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<channel>
	<title>cs &amp;laquo; WordPress.com Tag Feed</title>
	<link>http://en.wordpress.com/tag/cs/</link>
	<description>Feed of posts on WordPress.com tagged "cs"</description>
	<pubDate>Mon, 30 Nov 2009 07:40:26 +0000</pubDate>

	<generator>http://en.wordpress.com/tags/</generator>
	<language>en</language>

<item>
<title><![CDATA[Wonder why games aren't taken seriously?]]></title>
<link>http://mertesgameblog.wordpress.com/2009/11/30/i-wonder-why-games-arent-taken-seriously/</link>
<pubDate>Mon, 30 Nov 2009 01:04:20 +0000</pubDate>
<dc:creator>Merte</dc:creator>
<guid>http://mertesgameblog.wordpress.com/2009/11/30/i-wonder-why-games-arent-taken-seriously/</guid>
<description><![CDATA[Some hobbies are taken seriously, some are not. Some sports are taken seriously, some are not. Gamin]]></description>
<content:encoded><![CDATA[<div class='snap_preview'><p><img class="alignnone size-full wp-image-120" title="cs tournement russia" src="http://mertesgameblog.wordpress.com/files/2009/11/cs-tournement-russia.png" alt="" width="600" height="337" /></p>
<p style="text-align:justify;">Some hobbies are taken seriously, some are not. Some sports are taken seriously, some are not. Gaming is an activity popularly (and perhaps ignorantly) connected to immature and pubertal males. Why? Well, gaming tournaments like <a href="http://englishrussia.com/?p=5750">these</a> definitly don&#8217;t help.</p>
<p style="text-align:justify;"><strong>Game conventions like E3 are, to a large extent, the very display window of the game industry. And what would a gaming convention be without pleasant looking women with big boobs? Unheard of to most participants. We want to looka at new games, and we want them to be surrounded by half naked women.</strong></p>
<p style="text-align:justify;">A book convention or a film convention would be a much more classy experience. Why can&#8217;t games be classy? Well, that&#8217;s a good question. When a Counter Strike championship is taking place, and a pair of naked women start to rub themselves up against the competitors, in order to destract and test team loyalty, then <em>serious </em>isn&#8217;t exactly the first word that comes to mind.</p>
<p style="text-align:justify;">When will the gaming industry grow up? Not in a while, it seems.</p>
</div>]]></content:encoded>
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<item>
<title><![CDATA[So Disappointed!]]></title>
<link>http://sidestreetbooks.wordpress.com/2009/11/29/so-disappointed/</link>
<pubDate>Sun, 29 Nov 2009 20:51:08 +0000</pubDate>
<dc:creator>sidestreetbooks</dc:creator>
<guid>http://sidestreetbooks.wordpress.com/2009/11/29/so-disappointed/</guid>
<description><![CDATA[My family has not heard a word about the dogs we have applied for four days ago.  I do realize that ]]></description>
<content:encoded><![CDATA[<div class='snap_preview'><p>My family has not heard a word about the dogs we have applied for four days ago.  I do realize that it is the Thanksgiving holiday weekend, but I was hoping to hear something, anything from someone, anyone who could grant my family the wish of a dog.  One gal only needed to reply to an e-mail message!  But, it was not meant to be.  I guess that by not hearing anything, I have my answer, but I am deeply disappointed in the level of customer service in this day and age.  After all, I am a living, breathing prospect.  Shouldn&#8217;t the sellers be courting me with, &#8220;Gee, I see you applied for Sophie.  She&#8217;s not available, but we have Frank who has similar qualities.  Do you want to come see?  We are open from 10-3 today.&#8221;  How hard is that?</p>
<p>Maybe I have spent too many hours reading books about customer service, public relations, and marketing, and I know how these people <em>&#8220;should&#8221;</em> behave, but see that maybe my values newly acquired from various authors are not shared by the rescue organizations.  Sure, they&#8217;re great at push advertising (putting dogs and cats on TV morning shows and on Craig&#8217;s List), but where are their social marketing skills in this new era of marketing and retaining customers?</p>
<div id="attachment_42" class="wp-caption alignleft" style="width: 108px"><a href="http://www.amazon.com/New-Rules-Marketing-PR-Podcasting/dp/0470379286?&#38;camp=212361&#38;linkCode=wsw&#38;tag=sidstrboo02-20&#38;creative=380785"><img class="size-full wp-image-42" title="New Rules of Marketing Book" src="http://sidestreetbooks.wordpress.com/files/2009/11/new-rules-of-marketing-book1.jpg" alt="" width="98" height="136" /></a><p class="wp-caption-text">New Rules of Marketing &#38; PR</p></div>
<p>I learned the most relevant and easy-to-apply skills from David Meerman Scott who wrote <a title="The New Rules of Marketing" href="http://www.amazon.com/New-Rules-Marketing-PR-Podcasting/dp/0470379286?&#38;camp=212361&#38;linkCode=wsw&#38;tag=sidstrboo02-20&#38;creative=380785" target="_blank">The New Rules of Marketing and PR:  How to Use News Releases, Blogs, Podcasting, Viral Marketing &#38; Online Media to Reach Buyers Directly</a>.  I have quoted Mr. Scott so often that his ears must be burning nonstop.  He is also one of the most prolific posters on Facebook, and he is a real, down-to-earth, guy.  He lives and breathes what he writes about.  I e-mailed him and he e-mailed me back personally.  I tweeted the fact that I was reading his book, <a title="World Wide Rave" href="http://www.amazon.com/World-Wide-Rave-Creating-Triggers/dp/0470395001?&#38;camp=212361&#38;linkCode=wsw&#38;tag=sidstrboo02-20&#38;creative=380785" target="_blank">World Wide Rave</a>, and he actually contacted me to find out if I liked the book.  And I don&#8217;t mean a day later, or a week later, he responded within hours.  I wasn&#8217;t even looking for a response to my tweet, but there it was.  And what reaction does Mr. Scott have on me?  I am a raving fan!</p>
<p>This is how the animal rescue societies should deal with live leads; they might even send fewer dogs to their deaths.  Just something to think about.</p>
</div>]]></content:encoded>
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<item>
<title><![CDATA[x3Guard v3.1]]></title>
<link>http://x3uqm4.wordpress.com/2009/11/29/x3guard-v3-1/</link>
<pubDate>Sun, 29 Nov 2009 18:02:38 +0000</pubDate>
<dc:creator>x3uqm4</dc:creator>
<guid>http://x3uqm4.wordpress.com/2009/11/29/x3guard-v3-1/</guid>
<description><![CDATA[x3Guard v3.1 Sürümü. ~ Anti Speed Hack Değiştirildi. + Anti Speed Fire Eklendi, Speed Hack kullanara]]></description>
<content:encoded><![CDATA[<div class='snap_preview'><p>x3Guard v3.1 Sürümü.</p>
<p>~ Anti Speed Hack Değiştirildi.<br />
+ Anti Speed Fire Eklendi, Speed Hack kullanarak hızlı ateş edenler tespit edilebilinecek.<br />
+ Anti WallHack`deki buglar düzeltildi.<br />
+ Anti NameSpam Eklendi, sürekli isim değiştirenler 30 dakika banlanır.<br />
+ Daha fazla hile engellemesi.<br />
+ Anti Aim Tespit seviyesi yukseltildi, anında tespit yapılıyor.<br />
+ cl_bob, cl_bobcycle, cl_bobup, gl_max_size, gl_polyoffset, gl_overbright, gamma, brightness, gl_fog, gl_flipmatrix<br />
Komutları engellendi.</p>
<p>İndirme linki;<br />
Anti AimBot ile Anti Speed Hack`in çakışması sonucu oluşan AimBot`u banlama yüzünden kullanım dışıdır.</p>
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<item>
<title><![CDATA[Remote Participation UDS Lucid Lynx]]></title>
<link>http://pendulumtech.wordpress.com/2009/11/28/uds-lucid-lynx/</link>
<pubDate>Sat, 28 Nov 2009 16:17:59 +0000</pubDate>
<dc:creator>pendulumtech</dc:creator>
<guid>http://pendulumtech.wordpress.com/2009/11/28/uds-lucid-lynx/</guid>
<description><![CDATA[Obviously as I&#8217;m very new to being involved in the Ubuntu community, I didn&#8217;t go to Dall]]></description>
<content:encoded><![CDATA[<div class='snap_preview'><p>Obviously as I&#8217;m very new to being involved in the Ubuntu community, I didn&#8217;t go to Dallas for UDS Lucid Lynx earlier this month, however, I did decide to do as much remote participation as I could. I was quite surprised and pleased by how well remote participation was set up and how well it worked. The Ubuntu Wiki page about <a href="https://wiki.ubuntu.com/UDS-L/RemoteParticipation">remote participation</a> was useful, although the best guide in terms of laying it out plainly was Laura Czajkwoski&#8217;s <a href="http://www.lczajkowski.com/2009/11/12/how-to-participate-remotely-and-get-your-points-heard/">How to participate remotely and get your points heard</a>. Laura did a good guide with helpful suggestions such as joining IRC channels for the sessions you want to attend a head of time.</p>
<p>The hardest part for me was that I was in work or commuting during most of the hours that UDS was happening. I am allowed to listen to things while at work so I set up so I could listen to the icecasts. I did my best to balance listening to the ice casts and getting my work done with occasional moments of actually saying something on IRC.</p>
<p>Generally I thought the integration of those participating remotely with the people physically at the sessions was good. There were some communication issues, but not many. The one that bothered me the most wasn&#8217;t even one that effected me. One of the sessions decided to turn off their mic and essentially have a closed session. However, this was not announced anywhere so someone started asking in the IRC channel for the room the session was in and in #ubuntu-uds about the mic being off. Finally someone else who&#8217;d overheard discussion in a hallway about how the session leaders wanted to have a closed session said something in #ubuntu-uds. It would have taken less than a minute for it to be announced in the IRC channel (preferably both in the channel for the room and in #ubuntu-uds).</p>
<p>I pretty much followed the community track since I&#8217;m not really technical and that&#8217;s where most of the discussions I was interested in were happening. Highlights for me included all of the Ubuntu Women sessions;  I feel like real work and progress was made in just putting together a really concrete plan for what is needed in the next few months to get the project back on track and keep it there. While I didn&#8217;t get to pay attention as much as I&#8217;d have liked to, the Ubuntu NGO session also seemed to go well. The Community Roundtables were also good, however, I was a bit confused about why they didn&#8217;t start on Monday. To me it would have made sense to have had the first one on Monday to really give a roadmap for the week.</p>
<p>I know at other times I&#8217;ve had more to say about UDS that I can&#8217;t think of right now and I&#8217;m sure that another post will happen at some other point. I do want to say how much I enjoyed being able to participate remotely and how much I did feel a part of things. It definitely exceeded my expectations going in.</p>
</div>]]></content:encoded>
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<item>
<title><![CDATA[Zur Krise der Medien - Ein Beispiel: Das Magazin]]></title>
<link>http://philippe-wampfler.com/2009/11/28/zur-krise-der-medien-ein-beispiel-das-magazin/</link>
<pubDate>Sat, 28 Nov 2009 14:28:06 +0000</pubDate>
<dc:creator>phwampfler</dc:creator>
<guid>http://philippe-wampfler.com/2009/11/28/zur-krise-der-medien-ein-beispiel-das-magazin/</guid>
<description><![CDATA[Die WoZ dieser Woche ist als »WoZ Spezial« erschienen &#8211; und behandelt die Krise der Medien: Ei]]></description>
<content:encoded><![CDATA[<div class='snap_preview'><p>Die WoZ dieser Woche ist als »WoZ Spezial« erschienen &#8211; und behandelt die Krise der Medien: Eine Krise, die nicht nur durch den Einbruch am Werbemarkt entstanden ist, sondern aus mehreren Gründen zu einer Erosion journalistischer Standards und zu einer Preisgabe der Wertschätzung und des traditionellen Selbstverständnisses von Journalisten, wie Kurt Imhof im <a href="http://www.nzz.ch/nachrichten/kultur/medien/froehlich_im_falschen_leben_1.4025816.html">Interview mit der NZZ</a> festgehalten hat. In einer Umfrage hat er ermittelt, dass gerade den News-JournalistInnen von Gratiszeitungen und Lokalradios klassische journalistische Werte fehlten, sie sich andererseits aber mit ihrem Beruf identifizierten, und so, wenn sie zu »seriöseren« Medien wechseln, dieser Kultur mitnehmen. Imhof bilanziert:</p>
<blockquote>
<div>Das braucht es: Zunächst die Erinnerung an die uralte Einsicht der liberalen Aufklärungsbewegung, dass die Qualität der öffentlichen Kommunikation die Qualität der Demokratie bedingtes braucht auch die ebenso alte Einsicht, dass diese Aufgabe weder ein blosses Geschäft noch eine Aufgabe des Staats sein kann. Daraus folgt auf der strukturellen Seite die Reduktion der Abhängigkeit des Qualitätsjournalismus von Werbeeinnahmen, und zwar durch öffentliche Mittel und Stiftungsmittel sowie durch eine Steigerung der Verkaufspreise, durch den Abbau der Selbstkannibalisierung des Journalismus durch Gratismedien und durch die Lösung der indirekten Bindung der Einnahmen des öffentlichen Rundfunks an Einschaltquoten. Auf der kulturellen Seite ist ein gesteigertes Qualitätsbewusstsein für Journalismus aufseiten der Macher wie des Publikums Voraussetzung wie Produkt der genannten strukturellen Massnahmen.</div>
</blockquote>
<div>Zurück zur WoZ. In der Analyse der sich immer mehr verschiebenden Schnittstelle PR &#8211; Journalismus bemerkt <a href="http://www.woz.ch/artikel/2009/nr48/schweiz/18647.html">Susan Boos</a> einleitend:</div>
<div></div>
<blockquote>
<div>Der König hält sich Hofberichterstatter, der Diktator verfügt Zensur, und die Demokratie braucht kritischen, unabhängigen Journalismus, würde man meinen. Inzwischen ist aber vieles durcheinandergeraten wie zum Beispiel beim «Magazin» des «Tages-Anzeigers» vom 7. November. Auf dem Titelblatt sind lange Beine in Stilettos abgebildet, nur Beine, kein Kopf. Auf der nächsten Seite zwei dünne Frauen, viel Bein und Stilettos. Auf Seite drei kommt das eigentliche Titelblatt mit einem älteren Herrn in Trenchcoat, darunter das Zitat: «Auschwitz war für mich ein Gewinn.»</div>
<div>
<p>Das sitzt: «H&#38;M»-Werbung verschränkt mit Auschwitz. Der ungarische Schriftsteller und Nobelpreisträger Imre Kértesz, der Auschwitz überlebt hat, muss gegen die mageren Models des Modehauses antreten – das lässt sich kaum toppen.</p>
</div>
<div>Doch wem fällt es noch auf?</div>
</blockquote>
<div>Antwort: Mir ist das heute aufgefallen, und zwar erstens wieder auf der verdammten Titelseite (ich würde gerne eine andere Wortwahl vornehmen, aber es gelingt mir nicht: Wie kann<em> Das Magazin</em> die Titelseite verkaufen?):</div>
<div><a href="http://phwampfler.wordpress.com/files/2009/11/mag1.jpg"><img class="aligncenter size-full wp-image-576" title="mag1" src="http://phwampfler.wordpress.com/files/2009/11/mag1.jpg" alt="" width="331" height="476" /></a>Und zweitens beim Text von Daniel Binswanger. Zwar setzt er sich gewohnt kritisch-fundiert mit der Rolle der Schweizer Großbanken auseinander, nennt aber sowohl UBS als auch CS im Titel und siehe da &#8211; beim Stichwort »Lobbying-Offensive« platziert die CS doch auch gleich ein Inserat neben diesem Artikel. Die Frage, ob das Huhn (der Text) oder das Ei (die Inserentin) zuerst gewesen seien, drängt sich beängstigenderweise auf.</div>
<div><a href="http://phwampfler.wordpress.com/files/2009/11/mag2.jpg"><img class="aligncenter size-full wp-image-577" title="mag2" src="http://phwampfler.wordpress.com/files/2009/11/mag2.jpg" alt="" width="450" height="337" /></a>Es bleibt: Das werbefreie Internet (Kurzanleitung: Firefox installieren, AdBlockPlus installieren, Filterliste abonnieren, fertig) &#8211; bei dem zwar Artikel von Inserierenden eingekauft sein mögen &#8211;  und die WoZ.<br />
Noch ein P.S.:   </div>
<p><a href="http://phwampfler.files.wordpress.com/2009/11/p_480_320_8603b0dc-50af-414e-a264-01490801f693.jpeg"><img src="http://phwampfler.files.wordpress.com/2009/11/p_480_320_8603b0dc-50af-414e-a264-01490801f693.jpeg?w=200&#038;h=300" alt="" width="200" height="300" class="alignnone size-full wp-image-364" /></a></p>
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<title><![CDATA[MultiHack [HCMHIK] - sXe-Injected 8.4]]></title>
<link>http://cheatscs.wordpress.com/2009/11/27/multihack-hcmhik-sxe-injected-8-4/</link>
<pubDate>Fri, 27 Nov 2009 22:12:44 +0000</pubDate>
<dc:creator>krezz</dc:creator>
<guid>http://cheatscs.wordpress.com/2009/11/27/multihack-hcmhik-sxe-injected-8-4/</guid>
<description><![CDATA[MultiHack [HCMHIK] working with sXe-Injected 8.4 &#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;]]></description>
<content:encoded><![CDATA[<div class='snap_preview'><p>MultiHack [HCMHIK] working with sXe-Injected 8.4<br />
&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;<br />
www.SiCheats.com<br />
&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;<br />
www.YouTube.com/MatekHaxior<br />
&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;</p>
<p>*****<br />
INFO:<br />
*****<br />
This is MultiHack for sXe-Injected 8.4. Also this hack is working with all sXe-Injected from sXe-Injected 1.0 to 8.4.</p>
<p><strong>MultiHack Functions:           <em>&#60; Características do hack</em></strong><br />
- WallHack (3 Modes To Choose)<br />
- No Smoke<br />
- No Flash<br />
- No Sky<br />
- Lambert<br />
- New crossHair<br />
- AntiLocal Ban (BETA Version)</p>
<p><strong>INSTRUCTIONS:                &#60; <em>Instruções</em></strong><br />
*************<br />
1. Copy INSTALADOR.exe to the folder where you have HL.exe file<br />
2. Run INSTALADOR.exe and press INSTALAR button, then close INSTALADOR<br />
3. Run sXe-Injected 8.4<br />
4. Start Counter-Strike<br />
5. When Counter-Strike starts a small window will pop up in the top-left<br />
corner of the screen. Click on CARGAR CHEAT button, click OK and in new window choose sxe84.dll and click OPEN<br />
6. Now connect to any server with sXe-Injected 8.4 protection or without this protection<br />
7. In the game press F4 key to show HACK MENU. Choose and enable any options by your mouse.</p>
<p>-português:<br />
1- copie o INSTALADOR.exe para a pasta do CS (aonde fica o arquivo HL.exe)<br />
2- Rode o INSTALADOR.EXE e aperte em Instalar, depois feche o instalador<br />
3- Rode o SXE 8.4<br />
4- Rode o CS<br />
5- Quando o CS começar, vai abrir uma telinha no canto esquerdo (em cima), aperte em CARGAR CHEAT depois aperte em OK. Vai abrir uma tela nova e escolha o arquivo sxe84.dll e aperte em OPEN<br />
6- Agora conecte em um servidor com sxe<br />
7- Aperte F4 para abrir o menu do hack!<br />
<strong>CREDITS</strong>:<br />
********<br />
h4&#215;0r<br />
Cocodrilo<br />
Matek-Haxior<br />
Inexinferis &#8220;Karman&#8221;</p>
<p>****<br />
FAQ:<br />
****<br />
This hack was tested and 100% working on this PC configuration:          <em> &#60; Este hack foi testado e funcionou com essas configurações</em><br />
- Counter-Strike 1.6 (cs16full_v7.exe)<br />
- Counter-Strike PATCH v23<br />
- DirectX 9.0c<br />
- Windows XP Service Pack 3<br />
- ATI Radeon 9600 Pro<br />
- Omega Drivers for ATI Radeon 9600 Pro<br />
- NET Framework 3.5</p>
<p style="text-align:center;"><a href="http://www.megaupload.com/?d=JKELY444"><strong>DOWNLOAD &#8211; Megaupload</strong></a></p>
<p style="text-align:center;"><a href="http://rapidshare.com/files/313151453/WH__HCMHIK__sXe_8.4_sicheats.com.rar"><strong>DOWNLOAD &#8211; Rapidshare</strong></a></p>
<p style="text-align:center;"><a href="http://www.virustotal.com/pt/analisis/9d4838b76c9868183bf065eaa88287c78f4495a511fc33f1d0fbeeb2c3f16c2e-1259359901"><strong>SCAN</strong></a></p>
<p style="text-align:center;">obs: o link do rapidshare tem +5mb, coloquei um arquivo inutil junto para dar pontos. Caso não queira baixar um arquivo tão grande, use o Megaupload.<br />
<em>(the file at Rapidshare has +5mb, i just put a useless file at it just to get some points. If you don´t want to download such big file, use the link of Megaupload)</em></p>
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<title><![CDATA[Sustin comunitatea ExTreaM]]></title>
<link>http://tjohen.wordpress.com/2009/11/27/sustin-comunitatea-extream/</link>
<pubDate>Fri, 27 Nov 2009 18:29:45 +0000</pubDate>
<dc:creator>tjohen</dc:creator>
<guid>http://tjohen.wordpress.com/2009/11/27/sustin-comunitatea-extream/</guid>
<description><![CDATA[ExTreaM Community Echipa ExTreaM.RO va invita sa jucati Counter Strike pe cele 15 Servere dedicate a]]></description>
<content:encoded><![CDATA[<div class='snap_preview'><p>ExTreaM Community</p>
<p>Echipa ExTreaM.RO va invita sa jucati Counter Strike pe cele 15 Servere dedicate acestui joc , cu moduri diferite!<br />
<a href="www.extream.ro"><code>SITE</code></a><br />
<a href="www.extream.ro/forum">FORUM</a></p>
<p>———————————————————————————————————–<br />
Servere ExTreaM Counter Strike:</p>
<p>1. CS.ExTreaM.RO &#8211; Clasic<br />
2. CS2.ExTreaM.RO – Respawn<br />
3. KZ.ExTreaM.RO – Kreedz Climbing<br />
4. SURF.ExTreaM.RO:27016 &#8211; Surf Olympics<br />
5. HNS.ExTreaM.RO – Hide-N-Seek<br />
6. HNSTrain.ExTreaM.RO &#8211; Hide-N-Seek Train<br />
7. FUN.ExTreaM.RO – Fun<br />
8. HS.ExTreaM.RO – HeadShot Only<br />
9. DR.ExTreaM.RO &#8211; DeathRun<br />
10. GG.ExTreaM.RO – GunGame<br />
11. GGTeam.ExTreaM.RO &#8211; GunGame Team<br />
12. AWP.ExTreaM.RO – AWP Only<br />
13. ZP.ExTreaM.Ro – Zombie Plague<br />
14. ZM.ExTreaM.RO – Zombie Infection<br />
15. CACHE.ExTreaM.RO – Cache Mod<br />
———————————————————————————————————–<br />
Vizitati Forumul <a href="www.extream.ro/forum"></a> pentru Cereri , Nelamuriri , Probleme!<br />
Cu Respect echipa ExTreaM.RO</p>
</div>]]></content:encoded>
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<title><![CDATA[Steam-ul in romana]]></title>
<link>http://tjohen.wordpress.com/2009/11/27/7/</link>
<pubDate>Fri, 27 Nov 2009 17:44:19 +0000</pubDate>
<dc:creator>tjohen</dc:creator>
<guid>http://tjohen.wordpress.com/2009/11/27/7/</guid>
<description><![CDATA[Majoritatea stiti ce reprezinta aplicatia Steam, asa ca trec peste. In urma cu una sau doua zile Ste]]></description>
<content:encoded><![CDATA[<div class='snap_preview'><p>Majoritatea stiti ce reprezinta aplicatia Steam, asa ca trec peste. In urma cu una sau doua zile Steam a introdus si limba romana printre cele deja disponibile. Pentru a trece aplicatia in limba romana, intrati in   Steam -&#62; Settings -&#62; Interface -&#62; Select the language – Romana.﻿</p>
<p>&#160;</p>
<p>Poze :<br />
1.<a target='_blank' href='http://img267.imageshack.us/i/77655837.jpg/'><img src='http://img267.imageshack.us/img267/3220/77655837.th.jpg'></a></p>
<p>2.<a target='_blank' href='http://img205.imageshack.us/i/24182605.jpg/'><img src='http://img205.imageshack.us/img205/9569/24182605.th.jpg'></a></p>
<p>3.<a target='_blank' href='http://img205.imageshack.us/i/24182605.jpg/'><img src='http://img205.imageshack.us/img205/9569/24182605.th.jpg'></a></p>
<p>Pareri ?! Va e mai usor asa?</p>
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<title><![CDATA[Dezmembrez VW Transporter]]></title>
<link>http://tazvan.wordpress.com/2009/11/27/dezmembrez-vw-transporter/</link>
<pubDate>Fri, 27 Nov 2009 10:47:04 +0000</pubDate>
<dc:creator>tazvan</dc:creator>
<guid>http://tazvan.wordpress.com/2009/11/27/dezmembrez-vw-transporter/</guid>
<description><![CDATA[Dezmembrez doua VW Transporter din 1987, unul de persoane si unul de marfa: motor diesel 1600, tip C]]></description>
<content:encoded><![CDATA[Dezmembrez doua VW Transporter din 1987, unul de persoane si unul de marfa: motor diesel 1600, tip C]]></content:encoded>
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<title><![CDATA[It's a MAD, MAD, MAD, MAD World – Part I]]></title>
<link>http://focusblog.iatric.com/2009/11/25/its-a-mad-mad-mad-mad-world-%e2%80%93-part-i/</link>
<pubDate>Wed, 25 Nov 2009 16:43:45 +0000</pubDate>
<dc:creator>frankfortner</dc:creator>
<guid>http://focusblog.iatric.com/2009/11/25/its-a-mad-mad-mad-mad-world-%e2%80%93-part-i/</guid>
<description><![CDATA[by Frank Fortner In talking with many of our customers, I&#8217;m often amazed by the number of good]]></description>
<content:encoded><![CDATA[<div class='snap_preview'><p><strong>by Frank Fortner</strong></p>
<p>In talking with many of our customers, I&#8217;m often amazed by the number of good folks in the &#8220;MAGIC Kingdom&#8221; who still don&#8217;t fully realize what a significant shift in technology the MEDITECH Advanced Technology now shipping in (parts of) Client/Server version 6.x represents.  Some have even been led to believe 6.x is just another run-of-the-mill ring release that you migrate to after C/S 5.6.  I’ve spoken with a few beta sites and early adopters who might beg to differ.  For the sake of this post however, let&#8217;s concentrate on the new MEDITECH Advanced Database (MAD).  I want to highlight a few of the differences between the MAD and its predecessor (NPR) and since there is much to say on this topic, I’m going to break this into parts I and II.  In part I, we’ll look at the structure and design of the new database.</p>
<p>For starters, whereas the MAGIC/NPR database was termed &#8220;hierarchical,&#8221; the new Advanced Database is best described as &#8220;chronological&#8221; or &#8220;append-only,&#8221; which (in English) means that nothing is ever overwritten or deleted from it.  Most databases think in terms of add, insert or delete.  With MAD, you really just add.  There’s a slogan in there somewhere.    In order to illustrate how the MAD stores data, consider the following screenshot:</p>
<p><a href="http://iatric.wordpress.com/files/2009/11/edited_direction_dx1.jpg"><img title="How MAD stores data" src="http://iatric.wordpress.com/files/2009/11/edited_direction_dx1.jpg" alt="How MAD stores data" /></a></p>
<p>The highlighted section in the top half of the structure represents an initial entry in the MIS Directions Dictionary, where the facility of LAB has been created along with three corresponding applications, .DFT, LAB and PCS.  The lower un-highlighted section represents records that were later added due to an edit of the .DFT application and its schedule.  The advantage to this type of data storage is that it produces the mother-of-all audit trails.  A record of every addition, edit and deletion is stored, complete with the initials of the user responsible for each entry. The downside would seem to be the size of the database and how much larger it could potentially grow as more edits and deletions are made.  By the way… if you’re a old MAGIC programmer, you’ve probably realized you can still feel your way around a structure like this.</p>
<p>Keep in mind, when a program reads data from a chronological database, it has to essentially parse through the entire structure, so as more edits are made over time and the structure grows, you could pay a performance penalty.  At the same time, MEDITECH has implemented several tricks and techniques to make the reading of this type of file more efficient than it would appear to be at first glance.  In fact, MEDITECH has a special service program called ANP that has been highly optimized for reading from and writing to the MAD and it’s the ONLY program that is allowed to do so.  As a final word on performance, it’s safe to say your mileage may vary by application because some apps are more edit-intensive than others.</p>
<p>I hope this has provided you with a basic introduction to the new database structure and how it stores data as compared with its predecessor, NPR.  In part II, we’ll look at some other differences between the two database technologies.  As always, your comments and questions are welcome.  In addition, if you would like to see some other aspects of the Advanced Technology covered in future posts, please let us know.</p>
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<title><![CDATA[National holidays and counter-strike]]></title>
<link>http://moralots.wordpress.com/2009/11/25/national-holidays-and-counter-strike/</link>
<pubDate>Wed, 25 Nov 2009 09:56:48 +0000</pubDate>
<dc:creator>moralots</dc:creator>
<guid>http://moralots.wordpress.com/2009/11/25/national-holidays-and-counter-strike/</guid>
<description><![CDATA[I&#8217;m visiting home for about week now. I go back to the grind next week but I prefer not to rem]]></description>
<content:encoded><![CDATA[I&#8217;m visiting home for about week now. I go back to the grind next week but I prefer not to rem]]></content:encoded>
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<title><![CDATA[How to Buy a Diamond - The 5 &quot;C&quot;s]]></title>
<link>http://japanbuzz.wordpress.com/2009/11/24/how-to-buy-a-diamond-the-5-cs/</link>
<pubDate>Tue, 24 Nov 2009 17:26:07 +0000</pubDate>
<dc:creator>marvinhkolp1234</dc:creator>
<guid>http://japanbuzz.wordpress.com/2009/11/24/how-to-buy-a-diamond-the-5-cs/</guid>
<description><![CDATA[Diamonds are perhaps the most admired and desirable gems. The traditional engagement ring, the diamo]]></description>
<content:encoded><![CDATA[<div class='snap_preview'><p>Diamonds are perhaps the most admired and desirable gems. The traditional engagement ring, the diamond stud earrings, the diamond pendant all evoke the eternal beauty and precious aura of diamonds.</p>
<p>Buying diamond jewelry can be a new experience for most people, and can leave you feeling intimidated or overwhelmed by the amount of information and advertising out there.</p>
<p>Different characteristics of diamonds will influence the appearance and value, and some are more important than others. Whether the diamond is in a ring, or a necklace, or a pair of earrings, knowing the 5 &#8220;C&#8221;s, plus the shape of the diamond, will help to choose the right stone for you or for the one you are going to give the diamond jewelry to.</p>
<p>The 5 &#8220;C&#8221;s are Cut, Color, Clarity, Carat weight and Certification. Let&#8217;s start with the cut.</p>
<p>The cut of a diamond will determine its brilliance. Whatever the shape of the diamond, whether round, oval, pear, emerald, marquise or heart, the polished facets of the way the diamond is cut, and the better the cut, the more brilliance and sparkle it will have.</p>
<p>Next, let&#8217;s look at color. Color grades of diamonds actually refer to the lack of color. White diamonds, with little or no color, are considered higher grade than diamonds with visible color.</p>
<p>Clarity in diamonds refers to the absence of imperfections in the stone. Most diamonds have some tiny imperfections, and those with fewer, with more clarity, receive the highest clarity grades.</p>
<p>Carat weight is important, as it measures the weight of the diamond. Keep in mind that carat weight alone does not define the quality of a diamond &#8211; all of the 5 &#8220;C&#8221;s must be taken into account to determine quality and value.</p>
<p>Finally, the diamond should be certified by the GIA. The Gemological Institute of America will provide an unbiased diamond report based on the first 4 &#8220;C&#8221;s. Your diamond should have this certification. For more information on the GIA, visit their web site at http://www.gia.edu.</p>
<p>The more you know about diamonds, the better prepared you&#8217;ll be when the big day arrives &#8211; will it be a surprise engagement ring for your lady? Diamonds as that special birthday or holiday gift? A reward for yourself, &#8220;just because&#8221;? Imagine the wide eyes of the &#8220;sweet sixteen&#8221; who receives her first pair of diamond stud earrings!</p>
<p>It&#8217;s important to deal with reputable jewelers, be sure to get that GIA certification, ask questions, and you&#8217;ll be sure to choose just the right diamonds for your taste and budget.</p>
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<title><![CDATA[Longest Path: Method of Random Orientations ]]></title>
<link>http://tkramesh.wordpress.com/2009/11/24/longest-path-method-of-random-orientations/</link>
<pubDate>Tue, 24 Nov 2009 14:01:13 +0000</pubDate>
<dc:creator>tkramesh</dc:creator>
<guid>http://tkramesh.wordpress.com/2009/11/24/longest-path-method-of-random-orientations/</guid>
<description><![CDATA[In this post, we shall consider an NP-complete problem, namely that of determining whether a simple ]]></description>
<content:encoded><![CDATA[<div class='snap_preview'><p>In this post, we shall consider an NP-complete problem, namely that of determining whether a simple path of length k exists in a given graph, G = (V,E).</p>
<p>Formally,</p>
<p>LONGEST PATH PROBLEM</p>
<p>Input: undirected graph, G = (V,E), integer <img src='http://l.wordpress.com/latex.php?latex=k+%5Cgeq+0+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='k \geq 0 ' title='k \geq 0 ' class='latex' />.</p>
<p>Parameter: k</p>
<p>To find: Does G contain a simple path of length, k?</p>
<p>(Note: length refers to edge length here. In particular, a simple path of length k has k edges.)</p>
<p>The problem has a natural extension:-</p>
<p>EXTENDED LONGEST PATH PROBLEM</p>
<p>Input: undirected graph, G = (V,E), integer <img src='http://l.wordpress.com/latex.php?latex=k+%5Cgeq+0+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='k \geq 0 ' title='k \geq 0 ' class='latex' />.</p>
<p>Parameter: k</p>
<p>To find: All pairs of vertices <img src='http://l.wordpress.com/latex.php?latex=%28i%2Cj%29+%5Cin+V+%5Ctimes+V+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='(i,j) \in V \times V ' title='(i,j) \in V \times V ' class='latex' />, such that there exists a simple path of length k between i and j in G.</p>
<p>=======</p>
<p>This article is based on the seminal paper on Color-Coding by Noga Alon, Raphael Yuster, Uri Zwick [1995]. The method of random orientations is mentioned in the paper prior to a description of the color-coding approach.</p>
<p>=======</p>
<p>We concern ourselves with the Extended Longest Path problem.</p>
<p>Consider the adjacency matrix, A of input graph, G. (A is an <img src='http://l.wordpress.com/latex.php?latex=%26%23124%3BV%26%23124%3B+%5Ctimes+%26%23124%3BV%26%23124%3B+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#124;V&#124; \times &#124;V&#124; ' title='&#124;V&#124; \times &#124;V&#124; ' class='latex' /> matrix, with 0 / 1 entries, which we interpret as integers.)</p>
<p>We have, <img src='http://l.wordpress.com/latex.php?latex=A%5Bi%5D%5Bj%5D+%5Cneq+0+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='A[i][j] \neq 0 ' title='A[i][j] \neq 0 ' class='latex' /> iff there exists an edge <img src='http://l.wordpress.com/latex.php?latex=%7Bi%2Cj%7D+%5Cin+E+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='{i,j} \in E ' title='{i,j} \in E ' class='latex' />.</p>
<p>(Note: <img src='http://l.wordpress.com/latex.php?latex=A%5Bi%5D%5Bj%5D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='A[i][j] ' title='A[i][j] ' class='latex' /> represents the entry at the <img src='http://l.wordpress.com/latex.php?latex=i%5E%7Bth%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='i^{th} ' title='i^{th} ' class='latex' /> row and <img src='http://l.wordpress.com/latex.php?latex=j%5Eth+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='j^th ' title='j^th ' class='latex' /> column of matrix A.)</p>
<p>Consider the matrix, <img src='http://l.wordpress.com/latex.php?latex=A%5E2+%3D+A+%5Ctimes+A+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='A^2 = A \times A ' title='A^2 = A \times A ' class='latex' />.</p>
<p><img src='http://l.wordpress.com/latex.php?latex=A%5E2%5Bi%5D%5Bj%5D+%5Cneq+0+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='A^2[i][j] \neq 0 ' title='A^2[i][j] \neq 0 ' class='latex' /> iff there exists a path of length two between i and j in G. (Why? Verify for yourself.)</p>
<p>Generalizing, we can make the following statement for the matrix <img src='http://l.wordpress.com/latex.php?latex=A%5Ek+%3D+A%5E%7Bk-1%7D+%5Ctimes+A+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='A^k = A^{k-1} \times A ' title='A^k = A^{k-1} \times A ' class='latex' />.</p>
<p><img src='http://l.wordpress.com/latex.php?latex=A%5Ek%5Bi%5D%5Bj%5D+%5Cneq+0+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='A^k[i][j] \neq 0 ' title='A^k[i][j] \neq 0 ' class='latex' /> iff there exists a path of length k between i and j in G. (Why? use induction to prove this.)</p>
<p>Question: Do all paths represented in the matrix entries correspond to simple paths of G?</p>
<p>In other words, is the following statement true:</p>
<p><img src='http://l.wordpress.com/latex.php?latex=A%5Ek%5Bi%5D%5Bj%5D+%5Cneq+0+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='A^k[i][j] \neq 0 ' title='A^k[i][j] \neq 0 ' class='latex' /> iff there exists a simple path of length k between i and j in G.</p>
<p>&#8211;</p>
<p>By a little observation, it can be seen that for the matrix entry <img src='http://l.wordpress.com/latex.php?latex=A%5Ek%5Bi%5D%5Bj%5D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='A^k[i][j] ' title='A^k[i][j] ' class='latex' /> to be non-zero, the path between vertices i and j need not necessarily be simple. In other words, the path may contain cycles.</p>
<p>Hence, we can not infer from the fact of having <img src='http://l.wordpress.com/latex.php?latex=A%5Ek%5Bi%5D%5Bj%5D+%5Cneq+0+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='A^k[i][j] \neq 0 ' title='A^k[i][j] \neq 0 ' class='latex' />, the conclusion that there exists a simple path of length k between i and j in G.</p>
<p>&#8212;</p>
<p>How do we fix this problem?</p>
<p>Consider a graph, H that does not have any cycles (i.e. acyclic graph). Clearly, all paths in H are necessarily simple. (For a path to not be simple, the path needs to contain a cycle, which is precluded by the fact of H being acyclic.)</p>
<p>Let B denote the adjacency matrix of acyclic graph, H.</p>
<p>We can make the following statements:-</p>
<p><img src='http://l.wordpress.com/latex.php?latex=B%5Ek%5Bi%5D%5Bj%5D+%5Cneq+0+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='B^k[i][j] \neq 0 ' title='B^k[i][j] \neq 0 ' class='latex' /> iff there exists a path of length k between i and j in H.</p>
<p>And since all paths of H are necessarily simple, the above statement is equivalent to:-</p>
<p><img src='http://l.wordpress.com/latex.php?latex=B%5Ek%5Bi%5D%5Bj%5D+%5Cneq+0+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='B^k[i][j] \neq 0 ' title='B^k[i][j] \neq 0 ' class='latex' /> iff there exists a simple path of length k between i and j in H.</p>
<p>Therefore, if the input graph is acyclic, raising the adjacency matrix to the power k solves the Extended Longest Path Problem.</p>
<p>&#8212;-</p>
<p>Question: How do we obtain an acyclic graph, H from the given input graph, G?</p>
<p>Prior to answering this question, we shall digress briefly to the look at the notion of a Directed Acyclic Graph (abbreviated as DAG).</p>
<p>&#8212;</p>
<p>Consider an undirected graph, G = (V,E) on <img src='http://l.wordpress.com/latex.php?latex=n+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='n ' title='n ' class='latex' /> vertices. We shall construct a directed acyclic version of G.</p>
<p>Let <img src='http://l.wordpress.com/latex.php?latex=%5Cpi+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\pi ' title='\pi ' class='latex' /> be a permutation of the vertices i.e. <img src='http://l.wordpress.com/latex.php?latex=%5Cpi+%3A+V+-%26%2362%3B+%5C%7B1%2C...%2C%26%23124%3BV%26%23124%3B%5C%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\pi : V -&gt; \{1,...,&#124;V&#124;\} ' title='\pi : V -&gt; \{1,...,&#124;V&#124;\} ' class='latex' />, (<img src='http://l.wordpress.com/latex.php?latex=%5Cpi+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\pi ' title='\pi ' class='latex' /> is one-one and onto, i.e. bijective.)</p>
<p>Call the directed version of G as <img src='http://l.wordpress.com/latex.php?latex=G_%7Bdir%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='G_{dir} ' title='G_{dir} ' class='latex' />. The vertex set of <img src='http://l.wordpress.com/latex.php?latex=G_%7Bdir%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='G_{dir} ' title='G_{dir} ' class='latex' /> is V (same as G). For every edge of G, we have a corresponding directed edge in <img src='http://l.wordpress.com/latex.php?latex=G_%7Bdir%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='G_{dir} ' title='G_{dir} ' class='latex' />.</p>
<p>For each edge <img src='http://l.wordpress.com/latex.php?latex=%5C%7Bi%2Cj%5C%7D+%5Cin+E+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\{i,j\} \in E ' title='\{i,j\} \in E ' class='latex' /> of G, add edge <img src='http://l.wordpress.com/latex.php?latex=%28i%2Cj%29+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='(i,j) ' title='(i,j) ' class='latex' /> to <img src='http://l.wordpress.com/latex.php?latex=G_%7Bdir%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='G_{dir} ' title='G_{dir} ' class='latex' /> iff <img src='http://l.wordpress.com/latex.php?latex=%5Cpi+%28i%29+%26%2360%3B+%5Cpi+%28j%29+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\pi (i) &lt; \pi (j) ' title='\pi (i) &lt; \pi (j) ' class='latex' />.</p>
<p>(i.e. Orient every edge of G from the vertex having lower <img src='http://l.wordpress.com/latex.php?latex=%5Cpi+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\pi ' title='\pi ' class='latex' /> value to the vertex having greater <img src='http://l.wordpress.com/latex.php?latex=%5Cpi+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\pi ' title='\pi ' class='latex' /> value. )</p>
<p>Claim 1. <img src='http://l.wordpress.com/latex.php?latex=G_%7Bdir%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='G_{dir} ' title='G_{dir} ' class='latex' /> is acyclic.</p>
<p>Proof. Assume to the contrary that <img src='http://l.wordpress.com/latex.php?latex=G_%7Bdir%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='G_{dir} ' title='G_{dir} ' class='latex' /> has a cycle, <img src='http://l.wordpress.com/latex.php?latex=C+%3D+%28v_1%2C+v_2%2C+...%2C+v_i%2C+v_1%29+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='C = (v_1, v_2, ..., v_i, v_1) ' title='C = (v_1, v_2, ..., v_i, v_1) ' class='latex' />.</p>
<p>Hence, we have the following <img src='http://l.wordpress.com/latex.php?latex=i+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='i ' title='i ' class='latex' /> inequalities:-</p>
<p><img src='http://l.wordpress.com/latex.php?latex=%5Cpi+%28v_1%29+%26%2360%3B+%5Cpi+%28v_2%29+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\pi (v_1) &lt; \pi (v_2) ' title='\pi (v_1) &lt; \pi (v_2) ' class='latex' /></p>
<p><img src='http://l.wordpress.com/latex.php?latex=%5Cpi+%28v_2%29+%26%2360%3B+%5Cpi+%28v_3%29+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\pi (v_2) &lt; \pi (v_3) ' title='\pi (v_2) &lt; \pi (v_3) ' class='latex' /></p>
<p>&#8230;</p>
<p><img src='http://l.wordpress.com/latex.php?latex=%5Cpi+%28v_%7Bi-1%7D%29+%26%2360%3B+%5Cpi+%28v_i%29+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\pi (v_{i-1}) &lt; \pi (v_i) ' title='\pi (v_{i-1}) &lt; \pi (v_i) ' class='latex' /></p>
<p><img src='http://l.wordpress.com/latex.php?latex=%5Cpi+%28v_i%29+%26%2360%3B+%5Cpi+%28v_1%29+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\pi (v_i) &lt; \pi (v_1) ' title='\pi (v_i) &lt; \pi (v_1) ' class='latex' />.</p>
<p>From the first <img src='http://l.wordpress.com/latex.php?latex=%7Bi+-+1%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='{i - 1} ' title='{i - 1} ' class='latex' /> inequalities, we obtain:-</p>
<p><img src='http://l.wordpress.com/latex.php?latex=%5Cpi+%28v_1%29+%26%2360%3B+%5Cpi+%28v_i%29+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\pi (v_1) &lt; \pi (v_i) ' title='\pi (v_1) &lt; \pi (v_i) ' class='latex' />, which is contrary to the <img src='http://l.wordpress.com/latex.php?latex=i%5E%7Bth%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='i^{th} ' title='i^{th} ' class='latex' /> inequality.</p>
<p>Hence, <img src='http://l.wordpress.com/latex.php?latex=G_%7Bdir%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='G_{dir} ' title='G_{dir} ' class='latex' /> is acyclic. QED.</p>
<p>==</p>
<p>Claim 2 (Converse of Claim 1.). Given a Directed Acyclic Graph, G = (V,E), we can obtain a bijection <img src='http://l.wordpress.com/latex.php?latex=%5Cpi+%3A+V+%7B-%26%2362%3B%7D+%5C%7B1%2C...%2C+%26%23124%3BV%26%23124%3B%5C%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\pi : V {-&gt;} \{1,..., &#124;V&#124;\} ' title='\pi : V {-&gt;} \{1,..., &#124;V&#124;\} ' class='latex' />, such that for every edge <img src='http://l.wordpress.com/latex.php?latex=%28i%2Cj%29+%5Cin+E+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='(i,j) \in E ' title='(i,j) \in E ' class='latex' />, the following condition holds:<img src='http://l.wordpress.com/latex.php?latex=%5Cpi+%28i%29+%26%2360%3B+%5Cpi+%28j%29+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\pi (i) &lt; \pi (j) ' title='\pi (i) &lt; \pi (j) ' class='latex' />.</p>
<p>Proof-sketch.</p>
<p>Given any directed acyclic graph, G = (V,E), we have:-</p>
<p><img src='http://l.wordpress.com/latex.php?latex=%5Cexists+v+%5Cin+V+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\exists v \in V ' title='\exists v \in V ' class='latex' /> such that <img src='http://l.wordpress.com/latex.php?latex=%5Cforall+i+%5Cin+V%2C+%28i%2Cv%29+%5Cnotin+E+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\forall i \in V, (i,v) \notin E ' title='\forall i \in V, (i,v) \notin E ' class='latex' />.</p>
<p>(In other words, we can find a vertex in V, which has no incoming edges.)</p>
<p>Assign <img src='http://l.wordpress.com/latex.php?latex=%5Cpi+%28v%29+%3D+1+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\pi (v) = 1 ' title='\pi (v) = 1 ' class='latex' /> for one such vertex, v.</p>
<p>Remove <img src='http://l.wordpress.com/latex.php?latex=v+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='v ' title='v ' class='latex' /> from <img src='http://l.wordpress.com/latex.php?latex=G+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='G ' title='G ' class='latex' /> to get a new directed acyclic graph. Find a vertex, u that satisfies the above condition in this new graph, assign <img src='http://l.wordpress.com/latex.php?latex=%5Cpi+%28u%29+%3D+2+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\pi (u) = 2 ' title='\pi (u) = 2 ' class='latex' />.</p>
<p>Proceed in this manner until all vertices are assigned a value under the function, <img src='http://l.wordpress.com/latex.php?latex=%5Cpi+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\pi ' title='\pi ' class='latex' />.</p>
<p>End of proof-sketch.</p>
<p>===</p>
<p>We can now return to the question raised prior to the discussion on directed acyclic graphs.</p>
<p>To restate:</p>
<p>Question: How do we obtain an acyclic graph, H from the given input graph, G?</p>
<p>Solution: Take a random (What does &#8220;random&#8221; mean?) permutation <img src='http://l.wordpress.com/latex.php?latex=%5Cpi+%3A+V+%7B-%26%2362%3B%7D+%5C%7B1%2C+...%2C+%26%23124%3BV%26%23124%3B+%5C%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\pi : V {-&gt;} \{1, ..., &#124;V&#124; \} ' title='\pi : V {-&gt;} \{1, ..., &#124;V&#124; \} ' class='latex' />. Create an directed acyclic version of G as outlined in the preceding discussion. Call this graph, <img src='http://l.wordpress.com/latex.php?latex=G_%7Bdir%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='G_{dir} ' title='G_{dir} ' class='latex' />.</p>
<p>(By &#8220;random&#8221;, we mean a permutation selected uniformly at random from the set of n! possible permutations of the vertex set, V.)</p>
<p>Denote the adjacency matrix of <img src='http://l.wordpress.com/latex.php?latex=G_%7Bdir%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='G_{dir} ' title='G_{dir} ' class='latex' /> by B.</p>
<p>As seen earlier, we have:-</p>
<p><img src='http://l.wordpress.com/latex.php?latex=B%5Ek+%5Bi%5D%5Bj%5D+%5Cneq+0+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='B^k [i][j] \neq 0 ' title='B^k [i][j] \neq 0 ' class='latex' /> iff there exists a simple path in between i and j in $latex  G_{dir} $ of length k.</p>
<p>Since every simple path in <img src='http://l.wordpress.com/latex.php?latex=G_%7Bdir%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='G_{dir} ' title='G_{dir} ' class='latex' /> is also a simple path in G (Why is this true?), we have:-</p>
<p>If <img src='http://l.wordpress.com/latex.php?latex=B%5Ek+%5Bi%5D%5Bj%5D+%5Cneq+0+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='B^k [i][j] \neq 0 ' title='B^k [i][j] \neq 0 ' class='latex' />, then <img src='http://l.wordpress.com/latex.php?latex=%5Cexists+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\exists ' title='\exists ' class='latex' /> a simple path between i and j in G of length k.</p>
<p>Question: Is the converse of this above statement true?</p>
<p>In other words, is the following statement true:-</p>
<p>If there exists a simple path between i and j in G of length k, then <img src='http://l.wordpress.com/latex.php?latex=B%5Ek%5Bi%5D%5Bj%5D+%5Cneq+0+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='B^k[i][j] \neq 0 ' title='B^k[i][j] \neq 0 ' class='latex' />.</p>
<p>Answer: No.</p>
<p>The above question can also be rephrased as:</p>
<p>Are all simple paths in G carried over into <img src='http://l.wordpress.com/latex.php?latex=G_%7Bdir%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='G_{dir} ' title='G_{dir} ' class='latex' />?</p>
<p>(Take a simple path, p in G, and figure out for yourself how the edges of p need to be oriented for path, p to exist in <img src='http://l.wordpress.com/latex.php?latex=G_%7Bdir%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='G_{dir} ' title='G_{dir} ' class='latex' />. In particular, what does this imply about the <img src='http://l.wordpress.com/latex.php?latex=%5Cpi+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\pi ' title='\pi ' class='latex' /> values of the vertices along the path?)</p>
<p>==</p>
<p>Now, we can ask the question:</p>
<p>Question: What is the probability that a particular simple path, <img src='http://l.wordpress.com/latex.php?latex=p+%3D+%28v_1%2C+v_2%2C+...%2C+v_k%29+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='p = (v_1, v_2, ..., v_k) ' title='p = (v_1, v_2, ..., v_k) ' class='latex' /> of length k in G gets preserved in <img src='http://l.wordpress.com/latex.php?latex=G_%7Bdir%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='G_{dir} ' title='G_{dir} ' class='latex' /> given that we take a random permutation, <img src='http://l.wordpress.com/latex.php?latex=%5Cpi+%3A+V+%7B-%26%2362%3B%7D+%5C%7B1%2C+...%2C+%26%23124%3BV%26%23124%3B+%5C%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\pi : V {-&gt;} \{1, ..., &#124;V&#124; \}' title='\pi : V {-&gt;} \{1, ..., &#124;V&#124; \}' class='latex' /> to obtain <img src='http://l.wordpress.com/latex.php?latex=G_%7Bdir%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='G_{dir} ' title='G_{dir} ' class='latex' /> from <img src='http://l.wordpress.com/latex.php?latex=G+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='G ' title='G ' class='latex' />?</p>
<p>Solution: There are only two ways in which path <img src='http://l.wordpress.com/latex.php?latex=p+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='p ' title='p ' class='latex' /> can get preserved in <img src='http://l.wordpress.com/latex.php?latex=G_%7Bdir%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='G_{dir} ' title='G_{dir} ' class='latex' /> -</p>
<p>either as the directed path, <img src='http://l.wordpress.com/latex.php?latex=p1+%3D+%28v_1%2C+v_2%2C+...%2C+v_k%29+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='p1 = (v_1, v_2, ..., v_k) ' title='p1 = (v_1, v_2, ..., v_k) ' class='latex' />,</p>
<p>or as the directed path, <img src='http://l.wordpress.com/latex.php?latex=p2+%3D+%28v_1%2C+v_2%2C+...%2C+v_k%29+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='p2 = (v_1, v_2, ..., v_k) ' title='p2 = (v_1, v_2, ..., v_k) ' class='latex' />.</p>
<p>Path <img src='http://l.wordpress.com/latex.php?latex=p1+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='p1 ' title='p1 ' class='latex' /> exists only if <img src='http://l.wordpress.com/latex.php?latex=%5Cpi+%28v_1%29+%26%2360%3B+%5Cpi+%28v_2%29+%26%2360%3B...+%26%2360%3B+%5Cpi+%28v_k%29+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\pi (v_1) &lt; \pi (v_2) &lt;... &lt; \pi (v_k) ' title='\pi (v_1) &lt; \pi (v_2) &lt;... &lt; \pi (v_k) ' class='latex' />.</p>
<p>Path <img src='http://l.wordpress.com/latex.php?latex=p2+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='p2 ' title='p2 ' class='latex' /> exists only if <img src='http://l.wordpress.com/latex.php?latex=%5Cpi+%28v_1%29+%26%2362%3B+%5Cpi+%28v_2%29+%26%2362%3B+...+%26%2362%3B+%5Cpi+%28v_k%29+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\pi (v_1) &gt; \pi (v_2) &gt; ... &gt; \pi (v_k) ' title='\pi (v_1) &gt; \pi (v_2) &gt; ... &gt; \pi (v_k) ' class='latex' />.</p>
<p>Note that we are not concerned with the <img src='http://l.wordpress.com/latex.php?latex=%5Cpi+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\pi ' title='\pi ' class='latex' /> values of any of the other <img src='http://l.wordpress.com/latex.php?latex=n-k+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='n-k ' title='n-k ' class='latex' /> vertices of G.</p>
<p>Hence, we obtain the following:</p>
<p>Probability that a particular path, p in G, of length k, is preserved in <img src='http://l.wordpress.com/latex.php?latex=G_%7Bdir%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='G_{dir} ' title='G_{dir} ' class='latex' /> = 2 / (k+1)!.</p>
<p>(How do we get that?)</p>
<p>===</p>
<p>The above probability implies that to preserve any particular simple path of G (having length k), we need to take an expected number of (k+1)! / 2 random permutations.</p>
<p>===</p>
<p>Running time of the algorithm:</p>
<p>We can state the expected running time of the algorithm. We need to perform the following steps.</p>
<p>1. Given a particular random permutation, <img src='http://l.wordpress.com/latex.php?latex=%5Cpi+%3A+V+%7B-%26%2362%3B%7D+%5C%7B1%2C+...%2C+%26%23124%3BV%26%23124%3B+%5C%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\pi : V {-&gt;} \{1, ..., &#124;V&#124; \}' title='\pi : V {-&gt;} \{1, ..., &#124;V&#124; \}' class='latex' />.</p>
<p>Raise the adjacency matrix, B  of <img src='http://l.wordpress.com/latex.php?latex=G_%7Bdir%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='G_{dir} ' title='G_{dir} ' class='latex' /> to the power k.</p>
<p>This can be done via <img src='http://l.wordpress.com/latex.php?latex=O%28log+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='O(log ' title='O(log ' class='latex' /> <img src='http://l.wordpress.com/latex.php?latex=k%29+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='k) ' title='k) ' class='latex' /> matrix multiplications, each of which takes <img src='http://l.wordpress.com/latex.php?latex=O%28V%5E%5Comega%29+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='O(V^\omega) ' title='O(V^\omega) ' class='latex' /> time. (Here <img src='http://l.wordpress.com/latex.php?latex=%5Comega+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\omega ' title='\omega ' class='latex' /> is the exponent for matrix multiplication <img src='http://l.wordpress.com/latex.php?latex=%28%5Comega+%26%2360%3B+2.376%29+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='(\omega &lt; 2.376) ' title='(\omega &lt; 2.376) ' class='latex' />. )</p>
<p>2. Repeating the same for an expected number of <img src='http://l.wordpress.com/latex.php?latex=O%28+%28k%2B1%29%21+%29+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='O( (k+1)! ) ' title='O( (k+1)! ) ' class='latex' /> random permutations.</p>
<p>3. Keep track of of the <img src='http://l.wordpress.com/latex.php?latex=n+%5Ctimes+%28n-1%29+%2F+2+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='n \times (n-1) / 2 ' title='n \times (n-1) / 2 ' class='latex' /> pairs of vertices, for each of which we need to output a boolean Yes or No value (corresponding to whether or not a simple path of length k exists in G between that pair of vertices.) (Note: n = &#124;V&#124;).</p>
<p>Initialize all <img src='http://l.wordpress.com/latex.php?latex=n+%5Ctimes+%28n-1%29+%2F+2+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='n \times (n-1) / 2 ' title='n \times (n-1) / 2 ' class='latex' /> values of this global list to No at the beginning of the algorithm. For each permutation, if the matrix entry, <img src='http://l.wordpress.com/latex.php?latex=B%5Ek+%5Bi%5D%5Bj%5D+%5Cneq+0+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='B^k [i][j] \neq 0 ' title='B^k [i][j] \neq 0 ' class='latex' /> and if the value corresponding to pair (i,j) is listed as No in the global list, change it to Yes.</p>
<p>Hence, the expected running time of the algorithm is <img src='http://l.wordpress.com/latex.php?latex=O%28+%28k%2B1%29%21+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='O( (k+1)! ' title='O( (k+1)! ' class='latex' />.<img src='http://l.wordpress.com/latex.php?latex=log+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='log ' title='log ' class='latex' /> <img src='http://l.wordpress.com/latex.php?latex=k.+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='k. ' title='k. ' class='latex' /> <img src='http://l.wordpress.com/latex.php?latex=V%5E%5Comega%29+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='V^\omega) ' title='V^\omega) ' class='latex' />.</p>
<p>(We have ignored certain polynomial (in the size of the graph) factors in the running time. That is justified owing to the &#8220;supremacy&#8221; of the (k+1)! term over other factors.)</p>
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<item>
<title><![CDATA[Bütün Non-steam sürümleri]]></title>
<link>http://kaangural.wordpress.com/2009/11/23/butun-non-steam-surumleri/</link>
<pubDate>Mon, 23 Nov 2009 18:49:55 +0000</pubDate>
<dc:creator>kaangural</dc:creator>
<guid>http://kaangural.wordpress.com/2009/11/23/butun-non-steam-surumleri/</guid>
<description><![CDATA[- Patch v29 http://www.rapidshare.com/files/2166287 &#8230; ll_v29.exe - Patch v28 http://www.rapids]]></description>
<content:encoded><![CDATA[<div class='snap_preview'><p><img class="alignnone" src="http://i49.photobucket.com/albums/f287/Tidus000/20061110-counterstrike16frontei5cop.jpg" alt="" width="450" height="450" /></p>
<p>- Patch v29 <a href="http://www.rapidshare.com/files/21662874/cs16patch_full_v29.exe" target="_blank">http://www.rapidshare.com/files/2166287 &#8230; ll_v29.exe</a><br />
- Patch v28 <a href="http://www.rapidshare.com/files/19161015/cs16patch_full_v28.exe" target="_blank">http://www.rapidshare.com/files/1916101 &#8230; ll_v28.exe</a><br />
- Patch v27 <a href="http://www.rapidshare.com/files/19159904/cs16patch_full_v27.exe" target="_blank">http://www.rapidshare.com/files/1915990 &#8230; ll_v27.exe</a><br />
- Patch v26 <a href="http://www.rapidshare.com/files/19159846/cs16patch_full_v26.exe" target="_blank">http://www.rapidshare.com/files/1915984 &#8230; ll_v26.exe</a><br />
- Patch v25 <a href="http://www.rapidshare.com/files/20596492/cs16patch_full_v25.rar" target="_blank">http://www.rapidshare.com/files/2059649 &#8230; ll_v25.rar</a><br />
- Patch v24 <a href="http://www.rapidshare.com/files/19160050/cs16patch_full_V24.exe" target="_blank">http://www.rapidshare.com/files/1916005 &#8230; ll_V24.exe</a><br />
- Patch v23 <a href="http://rapidshare.com/files/162273995/cs16patch_full_V23.rar" target="_blank">http://rapidshare.com/files/162273995/c &#8230; ll_V23.rar</a><br />
- Patch v22 <a href="http://www.rapidshare.com/files/19159853/cs16patch_full_V22.exe" target="_blank">http://www.rapidshare.com/files/1915985 &#8230; ll_V22.exe</a><br />
- Patch v21 <a href="http://www.rapidshare.com/files/20596496/cs16patch_full_V21.exe" target="_blank">http://www.rapidshare.com/files/2059649 &#8230; ll_V21.exe</a><br />
- Patch v20 <a href="http://www.rapidshare.com/files/20596489/cs16patch_full_V20.exe" target="_blank">http://www.rapidshare.com/files/2059648 &#8230; ll_V20.exe</a><br />
- Patch v19 <a href="http://www.rapidshare.com/files/19159960/cs16patch_full_V19.exe" target="_blank">http://www.rapidshare.com/files/1915996 &#8230; ll_V19.exe</a></p>
</div>]]></content:encoded>
</item>
<item>
<title><![CDATA[Cs 1.6 sXe 8.2 Wall-Hack]]></title>
<link>http://kaangural.wordpress.com/2009/11/23/cs-1-6-sxe-8-2-wall-hack/</link>
<pubDate>Mon, 23 Nov 2009 18:30:58 +0000</pubDate>
<dc:creator>kaangural</dc:creator>
<guid>http://kaangural.wordpress.com/2009/11/23/cs-1-6-sxe-8-2-wall-hack/</guid>
<description><![CDATA[Kullanımı: * Tüm dosyaları valve klasörüne çıkartın ve programı çalıştırın. * [ Browse ] tuşuna basa]]></description>
<content:encoded><![CDATA[<div class='snap_preview'><p><strong>Kullanımı:</strong></p>
<p><strong>* Tüm dosyaları valve klasörüne çıkartın ve programı çalıştırın.<br />
* [ Browse ] tuşuna basarak atavratwall.sys dosyasını seçin.<br />
* [ Register Service ]  tuşuna basın wall hazırlansın.<br />
* [ Start Service ]  tuşuna basın.<br />
* Sxe&#8217;yi açın ve oyununuza girin.</strong></p>
<p><strong>Not: Tüm Sxe Sürümlerinde Çalışır.<br />
Not2: SADECE  CS 1.6 PATCH v26&#8242;larda ÇALIŞIR.<br />
Not3: Bu zaten piyasada olan bi wallHack programının eksiklikleri giderilmiş versiyonudur.</strong></p>
<p><strong>sXe 8.2&#8242;ye uyarlanmıştır.</strong></p>
<h1><strong><a href="http://www.indirdur.net/files/0VBJZQQB/sxe_8.2_wall_hack_www_netbilgini_org.rar">INDIR</a></strong></h1>
<p><strong>ÇALIŞMAZSA</strong></p>
<h1><strong><a href="http://www.upload.tc/download/4764/new8.2wall.rar.html">INDIR</a><br />
</strong></h1>
<p><strong>Şifre : </strong><a href="http://www.netbilgini.org/" target="_blank">www.netbilgini.org</a></p>
<p><strong>NOD32 ile taranmıştır.</strong></p>
<p><strong>Alternatif olarak virustotal taraması buyrun :  <a href="http://www.virustotal.com/tr/analisis/53f5ee9e8d1bc7e9b3a92dab4bef1bb639380b31482a3f661171a700d0d2c72f-1258908048" target="_blank">Virustotal. MD5: 0f901322d1d2d834b44a9285b9b9e565 Hacktool.Rootkit Trojan.Rootkit.Gen Rootkit.18687</a></strong></p>
<p><strong><span style="font-size:medium;"> <span style="color:darkred;"><br />
</span></span></strong></p>
</div>]]></content:encoded>
</item>
<item>
<title><![CDATA[¿Aburrido?, pierde el tiempo con el CS portable]]></title>
<link>http://loumalouomega.wordpress.com/2009/11/23/%c2%bfaburrido-pierde-el-tiempo-con-el-cs-portable/</link>
<pubDate>Mon, 23 Nov 2009 16:29:46 +0000</pubDate>
<dc:creator>loumalouomega</dc:creator>
<guid>http://loumalouomega.wordpress.com/2009/11/23/%c2%bfaburrido-pierde-el-tiempo-con-el-cs-portable/</guid>
<description><![CDATA[¿Te encuentras aburrido?, prueba a  jugar un juego que seguro que conocerás muy bien de años atrás, ]]></description>
<content:encoded><![CDATA[<div class='snap_preview'><p style="text-align:left;">¿Te encuentras aburrido?, prueba a  jugar un juego que seguro que conocerás muy bien de años atrás, el Counter Strike, ¿cómo?, pues con la la versión portable que adjunto no lo tendrás demasiado complicado pra jugar en cualquier momento en cualquier lugar, con ordenador por supuesto. Se trata de la versión 1.6, es decir la última de la generación clásica.</p>
<p style="text-align:left;">Ale a viciarse.</p>
<p style="text-align:center;"><a href="http://www.megaupload.com/?d=PD2L7C58"><img class="size-full wp-image-961 aligncenter" title="descargar" src="http://loumalouomega.wordpress.com/files/2009/11/descargar.png" alt="" width="300" height="300" /></a></p>
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<p style="text-align:left;"><strong>Actualización</strong>:me habían cortado el enlace, lo resubo.</p>
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<title><![CDATA[Photoshop stilleben!]]></title>
<link>http://mmaproject.wordpress.com/2009/11/23/photoshop-stilleben/</link>
<pubDate>Mon, 23 Nov 2009 14:45:20 +0000</pubDate>
<dc:creator>mmaproject</dc:creator>
<guid>http://mmaproject.wordpress.com/2009/11/23/photoshop-stilleben/</guid>
<description><![CDATA[Been drawing some on photoshop today, been a while since, so I&#8217;m warming up with a stilleben. ]]></description>
<content:encoded><![CDATA[<div class='snap_preview'><p>Been drawing some on photoshop today, been a while since, so I&#8217;m warming up with a stilleben.</p>
<p><a href="http://mmaproject.wordpress.com/files/2009/11/stilleben-frukter.jpg"><img src="http://mmaproject.wordpress.com/files/2009/11/stilleben-frukter.jpg?w=300" alt="" title="Stilleben frukter" width="300" height="212" class="alignnone size-medium wp-image-131" /></a></p>
<p>About 4 hours, WIP.</p>
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<title><![CDATA[GEDUNG SATE SEBAGAI HERITAGE BANDUNG]]></title>
<link>http://kulukutek.wordpress.com/2009/11/23/gedung-sate-sebagai-heritage-bandung/</link>
<pubDate>Mon, 23 Nov 2009 04:28:07 +0000</pubDate>
<dc:creator>kulukutek</dc:creator>
<guid>http://kulukutek.wordpress.com/2009/11/23/gedung-sate-sebagai-heritage-bandung/</guid>
<description><![CDATA[teaser&#8230;&#8230;bla a;alalalahjcishcashcoagcasgcascgasgcoagciageqwdf &nbsp; isi berita m.nckdhck]]></description>
<content:encoded><![CDATA[<div class='snap_preview'><p>teaser&#8230;&#8230;bla a;alalalahjcishcashcoagcasgcascgasgcoagciageqwdf</p>
<p>&#160;</p>
<p>isi berita m.nckdhckachkahcaohcasklchasklcagcaocf</p>
<p>dahdaksjdhajsdhajshdakdhaksdhdsadhalkdhalkdsa</p>
<p>&#160;</p>
<p>dskadhakdhakdhaskdhakdhakddsadasddsdadsadasdad</p>
<p>adajsdhaksdhadhsa</p>
<p>&#160;</p>
<p>jaskhxaskhxakshakd</p>
<p>dlasjdaskldjsaldjasldhaifbajfgiqwehioqfqbdfgqf</p>
<p><a href="http://kulukutek.wordpress.com/files/2009/11/gs.jpg"><img class="alignnone size-medium wp-image-3" title="gs" src="http://kulukutek.wordpress.com/files/2009/11/gs.jpg?w=300" alt="" width="300" height="225" /></a></p>
<p>&#160;</p>
<p>&#160;</p>
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<title><![CDATA[The Beach, Church and Life]]></title>
<link>http://breathofgrace.wordpress.com/2009/11/23/the-beach-church-and-life/</link>
<pubDate>Mon, 23 Nov 2009 03:48:37 +0000</pubDate>
<dc:creator>Dana</dc:creator>
<guid>http://breathofgrace.wordpress.com/2009/11/23/the-beach-church-and-life/</guid>
<description><![CDATA[The reason my previous entry ended so abruptly was due to killer legs. I mean, my legs were killing ]]></description>
<content:encoded><![CDATA[<div class='snap_preview'><p>The reason my previous entry ended so abruptly was due to killer legs. I mean, my legs were killing me, not that I <em>have </em>&#8220;killer legs.&#8221; Er, yes. Apparently, I&#8217;m told I have a rather odd and awkward sense of humor, which may be validated by these blog posts.</p>
<p>Yesterday I went to the beach with my college fellowship group, and we played volleyball, soccer and football. It was epic, I must say. We were there throughout the afternoon, and the sun was setting in hues of crimson and gold on the horizon as we were knocking each other down in football. But as you know, running through the sand is way more exhausting than on flat ground, and we were at it for hours. I haven&#8217;t exercised like that in far too long. Last night, I had to go to sleep just because the pain in my legs was nearly unbearable. +o.O+</p>
<p>Everyone was a bit beat up, though. One of the poor guys from our fellowship even broke something in his foot. Ouch. ):</p>
<p>But it really was a lot of fun. I&#8217;m so thankful for my fellowship group, because they are seriously amazing. I consider a lot of them brothers and sisters, which we all are in Christ.</p>
<p>In other news, I went to church today after unceremoniously dragging my painful self out of bed. (As it usually goes when I wake up to my alarm at 7 AM.) Not too be negative, because church is more than worth it, of course. We&#8217;re studying the Parable of the Soils in the Gospel of Mark now, and it&#8217;s been really enlightening. Through this and various other experiences I&#8217;ve gone through recently, I&#8217;ve come to grasp that as much as I try to lay the burden on myself unconsciously, only the Lord gives salvation. I am to sow the seed of His Word in the hearts of others and share the Good News, but the response is not my responsibility. I think it&#8217;s a concept we all <em>know</em>, but it doesn&#8217;t completely sink in, especially when you&#8217;re so frustrated with an unresponsive nonbeliever that you think their apathy or hostility is a result of your inferior methods. <em>No.</em> It is the state of their heart. And only Christ can change that.</p>
<p>And in college service, we&#8217;ve been going through a relationship series. Yes. Relationships. Boys and girls. <em>Romance</em>. Ha ha. I&#8217;ve really enjoyed it, in fact. It&#8217;s been encouraging to my spirit, and convicting in some of the attitudes and habits I know need to change within me. And sometimes, it&#8217;s just been outright hilarious.</p>
<p>Wow, sometimes I start these entries at a loss for topics, and then I realize I&#8217;ve written a load of&#8211;hopefully understandable&#8211;words minutes later. Perhaps that is a metaphor for &#8230; life.</p>
<p>Oh, my brain. There are days I wish it worked properly.</p>
<p>Well, I do need to get back to my programming project. Blah. My final project for CS 101 has been plaguing me because I haven&#8217;t started it, and then I don&#8217;t think I can until I design how I&#8217;m going to code it, and then I&#8217;m not sure how to design it, and then I&#8217;m on facebook. Story of my life.</p>
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<title><![CDATA[Couter Strike Flash 1]]></title>
<link>http://inorbt.com/2009/11/22/couter-strike-flash-1/</link>
<pubDate>Sun, 22 Nov 2009 01:58:16 +0000</pubDate>
<dc:creator>orbtblog</dc:creator>
<guid>http://inorbt.com/2009/11/22/couter-strike-flash-1/</guid>
<description><![CDATA[mó cara que eu não coloco jogos em flash.. , antes de jogar CSS eu jogava esses em flash pra me aque]]></description>
<content:encoded><![CDATA[<div class='snap_preview'><p>mó cara que eu não coloco jogos em flash.. , antes de jogar CSS eu jogava esses em flash pra me aquecer &#8230; tem varios outros, vou colocar com o tempo eles e muito mais</p>
<p><img class="aligncenter size-thumbnail wp-image-4279" title="cs flash1" src="http://orbt.wordpress.com/files/2009/11/cs-flash1.png?w=150" alt="" width="150" height="112" /></p>
<p>clique aqui abaixo e jogue!</p>
<p><!--more--></p>
<p><embed src='http://widgets.vodpod.com/w/video_embed/Groupvideo.3980554' type='application/x-shockwave-flash' AllowScriptAccess='always' pluginspage='http://www.macromedia.com/go/getflashplayer' wmode='transparent' flashvars='' /></p>
<div style="font-size:10px;">more about &#8220;<a href="http://vodpod.com/watch/2553821-untitled?pod=orbita">Couter Strike Flash 1</a>&#8220;, posted with <a href="http://vodpod.com?r=wp">vodpod</a></div>
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<title><![CDATA[CCDT３]]></title>
<link>http://kamadiary.wordpress.com/2009/11/21/ccdt%ef%bc%93/</link>
<pubDate>Sat, 21 Nov 2009 14:16:50 +0000</pubDate>
<dc:creator>KaMa@Liberty</dc:creator>
<guid>http://kamadiary.wordpress.com/2009/11/21/ccdt%ef%bc%93/</guid>
<description><![CDATA[CCDT３に参加しました。結果は２回戦敗退。２回戦は途中までいい感じだったのに、最後の方は焦ってほとんど走り撃ちになってしまった。 １回戦 ２回戦]]></description>
<content:encoded><![CDATA[<div class='snap_preview'><p>CCDT３に参加しました。結果は２回戦敗退。２回戦は途中までいい感じだったのに、最後の方は焦ってほとんど走り撃ちになってしまった。</p>
<p>１回戦</p>
<p><a href="http://kamadiary.wordpress.com/files/2009/11/ccdt3-1.png"><img class="alignnone size-medium wp-image-270" title="ccdt3-1" src="http://kamadiary.wordpress.com/files/2009/11/ccdt3-1.png?w=300" alt="" width="300" height="225" /></a></p>
<p>２回戦</p>
<p><a href="http://kamadiary.wordpress.com/files/2009/11/ccdt3-2.png"><img class="alignnone size-medium wp-image-271" title="ccdt3-2" src="http://kamadiary.wordpress.com/files/2009/11/ccdt3-2.png?w=300" alt="" width="300" height="225" /></a></p>
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<title><![CDATA[some of my desing's]]></title>
<link>http://sufiancool.wordpress.com/2009/11/20/some-of-my-desings/</link>
<pubDate>Fri, 20 Nov 2009 17:45:47 +0000</pubDate>
<dc:creator>sufiancool</dc:creator>
<guid>http://sufiancool.wordpress.com/2009/11/20/some-of-my-desings/</guid>
<description><![CDATA[hope u like it]]></description>
<content:encoded><![CDATA[<div class='snap_preview'><p style="text-align:center;"><img class="aligncenter" src="http://i867.photobucket.com/albums/ab234/snapbboy/111-1.png" alt="" width="462" height="490" /></p>
<p style="text-align:center;"><img class="alignnone" src="http://i867.photobucket.com/albums/ab234/snapbboy/Untitled-FFF1.png" alt="" width="500" height="490" /></p>
<p style="text-align:center;"><img class="alignnone" src="http://i867.photobucket.com/albums/ab234/snapbboy/434.png" alt="" width="247" height="80" /></p>
<p style="text-align:center;"><img class="alignnone" src="http://i867.photobucket.com/albums/ab234/snapbboy/Untitled-1-7.jpg" alt="" width="200" height="200" /></p>
<p style="text-align:center;"><img class="alignnone" src="http://i867.photobucket.com/albums/ab234/snapbboy/1246116270-LY_geniuses_2.png" alt="" width="233" height="224" /></p>
<p style="text-align:center;">hope u like it</p>
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<title><![CDATA[Steam e o futuro dos jogos de PC]]></title>
<link>http://mundosteam.wordpress.com/2009/11/19/steam-e-o-futuro-dos-jogos-de-pc/</link>
<pubDate>Thu, 19 Nov 2009 22:47:31 +0000</pubDate>
<dc:creator>mundosteam</dc:creator>
<guid>http://mundosteam.wordpress.com/2009/11/19/steam-e-o-futuro-dos-jogos-de-pc/</guid>
<description><![CDATA[A distribuição dos jogos para PC está sofrendo uma reviravolta. Cada vez mais, encontramos menos jog]]></description>
<content:encoded><![CDATA[<div class='snap_preview'><p>A distribuição dos jogos para PC está sofrendo uma reviravolta. Cada vez mais, encontramos menos jogos para PC disponíveis nas prateleiras da lojas de varejo, em uma proporção inversa ao jogos para consoles, como Playstation ou Nintendo Wii. Mas será que os jogos para PC estão morrendo? Os fabricantes não tem interesse em produzir mais jogos para PC devido a pirataria? Talvez a resposta para estas perguntas esteja na plataforma Steam.</p>
<p><strong>O que é o Steam?</strong></p>
<p>Steam é uma plataforma de distribuição de jogos criada pela Valve (produtora de jogos de sucesso, como Half-Life e seu MOD famoso Counter-Strike), com objetivo de reduzir os índices de pirataria, melhorar a distribuição de jogos através de download direto, oferecer servidores rápidos para jogos online e formar comunidades em torno dos jogos.</p>
<p>&#160;</p>
<div id="attachment_11" class="wp-caption aligncenter" style="width: 310px"><a href="http://mundosteam.wordpress.com/files/2009/11/imgsteam.jpg"><img class="size-medium wp-image-11" title="Loja Steam" src="http://mundosteam.wordpress.com/files/2009/11/imgsteam.jpg?w=300" alt="Loja Steam" width="300" height="225" /></a><p class="wp-caption-text">Loja Steam</p></div>
<p><strong>Quais as vantagens de usar o Steam?</strong></p>
<p>- Acesso imediato ao jogos: todos os jogos produzidos pela Valve e parceiros estão disponíveis em um só lugar. Após comprar o jogo é so fazer o download e jogar;</p>
<p>- Comunidade Steam: é facil encontrar e convidar um amigo para jogar, ou até mesmo conhecer novos amigos que compartilham os mesmos interesses, gostam dos mesmos jogos, podendo realizar torneios, disputas e desafios;</p>
<p>- Conversar com os amigos enquanto joga online, decidindo qual servidor usar para jogar;</p>
<p>- Busca rápida por centenas de servidores em todo o mundo, usando um buscador fácil de usar;</p>
<p>- Atualização automática dos jogos, aplicando patches e atualizações automaticamente;</p>
<p>- Permite jogar os jogos em qualquer computador, pois os jogos estão associados a uma conta e não ao computador;</p>
<p>- Desconto na pré-venda de jogos e finais de semana com jogos gratuitos;</p>
<p>Veja um Tour do Steam em <a href="http://www.steampowered.com/steamtour/?l=portuguese" target="_blank">http://www.steampowered.com/steamtour/?l=portuguese</a></p>
<p>Devido ao sucesso de vendas da plataforma (veja mais no blog <a href="http://www.campominado.com.br/noticias-e-novidades/vendas-de-games-por-meios-digitais-crescem-bastante" target="_blank">Campo Minado</a>), outros desenvolvedores de jogos começaram a oferecer seus títulos através da plataforma Steam. Diante de tantas vantagens, fica claro porque os jogos estão sumindo das plateleiras das loja do varejo.</p>
<p>Mas o Steam representa a morte dos jogos em caixinha, com manual, CDs e DVDs, CD-KEYS ou serial? Provavelmente não, mas só o futuro dirá. Não podemos esquecer dos jogadores que gostam de colecionar as caixinhas, dos que não tem banda larga para baixar os jogos, e dos títulos que não estam disponíveis no Steam.</p>
<p>Um golpe duro contra a pirataria, mas não o suficiente para aniquilar. Existem diversas cópias piratas dos jogos sob o título &#8220;no steam&#8221;, porém seus usuários ficam de fora das atualizações e  sobram apenas servidores não oficiais bugados ou que permitem trapaças.</p>
<p>Mesmo não desejando adquirir os jogos, vale a pena ter o steam instalado, pois é possível baixar jogos completos gratuitamente nos finais de semana, anuciaremos aqui no Mundo Steam, os Free Weekends, para que você possa desfrutar de jogos grátis.</p>
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<title><![CDATA[Sự lựa chọn]]></title>
<link>http://trqhuong.wordpress.com/2009/11/19/s%e1%bb%b1-l%e1%bb%b1a-ch%e1%bb%8dn/</link>
<pubDate>Thu, 19 Nov 2009 15:56:10 +0000</pubDate>
<dc:creator>HuongT</dc:creator>
<guid>http://trqhuong.wordpress.com/2009/11/19/s%e1%bb%b1-l%e1%bb%b1a-ch%e1%bb%8dn/</guid>
<description><![CDATA[Người ta không thể lựa chọn cho mình người Cha người Mẹ như ý&#8230; Người ta không thể lựa chọn cho]]></description>
<content:encoded><![CDATA[<div class='snap_preview'><p>Người ta không thể lựa chọn cho mình người Cha người Mẹ như ý&#8230;</p>
<p>Người ta không thể lựa chọn cho mình từng người anh em&#8230;</p>
<p>Người ta không thể lựa chọn cho mình một hình hài vừa mắt&#8230;</p>
<p>Người ta không thể lựa chọn cho mình một cái tên phù hợp&#8230;</p>
<p>Người ta cũng không thể lựa chọn cho mình những đứa con ngoan hiền&#8230;</p>
<p>Người ta cũng không thể lựa chọn cho mình ngày giờ nhắm mắt&#8230;</p>
<p>Người ta càng không thể lựa chọn cho mình một số phận hoàn hảo&#8230;</p>
<p>&#160;</p>
<p>Nhưng&#8230;</p>
<p>&#160;</p>
<p>Người ta cũng có thể lựa chọn cho mình một chỗ ở lý tưởng&#8230;</p>
<p>Người ta có thể lựa chọn cho mình một phong cách sống&#8230;</p>
<p>Người ta có thể lựa chọn cho mình những người bạn tốt&#8230;</p>
<p>Người ta có thể lựa chọn cho mình một nghề nghiệp ổn định&#8230;</p>
<p>Người ta cũng có thể lựa chọn cho mình người phối ngẫu tương xứng&#8230;</p>
<p>Người ta cũng có thể lựa chọn cho mình cách ra đi nhẹ nhàng&#8230;</p>
<p>&#160;</p>
<p>Nhưng&#8230;</p>
<p>&#160;</p>
<p>Có những điều người ta không thể và không bao giờ có quyền lựa chọn&#8230;</p>
<p>Đó là những điều người ta đã từng được lựa chọn&#8230;</p>
<p>Từ nhiều, nhiều cuộc đời trước&#8230;</p>
<p>mà mấy ai được hay &#8211; mấy ai được biết&#8230;</p>
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