2C%5Cvarepsilon%29+%5Ctimes+%5B0%2C1%5D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;varepsilon,&#92;varepsilon) &#92;times [0,1]' title='(&#92;varepsilon,&#92;varepsilon) &#92;times [0,1]' class='latex' />.  The first variation here can be computed as</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bds%7D+E%28%5Cgamma%29+%3D+%5Cint_0%5E1+g%28+%5Cnabla_X+X%2C+X+%29%5C+dt&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{ds} E(&#92;gamma) = &#92;int_0^1 g( &#92;nabla_X X, X )&#92; dt' title='&#92;displaystyle &#92;frac{d}{ds} E(&#92;gamma) = &#92;int_0^1 g( &#92;nabla_X X, X )&#92; dt' class='latex' /> (9)</p>
<p style="text-align:left;">where <img src='http://s0.wp.com/latex.php?latex=%5Cnabla_X&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_X' title='&#92;nabla_X' class='latex' /> is the pullback of the Levi-Civita connection on M with respect to <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' /> applied in the direction <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t' title='&#92;partial_t' class='latex' />; here we of course use that g is parallel with respect to this connection.  The torsion-free nature of this connection gives us the identity</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cnabla_Y+X+%3D+%5Cnabla_X+Y&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_Y X = &#92;nabla_X Y' title='&#92;nabla_Y X = &#92;nabla_X Y' class='latex' /> (10)</p>
<p style="text-align:left;">where <img src='http://s0.wp.com/latex.php?latex=Y+%3D+%5Cpartial_s+%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='Y = &#92;partial_s &#92;gamma' title='Y = &#92;partial_s &#92;gamma' class='latex' /> is the infinitesimal variation, and <img src='http://s0.wp.com/latex.php?latex=%5Cnabla_Y&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_Y' title='&#92;nabla_Y' class='latex' /> is the pullback of the Levi-Civita connection applied in the direction <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_s&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_s' title='&#92;partial_s' class='latex' /> (cf. Exercise 5 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/18/285g-lecture-6-finite-time-extinction-of-the-third-homotopy-group-ii/">Lecture 6</a>).  An integration by parts (again using the parallel nature of g) then gives the first variation formula</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bds%7D+E%28%5Cgamma%29+%3D+g%28+Y%2C+X+%29%26%23124%3B_%7Bt%3D0%7D%5E1+-+%5Cint_0%5E1+g%28+Y%2C+%5Cnabla_X+X+%29%5C+dt&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{ds} E(&#92;gamma) = g( Y, X )&#124;_{t=0}^1 - &#92;int_0^1 g( Y, &#92;nabla_X X )&#92; dt' title='&#92;displaystyle &#92;frac{d}{ds} E(&#92;gamma) = g( Y, X )&#124;_{t=0}^1 - &#92;int_0^1 g( Y, &#92;nabla_X X )&#92; dt' class='latex' />. (11)</p>
<p style="text-align:left;">If we fix the endpoints of <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' /> to be <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%28s%2C0%29+%3D+x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma(s,0) = x_0' title='&#92;gamma(s,0) = x_0' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%28s%2C1%29%3Dx_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma(s,1)=x_1' title='&#92;gamma(s,1)=x_1' class='latex' />, then the first term on the right-hand side of (11) vanishes.  If we consider arbitrary infinitesimal variations <img src='http://s0.wp.com/latex.php?latex=Y&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='Y' title='Y' class='latex' /> of <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' /> with fixed endpoints, we thus conclude that in order to be a minimiser for (7), that <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' /> must obey the <em>geodesic flow equation</em></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cnabla_X+X+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_X X = 0' title='&#92;nabla_X X = 0' class='latex' />. (12)</p>
<p style="text-align:left;">One consequence of this is that the speed <img src='http://s0.wp.com/latex.php?latex=%26%23124%3BX%26%23124%3B_g&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;X&#124;_g' title='&#124;X&#124;_g' class='latex' /> of such a minimiser must be constant, and from (7) we then conclude</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%26%23124%3BX%26%23124%3B_g+%3D+d%28x_0%2Cx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;X&#124;_g = d(x_0,x)' title='&#124;X&#124;_g = d(x_0,x)' class='latex' />. (13)</p>
<p style="text-align:left;">If we then vary a geodesic <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%280%2C%5Ccdot%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma(0,&#92;cdot)' title='&#92;gamma(0,&#92;cdot)' class='latex' /> with the initial endpoint <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%28s%2C0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma(s,0)' title='&#92;gamma(s,0)' class='latex' /> fixed at <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' /> and the final endpoint <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%28s%2C1%29+%3D+x%28s%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma(s,1) = x(s)' title='&#92;gamma(s,1) = x(s)' class='latex' /> variable, the variation formula (11) gives</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bds%7D+E%28%5Cgamma%29+%3D+g%28+x%27%28s%29%2C+X%28s%2C1%29+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{ds} E(&#92;gamma) = g( x&#039;(s), X(s,1) )' title='&#92;displaystyle &#92;frac{d}{ds} E(&#92;gamma) = g( x&#039;(s), X(s,1) )' class='latex' /> (14)</p>
<p style="text-align:left;">which, if we insert this back into (7) and use (13), gives</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bds%7D+d%28x_0%2Cx%29+%5Cleq+g%28+x%27%28s%29%2C+X%28s%2C1%29+%2F+%26%23124%3BX%28s%2C1%29%26%23124%3B_g+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{ds} d(x_0,x) &#92;leq g( x&#039;(s), X(s,1) / &#124;X(s,1)&#124;_g )' title='&#92;displaystyle &#92;frac{d}{ds} d(x_0,x) &#92;leq g( x&#039;(s), X(s,1) / &#124;X(s,1)&#124;_g )' class='latex' /> (13)</p>
<p style="text-align:left;">which is a (one-sided) version of the Gauss lemma. If one is inside the <a href="http://en.wikipedia.org/wiki/Cut_locus">cut locus</a>, then the metric function is smooth, and one can then replace the inequality with an equality by considering variations both forwards and backwards in the s variable, recovering the full Gauss lemma.  In particular, we conclude in this case that <img src='http://s0.wp.com/latex.php?latex=%5Cnabla+d%28x_0%2Cx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla d(x_0,x)' title='&#92;nabla d(x_0,x)' class='latex' /> is a unit vector.</p>
<p style="text-align:left;">Now we consider the second variation <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bd%5E2%7D%7Bds%5E2%7D+E%28%5Cgamma%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{d^2}{ds^2} E(&#92;gamma)' title='&#92;frac{d^2}{ds^2} E(&#92;gamma)' class='latex' /> of the energy, when <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' /> is already a geodesic.  For simplicity we assume that <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' /> evolves geodesically in the s direction, thus</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cnabla_Y+Y+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_Y Y = 0' title='&#92;nabla_Y Y = 0' class='latex' />. (14)</p>
<p style="text-align:left;">[Actually, since <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' /> is already a geodesic and thus is stationary with respect to perturbations that respect the endpoints, the values of <img src='http://s0.wp.com/latex.php?latex=%5Cnabla_Y+Y&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_Y Y' title='&#92;nabla_Y Y' class='latex' /> away from endpoints - which represents a second-order perturbation respecting the endpoints - will have no ultimate effect on the second variation of <img src='http://s0.wp.com/latex.php?latex=E%28%5Cgamma%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='E(&#92;gamma)' title='E(&#92;gamma)' class='latex' />.  Nevertheless it is convenient to assume (14) to avoid a few routine additional calculations.]</p>
<p style="text-align:left;">Differentiating (9) once more we obtain</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%5E2%7D%7Bds%5E2%7D+E%28%5Cgamma%29+%3D+%5Cint_0%5E1+g%28+%5Cnabla_Y+%5Cnabla_Y+X%2C+X+%29+%2B+%26%23124%3B%5Cnabla_Y+X%26%23124%3B_g%5E2+%5C+dt&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d^2}{ds^2} E(&#92;gamma) = &#92;int_0^1 g( &#92;nabla_Y &#92;nabla_Y X, X ) + &#124;&#92;nabla_Y X&#124;_g^2 &#92; dt' title='&#92;displaystyle &#92;frac{d^2}{ds^2} E(&#92;gamma) = &#92;int_0^1 g( &#92;nabla_Y &#92;nabla_Y X, X ) + &#124;&#92;nabla_Y X&#124;_g^2 &#92; dt' class='latex' />. (15)</p>
<p style="text-align:left;">Using (10), (14), and the definition of curvature, we have</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cnabla_Y+%5Cnabla_Y+X+%3D+%5Cnabla_Y+%5Cnabla_X+Y&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_Y &#92;nabla_Y X = &#92;nabla_Y &#92;nabla_X Y' title='&#92;nabla_Y &#92;nabla_Y X = &#92;nabla_Y &#92;nabla_X Y' class='latex' /></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%3D+%5Cnabla_X+%5Cnabla_Y+Y+%2B+%5Chbox%7BRiem%7D%28+Y%2C+X+%29+Y&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='= &#92;nabla_X &#92;nabla_Y Y + &#92;hbox{Riem}( Y, X ) Y' title='= &#92;nabla_X &#92;nabla_Y Y + &#92;hbox{Riem}( Y, X ) Y' class='latex' /> (16)</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%3D+-%5Chbox%7BRiem%7D%28+X%2C+Y+%29+Y&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='= -&#92;hbox{Riem}( X, Y ) Y' title='= -&#92;hbox{Riem}( X, Y ) Y' class='latex' /></p>
<p style="text-align:left;">and thus (by one further application of (10))</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%5E2%7D%7Bds%5E2%7D+E%28%5Cgamma%29+%3D+%5Cint_0%5E1+%26%23124%3B%5Cnabla_X+Y%26%23124%3B_g%5E2+-+g%28%5Chbox%7BRiem%7D%28X%2C+Y%29+Y%2C+X%29%5C+dt&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d^2}{ds^2} E(&#92;gamma) = &#92;int_0^1 &#124;&#92;nabla_X Y&#124;_g^2 - g(&#92;hbox{Riem}(X, Y) Y, X)&#92; dt' title='&#92;displaystyle &#92;frac{d^2}{ds^2} E(&#92;gamma) = &#92;int_0^1 &#124;&#92;nabla_X Y&#124;_g^2 - g(&#92;hbox{Riem}(X, Y) Y, X)&#92; dt' class='latex' />. (17)</p>
<p style="text-align:left;">Now let us fix the initial endpoint <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%28s%2C0%29+%3D+x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma(s,0) = x_0' title='&#92;gamma(s,0) = x_0' class='latex' /> and let the other endpoint <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%28s%2C1%29+%3D+x%28s%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma(s,1) = x(s)' title='&#92;gamma(s,1) = x(s)' class='latex' /> vary, thus <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_s+%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_s &#92;gamma' title='&#92;partial_s &#92;gamma' class='latex' /> equals 0 at time t=0 and equals <img src='http://s0.wp.com/latex.php?latex=x%27%28s%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x&#039;(s)' title='x&#039;(s)' class='latex' /> at time t=1.  From Cauchy-Schwarz we conclude</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cint_0%5E1+%26%23124%3B%5Cnabla_X+Y%26%23124%3B_g%5E2%5C+dt+%5Cleq+%5Cint_0%5E1+%28%5Cpartial_t+%26%23124%3BY%26%23124%3B_g%29%5E2%5C+dt+%5Cleq+%28%5Cint_0%5E1+%5Cpartial_t+%26%23124%3BY%26%23124%3B_g%5C+dt%29%5E2+%3D+%26%23124%3Bx%27%28s%29%26%23124%3B%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_0^1 &#124;&#92;nabla_X Y&#124;_g^2&#92; dt &#92;leq &#92;int_0^1 (&#92;partial_t &#124;Y&#124;_g)^2&#92; dt &#92;leq (&#92;int_0^1 &#92;partial_t &#124;Y&#124;_g&#92; dt)^2 = &#124;x&#039;(s)&#124;^2' title='&#92;int_0^1 &#124;&#92;nabla_X Y&#124;_g^2&#92; dt &#92;leq &#92;int_0^1 (&#92;partial_t &#124;Y&#124;_g)^2&#92; dt &#92;leq (&#92;int_0^1 &#92;partial_t &#124;Y&#124;_g&#92; dt)^2 = &#124;x&#039;(s)&#124;^2' class='latex' />. (18)</p>
<p style="text-align:left;">Actually, we can attain equality here by choosing the vector field <img src='http://s0.wp.com/latex.php?latex=Y&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='Y' title='Y' class='latex' /> appropriately:</p>
<p style="text-align:left;"><strong>Exercise 3.</strong> If we set <img src='http://s0.wp.com/latex.php?latex=Y+%3A%3D+t+v&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='Y := t v' title='Y := t v' class='latex' />, where v is the parallel transport of x&#8217;(s) along X, or more precisely the vector field that solves the ODE</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cnabla_X+v+%3D+0%3B+v%28s%2C1%29+%3D+x%27%28s%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_X v = 0; v(s,1) = x&#039;(s)' title='&#92;nabla_X v = 0; v(s,1) = x&#039;(s)' class='latex' /> (19)</p>
<p>show that all the inequalities in (18) are obeyed with equality. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>For such a vector field, we conclude that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%5E2%7D%7Bds%5E2%7D+E%28%5Cgamma%29+%3D+%26%23124%3Bx%27%28s%29%26%23124%3B%5E2+-+%5Cint_0%5E1+-+t%5E2+g%28%5Chbox%7BRiem%7D%28X%2C+v%29+v%2C+X%29%5C+dt&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d^2}{ds^2} E(&#92;gamma) = &#124;x&#039;(s)&#124;^2 - &#92;int_0^1 - t^2 g(&#92;hbox{Riem}(X, v) v, X)&#92; dt' title='&#92;displaystyle &#92;frac{d^2}{ds^2} E(&#92;gamma) = &#124;x&#039;(s)&#124;^2 - &#92;int_0^1 - t^2 g(&#92;hbox{Riem}(X, v) v, X)&#92; dt' class='latex' />. (20)</p>
<p>From this formula (and the first variation formula) we conclude that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%5E2%7D%7Bds%5E2%7D+%5Cfrac%7B1%7D%7B2%7D+d%28x_0%2Cx%29%5E2+%5Cleq+%26%23124%3Bx%27%28s%29%26%23124%3B%5E2+-+%5Cint_0%5E1+t%5E2+g%28%5Chbox%7BRiem%7D%28X%2C+v%29+v%2C+X%29%5C+dt&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d^2}{ds^2} &#92;frac{1}{2} d(x_0,x)^2 &#92;leq &#124;x&#039;(s)&#124;^2 - &#92;int_0^1 t^2 g(&#92;hbox{Riem}(X, v) v, X)&#92; dt' title='&#92;displaystyle &#92;frac{d^2}{ds^2} &#92;frac{1}{2} d(x_0,x)^2 &#92;leq &#124;x&#039;(s)&#124;^2 - &#92;int_0^1 t^2 g(&#92;hbox{Riem}(X, v) v, X)&#92; dt' class='latex' />. (21)</p>
<p>Now let <img src='http://s0.wp.com/latex.php?latex=x%27%280%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x&#039;(0)' title='x&#039;(0)' class='latex' /> vary over an orthonormal basis of the tangent space of x(0); by (19) we see that v determines an <a href="http://en.wikipedia.org/wiki/Orthonormal_frame">orthonormal frame</a> for s=0 and <img src='http://s0.wp.com/latex.php?latex=0+%5Cleq+t+%5Cleq+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &#92;leq t &#92;leq 1' title='0 &#92;leq t &#92;leq 1' class='latex' />.  Summing (21) over this basis (and using the formula for the Laplacian in <a href="http://en.wikipedia.org/wiki/Normal_coordinates">normal coordinates</a>) we conclude that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5CDelta+%5Cfrac%7B1%7D%7B2%7D+d%28x_0%2Cx%29%5E2+%5Cleq+d+-+%5Cint_0%5E1+t%5E2+%5Chbox%7BRic%7D%28X%2CX%29%5C+dt&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;Delta &#92;frac{1}{2} d(x_0,x)^2 &#92;leq d - &#92;int_0^1 t^2 &#92;hbox{Ric}(X,X)&#92; dt' title='&#92;displaystyle &#92;Delta &#92;frac{1}{2} d(x_0,x)^2 &#92;leq d - &#92;int_0^1 t^2 &#92;hbox{Ric}(X,X)&#92; dt' class='latex' />. (22)</p>
<p style="text-align:left;">In particular, for manifolds of non-negative Ricci curvature we have</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5CDelta+%5Cfrac%7B1%7D%7B2%7D+d%28x_0%2Cx%29%5E2+%5Cleq+d&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;Delta &#92;frac{1}{2} d(x_0,x)^2 &#92;leq d' title='&#92;displaystyle &#92;Delta &#92;frac{1}{2} d(x_0,x)^2 &#92;leq d' class='latex' /> (23)</p>
<p style="text-align:left;">from which (2) easily follows from the Gauss lemma.  (Observe that (23) is obeyed with equality in the Euclidean case.)</p>
<p style="text-align:left;">Now we develop analogous variational formulae for <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-length (and reduced length) on a Ricci flow.  We shall work formally for now, assuming that all infima are actually attained and that all quantities are as smooth as necessary for the analysis that follows to work; we then discuss later how to justify all of these assumptions.  As mentioned earlier, we normalise <img src='http://s0.wp.com/latex.php?latex=%5Ctau_1+%3D+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau_1 = 1' title='&#92;tau_1 = 1' class='latex' />.</p>
<p style="text-align:left;">Let us take a path <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%3A+%5B0%2C1%5D+%5Cto+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma: [0,1] &#92;to M' title='&#92;gamma: [0,1] &#92;to M' class='latex' /> and vary it with respect to some additional parameter s as before.  Differentiating (4), we obtain</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bds%7D+%7B%5Cmathcal+L%7D%28%5Cgamma%29+%3D+%5Cint_0%5E1+%5Csqrt%7B%5Ctau%7D+%28+%5Cnabla_Y+R+%2B+2+g%28+X%2C++%5Cnabla_Y+X+%29%29%5C+d%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{ds} {&#92;mathcal L}(&#92;gamma) = &#92;int_0^1 &#92;sqrt{&#92;tau} ( &#92;nabla_Y R + 2 g( X,  &#92;nabla_Y X ))&#92; d&#92;tau' title='&#92;displaystyle &#92;frac{d}{ds} {&#92;mathcal L}(&#92;gamma) = &#92;int_0^1 &#92;sqrt{&#92;tau} ( &#92;nabla_Y R + 2 g( X,  &#92;nabla_Y X ))&#92; d&#92;tau' class='latex' /> (24)</p>
<p>where <img src='http://s0.wp.com/latex.php?latex=X+%3A%3D+%5Cpartial_%5Ctau+%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='X := &#92;partial_&#92;tau &#92;gamma' title='X := &#92;partial_&#92;tau &#92;gamma' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=Y+%3A%3D+%5Cpartial_s+%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='Y := &#92;partial_s &#92;gamma' title='Y := &#92;partial_s &#92;gamma' class='latex' />.  On the other hand, if we have a Ricci flow <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_%5Ctau+g+%3D+2+%5Chbox%7BRic%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_&#92;tau g = 2 &#92;hbox{Ric}' title='&#92;partial_&#92;tau g = 2 &#92;hbox{Ric}' class='latex' />, we see that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cpartial_%5Ctau+g%28+X%2C+Y+%29+%3D+g%28+%5Cnabla_X+X%2C+Y+%29+%2B+g%28+X%2C+%5Cnabla_X+Y+%29+%2B+2+%5Chbox%7BRic%7D%28+X%2C+Y+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_&#92;tau g( X, Y ) = g( &#92;nabla_X X, Y ) + g( X, &#92;nabla_X Y ) + 2 &#92;hbox{Ric}( X, Y )' title='&#92;partial_&#92;tau g( X, Y ) = g( &#92;nabla_X X, Y ) + g( X, &#92;nabla_X Y ) + 2 &#92;hbox{Ric}( X, Y )' class='latex' />; (25)</p>
<p>placing this into (24) and using the fundamental theorem of calculus, we can express the right-hand side of (24) as</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=2+g%28+X%2C+Y+%29%28%5Ctau_1%29+-+2+%5Cint_0%5E1+%5Csqrt%7B%5Ctau%7D+g%28+Y%2C+G%28X%29+%29%5C+d%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='2 g( X, Y )(&#92;tau_1) - 2 &#92;int_0^1 &#92;sqrt{&#92;tau} g( Y, G(X) )&#92; d&#92;tau' title='2 g( X, Y )(&#92;tau_1) - 2 &#92;int_0^1 &#92;sqrt{&#92;tau} g( Y, G(X) )&#92; d&#92;tau' class='latex' /> (26)</p>
<p>where G(X) is the vector field</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=G+%3A%3D+%5Cnabla_X+X+-+%5Cfrac%7B1%7D%7B2%7D+%5Cnabla+R+%2B+%5Cfrac%7B1%7D%7B2%5Ctau%7D+X+%2B+2+%5Chbox%7BRic%7D%28X%2C%5Ccdot%29%5E%2A&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='G := &#92;nabla_X X - &#92;frac{1}{2} &#92;nabla R + &#92;frac{1}{2&#92;tau} X + 2 &#92;hbox{Ric}(X,&#92;cdot)^*' title='G := &#92;nabla_X X - &#92;frac{1}{2} &#92;nabla R + &#92;frac{1}{2&#92;tau} X + 2 &#92;hbox{Ric}(X,&#92;cdot)^*' class='latex' />. (27)</p>
<p style="text-align:left;">Here <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRic%7D%28X%2C%5Ccdot%29%5E%2A&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Ric}(X,&#92;cdot)^*' title='&#92;hbox{Ric}(X,&#92;cdot)^*' class='latex' /> is the vector field <img src='http://s0.wp.com/latex.php?latex=%28%5Chbox%7BRic%7D%28X%2C%5Ccdot%29%5E%2A%29%5E%5Calpha+%3D+g%5E%7B%5Calpha+%5Cbeta%7D+%5Chbox%7BRic%7D_%7B%5Cgamma+%5Cbeta%7D+X%5E%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;hbox{Ric}(X,&#92;cdot)^*)^&#92;alpha = g^{&#92;alpha &#92;beta} &#92;hbox{Ric}_{&#92;gamma &#92;beta} X^&#92;gamma' title='(&#92;hbox{Ric}(X,&#92;cdot)^*)^&#92;alpha = g^{&#92;alpha &#92;beta} &#92;hbox{Ric}_{&#92;gamma &#92;beta} X^&#92;gamma' class='latex' />, or equivalently it is the vector field Z such that <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRic%7D%28X%2CW%29+%3D+g%28Z%2CW%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Ric}(X,W) = g(Z,W)' title='&#92;hbox{Ric}(X,W) = g(Z,W)' class='latex' /> for all vector fields W.</p>
<p>Note that G does not depend on Y.  From this we see that in order for <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' /> to be a minimiser of <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D%28%5Cgamma%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}(&#92;gamma)' title='{&#92;mathcal L}(&#92;gamma)' class='latex' /> with the endpoints fixed, we must have G(X)=0, which is the parabolic analogue of the geodesic flow equation (14).</p>
<p><strong>Example 1. </strong>In the case of the trivial Euclidean flow, the minimal <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-path from <img src='http://s0.wp.com/latex.php?latex=%280%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(0,x_0)' title='(0,x_0)' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=%28-1%2Cx_1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(-1,x_1)' title='(-1,x_1)' class='latex' /> takes the form <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%28%5Ctau%29+%3D+x_0+%2B+v+%5Csqrt%7B%5Ctau%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma(&#92;tau) = x_0 + v &#92;sqrt{&#92;tau}' title='&#92;gamma(&#92;tau) = x_0 + v &#92;sqrt{&#92;tau}' class='latex' /> where <img src='http://s0.wp.com/latex.php?latex=v+%3A%3D+x_1-x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='v := x_1-x_0' title='v := x_1-x_0' class='latex' />, in which case <img src='http://s0.wp.com/latex.php?latex=X+%3D+%5Cfrac%7Bv%7D%7B2%5Csqrt%7B%5Ctau%7D%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='X = &#92;frac{v}{2&#92;sqrt{&#92;tau}}' title='X = &#92;frac{v}{2&#92;sqrt{&#92;tau}}' class='latex' />.  It is not hard to verify that G=0 in this case. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' />.</p>
<p>Arguing as in the elliptic case, we conclude (assuming the existence of a unique minimiser, and the local smoothness of reduced length) the first variation formula</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cpartial_s+l_%7B%280%2Cx_0%29%7D%28-1%2Cx_1%29+%3D+g%28+X%2C+%5Cpartial_s+x_1%29%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_s l_{(0,x_0)}(-1,x_1) = g( X, &#92;partial_s x_1)(1)' title='&#92;partial_s l_{(0,x_0)}(-1,x_1) = g( X, &#92;partial_s x_1)(1)' class='latex' /> (28)</p>
<p style="text-align:left;">or equivalently</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cnabla+l_%7B%280%2Cx_0%29%7D%28-1%2Cx_1%29+%3D+X%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla l_{(0,x_0)}(-1,x_1) = X(1)' title='&#92;nabla l_{(0,x_0)}(-1,x_1) = X(1)' class='latex' />. (29)</p>
<p><strong>Example 2. </strong>Continuing Example 1, note that <img src='http://s0.wp.com/latex.php?latex=l_%7B%280%2Cx_0%29%7D%28-1%2Cx_1%29+%3D+%26%23124%3Bx_1-x_0%26%23124%3B%5E2%2F4&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_{(0,x_0)}(-1,x_1) = &#124;x_1-x_0&#124;^2/4' title='l_{(0,x_0)}(-1,x_1) = &#124;x_1-x_0&#124;^2/4' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_%5Ctau+%5Cgamma+%3D+%28x_1-x_0%29%2F2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_&#92;tau &#92;gamma = (x_1-x_0)/2' title='&#92;partial_&#92;tau &#92;gamma = (x_1-x_0)/2' class='latex' />, which is of course consistent with (28). <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>Having computed the spatial derivative of the reduced length, we turn to the time derivative.  The simplest way to compute this is to observe that any partial segment of an <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-minimising path must again be a <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-minimising path.  From (4) and the fundamental theorem of calculus we have</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bd%5Ctau_1%7D+%7B%5Cmathcal+L%7D%28%5Cgamma%29%26%23124%3B_%7B%5Ctau_1+%3D+1%7D+%3D+R+%2B+%26%23124%3BX%26%23124%3B_g%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{d&#92;tau_1} {&#92;mathcal L}(&#92;gamma)&#124;_{&#92;tau_1 = 1} = R + &#124;X&#124;_g^2' title='&#92;displaystyle &#92;frac{d}{d&#92;tau_1} {&#92;mathcal L}(&#92;gamma)&#124;_{&#92;tau_1 = 1} = R + &#124;X&#124;_g^2' class='latex' /> (30)</p>
<p>where we vary <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' /> in <img src='http://s0.wp.com/latex.php?latex=%5Ctau_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau_1' title='&#92;tau_1' class='latex' /> by truncation; by (3) and the above discussion we conclude</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bd%5Ctau_1%7D+%28+2%5Csqrt%7B%5Ctau_1%7D+l_%7B%280%2Cx_0%29%7D%28-%5Ctau_1%2Cx_1%29+%29%26%23124%3B_%7B%5Ctau_1%3D1%7D+%3D+%28R+%2B+%26%23124%3BX%26%23124%3B_g%5E2%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{d&#92;tau_1} ( 2&#92;sqrt{&#92;tau_1} l_{(0,x_0)}(-&#92;tau_1,x_1) )&#124;_{&#92;tau_1=1} = (R + &#124;X&#124;_g^2)' title='&#92;displaystyle &#92;frac{d}{d&#92;tau_1} ( 2&#92;sqrt{&#92;tau_1} l_{(0,x_0)}(-&#92;tau_1,x_1) )&#124;_{&#92;tau_1=1} = (R + &#124;X&#124;_g^2)' class='latex' /> (31)</p>
<p>where <img src='http://s0.wp.com/latex.php?latex=%28%5Ctau_1%2Cx_1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;tau_1,x_1)' title='(&#92;tau_1,x_1)' class='latex' /> varies along <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' /> (in particular, <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_%7B%5Ctau_1%7D+x_1+%3D+X&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_{&#92;tau_1} x_1 = X' title='&#92;partial_{&#92;tau_1} x_1 = X' class='latex' />).  Applying the product and chain rules, we can expand the left-hand side of (31) as</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=l_%7B%280%2Cx_0%29%7D%28-1%2Cx_1%29+%2B+2+%5Cpartial_%7B%5Ctau_1%7Dl_%7B%280%2Cx_0%29%7D%28-%5Ctau_1%2Cx_1%29%26%23124%3B_%7B%5Ctau_1%3D-1%7D+%2B+2+g%28+%5Cnabla+l_%7B%280%2Cx_0%29%7D%28-1%2Cx_1%29%2C+X+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_{(0,x_0)}(-1,x_1) + 2 &#92;partial_{&#92;tau_1}l_{(0,x_0)}(-&#92;tau_1,x_1)&#124;_{&#92;tau_1=-1} + 2 g( &#92;nabla l_{(0,x_0)}(-1,x_1), X )' title='l_{(0,x_0)}(-1,x_1) + 2 &#92;partial_{&#92;tau_1}l_{(0,x_0)}(-&#92;tau_1,x_1)&#124;_{&#92;tau_1=-1} + 2 g( &#92;nabla l_{(0,x_0)}(-1,x_1), X )' class='latex' />; (32)</p>
<p>using (29), we conclude that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cpartial_%7B%5Ctau_1%7D+l_%7B%280%2Cx_0%29%7D%28-%5Ctau_1%2Cx_1%29%26%23124%3B_%7B%5Ctau_1%3D1%7D+%3D+%5Cfrac%7B1%7D%7B2%7D+%28R+%2B+%26%23124%3BX%26%23124%3B_g%5E2%29+-+%5Cfrac%7B1%7D%7B2%7D+l_%7B%280%2Cx_0%29%7D%28-1%2Cx_1%29+-++%26%23124%3BX%26%23124%3B_g%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_{&#92;tau_1} l_{(0,x_0)}(-&#92;tau_1,x_1)&#124;_{&#92;tau_1=1} = &#92;frac{1}{2} (R + &#124;X&#124;_g^2) - &#92;frac{1}{2} l_{(0,x_0)}(-1,x_1) -  &#124;X&#124;_g^2' title='&#92;partial_{&#92;tau_1} l_{(0,x_0)}(-&#92;tau_1,x_1)&#124;_{&#92;tau_1=1} = &#92;frac{1}{2} (R + &#124;X&#124;_g^2) - &#92;frac{1}{2} l_{(0,x_0)}(-1,x_1) -  &#124;X&#124;_g^2' class='latex' />. (33)</p>
<p>Now we turn to the second spatial variation of the reduced length.  Let <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' /> be a <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-minimiser, so that G=0.  Differentiating (24) again, we obtain</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%5E2%7D%7Bds%5E2%7D+%7B%5Cmathcal+L%7D%28%5Cgamma%29+%3D+%5Cint_0%5E%7B1%7D+%5Csqrt%7B%5Ctau%7D+%28+%5Cnabla_Y+%5Cnabla_Y+R+%2B+2+%26%23124%3B%5Cnabla_Y+X%26%23124%3B%5E2+%2B+2+g%28+X%2C++%5Cnabla_Y+%5Cnabla_Y+X+%29%29%5C+d%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d^2}{ds^2} {&#92;mathcal L}(&#92;gamma) = &#92;int_0^{1} &#92;sqrt{&#92;tau} ( &#92;nabla_Y &#92;nabla_Y R + 2 &#124;&#92;nabla_Y X&#124;^2 + 2 g( X,  &#92;nabla_Y &#92;nabla_Y X ))&#92; d&#92;tau' title='&#92;displaystyle &#92;frac{d^2}{ds^2} {&#92;mathcal L}(&#92;gamma) = &#92;int_0^{1} &#92;sqrt{&#92;tau} ( &#92;nabla_Y &#92;nabla_Y R + 2 &#124;&#92;nabla_Y X&#124;^2 + 2 g( X,  &#92;nabla_Y &#92;nabla_Y X ))&#92; d&#92;tau' class='latex' />. (34)</p>
<p style="text-align:left;">As in the elliptic case, it is convenient to assume that we have a geodesic variation (14).  In that case, we again have (16), and we also have <img src='http://s0.wp.com/latex.php?latex=%5Cnabla_Y+%5Cnabla_Y+R+%3D+%5Chbox%7BHess%7D%28R%29%28Y%2CY%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_Y &#92;nabla_Y R = &#92;hbox{Hess}(R)(Y,Y)' title='&#92;nabla_Y &#92;nabla_Y R = &#92;hbox{Hess}(R)(Y,Y)' class='latex' />.  Using (10), we thus express (34) as</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cint_0%5E%7B1%7D+%5Csqrt%7B%5Ctau%7D+%28+%5Chbox%7BHess%7D%28R%29%28Y%2CY%29+%2B+2+%26%23124%3B%5Cnabla_X+Y%26%23124%3B%5E2+-+2+g%28%5Chbox%7BRiem%7D%28X%2CY%29+Y%2C+X%29%29%5C+d%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_0^{1} &#92;sqrt{&#92;tau} ( &#92;hbox{Hess}(R)(Y,Y) + 2 &#124;&#92;nabla_X Y&#124;^2 - 2 g(&#92;hbox{Riem}(X,Y) Y, X))&#92; d&#92;tau' title='&#92;int_0^{1} &#92;sqrt{&#92;tau} ( &#92;hbox{Hess}(R)(Y,Y) + 2 &#124;&#92;nabla_X Y&#124;^2 - 2 g(&#92;hbox{Riem}(X,Y) Y, X))&#92; d&#92;tau' class='latex' />. (35)</p>
<p style="text-align:left;">As before, we optimise this in Y.  Because the metric g now changes in time by Ricci flow, one has to modify the prescription in Exercise 3 slightly.  More precisely, we now set <img src='http://s0.wp.com/latex.php?latex=Y+%3A%3D+%5Csqrt%7B%5Ctau%7D+v&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='Y := &#92;sqrt{&#92;tau} v' title='Y := &#92;sqrt{&#92;tau} v' class='latex' />, where v solves the following variant of (19),</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cnabla_X+v+%3D+-+%5Chbox%7BRic%7D%28v%2C%5Ccdot%29%5E%2A%3B+v%28s%2C1%29+%3D+x%27%28s%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_X v = - &#92;hbox{Ric}(v,&#92;cdot)^*; v(s,1) = x&#039;(s)' title='&#92;nabla_X v = - &#92;hbox{Ric}(v,&#92;cdot)^*; v(s,1) = x&#039;(s)' class='latex' />. (36)</p>
<p style="text-align:left;">The point of doing this is that the ODE is orthogonal; the length of v is preserved along X, as is the inner product between any two such v&#8217;s (cf. equation (15) from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/03/28/285g-lecture-1-ricci-flow/">Lecture 3</a>).  A brief computation then shows that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cnabla_X+Y+%3D+%5Cfrac%7B1%7D%7B2%5Csqrt%7B%5Ctau%7D%7D++v+-+%5Csqrt%7B%5Ctau%7D+%5Chbox%7BRic%7D%28v%2C%5Ccdot%29%5E%2A&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;nabla_X Y = &#92;frac{1}{2&#92;sqrt{&#92;tau}}  v - &#92;sqrt{&#92;tau} &#92;hbox{Ric}(v,&#92;cdot)^*' title='&#92;displaystyle &#92;nabla_X Y = &#92;frac{1}{2&#92;sqrt{&#92;tau}}  v - &#92;sqrt{&#92;tau} &#92;hbox{Ric}(v,&#92;cdot)^*' class='latex' /> (37)</p>
<p style="text-align:left;">and hence</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%26%23124%3B%5Cnabla_X+Y%26%23124%3B_g%5E2+%3D+%5Cfrac%7B1%7D%7B4%5Ctau%7D+%26%23124%3Bx%27%28s%29%26%23124%3B_g%5E2+%2B+%5Ctau+%26%23124%3B%5Chbox%7BRic%7D%28v%2C%5Ccdot%29%26%23124%3B%5E2+-+%5Chbox%7BRic%7D%28v%2Cv%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#124;&#92;nabla_X Y&#124;_g^2 = &#92;frac{1}{4&#92;tau} &#124;x&#039;(s)&#124;_g^2 + &#92;tau &#124;&#92;hbox{Ric}(v,&#92;cdot)&#124;^2 - &#92;hbox{Ric}(v,v)' title='&#92;displaystyle &#124;&#92;nabla_X Y&#124;_g^2 = &#92;frac{1}{4&#92;tau} &#124;x&#039;(s)&#124;_g^2 + &#92;tau &#124;&#92;hbox{Ric}(v,&#92;cdot)&#124;^2 - &#92;hbox{Ric}(v,v)' class='latex' />. (38)</p>
<p style="text-align:left;">Putting all of this into (35), we now see that the second variation (34) is equal to</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cint_0%5E1+%5Ctau%5E%7B3%2F2%7D+%5Chbox%7BHess%7D%28R%29%28v%2Cv%29+%2B+%5Cfrac%7B1%7D%7B2%5Ctau%5E%7B1%2F2%7D%7D+%26%23124%3Bx%27%28s%29%26%23124%3B_g%5E2+%2B+2%5Ctau%5E%7B3%2F2%7D+%26%23124%3B%5Chbox%7BRic%7D%28v%2C%5Ccdot%29%26%23124%3B%5E2+&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;int_0^1 &#92;tau^{3/2} &#92;hbox{Hess}(R)(v,v) + &#92;frac{1}{2&#92;tau^{1/2}} &#124;x&#039;(s)&#124;_g^2 + 2&#92;tau^{3/2} &#124;&#92;hbox{Ric}(v,&#92;cdot)&#124;^2 ' title='&#92;displaystyle &#92;int_0^1 &#92;tau^{3/2} &#92;hbox{Hess}(R)(v,v) + &#92;frac{1}{2&#92;tau^{1/2}} &#124;x&#039;(s)&#124;_g^2 + 2&#92;tau^{3/2} &#124;&#92;hbox{Ric}(v,&#92;cdot)&#124;^2 ' class='latex' /></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+-+2+%5Ctau%5E%7B1%2F2%7D+%5Chbox%7BRic%7D%28v%2Cv%29+-+2%5Ctau%5E%7B3%2F2%7D+g%28%5Chbox%7BRiem%7D%28X%2Cv%29+v%2C+X%29%5C+d%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle - 2 &#92;tau^{1/2} &#92;hbox{Ric}(v,v) - 2&#92;tau^{3/2} g(&#92;hbox{Riem}(X,v) v, X)&#92; d&#92;tau' title='&#92;displaystyle - 2 &#92;tau^{1/2} &#92;hbox{Ric}(v,v) - 2&#92;tau^{3/2} g(&#92;hbox{Riem}(X,v) v, X)&#92; d&#92;tau' class='latex' />. (39)</p>
<p style="text-align:left;">We now let <img src='http://s0.wp.com/latex.php?latex=x%27%280%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x&#039;(0)' title='x&#039;(0)' class='latex' /> range over an orthonormal basis of <img src='http://s0.wp.com/latex.php?latex=x%280%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x(0)' title='x(0)' class='latex' />, which leads to v being an orthonormal frame at every point (0,t).  Summing over (39) and also using (3), we conclude that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5CDelta+l_%7B%280%2Cx_0%29%7D%28-1%2Cx_1%29+%5Cleq+%5Cint_0%5E%7B1%7D+%5Cfrac%7B%5Ctau%5E%7B3%2F2%7D%7D%7B2%7D+%5CDelta+R+%2B+%5Cfrac%7Bd%7D%7B4%5Ctau%5E%7B1%2F2%7D%7D+%2B+%5Ctau%5E%7B3%2F2%7D%26%23124%3B%5Chbox%7BRic%7D%26%23124%3B_g%5E2+-+%5Ctau%5E%7B1%2F2%7D+R+-+%5Ctau%5E%7B3%2F2%7D+%5Chbox%7BRic%7D%28X%2CX%29%5C+d%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;Delta l_{(0,x_0)}(-1,x_1) &#92;leq &#92;int_0^{1} &#92;frac{&#92;tau^{3/2}}{2} &#92;Delta R + &#92;frac{d}{4&#92;tau^{1/2}} + &#92;tau^{3/2}&#124;&#92;hbox{Ric}&#124;_g^2 - &#92;tau^{1/2} R - &#92;tau^{3/2} &#92;hbox{Ric}(X,X)&#92; d&#92;tau' title='&#92;displaystyle &#92;Delta l_{(0,x_0)}(-1,x_1) &#92;leq &#92;int_0^{1} &#92;frac{&#92;tau^{3/2}}{2} &#92;Delta R + &#92;frac{d}{4&#92;tau^{1/2}} + &#92;tau^{3/2}&#124;&#92;hbox{Ric}&#124;_g^2 - &#92;tau^{1/2} R - &#92;tau^{3/2} &#92;hbox{Ric}(X,X)&#92; d&#92;tau' class='latex' />. (40)</p>
<p style="text-align:left;">Now we simplify the right-hand side of (40).  The second term is of course elementary:</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cint_0%5E1+%5Cfrac%7Bd%7D%7B4%5Ctau%5E%7B1%2F2%7D%7D%5C+d%5Ctau+%3D+%5Cfrac%7Bd%7D%7B2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;int_0^1 &#92;frac{d}{4&#92;tau^{1/2}}&#92; d&#92;tau = &#92;frac{d}{2}' title='&#92;displaystyle &#92;int_0^1 &#92;frac{d}{4&#92;tau^{1/2}}&#92; d&#92;tau = &#92;frac{d}{2}' class='latex' /> (41)</p>
<p style="text-align:left;">and this is consistent with the Euclidean case (in which <img src='http://s0.wp.com/latex.php?latex=%5CDelta+l_%7B%280%2Cx_0%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Delta l_{(0,x_0)}' title='&#92;Delta l_{(0,x_0)}' class='latex' /> is exactly <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bd%7D%7B2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{d}{2}' title='&#92;frac{d}{2}' class='latex' /> when <img src='http://s0.wp.com/latex.php?latex=%5Ctau_1%3D1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau_1=1' title='&#92;tau_1=1' class='latex' />, and all curvature terms vanish).  To simplify the remaining terms, we recall the variation formula</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=-%5Cpartial_%5Ctau+R+%3D+%5CDelta+R+%2B+2+%26%23124%3B%5Chbox%7BRic%7D%26%23124%3B_g%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='-&#92;partial_&#92;tau R = &#92;Delta R + 2 &#124;&#92;hbox{Ric}&#124;_g^2' title='-&#92;partial_&#92;tau R = &#92;Delta R + 2 &#124;&#92;hbox{Ric}&#124;_g^2' class='latex' /> (42)</p>
<p style="text-align:left;">for the scalar curvature (equation (31) of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/03/28/285g-lecture-1-ricci-flow/">Lecture 1</a>); by the chain rule, we thu have the total derivative formula</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bd%7D%7Bd%5Ctau%7D+R+%3D+-%5CDelta+R+-+2+%26%23124%3B%5Chbox%7BRic%7D%26%23124%3B_g%5E2+%2B+%5Cnabla_X+R&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{d}{d&#92;tau} R = -&#92;Delta R - 2 &#124;&#92;hbox{Ric}&#124;_g^2 + &#92;nabla_X R' title='&#92;frac{d}{d&#92;tau} R = -&#92;Delta R - 2 &#124;&#92;hbox{Ric}&#124;_g^2 + &#92;nabla_X R' class='latex' />. (43)</p>
<p style="text-align:left;">Inserting (41), (43) into (40) and integrating by parts, we express the right-hand side of (40) as</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7B2%7D+-+%5Cfrac%7B1%7D%7B2%7D+R+%2B+%5Cint_0%5E%7B1%7D++%5Cfrac%7B%5Ctau%5E%7B3%2F2%7D%7D%7B2%7D++%5Cnabla_X+R+-+%5Cfrac%7B%5Ctau%5E%7B1%2F2%7D%7D%7B4%7D+R+-+%5Ctau%5E%7B3%2F2%7D+%5Chbox%7BRic%7D%28X%2CX%29%5C+d%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{2} - &#92;frac{1}{2} R + &#92;int_0^{1}  &#92;frac{&#92;tau^{3/2}}{2}  &#92;nabla_X R - &#92;frac{&#92;tau^{1/2}}{4} R - &#92;tau^{3/2} &#92;hbox{Ric}(X,X)&#92; d&#92;tau' title='&#92;displaystyle &#92;frac{d}{2} - &#92;frac{1}{2} R + &#92;int_0^{1}  &#92;frac{&#92;tau^{3/2}}{2}  &#92;nabla_X R - &#92;frac{&#92;tau^{1/2}}{4} R - &#92;tau^{3/2} &#92;hbox{Ric}(X,X)&#92; d&#92;tau' class='latex' />. (44)</p>
<p style="text-align:left;">To simplify this further, recall that the quantity G defined in (27) vanishes.  This (and the fact that g evolves by Ricci flow <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_%5Ctau+g+%3D+2+%5Chbox%7BRic%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_&#92;tau g = 2 &#92;hbox{Ric}' title='&#92;partial_&#92;tau g = 2 &#92;hbox{Ric}' class='latex' />) allows one to compute the variation of <img src='http://s0.wp.com/latex.php?latex=%5Ctau+%26%23124%3BX%26%23124%3B_g%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau &#124;X&#124;_g^2' title='&#92;tau &#124;X&#124;_g^2' class='latex' />:</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cpartial_%5Ctau+%28%5Ctau+%26%23124%3BX%26%23124%3B_g%5E2%29+%3D+%5Ctau+%5Cpartial_X+R+-+2+%5Ctau+%5Chbox%7BRic%7D%28X%2CX%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_&#92;tau (&#92;tau &#124;X&#124;_g^2) = &#92;tau &#92;partial_X R - 2 &#92;tau &#92;hbox{Ric}(X,X)' title='&#92;partial_&#92;tau (&#92;tau &#124;X&#124;_g^2) = &#92;tau &#92;partial_X R - 2 &#92;tau &#92;hbox{Ric}(X,X)' class='latex' />. (45)</p>
<p style="text-align:left;">Inserting this into (44) and integrating by parts, one can rewrite (44) as</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7B2%7D+-+%5Cfrac%7B1%7D%7B2%7D+R+%2B+%5Cfrac%7B1%7D%7B2%7D+%26%23124%3BX%26%23124%3B_g%5E2+-+%5Cfrac%7B1%7D%7B4%7D+%5Cint_0%5E1+%5Csqrt%7B%5Ctau%7D+%28R+%2B+%26%23124%3BX%26%23124%3B%5E2%29%5C+d%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{2} - &#92;frac{1}{2} R + &#92;frac{1}{2} &#124;X&#124;_g^2 - &#92;frac{1}{4} &#92;int_0^1 &#92;sqrt{&#92;tau} (R + &#124;X&#124;^2)&#92; d&#92;tau' title='&#92;displaystyle &#92;frac{d}{2} - &#92;frac{1}{2} R + &#92;frac{1}{2} &#124;X&#124;_g^2 - &#92;frac{1}{4} &#92;int_0^1 &#92;sqrt{&#92;tau} (R + &#124;X&#124;^2)&#92; d&#92;tau' class='latex' /> (46)</p>
<p style="text-align:left;">and so by (3) we obtain the inequality</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5CDelta+l_%7B%280%2Cx_0%29%7D%28-1%2Cx_1%29+%5Cleq+%5Cfrac%7Bd%7D%7B2%7D+-+%5Cfrac%7B1%7D%7B2%7D+R+%2B+%5Cfrac%7B1%7D%7B2%7D+%26%23124%3BX%26%23124%3B_g%5E2+-+%5Cfrac%7B1%7D%7B2%7D+l_%7B%280%2Cx_0%29%7D%28-1%2Cx_1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Delta l_{(0,x_0)}(-1,x_1) &#92;leq &#92;frac{d}{2} - &#92;frac{1}{2} R + &#92;frac{1}{2} &#124;X&#124;_g^2 - &#92;frac{1}{2} l_{(0,x_0)}(-1,x_1)' title='&#92;Delta l_{(0,x_0)}(-1,x_1) &#92;leq &#92;frac{d}{2} - &#92;frac{1}{2} R + &#92;frac{1}{2} &#124;X&#124;_g^2 - &#92;frac{1}{2} l_{(0,x_0)}(-1,x_1)' class='latex' />. (47)</p>
<p style="text-align:left;">Combining (29), (33), and (47) we obtain (6) as desired.</p>
<p style="text-align:center;">&#8211; Analytical issues &#8211;</p>
<p style="text-align:left;">We now discuss in broad terms the analytical issues that one must address in order to make the above arguments rigorous.  We first review the classical elliptic theory (i.e. the theory of geodesics in a Riemannian manifold) before turning to Perelman&#8217;s parabolic theory of <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-geodesics in a flow of Riemannian metrics.</p>
<p style="text-align:left;">In a complete Riemannian manifold, a geodesic <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%3A+%5B0%2C1%5D+%5Cto+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma: [0,1] &#92;to M' title='&#92;gamma: [0,1] &#92;to M' class='latex' /> from a fixed point <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%280%29+%3D+x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma(0) = x_0' title='&#92;gamma(0) = x_0' class='latex' /> to some other point <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%281%29%3Dx_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma(1)=x_1' title='&#92;gamma(1)=x_1' class='latex' /> has a well-defined initial velocity vector <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%27%280%29+%3D+X%280%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma&#039;(0) = X(0)' title='&#92;gamma&#039;(0) = X(0)' class='latex' />, and conversely each initial velocity vector <img src='http://s0.wp.com/latex.php?latex=v+%3D+X%280%29%5Cin+T_%7Bx_0%7D+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='v = X(0)&#92;in T_{x_0} M' title='v = X(0)&#92;in T_{x_0} M' class='latex' /> determines a unique geodesic with an endpoint <img src='http://s0.wp.com/latex.php?latex=x_1+%3D+%5Cexp_%7Bx_0%7D%28v%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_1 = &#92;exp_{x_0}(v)' title='x_1 = &#92;exp_{x_0}(v)' class='latex' />, thus defining the <a href="http://en.wikipedia.org/wiki/Exponential_map">exponential map </a>based at <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' />.  One can show (from standard ODE theory) that this exponential map is smooth (with the derivative of this map controlled by <a href="http://en.wikipedia.org/wiki/Jacobi_field">Jacobi fields</a>).  Also, if M is connected, then any two points can be joined by a geodesic, and the exponential map is onto.  However, there can be vectors v for which this map degenerates (i.e. its derivative ceases to be invertible) &#8211; these correspond to the <a href="http://en.wikipedia.org/wiki/Conjugate_point">conjugate points</a> of <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' /> in M.</p>
<p style="text-align:left;">Define the <em>injectivity region</em> of <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' /> to be the set of all <img src='http://s0.wp.com/latex.php?latex=x_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_1' title='x_1' class='latex' /> for which there is a unique minimising geodesic from <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=x_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_1' title='x_1' class='latex' />, and that the exponential map is not degenerate along this geodesic (in particular, <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=x_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_1' title='x_1' class='latex' /> are not conjugate points).  An analysis of Jacobi fields reveals that the injectivity region is open, that the distance function is smooth in this region (except at the origin), and that all the computations given above for the distance function can be justified.  So it remains to understand what happens on the complement of the injectivity region, known as the <a href="http://en.wikipedia.org/wiki/Cut_locus">cut locus</a>.  Points on the cut locus are either conjugate points to <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' />, or are else places where minimising geodesics are not unique, which (by a variant of the Gauss lemma) forces the distance function to be non-differentiable at these points.  The former type of points form a set of measure zero, thanks to <a href="http://en.wikipedia.org/wiki/Sard%27s_theorem">Sard&#8217;s theorem</a>, whereas the latter set of points also form a set of measure zero, thanks to <a href="http://en.wikipedia.org/wiki/Rademacher's_theorem">Radamacher&#8217;s differentiation theorem</a> and the Lipschitz nature of the distance function (i.e. the <a href="http://en.wikipedia.org/wiki/Triangle_inequality">triangle inequality</a>).  Thus the injectivity region has full measure.  While this does mean that pointwise inequalities such as (2) now hold almost everywhere, this is unfortunately not quite enough to ensure that (2) holds in the sense of distributions, which is what one really needs in order to fully justify results such as the Bishop-Gromov inequality.  (Indeed, by considering simple examples such as the unit circle, we see that the distribution <img src='http://s0.wp.com/latex.php?latex=%5CDelta+r&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Delta r' title='&#92;Delta r' class='latex' /> can in fact contain some negative singular measures, although one should note that this does not actually contradict (2) due to the favourable sign of these singular components.)  Fortunately, one can address this technical issue by constructing barrier functions to the radius function r at every point <img src='http://s0.wp.com/latex.php?latex=x_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_1' title='x_1' class='latex' />, i.e. <img src='http://s0.wp.com/latex.php?latex=C%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C^2' title='C^2' class='latex' /> functions <img src='http://s0.wp.com/latex.php?latex=u%3Du_%7B%5Cvarepsilon%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u=u_{&#92;varepsilon}' title='u=u_{&#92;varepsilon}' class='latex' /> for each <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon &gt; 0' title='&#92;varepsilon &gt; 0' class='latex' /> which upper bound r near <img src='http://s0.wp.com/latex.php?latex=x_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_1' title='x_1' class='latex' /> (and match r exactly at <img src='http://s0.wp.com/latex.php?latex=x_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_1' title='x_1' class='latex' />, and which obeys the inequality (2) at <img src='http://s0.wp.com/latex.php?latex=x_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_1' title='x_1' class='latex' /> up to a loss of <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon' title='&#92;varepsilon' class='latex' />.  Such functions can be constructed at any <img src='http://s0.wp.com/latex.php?latex=x_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_1' title='x_1' class='latex' />, even those in the cut locus, by perturbing the origin <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' /> by an epsilon, and then one can use these barrier functions to justify (2) in the sense of distributions.  (I believe that these arguments to control the distance function outside of the injectivity region originate with <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=92069">a paper of Calabi</a>.)  From this one can rigorously justify the Bishop-Gromov inequality for all radii, even those exceeding the radius of injectivity.</p>
<p style="text-align:left;">Analogues of the above assertions hold for the monotonicity of Perelman reduced volume on flows on compact Ricci flows (and more generally for Ricci flows of complete manifolds of bounded curvature).  For instance, one can show (using compactness arguments in various weighted Sobolev spaces) that, as long as the manifold M is connected, a minimiser to (3) always exists, and is attained by an <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-geodesic (defined as a curve <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%3A+%5B0%2C%5Ctau_1%5D+%5Cto+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma: [0,&#92;tau_1] &#92;to M' title='&#92;gamma: [0,&#92;tau_1] &#92;to M' class='latex' /> for which the G quantity defined in (27) vanishes).  [One can easily reduce to the connected case, since the reduced length is clearly infinite when <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=x_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_1' title='x_1' class='latex' /> lie on distinct connected components.] Such geodesics turn out to have a well-defined &#8220;initial velocity&#8221; <img src='http://s0.wp.com/latex.php?latex=v+%3A%3D+%5Clim_%7B%5Ctau+%5Cto+0%7D+%5Csqrt%7B%5Ctau%7D+X%28%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='v := &#92;lim_{&#92;tau &#92;to 0} &#92;sqrt{&#92;tau} X(&#92;tau)' title='v := &#92;lim_{&#92;tau &#92;to 0} &#92;sqrt{&#92;tau} X(&#92;tau)' class='latex' />, as can be seen by working out the ODE for the quantity <img src='http://s0.wp.com/latex.php?latex=%5Csqrt%7B%5Ctau%7D+X%28%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;sqrt{&#92;tau} X(&#92;tau)' title='&#92;sqrt{&#92;tau} X(&#92;tau)' class='latex' /> (it is also convenient to reparameterise in terms of the variable <img src='http://s0.wp.com/latex.php?latex=r+%3A%3D+%5Csqrt%7B%5Ctau%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r := &#92;sqrt{&#92;tau}' title='r := &#92;sqrt{&#92;tau}' class='latex' /> to remove any apparent singularity at <img src='http://s0.wp.com/latex.php?latex=%5Ctau%3D0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau=0' title='&#92;tau=0' class='latex' />).  This leads to an <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-exponential map <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D%5Cexp_%7B%280%2Cx_0%29%2C%5Ctau_1%7D%3A+T_%7Bx_0%7D+M+%5Cto+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}&#92;exp_{(0,x_0),&#92;tau_1}: T_{x_0} M &#92;to M' title='{&#92;mathcal L}&#92;exp_{(0,x_0),&#92;tau_1}: T_{x_0} M &#92;to M' class='latex' /> for any fixed time <img src='http://s0.wp.com/latex.php?latex=-%5Ctau_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='-&#92;tau_1' title='-&#92;tau_1' class='latex' />, which is smooth.  The derivative of this map is controlled by <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-Jacobi fields, which are close analogues of their elliptic counterparts, and which lead to the notion of a <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-conjugate point <img src='http://s0.wp.com/latex.php?latex=x_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_1' title='x_1' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=%280%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(0,x_0)' title='(0,x_0)' class='latex' /> at the fixed time <img src='http://s0.wp.com/latex.php?latex=-%5Ctau_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='-&#92;tau_1' title='-&#92;tau_1' class='latex' />.  One can then define the injectivity domain and cut locus as before (again for a fixed time <img src='http://s0.wp.com/latex.php?latex=-%5Ctau_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='-&#92;tau_1' title='-&#92;tau_1' class='latex' />), and show as before that the former region has full measure.  This lets one rigorously derive (6) almost everywhere (especially after noting that any segment of a minimising <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-geodesic without conjugate points is again a minimising <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-geodesic without conjugate points, thus establishing that the injectivity region is in some sense &#8220;star-shaped&#8221;), but again one needs to justify (6) in the sense of distributions in order to derive the monotonicity of Perelman reduced volume.  This can again be done by use of barrier functions, perturbing the base point <img src='http://s0.wp.com/latex.php?latex=%280%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(0,x_0)' title='(0,x_0)' class='latex' /> both spatially and also backwards in time by an epsilon.  The details of this become rather technical; see for instance the <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2342013">paper of Ye</a> or the <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0605667">notes of Kleiner-Lott</a>, for details.</p>
<p style="text-align:left;">Thus far we have only discussed how reduced length and reduced volume behave on smooth Ricci flows of compact manifolds.  Of course, to fully establish the global existence of Ricci flow with surgery, one also needs to build an analogous theory for Ricci flows with surgery.  Here there turns out to be significant new technical difficulties, basically because one has to restrict attention to paths <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' /> which avoid all regions in which surgery is taking place.  This creates some &#8220;holes&#8221; in the region of integration for the reduced volume, as in some cases the minimising path between two points in spacetime goes through a surgery region.  Fortunately it turns out that (very roughly speaking) these holes only occur when the reduced length (or a somewhat technical modification thereof) is rather large, which means that the holes do not significantly impact lower bounds on this reduced volume, which is what is needed to establish <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsing.  If time permits, I will discuss this issue further in later lectures, once we have described surgery in more detail.</p>
<p style="text-align:left;">In order to control ancient <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsing solutions, which are complete but not necessarily compact, one also needs to extend the above theory to complete non-compact manifolds.  It turns out that this can be done as long as one has uniform bounds on curvature; a key task here is to establish that the reduced length <img src='http://s0.wp.com/latex.php?latex=l_%7B%280%2Cx_0%29%7D%28-%5Ctau_1%2Cx_1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_{(0,x_0)}(-&#92;tau_1,x_1)' title='l_{(0,x_0)}(-&#92;tau_1,x_1)' class='latex' /> behaves roughly like <img src='http://s0.wp.com/latex.php?latex=d%28x_0%2Cx_1%29%5E2%2F4%5Ctau_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d(x_0,x_1)^2/4&#92;tau_1' title='d(x_0,x_1)^2/4&#92;tau_1' class='latex' /> (which is basically what it is in the Euclidean case) as <img src='http://s0.wp.com/latex.php?latex=x_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_1' title='x_1' class='latex' /> goes to infinity, which allows the integrand in the definition of reduced volume to have enough decay to justify all computations.  The technical details here can be found in several places, including the <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2342013">paper of Ye</a>, the <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0605667">notes of Kleiner-Lott</a>, the book of <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2334563">Morgan-Tian</a>, and the <a class="snap_noshots" href="http://arxiv.org/abs/math/0612069">paper of Cao-Zhu</a>.</p>
<p style="text-align:left;"><strong>Remark 1.</strong> A theory analogous to Perelman&#8217;s theory above was worked out earlier <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=834612">by Li and Yau</a>, but with the Ricci flow replaced by a static manifold with a lower bound on Ricci curvature, and with a time-dependent potential attached to the Laplacian. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
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<title><![CDATA[285G, Lecture 9: Comparison geometry, the high-dimensional limit, and Perelman reduced volume]]></title>
<link>http://terrytao.wordpress.com/2008/04/27/285g-lecture-9-comparison-geometry-the-high-dimensional-limit-and-perelman-reduced-volume/</link>
<pubDate>Mon, 28 Apr 2008 02:08:42 +0000</pubDate>
<dc:creator>Terence Tao</dc:creator>
<guid>http://terrytao.wordpress.com/2008/04/27/285g-lecture-9-comparison-geometry-the-high-dimensional-limit-and-perelman-reduced-volume/</guid>
<description><![CDATA[We now turn to Perelman&#8217;s second scale-invariant monotone quantity for Ricci flow, now known a]]></description>
<content:encoded><![CDATA[<p>We now turn to Perelman&#8217;s second scale-invariant monotone quantity for Ricci flow, now known as the <em>Perelman reduced volume</em>.  We saw in the previous lecture that the monotonicity for Perelman entropy was ultimately derived (after some twists and turns) from the monotonicity of a potential under gradient flow.  In this lecture, we will show (at a heuristic level only) how the monotonicity of Perelman&#8217;s reduced volume can also be &#8220;derived&#8221;, in a formal sense, from another source of monotonicity, namely the relative <a href="http://en.wikipedia.org/wiki/Bishop-Gromov_inequality">Bishop-Gromov inequality</a> in comparison geometry (which has already been alluded to in previous lectures).  Interestingly, in order to obtain this connection, one must first reinterpret parabolic flows such as Ricci flow as the limit of a certain high-dimensional Riemannian manifold as the dimension becomes infinite; this is part of a more general philosophy that parabolic theory is in some sense an infinite-dimensional limit of elliptic theory.  Our treatment here is a (liberally reinterpreted) version of Section 6 of <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0211159">Perelman&#8217;s paper</a>.</p>
<p>In the next few lectures we shall give a rigorous proof of this monotonicity, without using the infinite-dimensional limit and instead using results related to the Li-Yau-Hamilton Harnack inequality.  (There are several other approaches to understanding Perelman&#8217;s reduced volume, such as <a class="snap_noshots" href="http://arxiv.org/abs/0804.0343">Lott&#8217;s formulation</a> based on optimal transport, but we will restrict attention in this course to the methods that are in <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0211159">Perelman&#8217;s original paper</a>.)</p>
<p><!--more--></p>
<p style="text-align:center;">&#8211; The Bishop-Gromov inequality &#8211;</p>
<p>Let p be a point in a complete d-dimensional Riemannian manifold <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g)' title='(M,g)' class='latex' />.  As noted in <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/20/285g-lecture-7-rescaling-of-ricci-flows-and-kappa-noncollapsing/">Lecture 7</a>, we can use the exponential map to pull back M and g to the tangent space <img src='http://s0.wp.com/latex.php?latex=T_p+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='T_p M' title='T_p M' class='latex' />, which is also equipped with the radial variable r and the radial vector field <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_r+%3D+%5Chbox%7Bgrad%7D%28r%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_r = &#92;hbox{grad}(r)' title='&#92;partial_r = &#92;hbox{grad}(r)' class='latex' />.  From Exercise 7 of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/20/285g-lecture-7-rescaling-of-ricci-flows-and-kappa-noncollapsing/">Lecture 7</a>, we have the transport equation</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D_%7B%5Cpartial_r%7D+d%5Cmu+%3D+%28%5CDelta+r%29%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}_{&#92;partial_r} d&#92;mu = (&#92;Delta r)&#92; d&#92;mu' title='{&#92;mathcal L}_{&#92;partial_r} d&#92;mu = (&#92;Delta r)&#92; d&#92;mu' class='latex' /> (1)</p>
<p>for the volume measure <img src='http://s0.wp.com/latex.php?latex=d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d&#92;mu' title='d&#92;mu' class='latex' />, and a transport inequality</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cnabla_%7B%5Cpartial_r%7D+%5CDelta+r+%2B+%5Cfrac%7B1%7D%7Bd-1%7D+%28%5CDelta+r%29%5E2+%5Cleq+%5Cnabla_%7B%5Cpartial_r%7D+%5CDelta+r+%2B+%26%23124%3B%5Chbox%7BHess%7D%28r%29%26%23124%3B%5E2+%3D+-+%5Chbox%7BRic%7D%28%5Cpartial_r%2C+%5Cpartial_r%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;nabla_{&#92;partial_r} &#92;Delta r + &#92;frac{1}{d-1} (&#92;Delta r)^2 &#92;leq &#92;nabla_{&#92;partial_r} &#92;Delta r + &#124;&#92;hbox{Hess}(r)&#124;^2 = - &#92;hbox{Ric}(&#92;partial_r, &#92;partial_r)' title='&#92;displaystyle &#92;nabla_{&#92;partial_r} &#92;Delta r + &#92;frac{1}{d-1} (&#92;Delta r)^2 &#92;leq &#92;nabla_{&#92;partial_r} &#92;Delta r + &#124;&#92;hbox{Hess}(r)&#124;^2 = - &#92;hbox{Ric}(&#92;partial_r, &#92;partial_r)' class='latex' /> (2)</p>
<p>for the Laplcian <img src='http://s0.wp.com/latex.php?latex=%5CDelta+r&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Delta r' title='&#92;Delta r' class='latex' /> which appears in (1).  In particular, if we assume the lower bound</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRic%7D+%5Cgeq+%28d-1%29+K+g&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Ric} &#92;geq (d-1) K g' title='&#92;hbox{Ric} &#92;geq (d-1) K g' class='latex' /> (3)</p>
<p>for Ricci curvature in a ball <img src='http://s0.wp.com/latex.php?latex=B%28p%2Cr_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B(p,r_0)' title='B(p,r_0)' class='latex' /> for some real number <img src='http://s0.wp.com/latex.php?latex=K&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='K' title='K' class='latex' />, then from the Gauss lemma (Lemma 1 of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/20/285g-lecture-7-rescaling-of-ricci-flows-and-kappa-noncollapsing/">Lecture 7</a>) we have</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cnabla_%7B%5Cpartial_r%7D+%5CDelta+r+%2B+%5Cfrac%7B1%7D%7Bd-1%7D+%28%5CDelta+r%29%5E2+%5Cleq+-%28d-1%29+K&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;nabla_{&#92;partial_r} &#92;Delta r + &#92;frac{1}{d-1} (&#92;Delta r)^2 &#92;leq -(d-1) K' title='&#92;displaystyle &#92;nabla_{&#92;partial_r} &#92;Delta r + &#92;frac{1}{d-1} (&#92;Delta r)^2 &#92;leq -(d-1) K' class='latex' />. (4)</p>
<p>Also, from an expansion around the origin (see e.g. (13) or (15) from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/20/285g-lecture-7-rescaling-of-ricci-flows-and-kappa-noncollapsing/">Lecture 7</a>) we have</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5CDelta+r+%3D+%5Cfrac%7Bd-1%7D%7Br%7D+%2B+O%28r%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;Delta r = &#92;frac{d-1}{r} + O(r)' title='&#92;displaystyle &#92;Delta r = &#92;frac{d-1}{r} + O(r)' class='latex' /> (5)</p>
<p>for small r.  In principle, (4) and (5) lead to upper bounds on <img src='http://s0.wp.com/latex.php?latex=%5CDelta+r&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Delta r' title='&#92;Delta r' class='latex' />, which when combined with (1) lead to upper bounds on <img src='http://s0.wp.com/latex.php?latex=d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d&#92;mu' title='d&#92;mu' class='latex' />, which in turn lead to upper bounds on <img src='http://s0.wp.com/latex.php?latex=B%28p%2Cr_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B(p,r_0)' title='B(p,r_0)' class='latex' />.  One can of course just go ahead and compute these bounds, but one computation-free way to proceed is to introduce the model geometry <img src='http://s0.wp.com/latex.php?latex=%28M_K%2C+g_K%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M_K, g_K)' title='(M_K, g_K)' class='latex' />, defined as</p>
<ol>
<li>the standard round sphere <img src='http://s0.wp.com/latex.php?latex=%5Csqrt%7BK%7D+%5Ccdot+S%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;sqrt{K} &#92;cdot S^d' title='&#92;sqrt{K} &#92;cdot S^d' class='latex' /> of radius <img src='http://s0.wp.com/latex.php?latex=%5Csqrt%7BK%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;sqrt{K}' title='&#92;sqrt{K}' class='latex' /> (and thus constant sectional curvature K) if <img src='http://s0.wp.com/latex.php?latex=K+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='K &gt; 0' title='K &gt; 0' class='latex' /> (Example 1 from Lecture 7);</li>
<li>the standard hyperbolic space <img src='http://s0.wp.com/latex.php?latex=%5Csqrt%7B-K%7D+%5Ccdot+H%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;sqrt{-K} &#92;cdot H^d' title='&#92;sqrt{-K} &#92;cdot H^d' class='latex' /> of constant sectional curvature K if <img src='http://s0.wp.com/latex.php?latex=K+%26%2360%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='K &lt; 0' title='K &lt; 0' class='latex' /> (Example 2 from Lecture 7); or</li>
<li>the standard Euclidean space <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+R%7D%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb R}^d' title='{&#92;Bbb R}^d' class='latex' /> if K=0.</li>
</ol>
<p>As all of these spaces are <a href="http://en.wikipedia.org/wiki/Homogeneous_space">homogeneous</a> (in fact, they are <a href="http://en.wikipedia.org/wiki/Riemannian_symmetric_space">symmetric spaces</a>), the choice of origin p in this model geometry is irrelevant.  Observe that the orthogonal group <img src='http://s0.wp.com/latex.php?latex=O%28d%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='O(d)' title='O(d)' class='latex' /> acts isometrically on each of these spaces, with the orbits being the spheres centred at p.  This implies that at any point q not equal to p, <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BHess%7D%28r%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Hess}(r)' title='&#92;hbox{Hess}(r)' class='latex' /> is invariant under conjugation by the stabiliser of that group on q, which easily implies that it is diagonal on the tangent space to the sphere (i.e. to the orthogonal complement of <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_r&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_r' title='&#92;partial_r' class='latex' />).  From this we see that for this model geometry, the inequality in (2) is in fact an equality.  Since the model geometry also has constant sectional curvature K (which implies equality in (3)), we thus see that one has equality in (4) for this model geometry as well.  From this we can conclude:</p>
<blockquote><p><strong>Lemma 1. </strong> (Relative Bishop-Gromov inequality)  With the assumptions as above, the volume ratio <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BVol%7D_%7BM%2Cg%7D%28B_%7BM%2Cg%7D%28p%2Cr%29%29+%2F+%5Chbox%7BVol%7D_%7BM_K%2Cg_K%7D%28B_%7BM_K%2Cg_K%7D%28p%2Cr%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Vol}_{M,g}(B_{M,g}(p,r)) / &#92;hbox{Vol}_{M_K,g_K}(B_{M_K,g_K}(p,r))' title='&#92;hbox{Vol}_{M,g}(B_{M,g}(p,r)) / &#92;hbox{Vol}_{M_K,g_K}(B_{M_K,g_K}(p,r))' class='latex' /> is a non-increasing function of r as <img src='http://s0.wp.com/latex.php?latex=0+%26%2360%3B+r+%26%2360%3B+r_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &lt; r &lt; r_0' title='0 &lt; r &lt; r_0' class='latex' />.</p></blockquote>
<p><strong>Exercise 1. </strong> Prove Lemma 1.  (Hints: One can avoid all issues with non-injectivity by working inside the <a href="http://en.wikipedia.org/wiki/Cut_locus_%28Riemannian_manifold%29">cut locus</a> of p, which determines a <a href="http://en.wikipedia.org/wiki/Star_domain">star-shaped</a> region in <img src='http://s0.wp.com/latex.php?latex=T_p+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='T_p M' title='T_p M' class='latex' />.  In the positive curvature case K &#62; 0, the model geometry <img src='http://s0.wp.com/latex.php?latex=M_K&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M_K' title='M_K' class='latex' /> has a finite radius of injectivity, but observe that we may without loss of generality reduce to the case when <img src='http://s0.wp.com/latex.php?latex=r_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_0' title='r_0' class='latex' /> is less than or equal to that radius (or one can invoke <a href="http://en.wikipedia.org/wiki/Myers_theorem">Myers&#8217; theorem</a>, see Exercise 2 below).  To prove the monotonicity of ratios of volumes of balls, it may be convenient to first achieve the analogous claim for ratios of volumes of spheres, and then use the Gauss lemma and the fundamental theorem of calculus to pass from spheres to balls.) <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p><strong>Exercise 2.</strong> Prove <a href="http://en.wikipedia.org/wiki/Myers_theorem">Myers&#8217; theorem</a>: if a Riemannian manifold obeys (3) everywhere for some <img src='http://s0.wp.com/latex.php?latex=K+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='K &gt; 0' title='K &gt; 0' class='latex' />, then the diameter of the manifold is at most <img src='http://s0.wp.com/latex.php?latex=%5Cpi%2F%5Csqrt%7BK%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;pi/&#92;sqrt{K}' title='&#92;pi/&#92;sqrt{K}' class='latex' />.  (Hint: in the model geometry, the sphere of radius r collapses to a point when r approaches <img src='http://s0.wp.com/latex.php?latex=%5Cpi%2F%5Csqrt%7BK%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;pi/&#92;sqrt{K}' title='&#92;pi/&#92;sqrt{K}' class='latex' />.) <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p><strong>Remark 1.</strong> This Lemma implies the volume comparison result <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7Bvol%7D%28B%28p%2Cr%29%29%2F%5Chbox%7Bvol%7D%28B%28p%2Cr%2F2%29%29+%3D+O%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{vol}(B(p,r))/&#92;hbox{vol}(B(p,r/2)) = O(1)' title='&#92;hbox{vol}(B(p,r))/&#92;hbox{vol}(B(p,r/2)) = O(1)' class='latex' /> whenever one has bounded normalised curvature, which was used in the <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/24/285a-lecture-8-ricci-flow-as-a-gradient-flow-log-sobolev-inequalities-and-perelman-entropy/">previous lecture</a>; indeed, thanks to the above inequality, it suffices to prove the claim for model geometries. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>Setting K=0, we obtain</p>
<blockquote><p><strong>Corollary 1.</strong> Let <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g)' title='(M,g)' class='latex' /> be a complete d-dimensional Riemannian manifold of non-negative Ricci curvature, and let p be a point in M.  Then <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BVol%7D%28B%28p%2Cr%29%29%2Fr%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Vol}(B(p,r))/r^d' title='&#92;hbox{Vol}(B(p,r))/r^d' class='latex' /> is a non-increasing function of r.</p></blockquote>
<p style="text-align:left;">Let us refer to the quantity <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BVol%7D%28B%28p%2Cr%29%29%2Fr%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Vol}(B(p,r))/r^d' title='&#92;hbox{Vol}(B(p,r))/r^d' class='latex' /> as the <em>Bishop-Gromov reduced volume</em> at the point p and the scale r; thus we see that this quantity is dimensionless (i.e. invariant under scaling of the manifold and of r), and non-increasing in r when one has non-negative Ricci curvature (and in particular, for Ricci-flat manifolds).</p>
<p style="text-align:left;"><strong>Exercise 3.</strong> Use the Bishop-Gromov inequality to state and prove a rigorous version of the following informal claim: if a Riemannian manifold is non-collapsed at a point p at one scale <img src='http://s0.wp.com/latex.php?latex=r_0+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_0 &gt; 0' title='r_0 &gt; 0' class='latex' /> (as defined in <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/20/285g-lecture-7-rescaling-of-ricci-flows-and-kappa-noncollapsing/">Lecture 7</a>), then it is also non-collapsed at all larger scales <img src='http://s0.wp.com/latex.php?latex=r_1+%26%2362%3B+r_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_1 &gt; r_0' title='r_1 &gt; r_0' class='latex' />.  <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:center;">&#8211; Parabolic theory as infinite-dimensional elliptic theory &#8211;</p>
<p style="text-align:left;">We now come to an interesting (but still mostly heuristic) correspondence principle between elliptic theory and parabolic theory, with the latter being viewed as an infinite-dimensional limit of the former, in a manner somewhat analogous to that of the <a href="http://en.wikipedia.org/wiki/Central_limit_theorem">central limit theorem</a> in probability.  To get some idea of what I mean by this correspondence, consider the following (extremely incomplete, non-rigorous, inaccurate, and imprecise) dictionary:</p>
<table border="1">
<tbody>
<tr>
<td valign="top">Elliptic</td>
<td valign="top">Parabolic</td>
</tr>
<tr>
<td valign="top">Riemannian manifold (M,g)</td>
<td valign="top">Riemannian flow <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /></td>
</tr>
<tr>
<td valign="top">Complete manifold</td>
<td valign="top">Ancient flow of complete manifolds</td>
</tr>
<tr>
<td valign="top">Spatial origin 0</td>
<td valign="top">Spacetime origin <img src='http://s0.wp.com/latex.php?latex=%280%2C0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(0,0)' title='(0,0)' class='latex' /></td>
</tr>
<tr>
<td valign="top">Elliptic scaling <img src='http://s0.wp.com/latex.php?latex=x+%5Cmapsto+%5Clambda+x&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x &#92;mapsto &#92;lambda x' title='x &#92;mapsto &#92;lambda x' class='latex' /></td>
<td valign="top">Parabolic scaling <img src='http://s0.wp.com/latex.php?latex=%28t%2Cx%29+%5Cmapsto+%28%5Clambda%5E2+t%2C+%5Clambda+x%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t,x) &#92;mapsto (&#92;lambda^2 t, &#92;lambda x)' title='(t,x) &#92;mapsto (&#92;lambda^2 t, &#92;lambda x)' class='latex' /></td>
</tr>
<tr>
<td valign="top">Laplace equation <img src='http://s0.wp.com/latex.php?latex=%5CDelta+u+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Delta u = 0' title='&#92;Delta u = 0' class='latex' /></td>
<td valign="top">Heat equation <img src='http://s0.wp.com/latex.php?latex=-%5Cpartial_t+u+%2B+%5CDelta+u+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='-&#92;partial_t u + &#92;Delta u = 0' title='-&#92;partial_t u + &#92;Delta u = 0' class='latex' /></td>
</tr>
<tr>
<td valign="top">Ricci flat manifold <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRic%7D+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Ric} = 0' title='&#92;hbox{Ric} = 0' class='latex' /></td>
<td valign="top">Ricci flow <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+g+%3D+-+2+%5Chbox%7BRic%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t g = - 2 &#92;hbox{Ric}' title='&#92;partial_t g = - 2 &#92;hbox{Ric}' class='latex' /></td>
</tr>
<tr>
<td valign="top">Mean value principle <img src='http://s0.wp.com/latex.php?latex=u%280%29+%3D+%5Cint_%7BS%5E%7Bd-1%7D%7D+u%28r%5Comega%29%5C+d%5Cmu%28%5Comega%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u(0) = &#92;int_{S^{d-1}} u(r&#92;omega)&#92; d&#92;mu(&#92;omega)' title='u(0) = &#92;int_{S^{d-1}} u(r&#92;omega)&#92; d&#92;mu(&#92;omega)' class='latex' /></td>
<td valign="top">Fundamental solution <img src='http://s0.wp.com/latex.php?latex=u%280%2C0%29+%3D+%5Cfrac%7B1%7D%7B%284%5Cpi%5Ctau%29%5E%7Bd%2F2%7D%7D+%5Cint_%7B%7B%5CBbb+R%7D%5Ed%7D+e%5E%7B-%26%23124%3Bx%26%23124%3B%5E2%2F4%5Ctau%7D+u%28-%5Ctau%2Cx%29%5C+dx&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u(0,0) = &#92;frac{1}{(4&#92;pi&#92;tau)^{d/2}} &#92;int_{{&#92;Bbb R}^d} e^{-&#124;x&#124;^2/4&#92;tau} u(-&#92;tau,x)&#92; dx' title='u(0,0) = &#92;frac{1}{(4&#92;pi&#92;tau)^{d/2}} &#92;int_{{&#92;Bbb R}^d} e^{-&#124;x&#124;^2/4&#92;tau} u(-&#92;tau,x)&#92; dx' class='latex' /></td>
</tr>
<tr>
<td valign="top">Normalised measure on the sphere <img src='http://s0.wp.com/latex.php?latex=r+%5Ccdot+S%5E%7Bd-1%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r &#92;cdot S^{d-1}' title='r &#92;cdot S^{d-1}' class='latex' /></td>
<td valign="top">Heat kernel <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B1%7D%7B%284%5Cpi%5Ctau%29%5E%7Bd%2F2%7D%7D+e%5E%7B-%26%23124%3Bx%26%23124%3B%5E2%2F4%5Ctau%7D%5C+dx&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{1}{(4&#92;pi&#92;tau)^{d/2}} e^{-&#124;x&#124;^2/4&#92;tau}&#92; dx' title='&#92;frac{1}{(4&#92;pi&#92;tau)^{d/2}} e^{-&#124;x&#124;^2/4&#92;tau}&#92; dx' class='latex' /></td>
</tr>
<tr>
<td valign="top">Maximum principle</td>
<td valign="top">Maximum principle</td>
</tr>
<tr>
<td valign="top">Ball of radius O(r) around spatial origin</td>
<td valign="top">Cylinder of radius O(r) and height <img src='http://s0.wp.com/latex.php?latex=O%28r%5E2%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='O(r^2)' title='O(r^2)' class='latex' /> extending backwards in time from spacetime origin</td>
</tr>
<tr>
<td valign="top">Radial variable r=&#124;x&#124;</td>
<td valign="top">&#124;x&#124; or <img src='http://s0.wp.com/latex.php?latex=%5Csqrt%7B-t%7D+%3D+%5Csqrt%7B%5Ctau%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;sqrt{-t} = &#92;sqrt{&#92;tau}' title='&#92;sqrt{-t} = &#92;sqrt{&#92;tau}' class='latex' /></td>
</tr>
<tr>
<td valign="top">Bishop-Gromov reduced volume</td>
<td valign="top">Perelman reduced volume</td>
</tr>
</tbody>
</table>
<p><strong>Remark 2. </strong>Of course, we have not defined Perelman reduced volume yet, but the point is that the monotonicity of Perelman reduced volume for Ricci flow is supposed to be the parabolic analogue of the monotonicity of Bishop-Gromov reduced volume for Ricci-flat manifolds.  Note that one has two competing notions of the parabolic radial variable, &#124;x&#124; and <img src='http://s0.wp.com/latex.php?latex=%5Csqrt%7B%5Ctau%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;sqrt{&#92;tau}' title='&#92;sqrt{&#92;tau}' class='latex' />, where <img src='http://s0.wp.com/latex.php?latex=%5Ctau+%3A%3D+-t&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau := -t' title='&#92;tau := -t' class='latex' /> is the backwards time variable; the ratio between these two competitors is essentially the <em>Perelman reduced length</em>, which does not really have a good analogue in the elliptic theory (except perhaps in the &#8220;latitude&#8221; variable one gets when decomposing a sphere into cylindrical coordinates). <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>It is well known that elliptic theory can be viewed as the static (i.e. steady state) special case of parabolic theory, but here we want to discuss a rather different connection between the two theories that goes in the opposite direction, in which we view parabolic theory as a limiting case of elliptic theory as the dimension d goes to infinity.</p>
<p>To motivate how this works, let us begin with a smooth ancient solution <img src='http://s0.wp.com/latex.php?latex=u%3A+%28-%5Cinfty%2C0%5D+%5Ctimes+%7B%5CBbb+R%7D%5Ed+%5Cto+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u: (-&#92;infty,0] &#92;times {&#92;Bbb R}^d &#92;to {&#92;Bbb R}' title='u: (-&#92;infty,0] &#92;times {&#92;Bbb R}^d &#92;to {&#92;Bbb R}' class='latex' /> to the Euclidean heat equation</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=-%5Cpartial_t+u+%2B+%5CDelta_x+u+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='-&#92;partial_t u + &#92;Delta_x u = 0' title='-&#92;partial_t u + &#92;Delta_x u = 0' class='latex' /> (6)</p>
<p>and ask how to convert it to a high-dimensional solution to the Laplace equation.  At first glance this looks unreasonable: the Laplacian only contains second order derivative terms, but we have to somehow generate the first-order derivative <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t' title='&#92;partial_t' class='latex' /> out of this.  The trick is to use polar coordinates.  Recall that if we parameterise a Euclidean variable <img src='http://s0.wp.com/latex.php?latex=y+%5Cin+%7B%5CBbb+R%7D%5EN&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y &#92;in {&#92;Bbb R}^N' title='y &#92;in {&#92;Bbb R}^N' class='latex' /> away from the origin as <img src='http://s0.wp.com/latex.php?latex=y+%3D+r+%5Comega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y = r &#92;omega' title='y = r &#92;omega' class='latex' /> for <img src='http://s0.wp.com/latex.php?latex=r+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r &gt; 0' title='r &gt; 0' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Comega+%5Cin+S%5E%7BN-1%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;omega &#92;in S^{N-1}' title='&#92;omega &#92;in S^{N-1}' class='latex' />, then the Laplacian <img src='http://s0.wp.com/latex.php?latex=%5CDelta_y+f&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Delta_y f' title='&#92;Delta_y f' class='latex' /> of a function <img src='http://s0.wp.com/latex.php?latex=f%3A+%7B%5CBbb+R%7D%5EN+%5Cto+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='f: {&#92;Bbb R}^N &#92;to {&#92;Bbb R}' title='f: {&#92;Bbb R}^N &#92;to {&#92;Bbb R}' class='latex' /> can be expressed by the classical formula</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5CDelta_y+f+%3D+%5Cpartial_%7Brr%7D+f+%2B+%5Cfrac%7BN-1%7D%7Br%7D+%5Cpartial_r+f+%2B+%5Cfrac%7B1%7D%7Br%5E2%7D+%5CDelta_%5Comega+f&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;Delta_y f = &#92;partial_{rr} f + &#92;frac{N-1}{r} &#92;partial_r f + &#92;frac{1}{r^2} &#92;Delta_&#92;omega f' title='&#92;displaystyle &#92;Delta_y f = &#92;partial_{rr} f + &#92;frac{N-1}{r} &#92;partial_r f + &#92;frac{1}{r^2} &#92;Delta_&#92;omega f' class='latex' /> (7)</p>
<p>where <img src='http://s0.wp.com/latex.php?latex=%5CDelta_%7B%5Comega%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Delta_{&#92;omega}' title='&#92;Delta_{&#92;omega}' class='latex' /> is the Laplace-Beltrami operator on the sphere.  In particular, if f is a radial or spherically symmetric function (so by abuse of notation we write <img src='http://s0.wp.com/latex.php?latex=f%28y%29+%3D+f%28r%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='f(y) = f(r)' title='f(y) = f(r)' class='latex' />), we have</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5CDelta_y+f+%3D+%5Cpartial_%7Brr%7D+f+%2B+%5Cfrac%7BN-1%7D%7Br%7D+%5Cpartial_r+f&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;Delta_y f = &#92;partial_{rr} f + &#92;frac{N-1}{r} &#92;partial_r f' title='&#92;displaystyle &#92;Delta_y f = &#92;partial_{rr} f + &#92;frac{N-1}{r} &#92;partial_r f' class='latex' />. (8)</p>
<p>Now if we look at the high-dimensional limit <img src='http://s0.wp.com/latex.php?latex=N+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='N &#92;to &#92;infty' title='N &#92;to &#92;infty' class='latex' /> (noting that f, being radial, is well defined in every dimension), we see that the first order term <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7BN-1%7D%7Br%7D+%5Cpartial_r+f&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{N-1}{r} &#92;partial_r f' title='&#92;frac{N-1}{r} &#92;partial_r f' class='latex' /> dominates, despite the fact that <img src='http://s0.wp.com/latex.php?latex=%5CDelta_y&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Delta_y' title='&#92;Delta_y' class='latex' /> is a second order operator.  To clarify this domination (and to bring into view the operator <img src='http://s0.wp.com/latex.php?latex=-%5Cpartial_t&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='-&#92;partial_t' title='-&#92;partial_t' class='latex' /> appearing in (6)), let us make the change of variables</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+t+%3D+-%5Ctau+%3D+-+%5Cfrac%7Br%5E2%7D%7B2N%7D+%3D+-%5Cfrac%7By_1%5E2+%2B+%5Cldots+%2B+y_N%5E2%7D%7B2N%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle t = -&#92;tau = - &#92;frac{r^2}{2N} = -&#92;frac{y_1^2 + &#92;ldots + y_N^2}{2N}' title='&#92;displaystyle t = -&#92;tau = - &#92;frac{r^2}{2N} = -&#92;frac{y_1^2 + &#92;ldots + y_N^2}{2N}' class='latex' /> (9)</p>
<p>(thus <img src='http://s0.wp.com/latex.php?latex=%5Ctau+%3D+-t&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau = -t' title='&#92;tau = -t' class='latex' /> is the average of the squared coordinates <img src='http://s0.wp.com/latex.php?latex=y_1%5E2%2C%5Cldots%2Cy_N%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y_1^2,&#92;ldots,y_N^2' title='y_1^2,&#92;ldots,y_N^2' class='latex' />).  A quick application of the chain rule then yields</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5CDelta_y+f+%3D+-%5Cfrac%7Bt%7D%7B2N%7D+%5Cpartial_%7Btt%7D+f++-+%5Cpartial_t+f&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;Delta_y f = -&#92;frac{t}{2N} &#92;partial_{tt} f  - &#92;partial_t f' title='&#92;displaystyle &#92;Delta_y f = -&#92;frac{t}{2N} &#92;partial_{tt} f  - &#92;partial_t f' class='latex' /> (10)</p>
<p>(one can also see this by writing <img src='http://s0.wp.com/latex.php?latex=f%28y%29+%3D+%5Ctilde+f%28t%29+%3D+%5Ctilde+f%28+-%28y_1%5E2%2B%5Cldots%2By_N%5E2%29%2F2N+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='f(y) = &#92;tilde f(t) = &#92;tilde f( -(y_1^2+&#92;ldots+y_N^2)/2N )' title='f(y) = &#92;tilde f(t) = &#92;tilde f( -(y_1^2+&#92;ldots+y_N^2)/2N )' class='latex' /> and applying the Laplacian operator <img src='http://s0.wp.com/latex.php?latex=%5CDelta_y&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Delta_y' title='&#92;Delta_y' class='latex' /> directly).  If we restrict attention to the region of <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+R%7D%5EN&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb R}^N' title='{&#92;Bbb R}^N' class='latex' /> where all the coordinates <img src='http://s0.wp.com/latex.php?latex=y_i&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y_i' title='y_i' class='latex' /> are O(1), so <img src='http://s0.wp.com/latex.php?latex=r%5E2+%3D+O%28N%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r^2 = O(N)' title='r^2 = O(N)' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Ctau+%3D+-t+%3D+O%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau = -t = O(1)' title='&#92;tau = -t = O(1)' class='latex' />, and fix <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+f&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde f' title='&#92;tilde f' class='latex' /> while letting N go off to infinity, we thus see that <img src='http://s0.wp.com/latex.php?latex=%5CDelta_y+f&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Delta_y f' title='&#92;Delta_y f' class='latex' /> converges to <img src='http://s0.wp.com/latex.php?latex=-+%5Cpartial_t+f&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='- &#92;partial_t f' title='- &#92;partial_t f' class='latex' /> (with errors that are <img src='http://s0.wp.com/latex.php?latex=O%281%2FN%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='O(1/N)' title='O(1/N)' class='latex' />).</p>
<p>Returning back to our ancient solution <img src='http://s0.wp.com/latex.php?latex=u%3A+%28-%5Cinfty%2C0%5D+%5Ctimes+%7B%5CBbb+R%7D%5Ed+%5Cto+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u: (-&#92;infty,0] &#92;times {&#92;Bbb R}^d &#92;to {&#92;Bbb R}' title='u: (-&#92;infty,0] &#92;times {&#92;Bbb R}^d &#92;to {&#92;Bbb R}' class='latex' /> to the heat equation (6), it is now clear how to express this solution as a high-dimensional nearly harmonic function: if we define the high-dimensional lift <img src='http://s0.wp.com/latex.php?latex=u%5E%7B%28N%29%7D%3A+%7B%5CBbb+R%7D%5EN+%5Ctimes+%7B%5CBbb+R%7D%5Ed+%5Cto+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u^{(N)}: {&#92;Bbb R}^N &#92;times {&#92;Bbb R}^d &#92;to {&#92;Bbb R}' title='u^{(N)}: {&#92;Bbb R}^N &#92;times {&#92;Bbb R}^d &#92;to {&#92;Bbb R}' class='latex' /> of u to the N+d-dimensional Euclidean space <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+R%7D%5EN+%5Ctimes+%7B%5CBbb+R%7D%5Ed+%3A%3D+%5C%7B+%28y%2Cx%29%3A+y+%5Cin+%7B%5CBbb+R%7D%5EN%2C+x+%5Cin+%7B%5CBbb+R%7D%5Ed+%5C%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb R}^N &#92;times {&#92;Bbb R}^d := &#92;{ (y,x): y &#92;in {&#92;Bbb R}^N, x &#92;in {&#92;Bbb R}^d &#92;}' title='{&#92;Bbb R}^N &#92;times {&#92;Bbb R}^d := &#92;{ (y,x): y &#92;in {&#92;Bbb R}^N, x &#92;in {&#92;Bbb R}^d &#92;}' class='latex' /> for some large N by using the change of variables (9), i.e.</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle++u%5E%7B%28N%29%7D%28y%2Cx%29+%3A%3D+u%28t%2Cx%29+%3D+u%28+-+%5Cfrac%7By_1%5E2%2B%5Cldots%2By_N%5E2%7D%7B2N%7D%2C+x+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle  u^{(N)}(y,x) := u(t,x) = u( - &#92;frac{y_1^2+&#92;ldots+y_N^2}{2N}, x )' title='&#92;displaystyle  u^{(N)}(y,x) := u(t,x) = u( - &#92;frac{y_1^2+&#92;ldots+y_N^2}{2N}, x )' class='latex' /> (11)</p>
<p>then we see from (10) and (6) that <img src='http://s0.wp.com/latex.php?latex=u%5E%7B%28N%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u^{(N)}' title='u^{(N)}' class='latex' /> is nearly harmonic as claimed; indeed we have</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5CDelta_%7By%2Cx%7D+u%5E%7B%28N%29%7D+%3D+%5Cfrac%7Br%5E2%7D%7B4N%5E2%7D+%5Cpartial_%7Btt%7D+u++-+%5Cpartial_t+u+%2B+%5CDelta_x+u+%3D+O%281%2FN%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Delta_{y,x} u^{(N)} = &#92;frac{r^2}{4N^2} &#92;partial_{tt} u  - &#92;partial_t u + &#92;Delta_x u = O(1/N)' title='&#92;Delta_{y,x} u^{(N)} = &#92;frac{r^2}{4N^2} &#92;partial_{tt} u  - &#92;partial_t u + &#92;Delta_x u = O(1/N)' class='latex' /> (12)</p>
<p>in the region <img src='http://s0.wp.com/latex.php?latex=y_i+%3D+O%281%29%2C+x+%3D+O%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y_i = O(1), x = O(1)' title='y_i = O(1), x = O(1)' class='latex' />, which implies as before that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=y_i+%3D+O%281%29%2C+x+%3D+O%281%29%2C+r%5E2+%3D+O%28N%29%2C+%5Ctau+%3D+-t+%3D+O%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y_i = O(1), x = O(1), r^2 = O(N), &#92;tau = -t = O(1)' title='y_i = O(1), x = O(1), r^2 = O(N), &#92;tau = -t = O(1)' class='latex' />. (13)</p>
<p><strong>Remark 3. </strong>Writing y in polar coordinates as <img src='http://s0.wp.com/latex.php?latex=y+%3D+r%5Comega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y = r&#92;omega' title='y = r&#92;omega' class='latex' />, the metric <img src='http://s0.wp.com/latex.php?latex=ds%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='ds^2' title='ds^2' class='latex' /> on <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+R%7D%5EN+%5Ctimes+%7B%5CBbb+R%7D%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb R}^N &#92;times {&#92;Bbb R}^d' title='{&#92;Bbb R}^N &#92;times {&#92;Bbb R}^d' class='latex' /> can be expressed as</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+ds%5E2+%3D+dr%5E2+%2B+r%5E2+d%5Comega%5E2+%2B+dx%5E2+%3D+%5Cfrac%7BN%7D%7B2%5Ctau%7D+d%5Ctau%5E2+%2B+%5Ctau+d%5Comega_%7B1%2F2N%7D%5E2+%2B+dx%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle ds^2 = dr^2 + r^2 d&#92;omega^2 + dx^2 = &#92;frac{N}{2&#92;tau} d&#92;tau^2 + &#92;tau d&#92;omega_{1/2N}^2 + dx^2' title='&#92;displaystyle ds^2 = dr^2 + r^2 d&#92;omega^2 + dx^2 = &#92;frac{N}{2&#92;tau} d&#92;tau^2 + &#92;tau d&#92;omega_{1/2N}^2 + dx^2' class='latex' /> (14)</p>
<p>where <img src='http://s0.wp.com/latex.php?latex=d%5Comega_%7B1%2F2N%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d&#92;omega_{1/2N}^2' title='d&#92;omega_{1/2N}^2' class='latex' /> is the metric on the sphere <img src='http://s0.wp.com/latex.php?latex=S%5EN&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='S^N' title='S^N' class='latex' /> of constant curvature <img src='http://s0.wp.com/latex.php?latex=1%2F2N&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='1/2N' title='1/2N' class='latex' />.  This expression is essentially the first equation in Section 6 of <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0211159">Perelman&#8217;s paper</a> in the Euclidean case.   Perelman works exclusively in polar coordinates, but I have found that the Cartesian coordinate approach can be more illuminating at times.  <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p><strong>Remark 4.</strong> The formula (9) seems closely related to <a href="http://en.wikipedia.org/wiki/It%C5%8D%27s_lemma">Itō&#8217;s formula</a> <img src='http://s0.wp.com/latex.php?latex=dt+%3D+%28dB%29%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='dt = (dB)^2' title='dt = (dB)^2' class='latex' /> from stochastic calculus, combined perhaps with the central limit theorem, though I was not able to make this connection absolutely precise.  Note that for reasons of duality, stochastic calculus tends to involve the backwards heat equation rather than the forwards heat equation (see e.g. the <a href="http://en.wikipedia.org/wiki/Black%E2%80%93Scholes">Black-Scholes formula</a>), which seems to explain why the minus sign in (9) is not present in Itō&#8217;s formula. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>To illustrate how this correspondence could be used, let us heuristically derive the classical formula</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+u%280%2C0%29+%3D+%5Cfrac%7B1%7D%7B%284%5Cpi%5Ctau%29%5E%7Bd%2F2%7D%7D+%5Cint_%7B%7B%5CBbb+R%7D%5Ed%7D+e%5E%7B-%26%23124%3Bx%26%23124%3B%5E2%2F4%5Ctau%7D+u%28-%5Ctau%2Cx%29%5C+dx&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle u(0,0) = &#92;frac{1}{(4&#92;pi&#92;tau)^{d/2}} &#92;int_{{&#92;Bbb R}^d} e^{-&#124;x&#124;^2/4&#92;tau} u(-&#92;tau,x)&#92; dx' title='&#92;displaystyle u(0,0) = &#92;frac{1}{(4&#92;pi&#92;tau)^{d/2}} &#92;int_{{&#92;Bbb R}^d} e^{-&#124;x&#124;^2/4&#92;tau} u(-&#92;tau,x)&#92; dx' class='latex' /> (15)</p>
<p>for solutions <img src='http://s0.wp.com/latex.php?latex=u%3A+%28-%5Cinfty%2C0%5D+%5Ctimes+%7B%5CBbb+R%7D%5Ed+%5Cto+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u: (-&#92;infty,0] &#92;times {&#92;Bbb R}^d &#92;to {&#92;Bbb R}' title='u: (-&#92;infty,0] &#92;times {&#92;Bbb R}^d &#92;to {&#92;Bbb R}' class='latex' /> to the heat equation (6) from the classical <a href="http://en.wikipedia.org/wiki/Harmonic_function#The_mean_value_property">mean value principle</a></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+u%5E%7B%28N%29%7D%280%2C0%29+%3D+%5Cfrac%7B1%7D%7B%5Chbox%7Bmes%7D%28r+%5Ccdot+S%5E%7BN%2Bd-1%7D%29%7D+%5Cint_%7BS%5E%7BN%2Bd-1%7D%7D+u%5E%7B%28N%29%7D%28r%5Comega%29%5C+d%5Comega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle u^{(N)}(0,0) = &#92;frac{1}{&#92;hbox{mes}(r &#92;cdot S^{N+d-1})} &#92;int_{S^{N+d-1}} u^{(N)}(r&#92;omega)&#92; d&#92;omega' title='&#92;displaystyle u^{(N)}(0,0) = &#92;frac{1}{&#92;hbox{mes}(r &#92;cdot S^{N+d-1})} &#92;int_{S^{N+d-1}} u^{(N)}(r&#92;omega)&#92; d&#92;omega' class='latex' /> (16)</p>
<p>for harmonic functions <img src='http://s0.wp.com/latex.php?latex=u%5E%7B%28N%29%7D%3A+%7B%5CBbb+R%7D%5EN+%5Ctimes+%7B%5CBbb+R%7D%5Ed+%5Cto+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u^{(N)}: {&#92;Bbb R}^N &#92;times {&#92;Bbb R}^d &#92;to {&#92;Bbb R}' title='u^{(N)}: {&#92;Bbb R}^N &#92;times {&#92;Bbb R}^d &#92;to {&#92;Bbb R}' class='latex' />.  Actually, it will be slightly simpler to use the mean value principle for balls rather than spheres,</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+u%5E%7B%28N%29%7D%280%2C0%29+%3D+%5Cfrac%7B1%7D%7B%5Chbox%7BVol%7D%28B%5E%7BN%2Bd%7D%280%2Cr_0%29%29%7D+%5Cint_%7B%26%23124%3By%26%23124%3B%5E2%2B%26%23124%3Bx%26%23124%3B%5E2+%5Cleq+r_0%5E2%7D+u%5E%7B%28N%29%7D%28y%2Cx%29%5C+dy+dx&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle u^{(N)}(0,0) = &#92;frac{1}{&#92;hbox{Vol}(B^{N+d}(0,r_0))} &#92;int_{&#124;y&#124;^2+&#124;x&#124;^2 &#92;leq r_0^2} u^{(N)}(y,x)&#92; dy dx' title='&#92;displaystyle u^{(N)}(0,0) = &#92;frac{1}{&#92;hbox{Vol}(B^{N+d}(0,r_0))} &#92;int_{&#124;y&#124;^2+&#124;x&#124;^2 &#92;leq r_0^2} u^{(N)}(y,x)&#92; dy dx' class='latex' />, (17)</p>
<p>though in high dimensions there is actually very little difference between balls and spheres (the bulk of the volume of a high-dimensional ball is concentrated near its boundary, which is a sphere).</p>
<p>Let <img src='http://s0.wp.com/latex.php?latex=u&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u' title='u' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=u%5E%7B%28N%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u^{(N)}' title='u^{(N)}' class='latex' /> be as in (6) and (11).  From (12) we see that <img src='http://s0.wp.com/latex.php?latex=u%5E%7B%28N%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u^{(N)}' title='u^{(N)}' class='latex' /> is almost harmonic; let us be non-rigorous and pretend that <img src='http://s0.wp.com/latex.php?latex=u%5E%7B%28N%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u^{(N)}' title='u^{(N)}' class='latex' /> is close enough to harmonic that the formula (17) remains accurate for this function.  We write the volume of the ball <img src='http://s0.wp.com/latex.php?latex=B%5E%7BN%2Bd%7D%280%2Cr_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B^{N+d}(0,r_0)' title='B^{N+d}(0,r_0)' class='latex' /> as <img src='http://s0.wp.com/latex.php?latex=C_%7BN%2Cd%7D+r_0%5E%7BN%2Bd%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C_{N,d} r_0^{N+d}' title='C_{N,d} r_0^{N+d}' class='latex' /> for some constant <img src='http://s0.wp.com/latex.php?latex=C_%7BN%2Cd%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C_{N,d}' title='C_{N,d}' class='latex' />.  As for the integrand in (17), we use polar coordinates <img src='http://s0.wp.com/latex.php?latex=y+%3D+r+%5Comega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y = r &#92;omega' title='y = r &#92;omega' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=dy+%3D+r%5E%7BN-1%7D+dr+d%5Comega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='dy = r^{N-1} dr d&#92;omega' title='dy = r^{N-1} dr d&#92;omega' class='latex' /> and rewrite (17) as</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+c_%7BN%2Cd%7D+r_0%5E%7B-N-d%7D+%5Cint_%7B%7B%5CBbb+R%7D%5Ed%7D+%5Cint_%7B0+%5Cleq+r+%5Cleq+%5Csqrt%7Br_0%5E2-%26%23124%3Bx%26%23124%3B%5E2%7D%7D+u%28+-r%5E2%2F2N%2C+x+%29+r%5E%7BN-1%7D+dr+dx&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle c_{N,d} r_0^{-N-d} &#92;int_{{&#92;Bbb R}^d} &#92;int_{0 &#92;leq r &#92;leq &#92;sqrt{r_0^2-&#124;x&#124;^2}} u( -r^2/2N, x ) r^{N-1} dr dx' title='&#92;displaystyle c_{N,d} r_0^{-N-d} &#92;int_{{&#92;Bbb R}^d} &#92;int_{0 &#92;leq r &#92;leq &#92;sqrt{r_0^2-&#124;x&#124;^2}} u( -r^2/2N, x ) r^{N-1} dr dx' class='latex' /> (18)</p>
<p style="text-align:left;">for some other constant <img src='http://s0.wp.com/latex.php?latex=c_%7BN%2Cd%7D+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='c_{N,d} &gt; 0' title='c_{N,d} &gt; 0' class='latex' />.  In view of (9), it is natural to write <img src='http://s0.wp.com/latex.php?latex=r_0%5E2+%3D+2N+%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_0^2 = 2N &#92;tau' title='r_0^2 = 2N &#92;tau' class='latex' /> for some <img src='http://s0.wp.com/latex.php?latex=%5Ctau+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau &gt; 0' title='&#92;tau &gt; 0' class='latex' />, and in view of (13) it is natural to work in the regime in which <img src='http://s0.wp.com/latex.php?latex=x+%3D+O%281%29%2C+%5Ctau+%3D+O%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x = O(1), &#92;tau = O(1)' title='x = O(1), &#92;tau = O(1)' class='latex' />, and <img src='http://s0.wp.com/latex.php?latex=r_0%5E2+%3D+O%28N%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_0^2 = O(N)' title='r_0^2 = O(N)' class='latex' />.  Because <img src='http://s0.wp.com/latex.php?latex=r%5E%7BN-1%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r^{N-1}' title='r^{N-1}' class='latex' /> is so rapidly increasing when N is large, the bulk of the inner integral is concentrated at its endpoint (cf. our previous remark about high-dimensional balls concentrating near their boundary), and so we expect</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cint_%7B0+%5Cleq+r+%5Cleq+%5Csqrt%7Br_0%5E2-%26%23124%3Bx%26%23124%3B%5E2%7D%7D+u%28+-r%5E2%2F2N%2C+x+%29+r%5E%7BN-1%7D+dr+&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;int_{0 &#92;leq r &#92;leq &#92;sqrt{r_0^2-&#124;x&#124;^2}} u( -r^2/2N, x ) r^{N-1} dr ' title='&#92;displaystyle &#92;int_{0 &#92;leq r &#92;leq &#92;sqrt{r_0^2-&#124;x&#124;^2}} u( -r^2/2N, x ) r^{N-1} dr ' class='latex' /></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Capprox+%5Cfrac%7B1%7D%7BN%7D+%28%5Csqrt%7Br_0%5E2-%26%23124%3Bx%26%23124%3B%5E2%7D%29%5EN+u%28+-+%28r_0%5E2-%26%23124%3Bx%26%23124%3B%5E2%29%2F2N%2C+x+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;approx &#92;frac{1}{N} (&#92;sqrt{r_0^2-&#124;x&#124;^2})^N u( - (r_0^2-&#124;x&#124;^2)/2N, x )' title='&#92;displaystyle &#92;approx &#92;frac{1}{N} (&#92;sqrt{r_0^2-&#124;x&#124;^2})^N u( - (r_0^2-&#124;x&#124;^2)/2N, x )' class='latex' />. (19)</p>
<p style="text-align:left;">Since <img src='http://s0.wp.com/latex.php?latex=r_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_0' title='r_0' class='latex' /> is so much larger than &#124;x&#124; in our regime of interest, we can heuristically approximate <img src='http://s0.wp.com/latex.php?latex=u%28+-+%28r_0%5E2-%26%23124%3Bx%26%23124%3B%5E2%29%2F2N%2C+x%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u( - (r_0^2-&#124;x&#124;^2)/2N, x)' title='u( - (r_0^2-&#124;x&#124;^2)/2N, x)' class='latex' /> by <img src='http://s0.wp.com/latex.php?latex=u%28+-r_0%5E2%2F2N%2Cx%29+%3D+u%28-%5Ctau%2Cx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u( -r_0^2/2N,x) = u(-&#92;tau,x)' title='u( -r_0^2/2N,x) = u(-&#92;tau,x)' class='latex' />.  Also, by Taylor approximation we have</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%28%5Csqrt%7Br_0%5E2-%26%23124%3Bx%26%23124%3B%5E2%7D%29%5EN+%5Capprox+r_0%5E%7BN%2F2%7D+%5Cexp%28+-+%5Cfrac%7BN+%26%23124%3Bx%26%23124%3B%5E2%7D%7B2+r_0%5E2%7D+%29.&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle (&#92;sqrt{r_0^2-&#124;x&#124;^2})^N &#92;approx r_0^{N/2} &#92;exp( - &#92;frac{N &#124;x&#124;^2}{2 r_0^2} ).' title='&#92;displaystyle (&#92;sqrt{r_0^2-&#124;x&#124;^2})^N &#92;approx r_0^{N/2} &#92;exp( - &#92;frac{N &#124;x&#124;^2}{2 r_0^2} ).' class='latex' /> (20)</p>
<p style="text-align:left;">Putting all this together, and substituting <img src='http://s0.wp.com/latex.php?latex=r_0%5E2+%3D+2N%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_0^2 = 2N&#92;tau' title='r_0^2 = 2N&#92;tau' class='latex' />, we heuristically conclude</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+u%280%2C0%29+%5Capprox+%5Cfrac%7B%5Ctilde+c_%7BN%2Cd%7D%7D%7B%5Ctau%5E%7Bd%2F2%7D%7D+%5Cint_%7B%7B%5CBbb+R%7D%5Ed%7D+e%5E%7B-%26%23124%3Bx%26%23124%3B%5E2%2F4%5Ctau%7D+u%28-%5Ctau%2Cx%29%5C+dx&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle u(0,0) &#92;approx &#92;frac{&#92;tilde c_{N,d}}{&#92;tau^{d/2}} &#92;int_{{&#92;Bbb R}^d} e^{-&#124;x&#124;^2/4&#92;tau} u(-&#92;tau,x)&#92; dx' title='&#92;displaystyle u(0,0) &#92;approx &#92;frac{&#92;tilde c_{N,d}}{&#92;tau^{d/2}} &#92;int_{{&#92;Bbb R}^d} e^{-&#124;x&#124;^2/4&#92;tau} u(-&#92;tau,x)&#92; dx' class='latex' /> (21)</p>
<p style="text-align:left;">for some other constant <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+c_%7BN%2Cd%7D+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde c_{N,d} &gt; 0' title='&#92;tilde c_{N,d} &gt; 0' class='latex' />.  Taking limits as <img src='http://s0.wp.com/latex.php?latex=N+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='N &#92;to &#92;infty' title='N &#92;to &#92;infty' class='latex' /> we heuristically obtain (15) up to a constant.</p>
<p style="text-align:left;"><strong>Exercise 4. </strong>Work through the calculations more carefully (but still heuristically), using <a href="http://en.wikipedia.org/wiki/Stirling%27s_approximation">Stirling&#8217;s approximation</a> to the <a href="http://en.wikipedia.org/wiki/Gamma_function">Gamma function</a>, together with the <a href="http://en.wikipedia.org/wiki/Unit_sphere#General_area_and_volume_formulas">classical formulae for the volume of balls and spheres</a>, to verify that one does indeed get the right constant of <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B1%7D%7B%284%5Cpi%29%5E%7Bd%2F2%7D%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{1}{(4&#92;pi)^{d/2}}' title='&#92;frac{1}{(4&#92;pi)^{d/2}}' class='latex' /> in (15) at the end of the day (as one must). <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;">Now let us perform a variant of the above computations which is more closely related to the monotonicity of Perelman&#8217;s reduced volume.  The Euclidean space <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+R%7D%5EN+%5Ctimes+%7B%5CBbb+R%7D%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb R}^N &#92;times {&#92;Bbb R}^d' title='{&#92;Bbb R}^N &#92;times {&#92;Bbb R}^d' class='latex' /> is of course Ricci-flat, and so from Corollary 1 we know that the Bishop-Gromov reduced volume</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+r_0%5E%7B-N-d%7D+%5Cint_%7B%26%23124%3By%26%23124%3B%5E2%2B%26%23124%3Bx%26%23124%3B%5E2+%5Cleq+r_0%5E2%7D%5C+dy+dx&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle r_0^{-N-d} &#92;int_{&#124;y&#124;^2+&#124;x&#124;^2 &#92;leq r_0^2}&#92; dy dx' title='&#92;displaystyle r_0^{-N-d} &#92;int_{&#124;y&#124;^2+&#124;x&#124;^2 &#92;leq r_0^2}&#92; dy dx' class='latex' /> (22)</p>
<p style="text-align:left;">is non-decreasing in <img src='http://s0.wp.com/latex.php?latex=r_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_0' title='r_0' class='latex' /> (and thus non-decreasing in <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' />).  (Of course, being Euclidean, (22) is equal to a constant <img src='http://s0.wp.com/latex.php?latex=C_%7BN%2Cd%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C_{N,d}' title='C_{N,d}' class='latex' />; but let us ignore this fact (which we have already used in our heuristic derivation of (15)) for now.)  Repeating all the above computations (but with u and <img src='http://s0.wp.com/latex.php?latex=u%5E%7B%28N%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u^{(N)}' title='u^{(N)}' class='latex' /> replaced by 1) we thus heuristically conclude that the quantity</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7B1%7D%7B%5Ctau%5E%7Bd%2F2%7D%7D+%5Cint_%7B%7B%5CBbb+R%7D%5Ed%7D+e%5E%7B-%26%23124%3Bx%26%23124%3B%5E2%2F4%5Ctau%7D%5C+dx&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{1}{&#92;tau^{d/2}} &#92;int_{{&#92;Bbb R}^d} e^{-&#124;x&#124;^2/4&#92;tau}&#92; dx' title='&#92;displaystyle &#92;frac{1}{&#92;tau^{d/2}} &#92;int_{{&#92;Bbb R}^d} e^{-&#124;x&#124;^2/4&#92;tau}&#92; dx' class='latex' /> (23)</p>
<p style="text-align:left;">is also non-decreasing in <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' />.  (Indeed, this quantity is equal to <img src='http://s0.wp.com/latex.php?latex=%284%5Cpi%29%5E%7Bd%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(4&#92;pi)^{d/2}' title='(4&#92;pi)^{d/2}' class='latex' /> for all <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' />.)  The quantity (23) is precisely the <em>Perelman reduced volume</em> of Euclidean space <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+R%7D%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb R}^d' title='{&#92;Bbb R}^d' class='latex' /> (which we view as a trivial example of an ancient Ricci flow) at the spacetime origin (0,0) and backwards time parameter <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' />.</p>
<p style="text-align:center;">&#8211; From Ricci flow to Ricci flat manifolds &#8211;</p>
<p style="text-align:left;">We have seen how ancient solutions to the heat equation on a Euclidean spacetime can be viewed as (approximately) harmonic functions on an &#8220;infinitely high dimensional&#8221; Euclidean space.  Now we would like to analogously view ancient solutions to a heat equation on a flow <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> of Riemannian manifolds as harmonic functions on an &#8220;infinitely high dimensional&#8221; Riemannian manifold, and similarly to view ancient Ricci flows as infinite dimensional infinitely high dimensional Ricci-flat manifolds.</p>
<p style="text-align:left;">Let&#8217;s begin with the former task.  Starting with an ancient flow <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> of d-dimensional Riemannian metrics for <img src='http://s0.wp.com/latex.php?latex=t+%5Cin+%28-%5Cinfty%2C0%5D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;in (-&#92;infty,0]' title='t &#92;in (-&#92;infty,0]' class='latex' /> (which we will not assume to be a Ricci flow just yet) and a large integer N, we can consider the N+d-dimesional manifold <img src='http://s0.wp.com/latex.php?latex=M%5E%7B%28N%29%7D+%3A%3D+%7B%5CBbb+R%7D%5EN+%5Ctimes+M+%3D+%5C%7B+%28y%2Cx%29%3A+y+%5Cin+%7B%5CBbb+R%7D%5EN%2C+x+%5Cin+M+%5C%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M^{(N)} := {&#92;Bbb R}^N &#92;times M = &#92;{ (y,x): y &#92;in {&#92;Bbb R}^N, x &#92;in M &#92;}' title='M^{(N)} := {&#92;Bbb R}^N &#92;times M = &#92;{ (y,x): y &#92;in {&#92;Bbb R}^N, x &#92;in M &#92;}' class='latex' />.  As a first attempt to mimic the situation in the Euclidean case, it is natural to endow <img src='http://s0.wp.com/latex.php?latex=M%5E%7B%28N%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M^{(N)}' title='M^{(N)}' class='latex' /> with the Riemannian metric <img src='http://s0.wp.com/latex.php?latex=g%5E%7B%28N%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='g^{(N)}' title='g^{(N)}' class='latex' /> given by the formula</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%28dg%5E%7B%28N%29%7D%29%5E2+%3D+dy%5E2+%2B+dg%28t%29%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(dg^{(N)})^2 = dy^2 + dg(t)^2' title='(dg^{(N)})^2 = dy^2 + dg(t)^2' class='latex' /> (24)</p>
<p style="text-align:left;">where t is given by the formula (9).  In terms of local coordinates, if we use the indices a,b,c to denote the d indices for the x variable and i,j,k to denote the N indices for the y variable, we have</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=g%5E%7B%28N%29%7D_%7Bab%7D+%3D+g_%7Bab%7D%28t%29%3B+g%5E%7B%28N%29%7D_%7Bai%7D+%3D+g%5E%7B%28N%29%7D_%7Bia%7D+%3D+0%3B+g%5E%7B%28N%29%7D_%7Bij%7D+%3D+%5Cdelta_%7Bij%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='g^{(N)}_{ab} = g_{ab}(t); g^{(N)}_{ai} = g^{(N)}_{ia} = 0; g^{(N)}_{ij} = &#92;delta_{ij}' title='g^{(N)}_{ab} = g_{ab}(t); g^{(N)}_{ai} = g^{(N)}_{ia} = 0; g^{(N)}_{ij} = &#92;delta_{ij}' class='latex' /> (25)</p>
<p style="text-align:left;">where <img src='http://s0.wp.com/latex.php?latex=%5Cdelta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;delta' title='&#92;delta' class='latex' /> is the Kronecker delta.  From this we see that the volume measure <img src='http://s0.wp.com/latex.php?latex=d%5Cmu%5E%7B%28N%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d&#92;mu^{(N)}' title='d&#92;mu^{(N)}' class='latex' /> on <img src='http://s0.wp.com/latex.php?latex=M%5E%7B%28N%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M^{(N)}' title='M^{(N)}' class='latex' /> is given by</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=d%5Cmu%5E%7B%28N%29%7D+%3D+d%5Cmu%28t%29+dy&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d&#92;mu^{(N)} = d&#92;mu(t) dy' title='d&#92;mu^{(N)} = d&#92;mu(t) dy' class='latex' /> (26)</p>
<p style="text-align:left;">and the Dirichlet form</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=E%5E%7B%28N%29%7D%28u%2Cv%29+%3A%3D+%5Cint_%7BM%5E%7B%28N%29%7D%7D+g%5E%7B%28N%29%7D%28+%5Cnabla%5E%7B%28N%29%7D+u%2C+%5Cnabla%5E%7B%28N%29%7D+v+%29%5C+d%5Cmu%5E%7B%28N%29%7D+&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='E^{(N)}(u,v) := &#92;int_{M^{(N)}} g^{(N)}( &#92;nabla^{(N)} u, &#92;nabla^{(N)} v )&#92; d&#92;mu^{(N)} ' title='E^{(N)}(u,v) := &#92;int_{M^{(N)}} g^{(N)}( &#92;nabla^{(N)} u, &#92;nabla^{(N)} v )&#92; d&#92;mu^{(N)} ' class='latex' /></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%3D+-+%5Cint_%7BM%5E%7B%28N%29%7D%7D+%5CDelta%5E%7B%28N%29%7D+u+v%5C+d%5Cmu%5E%7B%28N%29%7D+&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='= - &#92;int_{M^{(N)}} &#92;Delta^{(N)} u v&#92; d&#92;mu^{(N)} ' title='= - &#92;int_{M^{(N)}} &#92;Delta^{(N)} u v&#92; d&#92;mu^{(N)} ' class='latex' /> (27)</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%3D+-+%5Cint_%7BM%5E%7B%28N%29%7D%7D+u+%5CDelta%5E%7B%28N%29%7D+v%5C+d%5Cmu%5E%7B%28N%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='= - &#92;int_{M^{(N)}} u &#92;Delta^{(N)} v&#92; d&#92;mu^{(N)}' title='= - &#92;int_{M^{(N)}} u &#92;Delta^{(N)} v&#92; d&#92;mu^{(N)}' class='latex' /></p>
<p style="text-align:left;">for this Riemannian manifold is given by</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+E%5E%7B%28N%29%7D%28u%2Cv%29+%3D+%5Cint_%7B%7B%5CBbb+R%7D%5EN%7D+%5Cint_%7BM%28t%29%7D+%5Cnabla_y+u+%5Ccdot+%5Cnabla_y+v+%2B+g%28t%29%28+%5Cnabla_%7Bx%2Cg%28t%29%7D+u%2C+%5Cnabla_%7Bx%2Cg%28t%29%7D+v%29%5C+d%5Cmu%28t%29+dy&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle E^{(N)}(u,v) = &#92;int_{{&#92;Bbb R}^N} &#92;int_{M(t)} &#92;nabla_y u &#92;cdot &#92;nabla_y v + g(t)( &#92;nabla_{x,g(t)} u, &#92;nabla_{x,g(t)} v)&#92; d&#92;mu(t) dy' title='&#92;displaystyle E^{(N)}(u,v) = &#92;int_{{&#92;Bbb R}^N} &#92;int_{M(t)} &#92;nabla_y u &#92;cdot &#92;nabla_y v + g(t)( &#92;nabla_{x,g(t)} u, &#92;nabla_{x,g(t)} v)&#92; d&#92;mu(t) dy' class='latex' />, (28)</p>
<p style="text-align:left;">where <img src='http://s0.wp.com/latex.php?latex=%5Cnabla_%7Bx%2Cg%28t%29%7D+u&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_{x,g(t)} u' title='&#92;nabla_{x,g(t)} u' class='latex' /> is the gradient of u in the x variable using the metric g(t).  We can then integrate by parts to compute the Laplacian <img src='http://s0.wp.com/latex.php?latex=%5CDelta%5E%7B%28N%29%7D+u&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Delta^{(N)} u' title='&#92;Delta^{(N)} u' class='latex' />.  Recalling that <img src='http://s0.wp.com/latex.php?latex=d%5Cmu%28t%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d&#92;mu(t)' title='d&#92;mu(t)' class='latex' /> varies in t by the formula</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bdt%7D+d%5Cmu%28t%29+%3D+%5Cfrac%7B1%7D%7B2%7D+%5Chbox%7Btr%7D%28%5Cdot+g%29+d%5Cmu%28t%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{dt} d&#92;mu(t) = &#92;frac{1}{2} &#92;hbox{tr}(&#92;dot g) d&#92;mu(t)' title='&#92;displaystyle &#92;frac{d}{dt} d&#92;mu(t) = &#92;frac{1}{2} &#92;hbox{tr}(&#92;dot g) d&#92;mu(t)' class='latex' /> (29)</p>
<p style="text-align:left;">(equation (19) from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/03/28/285g-lecture-1-ricci-flow/">Lecture 1</a>) and using (9) and the chain rule, we see that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5CDelta%5E%7B%28N%29%7D+u%5E%7B%28N%29%7D+%3D+%5CDelta_y+u%5E%7B%28N%29%7D+%2B+%5CDelta_%7Bx%2C+g%28t%29%7D+u%5E%7B%28N%29%7D+-+%5Cfrac%7Br%7D%7B2N%7D+%5Chbox%7Btr%7D%28%5Cdot+g%29+%5Cpartial_r+u%5E%7B%28N%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;Delta^{(N)} u^{(N)} = &#92;Delta_y u^{(N)} + &#92;Delta_{x, g(t)} u^{(N)} - &#92;frac{r}{2N} &#92;hbox{tr}(&#92;dot g) &#92;partial_r u^{(N)}' title='&#92;displaystyle &#92;Delta^{(N)} u^{(N)} = &#92;Delta_y u^{(N)} + &#92;Delta_{x, g(t)} u^{(N)} - &#92;frac{r}{2N} &#92;hbox{tr}(&#92;dot g) &#92;partial_r u^{(N)}' class='latex' /> (30)</p>
<p>where <img src='http://s0.wp.com/latex.php?latex=%5CDelta_%7Bx%2Cg%28t%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Delta_{x,g(t)}' title='&#92;Delta_{x,g(t)}' class='latex' /> is the Laplace-Beltrami operator in the x variable using the metric g(t).  If we specialise to radial functions</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=u%5E%7B%28N%29%7D%28y%2Cx%29+%3D+u%28t%2Cx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u^{(N)}(y,x) = u(t,x)' title='u^{(N)}(y,x) = u(t,x)' class='latex' /> (31)</p>
<p>and use (10) and the chain rule, we can rewrite (29) as</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+-%5Cfrac%7Bt%7D%7B2N%7D+%5Cpartial_%7Btt%7D+u+-+%5Cpartial_t+u+%2B+%5CDelta_%7Bx%2Cg%28t%29%7D+u+%2B+%5Cfrac%7Bt%7D%7BN%7D+%5Chbox%7Btr%7D%28%5Cdot+g%29++%5Cpartial_t+u&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle -&#92;frac{t}{2N} &#92;partial_{tt} u - &#92;partial_t u + &#92;Delta_{x,g(t)} u + &#92;frac{t}{N} &#92;hbox{tr}(&#92;dot g)  &#92;partial_t u' title='&#92;displaystyle -&#92;frac{t}{2N} &#92;partial_{tt} u - &#92;partial_t u + &#92;Delta_{x,g(t)} u + &#92;frac{t}{N} &#92;hbox{tr}(&#92;dot g)  &#92;partial_t u' class='latex' /> (32)</p>
<p>Thus we see that if u solves the heat equation <img src='http://s0.wp.com/latex.php?latex=u_t+%3D+%5CDelta_%7Bg%28t%29%7D+u&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u_t = &#92;Delta_{g(t)} u' title='u_t = &#92;Delta_{g(t)} u' class='latex' />, then its lift <img src='http://s0.wp.com/latex.php?latex=u%5E%7B%28N%29%7D%3A+M%5E%7B%28N%29%7D+%5Cto+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u^{(N)}: M^{(N)} &#92;to {&#92;Bbb R}' title='u^{(N)}: M^{(N)} &#92;to {&#92;Bbb R}' class='latex' /> is approximately harmonic in the sense that <img src='http://s0.wp.com/latex.php?latex=%5CDelta%5E%7B%28N%29%7D+u%5E%7B%28N%29%7D+%3D+O%281%2FN%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Delta^{(N)} u^{(N)} = O(1/N)' title='&#92;Delta^{(N)} u^{(N)} = O(1/N)' class='latex' /> in the region where <img src='http://s0.wp.com/latex.php?latex=-t+%3D+%5Ctau+%3D+O%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='-t = &#92;tau = O(1)' title='-t = &#92;tau = O(1)' class='latex' /> and x is confined to a compact region of space.</p>
<p><strong>Remark 5.</strong> The <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bt%7D%7BN%7D+%5Chbox%7Btr%7D%28%5Cdot+g%29++%5Cpartial_t+u&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{t}{N} &#92;hbox{tr}(&#92;dot g)  &#92;partial_t u' title='&#92;frac{t}{N} &#92;hbox{tr}(&#92;dot g)  &#92;partial_t u' class='latex' /> term in (32) is somewhat annoying; we will later tweak the metric (24) in order to remove it (at the cost of other, more acceptable, terms). <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>Now let us see whether Ricci flows <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2C+g%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M, g(t))' title='t &#92;mapsto (M, g(t))' class='latex' /> lift to approximately Ricci-flat manifolds <img src='http://s0.wp.com/latex.php?latex=M%5E%7B%28N%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M^{(N)}' title='M^{(N)}' class='latex' />.  We begin by computing the <a href="http://en.wikipedia.org/wiki/Christoffel_symbol">Christoffel symbols</a> <img src='http://s0.wp.com/latex.php?latex=%28%5CGamma%5E%7B%28N%29%7D%29%5E%7B%5Cgamma%7D_%7B%5Calpha+%5Cbeta%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;Gamma^{(N)})^{&#92;gamma}_{&#92;alpha &#92;beta}' title='(&#92;Gamma^{(N)})^{&#92;gamma}_{&#92;alpha &#92;beta}' class='latex' /> in local coordinates, where <img src='http://s0.wp.com/latex.php?latex=%5Calpha%2C%5Cbeta%2C%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;alpha,&#92;beta,&#92;gamma' title='&#92;alpha,&#92;beta,&#92;gamma' class='latex' /> refer to the N+d combined indices coming from the indices a on M and the indices i on <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+R%7D%5EN&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb R}^N' title='{&#92;Bbb R}^N' class='latex' />.  We recall the standard formula</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5CGamma%5E%7B%5Cgamma%7D_%7B%5Calpha+%5Cbeta%7D+%3D+%5Cfrac%7B1%7D%7B2%7D+g%5E%7B%5Cgamma+%5Cdelta%7D+%28+%5Cpartial_%5Calpha+g_%7B%5Cbeta+%5Cdelta%7D+%2B+%5Cpartial_%5Cbeta+g_%7B%5Calpha+%5Cdelta%7D+-+%5Cpartial_%5Cdelta+g_%7B%5Calpha+%5Cbeta%7D+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;Gamma^{&#92;gamma}_{&#92;alpha &#92;beta} = &#92;frac{1}{2} g^{&#92;gamma &#92;delta} ( &#92;partial_&#92;alpha g_{&#92;beta &#92;delta} + &#92;partial_&#92;beta g_{&#92;alpha &#92;delta} - &#92;partial_&#92;delta g_{&#92;alpha &#92;beta} )' title='&#92;displaystyle &#92;Gamma^{&#92;gamma}_{&#92;alpha &#92;beta} = &#92;frac{1}{2} g^{&#92;gamma &#92;delta} ( &#92;partial_&#92;alpha g_{&#92;beta &#92;delta} + &#92;partial_&#92;beta g_{&#92;alpha &#92;delta} - &#92;partial_&#92;delta g_{&#92;alpha &#92;beta} )' class='latex' /> (33)</p>
<p>for the Christoffel symbols of a general Riemannian manifold in local coordinates.  Specialising to the metric (25), some computation reveals that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%28%5CGamma%5E%7B%28N%29%7D%29%5Ei_%7Bjk%7D+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle (&#92;Gamma^{(N)})^i_{jk} = 0' title='&#92;displaystyle (&#92;Gamma^{(N)})^i_{jk} = 0' class='latex' /></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%28%5CGamma%5E%7B%28N%29%7D%29%5Ei_%7Bja%7D+%3D+%28%5CGamma%5E%7B%28N%29%7D%29%5Ei_%7Baj%7D+%3D+%28%5CGamma%5E%7B%28N%29%7D%29%5Ea_%7Bij%7D+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle (&#92;Gamma^{(N)})^i_{ja} = (&#92;Gamma^{(N)})^i_{aj} = (&#92;Gamma^{(N)})^a_{ij} = 0' title='&#92;displaystyle (&#92;Gamma^{(N)})^i_{ja} = (&#92;Gamma^{(N)})^i_{aj} = (&#92;Gamma^{(N)})^a_{ij} = 0' class='latex' /></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%28%5CGamma%5E%7B%28N%29%7D%29%5Ei_%7Bab%7D+%3D+%5Cfrac%7By_i%7D%7B2N%7D++%5Cdot+g_%7Bab%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle (&#92;Gamma^{(N)})^i_{ab} = &#92;frac{y_i}{2N}  &#92;dot g_{ab}' title='&#92;displaystyle (&#92;Gamma^{(N)})^i_{ab} = &#92;frac{y_i}{2N}  &#92;dot g_{ab}' class='latex' /> (34)</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%28%5CGamma%5E%7B%28N%29%7D%29%5Ea_%7Bib%7D+%3D+%28%5CGamma%5E%7B%28N%29%7D%29%5Ea_%7Bbi%7D+%3D+-%5Cfrac%7By_i%7D%7B2N%7D+g%5E%7Bac%7D++%5Cdot+g_%7Bcb%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle (&#92;Gamma^{(N)})^a_{ib} = (&#92;Gamma^{(N)})^a_{bi} = -&#92;frac{y_i}{2N} g^{ac}  &#92;dot g_{cb}' title='&#92;displaystyle (&#92;Gamma^{(N)})^a_{ib} = (&#92;Gamma^{(N)})^a_{bi} = -&#92;frac{y_i}{2N} g^{ac}  &#92;dot g_{cb}' class='latex' /></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%28%5CGamma%5E%7B%28N%29%7D%29%5Ea_%7Bbc%7D+%3D+%5CGamma%5Ea_%7Bbc%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle (&#92;Gamma^{(N)})^a_{bc} = &#92;Gamma^a_{bc}' title='&#92;displaystyle (&#92;Gamma^{(N)})^a_{bc} = &#92;Gamma^a_{bc}' class='latex' />.</p>
<p>Now the Ricci curvature <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRic%7D_%7B%5Calpha+%5Cbeta%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Ric}_{&#92;alpha &#92;beta}' title='&#92;hbox{Ric}_{&#92;alpha &#92;beta}' class='latex' /> can be computed from the Christoffel symbols by the standard formula</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRic%7D_%7B%5Calpha+%5Cbeta%7D+%3D+%5Cpartial_%5Cgamma+%5CGamma%5E%5Cgamma_%7B%5Calpha+%5Cbeta%7D+-+%5Cpartial_%5Cbeta+%5CGamma%5E%5Cgamma_%7B%5Calpha+%5Cgamma%7D++%2B+%5CGamma_%7B%5Calpha+%5Cbeta%7D%5E%5Cgamma+%5CGamma%5E%5Cmu_%7B%5Cgamma+%5Cmu%7D+-+%5CGamma%5E%5Cmu_%7B%5Calpha+%5Cgamma%7D+%5CGamma%5E%5Cgamma_%7B%5Cbeta+%5Cmu%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Ric}_{&#92;alpha &#92;beta} = &#92;partial_&#92;gamma &#92;Gamma^&#92;gamma_{&#92;alpha &#92;beta} - &#92;partial_&#92;beta &#92;Gamma^&#92;gamma_{&#92;alpha &#92;gamma}  + &#92;Gamma_{&#92;alpha &#92;beta}^&#92;gamma &#92;Gamma^&#92;mu_{&#92;gamma &#92;mu} - &#92;Gamma^&#92;mu_{&#92;alpha &#92;gamma} &#92;Gamma^&#92;gamma_{&#92;beta &#92;mu}' title='&#92;hbox{Ric}_{&#92;alpha &#92;beta} = &#92;partial_&#92;gamma &#92;Gamma^&#92;gamma_{&#92;alpha &#92;beta} - &#92;partial_&#92;beta &#92;Gamma^&#92;gamma_{&#92;alpha &#92;gamma}  + &#92;Gamma_{&#92;alpha &#92;beta}^&#92;gamma &#92;Gamma^&#92;mu_{&#92;gamma &#92;mu} - &#92;Gamma^&#92;mu_{&#92;alpha &#92;gamma} &#92;Gamma^&#92;gamma_{&#92;beta &#92;mu}' class='latex' />. (35)</p>
<p>If we apply this formula we obtain (after some computation)</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Chbox%7BRic%7D%5E%7B%28N%29%7D_%7Bij%7D+%3D+%5Cfrac%7B%5Cdelta_%7Bij%7D%7D%7B2N%7D+%5Chbox%7Btr%7D%28%5Cdot+g%29+%2B+O%28+1+%2F+N%5E2+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;hbox{Ric}^{(N)}_{ij} = &#92;frac{&#92;delta_{ij}}{2N} &#92;hbox{tr}(&#92;dot g) + O( 1 / N^2 )' title='&#92;displaystyle &#92;hbox{Ric}^{(N)}_{ij} = &#92;frac{&#92;delta_{ij}}{2N} &#92;hbox{tr}(&#92;dot g) + O( 1 / N^2 )' class='latex' /></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Chbox%7BRic%7D%5E%7B%28N%29%7D_%7Bia%7D+%3D+O%28+1+%2F+N+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;hbox{Ric}^{(N)}_{ia} = O( 1 / N )' title='&#92;displaystyle &#92;hbox{Ric}^{(N)}_{ia} = O( 1 / N )' class='latex' /> (36)</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Chbox%7BRic%7D%5E%7B%28N%29%7D_%7Bab%7D+%3D+%5Chbox%7BRic%7D_%7Bab%7D+%2B+%5Cfrac%7B1%7D%7B2%7D+%5Cdot+g_%7Bab%7D+%2B+O%281%2FN%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;hbox{Ric}^{(N)}_{ab} = &#92;hbox{Ric}_{ab} + &#92;frac{1}{2} &#92;dot g_{ab} + O(1/N)' title='&#92;displaystyle &#92;hbox{Ric}^{(N)}_{ab} = &#92;hbox{Ric}_{ab} + &#92;frac{1}{2} &#92;dot g_{ab} + O(1/N)' class='latex' />.</p>
<p style="text-align:left;">We thus see that if the original flow <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> obeys the Ricci flow equation <img src='http://s0.wp.com/latex.php?latex=%5Cdot+g+%3D+-2+%5Chbox%7BRic%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;dot g = -2 &#92;hbox{Ric}' title='&#92;dot g = -2 &#92;hbox{Ric}' class='latex' />, then the lifted manifold <img src='http://s0.wp.com/latex.php?latex=%28M%5E%7B%28N%29%7D%2C+%5Cmu%5E%7B%28N%29%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M^{(N)}, &#92;mu^{(N)})' title='(M^{(N)}, &#92;mu^{(N)})' class='latex' /> is nearly Ricci flat in the sense that all components of the Ricci curvature tensor are O(1/N) (in the region <img src='http://s0.wp.com/latex.php?latex=t+%3D+O%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t = O(1)' title='t = O(1)' class='latex' />).  In fact the above estimates show that the Ricci curvature tensor is also O(1/N) in the operator norm sense and <img src='http://s0.wp.com/latex.php?latex=O%281%2F%5Csqrt%7BN%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='O(1/&#92;sqrt{N})' title='O(1/&#92;sqrt{N})' class='latex' /> in the <a href="http://en.wikipedia.org/wiki/Hilbert-Schmidt_operator">Hilbert-Schmidt</a> (or <a href="http://en.wikipedia.org/wiki/Frobenius_norm#Frobenius_norm">Frobenius</a>) sense.</p>
<p style="text-align:left;">It turns out that this approximation is not quite good enough for applications to Ricci flow, mainly because the <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B%5Cdelta_%7Bij%7D%7D%7B2N%7D+%5Chbox%7Btr%7D%28%5Cdot+g%29+%3D+-+R+%5Cdelta_%7Bij%7D+%2F+N&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{&#92;delta_{ij}}{2N} &#92;hbox{tr}(&#92;dot g) = - R &#92;delta_{ij} / N' title='&#92;frac{&#92;delta_{ij}}{2N} &#92;hbox{tr}(&#92;dot g) = - R &#92;delta_{ij} / N' class='latex' /> term in (36) gives a significant contribution to the trace of the Ricci tensor <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRic%7D%5E%7B%28N%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Ric}^{(N)}' title='&#92;hbox{Ric}^{(N)}' class='latex' /> (i.e. the scalar curvature <img src='http://s0.wp.com/latex.php?latex=R%5E%7B%28N%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R^{(N)}' title='R^{(N)}' class='latex' />), even in the limit <img src='http://s0.wp.com/latex.php?latex=N+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='N &#92;to &#92;infty' title='N &#92;to &#92;infty' class='latex' />.  It turns out however that one can eliminate this problem by adding a correction term to the metric (24) involving the scalar curvature.  More precisely, given an ancient Ricci flow <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' />, define the modified metric <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+g%5E%7B%28N%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde g^{(N)}' title='&#92;tilde g^{(N)}' class='latex' /> by the formula</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%28d%5Ctilde+g%5E%7B%28N%29%7D%29%5E2+%3D+dy%5E2+%2B+%5Cfrac%7Br%5E2%7D%7BN%5E2%7D+R%28t%29+dr%5E2+%2B+dg%28t%29%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle (d&#92;tilde g^{(N)})^2 = dy^2 + &#92;frac{r^2}{N^2} R(t) dr^2 + dg(t)^2' title='&#92;displaystyle (d&#92;tilde g^{(N)})^2 = dy^2 + &#92;frac{r^2}{N^2} R(t) dr^2 + dg(t)^2' class='latex' /> (37)</p>
<p style="text-align:left;">where of course <img src='http://s0.wp.com/latex.php?latex=dr+%3D+%5Csum_%7Bi%3D1%7D%5EN+%5Cfrac%7By_i%7D%7Br%7D+dy_i&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='dr = &#92;sum_{i=1}^N &#92;frac{y_i}{r} dy_i' title='dr = &#92;sum_{i=1}^N &#92;frac{y_i}{r} dy_i' class='latex' /> is the derivative of the radial variable r, and R(t,x) is the scalar curvature of g(t) at x.  In coordinates, we have</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Ctilde+g%5E%7B%28N%29%7D_%7Bij%7D+%3D+%5Cdelta_%7Bij%7D+%2B+%5Cfrac%7By_i+y_j%7D%7BN%5E2%7D+R%28t%29%3B+%5Ctilde+g%5E%7B%28N%29%7D_%7Bia%7D+%3D+0%3B+%5Ctilde+g%5E%7B%28N%29%7D_%7Bab%7D+%3D+g_%7Bab%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;tilde g^{(N)}_{ij} = &#92;delta_{ij} + &#92;frac{y_i y_j}{N^2} R(t); &#92;tilde g^{(N)}_{ia} = 0; &#92;tilde g^{(N)}_{ab} = g_{ab}' title='&#92;displaystyle &#92;tilde g^{(N)}_{ij} = &#92;delta_{ij} + &#92;frac{y_i y_j}{N^2} R(t); &#92;tilde g^{(N)}_{ia} = 0; &#92;tilde g^{(N)}_{ab} = g_{ab}' class='latex' />. (38)</p>
<p style="text-align:left;"><strong>Exercise 5.</strong> Let <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> be a smooth ancient Ricci flow on <img src='http://s0.wp.com/latex.php?latex=%28-%5Cinfty%2C0%5D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(-&#92;infty,0]' title='(-&#92;infty,0]' class='latex' />, and let <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+g%5E%7B%28N%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde g^{(N)}' title='&#92;tilde g^{(N)}' class='latex' /> be defined by (37).  Show that in the region where <img src='http://s0.wp.com/latex.php?latex=y_i+%3D+O%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='y_i = O(1)' title='y_i = O(1)' class='latex' /> (so <img src='http://s0.wp.com/latex.php?latex=-t+%3D+%5Ctau+%3D+O%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='-t = &#92;tau = O(1)' title='-t = &#92;tau = O(1)' class='latex' />) and x ranges in a compact set, the Christoffel symbols <img src='http://s0.wp.com/latex.php?latex=%28%5Ctilde+%5CGamma%5E%7B%28N%29%7D%29%5E%7B%5Cgamma%7D_%7B%5Calpha+%5Cbeta%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;tilde &#92;Gamma^{(N)})^{&#92;gamma}_{&#92;alpha &#92;beta}' title='(&#92;tilde &#92;Gamma^{(N)})^{&#92;gamma}_{&#92;alpha &#92;beta}' class='latex' /> take the form</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%28%5Ctilde+%5CGamma%5E%7B%28N%29%7D%29%5Ei_%7Bjk%7D+%3D+%5Cfrac%7B%5Cdelta_%7Bjk%7D%7D%7BN%5E2%7D+R+y_i+%2B+O%281%2FN%5E3%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;tilde &#92;Gamma^{(N)})^i_{jk} = &#92;frac{&#92;delta_{jk}}{N^2} R y_i + O(1/N^3)' title='(&#92;tilde &#92;Gamma^{(N)})^i_{jk} = &#92;frac{&#92;delta_{jk}}{N^2} R y_i + O(1/N^3)' class='latex' /></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%28%5Ctilde+%5CGamma%5E%7B%28N%29%7D%29%5Ei_%7Bja%7D%2C+%28%5Ctilde+%5CGamma%5E%7B%28N%29%7D%29%5Ei_%7Baj%7D%2C+%28%5Ctilde+%5CGamma%5E%7B%28N%29%7D%29%5Ea_%7Bij%7D+%3D+O%281%2FN%5E2%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;tilde &#92;Gamma^{(N)})^i_{ja}, (&#92;tilde &#92;Gamma^{(N)})^i_{aj}, (&#92;tilde &#92;Gamma^{(N)})^a_{ij} = O(1/N^2)' title='(&#92;tilde &#92;Gamma^{(N)})^i_{ja}, (&#92;tilde &#92;Gamma^{(N)})^i_{aj}, (&#92;tilde &#92;Gamma^{(N)})^a_{ij} = O(1/N^2)' class='latex' /></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%28%5Ctilde+%5CGamma%5E%7B%28N%29%7D%29%5Ei_%7Bab%7D+%3D+%5Cfrac%7By_i%7D%7B2N%7D++%5Cdot+g_%7Bab%7D+%2B+O%281%2FN%5E2%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;tilde &#92;Gamma^{(N)})^i_{ab} = &#92;frac{y_i}{2N}  &#92;dot g_{ab} + O(1/N^2)' title='(&#92;tilde &#92;Gamma^{(N)})^i_{ab} = &#92;frac{y_i}{2N}  &#92;dot g_{ab} + O(1/N^2)' class='latex' /> (39)</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%28%5Ctilde+%5CGamma%5E%7B%28N%29%7D%29%5Ea_%7Bib%7D+%3D+%28%5Ctilde+%5CGamma%5E%7B%28N%29%7D%29%5Ea_%7Bbi%7D+%3D+-+%5Cfrac%7By_i%7D%7B2N%7D+g%5E%7Bac%7D++%5Cdot+g_%7Bcb%7D+%2B+O%281%2FN%5E2%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;tilde &#92;Gamma^{(N)})^a_{ib} = (&#92;tilde &#92;Gamma^{(N)})^a_{bi} = - &#92;frac{y_i}{2N} g^{ac}  &#92;dot g_{cb} + O(1/N^2)' title='(&#92;tilde &#92;Gamma^{(N)})^a_{ib} = (&#92;tilde &#92;Gamma^{(N)})^a_{bi} = - &#92;frac{y_i}{2N} g^{ac}  &#92;dot g_{cb} + O(1/N^2)' class='latex' /></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%28%5Ctilde+%5CGamma%5E%7B%28N%29%7D%29%5Ea_%7Bbc%7D+%3D+%5CGamma%5Ea_%7Bbc%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;tilde &#92;Gamma^{(N)})^a_{bc} = &#92;Gamma^a_{bc}' title='(&#92;tilde &#92;Gamma^{(N)})^a_{bc} = &#92;Gamma^a_{bc}' class='latex' />.</p>
<p>and the Ricci curvature <img src='http://s0.wp.com/latex.php?latex=%5Cwidetilde%7B%5Chbox%7BRic%7D%7D%5E%7B%28N%29%7D_%7B%5Calpha+%5Cbeta%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;widetilde{&#92;hbox{Ric}}^{(N)}_{&#92;alpha &#92;beta}' title='&#92;widetilde{&#92;hbox{Ric}}^{(N)}_{&#92;alpha &#92;beta}' class='latex' /> takes the form</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cwidetilde%7B%5Chbox%7BRic%7D%7D%5E%7B%28N%29%7D_%7Bij%7D+%3D+O%28+1+%2F+N%5E2+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;widetilde{&#92;hbox{Ric}}^{(N)}_{ij} = O( 1 / N^2 )' title='&#92;widetilde{&#92;hbox{Ric}}^{(N)}_{ij} = O( 1 / N^2 )' class='latex' /></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cwidetilde%7B%5Chbox%7BRic%7D%7D%5E%7B%28N%29%7D_%7Bia%7D+%3D+O%28+1+%2F+N+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;widetilde{&#92;hbox{Ric}}^{(N)}_{ia} = O( 1 / N )' title='&#92;widetilde{&#92;hbox{Ric}}^{(N)}_{ia} = O( 1 / N )' class='latex' /> (40)</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cwidetilde%7B%5Chbox%7BRic%7D%7D%5E%7B%28N%29%7D_%7Bab%7D+%3D+O%281%2FN%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;widetilde{&#92;hbox{Ric}}^{(N)}_{ab} = O(1/N)' title='&#92;widetilde{&#92;hbox{Ric}}^{(N)}_{ab} = O(1/N)' class='latex' />.</p>
<p style="text-align:left;">In particular, <img src='http://s0.wp.com/latex.php?latex=%5Cwidetilde%7B%5Chbox%7BRic%7D%7D%5E%7B%28N%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;widetilde{&#92;hbox{Ric}}^{(N)}' title='&#92;widetilde{&#92;hbox{Ric}}^{(N)}' class='latex' /> has norm <img src='http://s0.wp.com/latex.php?latex=O%281%2F%5Csqrt%7BN%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='O(1/&#92;sqrt{N})' title='O(1/&#92;sqrt{N})' class='latex' /> in the <a href="http://en.wikipedia.org/wiki/Trace_class">trace</a> (i.e. <a href="http://en.wikipedia.org/wiki/Nuclear_operator">nuclear</a>) norm (and hence in the Hilbert-Schmidt/Frobenius and operator norms). <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;"><strong>Exercise 6. </strong> Let the assumptions and notation be as in Exercise 5, let <img src='http://s0.wp.com/latex.php?latex=u%3A+%28-%5Cinfty%2C0%5D+%5Ctimes+M+%5Cto+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u: (-&#92;infty,0] &#92;times M &#92;to {&#92;Bbb R}' title='u: (-&#92;infty,0] &#92;times M &#92;to {&#92;Bbb R}' class='latex' /> be a smooth function, and let <img src='http://s0.wp.com/latex.php?latex=u%5E%7B%28N%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u^{(N)}' title='u^{(N)}' class='latex' /> be as in (31).  Show that the Laplacian <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+%5CDelta%5E%7B%28N%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde &#92;Delta^{(N)}' title='&#92;tilde &#92;Delta^{(N)}' class='latex' /> associated to <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+g%5E%7B%28N%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde g^{(N)}' title='&#92;tilde g^{(N)}' class='latex' /> obeys a similar formula to (32), but with the <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Br%7D%7B2N%7D+%5Chbox%7Btr%7D%28%5Cdot+g%29+%5Cpartial_r+u%5E%7B%28N%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{r}{2N} &#92;hbox{tr}(&#92;dot g) &#92;partial_r u^{(N)}' title='&#92;frac{r}{2N} &#92;hbox{tr}(&#92;dot g) &#92;partial_r u^{(N)}' class='latex' /> term replaced by terms which are <img src='http://s0.wp.com/latex.php?latex=O%281%2FN%5E2%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='O(1/N^2)' title='O(1/N^2)' class='latex' /> when t, x are bounded. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:center;">&#8211; Perelman&#8217;s reduced length and reduced volume &#8211;</p>
<p style="text-align:left;">In the previous discussion, we have converted a Ricci flow <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> to a Riemannian manifold <img src='http://s0.wp.com/latex.php?latex=%28M%5E%7B%28N%29%7D%2C+%5Ctilde+g%5E%7B%28N%29%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M^{(N)}, &#92;tilde g^{(N)})' title='(M^{(N)}, &#92;tilde g^{(N)})' class='latex' /> of much higher dimension which is almost Ricci flat.  Let us adopt the heuristic that this latter manifold is sufficiently close to being Ricci flat that the Bishop-Gromov inequality (Corollary 1) holds (at least in the asymptotic limit <img src='http://s0.wp.com/latex.php?latex=N+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='N &#92;to &#92;infty' title='N &#92;to &#92;infty' class='latex' />), thus the Bishop-Gromov reduced volume <img src='http://s0.wp.com/latex.php?latex=r_0%5E%7B-N-d%7D+B_%7B%5Ctilde+g%5E%7B%28N%29%7D%7D%28%280%2Cx_0%29%2Cr_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_0^{-N-d} B_{&#92;tilde g^{(N)}}((0,x_0),r_0)' title='r_0^{-N-d} B_{&#92;tilde g^{(N)}}((0,x_0),r_0)' class='latex' /> should heuristically be non-increasing in <img src='http://s0.wp.com/latex.php?latex=r_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_0' title='r_0' class='latex' />, where we fix a spatial origin <img src='http://s0.wp.com/latex.php?latex=x_0+%5Cin+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0 &#92;in M' title='x_0 &#92;in M' class='latex' />.</p>
<p style="text-align:left;">In order to exploit the above heuristic, we first need to understand the distance function on <img src='http://s0.wp.com/latex.php?latex=%28%5Ctilde+M%2C+g%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;tilde M, g(t))' title='(&#92;tilde M, g(t))' class='latex' />.  Let <img src='http://s0.wp.com/latex.php?latex=%28y_1%2Cx_1%29+%3D+%28r_1%5Comega_1%2C+x_1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(y_1,x_1) = (r_1&#92;omega_1, x_1)' title='(y_1,x_1) = (r_1&#92;omega_1, x_1)' class='latex' /> be a point in <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+M+%3D+%7B%5CBbb+R%7D%5EN+%5Ctimes+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde M = {&#92;Bbb R}^N &#92;times M' title='&#92;tilde M = {&#92;Bbb R}^N &#92;times M' class='latex' />, and consider a length-minimising geodesic <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%5E%7B%28N%29%7D%3A+%5B0%2C%5Ctau_1%5D+%5Cto+%5Ctilde+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma^{(N)}: [0,&#92;tau_1] &#92;to &#92;tilde M' title='&#92;gamma^{(N)}: [0,&#92;tau_1] &#92;to &#92;tilde M' class='latex' /> from <img src='http://s0.wp.com/latex.php?latex=%280%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(0,x_0)' title='(0,x_0)' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=%28r_1%5Comega_1%2C+x_1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(r_1&#92;omega_1, x_1)' title='(r_1&#92;omega_1, x_1)' class='latex' />, where we have normalised the length <img src='http://s0.wp.com/latex.php?latex=%5Ctau_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau_1' title='&#92;tau_1' class='latex' /> of the parameter interval by the formula <img src='http://s0.wp.com/latex.php?latex=%5Ctau_1+%3D+r_1%5E2%2F2N&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau_1 = r_1^2/2N' title='&#92;tau_1 = r_1^2/2N' class='latex' />.</p>
<p style="text-align:left;">Observe that the metric (37) can be rewritten in polar coordinates (after substituting <img src='http://s0.wp.com/latex.php?latex=-t+%3D+%5Ctau+%3D+r%5E2%2F2N&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='-t = &#92;tau = r^2/2N' title='-t = &#92;tau = r^2/2N' class='latex' />) as</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%28d%5Ctilde+g%5E%7B%28N%29%7D%29%5E2+%3D+%28%5Cfrac%7BN%7D%7B2%5Ctau%7D+%2B+R%29+d%5Ctau%5E2+%2B+2N%5Ctau+d%5Comega%5E2+%2B+dg%28-%5Ctau%29%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle (d&#92;tilde g^{(N)})^2 = (&#92;frac{N}{2&#92;tau} + R) d&#92;tau^2 + 2N&#92;tau d&#92;omega^2 + dg(-&#92;tau)^2' title='&#92;displaystyle (d&#92;tilde g^{(N)})^2 = (&#92;frac{N}{2&#92;tau} + R) d&#92;tau^2 + 2N&#92;tau d&#92;omega^2 + dg(-&#92;tau)^2' class='latex' /> (41)</p>
<p style="text-align:left;">(which is essentially the first formula in Section 6 of <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0211159">Perelman&#8217;s paper</a>).  Note that the angular variable <img src='http://s0.wp.com/latex.php?latex=%5Comega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;omega' title='&#92;omega' class='latex' /> only influences the second term in this metric and not the other two.  Because of this, one sees that the geodesic <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%5E%7B%28N%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma^{(N)}' title='&#92;gamma^{(N)}' class='latex' /> must keep <img src='http://s0.wp.com/latex.php?latex=%5Comega&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;omega' title='&#92;omega' class='latex' /> constant in order to be length-minimising (i.e. <img src='http://s0.wp.com/latex.php?latex=%5Comega+%3D+%5Comega_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;omega = &#92;omega_1' title='&#92;omega = &#92;omega_1' class='latex' /> for the duration of the geodesic).  Turning next to the <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' /> variable, we then see that for N large enough, the geodesic <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%5E%7B%28N%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma^{(N)}' title='&#92;gamma^{(N)}' class='latex' /> should increase <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' /> continuously from 0 to <img src='http://s0.wp.com/latex.php?latex=%5Ctau_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau_1' title='&#92;tau_1' class='latex' /> (as the <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7BN%7D%7B2%5Ctau%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{N}{2&#92;tau}' title='&#92;frac{N}{2&#92;tau}' class='latex' /> term in (41) will severely penalise any backtracking.  After a reparameterisation we may in fact assume that <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' /> increases at constant speed, thus we have</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cgamma%5E%7B%28N%29%7D%28%5Ctau%29+%3D+%28+%5Csqrt%7B2N%5Ctau%7D+%5Comega_1%2C+%5Cgamma%28%5Ctau%29+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;gamma^{(N)}(&#92;tau) = ( &#92;sqrt{2N&#92;tau} &#92;omega_1, &#92;gamma(&#92;tau) )' title='&#92;displaystyle &#92;gamma^{(N)}(&#92;tau) = ( &#92;sqrt{2N&#92;tau} &#92;omega_1, &#92;gamma(&#92;tau) )' class='latex' /> (42)</p>
<p style="text-align:left;">for some path <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%3A+%5B0%2C%5Ctau_1%5D+%5Cto+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma: [0,&#92;tau_1] &#92;to M' title='&#92;gamma: [0,&#92;tau_1] &#92;to M' class='latex' /> from <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=x_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_1' title='x_1' class='latex' />.  Using (41), the length of this geodesic is</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cint_0%5E%7B%5Ctau_1%7D+%5Csqrt%7B+%5Cfrac%7BN%7D%7B2%5Ctau%7D+%2B+R+%2B+%26%23124%3B%5Cgamma%27%28%5Ctau%29+%26%23124%3B_%7Bg%28-%5Ctau%29%7D%5E2%7D%5C+d%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;int_0^{&#92;tau_1} &#92;sqrt{ &#92;frac{N}{2&#92;tau} + R + &#124;&#92;gamma&#039;(&#92;tau) &#124;_{g(-&#92;tau)}^2}&#92; d&#92;tau' title='&#92;displaystyle &#92;int_0^{&#92;tau_1} &#92;sqrt{ &#92;frac{N}{2&#92;tau} + R + &#124;&#92;gamma&#039;(&#92;tau) &#124;_{g(-&#92;tau)}^2}&#92; d&#92;tau' class='latex' /> (43)</p>
<p style="text-align:left;">which by Taylor expansion is equal to</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Csqrt%7B2N%5Ctau_1%7D+%2B+%5Cfrac%7B1%7D%7B%5Csqrt%7B2N%7D%7D+%7B%5Cmathcal+L%7D%28%5Cgamma%29+%2B+O%28N%5E%7B-3%2F2%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;sqrt{2N&#92;tau_1} + &#92;frac{1}{&#92;sqrt{2N}} {&#92;mathcal L}(&#92;gamma) + O(N^{-3/2})' title='&#92;displaystyle &#92;sqrt{2N&#92;tau_1} + &#92;frac{1}{&#92;sqrt{2N}} {&#92;mathcal L}(&#92;gamma) + O(N^{-3/2})' class='latex' /> (44)</p>
<p style="text-align:left;">where the <em><img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-length</em> of <img src='http://s0.wp.com/latex.php?latex=%5Cgamma&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma' title='&#92;gamma' class='latex' /> is defined as</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D%28%5Cgamma%29+%3A%3D+%5Cint_0%5E%7B%5Ctau_1%7D+%5Csqrt%7B%5Ctau%7D+%28+R+%2B+%26%23124%3B%5Cgamma%27%28%5Ctau%29%26%23124%3B_%7Bg%28-%5Ctau%29%7D%5E2+%29%5C+d%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}(&#92;gamma) := &#92;int_0^{&#92;tau_1} &#92;sqrt{&#92;tau} ( R + &#124;&#92;gamma&#039;(&#92;tau)&#124;_{g(-&#92;tau)}^2 )&#92; d&#92;tau' title='{&#92;mathcal L}(&#92;gamma) := &#92;int_0^{&#92;tau_1} &#92;sqrt{&#92;tau} ( R + &#124;&#92;gamma&#039;(&#92;tau)&#124;_{g(-&#92;tau)}^2 )&#92; d&#92;tau' class='latex' /> (45)</p>
<p style="text-align:left;">Note that this quantity is independent of N.  Thus, heuristically, geodesics in <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+M%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal M}' title='{&#92;mathcal M}' class='latex' /> from <img src='http://s0.wp.com/latex.php?latex=%280%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(0,x_0)' title='(0,x_0)' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=%28r_1+%5Comega_1%2Cx_1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(r_1 &#92;omega_1,x_1)' title='(r_1 &#92;omega_1,x_1)' class='latex' /> should (approximately) minimise the <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-length.  If we define <img src='http://s0.wp.com/latex.php?latex=L_%7B%280%2Cx_0%29%7D%28-%5Ctau_1%2Cx_1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='L_{(0,x_0)}(-&#92;tau_1,x_1)' title='L_{(0,x_0)}(-&#92;tau_1,x_1)' class='latex' /> to be the infimum of <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D%28%5Cgamma%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}(&#92;gamma)' title='{&#92;mathcal L}(&#92;gamma)' class='latex' /> over all paths <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%3A+%5B0%2C%5Ctau_1%5D+%5Cto+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma: [0,&#92;tau_1] &#92;to M' title='&#92;gamma: [0,&#92;tau_1] &#92;to M' class='latex' /> from <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0' title='x_0' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=x_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_1' title='x_1' class='latex' />, we thus obtain the heuristic approximation</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+d_%7B%5Ctilde+g%5E%7B%28N%29%7D%7D%28+%280%2Cx_0%29%2C+%28r_1+%5Comega_1%2C+x_1%29+%29+%3D+%5Csqrt%7B2N%5Ctau_1%7D+%2B+%5Cfrac%7B1%7D%7B%5Csqrt%7B2N%7D%7D+L_%7B%280%2Cx_0%29%7D%28-%5Ctau_1%2Cx_1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle d_{&#92;tilde g^{(N)}}( (0,x_0), (r_1 &#92;omega_1, x_1) ) = &#92;sqrt{2N&#92;tau_1} + &#92;frac{1}{&#92;sqrt{2N}} L_{(0,x_0)}(-&#92;tau_1,x_1)' title='&#92;displaystyle d_{&#92;tilde g^{(N)}}( (0,x_0), (r_1 &#92;omega_1, x_1) ) = &#92;sqrt{2N&#92;tau_1} + &#92;frac{1}{&#92;sqrt{2N}} L_{(0,x_0)}(-&#92;tau_1,x_1)' class='latex' />. (46)</p>
<p style="text-align:left;"><strong>Exercise 7.</strong> When M is the Euclidean space <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+R%7D%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb R}^d' title='{&#92;Bbb R}^d' class='latex' /> (with the trivial Ricci flow, of course), show that <img src='http://s0.wp.com/latex.php?latex=L_%7B%280%2Cx_0%29%7D%28-%5Ctau_1%2Cx_1%29+%3D+%26%23124%3Bx_1-x_0%26%23124%3B%5E2+%2F+2+%5Csqrt%7B%5Ctau_1%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='L_{(0,x_0)}(-&#92;tau_1,x_1) = &#124;x_1-x_0&#124;^2 / 2 &#92;sqrt{&#92;tau_1}' title='L_{(0,x_0)}(-&#92;tau_1,x_1) = &#124;x_1-x_0&#124;^2 / 2 &#92;sqrt{&#92;tau_1}' class='latex' />, and the minimiser is given by <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%28%5Ctau%29+%3D+x_0+%2B+%5Csqrt%7B%5Cfrac%7B%5Ctau%7D%7B%5Ctau_1%7D%7D+%28x_1-x_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma(&#92;tau) = x_0 + &#92;sqrt{&#92;frac{&#92;tau}{&#92;tau_1}} (x_1-x_0)' title='&#92;gamma(&#92;tau) = x_0 + &#92;sqrt{&#92;frac{&#92;tau}{&#92;tau_1}} (x_1-x_0)' class='latex' />. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;">From (46) we see that the ball in <img src='http://s0.wp.com/latex.php?latex=%28M%5E%7B%28N%29%7D%2C+%5Ctilde+g%5E%7B%28N%29%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M^{(N)}, &#92;tilde g^{(N)})' title='(M^{(N)}, &#92;tilde g^{(N)})' class='latex' /> of radius <img src='http://s0.wp.com/latex.php?latex=r_0+%3D+%5Csqrt%7B2N+%5Ctau_0%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_0 = &#92;sqrt{2N &#92;tau_0}' title='r_0 = &#92;sqrt{2N &#92;tau_0}' class='latex' /> centred at <img src='http://s0.wp.com/latex.php?latex=%280%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(0,x_0)' title='(0,x_0)' class='latex' /> (where, as always, we are in the regime <img src='http://s0.wp.com/latex.php?latex=%5Ctau_0+%3D+O%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau_0 = O(1)' title='&#92;tau_0 = O(1)' class='latex' />, so <img src='http://s0.wp.com/latex.php?latex=r_0%5E2+%3D+O%28N%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_0^2 = O(N)' title='r_0^2 = O(N)' class='latex' />) should heuristically take the form</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5C%7B+%28r_1+%5Comega_1%2C+x_1%29%3A+L_%7B%280%2Cx_0%29%7D%28-%5Ctau_1%2Cx_1%29+%5Cleq+2N+%28%5Csqrt%7B%5Ctau_0%7D-%5Csqrt%7B%5Ctau_1%7D%29+%5C%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;{ (r_1 &#92;omega_1, x_1): L_{(0,x_0)}(-&#92;tau_1,x_1) &#92;leq 2N (&#92;sqrt{&#92;tau_0}-&#92;sqrt{&#92;tau_1}) &#92;}' title='&#92;{ (r_1 &#92;omega_1, x_1): L_{(0,x_0)}(-&#92;tau_1,x_1) &#92;leq 2N (&#92;sqrt{&#92;tau_0}-&#92;sqrt{&#92;tau_1}) &#92;}' class='latex' />. (47)</p>
<p style="text-align:left;">If we make the plausible assumption that <img src='http://s0.wp.com/latex.php?latex=L_%7B%280%2Cx_0%29%7D%28-%5Ctau%2Cx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='L_{(0,x_0)}(-&#92;tau,x)' title='L_{(0,x_0)}(-&#92;tau,x)' class='latex' /> varies smoothly in <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' />, then (47) is heuristically close (when N is large) to</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5C%7B+%28r_1+%5Comega_1%2C+x_1%29%3A+L_%7B%280%2Cx_0%29%7D%28-%5Ctau_0%2Cx_1%29+%5Cleq+2N+%28%5Csqrt%7B%5Ctau_0%7D-%5Csqrt%7B%5Ctau_1%7D%29+%5C%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;{ (r_1 &#92;omega_1, x_1): L_{(0,x_0)}(-&#92;tau_0,x_1) &#92;leq 2N (&#92;sqrt{&#92;tau_0}-&#92;sqrt{&#92;tau_1}) &#92;}' title='&#92;{ (r_1 &#92;omega_1, x_1): L_{(0,x_0)}(-&#92;tau_0,x_1) &#92;leq 2N (&#92;sqrt{&#92;tau_0}-&#92;sqrt{&#92;tau_1}) &#92;}' class='latex' /> (48)</p>
<p>or equivalently</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5C%7B+%28r_1+%5Comega_1%2C+x_1%29%3A+r_1+%5Cleq+r_0+-+%5Csqrt%7B2N%7D+L_%7B%280%2Cx_0%29%7D%28-%5Ctau_0%2Cx_1%29+%5C%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;{ (r_1 &#92;omega_1, x_1): r_1 &#92;leq r_0 - &#92;sqrt{2N} L_{(0,x_0)}(-&#92;tau_0,x_1) &#92;}' title='&#92;{ (r_1 &#92;omega_1, x_1): r_1 &#92;leq r_0 - &#92;sqrt{2N} L_{(0,x_0)}(-&#92;tau_0,x_1) &#92;}' class='latex' />. (49)</p>
<p>Now, the volume measure of (37) is of the form <img src='http://s0.wp.com/latex.php?latex=%281+%2B+O%281%2FN%29%29+dy+d%5Cmu%28t%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(1 + O(1/N)) dy d&#92;mu(t)' title='(1 + O(1/N)) dy d&#92;mu(t)' class='latex' />, and so the volume of (49) is approximately</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+C_N+%5Cint_M+%5Cint_0%5E%7Br_0+-+%5Csqrt%7B2N%7D+L_%7B%280%2Cx_0%29%7D%28-%5Ctau_0%2Cx_1%29%7D+r_1%5E%7BN-1%7D%5C+dr_1+d%5Cmu%28t_1%29%28x_1%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle C_N &#92;int_M &#92;int_0^{r_0 - &#92;sqrt{2N} L_{(0,x_0)}(-&#92;tau_0,x_1)} r_1^{N-1}&#92; dr_1 d&#92;mu(t_1)(x_1)' title='&#92;displaystyle C_N &#92;int_M &#92;int_0^{r_0 - &#92;sqrt{2N} L_{(0,x_0)}(-&#92;tau_0,x_1)} r_1^{N-1}&#92; dr_1 d&#92;mu(t_1)(x_1)' class='latex' />.  (50)</p>
<p>(Note there is a slight abuse of notation since <img src='http://s0.wp.com/latex.php?latex=t_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_1' title='t_1' class='latex' /> depends on <img src='http://s0.wp.com/latex.php?latex=r_1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_1' title='r_1' class='latex' />, but it will soon be clear that this abuse is harmless.)  When N is large, the inner integral is dominated by its right endpoint as before, and so (50) is approximately</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7B1%7D%7BN%7D+C_N+%5Cint_M+%28r_0+-+%5Csqrt%7B2N%7D+L_%7B%280%2Cx_0%29%7D%28-%5Ctau_0%2Cx%29%29%5EN+d%5Cmu%28t_0%29%28x%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{1}{N} C_N &#92;int_M (r_0 - &#92;sqrt{2N} L_{(0,x_0)}(-&#92;tau_0,x))^N d&#92;mu(t_0)(x)' title='&#92;displaystyle &#92;frac{1}{N} C_N &#92;int_M (r_0 - &#92;sqrt{2N} L_{(0,x_0)}(-&#92;tau_0,x))^N d&#92;mu(t_0)(x)' class='latex' />.  (51)</p>
<p>We can Taylor expand this to be approximately</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7B1%7D%7BN%7D+C_N+r_0%5EN+%5Cint_M+%5Cexp%28-+l_%7B%280%2Cx_0%29%7D%28-%5Ctau_0%2Cx%29+%29%5C+d%5Cmu%28t_0%29%28x%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{1}{N} C_N r_0^N &#92;int_M &#92;exp(- l_{(0,x_0)}(-&#92;tau_0,x) )&#92; d&#92;mu(t_0)(x)' title='&#92;displaystyle &#92;frac{1}{N} C_N r_0^N &#92;int_M &#92;exp(- l_{(0,x_0)}(-&#92;tau_0,x) )&#92; d&#92;mu(t_0)(x)' class='latex' /> (52)</p>
<p>where the <em>Perelman reduced length</em> <img src='http://s0.wp.com/latex.php?latex=l_%7B%280%2Cx_0%29%7D%28-%5Ctau_0%2Cx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_{(0,x_0)}(-&#92;tau_0,x)' title='l_{(0,x_0)}(-&#92;tau_0,x)' class='latex' /> is defined as</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+l_%7B%280%2Cx_0%29%7D%28-%5Ctau%2Cx%29+%3A%3D+%5Cfrac%7BL_%7B%280%2Cx_0%29%7D%28-%5Ctau%2Cx%29%7D%7B2%5Csqrt%7B%5Ctau%7D%7D+%3D+%5Cfrac%7B%5Csqrt%7B2N%7D+L_%7B%280%2Cx_0%29%7D%28-%5Ctau%2Cx%29%7D%7B2r_0%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle l_{(0,x_0)}(-&#92;tau,x) := &#92;frac{L_{(0,x_0)}(-&#92;tau,x)}{2&#92;sqrt{&#92;tau}} = &#92;frac{&#92;sqrt{2N} L_{(0,x_0)}(-&#92;tau,x)}{2r_0}' title='&#92;displaystyle l_{(0,x_0)}(-&#92;tau,x) := &#92;frac{L_{(0,x_0)}(-&#92;tau,x)}{2&#92;sqrt{&#92;tau}} = &#92;frac{&#92;sqrt{2N} L_{(0,x_0)}(-&#92;tau,x)}{2r_0}' class='latex' /> (53)</p>
<p><strong>Example 1.</strong> Continuing the Euclidean example of Exercise 7, we have <img src='http://s0.wp.com/latex.php?latex=l_%7B%280%2Cx_0%29%7D%28-%5Ctau%2Cx%29+%3D+%26%23124%3Bx-x_0%26%23124%3B%5E2%2F4%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_{(0,x_0)}(-&#92;tau,x) = &#124;x-x_0&#124;^2/4&#92;tau' title='l_{(0,x_0)}(-&#92;tau,x) = &#124;x-x_0&#124;^2/4&#92;tau' class='latex' />, which is the familiar exponent in the fundamental solution (15).  This is, of course, not a coincidence. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>From (52) we thus heuristically conclude that the Bishop-Gromov reduced volume of <img src='http://s0.wp.com/latex.php?latex=%28M%5E%7B%28N%29%7D%2C+%5Ctilde+g%5E%7B%28N%29%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M^{(N)}, &#92;tilde g^{(N)})' title='(M^{(N)}, &#92;tilde g^{(N)})' class='latex' /> at <img src='http://s0.wp.com/latex.php?latex=%280%2Cx_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(0,x_0)' title='(0,x_0)' class='latex' /> and at radius <img src='http://s0.wp.com/latex.php?latex=r_0+%3D+%5Csqrt%7B2N%5Ctau_0%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_0 = &#92;sqrt{2N&#92;tau_0}' title='r_0 = &#92;sqrt{2N&#92;tau_0}' class='latex' /> is approximately equal to a constant multiple of <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+V_%7B%280%2Cx_0%29%7D%28+-%5Ctau+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde V_{(0,x_0)}( -&#92;tau )' title='&#92;tilde V_{(0,x_0)}( -&#92;tau )' class='latex' />, where the <em>Perelman reduced volume</em> <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+V_%7B%280%2Cx_0%29%7D%28+-%5Ctau+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde V_{(0,x_0)}( -&#92;tau )' title='&#92;tilde V_{(0,x_0)}( -&#92;tau )' class='latex' /> is defined as</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Ctilde+V_%7B%280%2Cx_0%29%7D%28+-%5Ctau+%29+%3A%3D+%5Cint_M+%5Ctau%5E%7B-d%2F2%7D+%5Cexp%28+-+l_%7B%280%2Cx_0%29%7D%28+-%5Ctau%2Cx%29+%29%5C+d%5Cmu%28-%5Ctau%29%28x%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;tilde V_{(0,x_0)}( -&#92;tau ) := &#92;int_M &#92;tau^{-d/2} &#92;exp( - l_{(0,x_0)}( -&#92;tau,x) )&#92; d&#92;mu(-&#92;tau)(x)' title='&#92;displaystyle &#92;tilde V_{(0,x_0)}( -&#92;tau ) := &#92;int_M &#92;tau^{-d/2} &#92;exp( - l_{(0,x_0)}( -&#92;tau,x) )&#92; d&#92;mu(-&#92;tau)(x)' class='latex' />. (54)</p>
<p><strong>Example 2.</strong> Again continuing the Euclidean example, the reduced volume in Euclidean space (with the trivial Ricci flow) is always <img src='http://s0.wp.com/latex.php?latex=%284%5Cpi%29%5E%7Bd%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(4&#92;pi)^{d/2}' title='(4&#92;pi)^{d/2}' class='latex' />. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p><em>Formally</em> applying Corollary 1, we are thus led to</p>
<blockquote><p><strong>Conjecture 1.</strong> (Monotonicity of Perelman reduced volume)  Let <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> be a Ricci flow on <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5B-T%2C0%5D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[-T,0]' title='{}[-T,0]' class='latex' />, and let <img src='http://s0.wp.com/latex.php?latex=x_0+%5Cin+M_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_0 &#92;in M_0' title='x_0 &#92;in M_0' class='latex' />.  Then the quantity <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+V_%7B%280%2Cx_0%29%7D%28+-%5Ctau+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde V_{(0,x_0)}( -&#92;tau )' title='&#92;tilde V_{(0,x_0)}( -&#92;tau )' class='latex' /> for <img src='http://s0.wp.com/latex.php?latex=0+%26%2360%3B+%5Ctau+%5Cleq+T&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &lt; &#92;tau &#92;leq T' title='0 &lt; &#92;tau &#92;leq T' class='latex' /> is monotone non-increasing in <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' />.</p></blockquote>
<p><strong>Remark 6. </strong>Note here we are not taking the Ricci flow to be ancient; this would correspond to the manifold <img src='http://s0.wp.com/latex.php?latex=M%5E%7B%28N%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M^{(N)}' title='M^{(N)}' class='latex' /> being replaced by an incomplete manifold, of radius about <img src='http://s0.wp.com/latex.php?latex=%5Csqrt%7B2NT%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;sqrt{2NT}' title='&#92;sqrt{2NT}' class='latex' />.  However, because of the restriction <img src='http://s0.wp.com/latex.php?latex=%5Ctau+%5Cleq+T&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau &#92;leq T' title='&#92;tau &#92;leq T' class='latex' />, the above heuristic arguments never &#8220;encounter&#8221; the lack of completeness, and so it is reasonable to expect that the conjecture will continue to hold in the non-ancient case.  This is of course an essential point for our applications, since the Ricci flows we study are not assumed to be ancient. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p><strong>Remark 7.</strong> At an crude heuristic level, the Perelman reduced volume <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+V_%7B%280%2Cx_0%29%7D%28+-%5Ctau+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde V_{(0,x_0)}( -&#92;tau )' title='&#92;tilde V_{(0,x_0)}( -&#92;tau )' class='latex' /> is roughly like <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BVol%7D_%7Bg%28-%5Ctau%29%7D%28+-%5Ctau%2C+O%28%5Csqrt%7B%5Ctau%7D%29+%29+%2F+%5Ctau%5E%7Bd%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Vol}_{g(-&#92;tau)}( -&#92;tau, O(&#92;sqrt{&#92;tau}) ) / &#92;tau^{d/2}' title='&#92;hbox{Vol}_{g(-&#92;tau)}( -&#92;tau, O(&#92;sqrt{&#92;tau}) ) / &#92;tau^{d/2}' class='latex' /> (since, in view of Exercise 7, we expect <img src='http://s0.wp.com/latex.php?latex=l_%7B%280%2Cx_0%29%7D%28-%5Ctau%2Cx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='l_{(0,x_0)}(-&#92;tau,x)' title='l_{(0,x_0)}(-&#92;tau,x)' class='latex' /> to behave like <img src='http://s0.wp.com/latex.php?latex=d%28x_0%2Cx%29%5E2%2F%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d(x_0,x)^2/&#92;tau' title='d(x_0,x)^2/&#92;tau' class='latex' />, especially in regions of bounded normalised curvature, where we are deliberately vague about exactly what metric we using to define d).  This heuristic suggests that Conjecture 1 should be able to establish the non-collapsing result we want (Theorem 2 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/20/285g-lecture-7-rescaling-of-ricci-flows-and-kappa-noncollapsing/">Lecture 7</a>).  This will be made more rigorous in subsequent lectures. For now, we observe that the Perelman reduced length and reduced volume are dimensionless (just as the Bishop-Gromov reduced volume is), which as discussed in <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/20/285g-lecture-7-rescaling-of-ricci-flows-and-kappa-noncollapsing/">Lecture 7</a> is basically a necessary condition in order for this quantity to force non-collapsing of the geometry. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>As far as I am aware, there is no rigorous proof of Conjecture 1 that follows the above high-dimensional comparison geometry heuristic argument.  Nevertheless, it is possible to prove Conjecture 1 by other means, and in particular by developing parabolic analogues of all the comparison geometry machinery that is used to prove the Bishop-Gromov inequality (and in particular, developing a theory of <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}' title='{&#92;mathcal L}' class='latex' />-geodesics analogous to the &#8220;elliptic&#8221; theory of geodesics on a Riemannian manifold.  This will be the focus of the next few lectures.</p>
<p style="text-align:left;"><strong>Remark 8.</strong> It seems of interest to try to make the above arguments more rigorous, and to expand the dictionary between elliptic and parabolic equations.  I do not know however of much literature in this direction, apart from Section 6 of <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0211159">Perelman&#8217;s original paper</a> (see also Section 3.1 of <a class="snap_noshots" href="http://arxiv.org/abs/math/0612069">Cao-Zhu</a>), in which a few other parabolic notions (e.g. the backwards heat equation, or the modified Ricci flow from the <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/24/285a-lecture-8-ricci-flow-as-a-gradient-flow-log-sobolev-inequalities-and-perelman-entropy/">previous lecture</a>) are reinterpreted as high-dimensional elliptic notions. See however the work of <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=1362964">Chow and Chu</a> (see also this <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=1406020">sequel paper</a>), which views parabolic theory as a degenerate version of elliptic theory; Perelman&#8217;s viewpoint can be interpreted as a regularisation of Chow-Chu&#8217;s viewpoint. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
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<title><![CDATA[285G, Lecture 8: Ricci flow as a gradient flow, log-Sobolev inequalities, and Perelman entropy]]></title>
<link>http://terrytao.wordpress.com/2008/04/24/285a-lecture-8-ricci-flow-as-a-gradient-flow-log-sobolev-inequalities-and-perelman-entropy/</link>
<pubDate>Fri, 25 Apr 2008 00:10:48 +0000</pubDate>
<dc:creator>Terence Tao</dc:creator>
<guid>http://terrytao.wordpress.com/2008/04/24/285a-lecture-8-ricci-flow-as-a-gradient-flow-log-sobolev-inequalities-and-perelman-entropy/</guid>
<description><![CDATA[It is well known that the heat equation (1) on a compact Riemannian manifold (M,g) (with metric g st]]></description>
<content:encoded><![CDATA[<p>It is well known that the <a href="http://en.wikipedia.org/wiki/Heat_equation">heat equation</a></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdot+f+%3D+%5CDelta+f&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;dot f = &#92;Delta f' title='&#92;dot f = &#92;Delta f' class='latex' /> (1)</p>
<p>on a compact Riemannian manifold (M,g) (with metric g static, i.e. independent of time), where <img src='http://s0.wp.com/latex.php?latex=f%3A+%5B0%2CT%5D+%5Ctimes+M+%5Cto+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='f: [0,T] &#92;times M &#92;to {&#92;Bbb R}' title='f: [0,T] &#92;times M &#92;to {&#92;Bbb R}' class='latex' /> is a scalar field, can be interpreted as the <a href="http://en.wikipedia.org/wiki/Gradient_flow#Gradient_field">gradient flow</a> for the <a href="http://en.wikipedia.org/wiki/Dirichlet_energy">Dirichlet energy</a> functional</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+E%28f%29+%3A%3D+%5Cfrac%7B1%7D%7B2%7D+%5Cint_M+%26%23124%3B%5Cnabla+f%26%23124%3B_g%5E2%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle E(f) := &#92;frac{1}{2} &#92;int_M &#124;&#92;nabla f&#124;_g^2&#92; d&#92;mu' title='&#92;displaystyle E(f) := &#92;frac{1}{2} &#92;int_M &#124;&#92;nabla f&#124;_g^2&#92; d&#92;mu' class='latex' /> (2)</p>
<p>using the inner product <img src='http://s0.wp.com/latex.php?latex=%5Clangle+f_1%2C+f_2+%5Crangle_%5Cmu+%3A%3D+%5Cint_M+f_1+f_2%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;langle f_1, f_2 &#92;rangle_&#92;mu := &#92;int_M f_1 f_2&#92; d&#92;mu' title='&#92;langle f_1, f_2 &#92;rangle_&#92;mu := &#92;int_M f_1 f_2&#92; d&#92;mu' class='latex' /> associated to the volume measure <img src='http://s0.wp.com/latex.php?latex=d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d&#92;mu' title='d&#92;mu' class='latex' />.  Indeed, if we evolve f in time at some arbitrary rate <img src='http://s0.wp.com/latex.php?latex=%5Cdot+f&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;dot f' title='&#92;dot f' class='latex' />, a simple application of integration by parts (equation (29) from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/03/28/285g-lecture-1-ricci-flow/">Lecture 1</a>) gives</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bdt%7D+E%28f%29+%3D+-+%5Cint_M+%28%5CDelta+f%29+%5Cdot+f%5C+d%5Cmu+%3D+%5Clangle+-%5CDelta+f%2C+%5Cdot+f+%5Crangle_%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{dt} E(f) = - &#92;int_M (&#92;Delta f) &#92;dot f&#92; d&#92;mu = &#92;langle -&#92;Delta f, &#92;dot f &#92;rangle_&#92;mu' title='&#92;displaystyle &#92;frac{d}{dt} E(f) = - &#92;int_M (&#92;Delta f) &#92;dot f&#92; d&#92;mu = &#92;langle -&#92;Delta f, &#92;dot f &#92;rangle_&#92;mu' class='latex' /> (3)</p>
<p>from which we see that (1) is indeed the gradient flow for (3) with respect to the inner product.  In particular, if f solves the heat equation (1), we see that the Dirichlet energy is decreasing in time:</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bdt%7D+E%28f%29+%3D+-+%5Cint_M+%26%23124%3B%5CDelta+f%26%23124%3B%5E2%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{dt} E(f) = - &#92;int_M &#124;&#92;Delta f&#124;^2&#92; d&#92;mu' title='&#92;displaystyle &#92;frac{d}{dt} E(f) = - &#92;int_M &#124;&#92;Delta f&#124;^2&#92; d&#92;mu' class='latex' />. (4)</p>
<p>Thus we see that by representing the PDE (1) as a gradient flow, we automatically gain a controlled quantity of the evolution, namely the energy functional that is generating the gradient flow.  This representation also strongly suggests (though does not quite prove) that solutions of (1) should eventually converge to stationary points of the Dirichlet energy (2), which by (3) are just the harmonic functions (i.e. the functions f with <img src='http://s0.wp.com/latex.php?latex=%5CDelta+f+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Delta f = 0' title='&#92;Delta f = 0' class='latex' />).</p>
<p>As one very quick application of the gradient flow interpretation, we can assert that the only periodic (or &#8220;breather&#8221;) solutions to the heat equation (1) are the harmonic functions (which, in fact, must be constant if M is compact, thanks to the maximum principle).  Indeed, if a solution f was periodic, then the monotone functional E must be constant, which by (4) implies that f is harmonic as claimed.</p>
<p>It would therefore be desirable to represent Ricci flow as a gradient flow also, in order to  gain a new controlled quantity, and also to gain some hints as to what the asymptotic behaviour of Ricci flows should be.  It turns out that one cannot quite do this directly (there is an obstruction caused by <em>gradient steady solitons</em>, of which we shall say more later); but Perelman nevertheless observed that one <em>can</em> interpret Ricci flow as gradient flow if one first quotients out the diffeomorphism invariance of the flow.  In fact, there are infinitely many such gradient flow interpretations available.  This fact already allows one to rule out &#8220;breather&#8221; solutions to Ricci flow, and also reveals some information about how <a href="http://en.wikipedia.org/wiki/Poincar%C3%A9_inequality">Poincaré&#8217;s inequality</a> deforms under this flow.</p>
<p>The energy functionals associated to the above interpretations are subcritical (in fact, they are much like <img src='http://s0.wp.com/latex.php?latex=R_%7B%5Cmin%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R_{&#92;min}' title='R_{&#92;min}' class='latex' />) but they are not coercive; Poincaré&#8217;s inequality holds both in collapsed and non-collapsed geometries, and so these functionals are not excluding the former.  However, Perelman discovered a perturbation of these functionals associated to a deeper inequality, the <em>log-Sobolev inequality</em> (first introduced <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=420249">by Gross</a> in Euclidean space).  This inequality <em>is</em> sensitive to volume collapsing at a given scale.  Furthermore, by optimising over the scale parameter, the controlled quantity (now known as the <em>Perelman entropy</em>) becomes scale-invariant and prevents collapsing at any scale &#8211; precisely what is needed to carry out the first phase of the strategy outlined in the <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/20/285g-lecture-7-rescaling-of-ricci-flows-and-kappa-noncollapsing/">previous lecture</a> to establish global existence of Ricci flow with surgery.</p>
<p>The material here is loosely based on <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0211159">Perelman&#8217;s paper</a>, <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0605667">Kleiner-Lott&#8217;s notes</a>, and <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2251315">Müller&#8217;s book</a>.</p>
<p><!--more--></p>
<p style="text-align:center;">&#8211; Ricci flow as gradient flow &#8211;</p>
<p>We would like to represent Ricci flow</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdot+g+%3D+-+2+%5Chbox%7BRic%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;dot g = - 2 &#92;hbox{Ric}' title='&#92;dot g = - 2 &#92;hbox{Ric}' class='latex' /> (5)</p>
<p>as a gradient flow of some functional (with respect to some inner product, or at least with respect to some Riemannian metric on the space of all metrics g).  We will assume that all quantities are smooth and that the manifold is either compact or that all expressions being integrated are rapidly decreasing at infinity (so no boundary terms etc. arise from integration by parts).</p>
<p>To do this, our starting point will be the first variation formula for the scalar curvature R (equation (15) from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/03/28/285g-lecture-1-ricci-flow/">Lecture 1</a>) for an arbitrary instantaneous deformation <img src='http://s0.wp.com/latex.php?latex=%5Cdot+g&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;dot g' title='&#92;dot g' class='latex' /> of the metric g:</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdot+R+%3D+-+%5Chbox%7BRic%7D%5E%7B%5Calpha+%5Cbeta%7D+%5Cdot+g_%7B%5Calpha+%5Cbeta%7D+-+%5CDelta+%5Chbox%7Btr%7D%28%5Cdot+g%29+%2B%5Cnabla%5E%5Calpha+%5Cnabla%5E%5Cbeta+%5Cdot+g_%7B%5Calpha+%5Cbeta%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;dot R = - &#92;hbox{Ric}^{&#92;alpha &#92;beta} &#92;dot g_{&#92;alpha &#92;beta} - &#92;Delta &#92;hbox{tr}(&#92;dot g) +&#92;nabla^&#92;alpha &#92;nabla^&#92;beta &#92;dot g_{&#92;alpha &#92;beta}' title='&#92;dot R = - &#92;hbox{Ric}^{&#92;alpha &#92;beta} &#92;dot g_{&#92;alpha &#92;beta} - &#92;Delta &#92;hbox{tr}(&#92;dot g) +&#92;nabla^&#92;alpha &#92;nabla^&#92;beta &#92;dot g_{&#92;alpha &#92;beta}' class='latex' />. (6)</p>
<p>We can integrate in M to eliminate the latter two terms on the right-hand side (by Stokes theorem, see equation (28) from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/03/28/285g-lecture-1-ricci-flow/">Lecture 1</a>) to get</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cint_M+%5Cdot+R%5C+d%5Cmu+%3D+-+%5Cint_M+%5Chbox%7BRic%7D%5E%7B%5Calpha+%5Cbeta%7D+%5Cdot+g_%7B%5Calpha+%5Cbeta%7D+%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;int_M &#92;dot R&#92; d&#92;mu = - &#92;int_M &#92;hbox{Ric}^{&#92;alpha &#92;beta} &#92;dot g_{&#92;alpha &#92;beta} &#92; d&#92;mu' title='&#92;displaystyle &#92;int_M &#92;dot R&#92; d&#92;mu = - &#92;int_M &#92;hbox{Ric}^{&#92;alpha &#92;beta} &#92;dot g_{&#92;alpha &#92;beta} &#92; d&#92;mu' class='latex' />. (7)</p>
<p>This looks rather promising; it suggests that if we introduce the <a href="http://en.wikipedia.org/wiki/Einstein-Hilbert_action">Einstein-Hilbert functional</a></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+H%28M%2Cg%29+%3A%3D+%5Cint_M+R%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle H(M,g) := &#92;int_M R&#92; d&#92;mu' title='&#92;displaystyle H(M,g) := &#92;int_M R&#92; d&#92;mu' class='latex' /> (8)</p>
<p>then the Ricci flow (5) might be interpretable as a gradient flow for -2H.</p>
<p>Unfortunately, there is a problem because R is not the only time-dependent quantity in the right-hand side of (8); the volume measure <img src='http://s0.wp.com/latex.php?latex=d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d&#92;mu' title='d&#92;mu' class='latex' /> also evolves in time by the formula</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bdt%7D+d%5Cmu+%3D+%5Cfrac%7B1%7D%7B2%7D+%5Chbox%7Btr%7D%28%5Cdot+g%29%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{dt} d&#92;mu = &#92;frac{1}{2} &#92;hbox{tr}(&#92;dot g)&#92; d&#92;mu' title='&#92;displaystyle &#92;frac{d}{dt} d&#92;mu = &#92;frac{1}{2} &#92;hbox{tr}(&#92;dot g)&#92; d&#92;mu' class='latex' /> (9)</p>
<p>(see equation (19) from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/03/28/285g-lecture-1-ricci-flow/">Lecture 1</a>).  Thus, from the product rule, the true variation of the Einstein-Hilbert functional is given by the formula</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bdt%7D+H%28M%2Cg%29+%3D+%5Cint_M+%28-+%5Chbox%7BRic%7D%5E%7B%5Calpha+%5Cbeta%7D+%2B+%5Cfrac%7B1%7D%7B2%7D+R+g%5E%7B%5Calpha+%5Cbeta%7D%29+%5Cdot+g_%7B%5Calpha+%5Cbeta%7D%5C+d%5Cmu.&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{dt} H(M,g) = &#92;int_M (- &#92;hbox{Ric}^{&#92;alpha &#92;beta} + &#92;frac{1}{2} R g^{&#92;alpha &#92;beta}) &#92;dot g_{&#92;alpha &#92;beta}&#92; d&#92;mu.' title='&#92;displaystyle &#92;frac{d}{dt} H(M,g) = &#92;int_M (- &#92;hbox{Ric}^{&#92;alpha &#92;beta} + &#92;frac{1}{2} R g^{&#92;alpha &#92;beta}) &#92;dot g_{&#92;alpha &#92;beta}&#92; d&#92;mu.' class='latex' /> (10)</p>
<p>So the gradient flow of -2H (using the inner product associated to <img src='http://s0.wp.com/latex.php?latex=d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d&#92;mu' title='d&#92;mu' class='latex' />) is not Ricci flow, but is instead a rather strange flow</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdot+g+%3D+-2+%5Chbox%7BRic%7D+%2B+R+g+%3D+-2G&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;dot g = -2 &#92;hbox{Ric} + R g = -2G' title='&#92;dot g = -2 &#92;hbox{Ric} + R g = -2G' class='latex' /> (11)</p>
<p>where <img src='http://s0.wp.com/latex.php?latex=G%3A%3D+%5Chbox%7BRic%7D+-+%5Cfrac%7B1%7D%7B2%7D+R&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='G:= &#92;hbox{Ric} - &#92;frac{1}{2} R' title='G:= &#92;hbox{Ric} - &#92;frac{1}{2} R' class='latex' /> is the <a href="http://en.wikipedia.org/wiki/Einstein_tensor">Einstein tensor</a>.  This flow does not have any particularly nice properties in general (it is not parabolic in three and higher dimensions, even after applying the de Turck trick from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/03/28/285g-lecture-1-ricci-flow/">Lecture 1</a>).  On the other hand, in two dimensions the right-hand side of (10) vanishes and H(M,g) becomes invariant under deformations (we have already exploited this fact to prove the <a href="http://en.wikipedia.org/wiki/Gauss%E2%80%93Bonnet_theorem">Gauss-Bonnet formula</a>, see Proposition 1 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/11/285g-lecture-4-finite-time-extinction-of-the-second-homotopy-group/">Lecture 4</a>).  More generally, we recover see from (10) the fact (well known in general relativity) that the (formal) stationary points of the Einstein-Hilbert functional are precisely the solutions of the vacuum <a href="http://en.wikipedia.org/wiki/Einstein_field_equations">Einstein equations</a> <img src='http://s0.wp.com/latex.php?latex=G%3D0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='G=0' title='G=0' class='latex' /> (or equivalently, <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRic%7D%3D0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Ric}=0' title='&#92;hbox{Ric}=0' class='latex' /> in any dimension other than 2).</p>
<p>We see that the variation of the measure <img src='http://s0.wp.com/latex.php?latex=d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d&#92;mu' title='d&#92;mu' class='latex' /> in time is causing us some difficulty.  To fix this problem, let us take the (rather non-geometric looking) step of replacing this evolving measure <img src='http://s0.wp.com/latex.php?latex=d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d&#92;mu' title='d&#92;mu' class='latex' /> by some static measure <img src='http://s0.wp.com/latex.php?latex=dm&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='dm' title='dm' class='latex' /> which we select in advance, and consider instead the variation of the functional <img src='http://s0.wp.com/latex.php?latex=%5Cint_M+R%5C+dm&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_M R&#92; dm' title='&#92;int_M R&#92; dm' class='latex' /> with respect to some arbitrary perturbation <img src='http://s0.wp.com/latex.php?latex=%5Cdot+g&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;dot g' title='&#92;dot g' class='latex' />.  Now that m is static, we can apply (6) to get</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bdt%7D+%5Cint_M+R%5C+dm+%3D+%5Cint_M+%28-+%5Chbox%7BRic%7D%5E%7B%5Calpha+%5Cbeta%7D+%5Cdot+g_%7B%5Calpha+%5Cbeta%7D+-+%5CDelta+%5Chbox%7Btr%7D%28%5Cdot+g%29+%2B%5Cnabla%5E%5Calpha+%5Cnabla%5E%5Cbeta+%5Cdot+g_%7B%5Calpha+%5Cbeta%7D%29%5C+dm&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{dt} &#92;int_M R&#92; dm = &#92;int_M (- &#92;hbox{Ric}^{&#92;alpha &#92;beta} &#92;dot g_{&#92;alpha &#92;beta} - &#92;Delta &#92;hbox{tr}(&#92;dot g) +&#92;nabla^&#92;alpha &#92;nabla^&#92;beta &#92;dot g_{&#92;alpha &#92;beta})&#92; dm' title='&#92;displaystyle &#92;frac{d}{dt} &#92;int_M R&#92; dm = &#92;int_M (- &#92;hbox{Ric}^{&#92;alpha &#92;beta} &#92;dot g_{&#92;alpha &#92;beta} - &#92;Delta &#92;hbox{tr}(&#92;dot g) +&#92;nabla^&#92;alpha &#92;nabla^&#92;beta &#92;dot g_{&#92;alpha &#92;beta})&#92; dm' class='latex' />. (12)</p>
<p>Previously, we used Stokes&#8217; theorem to eliminate the latter two terms on the right-hand side to leave us with the one term <img src='http://s0.wp.com/latex.php?latex=%5Cint_M+%5Chbox%7BRic%7D%5E%7B%5Calpha+%5Cbeta%7D+%5Cdot+g_%7B%5Calpha+%5Cbeta%7D%5C+dm&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_M &#92;hbox{Ric}^{&#92;alpha &#92;beta} &#92;dot g_{&#92;alpha &#92;beta}&#92; dm' title='&#92;int_M &#92;hbox{Ric}^{&#92;alpha &#92;beta} &#92;dot g_{&#92;alpha &#92;beta}&#92; dm' class='latex' /> that we do want.  Unfortunately, Stokes&#8217; theorem only applies for the volume measure <img src='http://s0.wp.com/latex.php?latex=d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d&#92;mu' title='d&#92;mu' class='latex' />, not for our static measure <img src='http://s0.wp.com/latex.php?latex=dm&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='dm' title='dm' class='latex' />!  In order to apply Stokes&#8217; theorem, we must therefore convert the static measure back to volume measure.  The <a href="http://en.wikipedia.org/wiki/Radon-Nikodym_derivative">Radon-Nikodym derivative</a> <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bd%5Cmu%7D%7Bdm%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{d&#92;mu}{dm}' title='&#92;frac{d&#92;mu}{dm}' class='latex' /> of the two measures should be some positive function, which we shall denote by <img src='http://s0.wp.com/latex.php?latex=e%5Ef&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='e^f' title='e^f' class='latex' /> for some scalar (and time-varying) function <img src='http://s0.wp.com/latex.php?latex=f%3A+M+%5Cto+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='f: M &#92;to {&#92;Bbb R}' title='f: M &#92;to {&#92;Bbb R}' class='latex' />, thus</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=dm+%3D+e%5E%7B-f%7D+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='dm = e^{-f} d&#92;mu' title='dm = e^{-f} d&#92;mu' class='latex' />. (13)</p>
<p>Inserting (13) into (12), integrating by parts using the volume measure <img src='http://s0.wp.com/latex.php?latex=d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d&#92;mu' title='d&#92;mu' class='latex' />, and then using (13) again to convert back to the static measure <img src='http://s0.wp.com/latex.php?latex=dm&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='dm' title='dm' class='latex' />, we see after a little calculation that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cint_M+%5CDelta+%5Chbox%7Btr%7D%28%5Cdot+g%29%5C+dm+%3D+%5Cint_M+%28+%26%23124%3B%5Cnabla+f%26%23124%3B_g%5E2+-+%5CDelta+f%29+%5Chbox%7Btr%7D%28%5Cdot+g%29%5C+dm&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;int_M &#92;Delta &#92;hbox{tr}(&#92;dot g)&#92; dm = &#92;int_M ( &#124;&#92;nabla f&#124;_g^2 - &#92;Delta f) &#92;hbox{tr}(&#92;dot g)&#92; dm' title='&#92;displaystyle &#92;int_M &#92;Delta &#92;hbox{tr}(&#92;dot g)&#92; dm = &#92;int_M ( &#124;&#92;nabla f&#124;_g^2 - &#92;Delta f) &#92;hbox{tr}(&#92;dot g)&#92; dm' class='latex' /> (14)</p>
<p>and similarly</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cint_M+%5Cnabla%5E%5Calpha+%5Cnabla%5E%5Cbeta+%5Cdot+g_%7B%5Calpha+%5Cbeta%7D%5C+dm+%3D+%5Cint_M+%28+%28%5Cnabla%5E%5Calpha+f%29+%28%5Cnabla%5E%5Cbeta+g%29+-+%5Cnabla%5E%7B%5Calpha%7D+%5Cnabla%5E%7B%5Cbeta%7D+f%29+%5Cdot+g_%7B%5Calpha+%5Cbeta%7D+%5C+dm&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;int_M &#92;nabla^&#92;alpha &#92;nabla^&#92;beta &#92;dot g_{&#92;alpha &#92;beta}&#92; dm = &#92;int_M ( (&#92;nabla^&#92;alpha f) (&#92;nabla^&#92;beta g) - &#92;nabla^{&#92;alpha} &#92;nabla^{&#92;beta} f) &#92;dot g_{&#92;alpha &#92;beta} &#92; dm' title='&#92;displaystyle &#92;int_M &#92;nabla^&#92;alpha &#92;nabla^&#92;beta &#92;dot g_{&#92;alpha &#92;beta}&#92; dm = &#92;int_M ( (&#92;nabla^&#92;alpha f) (&#92;nabla^&#92;beta g) - &#92;nabla^{&#92;alpha} &#92;nabla^{&#92;beta} f) &#92;dot g_{&#92;alpha &#92;beta} &#92; dm' class='latex' /> (15)</p>
<p style="text-align:left;">and so we can express the right-hand side of (12) as</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Clangle+-%5Chbox%7BRic%7D%5E%7B%5Calpha+%5Cbeta%7D+-+%28%26%23124%3B%5Cnabla+f%26%23124%3B_g%5E2+-+%5CDelta+f%29+g%5E%7B%5Calpha+%5Cbeta%7D+%2B+++%28%5Cnabla%5E%5Calpha+f%29+%28%5Cnabla%5E%5Cbeta+f%29+-+%5Cnabla%5E%7B%5Calpha%7D+%5Cnabla%5E%7B%5Cbeta%7D+f%2C+%5Cdot+g_%7B%5Calpha+%5Cbeta%7D+%5Crangle_m&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;langle -&#92;hbox{Ric}^{&#92;alpha &#92;beta} - (&#124;&#92;nabla f&#124;_g^2 - &#92;Delta f) g^{&#92;alpha &#92;beta} +   (&#92;nabla^&#92;alpha f) (&#92;nabla^&#92;beta f) - &#92;nabla^{&#92;alpha} &#92;nabla^{&#92;beta} f, &#92;dot g_{&#92;alpha &#92;beta} &#92;rangle_m' title='&#92;langle -&#92;hbox{Ric}^{&#92;alpha &#92;beta} - (&#124;&#92;nabla f&#124;_g^2 - &#92;Delta f) g^{&#92;alpha &#92;beta} +   (&#92;nabla^&#92;alpha f) (&#92;nabla^&#92;beta f) - &#92;nabla^{&#92;alpha} &#92;nabla^{&#92;beta} f, &#92;dot g_{&#92;alpha &#92;beta} &#92;rangle_m' class='latex' />. (16)</p>
<p style="text-align:left;">This looks rather unpleasant; we managed to eradicate the scalar curvature term <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B1%7D%7B2%7D+R&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{1}{2} R' title='&#92;frac{1}{2} R' class='latex' /> that was present in the variation in (10), but at the cost of introducing four new terms involving f.  But to deal with this, first observe from differentiating (13) and using (9) and the static nature of dm that we know the first variation of f:</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdot+f+%3D+%5Cfrac%7B1%7D%7B2%7D+%5Chbox%7Btr%7D%28%5Cdot+g%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;dot f = &#92;frac{1}{2} &#92;hbox{tr}(&#92;dot g)' title='&#92;dot f = &#92;frac{1}{2} &#92;hbox{tr}(&#92;dot g)' class='latex' />. (17)</p>
<p style="text-align:left;">So the term <img src='http://s0.wp.com/latex.php?latex=%5Clangle+%5CDelta+f+g%5E%7B%5Calpha+%5Cbeta%7D%2C+%5Cdot+g_%7B%5Calpha+%5Cbeta%7D+%5Crangle_m&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;langle &#92;Delta f g^{&#92;alpha &#92;beta}, &#92;dot g_{&#92;alpha &#92;beta} &#92;rangle_m' title='&#92;langle &#92;Delta f g^{&#92;alpha &#92;beta}, &#92;dot g_{&#92;alpha &#92;beta} &#92;rangle_m' class='latex' /> that appears in (16) can be rewritten as <img src='http://s0.wp.com/latex.php?latex=2+%5Cint_M+%28%5CDelta+f%29+%5Cdot+f%5C+dm&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='2 &#92;int_M (&#92;Delta f) &#92;dot f&#92; dm' title='2 &#92;int_M (&#92;Delta f) &#92;dot f&#92; dm' class='latex' />.  Now this term looks familiar&#8230; in fact, it essentially the variation (3) of the Dirichlet energy functional for the measure dm!  This suggests that we may be able to simplify (16) if we modify our functional <img src='http://s0.wp.com/latex.php?latex=%5Cint_M+R%5C+dm&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_M R&#92; dm' title='&#92;int_M R&#92; dm' class='latex' /> by adding some multiple of the Dirichlet functional <img src='http://s0.wp.com/latex.php?latex=E+%3A%3D+%5Cfrac%7B1%7D%7B2%7D+%5Cint_M+%26%23124%3B%5Cnabla+f%26%23124%3B_g%5E2%5C+dm&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='E := &#92;frac{1}{2} &#92;int_M &#124;&#92;nabla f&#124;_g^2&#92; dm' title='E := &#92;frac{1}{2} &#92;int_M &#124;&#92;nabla f&#124;_g^2&#92; dm' class='latex' />.</p>
<p style="text-align:left;">One cannot apply (3) directly, though, because (a) g is evolving in time, rather than static, and also (b) dm is not the volume measure for g.  But we have all the equations to deal with this, and one can compute the first variation of E:</p>
<p style="text-align:left;"><strong>Exercise 1. </strong>Show that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bdt%7D+E+%3D+-+%5Cfrac%7B1%7D%7B2%7D+%5Clangle+%5CDelta+f+g%5E%7B%5Calpha+%5Cbeta%7D+-+%26%23124%3B%5Cnabla+f%26%23124%3B_g%5E2+g%5E%7B%5Calpha+%5Cbeta%7D+%2B+%28%5Cnabla+f%29%5E%5Calpha+%28%5Cnabla+f%29%5E%7B%5Cbeta%7D%2C++%5Cdot+g_%7B%5Calpha+%5Cbeta%7D+%5Crangle_m&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{dt} E = - &#92;frac{1}{2} &#92;langle &#92;Delta f g^{&#92;alpha &#92;beta} - &#124;&#92;nabla f&#124;_g^2 g^{&#92;alpha &#92;beta} + (&#92;nabla f)^&#92;alpha (&#92;nabla f)^{&#92;beta},  &#92;dot g_{&#92;alpha &#92;beta} &#92;rangle_m' title='&#92;displaystyle &#92;frac{d}{dt} E = - &#92;frac{1}{2} &#92;langle &#92;Delta f g^{&#92;alpha &#92;beta} - &#124;&#92;nabla f&#124;_g^2 g^{&#92;alpha &#92;beta} + (&#92;nabla f)^&#92;alpha (&#92;nabla f)^{&#92;beta},  &#92;dot g_{&#92;alpha &#92;beta} &#92;rangle_m' class='latex' />. (18)</p>
<p style="text-align:left;">(Hint: expand out <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Cnabla+f%26%23124%3B_g%5E2+%3D+g%5E%7B%5Calpha+%5Cbeta%7D+%28%5Cnabla_%5Calpha+f%29+%28%5Cnabla_%5Cbeta+f%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;nabla f&#124;_g^2 = g^{&#92;alpha &#92;beta} (&#92;nabla_&#92;alpha f) (&#92;nabla_&#92;beta f)' title='&#124;&#92;nabla f&#124;_g^2 = g^{&#92;alpha &#92;beta} (&#92;nabla_&#92;alpha f) (&#92;nabla_&#92;beta f)' class='latex' /> and use (3) from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/03/28/285g-lecture-1-ricci-flow/">Lecture 1</a>.) <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;">If we thus define the functional</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%7B%5Cmathcal+F%7D_m%28+M%2C+g+%29+%3A%3D+%5Cint_M+%28R+%2B+%26%23124%3B%5Cnabla+f%26%23124%3B%5E2%29%5C+dm&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle {&#92;mathcal F}_m( M, g ) := &#92;int_M (R + &#124;&#92;nabla f&#124;^2)&#92; dm' title='&#92;displaystyle {&#92;mathcal F}_m( M, g ) := &#92;int_M (R + &#124;&#92;nabla f&#124;^2)&#92; dm' class='latex' /> (19)</p>
<p style="text-align:left;">we see from (16), (18) that we get a lot of cancellation, ending up with</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bdt%7D+%7B%5Cmathcal+F%7D_m%28+M%2C+g+%29+%3D+-+%5Clangle+%5Chbox%7BRic%7D%5E%7B%5Calpha+%5Cbeta%7D+%2B+%5Cnabla%5E%7B%5Calpha%7D+%5Cnabla%5E%7B%5Cbeta%7D+f%2C+%5Cdot+g_%7B%5Calpha+%5Cbeta%7D+%5Crangle_m&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{dt} {&#92;mathcal F}_m( M, g ) = - &#92;langle &#92;hbox{Ric}^{&#92;alpha &#92;beta} + &#92;nabla^{&#92;alpha} &#92;nabla^{&#92;beta} f, &#92;dot g_{&#92;alpha &#92;beta} &#92;rangle_m' title='&#92;displaystyle &#92;frac{d}{dt} {&#92;mathcal F}_m( M, g ) = - &#92;langle &#92;hbox{Ric}^{&#92;alpha &#92;beta} + &#92;nabla^{&#92;alpha} &#92;nabla^{&#92;beta} f, &#92;dot g_{&#92;alpha &#92;beta} &#92;rangle_m' class='latex' />. (20)</p>
<p>Thus the gradient flow of <img src='http://s0.wp.com/latex.php?latex=-2%7B%5Cmathcal+F%7D_m%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='-2{&#92;mathcal F}_m(M,g)' title='-2{&#92;mathcal F}_m(M,g)' class='latex' /> with respect to the inner product <img src='http://s0.wp.com/latex.php?latex=%5Clangle+h%2C+k+%5Crangle_m+%3A%3D+%5Cint_M+h%5E%7B%5Calpha+%5Cbeta%7D+k_%7B%5Calpha+%5Cbeta%7D%5C+dm&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;langle h, k &#92;rangle_m := &#92;int_M h^{&#92;alpha &#92;beta} k_{&#92;alpha &#92;beta}&#92; dm' title='&#92;langle h, k &#92;rangle_m := &#92;int_M h^{&#92;alpha &#92;beta} k_{&#92;alpha &#92;beta}&#92; dm' class='latex' /> on symmetric two-forms (or more precisely, on the tangent space of such forms at g) is given by</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdot+g_%7B%5Calpha+%5Cbeta%7D+%3D+-+2+%5Chbox%7BRic%7D_%7B%5Calpha+%5Cbeta%7D+-+2+%5Cnabla_%7B%5Calpha%7D+%5Cnabla_%7B%5Cbeta%7D+f&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;dot g_{&#92;alpha &#92;beta} = - 2 &#92;hbox{Ric}_{&#92;alpha &#92;beta} - 2 &#92;nabla_{&#92;alpha} &#92;nabla_{&#92;beta} f' title='&#92;dot g_{&#92;alpha &#92;beta} = - 2 &#92;hbox{Ric}_{&#92;alpha &#92;beta} - 2 &#92;nabla_{&#92;alpha} &#92;nabla_{&#92;beta} f' class='latex' />. (21)</p>
<p style="text-align:left;">From (17) we see that f now evolves by a backward heat equation</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdot+f+%3D+-+%5CDelta+f+-+R&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;dot f = - &#92;Delta f - R' title='&#92;dot f = - &#92;Delta f - R' class='latex' />. (22)</p>
<p style="text-align:left;">With this flow, we see that <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+F%7D_m&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal F}_m' title='{&#92;mathcal F}_m' class='latex' /> is monotone increasing, with</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bdt%7D+%7B%5Cmathcal+F%7D_m+%3D+2+%5Cint_M+%26%23124%3B%5Chbox%7BRic%7D+%2B+%5Chbox%7BHess%7D%28f%29%26%23124%3B%5E2%5C+dm&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{dt} {&#92;mathcal F}_m = 2 &#92;int_M &#124;&#92;hbox{Ric} + &#92;hbox{Hess}(f)&#124;^2&#92; dm' title='&#92;displaystyle &#92;frac{d}{dt} {&#92;mathcal F}_m = 2 &#92;int_M &#124;&#92;hbox{Ric} + &#92;hbox{Hess}(f)&#124;^2&#92; dm' class='latex' />. (23)</p>
<p style="text-align:left;">The equation (21) is<em> almost</em> Ricci flow (5), but with one additional term associated with f. But we can observe (using equation (25) from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/03/28/285g-lecture-1-ricci-flow/">Lecture 1</a>) that <img src='http://s0.wp.com/latex.php?latex=2%5Cnabla_%7B%5Calpha%7D+%5Cnabla_%7B%5Cbeta%7D+f+%3D+%7B%5Cmathcal+L%7D_%7B%5Cnabla+f%7D+g_%7B%5Calpha+%5Cbeta%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='2&#92;nabla_{&#92;alpha} &#92;nabla_{&#92;beta} f = {&#92;mathcal L}_{&#92;nabla f} g_{&#92;alpha &#92;beta}' title='2&#92;nabla_{&#92;alpha} &#92;nabla_{&#92;beta} f = {&#92;mathcal L}_{&#92;nabla f} g_{&#92;alpha &#92;beta}' class='latex' /> is just the Lie derivative of g in the direction of the gradient vector field <img src='http://s0.wp.com/latex.php?latex=%5Cnabla%5E%5Cgamma+f&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla^&#92;gamma f' title='&#92;nabla^&#92;gamma f' class='latex' />.  Thus we see that (23) is a modified Ricci flow (see equation (36) from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/03/28/285g-lecture-1-ricci-flow/">Lecture 1</a>), which is conjugate to genuine Ricci flow by a diffeomorphism as discussed in that lecture.  Thus while we have not established Ricci flow as a gradient flow directly, we have managed to find a whole family of gradient flows (parameterised by a choice of static measure dm, or equivalently by a choice of potential function f evolving by (17)) which are equivalent to Ricci flow modulo diffeomorphism.  (Indeed, by placing an appropriate Riemannian structure on the moduli space of metrics modulo diffeomorphism, one can express Ricci flow modulo diffeomorphism as a true (formal) gradient flow; see Section 9 of the <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0605667">Kleiner-Lott notes</a>.)  As remarked in <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0211159">Perelman&#8217;s paper</a>, one can view f as a kind of gauge function for the Ricci flow.</p>
<p style="text-align:left;"><strong>Example 1.</strong> If (M,g) is a Euclidean space <img src='http://s0.wp.com/latex.php?latex=M+%3D+%7B%5CBbb+R%7D%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M = {&#92;Bbb R}^d' title='M = {&#92;Bbb R}^d' class='latex' /> with the contracted Euclidean metric <img src='http://s0.wp.com/latex.php?latex=g+%3D+%5Cfrac%7B%5Ctau%7D%7Bt_0%7D+%5Ceta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='g = &#92;frac{&#92;tau}{t_0} &#92;eta' title='g = &#92;frac{&#92;tau}{t_0} &#92;eta' class='latex' /> for times <img src='http://s0.wp.com/latex.php?latex=0+%5Cleq+t+%26%2360%3B+t_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &#92;leq t &lt; t_0' title='0 &#92;leq t &lt; t_0' class='latex' />, where <img src='http://s0.wp.com/latex.php?latex=%5Ctau+%3A%3D+t_0+-+t&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau := t_0 - t' title='&#92;tau := t_0 - t' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Ceta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;eta' title='&#92;eta' class='latex' /> is the standard metric, with <img src='http://s0.wp.com/latex.php?latex=dm&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='dm' title='dm' class='latex' /> equal to the Gaussian measure <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B1%7D%7B%284%5Cpi+t_0%29%5E%7Bd%2F2%7D%7D+e%5E%7B-%26%23124%3Bx%26%23124%3B%5E2%2F4t_0%7D%5C+dx&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{1}{(4&#92;pi t_0)^{d/2}} e^{-&#124;x&#124;^2/4t_0}&#92; dx' title='&#92;frac{1}{(4&#92;pi t_0)^{d/2}} e^{-&#124;x&#124;^2/4t_0}&#92; dx' class='latex' /> (thus <img src='http://s0.wp.com/latex.php?latex=f%28t%2Cx%29+%3D+%5Cfrac%7B%26%23124%3Bx%26%23124%3B%5E2%7D%7B4t_0%7D+%2B+%5Cfrac%7Bd%7D%7B2%7D+%5Clog%284%5Cpi+%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='f(t,x) = &#92;frac{&#124;x&#124;^2}{4t_0} + &#92;frac{d}{2} &#92;log(4&#92;pi &#92;tau)' title='f(t,x) = &#92;frac{&#124;x&#124;^2}{4t_0} + &#92;frac{d}{2} &#92;log(4&#92;pi &#92;tau)' class='latex' />), then g, f solve (21), (22). (One has to be a bit careful here because M is non-compact, of course.) <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;">We can of course conjugate away the infinitesimal diffeomorphism given by the vector field <img src='http://s0.wp.com/latex.php?latex=%5Cnabla+f&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla f' title='&#92;nabla f' class='latex' />, which converts the system (21), (22) to the system</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdot+g+%3D+-2%5Chbox%7BRic%7D%3B+%5Cquad+%5Cdot+f+%3D+-%5CDelta+f+%2B+%26%23124%3B%5Cnabla+f%26%23124%3B_g%5E2+-+R&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;dot g = -2&#92;hbox{Ric}; &#92;quad &#92;dot f = -&#92;Delta f + &#124;&#92;nabla f&#124;_g^2 - R' title='&#92;dot g = -2&#92;hbox{Ric}; &#92;quad &#92;dot f = -&#92;Delta f + &#124;&#92;nabla f&#124;_g^2 - R' class='latex' /> (24)</p>
<p style="text-align:left;">(here we use the fact that <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D_%7B%5Cnabla+f%7D+f+%3D+%26%23124%3B%5Cnabla+f%26%23124%3B_g%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}_{&#92;nabla f} f = &#124;&#92;nabla f&#124;_g^2' title='{&#92;mathcal L}_{&#92;nabla f} f = &#124;&#92;nabla f&#124;_g^2' class='latex' />), which is Ricci flow coupled with a nonlinear backwards heat equation for the potential f.  (Note that the equation for f is not always solvable forwards in time for any non-zero amount of time, but we can always solve it instantaneously for a fixed time, which is good enough for first variation analysis.)  The non-linear backwards heat equation equation for f can be linearised by setting <img src='http://s0.wp.com/latex.php?latex=u+%3A%3D+e%5E%7B-f%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u := e^{-f}' title='u := e^{-f}' class='latex' />, in which case it becomes the <em>adjoint heat equation</em></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdot+u+%3D+-+%5CDelta+u+%2B+R+u&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;dot u = - &#92;Delta u + R u' title='&#92;dot u = - &#92;Delta u + R u' class='latex' />. (24&#8242;)</p>
<p style="text-align:left;"><strong>Exercise 2. </strong>Writing <img src='http://s0.wp.com/latex.php?latex=dm+%3A%3D+u+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='dm := u d&#92;mu' title='dm := u d&#92;mu' class='latex' />, show that (24&#8242;) is equivalent to the equation</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bd%7D%7Bdt%7D+dm+%3D+-+%5CDelta+dm&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{d}{dt} dm = - &#92;Delta dm' title='&#92;frac{d}{dt} dm = - &#92;Delta dm' class='latex' /> (24&#8221;)</p>
<p style="text-align:left;">where <img src='http://s0.wp.com/latex.php?latex=dm&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='dm' title='dm' class='latex' /> is viewed as a d-form for the purposes of applying the Laplacian.  Thus the adjoint heat equation can be viewed as the backwards heat equation for d-forms. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;"><strong>Example 2.</strong> If (M,g) is a static Euclidean space <img src='http://s0.wp.com/latex.php?latex=M+%3D+%7B%5CBbb+R%7D%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M = {&#92;Bbb R}^d' title='M = {&#92;Bbb R}^d' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=f%28t%2Cx%29+%3D+%5Cfrac%7B%26%23124%3Bx%26%23124%3B%5E2%7D%7B4%5Ctau%7D+%2B+%5Cfrac%7Bd%7D%7B2%7D+%5Clog%284%5Cpi+%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='f(t,x) = &#92;frac{&#124;x&#124;^2}{4&#92;tau} + &#92;frac{d}{2} &#92;log(4&#92;pi &#92;tau)' title='f(t,x) = &#92;frac{&#124;x&#124;^2}{4&#92;tau} + &#92;frac{d}{2} &#92;log(4&#92;pi &#92;tau)' class='latex' /> with <img src='http://s0.wp.com/latex.php?latex=%5Ctau+%3D+t_0+-+t&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau = t_0 - t' title='&#92;tau = t_0 - t' class='latex' /> and the time variable t is restricted to be less than <img src='http://s0.wp.com/latex.php?latex=t_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_0' title='t_0' class='latex' />, then g, f solve (24), and <img src='http://s0.wp.com/latex.php?latex=dm+%3D+e%5E%7B-f%7D+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='dm = e^{-f} d&#92;mu' title='dm = e^{-f} d&#92;mu' class='latex' /> is the Gaussian measure <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B1%7D%7B%284%5Cpi+%5Ctau%29%5E%7Bd%2F2%7D%7D+e%5E%7B-%26%23124%3Bx%26%23124%3B%5E2%2F4%5Ctau%7D%5C+dx&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{1}{(4&#92;pi &#92;tau)^{d/2}} e^{-&#124;x&#124;^2/4&#92;tau}&#92; dx' title='&#92;frac{1}{(4&#92;pi &#92;tau)^{d/2}} e^{-&#124;x&#124;^2/4&#92;tau}&#92; dx' class='latex' />, which solves the backwards heat equation. Note that this is the conjugated version of Example 1. Again, one needs to take care because M is non-compact. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;">By performing this conjugation, the measure m is no longer static, and we reflect this by changing the notation a little to</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%7B%5Cmathcal+F%7D%28M%2C+g%2C+f%29+%3A%3D+%7B%5Cmathcal+F%7D_%7Be%5E%7B-f%7D+%5Cmu%7D%28M%2Cg%29+%3D+%5Cint_M+%28%26%23124%3B%5Cnabla+f%26%23124%3B%5E2+%2B+R%29+e%5E%7B-f%7D%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle {&#92;mathcal F}(M, g, f) := {&#92;mathcal F}_{e^{-f} &#92;mu}(M,g) = &#92;int_M (&#124;&#92;nabla f&#124;^2 + R) e^{-f}&#92; d&#92;mu' title='&#92;displaystyle {&#92;mathcal F}(M, g, f) := {&#92;mathcal F}_{e^{-f} &#92;mu}(M,g) = &#92;int_M (&#124;&#92;nabla f&#124;^2 + R) e^{-f}&#92; d&#92;mu' class='latex' />. (25)</p>
<p style="text-align:left;">The relationship between <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+F%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal F}' title='{&#92;mathcal F}' class='latex' /> and the flow (24) is analogous to that between <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+F%7D_m&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal F}_m' title='{&#92;mathcal F}_m' class='latex' /> and (21), (22).  For instance, we have the following analogue of (23):</p>
<p style="text-align:left;"><strong>Exercise 3. </strong> If g, f solve (24), show that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bdt%7D+%7B%5Cmathcal+F%7D%28M%2C+g%2C+f%29+%3D+2+%5Cint_M+%26%23124%3B%5Chbox%7BRic%7D+%2B+%5Chbox%7BHess%7D%28f%29%26%23124%3B%5E2+e%5E%7B-f%7D%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{dt} {&#92;mathcal F}(M, g, f) = 2 &#92;int_M &#124;&#92;hbox{Ric} + &#92;hbox{Hess}(f)&#124;^2 e^{-f}&#92; d&#92;mu' title='&#92;displaystyle &#92;frac{d}{dt} {&#92;mathcal F}(M, g, f) = 2 &#92;int_M &#124;&#92;hbox{Ric} + &#92;hbox{Hess}(f)&#124;^2 e^{-f}&#92; d&#92;mu' class='latex' />. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /> (26)</p>
<p style="text-align:left;">Thus <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+F%7D%28M%2Cg%2Cf%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal F}(M,g,f)' title='{&#92;mathcal F}(M,g,f)' class='latex' /> is monotone non-decreasing in time.  We would like to use this to develop a controlled quantity for Ricci flow, but we need to eliminate f.  This can be accomplished by taking an infimum, defining</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Clambda%28M%2Cg%29+%3A%3D+%5Cinf_%7Bf%3A+%5Cint_M+e%5E%7B-f%7D%5C+d%5Cmu+%3D+1%7D+%7B%5Cmathcal+F%7D%28M%2Cg%2Cf%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;lambda(M,g) := &#92;inf_{f: &#92;int_M e^{-f}&#92; d&#92;mu = 1} {&#92;mathcal F}(M,g,f)' title='&#92;displaystyle &#92;lambda(M,g) := &#92;inf_{f: &#92;int_M e^{-f}&#92; d&#92;mu = 1} {&#92;mathcal F}(M,g,f)' class='latex' />. (27)</p>
<p style="text-align:left;">The normalisation <img src='http://s0.wp.com/latex.php?latex=%5Cint_M+e%5E%7B-f%7D%5C+d%5Cmu+%3D+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_M e^{-f}&#92; d&#92;mu = 1' title='&#92;int_M e^{-f}&#92; d&#92;mu = 1' class='latex' /> (which makes dm a probability measure) is needed to ensure a meaningful infimum; note that this normalisation is preserved by the flow (24) since dm is only moved around by diffeomorphisms.  This quantity has an interpretation as the best constant in a Poincaré inequality:</p>
<p style="text-align:left;"><strong>Exercise 4.</strong> Show that <img src='http://s0.wp.com/latex.php?latex=%5Clambda%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;lambda(M,g)' title='&#92;lambda(M,g)' class='latex' /> is the least number for which one has the inequality</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cint_M+4+%26%23124%3B%5Cnabla+u%26%23124%3B_g%5E2+%2B+R%26%23124%3Bu%26%23124%3B%5E2%5C+d%5Cmu+%5Cgeq+%5Clambda%28M%2Cg%29+%5Cint_M+%26%23124%3Bu%26%23124%3B%5E2%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;int_M 4 &#124;&#92;nabla u&#124;_g^2 + R&#124;u&#124;^2&#92; d&#92;mu &#92;geq &#92;lambda(M,g) &#92;int_M &#124;u&#124;^2&#92; d&#92;mu' title='&#92;displaystyle &#92;int_M 4 &#124;&#92;nabla u&#124;_g^2 + R&#124;u&#124;^2&#92; d&#92;mu &#92;geq &#92;lambda(M,g) &#92;int_M &#124;u&#124;^2&#92; d&#92;mu' class='latex' /> (28)</p>
<p style="text-align:left;">for all <img src='http://s0.wp.com/latex.php?latex=u&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u' title='u' class='latex' /> in the <a href="http://en.wikipedia.org/wiki/Sobolev_space">Sobolev space</a> <img src='http://s0.wp.com/latex.php?latex=H%5E1%28M%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='H^1(M)' title='H^1(M)' class='latex' />.  (<em>Hint</em>: reduce to the case when u is positive and smooth and then make the substitution <img src='http://s0.wp.com/latex.php?latex=u+%3D+e%5E%7B-f%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u = e^{-f/2}' title='u = e^{-f/2}' class='latex' />.) Conclude in particular that <img src='http://s0.wp.com/latex.php?latex=%5Clambda%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;lambda(M,g)' title='&#92;lambda(M,g)' class='latex' /> is finite, that it is the least eigenvalue of the self-adjoint modified Laplacian <img src='http://s0.wp.com/latex.php?latex=-4%5CDelta+%2B+4R&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='-4&#92;Delta + 4R' title='-4&#92;Delta + 4R' class='latex' />, and lies between <img src='http://s0.wp.com/latex.php?latex=R_%7B%5Cmin%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R_{&#92;min}' title='R_{&#92;min}' class='latex' /> and the average scalar curvature <img src='http://s0.wp.com/latex.php?latex=%5Coverline%7BR%7D+%3A%3D+%5Cint_M+R%5C+d%5Cmu+%2F+%5Cint_M%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;overline{R} := &#92;int_M R&#92; d&#92;mu / &#92;int_M&#92; d&#92;mu' title='&#92;overline{R} := &#92;int_M R&#92; d&#92;mu / &#92;int_M&#92; d&#92;mu' class='latex' />. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;">A variational argument (using the standard fact that <img src='http://s0.wp.com/latex.php?latex=H%5E1%28M%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='H^1(M)' title='H^1(M)' class='latex' /> embeds compactly into <img src='http://s0.wp.com/latex.php?latex=L%5E2%28M%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='L^2(M)' title='L^2(M)' class='latex' />) shows that equality in (28) is attained by some strictly positive <img src='http://s0.wp.com/latex.php?latex=u+%3D+e%5E%7B-f%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u = e^{-f/2}' title='u = e^{-f/2}' class='latex' /> with norm <img src='http://s0.wp.com/latex.php?latex=%5Cint_M+%26%23124%3Bu%26%23124%3B%5E2%5C+d%5Cmu+%3D+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_M &#124;u&#124;^2&#92; d&#92;mu = 1' title='&#92;int_M &#124;u&#124;^2&#92; d&#92;mu = 1' class='latex' />, and so the infimum in (27) is also attained for some f.  Applying the flow (24) instantaneously at a given time, we conclude (formally, at least) that we have the monotonicity formula</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bdt%7D+%5Clambda%28M%2Cg%29+%3D+2+%5Cint_M+%26%23124%3B%5Chbox%7BRic%7D+%2B+%5Chbox%7BHess%7D%28f%29%26%23124%3B%5E2+e%5E%7B-f%7D%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{dt} &#92;lambda(M,g) = 2 &#92;int_M &#124;&#92;hbox{Ric} + &#92;hbox{Hess}(f)&#124;^2 e^{-f}&#92; d&#92;mu' title='&#92;displaystyle &#92;frac{d}{dt} &#92;lambda(M,g) = 2 &#92;int_M &#124;&#92;hbox{Ric} + &#92;hbox{Hess}(f)&#124;^2 e^{-f}&#92; d&#92;mu' class='latex' /> (29)</p>
<p style="text-align:left;">for any solution to Ricci flow (5), where f is the extremiser for (27) (note that this extremiser f need not evolve via (25)).  (One can in fact make this formula rigorous whenever the Ricci flow is smooth and M is compact, but we will not detail this here.)</p>
<p style="text-align:left;">This monotonicity is similar to the monotonicity of <img src='http://s0.wp.com/latex.php?latex=R_%7B%5Cmin%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R_{&#92;min}' title='R_{&#92;min}' class='latex' />.  For instance, the functional <img src='http://s0.wp.com/latex.php?latex=%5Clambda%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;lambda(M,g)' title='&#92;lambda(M,g)' class='latex' /> has a dimension of -2 in the sense of the previous lecture, same as <img src='http://s0.wp.com/latex.php?latex=R_%7B%5Cmin%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R_{&#92;min}' title='R_{&#92;min}' class='latex' />.  As further evidence of similarity, we have:</p>
<p style="text-align:left;"><strong>Exercise 5.</strong> Show that <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bd%7D%7Bdt%7D+%5Clambda%28M%2Cg%29+%5Cgeq+%5Cfrac%7B2%7D%7Bd%7D+%5Clambda%28M%2Cg%29%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{d}{dt} &#92;lambda(M,g) &#92;geq &#92;frac{2}{d} &#92;lambda(M,g)^2' title='&#92;frac{d}{dt} &#92;lambda(M,g) &#92;geq &#92;frac{2}{d} &#92;lambda(M,g)^2' class='latex' />, and use this to conclude an analogue of Proposition 1 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/04/285g-lecture-3-the-maximum-principle-and-the-pinching-phenomenon/">Lecture 3</a> for <img src='http://s0.wp.com/latex.php?latex=%5Clambda%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;lambda(M,g)' title='&#92;lambda(M,g)' class='latex' />.  In particular conclude that Ricci flow must develop a finite time singularity if <img src='http://s0.wp.com/latex.php?latex=%5Clambda%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;lambda(M,g)' title='&#92;lambda(M,g)' class='latex' /> is positive. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;"><strong>Exercise 6.</strong> If <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g)' title='(M,g)' class='latex' /> is a Ricci flow which is a <em>steady breather</em> in the sense that it is periodic modulo isometries (thus <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g(t))' title='(M,g(t))' class='latex' /> is isometries to <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%280%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g(0))' title='(M,g(0))' class='latex' /> for some <img src='http://s0.wp.com/latex.php?latex=t+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &gt; 0' title='t &gt; 0' class='latex' />), show that at time zero we have</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRic%7D+%3D+-+%5Chbox%7BHess%7D%28f%29+%3D+-+%5Cfrac%7B1%7D%7B2%7D+%5Cmathcal%7BL%7D_%7B%5Cnabla+f%7D+g&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Ric} = - &#92;hbox{Hess}(f) = - &#92;frac{1}{2} &#92;mathcal{L}_{&#92;nabla f} g' title='&#92;hbox{Ric} = - &#92;hbox{Hess}(f) = - &#92;frac{1}{2} &#92;mathcal{L}_{&#92;nabla f} g' class='latex' /> (30)</p>
<p style="text-align:left;">for some <img src='http://s0.wp.com/latex.php?latex=f%3A+M+%5Cto+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='f: M &#92;to {&#92;Bbb R}' title='f: M &#92;to {&#92;Bbb R}' class='latex' />.  Conclude that <img src='http://s0.wp.com/latex.php?latex=g%28t%29+%3D+%5Cexp%28+t+%5Cnabla+f+%29%5E%2A+g%280%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='g(t) = &#92;exp( t &#92;nabla f )^* g(0)' title='g(t) = &#92;exp( t &#92;nabla f )^* g(0)' class='latex' />, thus <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g(t))' title='(M,g(t))' class='latex' /> simply evolves by diffeomorphism by the gradient field f.  (For this you may need to use the uniqueness of the initial value problem for Ricci flow.)  In other words, all steady breathers are <em>gradient steady solitons</em>. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;"><strong>Remark 1.</strong> One can apply a similar argument to deal with compact <em>expanding breathers</em> (in which <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g(t))' title='(M,g(t))' class='latex' /> is isometric to a larger dilate of <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%280%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g(0))' title='(M,g(0))' class='latex' /> for some <img src='http://s0.wp.com/latex.php?latex=t%26%2362%3B0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t&gt;0' title='t&gt;0' class='latex' /> by normalising <img src='http://s0.wp.com/latex.php?latex=%5Clambda%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;lambda(M,g)' title='&#92;lambda(M,g)' class='latex' /> by a power of the volume as in Exercise 1 of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/20/285g-lecture-7-rescaling-of-ricci-flows-and-kappa-noncollapsing/">Lecture 7</a>, concluding that such breathers are necessarily gradient expanding solitons with</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRic%7D+%3D+-+%5Chbox%7BHess%7D%28f%29+-+%5Cfrac%7Bg%7D%7B2%5Csigma%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Ric} = - &#92;hbox{Hess}(f) - &#92;frac{g}{2&#92;sigma}' title='&#92;hbox{Ric} = - &#92;hbox{Hess}(f) - &#92;frac{g}{2&#92;sigma}' class='latex' /> (31)</p>
<p style="text-align:left;">at time zero for some potential f and some <img src='http://s0.wp.com/latex.php?latex=%5Csigma+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;sigma &gt; 0' title='&#92;sigma &gt; 0' class='latex' />; see <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0211159">Perelman&#8217;s paper</a> (or Section 7 of <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0605667">Kleiner-Lott</a>) for details.  With a little more work (using the maximum principle) one can in fact show that f is constant, and so the only compact expanding breathers are Einstein manifolds. (Actually, this result can also be established using Exercise 1 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/20/285g-lecture-7-rescaling-of-ricci-flows-and-kappa-noncollapsing/">Lecture 7</a> directly, as follows from the <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=1714939">work of Hamilton</a>.)  This normalisation of <img src='http://s0.wp.com/latex.php?latex=%5Clambda%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;lambda(M,g)' title='&#92;lambda(M,g)' class='latex' /> is also closely related to the <a href="http://en.wikipedia.org/wiki/Yamabe_invariant">Yamabe invariant</a> of M; see this <a href="http://arxiv.org/abs/math/0608504">paper of Kotschick</a> for further discussion.  <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;"><strong>Example 3.</strong> Any Ricci-flat manifold (i.e. <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRic%7D%3D0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Ric}=0' title='&#92;hbox{Ric}=0' class='latex' />) is of course a gradient steady soliton with <img src='http://s0.wp.com/latex.php?latex=f+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='f = 0' title='f = 0' class='latex' />.  A more non-trivial example is given by <em>Hamilton&#8217;s cigar soliton</em> (also known as <em>Witten&#8217;s black hole</em>), which is the two-dimensional manifold <img src='http://s0.wp.com/latex.php?latex=M+%3D+%7B%5CBbb+R%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M = {&#92;Bbb R}^2' title='M = {&#92;Bbb R}^2' class='latex' /> with the conformal metric <img src='http://s0.wp.com/latex.php?latex=dg%5E2+%3D+%5Cfrac%7Bdx%5E2%2Bdy%5E2%7D%7B1%2Bx%5E2%2By%5E2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='dg^2 = &#92;frac{dx^2+dy^2}{1+x^2+y^2}' title='dg^2 = &#92;frac{dx^2+dy^2}{1+x^2+y^2}' class='latex' /> and gradient function <img src='http://s0.wp.com/latex.php?latex=f+%3A%3D+%5Clog+%5Csqrt%7B1%2Bx%5E2%2By%5E2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='f := &#92;log &#92;sqrt{1+x^2+y^2}' title='f := &#92;log &#92;sqrt{1+x^2+y^2}' class='latex' />; we leave the verification of the gradient shrinking property (30) as an exercise.   <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;"><strong>Remark 2.</strong> If Ricci flow was a gradient flow for a functional which was geometric (or more precisely, invariant under diffeomorphism), then this flow could not deform a metric by any non-trivial diffeomorphism (since this is a stationary direction for this functional, rather than a steepest descent).  Thus the existence of non-trivial gradient steady solitons, such as the cigar soliton, explains why Ricci flow cannot be directly expressed as a gradient flow without introducing a non-geometric object such as the reference measure dm or the potential function f.  (See also Proposition 1.7 of <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2251315">Müller&#8217;s book</a> for a different way of seeing that Ricci flow is not a pure gradient flow.) <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;"><strong>Exercise 7. </strong>If (M,g) is a gradient steady soliton with potential f, show that <img src='http://s0.wp.com/latex.php?latex=R+%2B+%5CDelta+f+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R + &#92;Delta f = 0' title='R + &#92;Delta f = 0' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Cnabla+f%26%23124%3B%5E2+%2B+R+%3D+%5Chbox%7Bconst%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;nabla f&#124;^2 + R = &#92;hbox{const}' title='&#124;&#92;nabla f&#124;^2 + R = &#92;hbox{const}' class='latex' />, and <img src='http://s0.wp.com/latex.php?latex=%5Cdot+f+%3D+%26%23124%3B%5Cnabla+f%26%23124%3B%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;dot f = &#124;&#92;nabla f&#124;^2' title='&#92;dot f = &#124;&#92;nabla f&#124;^2' class='latex' />.  (Hint: to prove the second identity, differentiate (30) and use the second Bianchi identity (Exercise 7 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/03/26/285g-lecture-0-riemannian-manifolds-and-curvature/">Lecture 0</a>).) Use the maximum principle to then conclude that the only compact gradient steady solitons are the Ricci-flat manifolds.  <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:center;">&#8211; Nash entropy &#8211;</p>
<p style="text-align:left;">Let us return to our analysis of the functional <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+F%7D_m%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal F}_m(M,g)' title='{&#92;mathcal F}_m(M,g)' class='latex' />, in which <img src='http://s0.wp.com/latex.php?latex=dm%3De%5E%7B-f%7D%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='dm=e^{-f}&#92; d&#92;mu' title='dm=e^{-f}&#92; d&#92;mu' class='latex' /> was fixed and g evolved by the modified Ricci flow (21) (which forced f to evolve by the backwards heat equation (22)).  We then obtained the monotonicity formula (23).  We shall normalise dm to be a probability measure.</p>
<p style="text-align:left;">We can squeeze a little bit more out of this formula &#8211; in particular, making it scale invariant &#8211; by introducing the <em>Nash entropy</em></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=N_m%28M%2Cg%29+%3A%3D+%5Cint+%5Clog+%5Cfrac%7Bdm%7D%7Bd%5Cmu%7D%5C+dm+%3D+-+%5Cint+f%5C+dm&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='N_m(M,g) := &#92;int &#92;log &#92;frac{dm}{d&#92;mu}&#92; dm = - &#92;int f&#92; dm' title='N_m(M,g) := &#92;int &#92;log &#92;frac{dm}{d&#92;mu}&#92; dm = - &#92;int f&#92; dm' class='latex' /> (31)</p>
<p style="text-align:left;">which is the <a href="http://en.wikipedia.org/wiki/Kullback-Leibler_divergence">relative entropy</a> of <img src='http://s0.wp.com/latex.php?latex=d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d&#92;mu' title='d&#92;mu' class='latex' /> with respect to the background measure dm.  (Some further relations and analogies between the functionals described here and notions of entropy from statistical mechanics are discussed in <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0211159">Perelman&#8217;s paper</a>.) From (22) and one integration by parts (using (13), of course) we know how this entropy changes with time:</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bdt%7D+N_m%28M%2Cg%29+%3D+%5Cint+%28%26%23124%3B%5Cnabla+f%26%23124%3B%5E2+%2B+R%29%5C+dm+%3D+%7B%5Cmathcal+F%7D_m%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{dt} N_m(M,g) = &#92;int (&#124;&#92;nabla f&#124;^2 + R)&#92; dm = {&#92;mathcal F}_m(M,g)' title='&#92;displaystyle &#92;frac{d}{dt} N_m(M,g) = &#92;int (&#124;&#92;nabla f&#124;^2 + R)&#92; dm = {&#92;mathcal F}_m(M,g)' class='latex' />. (32)</p>
<p style="text-align:left;">To exploit this identity, let us first consider the case of gradient shrinking solitons:</p>
<p><strong>Exercise 8.</strong> Suppose that a Riemannian manifold (M,g)=(M,g(0)) verifies an equation of the form</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRic%7D+%3D+-+%5Chbox%7BHess%7D%28f%29+%2B+%5Cfrac%7B1%7D%7B2%5Ctau%7D+g&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Ric} = - &#92;hbox{Hess}(f) + &#92;frac{1}{2&#92;tau} g' title='&#92;hbox{Ric} = - &#92;hbox{Hess}(f) + &#92;frac{1}{2&#92;tau} g' class='latex' /> (33)</p>
<p style="text-align:left;">for some function f and some <img src='http://s0.wp.com/latex.php?latex=%5Ctau+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau &gt; 0' title='&#92;tau &gt; 0' class='latex' />.  Show that this equation is preserved for times <img src='http://s0.wp.com/latex.php?latex=0+%5Cleq+t+%26%2360%3B+%5Ctau%280%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &#92;leq t &lt; &#92;tau(0)' title='0 &#92;leq t &lt; &#92;tau(0)' class='latex' /> if g evolves by Ricci flow, if <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' /> evolves by <img src='http://s0.wp.com/latex.php?latex=%5Cdot+%5Ctau+%3D+-1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;dot &#92;tau = -1' title='&#92;dot &#92;tau = -1' class='latex' /> (i.e. <img src='http://s0.wp.com/latex.php?latex=%5Ctau%28t%29+%3D+%5Ctau%280%29-t&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau(t) = &#92;tau(0)-t' title='&#92;tau(t) = &#92;tau(0)-t' class='latex' />), and <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+f+%3D+%26%23124%3B%5Cnabla+f%26%23124%3B_g%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_t f = &#124;&#92;nabla f&#124;_g^2' title='&#92;partial_t f = &#124;&#92;nabla f&#124;_g^2' class='latex' />, and that <img src='http://s0.wp.com/latex.php?latex=g%28t%29+%3D+%5Cfrac%7B%5Ctau%28t%29%7D%7B%5Ctau%280%29%7D+%5Cexp%28+t+%5Cnabla+f+%29+g%280%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='g(t) = &#92;frac{&#92;tau(t)}{&#92;tau(0)} &#92;exp( t &#92;nabla f ) g(0)' title='g(t) = &#92;frac{&#92;tau(t)}{&#92;tau(0)} &#92;exp( t &#92;nabla f ) g(0)' class='latex' /> for all <img src='http://s0.wp.com/latex.php?latex=0+%5Cleq+t+%26%2360%3B+%5Ctau%280%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &#92;leq t &lt; &#92;tau(0)' title='0 &#92;leq t &lt; &#92;tau(0)' class='latex' />.  Such solutions are known as <em>gradient shrinking solitons</em>; they combine Ricci flow with the diffeomorphism and scaling flows from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/03/28/285g-lecture-1-ricci-flow/">Lecture 1</a>.  Note that any positively curved <a href="http://en.wikipedia.org/wiki/Einstein_manifold">Einstein manifold</a>, such as the sphere, will be a gradient shrinking soliton (with f=0). Example 1 also shows that Euclidean space can also be viewed as a gradient shrinking soliton.  <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;">If we are to find a scale-invariant (and diffeomorphism-invariant) monotone quantity for Ricci flow, it had better be constant on the gradient shrinking solitons.  In analogy with (23), we would therefore like the variation of this monotone quantity with respect to Ricci flow to look something like</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+2%5Cint_M+%26%23124%3B%5Chbox%7BRic%7D+%2B+%5Chbox%7BHess%7D%28f%29+-+%5Cfrac%7B1%7D%7B2%5Ctau%7D+g%26%23124%3B_g%5E2%5C+dm&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle 2&#92;int_M &#124;&#92;hbox{Ric} + &#92;hbox{Hess}(f) - &#92;frac{1}{2&#92;tau} g&#124;_g^2&#92; dm' title='&#92;displaystyle 2&#92;int_M &#124;&#92;hbox{Ric} + &#92;hbox{Hess}(f) - &#92;frac{1}{2&#92;tau} g&#124;_g^2&#92; dm' class='latex' /> (34)</p>
<p style="text-align:left;">where <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' /> is some quantity decreasing at the constant rate</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdot+%5Ctau+%3D+-1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;dot &#92;tau = -1' title='&#92;dot &#92;tau = -1' class='latex' />.  (35)</p>
<p style="text-align:left;">But the scaling is wrong; time has dimension 2 with respect to the Ricci flow scaling, and so the dimension of a variation of a scale-invariant quantity should be -2, while the expression (34) has dimension -4.  (Note that f should be dimensionless (up to logarithms), <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' /> has the same dimension of time, i.e. 2, and <img src='http://s0.wp.com/latex.php?latex=%5Cint_M+dm%3D1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_M dm=1' title='&#92;int_M dm=1' class='latex' /> is of course dimensionless.)  So actually we should be looking at</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+2%5Ctau%5Cint_M+%26%23124%3B%5Chbox%7BRic%7D+%2B+%5Chbox%7BHess%7D%28f%29+-+%5Cfrac%7B1%7D%7B2%5Ctau%7D+g%26%23124%3B_g%5E2%5C+dm&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle 2&#92;tau&#92;int_M &#124;&#92;hbox{Ric} + &#92;hbox{Hess}(f) - &#92;frac{1}{2&#92;tau} g&#124;_g^2&#92; dm' title='&#92;displaystyle 2&#92;tau&#92;int_M &#124;&#92;hbox{Ric} + &#92;hbox{Hess}(f) - &#92;frac{1}{2&#92;tau} g&#124;_g^2&#92; dm' class='latex' />. (36)</p>
<p style="text-align:left;">To find a functional whose derivative is (36), we expand the integrand as</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Chbox%7BRic%7D+%2B+%5Chbox%7BHess%7D%28f%29+-+%5Cfrac%7B1%7D%7B2%5Ctau%7D+g%26%23124%3B_g%5E2+%3D+%26%23124%3B%5Chbox%7BRic%7D+%2B+%5Chbox%7BHess%7D%28f%29%26%23124%3B_g%5E2+-+%5Cfrac%7B1%7D%7B%5Ctau%7D+%28R+%2B+%5CDelta+f%29+%2B+%5Cfrac%7Bd%7D%7B4%5Ctau%5E2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;hbox{Ric} + &#92;hbox{Hess}(f) - &#92;frac{1}{2&#92;tau} g&#124;_g^2 = &#124;&#92;hbox{Ric} + &#92;hbox{Hess}(f)&#124;_g^2 - &#92;frac{1}{&#92;tau} (R + &#92;Delta f) + &#92;frac{d}{4&#92;tau^2}' title='&#124;&#92;hbox{Ric} + &#92;hbox{Hess}(f) - &#92;frac{1}{2&#92;tau} g&#124;_g^2 = &#124;&#92;hbox{Ric} + &#92;hbox{Hess}(f)&#124;_g^2 - &#92;frac{1}{&#92;tau} (R + &#92;Delta f) + &#92;frac{d}{4&#92;tau^2}' class='latex' />. (37)</p>
<p style="text-align:left;">Using (32) and the normalisation <img src='http://s0.wp.com/latex.php?latex=%5Cint_M%5C+dg+%3D+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_M&#92; dg = 1' title='&#92;int_M&#92; dg = 1' class='latex' />, we can thus express (36) as</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Ctau+%5Cfrac%7Bd%7D%7Bdt%7D+%7B%5Cmathcal+F%7D_m%28M%2Cg%29+-+2+%7B%5Cmathcal+F%7D_m%28M%2Cg%29+%2B+%5Cfrac%7Bd%7D%7B2%5Ctau%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau &#92;frac{d}{dt} {&#92;mathcal F}_m(M,g) - 2 {&#92;mathcal F}_m(M,g) + &#92;frac{d}{2&#92;tau}' title='&#92;tau &#92;frac{d}{dt} {&#92;mathcal F}_m(M,g) - 2 {&#92;mathcal F}_m(M,g) + &#92;frac{d}{2&#92;tau}' class='latex' />. (38)</p>
<p style="text-align:left;">Using (32) and (35), we can express this as a total derivative:</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bdt%7D+%28%5Ctau+%7B%5Cmathcal+F%7D_m%28M%2Cg%29+-+N_m%28M%2Cg%29+%2B+%5Cfrac%7Bd%7D%7B2%7D+%5Clog+%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{dt} (&#92;tau {&#92;mathcal F}_m(M,g) - N_m(M,g) + &#92;frac{d}{2} &#92;log &#92;tau)' title='&#92;displaystyle &#92;frac{d}{dt} (&#92;tau {&#92;mathcal F}_m(M,g) - N_m(M,g) + &#92;frac{d}{2} &#92;log &#92;tau)' class='latex' />. (39)</p>
<p style="text-align:left;">Thus the quantity in parentheses is monotone increasing in time under Ricci flow (and with f, <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' /> evolving by (22), (35)).</p>
<p style="text-align:left;">In analogy with Example 1, we rewrite the potential function f as</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=f+%3D+%5Ctilde+f+%2B+%5Cfrac%7Bd%7D%7B2%7D+%5Clog%284%5Cpi+%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='f = &#92;tilde f + &#92;frac{d}{2} &#92;log(4&#92;pi &#92;tau)' title='f = &#92;tilde f + &#92;frac{d}{2} &#92;log(4&#92;pi &#92;tau)' class='latex' /> (40)</p>
<p style="text-align:left;">then <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+f&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde f' title='&#92;tilde f' class='latex' /> obeys the slight variant of (22)</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bdt%7D+%5Ctilde+f+%3D+-%5CDelta+f+-+R+%2B+%5Cfrac%7Bd%7D%7B2%5Ctau%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{dt} &#92;tilde f = -&#92;Delta f - R + &#92;frac{d}{2&#92;tau}' title='&#92;displaystyle &#92;frac{d}{dt} &#92;tilde f = -&#92;Delta f - R + &#92;frac{d}{2&#92;tau}' class='latex' /> (41)</p>
<p style="text-align:left;">and is related to the fixed measure m by the formula</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=dm+%3D+%284%5Cpi+%5Ctau%29%5E%7B-d%2F2%7D+e%5E%7B-%5Ctilde+f%7D%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='dm = (4&#92;pi &#92;tau)^{-d/2} e^{-&#92;tilde f}&#92; d&#92;mu' title='dm = (4&#92;pi &#92;tau)^{-d/2} e^{-&#92;tilde f}&#92; d&#92;mu' class='latex' /> (42)</p>
<p style="text-align:left;">and the equality between (36) and (39) becomes</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bdt%7D+%7B%5Cmathcal+W%7D_m%28M%2Cg%2C%5Ctau%29+%3D+2%5Ctau%5Cint_M+%26%23124%3B%5Chbox%7BRic%7D+%2B+%5Chbox%7BHess%7D%28%5Ctilde+f%29+-+%5Cfrac%7B1%7D%7B2%5Ctau%7D+g%26%23124%3B_g%5E2%5C+dm&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{dt} {&#92;mathcal W}_m(M,g,&#92;tau) = 2&#92;tau&#92;int_M &#124;&#92;hbox{Ric} + &#92;hbox{Hess}(&#92;tilde f) - &#92;frac{1}{2&#92;tau} g&#124;_g^2&#92; dm' title='&#92;displaystyle &#92;frac{d}{dt} {&#92;mathcal W}_m(M,g,&#92;tau) = 2&#92;tau&#92;int_M &#124;&#92;hbox{Ric} + &#92;hbox{Hess}(&#92;tilde f) - &#92;frac{1}{2&#92;tau} g&#124;_g^2&#92; dm' class='latex' /> (43)</p>
<p style="text-align:left;">where</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%7B%5Cmathcal+W%7D_m%28M%2Cg%2C%5Ctau%29+%3A%3D+%5Cint_M+%5B%5Ctau%28R+%2B+%26%23124%3B%5Cnabla+%5Ctilde+f%26%23124%3B%5E2%29+%2B+%5Ctilde+f+-+d%5D%5C+dm&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle {&#92;mathcal W}_m(M,g,&#92;tau) := &#92;int_M [&#92;tau(R + &#124;&#92;nabla &#92;tilde f&#124;^2) + &#92;tilde f - d]&#92; dm' title='&#92;displaystyle {&#92;mathcal W}_m(M,g,&#92;tau) := &#92;int_M [&#92;tau(R + &#124;&#92;nabla &#92;tilde f&#124;^2) + &#92;tilde f - d]&#92; dm' class='latex' />. (44)</p>
<p style="text-align:left;">The -d term here is harmless (since m is fixed), and is in place to normalise this expression to vanish in the Euclidean case (Example 1, where now <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+f%28t%2Cx%29+%3D+%26%23124%3Bx%26%23124%3B%5E2%2F4t_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde f(t,x) = &#124;x&#124;^2/4t_0' title='&#92;tilde f(t,x) = &#124;x&#124;^2/4t_0' class='latex' />).</p>
<p style="text-align:left;">As before, it is convenient to conjugate away the diffeomorphism by <img src='http://s0.wp.com/latex.php?latex=%5Cnabla+f&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla f' title='&#92;nabla f' class='latex' /> to recover a pure Ricci flow.  Define the <em>Perelman entropy</em> <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+W%7D%28M%2Cg%2Cf%2C%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal W}(M,g,f,&#92;tau)' title='{&#92;mathcal W}(M,g,f,&#92;tau)' class='latex' /> of a manifold <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g)' title='(M,g)' class='latex' />, a scalar function <img src='http://s0.wp.com/latex.php?latex=f%3A+M+%5Cto+%7B%5CBbb+R%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='f: M &#92;to {&#92;Bbb R}' title='f: M &#92;to {&#92;Bbb R}' class='latex' />, and a positive real <img src='http://s0.wp.com/latex.php?latex=%5Ctau+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau &gt; 0' title='&#92;tau &gt; 0' class='latex' />, by</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%7B%5Cmathcal+W%7D%28M%2Cg%2Cf%2C%5Ctau%29+%3D+%5Cint_M+%5B%5Ctau%28R+%2B+%26%23124%3B%5Cnabla+f%26%23124%3B%5E2%29+%2B+f+-+d%5D+%284%5Cpi+%5Ctau%29%5E%7B-d%2F2%7D+e%5E%7B-f%7D%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle {&#92;mathcal W}(M,g,f,&#92;tau) = &#92;int_M [&#92;tau(R + &#124;&#92;nabla f&#124;^2) + f - d] (4&#92;pi &#92;tau)^{-d/2} e^{-f}&#92; d&#92;mu' title='&#92;displaystyle {&#92;mathcal W}(M,g,f,&#92;tau) = &#92;int_M [&#92;tau(R + &#124;&#92;nabla f&#124;^2) + f - d] (4&#92;pi &#92;tau)^{-d/2} e^{-f}&#92; d&#92;mu' class='latex' />. (45)</p>
<p style="text-align:left;">Note that this quantity has dimension 0 (if f is viewed as dimensionless, and <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' /> given the dimension 2).</p>
<p style="text-align:left;"><strong>Exercise 9.</strong> Suppose that g evolves by Ricci flow  (5), f evolves by the nonlinear backward heat equation</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdot+f+%3D+-%5CDelta+f+%2B+%26%23124%3B%5Cnabla+f%26%23124%3B%5E2+-+R+%2B+%5Cfrac%7Bd%7D%7B2%5Ctau%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;dot f = -&#92;Delta f + &#124;&#92;nabla f&#124;^2 - R + &#92;frac{d}{2&#92;tau}' title='&#92;dot f = -&#92;Delta f + &#124;&#92;nabla f&#124;^2 - R + &#92;frac{d}{2&#92;tau}' class='latex' />, (46)</p>
<p style="text-align:left;">and <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' /> evolves by (35).  Show that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bdt%7D+%7B%5Cmathcal+W%7D%28M%2Cg%2Cf%2C%5Ctau%29+%3D+2%5Ctau+%5Cint_M+%26%23124%3B%5Chbox%7BRic%7D+%2B+%5Chbox%7BHess%7D%28f%29+-+%5Cfrac%7B1%7D%7B2%5Ctau%7D+g%26%23124%3B_g%5E2+%284%5Cpi+%5Ctau%29%5E%7B-d%2F2%7D+e%5E%7B-f%7D%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{dt} {&#92;mathcal W}(M,g,f,&#92;tau) = 2&#92;tau &#92;int_M &#124;&#92;hbox{Ric} + &#92;hbox{Hess}(f) - &#92;frac{1}{2&#92;tau} g&#124;_g^2 (4&#92;pi &#92;tau)^{-d/2} e^{-f}&#92; d&#92;mu' title='&#92;displaystyle &#92;frac{d}{dt} {&#92;mathcal W}(M,g,f,&#92;tau) = 2&#92;tau &#92;int_M &#124;&#92;hbox{Ric} + &#92;hbox{Hess}(f) - &#92;frac{1}{2&#92;tau} g&#124;_g^2 (4&#92;pi &#92;tau)^{-d/2} e^{-f}&#92; d&#92;mu' class='latex' />. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /> (47)</p>
<p style="text-align:left;">If we write <img src='http://s0.wp.com/latex.php?latex=u+%3A%3D+%284%5Cpi+%5Ctau%29%5E%7B-d%2F2%7D+e%5E%7B-f%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u := (4&#92;pi &#92;tau)^{-d/2} e^{-f}' title='u := (4&#92;pi &#92;tau)^{-d/2} e^{-f}' class='latex' />, show that (46) is also equivalent to the adjoint heat equation</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdot+u+%3D+-+%5CDelta+u+%2B+R+u&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;dot u = - &#92;Delta u + R u' title='&#92;dot u = - &#92;Delta u + R u' class='latex' />. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /> (48)</p>
<p style="text-align:left;">We have thus obtained a scale-invariant monotonicity formula, albeit one which depends on two additional time-varying parameters, f and <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' />.  To eliminate them, the obvious thing to do is to just take the infimum over all f and <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' />; but we need to be sure that the infimum exists at all.  This will be studied next.</p>
<p style="text-align:center;">&#8211; Connection to the log-Sobolev inequality &#8211;</p>
<p style="text-align:left;">We have just established the monotonicity formula (47) whenever g evolves by Ricci flow (5) and f, <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' /> evolve by (46), (35).  Let us now temporarily specialise to the case when <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g)' title='(M,g)' class='latex' /> is a static Euclidean space <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+R%7D%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb R}^d' title='{&#92;Bbb R}^d' class='latex' /> (which of course obeys Ricci flow), and <img src='http://s0.wp.com/latex.php?latex=%5Ctau+%3D+-t&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau = -t' title='&#92;tau = -t' class='latex' /> (which of course obeys (35)), and now restrict to negative times <img src='http://s0.wp.com/latex.php?latex=t+%26%2360%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &lt; 0' title='t &lt; 0' class='latex' />.  Now all curvatures <img src='http://s0.wp.com/latex.php?latex=R%2C+%5Chbox%7BRic%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R, &#92;hbox{Ric}' title='R, &#92;hbox{Ric}' class='latex' /> vanish, thus for instance by (48) we see that <img src='http://s0.wp.com/latex.php?latex=u%3D%284%5Cpi+%5Ctau%29%5E%7B-d%2F2%7D+e%5E%7B-f%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u=(4&#92;pi &#92;tau)^{-d/2} e^{-f}' title='u=(4&#92;pi &#92;tau)^{-d/2} e^{-f}' class='latex' /> obeys the free backwards heat equation <img src='http://s0.wp.com/latex.php?latex=%5Cdot+u+%3D+-+%5CDelta+u&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;dot u = - &#92;Delta u' title='&#92;dot u = - &#92;Delta u' class='latex' />.  We will normalise <img src='http://s0.wp.com/latex.php?latex=dm+%3D+u%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='dm = u&#92; d&#92;mu' title='dm = u&#92; d&#92;mu' class='latex' /> to be a probability measure, thus <img src='http://s0.wp.com/latex.php?latex=%5Cint_%7B%7B%5CBbb+R%7D%5Ed%7D+u%5C+dx+%3D+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_{{&#92;Bbb R}^d} u&#92; dx = 1' title='&#92;int_{{&#92;Bbb R}^d} u&#92; dx = 1' class='latex' />.</p>
<p style="text-align:left;"><strong>Example 4.</strong> The key example to keep in mind here is <img src='http://s0.wp.com/latex.php?latex=f%28t%2Cx%29+%3D+%26%23124%3Bx%26%23124%3B%5E2%2F4%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='f(t,x) = &#124;x&#124;^2/4&#92;tau' title='f(t,x) = &#124;x&#124;^2/4&#92;tau' class='latex' />, in which case u becomes the backwards heat kernel <img src='http://s0.wp.com/latex.php?latex=u%28t%2Cx%29+%3D+%284%5Cpi+%5Ctau%29%5E%7B-d%2F2%7D+e%5E%7B-%26%23124%3Bx%26%23124%3B%5E2%2F4%5Ctau%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u(t,x) = (4&#92;pi &#92;tau)^{-d/2} e^{-&#124;x&#124;^2/4&#92;tau}' title='u(t,x) = (4&#92;pi &#92;tau)^{-d/2} e^{-&#124;x&#124;^2/4&#92;tau}' class='latex' />. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;">We can now re-express the functional (45) in terms of u as</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%7B%5Cmathcal+W%7D%28M%2Cg%2Cf%2C%5Ctau%29+%3D+%5Cint_%7B%7B%5CBbb+R%7D%5Ed%7D+%28%5Ctau+%5Cfrac%7B%26%23124%3B%5Cnabla+u%26%23124%3B%5E2%7D%7Bu%7D+-+u+%5Clog+u%29%5C+dx+-+%5Cfrac%7Bd%7D%7B2%7D+%5Clog%284%5Cpi+%5Ctau%29+-+d&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle {&#92;mathcal W}(M,g,f,&#92;tau) = &#92;int_{{&#92;Bbb R}^d} (&#92;tau &#92;frac{&#124;&#92;nabla u&#124;^2}{u} - u &#92;log u)&#92; dx - &#92;frac{d}{2} &#92;log(4&#92;pi &#92;tau) - d' title='&#92;displaystyle {&#92;mathcal W}(M,g,f,&#92;tau) = &#92;int_{{&#92;Bbb R}^d} (&#92;tau &#92;frac{&#124;&#92;nabla u&#124;^2}{u} - u &#92;log u)&#92; dx - &#92;frac{d}{2} &#92;log(4&#92;pi &#92;tau) - d' class='latex' />. (49)</p>
<p>One easily verifies by direct calculation that this expression vanishes in the model case of Example 4.  For more general u, we know that this quantity is monotone increasing in time, and so</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+W%7D%28M%2Cg%2Cf%2C%5Ctau%29%28t%29+%5Cgeq+%5Clim_%7Bt+%5Cto+-%5Cinfty%7D+%7B%5Cmathcal+W%7D%28M%2Cg%2Cf%2C%5Ctau%29%28t%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal W}(M,g,f,&#92;tau)(t) &#92;geq &#92;lim_{t &#92;to -&#92;infty} {&#92;mathcal W}(M,g,f,&#92;tau)(t)' title='{&#92;mathcal W}(M,g,f,&#92;tau)(t) &#92;geq &#92;lim_{t &#92;to -&#92;infty} {&#92;mathcal W}(M,g,f,&#92;tau)(t)' class='latex' />. (50)</p>
<p>Now suppose u is some non-negative test function <img src='http://s0.wp.com/latex.php?latex=u_0%28x%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u_0(x)' title='u_0(x)' class='latex' /> at time zero with total mass 1, then from the fundamental solution for the backwards heat equation we have</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+u%28t%2Cx%29+%3D+%5Cfrac%7B1%7D%7B%284%5Cpi+%5Ctau%29%5E%7Bd%2F2%7D%7D+%5Cint_%7B%7B%5CBbb+R%7D%5Ed%7D+e%5E%7B-%26%23124%3Bx-y%26%23124%3B%5E2%2F4%5Ctau%7D+u_0%28y%29%5C+dy+%3D+%5Cfrac%7B1%7D%7B%284%5Cpi+%5Ctau%29%5E%7Bd%2F2%7D%7D+%5Ctilde+u%28+t%2C+x%2F%5Csqrt%7B%5Ctau%7D+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle u(t,x) = &#92;frac{1}{(4&#92;pi &#92;tau)^{d/2}} &#92;int_{{&#92;Bbb R}^d} e^{-&#124;x-y&#124;^2/4&#92;tau} u_0(y)&#92; dy = &#92;frac{1}{(4&#92;pi &#92;tau)^{d/2}} &#92;tilde u( t, x/&#92;sqrt{&#92;tau} )' title='&#92;displaystyle u(t,x) = &#92;frac{1}{(4&#92;pi &#92;tau)^{d/2}} &#92;int_{{&#92;Bbb R}^d} e^{-&#124;x-y&#124;^2/4&#92;tau} u_0(y)&#92; dy = &#92;frac{1}{(4&#92;pi &#92;tau)^{d/2}} &#92;tilde u( t, x/&#92;sqrt{&#92;tau} )' class='latex' /> (51)</p>
<p>where <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+u&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde u' title='&#92;tilde u' class='latex' /> is the renormalised solution</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Ctilde+u%28t%2C+x%29+%3A%3D+%5Cint_%7B%7B%5CBbb+R%7D%5Ed%7D+e%5E%7B-%26%23124%3Bx+-+%28y%2F%5Csqrt%7B%5Ctau%7D%29%26%23124%3B%5E2+%2F+4%7D+u_0%28y%29%5C+dy&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;tilde u(t, x) := &#92;int_{{&#92;Bbb R}^d} e^{-&#124;x - (y/&#92;sqrt{&#92;tau})&#124;^2 / 4} u_0(y)&#92; dy' title='&#92;displaystyle &#92;tilde u(t, x) := &#92;int_{{&#92;Bbb R}^d} e^{-&#124;x - (y/&#92;sqrt{&#92;tau})&#124;^2 / 4} u_0(y)&#92; dy' class='latex' />. (52)</p>
<p>Observe that <img src='http://s0.wp.com/latex.php?latex=%5Ctilde+u%28t%2Cx%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tilde u(t,x)' title='&#92;tilde u(t,x)' class='latex' /> converges pointwise to <img src='http://s0.wp.com/latex.php?latex=e%5E%7B-%26%23124%3Bx%26%23124%3B%5E2%2F4%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='e^{-&#124;x&#124;^2/4}' title='e^{-&#124;x&#124;^2/4}' class='latex' /> as <img src='http://s0.wp.com/latex.php?latex=t+%5Cto+-%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;to -&#92;infty' title='t &#92;to -&#92;infty' class='latex' /> for fixed x.  Thus in some renormalised sense this general solution is converging to the model solution in Example 3 in the limit <img src='http://s0.wp.com/latex.php?latex=t+%5Cto+-%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;to -&#92;infty' title='t &#92;to -&#92;infty' class='latex' />.</p>
<p>We can rewrite the functional (49) after some calculation as</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%7B%5Cmathcal+W%7D%28M%2Cg%2Cf%2C%5Ctau%29+%3D+%5Cint_%7B%7B%5CBbb+R%7D%5Ed%7D+%5B%5Ctau+%5Cfrac%7B%26%23124%3B%5Cnabla+%5Ctilde+u%26%23124%3B%5E2%7D%7B%5Ctilde+u%5E2%7D+-+%5Clog+%5Ctilde+u%5D+%28-4%5Cpi%29%5E%7B-d%2F2%7D+%5Ctilde+u%5C+dx+-+d&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle {&#92;mathcal W}(M,g,f,&#92;tau) = &#92;int_{{&#92;Bbb R}^d} [&#92;tau &#92;frac{&#124;&#92;nabla &#92;tilde u&#124;^2}{&#92;tilde u^2} - &#92;log &#92;tilde u] (-4&#92;pi)^{-d/2} &#92;tilde u&#92; dx - d' title='&#92;displaystyle {&#92;mathcal W}(M,g,f,&#92;tau) = &#92;int_{{&#92;Bbb R}^d} [&#92;tau &#92;frac{&#124;&#92;nabla &#92;tilde u&#124;^2}{&#92;tilde u^2} - &#92;log &#92;tilde u] (-4&#92;pi)^{-d/2} &#92;tilde u&#92; dx - d' class='latex' />. (53)</p>
<p>One can check that <img src='http://s0.wp.com/latex.php?latex=%5Cnabla+%5Ctilde+u&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla &#92;tilde u' title='&#92;nabla &#92;tilde u' class='latex' /> is converging pointwise to <img src='http://s0.wp.com/latex.php?latex=%5Cnabla+e%5E%7B-%26%23124%3Bx%26%23124%3B%5E2%2F4%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla e^{-&#124;x&#124;^2/4}' title='&#92;nabla e^{-&#124;x&#124;^2/4}' class='latex' />.  A careful application of dominated convergence then shows that in the limit <img src='http://s0.wp.com/latex.php?latex=t+%5Cto+-%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;to -&#92;infty' title='t &#92;to -&#92;infty' class='latex' />, (53) converges to the value attained in Example 3, i.e. zero.  By the monotonicity formula, we have thus demonstrated that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+W%7D%28M%2Cg%2Cf%2C%5Ctau%29+%5Cgeq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal W}(M,g,f,&#92;tau) &#92;geq 0' title='{&#92;mathcal W}(M,g,f,&#92;tau) &#92;geq 0' class='latex' /> (54)</p>
<p>for all times <img src='http://s0.wp.com/latex.php?latex=-%5Cinfty+%26%2360%3B+t+%26%2360%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='-&#92;infty &lt; t &lt; 0' title='-&#92;infty &lt; t &lt; 0' class='latex' />.  Writing <img src='http://s0.wp.com/latex.php?latex=u+%3D+%5Cphi%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u = &#92;phi^2' title='u = &#92;phi^2' class='latex' /> and rearranging (49), we conclude the <em>log-Sobolev inequality</em></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+2%5Cint_%7B%7B%5CBbb+R%7D%5Ed%7D+%5Cphi%5E2+%5Clog+%5Cphi%5C+dx+%5Cleq++4%5Ctau+%5Cint_%7B%7B%5CBbb+R%7D%5Ed%7D++%26%23124%3B%5Cnabla+%5Cphi%26%23124%3B%5E2%5C+dx+-+%5Cfrac%7Bd%7D%7B2%7D+%5Clog%284+%5Cpi+%5Ctau%29++-+d&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle 2&#92;int_{{&#92;Bbb R}^d} &#92;phi^2 &#92;log &#92;phi&#92; dx &#92;leq  4&#92;tau &#92;int_{{&#92;Bbb R}^d}  &#124;&#92;nabla &#92;phi&#124;^2&#92; dx - &#92;frac{d}{2} &#92;log(4 &#92;pi &#92;tau)  - d' title='&#92;displaystyle 2&#92;int_{{&#92;Bbb R}^d} &#92;phi^2 &#92;log &#92;phi&#92; dx &#92;leq  4&#92;tau &#92;int_{{&#92;Bbb R}^d}  &#124;&#92;nabla &#92;phi&#124;^2&#92; dx - &#92;frac{d}{2} &#92;log(4 &#92;pi &#92;tau)  - d' class='latex' /> (55)</p>
<p>valid whenever <img src='http://s0.wp.com/latex.php?latex=%5Ctau+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau &gt; 0' title='&#92;tau &gt; 0' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Cint_%7B%7B%5CBbb+R%7D%5Ed%7D+%5Cphi%5E2%5C+dx+%3D+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_{{&#92;Bbb R}^d} &#92;phi^2&#92; dx = 1' title='&#92;int_{{&#92;Bbb R}^d} &#92;phi^2&#92; dx = 1' class='latex' />.</p>
<p><strong>Exercise 10. </strong>By letting <img src='http://s0.wp.com/latex.php?latex=dm+%3A%3D+%284%5Cpi+%5Ctau%29%5E%7B-d%2F2%7D+e%5E%7B-%26%23124%3Bx%26%23124%3B%5E2%2F4%5Ctau%7D+dx&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='dm := (4&#92;pi &#92;tau)^{-d/2} e^{-&#124;x&#124;^2/4&#92;tau} dx' title='dm := (4&#92;pi &#92;tau)^{-d/2} e^{-&#124;x&#124;^2/4&#92;tau} dx' class='latex' /> be standard Gaussian measure and writing <img src='http://s0.wp.com/latex.php?latex=u+dx+%3D+F%5E2+dm&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='u dx = F^2 dm' title='u dx = F^2 dm' class='latex' />, deduce the original log-Sobolev inequality</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cint_%7B%7B%5CBbb+R%7D%5Ed%7D+F%5E2+%5Clog+F%5E2%5C+dm+%5Cleq+%5Cfrac%7B1%7D%7B%5Ctau%7D+%5Cint_%7B%7B%5CBbb+R%7D%5Ed%7D+%26%23124%3B%5Cnabla+F%26%23124%3B%5E2+dm&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;int_{{&#92;Bbb R}^d} F^2 &#92;log F^2&#92; dm &#92;leq &#92;frac{1}{&#92;tau} &#92;int_{{&#92;Bbb R}^d} &#124;&#92;nabla F&#124;^2 dm' title='&#92;displaystyle &#92;int_{{&#92;Bbb R}^d} F^2 &#92;log F^2&#92; dm &#92;leq &#92;frac{1}{&#92;tau} &#92;int_{{&#92;Bbb R}^d} &#124;&#92;nabla F&#124;^2 dm' class='latex' /> (56)</p>
<p><a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=420249">of Gross</a>, valid whenever <img src='http://s0.wp.com/latex.php?latex=%5Ctau+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau &gt; 0' title='&#92;tau &gt; 0' class='latex' /> <img src='http://s0.wp.com/latex.php?latex=%5Cint_%7B%7B%5CBbb+R%7D%5Ed%7D+F%5E2%5C+dm+%3D+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_{{&#92;Bbb R}^d} F^2&#92; dm = 1' title='&#92;int_{{&#92;Bbb R}^d} F^2&#92; dm = 1' class='latex' />. [One key feature of this inequality, as compared to more traditional Sobolev inequalities, is that it is almost completely independent of the dimension d.] <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p><strong>Remark 3.</strong> We have seen how knowledge of the heat kernel can lead to log-Sobolev inequalities, by evolving by the (backwards) heat flow (this is an example of the <em>semigroup method</em> for proving inequalities).  This connection can in fact be reversed, using log-Sobolev inequalities to deduce information about heat kernels.  Heat kernels can in turn be used to deduce ordinary Sobolev estimates, which then imply log-Sobolev estimates by convexity inequalities such as Hölder&#8217;s inequality, thus showing that all these phenomena are morally equivalent.  There is a vast literature on these subjects (and other related topics, such as hypercontractivity); so much so that there are not only multiple surveys on the subject, but even a <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2325763">survey of all the surveys</a>.  <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>We now return to the case of general Ricci flows (not just the Euclidean one).</p>
<p><strong>Exercise 11.</strong> Let (M,g) be a compact Riemannian manifold, and let <img src='http://s0.wp.com/latex.php?latex=%5Ctau+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau &gt; 0' title='&#92;tau &gt; 0' class='latex' />.  Using the Euclidean log-Sobolev inequality (48), show that we have a lower bound of the form <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+W%7D%28M%2Cg%2Cf%2C%5Ctau%29+%5Cgeq+-+C%28M%2Cg%2C%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal W}(M,g,f,&#92;tau) &#92;geq - C(M,g,&#92;tau)' title='{&#92;mathcal W}(M,g,f,&#92;tau) &#92;geq - C(M,g,&#92;tau)' class='latex' /> for all functions f with <img src='http://s0.wp.com/latex.php?latex=%5Cint+%284%5Cpi+%5Ctau%29%5E%7B-d%2F2%7D+e%5E%7B-f%7D%5C+d%5Cmu+%3D+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int (4&#92;pi &#92;tau)^{-d/2} e^{-f}&#92; d&#92;mu = 1' title='&#92;int (4&#92;pi &#92;tau)^{-d/2} e^{-f}&#92; d&#92;mu = 1' class='latex' />.  Show in fact that <img src='http://s0.wp.com/latex.php?latex=C%28M%2Cg%2C%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C(M,g,&#92;tau)' title='C(M,g,&#92;tau)' class='latex' /> can be chosen to depend only on <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' />, the dimension, an upper bound for the magnitude of the RIemann curvature, and a lower bound for the injectivity radius.  Using a rescaling and compactness argument, show also that we can take <img src='http://s0.wp.com/latex.php?latex=C%28M%2Cg%2C%5Ctau%29+%5Cto+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='C(M,g,&#92;tau) &#92;to 0' title='C(M,g,&#92;tau) &#92;to 0' class='latex' /> as <img src='http://s0.wp.com/latex.php?latex=%5Ctau+%5Cto+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau &#92;to 0' title='&#92;tau &#92;to 0' class='latex' />.  (Details can be found in Section 3.1 of <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0211159">Perelman&#8217;s paper</a>.)  <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>We can now define the quantity <img src='http://s0.wp.com/latex.php?latex=%5Cmu%28M%2Cg%2C%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;mu(M,g,&#92;tau)' title='&#92;mu(M,g,&#92;tau)' class='latex' /> to be the infimum of <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+W%7D%28M%2Cg%2Cf%2C%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal W}(M,g,f,&#92;tau)' title='{&#92;mathcal W}(M,g,f,&#92;tau)' class='latex' /> for all functions f with <img src='http://s0.wp.com/latex.php?latex=%5Cint+%284%5Cpi+%5Ctau%29%5E%7B-d%2F2%7D+e%5E%7B-f%7D%5C+d%5Cmu+%3D+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int (4&#92;pi &#92;tau)^{-d/2} e^{-f}&#92; d&#92;mu = 1' title='&#92;int (4&#92;pi &#92;tau)^{-d/2} e^{-f}&#92; d&#92;mu = 1' class='latex' />; thus <img src='http://s0.wp.com/latex.php?latex=%5Cmu%28M%2Cg%2C%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;mu(M,g,&#92;tau)' title='&#92;mu(M,g,&#92;tau)' class='latex' /> is non-decreasing if we evolve <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' /> by (35).   Thus we have obtained a one-parameter family of dimensionless monotone quantities (recalling that <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' /> has dimension 2 with respect to scaling).</p>
<p><strong>Remark 4.</strong> One can interpret <img src='http://s0.wp.com/latex.php?latex=%5Cmu%28M%2Cg%2C%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;mu(M,g,&#92;tau)' title='&#92;mu(M,g,&#92;tau)' class='latex' /> as a nonlinear analogue of the eigenvalue <img src='http://s0.wp.com/latex.php?latex=%5Clambda%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;lambda(M,g)' title='&#92;lambda(M,g)' class='latex' />.  Indeed, just as <img src='http://s0.wp.com/latex.php?latex=%5Clambda%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;lambda(M,g)' title='&#92;lambda(M,g)' class='latex' /> is the least number <img src='http://s0.wp.com/latex.php?latex=%5Clambda&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;lambda' title='&#92;lambda' class='latex' /> for which one can solve the linear eigenfunction equation</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%284%5CDelta+%2B+R%29+%5CPhi+%3D+%5Clambda+%5CPhi&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(4&#92;Delta + R) &#92;Phi = &#92;lambda &#92;Phi' title='(4&#92;Delta + R) &#92;Phi = &#92;lambda &#92;Phi' class='latex' /> (57)</p>
<p>subject to the constraint <img src='http://s0.wp.com/latex.php?latex=%5Cint_M+%5CPhi%5E2+%3D+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_M &#92;Phi^2 = 1' title='&#92;int_M &#92;Phi^2 = 1' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=%5Cmu%28M%2Cg%2C%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;mu(M,g,&#92;tau)' title='&#92;mu(M,g,&#92;tau)' class='latex' /> is the least number <img src='http://s0.wp.com/latex.php?latex=%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;mu' title='&#92;mu' class='latex' /> for which one can solve the nonlinear eigenfunction equation</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Ctau+%284%5CDelta%2BR%29+%5CPhi++%3D+2+%5CPhi+%5Clog+%5CPhi+%2B+%28%5Cmu%2Bd%29+%5CPhi&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau (4&#92;Delta+R) &#92;Phi  = 2 &#92;Phi &#92;log &#92;Phi + (&#92;mu+d) &#92;Phi' title='&#92;tau (4&#92;Delta+R) &#92;Phi  = 2 &#92;Phi &#92;log &#92;Phi + (&#92;mu+d) &#92;Phi' class='latex' /> (58)</p>
<p>subject to the constraints <img src='http://s0.wp.com/latex.php?latex=%5CPhi+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;Phi &gt; 0' title='&#92;Phi &gt; 0' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Cint_M+%284%5Cpi+%5Ctau%29%5E%7B-d%2F2%7D+%5CPhi%5E2%5C+d%5Cmu+%3D+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_M (4&#92;pi &#92;tau)^{-d/2} &#92;Phi^2&#92; d&#92;mu = 1' title='&#92;int_M (4&#92;pi &#92;tau)^{-d/2} &#92;Phi^2&#92; d&#92;mu = 1' class='latex' />.  In particular we expect <img src='http://s0.wp.com/latex.php?latex=%5Cmu%28M%2Cg%2C%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;mu(M,g,&#92;tau)' title='&#92;mu(M,g,&#92;tau)' class='latex' /> to behave roughly like <img src='http://s0.wp.com/latex.php?latex=%5Ctau+%5Clambda%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau &#92;lambda(M,g)' title='&#92;tau &#92;lambda(M,g)' class='latex' /> in the limit <img src='http://s0.wp.com/latex.php?latex=%5Ctau+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau &#92;to &#92;infty' title='&#92;tau &#92;to &#92;infty' class='latex' />. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;"><strong>Exercise 12. </strong>Show that the only shrinking breathers (those in which <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g(t))' title='(M,g(t))' class='latex' /> is isometric to a contraction of <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%280%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g(0))' title='(M,g(0))' class='latex' /> for some <img src='http://s0.wp.com/latex.php?latex=t%26%2362%3B0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t&gt;0' title='t&gt;0' class='latex' />) are the gradient shrinking solitons. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:center;">&#8211; Non-collapsing &#8211;</p>
<p>We now relate log-Sobolev inequalities (i.e. lower bounds on <img src='http://s0.wp.com/latex.php?latex=%5Cmu%28M%2Cg%2C%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;mu(M,g,&#92;tau)' title='&#92;mu(M,g,&#92;tau)' class='latex' />) to non-collapsing.   We first note that by substituting <img src='http://s0.wp.com/latex.php?latex=%284%5Cpi+%5Ctau%29%5E%7B-d%2F2%7D+e%5E%7B-f%7D+%3D+%5Cphi%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(4&#92;pi &#92;tau)^{-d/2} e^{-f} = &#92;phi^2' title='(4&#92;pi &#92;tau)^{-d/2} e^{-f} = &#92;phi^2' class='latex' /> into (45) as in the Euclidean case, that we have the log-Sobolev inequality</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cint_%7BM%7D+%5Cphi%5E2+%5Clog+%5Cphi%5E2%5C+d%5Cmu+%5Cleq+4%5Ctau+%5Cint_%7BM%7D+%26%23124%3B%5Cnabla+%5Cphi%26%23124%3B_g%5E2%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;int_{M} &#92;phi^2 &#92;log &#92;phi^2&#92; d&#92;mu &#92;leq 4&#92;tau &#92;int_{M} &#124;&#92;nabla &#92;phi&#124;_g^2&#92; d&#92;mu' title='&#92;displaystyle &#92;int_{M} &#92;phi^2 &#92;log &#92;phi^2&#92; d&#92;mu &#92;leq 4&#92;tau &#92;int_{M} &#124;&#92;nabla &#92;phi&#124;_g^2&#92; d&#92;mu' class='latex' /></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%2B+%5Ctau+%5Cint_M+R+%26%23124%3B%5Cphi%26%23124%3B%5E2%5C+d%5Cmu+-+%5Cfrac%7Bd%7D%7B2%7D+%5Clog%284+%5Cpi+%5Ctau%29+-+d+-+%5Cmu%28M%2Cg%2C%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle + &#92;tau &#92;int_M R &#124;&#92;phi&#124;^2&#92; d&#92;mu - &#92;frac{d}{2} &#92;log(4 &#92;pi &#92;tau) - d - &#92;mu(M,g,&#92;tau)' title='&#92;displaystyle + &#92;tau &#92;int_M R &#124;&#92;phi&#124;^2&#92; d&#92;mu - &#92;frac{d}{2} &#92;log(4 &#92;pi &#92;tau) - d - &#92;mu(M,g,&#92;tau)' class='latex' /> (59)</p>
<p>whenever <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' /> is non-negative with <img src='http://s0.wp.com/latex.php?latex=%5Cint_M+%5Cphi%5E2%5C+d%5Cmu+%3D+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_M &#92;phi^2&#92; d&#92;mu = 1' title='&#92;int_M &#92;phi^2&#92; d&#92;mu = 1' class='latex' />.</p>
<p>To use this, suppose we have a ball <img src='http://s0.wp.com/latex.php?latex=B+%3D+B%28p%2C%5Csqrt%7B%5Ctau%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B = B(p,&#92;sqrt{&#92;tau})' title='B = B(p,&#92;sqrt{&#92;tau})' class='latex' /> which has bounded normalised curvature, so in particular <img src='http://s0.wp.com/latex.php?latex=R+%3D+O%28+%5Ctau%5E%7B-1%7D+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R = O( &#92;tau^{-1} )' title='R = O( &#92;tau^{-1} )' class='latex' /> on this ball.<br />
On the other hand, if <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' /> is supported on B with <img src='http://s0.wp.com/latex.php?latex=L%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='L^2' title='L^2' class='latex' /> mass 1, then from <a href="http://en.wikipedia.org/wiki/Jensen%27s_inequality">Jensen&#8217;s inequality</a> we have</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cint_%7BM%7D+%5Cphi%5E2+%5Clog+%5Cphi%5E2%5C+d%5Cmu+%5Cgeq+%5Clog+%5Cfrac%7B1%7D%7B%5Chbox%7BVol%7D%28B%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;int_{M} &#92;phi^2 &#92;log &#92;phi^2&#92; d&#92;mu &#92;geq &#92;log &#92;frac{1}{&#92;hbox{Vol}(B)}' title='&#92;displaystyle &#92;int_{M} &#92;phi^2 &#92;log &#92;phi^2&#92; d&#92;mu &#92;geq &#92;log &#92;frac{1}{&#92;hbox{Vol}(B)}' class='latex' /> (54)</p>
<p>and we thus conclude from (59) that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Clog+%5Cfrac%7B%5Ctau%5E%7Bd%2F2%7D%7D%7B%5Chbox%7BVol%7D%7D+%5Cleq+4+%5Ctau+%5Cint_M+%26%23124%3B%5Cnabla+%5Cphi%26%23124%3B_g%5E2+%2B+O%281%29+-+%5Cmu%28M%2Cg%2C%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;displaystyle &#92;log &#92;frac{&#92;tau^{d/2}}{&#92;hbox{Vol}} &#92;leq 4 &#92;tau &#92;int_M &#124;&#92;nabla &#92;phi&#124;_g^2 + O(1) - &#92;mu(M,g,&#92;tau)' title='&#92;displaystyle &#92;log &#92;frac{&#92;tau^{d/2}}{&#92;hbox{Vol}} &#92;leq 4 &#92;tau &#92;int_M &#124;&#92;nabla &#92;phi&#124;_g^2 + O(1) - &#92;mu(M,g,&#92;tau)' class='latex' />. (60)</p>
<p>If we let <img src='http://s0.wp.com/latex.php?latex=%5Cphi%28x%29+%3A%3D+c+%5Cpsi%28+d%28x%2Cp%29+%2F+%5Csqrt%7B%5Ctau%7D+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;phi(x) := c &#92;psi( d(x,p) / &#92;sqrt{&#92;tau} )' title='&#92;phi(x) := c &#92;psi( d(x,p) / &#92;sqrt{&#92;tau} )' class='latex' />, where <img src='http://s0.wp.com/latex.php?latex=%5Cpsi&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;psi' title='&#92;psi' class='latex' /> is a bump function that equals 1on [-1/2,1/2] and is supported on [-1,1] (thus <img src='http://s0.wp.com/latex.php?latex=%5Cphi%3Dc&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;phi=c' title='&#92;phi=c' class='latex' /> on the ball <img src='http://s0.wp.com/latex.php?latex=B_%7B1%2F2%7D+%3A%3D+B%28+p%2C+%5Csqrt%7B%5Ctau%7D%2F2+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_{1/2} := B( p, &#92;sqrt{&#92;tau}/2 )' title='B_{1/2} := B( p, &#92;sqrt{&#92;tau}/2 )' class='latex' />, and <img src='http://s0.wp.com/latex.php?latex=c+%5Cleq+1%2F%5Chbox%7BVol%7D%28B_%7B1%2F2%7D%29%5E%7B1%2F2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='c &#92;leq 1/&#92;hbox{Vol}(B_{1/2})^{1/2}' title='c &#92;leq 1/&#92;hbox{Vol}(B_{1/2})^{1/2}' class='latex' /> is the normalisation constant needed to ensure that <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' /> has <img src='http://s0.wp.com/latex.php?latex=L%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='L^2' title='L^2' class='latex' /> mass one, then <img src='http://s0.wp.com/latex.php?latex=%5Cnabla+%5Cphi+%3D+O%28+c+%2F+%5Csqrt%7B%5Ctau%7D+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla &#92;phi = O( c / &#92;sqrt{&#92;tau} )' title='&#92;nabla &#92;phi = O( c / &#92;sqrt{&#92;tau} )' class='latex' /> on this ball, and so we conclude</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Clog+%5Cfrac%7B%5Ctau%5E%7Bd%2F2%7D%7D%7B%5Chbox%7BVol%7D%28B%29%7D+%5Cleq+O%28+%5Chbox%7BVol%7D%28+B+%29+%2F+%5Chbox%7BVol%7D%28+B_%7B1%2F2%7D+%29+%29+-+%5Cmu%28M%2Cg%2C%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;log &#92;frac{&#92;tau^{d/2}}{&#92;hbox{Vol}(B)} &#92;leq O( &#92;hbox{Vol}( B ) / &#92;hbox{Vol}( B_{1/2} ) ) - &#92;mu(M,g,&#92;tau)' title='&#92;log &#92;frac{&#92;tau^{d/2}}{&#92;hbox{Vol}(B)} &#92;leq O( &#92;hbox{Vol}( B ) / &#92;hbox{Vol}( B_{1/2} ) ) - &#92;mu(M,g,&#92;tau)' class='latex' />. (61)</p>
<p>At this point we need to invoke the relative <a href="http://en.wikipedia.org/wiki/Bishop-Gromov_inequality">Bishop-Gromov inequality</a> from comparison geometry, which among other things ensures that <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BVol%7D%28B%29+%3D+O%28+%5Chbox%7BVol%7D%28B_%7B1%2F2%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Vol}(B) = O( &#92;hbox{Vol}(B_{1/2})' title='&#92;hbox{Vol}(B) = O( &#92;hbox{Vol}(B_{1/2})' class='latex' /> under the assumption of bounded normalised curvature.  Indeed, from equations (15) and (17) from the previous lecture we see that <img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D_%7B%5Cpartial_r%7D%5C+d%5Cmu+%3D+O%28+1%2Fr+%29%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}_{&#92;partial_r}&#92; d&#92;mu = O( 1/r )&#92; d&#92;mu' title='{&#92;mathcal L}_{&#92;partial_r}&#92; d&#92;mu = O( 1/r )&#92; d&#92;mu' class='latex' /> inside the ball of radius <img src='http://s0.wp.com/latex.php?latex=1%2F%5Csqrt%7B%5Ctau%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='1/&#92;sqrt{&#92;tau}' title='1/&#92;sqrt{&#92;tau}' class='latex' />, from which the claim easily follows within the radius of injectivity.  (To generalise the inequality beyond this region, one simply works on the region inside the <a href="http://en.wikipedia.org/wiki/Cut_locus_(Riemannian_manifold)">cut locus</a>, which is star-shaped around the origin in <img src='http://s0.wp.com/latex.php?latex=T_p+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='T_p M' title='T_p M' class='latex' />.)</p>
<p>Using this inequality, we thus conclude that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BVol%7D%28B%29+%5Cgg+%5Ctau%5E%7Bd%2F2%7D+%5Cexp%28+%5Cmu%28+M%2Cg%2C%5Ctau%29+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Vol}(B) &#92;gg &#92;tau^{d/2} &#92;exp( &#92;mu( M,g,&#92;tau) )' title='&#92;hbox{Vol}(B) &#92;gg &#92;tau^{d/2} &#92;exp( &#92;mu( M,g,&#92;tau) )' class='latex' />. (62)</p>
<p>Thus a lower bound on <img src='http://s0.wp.com/latex.php?latex=%5Cmu%28M%2Cg%2C%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;mu(M,g,&#92;tau)' title='&#92;mu(M,g,&#92;tau)' class='latex' /> enforces non-collapsing of volume at scale <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' />.</p>
<p><strong>Exercise 13.</strong> Use (62), Exercise 11 and the monotonicity properties of <img src='http://s0.wp.com/latex.php?latex=%5Cmu%28M%2Cg%2C%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;mu(M,g,&#92;tau)' title='&#92;mu(M,g,&#92;tau)' class='latex' /> to establish <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsing of Ricci flows (Theorem 2 from the <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/20/285g-lecture-7-rescaling-of-ricci-flows-and-kappa-noncollapsing/">previous lecture</a>). <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p><strong>Remark 5. </strong>This argument in fact establishes a stronger form of non-collapsing, in which in order to get non-collapsing at time <img src='http://s0.wp.com/latex.php?latex=t_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_0' title='t_0' class='latex' /> and scale <img src='http://s0.wp.com/latex.php?latex=r_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_0' title='r_0' class='latex' />, one only needs bounded normalised curvature at time <img src='http://s0.wp.com/latex.php?latex=t_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_0' title='t_0' class='latex' /> (instead of on the time interval <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5Bt_0-r_0%5E2%2Ct_0%5D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[t_0-r_0^2,t_0]' title='{}[t_0-r_0^2,t_0]' class='latex' />).  It also works in arbitrary dimension. The second proof of non-collapsing that we will give, based on the Perelman reduced volume instead of Perelman entropy, needs the spacetime bounded normalised curvature assumption but also works in arbitrary dimension.  <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p><strong>Remark 6. </strong>The parameter <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' /> in the above result, which measures the quality of the non-collapsing, will deteriorate with time T.  This is because the decay of <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' /> from (35) entails that in order to get non-collapsing of the manifold at time <img src='http://s0.wp.com/latex.php?latex=t_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_0' title='t_0' class='latex' /> and scale <img src='http://s0.wp.com/latex.php?latex=r_0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_0' title='r_0' class='latex' />, one needs some non-collapsing at time zero and scale <img src='http://s0.wp.com/latex.php?latex=%5Csqrt%7Br_0+%2B+t_0%5E2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;sqrt{r_0 + t_0^2}' title='&#92;sqrt{r_0 + t_0^2}' class='latex' />.  Of course, since the manifold is initially compact, one always has some non-collapsing at each scale, but the quantitative constants associated to this non-collapsing will deteriorate as the scale increases, which will happen when T increases.  Fortunately (and especially in view of our finite time extinction results) we only need to analyse Ricci flow on compact (though potentially rather large) time intervals <img src='http://s0.wp.com/latex.php?latex=%7B%7D%5B0%2CT%5D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{}[0,T]' title='{}[0,T]' class='latex' />. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p><strong>Remark 7.</strong> It was recently shown <a class="snap_noshots" href="http://arxiv.org/abs/0706.1594">by Zhang</a> that the monotonicity properties of the quantities <img src='http://s0.wp.com/latex.php?latex=%5Cmu%28M%2Cg%2C%5Ctau%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;mu(M,g,&#92;tau)' title='&#92;mu(M,g,&#92;tau)' class='latex' /> also hold for Ricci flows with surgery.  This should enable one to completely replace all applications of Perelman reduced volume in the existing proof of the Poincaré conjecture in the literature by Perelman (as well as in the expositions of <a class="snap_noshots" href="http://arxiv.org/abs/math.DG/0605667">Kleiner-Lott</a>, <a class="snap_noshots" href="http://arxiv.org/abs/math/0612069">Cao-Zhu</a>, and <a class="snap_noshots" href="http://arxiv.org/abs/math/0607607">Morgan-Tian</a>) by Perelman entropy, which may lead to a shorter proof overall (although one still needs the Perelman reduced length for another purpose, namely to control the geometry of ancient non-collapsed Ricci flows).  However, we shall mostly follow the original arguments of Perelman in this course. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p><strong>Remark 8. </strong>The above entropy functionals are also useful for studying the forward or backward heat equation on a static Riemannian manifold <img src='http://s0.wp.com/latex.php?latex=%28M%2Cg%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M,g)' title='(M,g)' class='latex' /> (basically, one keeps the heat-type equations for u or f but now replace Ricci flow by the trivial flow <img src='http://s0.wp.com/latex.php?latex=%5Cdot+g+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;dot g = 0' title='&#92;dot g = 0' class='latex' />).  However, some sign assumptions on curvature are now needed to recover the same type of monotonicity results.  See this <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2030576">paper of Ni</a> for details. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>[<em>Update</em>, April 25: some corrections.]</p>
]]></content:encoded>
</item>
<item>
<title><![CDATA[285G, Lecture 7: Rescaling of Ricci flows and κ-noncollapsing]]></title>
<link>http://terrytao.wordpress.com/2008/04/20/285g-lecture-7-rescaling-of-ricci-flows-and-kappa-noncollapsing/</link>
<pubDate>Mon, 21 Apr 2008 04:58:35 +0000</pubDate>
<dc:creator>Terence Tao</dc:creator>
<guid>http://terrytao.wordpress.com/2008/04/20/285g-lecture-7-rescaling-of-ricci-flows-and-kappa-noncollapsing/</guid>
<description><![CDATA[We now set aside our discussion of the finite time extinction results for Ricci flow with surgery (T]]></description>
<content:encoded><![CDATA[<p>We now set aside our discussion of the finite time extinction results for Ricci flow with surgery (Theorem 4 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/01/285g-lecture-2-the-ricci-flow-approach-to-the-poincare-conjecture/">Lecture 2</a>), and turn instead to the main portion of Perelman&#8217;s argument, which is to establish the global existence result for Ricci flow with surgery (Theorem 2 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/01/285g-lecture-2-the-ricci-flow-approach-to-the-poincare-conjecture/">Lecture 2</a>), as well as the discreteness of the surgery times (Theorem 3 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/01/285g-lecture-2-the-ricci-flow-approach-to-the-poincare-conjecture/">Lecture 2</a>).</p>
<p>As mentioned in <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/03/28/285g-lecture-1-ricci-flow/">Lecture 1</a>, <em>local</em> existence of the Ricci flow is a fairly standard application of nonlinear parabolic theory, once one uses de Turck&#8217;s trick to transform Ricci flow into an explicitly parabolic equation.  The trouble is, of course, that Ricci flow can and does develop singularities (indeed, we have just spent several lectures showing that singularities must inevitably develop when certain topological hypotheses (e.g. simple connectedness) or geometric hypotheses (e.g. positive scalar curvature) occur).  In principle, one can use surgery to remove the most singular parts of the manifold at every singularity time and then restart the Ricci flow, but in order to do this one needs some rather precise control on the geometry and topology of these singular regions.  (In particular, there are some hypothetical bad singularity scenarios which cannot be easily removed by surgery, due to topological obstructions; a major difficulty in the Perelman program is to show that such scenarios in fact cannot occur in a Ricci flow.)</p>
<p>In order to analyse these singularities, Hamilton and then Perelman employed the standard nonlinear PDE technique of &#8220;blowing up&#8221; the singularity using the scaling symmetry, and then exploiting as much &#8220;compactness&#8221; as is available in order to extract an &#8220;asymptotic profile&#8221; of that singularity from a sequence of such blowups, which had better properties than the original Ricci flow.  [The PDE notion of a blowing up a solution around a singularity, by the way, is vaguely analogous to the algebraic geometry notion of <a href="http://en.wikipedia.org/wiki/Blowing_up">blowing up</a> a variety around a singularity, though the two notions are certainly not identical.] A sufficiently good classification of all the possible asymptotic profiles will, in principle, lead to enough structural properties on general singularities to Ricci flow that one can see how to perform surgery in a manner which controls both the geometry and the topology.</p>
<p>However, in order to carry out this program it is necessary to obtain geometric control on the Ricci flow which does not deteriorate when one blows up the solution; in the jargon of nonlinear PDE, we need to obtain bounds on some quantity which is both <em>coercive</em> (it bounds the geometry) and either <em>critical</em> (it is essentially invariant under rescaling) or <em>subcritical</em> (it becomes more powerful when one blows up the solution) with respect to the scaling symmetry.  The discovery of controlled quantities for Ricci flow which were simultaneously coercive and critical was Perelman&#8217;s first major breakthrough in the subject (previously known controlled quantities were either supercritical or only partially coercive); it made it possible, at least <em>in principle</em>, to analyse general singularities of Ricci flow and thus to begin the surgery program discussed above.  (In contrast, the main reason why questions such as <a class="snap_noshots" href="http://terrytao.wordpress.com/2007/03/18/why-global-regularity-for-navier-stokes-is-hard/">Navier-Stokes global regularity are so difficult</a> is that no controlled quantity which is both coercive and critical or subcritical is known.)  The mere existence of such a quantity does not by any means establish global existence of Ricci flow with surgery immediately, but it does give one a non-trivial starting point from which one can hope to make progress.</p>
<p><!--more--></p>
<p>To be a more precise, recall from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/03/28/285g-lecture-1-ricci-flow/">Lecture 1</a> that the Ricci flow equation <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bd%7D%7Bdt%7D+g+%3D+-2+%5Chbox%7BRic%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;frac{d}{dt} g = -2 &#92;hbox{Ric}' title='&#92;frac{d}{dt} g = -2 &#92;hbox{Ric}' class='latex' />, in any spatial dimension d, has two basic symmetries (besides the geometric symmetry of diffeomorphism invariance); it has the obvious time-translation symmetry <img src='http://s0.wp.com/latex.php?latex=g%28t%29+%5Cmapsto+g%28t-t_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='g(t) &#92;mapsto g(t-t_0)' title='g(t) &#92;mapsto g(t-t_0)' class='latex' /> (keeping the manifold M fixed), but it also has the scaling symmetry</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=g%28t%29+%5Cmapsto+%5Clambda%5E2+g%28+%5Cfrac%7Bt%7D%7B%5Clambda%5E2%7D+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='g(t) &#92;mapsto &#92;lambda^2 g( &#92;frac{t}{&#92;lambda^2} )' title='g(t) &#92;mapsto &#92;lambda^2 g( &#92;frac{t}{&#92;lambda^2} )' class='latex' /> (1)</p>
<p>for any <img src='http://s0.wp.com/latex.php?latex=%5Clambda+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;lambda &gt; 0' title='&#92;lambda &gt; 0' class='latex' /> (again keeping M fixed as a topological manifold).  When applied with <img src='http://s0.wp.com/latex.php?latex=%5Clambda+%26%2360%3B+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;lambda &lt; 1' title='&#92;lambda &lt; 1' class='latex' />, this scaling shrinks all lengths on the manifold M by a factor <img src='http://s0.wp.com/latex.php?latex=%5Clambda&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;lambda' title='&#92;lambda' class='latex' /> (recall that the length <img src='http://s0.wp.com/latex.php?latex=%26%23124%3Bv%26%23124%3B_g&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;v&#124;_g' title='&#124;v&#124;_g' class='latex' /> of a tangent vector v is given by the <em>square root</em> of <img src='http://s0.wp.com/latex.php?latex=g%28v%2Cv%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='g(v,v)' title='g(v,v)' class='latex' />), and also speeds up the flow of time by a factor <img src='http://s0.wp.com/latex.php?latex=1%2F%5Clambda%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='1/&#92;lambda^2' title='1/&#92;lambda^2' class='latex' />; conversely, when applied with <img src='http://s0.wp.com/latex.php?latex=%5Clambda+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;lambda &gt; 0' title='&#92;lambda &gt; 0' class='latex' />, the scaling expands all lengths by a factor <img src='http://s0.wp.com/latex.php?latex=%5Clambda&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;lambda' title='&#92;lambda' class='latex' />, and slows down the flow of time by <img src='http://s0.wp.com/latex.php?latex=1%2F%5Clambda%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='1/&#92;lambda^2' title='1/&#92;lambda^2' class='latex' />.</p>
<p>Suppose now that one has a Ricci flow <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> which becomes singular at some time T &#62; 0.  To analyse the behaviour of the flow as one approaches the singular time T, one picks a sequence of times <img src='http://s0.wp.com/latex.php?latex=t_n+%5Cto+T%5E-&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_n &#92;to T^-' title='t_n &#92;to T^-' class='latex' /> approaching T from below, a sequence of marked points <img src='http://s0.wp.com/latex.php?latex=x_n+%5Cin+M%28t_n%29+%3D+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_n &#92;in M(t_n) = M' title='x_n &#92;in M(t_n) = M' class='latex' /> on the manifold, and a sequence of length scales <img src='http://s0.wp.com/latex.php?latex=L_n+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='L_n &gt; 0' title='L_n &gt; 0' class='latex' /> which go to zero as <img src='http://s0.wp.com/latex.php?latex=n+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='n &#92;to &#92;infty' title='n &#92;to &#92;infty' class='latex' />.  One then considers the blown up Ricci flows <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%5E%7B%28n%29%7D%2C+g%5E%7B%28n%29%7D%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M^{(n)}, g^{(n)}(t))' title='t &#92;mapsto (M^{(n)}, g^{(n)}(t))' class='latex' />, where <img src='http://s0.wp.com/latex.php?latex=M%5E%7B%28n%29%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M^{(n)}' title='M^{(n)}' class='latex' /> is equal to M as a topological manifold (with <img src='http://s0.wp.com/latex.php?latex=x_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_n' title='x_n' class='latex' /> as a marked point or &#8220;origin&#8221; O), and <img src='http://s0.wp.com/latex.php?latex=g%5E%7B%28n%29%7D%28t%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='g^{(n)}(t)' title='g^{(n)}(t)' class='latex' /> is the flow of metrics given by the formula</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=g%5E%7B%28n%29%7D%28t%29+%3A%3D+%5Cfrac%7B1%7D%7BL_n%5E2%7D+g%28+t_n+%2B+L_n%5E2+t+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='g^{(n)}(t) := &#92;frac{1}{L_n^2} g( t_n + L_n^2 t )' title='g^{(n)}(t) := &#92;frac{1}{L_n^2} g( t_n + L_n^2 t )' class='latex' />. (2)</p>
<p>Thus the flow <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%5E%7B%28n%29%7D%2C+g%5E%7B%28n%29%7D%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M^{(n)}, g^{(n)}(t))' title='t &#92;mapsto (M^{(n)}, g^{(n)}(t))' class='latex' /> represents a renormalised flow in which the time <img src='http://s0.wp.com/latex.php?latex=t_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t_n' title='t_n' class='latex' /> has been redesignated as the temporal origin 0, the point <img src='http://s0.wp.com/latex.php?latex=x_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x_n' title='x_n' class='latex' /> has been redesignated as the spatial origin O, and the length scale <img src='http://s0.wp.com/latex.php?latex=L_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='L_n' title='L_n' class='latex' /> has been redesignated as the unit length scale (and the time scale <img src='http://s0.wp.com/latex.php?latex=L_n%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='L_n^2' title='L_n^2' class='latex' /><br />
has been redesignated as the unit time scale).  Thus the behaviour of the rescaled flow <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%5E%7B%28n%29%7D%2C+g%5E%7B%28n%29%7D%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M^{(n)}, g^{(n)}(t))' title='t &#92;mapsto (M^{(n)}, g^{(n)}(t))' class='latex' />at unit scales of space and time around the spacetime origin (thus <img src='http://s0.wp.com/latex.php?latex=t+%3D+O%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t = O(1)' title='t = O(1)' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=x+%5Cin+B%28O%2CO%281%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x &#92;in B(O,O(1))' title='x &#92;in B(O,O(1))' class='latex' />) correspond to the behaviour of the original flow <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28T%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(T))' title='t &#92;mapsto (M,g(T))' class='latex' /> at spatial scale <img src='http://s0.wp.com/latex.php?latex=L_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='L_n' title='L_n' class='latex' /> and time scale <img src='http://s0.wp.com/latex.php?latex=L_n%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='L_n^2' title='L_n^2' class='latex' /> around the spacetime point <img src='http://s0.wp.com/latex.php?latex=%28t_n%2Cx_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_n,x_n)' title='(t_n,x_n)' class='latex' />, thus <img src='http://s0.wp.com/latex.php?latex=t+%3D+t_n+%2B+O%28+L_n%5E2+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t = t_n + O( L_n^2 )' title='t = t_n + O( L_n^2 )' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=x+%5Cin+B%28x_n%2CO%28L_n%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='x &#92;in B(x_n,O(L_n))' title='x &#92;in B(x_n,O(L_n))' class='latex' />.</p>
<p>Because the original Ricci flow existed on the time interval <img src='http://s0.wp.com/latex.php?latex=0+%5Cleq+t+%26%2360%3B+T&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='0 &#92;leq t &lt; T' title='0 &#92;leq t &lt; T' class='latex' />, the rescaled Ricci flow will exist on the time interval <img src='http://s0.wp.com/latex.php?latex=-%5Cfrac%7Bt_n%7D%7BL_n%5E2%7D+%5Cleq+t+%26%2360%3B+%5Cfrac%7BT-t_n%7D%7BL_n%5E2%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='-&#92;frac{t_n}{L_n^2} &#92;leq t &lt; &#92;frac{T-t_n}{L_n^2}' title='-&#92;frac{t_n}{L_n^2} &#92;leq t &lt; &#92;frac{T-t_n}{L_n^2}' class='latex' />.  In particular, in the limit <img src='http://s0.wp.com/latex.php?latex=n+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='n &#92;to &#92;infty' title='n &#92;to &#92;infty' class='latex' /> (leaving aside for the moment the question of what &#8220;limit&#8221; means precisely here), these Ricci flows become increasingly <em>ancient</em>, in that they will have existed on the entire past time interval <img src='http://s0.wp.com/latex.php?latex=-%5Cinfty+%26%2360%3B+t+%5Cleq+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='-&#92;infty &lt; t &#92;leq 0' title='-&#92;infty &lt; t &#92;leq 0' class='latex' /> in the limit.</p>
<p>The strategy is now to show that these renormalised Ricci flows <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%5E%7B%28n%29%7D%2Cg%5E%7B%28n%29%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M^{(n)},g^{(n)})' title='t &#92;mapsto (M^{(n)},g^{(n)})' class='latex' /> (with the marked origin O) exhibit enough &#8220;compactness&#8221; that there exists a subsequence of such flows which converge to some asymptotic limiting profile <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%5E%7B%28%5Cinfty%29%7D%2C+g%5E%7B%28%5Cinfty%29%7D%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M^{(&#92;infty)}, g^{(&#92;infty)})' title='t &#92;mapsto (M^{(&#92;infty)}, g^{(&#92;infty)})' class='latex' /> in some sense.  (We will define the precise notion of convergence of such flows later, but <a href="http://en.wikipedia.org/wiki/Gromov%E2%80%93Hausdorff_convergence">pointed Gromov-Hausdorff convergence</a> is a good first approximation of the convergence concept to keep in mind for now.)  If the notion of convergence is strong enough, then we will be able to conclude that this limiting profile of Ricci flows is also a Ricci flow.  (Actually, due to the parabolic smoothing effects of Ricci flow, we will be able to automatically upgrade weak notions of convergence to strong ones, and so this step is in fact rather easy.)  This limiting Ricci flow has better properties than the renormalised flows; for instance, while the renormalised flows are almost ancient, the limiting flow actually <em>is</em> an ancient solution.  Also, while the Hamilton-Ivey pinching phenomenon from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/04/285g-lecture-3-the-maximum-principle-and-the-pinching-phenomenon/">Lecture 3 </a>suggests that the renormalised flows have mostly non-negative curvature, the limiting flow will have everywhere non-negative curvature (provided that the points <img src='http://s0.wp.com/latex.php?latex=%28t_n%2Cx_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_n,x_n)' title='(t_n,x_n)' class='latex' /> and scales <img src='http://s0.wp.com/latex.php?latex=L_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='L_n' title='L_n' class='latex' /> are chosen properly; we will return to this &#8220;point-picking&#8221; issue later in this course).</p>
<p>If one was able to classify all possible asymptotic profiles to Ricci flow, this would yield quite a bit of information on singularities to such flows, by the standard and general nonlinear PDE method of <em>compactness and contradiction</em>.  This method, roughly speaking, runs as follows.  Suppose we want to claim that whenever one is sufficiently close to a singularity, some scale-invariant property P eventually occurs.  (In our specific application, P is roughly speaking going to assert that the geometry and topology of high-curvature regions can be classified as belonging to one of a short list of possible &#8220;canonical neighbourhood&#8221; types, all of which turn out to be amenable to surgery.)  To prove this, we argue by contradiction, assuming we can find a Ricci flow <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> in which P fails on a sequence of points in spacetime that approach the singularity, and on some sequence of scales going to zero.  We then rescale the flow to create a sequence of rescaled Ricci flows <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%5E%7B%28n%29%7D%2Cg%5E%7B%28n%29%7D%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M^{(n)},g^{(n)}(t))' title='t &#92;mapsto (M^{(n)},g^{(n)}(t))' class='latex' /> as discussed above, each of which exhibits failure of P at unit scales near the origin (here we use the hypothesis that P is scale-invariant).  Now, we use compactness to find a subsequence of flows converging to an asymptotic profile <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%5E%7B%28%5Cinfty%29%7D%2C+g%5E%7B%28%5Cinfty%29%7D%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M^{(&#92;infty)}, g^{(&#92;infty)}(t))' title='t &#92;mapsto (M^{(&#92;infty)}, g^{(&#92;infty)}(t))' class='latex' />.  If the convergence is strong enough, the asymptotic profile will also exhibit failure of P.  But now one simply goes through the list of all possible profiles in one&#8217;s classification and verifies that each of them obeys P; and one is done.</p>
<p>Unfortunately, just knowing that a Ricci flow is ancient and has everywhere non-negative curvature does not seem enough, by itself, to obtain a full classification of asymptotic profiles (though one can definitely say some non-trivial statements about ancient Ricci flows with non-negative curvature, most notably the <em>Li-Yau-Hamilton inequality</em>, which we will discuss later).  To proceed further, one needs further control on asymptotic profiles <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%5E%7B%28%5Cinfty%29%7D%2C+g%5E%7B%28%5Cinfty%29%7D%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M^{(&#92;infty)}, g^{(&#92;infty)}(t))' title='t &#92;mapsto (M^{(&#92;infty)}, g^{(&#92;infty)}(t))' class='latex' />.  The only reasonable way to obtain such control is to obtain control on the rescaled flows <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%5E%7B%28n%29%7D%2C+g%5E%7B%28n%29%7D%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M^{(n)}, g^{(n)}(t))' title='t &#92;mapsto (M^{(n)}, g^{(n)}(t))' class='latex' /> which is uniform in n.  While some control of this sort can be established merely by choosing the points <img src='http://s0.wp.com/latex.php?latex=%28t_n%2Cx_n%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(t_n,x_n)' title='(t_n,x_n)' class='latex' /> and scales <img src='http://s0.wp.com/latex.php?latex=L_n&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='L_n' title='L_n' class='latex' /> in a clever manner, there is a limit as to what one can accomplish just by point-picking alone (especially if one is interested in establishing properties P that apply to quite general regions of spacetime and general scales, rather than specific, hand-picked regions and scales).  To really get good control on the rescaled flows <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%5E%7B%28n%29%7D%2C+g%5E%7B%28n%29%7D%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M^{(n)}, g^{(n)}(t))' title='t &#92;mapsto (M^{(n)}, g^{(n)}(t))' class='latex' />, one needs to obtain control on the original flow <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> which does not deteriorate when one passes from the original flow to the rescaled flow.</p>
<p>One can express what &#8220;does not deteriorate&#8221; means more precisely using the language of <a href="http://en.wikipedia.org/wiki/Dimensional_analysis">dimensional analysis</a>, or more precisely using the concepts of subcriticality, criticality, and supercriticality from nonlinear PDE.  Suppose we have some (non-negative) scalar quantity <img src='http://s0.wp.com/latex.php?latex=F%28+M%2C+g%28%5Ccdot%29+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='F( M, g(&#92;cdot) )' title='F( M, g(&#92;cdot) )' class='latex' /> that measures some aspect of a flow <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2C+g%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M, g(t))' title='t &#92;mapsto (M, g(t))' class='latex' />.  [Dimensional analysis becomes trickier when considering tensor-valued quantities, though in practice one can use the magnitude of such quantities as a scalar-valued proxy for these tensor-valued objects; see <a class="snap_noshots" href="http://arxiv.org/abs/math/0610903">my paper on Perelman's argument</a> for some further discussion.] In many situations, this quantity has some specific <em>dimension</em> k, in the sense that one has a scaling relationship</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=F%28+M%2C+%5Clambda%5E2+g%28+%5Cfrac%7B%5Ccdot%7D%7B%5Clambda%5E2%7D+%29+%29+%3D+%5Clambda%5Ek+F%28+M%2C+g%28%5Ccdot%29+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='F( M, &#92;lambda^2 g( &#92;frac{&#92;cdot}{&#92;lambda^2} ) ) = &#92;lambda^k F( M, g(&#92;cdot) )' title='F( M, &#92;lambda^2 g( &#92;frac{&#92;cdot}{&#92;lambda^2} ) ) = &#92;lambda^k F( M, g(&#92;cdot) )' class='latex' /> (3)</p>
<p>that measures how that quantity changes under the rescaling (1).  In dimensional analysis language, (3) asserts that F has the units <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7Blength%7D%5Ek&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{length}^k' title='&#92;hbox{length}^k' class='latex' />.</p>
<p>Assuming that F is also invariant under time translation (and under changes of spatial origin), (3) implies that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=F%28+M%5E%7B%28n%29%7D%2C+g%5E%7B%28n%29%7D%28%5Ccdot%29+%29+%3D+L_n%5E%7B-k%7D+F%28+M%2C+g%28%5Ccdot%29+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='F( M^{(n)}, g^{(n)}(&#92;cdot) ) = L_n^{-k} F( M, g(&#92;cdot) )' title='F( M^{(n)}, g^{(n)}(&#92;cdot) ) = L_n^{-k} F( M, g(&#92;cdot) )' class='latex' />. (4)</p>
<p>Thus, if F is <em>critical</em> or <a href="http://en.wikipedia.org/wiki/Dimensionless_quantity">dimensionless</a> (which means that k=0) or <em>subcritical</em> (which means that <img src='http://s0.wp.com/latex.php?latex=k+%26%2360%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='k &lt; 0' title='k &lt; 0' class='latex' />), any upper bound on F for the original Ricci flow <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2Cg%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M,g(t))' title='t &#92;mapsto (M,g(t))' class='latex' /> will imply uniform bounds on the rescaled flows <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%5E%7B%28n%29%7D%2Cg%5E%7B%28n%29%7D%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M^{(n)},g^{(n)}(t))' title='t &#92;mapsto (M^{(n)},g^{(n)}(t))' class='latex' />, and thus (assuming the convergence is strong enough, and F has some good continuity properties) on the asymptotic profile <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%5E%7B%28%5Cinfty%29%7D%2C+g%5E%7B%28%5Cinfty%29%7D%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M^{(&#92;infty)}, g^{(&#92;infty)}(t))' title='t &#92;mapsto (M^{(&#92;infty)}, g^{(&#92;infty)}(t))' class='latex' />.  In the subcritical case, F should in fact now vanish in the limit.  On the other hand, if F is <em>supercritical</em> (which means that <img src='http://s0.wp.com/latex.php?latex=k+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='k &gt; 0' title='k &gt; 0' class='latex' />) then no information about the asymptotic profile <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%5E%7B%28%5Cinfty%29%7D%2C+g%5E%7B%28%5Cinfty%29%7D%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M^{(&#92;infty)}, g^{(&#92;infty)}(t))' title='t &#92;mapsto (M^{(&#92;infty)}, g^{(&#92;infty)}(t))' class='latex' /> is obtained.</p>
<p>In order for control of <img src='http://s0.wp.com/latex.php?latex=F%28M%5E%7B%28%5Cinfty%29%7D%2C+g%5E%7B%28%5Cinfty%29%7D%28%5Ccdot%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='F(M^{(&#92;infty)}, g^{(&#92;infty)}(&#92;cdot))' title='F(M^{(&#92;infty)}, g^{(&#92;infty)}(&#92;cdot))' class='latex' /> to be truly useful, we would like the quantity F to be <em>coercive</em>.  This term is not precisely defined (though it is somewhat analogous to the notion of a <a href="http://en.wikipedia.org/wiki/Proper_map">proper map</a>), but coercivity basically means that upper bounds on <img src='http://s0.wp.com/latex.php?latex=F%28M%2C+g%28%5Ccdot%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='F(M, g(&#92;cdot))' title='F(M, g(&#92;cdot))' class='latex' /> translate to some upper bounds on various norms or similar quantities measuring the &#8220;size&#8221; of <img src='http://s0.wp.com/latex.php?latex=%28M%2C+g%28%5Ccdot%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M, g(&#92;cdot))' title='(M, g(&#92;cdot))' class='latex' />, and (hopefully) to then obtain useful bounds on the topology and geometry of <img src='http://s0.wp.com/latex.php?latex=%28M%2C+g%28%5Ccdot%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M, g(&#92;cdot))' title='(M, g(&#92;cdot))' class='latex' />.</p>
<p>Let us give some examples of various such quantities F for Ricci flow.  We begin with some supercritical quantities:</p>
<ol>
<li>Any length-type quantity, e.g. the diameter <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7Bdiam%7D%28M%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{diam}(M)' title='&#92;hbox{diam}(M)' class='latex' /> of the manifold, or the <a href="http://en.wikipedia.org/wiki/Injectivity_radius">injectivity radius</a>, has dimension 1 and is thus supercritical.</li>
<li>The various widths <img src='http://s0.wp.com/latex.php?latex=W_2%28t%29%2C+W_3%28t%29%2C+%5Ctilde+W_3%28t%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='W_2(t), W_3(t), &#92;tilde W_3(t)' title='W_2(t), W_3(t), &#92;tilde W_3(t)' class='latex' /> of 3-dimensional Ricci flows from the previous lectures, which were based on areas of minimal surfaces, have dimension 2 and are also supercritical.   Thus the various bounds we have on these quantities from Lectures <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/11/285g-lecture-4-finite-time-extinction-of-the-second-homotopy-group/">4</a>, <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/15/285g-lecture-5-finite-time-extinction-of-the-third-homotopy-group-i/">5</a>, <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/18/285g-lecture-6-finite-time-extinction-of-the-third-homotopy-group-ii/">6</a> do not directly tell us anything about asymptotic profiles.</li>
<li>The volume <img src='http://s0.wp.com/latex.php?latex=%5Cint_M%5C+d%5Cmu&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;int_M&#92; d&#92;mu' title='&#92;int_M&#92; d&#92;mu' class='latex' /> of 3-manifolds has dimension 3 and is thus also supercritical.  Thus upper bounds on volume, such as Corollary 2 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/04/285g-lecture-3-the-maximum-principle-and-the-pinching-phenomenon/">Lecture 3</a>, do not directly tell us anything about asymptotic profiles (though they are useful for other tasks, most notably for ensuring that surgery times are discrete, see Theorem 3 from <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/01/285g-lecture-2-the-ricci-flow-approach-to-the-poincare-conjecture/">Lecture 2</a>).</li>
</ol>
<p>As for subcritical quantities, one notable one is the minimal scalar curvature <img src='http://s0.wp.com/latex.php?latex=R_%7B%5Chbox%7Bmin%7D%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R_{&#92;hbox{min}}' title='R_{&#92;hbox{min}}' class='latex' />.  One can check (cf. the dimensional analysis at the end of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/03/26/285g-lecture-0-riemannian-manifolds-and-curvature/">Lecture 0</a>)<br />
that scalar curvature has dimension -2 and is thus subcritical.  The quantity <img src='http://s0.wp.com/latex.php?latex=F%28M%2C+g%28%5Ccdot%29%29+%3A%3D+%5Csup_t+%5Cmax%28+-+R_%7B%5Chbox%7Bmin%7D%7D%2C+0+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='F(M, g(&#92;cdot)) := &#92;sup_t &#92;max( - R_{&#92;hbox{min}}, 0 )' title='F(M, g(&#92;cdot)) := &#92;sup_t &#92;max( - R_{&#92;hbox{min}}, 0 )' class='latex' />, that measures the maximal amount of negative scalar curvature present in a Ricci flow, is then bounded (by the maximum principle, see Proposition 2 of <a class="snap_noshots" href="http://terrytao.wordpress.com/2008/04/04/285g-lecture-3-the-maximum-principle-and-the-pinching-phenomenon/">Lecture 3</a>), and so by the previous discussion will vanish for asymptotic profiles; in other words, asymptotic profiles always have non-negative scalar curvature.    Unfortunately, this quantity is only partially coercive; it prevents scalar curvature from becoming arbitrarily large and negative, but does not prevent scalar curvature from becoming arbitrarily large and positive.  (Also, it is possible for other curvatures, such as Ricci and Riemann curvatures, to be large even while the scalar curvature is small or even zero.)  So this quantity does say something non-trivial about asymptotic profiles, but is insufficient by itself to fully control such profiles.</p>
<p>In the next lecture we shall see that the least eigenvalue <img src='http://s0.wp.com/latex.php?latex=%5Clambda_1%28+-4%5CDelta+%2B+R+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;lambda_1( -4&#92;Delta + R )' title='&#92;lambda_1( -4&#92;Delta + R )' class='latex' /> of the modified Laplace-Beltrami operator, which can be viewed as an analytic analogue of the geometric quantity <img src='http://s0.wp.com/latex.php?latex=R_%7B%5Cmin%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R_{&#92;min}' title='R_{&#92;min}' class='latex' /> related to Poincaré inequalities, also enjoys a monotonicity property (which is connected to a certain gradient flow interpretation of (modified) Ricci flow); like <img src='http://s0.wp.com/latex.php?latex=R_%7B%5Cmin%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='R_{&#92;min}' title='R_{&#92;min}' class='latex' />, the least eigenvalue has dimension -2 and is thus also subcritical, but again it is not fully coercive, as it only prevents scalar curvature from becoming too negative.</p>
<p>So far we have not discussed any critical quantities.  (One can create some trivial examples of critical quantities, such as the dimension <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7Bdim%7D%28M%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{dim}(M)' title='&#92;hbox{dim}(M)' class='latex' /> or topological quantities such as <img src='http://s0.wp.com/latex.php?latex=%5Cpi_1%28M%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;pi_1(M)' title='&#92;pi_1(M)' class='latex' />, but these are not obviously coercive (the topological coercivity of the latter quantity being, of course, precisely the Poincaré conjecture that we are trying to prove!).)    One way to create critical quantities is to somehow combine subcritical and supercritical examples together.  Here is one simple example, due <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=1714939">to Hamilton</a>:</p>
<p><strong>Exercise 1. </strong> Show that the quantity <img src='http://s0.wp.com/latex.php?latex=%5Cmax%28+-+R_%7B%5Cmin%7D%28t%29+V%28t%29%5E%7B2%2Fd%7D%2C+0+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;max( - R_{&#92;min}(t) V(t)^{2/d}, 0 )' title='&#92;max( - R_{&#92;min}(t) V(t)^{2/d}, 0 )' class='latex' /> is critical  (scale-invariant) and monotone non-increasing in time under d-dimensional Ricci flow, where <img src='http://s0.wp.com/latex.php?latex=V+%3D+%5Cint_M%5C+d%5Cmu%28t%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='V = &#92;int_M&#92; d&#92;mu(t)' title='V = &#92;int_M&#92; d&#92;mu(t)' class='latex' /> denotes the volume of <img src='http://s0.wp.com/latex.php?latex=%28M%2C+g%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(M, g(t))' title='(M, g(t))' class='latex' /> at time t. (This quantity can be used, for instance, to show that Ricci flow admits no &#8220;breather&#8221; solutions, i.e. non-constant periodic solutions; see the discussion in <a class="snap_noshots" href="http://arxiv.org/abs/math/0211159">Perelman&#8217;s paper</a>.  Unfortunately, as with previous examples, it is not fully coercive.) <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>In the next few lectures, we will see two more advanced versions of critical controlled quantities of an analytic nature, the <em>Perelman entropy</em> (a scale-invariant version of the minimal eigenvalue <img src='http://s0.wp.com/latex.php?latex=%5Clambda_1%28+-4%5CDelta+%2B+R+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;lambda_1( -4&#92;Delta + R )' title='&#92;lambda_1( -4&#92;Delta + R )' class='latex' />, which is to log-Sobolev inequalities as the latter quantity is to Poincaré inequalities) and the <em>Perelman reduced volume</em> (which measures how heat-type kernels on Ricci flows compare against heat kernels on Euclidean space).   These quantities were both introduced in <a class="snap_noshots" href="http://arxiv.org/abs/math/0211159">Perelman&#8217;s first paper</a>.  The key feature of these new critical quantities, which distinguishes them from previously known examples, is that they are now <em>coercive</em>: they provide a crucial scale-invariant geometric control on a flow <img src='http://s0.wp.com/latex.php?latex=t+%5Cmapsto+%28M%2C+g%28t%29%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='t &#92;mapsto (M, g(t))' title='t &#92;mapsto (M, g(t))' class='latex' />, which is now known as <em><img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' />-noncollapsing</em>.  This control, which describes a relationship between the supercritical quantities of length and volume and the subcritical quantities of curvature, will be discussed next.</p>
<p style="text-align:center;">&#8211; Length, volume, curvature, and collapsing &#8211;</p>
<p style="text-align:left;">Let p be a point in a d-dimensional complete Riemannian manifold (M,g) (we make no assumptions on the dimension d here).  We will establish here some basic results in <em>comparison geometry</em>, which seeks to understand the relationship between the Riemann curvature <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BRiem%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Riem}' title='&#92;hbox{Riem}' class='latex' /> of the manifold M, and various geometric quantities of M such as the volume of balls and the injectivity radius, especially when compared against model geometries such as the sphere and hyperbolic space.  (This is only a brief introduction; see e.g. Chapters 6, 9, and 10 of <a class="snap_noshots" href="http://www.ams.org/mathscinet-getitem?mr=2243772">Petersen&#8217;s book</a> for a more detailed treatment.)</p>
<p style="text-align:left;">Of course, in the case of Euclidean space <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+R%7D%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb R}^d' title='{&#92;Bbb R}^d' class='latex' /> with the Euclidean metric, the Riemann curvature is identically zero, and the volume of B(p,r) is <img src='http://s0.wp.com/latex.php?latex=c_d+r%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='c_d r^d' title='c_d r^d' class='latex' /> for some explicit constant <img src='http://s0.wp.com/latex.php?latex=c_d+%3A%3D+%5Cfrac%7B%5Cpi%5E%7Bd%2F2%7D%7D%7B%5CGamma%28%5Cfrac%7Bd%7D%7B2%7D%2B1%29%7D+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='c_d := &#92;frac{&#92;pi^{d/2}}{&#92;Gamma(&#92;frac{d}{2}+1)} &gt; 0' title='c_d := &#92;frac{&#92;pi^{d/2}}{&#92;Gamma(&#92;frac{d}{2}+1)} &gt; 0' class='latex' /> depending only on dimension.  For Riemannian manifolds, it is easy to see that the volume of B(p,r) is <img src='http://s0.wp.com/latex.php?latex=%281%2Bo%281%29%29+c_d+r%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(1+o(1)) c_d r^d' title='(1+o(1)) c_d r^d' class='latex' /> in the limit <img src='http://s0.wp.com/latex.php?latex=r+%5Cto+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r &#92;to 0' title='r &#92;to 0' class='latex' />; for more precise asymptotics, see Exercises 7 and 8 below.</p>
<p style="text-align:left;">One of the most effective tools to study these questions comes from <a href="http://en.wikipedia.org/wiki/Normal_coordinates">normal coordinates</a>, or more precisely from the <a href="http://en.wikipedia.org/wiki/Exponential_map">exponential map</a> <img src='http://s0.wp.com/latex.php?latex=%5Cexp_p%3A+T_p+M+%5Cto+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;exp_p: T_p M &#92;to M' title='&#92;exp_p: T_p M &#92;to M' class='latex' /> from the tangent space <img src='http://s0.wp.com/latex.php?latex=T_p+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='T_p M' title='T_p M' class='latex' /> to M, defined by setting <img src='http://s0.wp.com/latex.php?latex=%5Cexp_p%28v%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;exp_p(v)' title='&#92;exp_p(v)' class='latex' /> to be the value of <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%281%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma(1)' title='&#92;gamma(1)' class='latex' />, where <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%3A%5B0%2C1%5D+%5Cto+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma:[0,1] &#92;to M' title='&#92;gamma:[0,1] &#92;to M' class='latex' /> is the unique constant-speed geodesic with <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%280%29%3Dp&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma(0)=p' title='&#92;gamma(0)=p' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%27%280%29%3Dv&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;gamma&#039;(0)=v' title='&#92;gamma&#039;(0)=v' class='latex' />.  By the <a href="http://en.wikipedia.org/wiki/Hopf%E2%80%93Rinow_theorem">Hopf-Rinow theorem</a>, M is complete (in the metric sense) if and only if the exponential map is defined on all of <img src='http://s0.wp.com/latex.php?latex=T_p+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='T_p M' title='T_p M' class='latex' />.  Henceforth we will always assume M to be complete.  The ball <img src='http://s0.wp.com/latex.php?latex=B%28p%2Cr%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B(p,r)' title='B(p,r)' class='latex' /> of radius <img src='http://s0.wp.com/latex.php?latex=r+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r &gt; 0' title='r &gt; 0' class='latex' /> in M centred at p is then the image under the exponential map of the ball <img src='http://s0.wp.com/latex.php?latex=B_%7BT_p+M%7D%280%2Cr%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_{T_p M}(0,r)' title='B_{T_p M}(0,r)' class='latex' /> of the tangent space of the same radius (using the metric <img src='http://s0.wp.com/latex.php?latex=g%28p%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='g(p)' title='g(p)' class='latex' />, of course):</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=B%28p%2Cr%29+%3D+%5Cexp_p%28+B_%7BT_p+M%7D%280%2Cr%29+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B(p,r) = &#92;exp_p( B_{T_p M}(0,r) )' title='B(p,r) = &#92;exp_p( B_{T_p M}(0,r) )' class='latex' />. (5)</p>
<p style="text-align:left;">Thus we can study the balls centred at p by using the exponential map to pull back to the tangent space <img src='http://s0.wp.com/latex.php?latex=T_p+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='T_p M' title='T_p M' class='latex' /> and analysing the geometry there.  Two radii become relevant for this approach:</p>
<ol>
<li>The <em>injectivity radius</em> at p is the supremum of all radii r such that <img src='http://s0.wp.com/latex.php?latex=%5Cexp_p&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;exp_p' title='&#92;exp_p' class='latex' /> is injective on <img src='http://s0.wp.com/latex.php?latex=B_%7BT_p+M%7D%280%2Cr%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_{T_p M}(0,r)' title='B_{T_p M}(0,r)' class='latex' />.</li>
<li>The <em>conjugate radius</em> at p is the supremum of all radii r such that <img src='http://s0.wp.com/latex.php?latex=%5Cexp_p&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;exp_p' title='&#92;exp_p' class='latex' /> is an <a href="http://en.wikipedia.org/wiki/Immersion_%28mathematics%29">immersion</a> on <img src='http://s0.wp.com/latex.php?latex=B_%7BT_p+M%7D%280%2Cr%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B_{T_p M}(0,r)' title='B_{T_p M}(0,r)' class='latex' />.</li>
</ol>
<p>In many situations, these two radii are equal, but there are cases in which the injectivity radius is smaller. In fact the injectivity radius is always less than or equal to the conjugate radius; see Exercise 4 below.</p>
<p><strong>Example 1.</strong> (Sphere) Let <img src='http://s0.wp.com/latex.php?latex=K+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='K &gt; 0' title='K &gt; 0' class='latex' />, and let <img src='http://s0.wp.com/latex.php?latex=M+%3D+%5Cfrac%7B1%7D%7B%5Csqrt%7BK%7D%7D+S%5Ed+%3A%3D+%5C%7B+%28x_1%2C%5Cldots%2Cx_%7Bd%2B1%7D%29+%5Cin+%7B%5CBbb+R%7D%5E%7Bd%2B1%7D%3A+x_1%5E2+%2B+%5Cldots+%2B+x_%7Bd%2B1%7D%5E2+%3D+1%2FK+%5C%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M = &#92;frac{1}{&#92;sqrt{K}} S^d := &#92;{ (x_1,&#92;ldots,x_{d+1}) &#92;in {&#92;Bbb R}^{d+1}: x_1^2 + &#92;ldots + x_{d+1}^2 = 1/K &#92;}' title='M = &#92;frac{1}{&#92;sqrt{K}} S^d := &#92;{ (x_1,&#92;ldots,x_{d+1}) &#92;in {&#92;Bbb R}^{d+1}: x_1^2 + &#92;ldots + x_{d+1}^2 = 1/K &#92;}' class='latex' /> be the sphere of radius <img src='http://s0.wp.com/latex.php?latex=1%2F%5Csqrt%7BK%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='1/&#92;sqrt{K}' title='1/&#92;sqrt{K}' class='latex' />, with the metric induced from the metric <img src='http://s0.wp.com/latex.php?latex=ds%5E2+%3D+dx_1%5E2+%2B+%5Cldots+%2B+dx_%7Bd%2B1%7D%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='ds^2 = dx_1^2 + &#92;ldots + dx_{d+1}^2' title='ds^2 = dx_1^2 + &#92;ldots + dx_{d+1}^2' class='latex' /> of Euclidean space <img src='http://s0.wp.com/latex.php?latex=%7B%5CBbb+R%7D%5E%7Bd%2B1%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;Bbb R}^{d+1}' title='{&#92;Bbb R}^{d+1}' class='latex' />.  Then at every point p of M, the injectivity radius and conjugate radius are both equal to <img src='http://s0.wp.com/latex.php?latex=%5Cpi%2F%5Csqrt%7BK%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;pi/&#92;sqrt{K}' title='&#92;pi/&#92;sqrt{K}' class='latex' />, which is also the diameter of the manifold.  Note also that this manifold has constant sectional curvature K. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p><strong>Example 2.</strong> (Hyperbolic space) Let <img src='http://s0.wp.com/latex.php?latex=K+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='K &gt; 0' title='K &gt; 0' class='latex' />, and let <img src='http://s0.wp.com/latex.php?latex=M+%3D+%5Cfrac%7B1%7D%7B%5Csqrt%7BK%7D%7D+H%5Ed+%3A%3D+%5C%7B+%28t%2Cx_1%2C%5Cldots%2Cx_d%29+%5Cin+%7B%5CBbb+R%7D%5E%7B1%2Bd%7D%3A+x_1%5E2+%2B+%5Cldots+x_d+-+t%5E2+%3D+1%2FK+%3B+t+%26%2362%3B+0+%5C%7D+%5Csubset+%7B%5CBbb+R%7D%5E%7B1%2Bd%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M = &#92;frac{1}{&#92;sqrt{K}} H^d := &#92;{ (t,x_1,&#92;ldots,x_d) &#92;in {&#92;Bbb R}^{1+d}: x_1^2 + &#92;ldots x_d - t^2 = 1/K ; t &gt; 0 &#92;} &#92;subset {&#92;Bbb R}^{1+d}' title='M = &#92;frac{1}{&#92;sqrt{K}} H^d := &#92;{ (t,x_1,&#92;ldots,x_d) &#92;in {&#92;Bbb R}^{1+d}: x_1^2 + &#92;ldots x_d - t^2 = 1/K ; t &gt; 0 &#92;} &#92;subset {&#92;Bbb R}^{1+d}' class='latex' /> be hyperbolic space of hyperbolic radius <img src='http://s0.wp.com/latex.php?latex=1%2F%5Csqrt%7BK%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='1/&#92;sqrt{K}' title='1/&#92;sqrt{K}' class='latex' />, with the metric induced from the metric <img src='http://s0.wp.com/latex.php?latex=ds%5E2+%3D+dx_1%5E2+%2B+%5Cldots+%2B+dx_d%5E2+-+dt%5E2&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='ds^2 = dx_1^2 + &#92;ldots + dx_d^2 - dt^2' title='ds^2 = dx_1^2 + &#92;ldots + dx_d^2 - dt^2' class='latex' /> of Minkowski space.  Then at any point p in M, e.g. p = (1,0), the injectivity radius, conjugate radius, and diameter are infinite.  This manifold has constant sectional curvature -K. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p><strong>Example 3. </strong>(Torus)  Let <img src='http://s0.wp.com/latex.php?latex=r+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r &gt; 0' title='r &gt; 0' class='latex' />, and let <img src='http://s0.wp.com/latex.php?latex=M+%3D+%28%7B%5CBbb+R%7D%2Fr%7B%5CBbb+Z%7D%29%5Ed&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='M = ({&#92;Bbb R}/r{&#92;Bbb Z})^d' title='M = ({&#92;Bbb R}/r{&#92;Bbb Z})^d' class='latex' /> be the d-torus which is the product of d circles of length r.  Then for any point p in M, the injectivity radius is r/2 and the conjugate radius is infinite.  Here the sectional curvature is of course 0 everywhere. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>The metric g on M induces a pullback metric on <img src='http://s0.wp.com/latex.php?latex=T_p+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='T_p M' title='T_p M' class='latex' />, which by abuse of notation we shall also call g.  This metric can degenerate once one passes the conjugate radius, but let us ignore this issue for the time being.  On <img src='http://s0.wp.com/latex.php?latex=T_p+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='T_p M' title='T_p M' class='latex' />, we have the radial variable r (defined as the magnitude of a tangent vector with respect to g(p)), and the radial vector field <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_r&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_r' title='&#92;partial_r' class='latex' /> (defined as the dual vector field to r using polar coordinates), which is smooth away from the origin.</p>
<p>In Euclidean space, the vector field <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_r&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_r' title='&#92;partial_r' class='latex' /> is the gradient of r.  Happily, the same fact is true for more general Riemannian manifolds:</p>
<blockquote><p><strong>Lemma 1.</strong> (Gauss lemma)</p>
<ol>
<li>Away from the origin, we have <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Cpartial_r%26%23124%3B_g+%3D+1&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;partial_r&#124;_g = 1' title='&#124;&#92;partial_r&#124;_g = 1' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Cnabla_%7B%5Cpartial_r%7D+%5Cpartial_r+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_{&#92;partial_r} &#92;partial_r = 0' title='&#92;nabla_{&#92;partial_r} &#92;partial_r = 0' class='latex' />.</li>
<li>Away from the origin, <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_r&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_r' title='&#92;partial_r' class='latex' /> is the gradient <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7Bgrad%7D+r&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{grad} r' title='&#92;hbox{grad} r' class='latex' /> of r with respect to the metric g, thus <img src='http://s0.wp.com/latex.php?latex=%28%5Cpartial_r%29%5E%5Calpha+%3D+%5Cnabla%5E%5Calpha+r&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='(&#92;partial_r)^&#92;alpha = &#92;nabla^&#92;alpha r' title='(&#92;partial_r)^&#92;alpha = &#92;nabla^&#92;alpha r' class='latex' />.</li>
</ol>
</blockquote>
<p><strong>Exercise 2.</strong> Prove Lemma 1.  (Hint: part 1 follows from the geodesic flow equation <img src='http://s0.wp.com/latex.php?latex=%5Cnabla_%7B%5Cdot+%5Cgamma%7D+%5Cdot+%5Cgamma+%3D+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_{&#92;dot &#92;gamma} &#92;dot &#92;gamma = 0' title='&#92;nabla_{&#92;dot &#92;gamma} &#92;dot &#92;gamma = 0' class='latex' />.  For part 2, one way to proceed is to establish the ODE</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cnabla_%7B%5Cpartial_r%7D+%28+%5Cpartial_r+-+%5Chbox%7Bgrad%7D+r+%29%5E%5Calpha+%3D+%28%5Cnabla%5E%5Calpha+%28%5Cpartial_r%29_%5Cbeta%29+%28+%5Cpartial_r+-+%5Chbox%7Bgrad%7D+r+%29%5E%5Cbeta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_{&#92;partial_r} ( &#92;partial_r - &#92;hbox{grad} r )^&#92;alpha = (&#92;nabla^&#92;alpha (&#92;partial_r)_&#92;beta) ( &#92;partial_r - &#92;hbox{grad} r )^&#92;beta' title='&#92;nabla_{&#92;partial_r} ( &#92;partial_r - &#92;hbox{grad} r )^&#92;alpha = (&#92;nabla^&#92;alpha (&#92;partial_r)_&#92;beta) ( &#92;partial_r - &#92;hbox{grad} r )^&#92;beta' class='latex' /> (6)</p>
<p>and then apply Gronwall&#8217;s inequality. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p>Lemma 1 gives some important relationships between the radial vector field <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_r&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_r' title='&#92;partial_r' class='latex' /> and the Hessian <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BHess%7D%28r%29_%7B%5Calpha+%5Cbeta%7D+%3A%3D+%5Cnabla_%5Calpha+%5Cnabla_%5Cbeta+r+%3D+%5Cnabla_%5Calpha+%28%5Cpartial_r%29_%5Cbeta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Hess}(r)_{&#92;alpha &#92;beta} := &#92;nabla_&#92;alpha &#92;nabla_&#92;beta r = &#92;nabla_&#92;alpha (&#92;partial_r)_&#92;beta' title='&#92;hbox{Hess}(r)_{&#92;alpha &#92;beta} := &#92;nabla_&#92;alpha &#92;nabla_&#92;beta r = &#92;nabla_&#92;alpha (&#92;partial_r)_&#92;beta' class='latex' /> (which can be viewed as the second fundamental form of the spheres centred at p):</p>
<p><strong>Exercise 3. </strong>Away from the origin, obtain the deformation formula</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%7B%5Cmathcal+L%7D_%7B%5Cpartial_r%7D+g+%3D+2+%5Chbox%7BHess%7D%28r%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='{&#92;mathcal L}_{&#92;partial_r} g = 2 &#92;hbox{Hess}(r)' title='{&#92;mathcal L}_{&#92;partial_r} g = 2 &#92;hbox{Hess}(r)' class='latex' /> (7)</p>
<p>and the <a href="http://en.wikipedia.org/wiki/Riccati_equation">Riccati-type equation<br />
</a></p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cnabla_%7B%5Cpartial_r%7D+%5Chbox%7BHess%7D_%7B%5Calpha+%5Cbeta%7D+%2B%5Chbox%7BHess%7D_%7B%5Calpha+%5Cbeta%7D+%5Chbox%7BHess%7D%5E%5Cbeta_%5Cgamma+%3D+%5Chbox%7BRiem%7D_%7B%5Calpha%5Cgamma%5Cbeta%7D%5E%5Cdelta+%28%5Cpartial_r%29%5E%5Cgamma+%28%5Cpartial_r%29_%5Cdelta&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;nabla_{&#92;partial_r} &#92;hbox{Hess}_{&#92;alpha &#92;beta} +&#92;hbox{Hess}_{&#92;alpha &#92;beta} &#92;hbox{Hess}^&#92;beta_&#92;gamma = &#92;hbox{Riem}_{&#92;alpha&#92;gamma&#92;beta}^&#92;delta (&#92;partial_r)^&#92;gamma (&#92;partial_r)_&#92;delta' title='&#92;nabla_{&#92;partial_r} &#92;hbox{Hess}_{&#92;alpha &#92;beta} +&#92;hbox{Hess}_{&#92;alpha &#92;beta} &#92;hbox{Hess}^&#92;beta_&#92;gamma = &#92;hbox{Riem}_{&#92;alpha&#92;gamma&#92;beta}^&#92;delta (&#92;partial_r)^&#92;gamma (&#92;partial_r)_&#92;delta' class='latex' />.  <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /> (8)</p>
<p style="text-align:left;">Also, show that <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BHess%7D_%7B%5Calpha+%5Cbeta%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Hess}_{&#92;alpha &#92;beta}' title='&#92;hbox{Hess}_{&#92;alpha &#92;beta}' class='latex' /> has <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_r&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;partial_r' title='&#92;partial_r' class='latex' /> as a null eigenvector. <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p><strong>Exercise 4.</strong> Show that the injectivity radius <img src='http://s0.wp.com/latex.php?latex=r_i&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_i' title='r_i' class='latex' /> of a point p cannot exceed the conjugacy radius <img src='http://s0.wp.com/latex.php?latex=r_c&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_c' title='r_c' class='latex' />.  (Hint: there are several ways to establish this.  Here is one: suppose for contradiction that  <img src='http://s0.wp.com/latex.php?latex=r_i+%26%2362%3B+r_c&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_i &gt; r_c' title='r_i &gt; r_c' class='latex' />, thus <img src='http://s0.wp.com/latex.php?latex=r_i+%26%2362%3B+%281%2B%5Cvarepsilon%29+r_c&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_i &gt; (1+&#92;varepsilon) r_c' title='r_i &gt; (1+&#92;varepsilon) r_c' class='latex' /> for some small <img src='http://s0.wp.com/latex.php?latex=%5Cvarepsilon+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;varepsilon &gt; 0' title='&#92;varepsilon &gt; 0' class='latex' />.  Let <img src='http://s0.wp.com/latex.php?latex=v+%5Cin+T_p+M&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='v &#92;in T_p M' title='v &#92;in T_p M' class='latex' /> be a vector of magnitude at most <img src='http://s0.wp.com/latex.php?latex=r_c&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_c' title='r_c' class='latex' />.  Observe that the function <img src='http://s0.wp.com/latex.php?latex=d%28p%2C+x%29+%2B+d%28+%5Cexp_p%28%281%2B%5Cvarepsilon%29+v%29%2C+x%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='d(p, x) + d( &#92;exp_p((1+&#92;varepsilon) v), x)' title='d(p, x) + d( &#92;exp_p((1+&#92;varepsilon) v), x)' class='latex' /> achieves a global minimum at <img src='http://s0.wp.com/latex.php?latex=%5Cexp_p%28v%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;exp_p(v)' title='&#92;exp_p(v)' class='latex' /> whenever and so has non-negative Hessian.  Use this to obtain a lower bound on <img src='http://s0.wp.com/latex.php?latex=%5Chbox%7BHess%7D%28r%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;hbox{Hess}(r)' title='&#92;hbox{Hess}(r)' class='latex' /> on <img src='http://s0.wp.com/latex.php?latex=B%28p%2Cr_c%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B(p,r_c)' title='B(p,r_c)' class='latex' />, and combine this with Exercise 3 to show that the exponential map is in fact immersed on a neighbourhood of <img src='http://s0.wp.com/latex.php?latex=B%28p%2Cr_c%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B(p,r_c)' title='B(p,r_c)' class='latex' />, a contradiction.  Another approach is based on Klingenberg&#8217;s inequality (see Lemma 2 below), while a third approach is based on the second variation formula for the energy of a geodesic.) <img src='http://s0.wp.com/latex.php?latex=%5Cdiamond&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;diamond' title='&#92;diamond' class='latex' /></p>
<p style="text-align:left;">Let us now impose the bound that all sectional curvatures are bounded by some <img src='http://s0.wp.com/latex.php?latex=K+%26%2362%3B+0&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='K &gt; 0' title='K &gt; 0' class='latex' /> on a ball <img src='http://s0.wp.com/latex.php?latex=B%28p%2Cr_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B(p,r_0)' title='B(p,r_0)' class='latex' />, thus</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%26%23124%3Bg%28+%5Chbox%7BRiem%7D%28X%2CY%29+X%2C+Y%29%26%23124%3B+%5Cleq+K&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;g( &#92;hbox{Riem}(X,Y) X, Y)&#124; &#92;leq K' title='&#124;g( &#92;hbox{Riem}(X,Y) X, Y)&#124; &#92;leq K' class='latex' /> (9)</p>
<p style="text-align:left;">for all orthonormal tangent vectors X, Y at any point in <img src='http://s0.wp.com/latex.php?latex=B%28p%2Cr_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B(p,r_0)' title='B(p,r_0)' class='latex' />.  From Example 1 we know that the exponential map can become singular past the radius <img src='http://s0.wp.com/latex.php?latex=%5Cpi%2F%5Csqrt%7BK%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#92;pi/&#92;sqrt{K}' title='&#92;pi/&#92;sqrt{K}' class='latex' />, so let us also assume that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=r_0+%5Cleq+%5Cpi%2F%5Csqrt%7BK%7D&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='r_0 &#92;leq &#92;pi/&#92;sqrt{K}' title='r_0 &#92;leq &#92;pi/&#92;sqrt{K}' class='latex' />. (10)</p>
<p style="text-align:left;">Note that the sectional curvature bound also implies a Ricci curvature bound <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Chbox%7BRic%7D%28X%2CX%29%26%23124%3B+%5Cleq+%28d-1%29K&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;hbox{Ric}(X,X)&#124; &#92;leq (d-1)K' title='&#124;&#92;hbox{Ric}(X,X)&#124; &#92;leq (d-1)K' class='latex' /> for all unit tangent vectors based in <img src='http://s0.wp.com/latex.php?latex=B%28p%2Cr_0%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='B(p,r_0)' title='B(p,r_0)' class='latex' />.</p>
<p style="text-align:left;">From (9) and (10) we see that <img src='http://s0.wp.com/latex.php?latex=%26%23124%3B%5Chbox%7BRiem%7D%26%23124%3B_g+%3D+O_d%28+r_0%5E%7B-2%7D+%29&amp;bg=ffffff&amp;fg=000&amp;s=0' alt='&#124;&#92;hbox{Riem}&#124;_g = O_d( r_0^{-2} )' title='&#124;&#92;hbox{Riem}&#124;_g = O_d( r_0^{-2} )' class='latex' /> on the ball <img src=