We construct the spanning tree T of G. We can construct a hamiltonian cycle in the easily.… more →
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mhedayat wrote 2 years ago: As of August 27, 2007 the Bankruptcy Court for the Northern Dstrict of Illinois, Eastern Division, r … more →
yuhanlyu wrote 2 years ago: We construct the spanning tree T of G. We can construct a hamiltonian cycle in the easily. … more →
yuhanlyu wrote 2 years ago: If P=NP, then NP=co-NP, contradiction. … more →
yuhanlyu wrote 2 years ago: If we can solve problem in polynomial time, then we can verify it in polynomial time. … more →
yuhanlyu wrote 2 years ago: If φ is not tautology, then there is at least one assignment can’t satisfy φ. … more →
yuhanlyu wrote 2 years ago: Run topological sort first. If there is a hamiltonian path, then the graph has a linear ordering and … more →
yuhanlyu wrote 2 years ago: Like hamiltonian cycle, we can verify it easily. … more →
yuhanlyu wrote 2 years ago: Enumerate all the possible certificate and verify it. … more →
yuhanlyu wrote 2 years ago: NP = coNP is an open problem. … more →
yuhanlyu wrote 2 years ago: If we delete the edge and the result graph has hamiitonian cycle, then the edge is useless. We delet … more →
yuhanlyu wrote 2 years ago: Because bipartite graph does not have odd length cycle, it has no Hamitonian cycle. … more →
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