with and in arithmetic sequence.

There are solutions of the form:

………. (1, 2, 3), (7, 8, 9)

………. (2, 4, 6), (14, 16, 18) 235 more words

with and in arithmetic sequence.

There are solutions of the form:

………. (1, 2, 3), (7, 8, 9)

………. (2, 4, 6), (14, 16, 18) 235 more words

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We re starting C Programming Tutorial Series.We will try to satisfy our readers by giving some quality content in this series. 180 more words

**1487**, **4817**, and **8147** are prime numbers.

and, 4817 and 8147 are digit permutations of 1487

and they are in arithmetic progression:

4817 – 1487 = 8147 – 4817 = 3330… 74 more words

We know that if you multiply any four consecutive positive integers and add 1 to the product, you’ll get a square number.

The product of four consecutive terms of an arithmetic progression added to the fourth power of the common difference is always a perfect square… 26 more words

I’m counting to infinity.

I started yesterday at three

And took a break at night to sleep

(But even then I counted sheep

And tallied, too, the several screams… 181 more words

Numbers in arithmetic progressions – common difference **d = 3** – the sum of whose squares is a square.

In this puzzle, the sequence needs to have at least 3 terms. 94 more words

x, y, and z, are consecutive terms of an arithmetic progression,

For **n = 27**, the equation , has exactly two solutions.

And the equation , has exactly three solutions, for n = … 68 more words